Area and Perimeter is an important and basic topic in the **Mensuration** of 2-D or Planar Figures. The area is used to measure the space occupied by the planar figures. The perimeter is used to measure the boundaries of the closed figures. In Mathematics, these are two major formulas to solve the problems in the 2-dimensional shapes.

Each and every shape has two properties that are Area and Perimeter. Students can find the area and perimeter of different shapes like Circle, Rectangle, Square, Parallelogram, Rhombus, Trapezium, Quadrilateral, Pentagon, Hexagon, and Octagon. The properties of the figures will vary based on their structures, angles, and size. Scroll down this page to learn deeply about the area and perimeter of all the two-dimensional shapes.

## Area and Perimeter Definition

**Area:** Area is defined as the measure of the space enclosed by the planar figure or shape. The Units to measure the area of the closed figure is square centimeters or meters.

**Perimeter:** Perimeter is defined as the measure of the length of the boundary of the two-dimensional planar figure. The units to measure the perimeter of the closed figures is centimeters or meters.

### Formulas for Area and Perimeter of 2-D Shapes

**1. Area and Perimeter of Rectangle:**

- Area = l × b
- Perimeter = 2 (l + b)
- Diagnol = √l² + b²

Where, l = length

b = breadth

**2. Area and Perimeter of Square:**

- Area = s × s
- Perimeter = 4s

Where s = side of the square

**3. Area and Perimeter of Parallelogram:**

- Area = bh
- Perimeter = 2( b + h)

Where, b = base

h = height

**4. Area and Perimeter of Trapezoid:**

- Area = 1/2 × h (a + b)
- Perimeter = a + b + c + d

Where, a, b, c, d are the sides of the trapezoid

h is the height of the trapezoid

**5. Area and Perimeter of Triangle:**

- Area = 1/2 × b × h
- Perimeter = a + b + c

Where, b = base

h = height

a, b, c are the sides of the triangle

**6. Area and Perimeter of Pentagon:**

- Area = (5/2) s × a
- Perimeter = 5s

Where s is the side of the pentagon

a is the length

**7. Area and Perimeter of Hexagon:**

- Area = 1/2 × P × a
- Perimeter = s + s + s + s + s + s = 6s

Where s is the side of the hexagon.

**8. Area and Perimeter of Rhombus:**

- Area = 1/2 (d1 + d2)
- Perimeter = 4a

Where d1 and d2 are the diagonals of the rhombus

a is the side of the rhombus

**9. Area and Perimeter of Circle:**

- Area = Πr²
- Circumference of the circle = 2Πr

Where r is the radius of the circle

Π = 3.14 or 22/7

**10. Area and Perimeter of Octagon:**

- Area = 2(1 + √2) s²
- Perimeter = 8s

Where s is the side of the octagon.

### Solved Examples on Area and Perimeter

Here are some of the examples of the area and perimeter of the geometric figures. Students can easily understand the concept of the area and perimeter with the help of these problems.

**1. Find the area and perimeter of the rectangle whose length is 8m and breadth is 4m?**

Solution:

Given,

l = 8m

b = 4m

Area of the rectangle = l × b

A = 8m × 4m

A = 32 sq. meters

The perimeter of the rectangle = 2(l + b)

P = 2(8m + 4m)

P = 2(12m)

P = 24 meters

Therefore the area and perimeter of the rectangle is 32 sq. m and 24 meters.

**2. Calculate the area of the rhombus whose diagonals are 6 cm and 5 cm?**

Solution:

Given,

d1 = 6cm

d2 = 5 cm

Area = 1/2 (d1 + d2)

A = 1/2 (6 cm + 5cm)

A = 1/2 × 11 cm

A = 5.5 sq. cm

Thus the area of the rhombus is 5.5 sq. cm

**3. Find the area of the triangle whose base and height are 11 cm and 7 cm?**

Solution:

Given,

Base = 11 cm

Height = 7 cm

We know that

Area of the triangle = 1/2 × b × h

A = 1/2 × 11 cm × 7 cm

A = 1/2 × 77 sq. cm

A = 38.5 sq. cm

Thus the area of the triangle is 38.5 sq. cm.

**4. Find the area of the circle whose radius is 7 cm?**

Solution:

Given,

Radius = 7 cm

We know that,

Area of the circle = Πr²

Π = 3.14

A = 3.14 × 7 cm × 7 cm

A = 3.14 × 49 sq. cm

A = 153.86 sq. cm

Therefore the area of the circle is 153.86 sq. cm.

**5. Find the area of the trapezoid if the length, breadth, and height is 8 cm, 4 cm, and 5 cm?**

Solution:

Given,

a = 8 cm

b = 4 cm

h = 5 cm

We know that,

Area of the trapezoid = 1/2 × h(a + b)

A = 1/2 × (8 + 4)5

A = 1/2 × 12 × 5

A = 6 cm× 5 cm

A = 30 sq. cm

Therefore the area of the trapezoid is 30 sq. cm.

**6. Find the perimeter of the pentagon whose side is 5 meters?**

Solution:

Given that,

Side = 5 m

The perimeter of the pentagon = 5s

P = 5 × 5 m

P = 25 meters

Therefore the perimeter of the pentagon is 25 meters.

### FAQs on Area and Perimeter

**1. How does Perimeter relate to Area?**

The perimeter is the boundary of the closed figure whereas the area is the space occupied by the planar.

**2. How to calculate the perimeter?**

The perimeter can be calculated by adding the lengths of all the sides of the figure.

**3. What is the formula for perimeter?**

The formula for perimeter is the sum of all the sides.