Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

One has to learn the concepts if he/she wants to become a master in maths. The fundamentals in Go Math Grade 8 Answer Key Chapter 12 The Pythagorean theorem will help you to learn the subject. You need to practice from the beginning itself. We will help you to achieve your dreams by providing simple methods to solve the problems in an easy manner. Download Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem free pdf to help you to gain a grip over the subject.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

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Chapter 12- Lesson 1: 

Chapter 12- Lesson 2: 

Chapter 12- Lesson 3: 

Guided Practice – The Pythagorean Theorem – Page No. 378

The Pythagorean Theorem

Question 1.
Find the length of the missing side of the triangle
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 1
a2 + b2 = c2 → 242 + ? = c2 → ? = c2
The length of the hypotenuse is _____ feet.
_____ feet

Answer: The length of the hypotenuse is 26 feet.

Explanation: According to Pythagorean Theorem, we shall consider values of a = 24ft, b = 10ft.
Therefore c = √(a2 +b2)
c = √(242 + 102)
= √(576 + 100)
= √676 = 26ft

Question 2.
Mr. Woo wants to ship a fishing rod that is 42 inches long to his son. He has a box with the dimensions shown.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 2
a. Find the square of the length of the diagonal across the bottom of the box.
________ inches

Answer: 1700 inches.

Explanation: Here we consider the length of the diagonal across the bottom of the box as d.
Therefore, according to Pythagorean Theorem
W2 + l2 = d2
402 + 102 = d2
1600 + 100 = d2
1700 = d2

Question 2.
b. Find the length from a bottom corner to the opposite top corner to the nearest tenth. Will the fishing rod fit?
________ inches

Answer: 42.42 inches.

Explanation: We denote by r, the length from the bottom corner to the opposite top corner. We use our Pythagorean formula to find r.
h2 + s2 = r2
102 + 1700 = r2
100 + 1700 = r2
1800 = r2,    r = √1800 => 42.42 inches

ESSENTIAL QUESTION CHECK-IN

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 378 Q3

12.1 Independent Practice – The Pythagorean Theorem – Page No. 379

Independent Practice - The Pythagorean Theorem

Find the length of the missing side of each triangle. Round your answers to the nearest tenth.

Question 4.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 3
________ cm

Answer: 8.9 cm.

Explanation: According to Pythagorean theorem we consider values of a = 4cm, b = 8cm.
c2 = a2 + b2
= 42 + 82
= 16 + 64
c2= 80, c= √80 => 8.944
After rounding to nearest tenth value c= 8.9cm

Question 5.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 4
________ in.

Answer: 11.5 in.

Explanation: According to Pythagorean theorem we consider values of b = 8in, c= 14in
c2 = a2 + b2
142 = a2 + 82
196 = a2 + 64
a2 = 196 – 64
a  = √132 => 11.4891
a = 11.5 in

Question 6.
The diagonal of a rectangular big-screen TV screen measures 152 cm. The length measures 132 cm. What is the height of the screen?
________ cm

Answer: 75.4 cm

Explanation: Let’s consider the diagonal of the TV screen as C = 152cm, length as A = 132 cm, and height of the screen as B.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem
As C2 = A2 + B2
   1522 = 1322 + B2
23,104 = 17,424 + B2
B2 = 23,104 – 17,424
B = √5680 => 75.365
So the height of the screen B = 75.4cm

Question 7.
Dylan has a square piece of metal that measures 10 inches on each side. He cuts the metal along the diagonal, forming two right triangles. What is the length of the hypotenuse of each right triangle to the nearest tenth of an inch?
________ in.

Answer: 14.1in.

Explanation:
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

Using the Pythagorean Theorem, we have:
a2 + b2 = c2
102 + 102 = c2
100 + 100 = c2
200 = c2
We are told to round the length of the hypotenuse of each right triangle to the nearest tenth of an inch, therefore: c = 14.1in

Question 8.
Represent Real-World Problems A painter has a 24-foot ladder that he is using to paint a house. For safety reasons, the ladder must be placed at least 8 feet from the base of the side of the house. To the nearest tenth of a foot, how high can the ladder safely reach?
________ ft

Answer: 22.6 ft.

Explanation: Consider the below diagram. Length of the ladder C = 24ft, placed at a distance from the base B = 8ft, let the safest height be A.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

By using Pythagorean Theorem:
C2 = A2 + B2
242 = A2 + 82
576 = A2 + 64
A2 = 576 – 64 => 512
A = √512 => 22.627
After rounding to nearest tenth, value of A = 22.6ft

Question 9.
What is the longest flagpole (in whole feet) that could be shipped in a box that measures 2 ft by 2 ft by 12 ft?
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 5
________ ft

Answer: The longest flagpole (in whole feet) that could be shipped in this box is 12 feet.

Explanation: From the above diagram we have to find the value of r, which gives us the length longest flagpole that could be shipped in the box. Where width w = 2ft, height h = 2ft and length l = 12ft.

First find s, the length of the diagonal across the bottom of the box.
w2 + l2 = s2
22 + 122 = s2
4 + 144 = s2
148 = s2
We use our expression for s to find r, since triangle with sides s, r, and h also form a right-angle triangle.
h2 + s2 = r2
22 + 148 = r2
4 + 148 = r2
152 = r2
r = 12.33ft.

Question 10.
Sports American football fields measure 100 yards long between the end zones, and are 53 \(\frac{1}{3}\) yards wide. Is the length of the diagonal across this field more or less than 120 yards? Explain.
____________

Answer: The diagonal across this field is less than 120 yards.

Explanation: From the above details we will get a diagram as shown below.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

We are given l = 100 and w = 53  =  . If we denote with d the diagonal of the field, using the Pythagorean Theorem, we have:
l2 + w2 = d2
1002 + (160/3)2 = d2
10000 + (25600/9) = d2
9*10000 + 9*(25600/9) = 9* d2
90000 + 25600 = 9 d2
(115600/9) = d2
(340/9) = d2
d = 113.3
Hence the diagonal across this field is less than 120 yards.

Question 11.
Justify Reasoning A tree struck by lightning broke at a point 12 ft above the ground as shown. What was the height of the tree to the nearest tenth of a foot? Explain your reasoning.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 6
________ ft

Answer: The total height of the tree was 52.8ft

Explanation:

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem
By using the Pythagorean Theorem
a2 + b= c2
122 + 392 = c2
144 + 1521 = c2
1665 = c2
We are told to round the length of the hypotenuse to the nearest tenth of a foot, therefore: c = 40.8ft.
Therefore, the total height of the tree was:
height = a+c
height = 12 +40.8
height = 52.8 feet

FOCUS ON HIGHER ORDER THINKING – The Pythagorean Theorem – Page No. 380

Question 12.
Multistep Main Street and Washington Avenue meet at a right angle. A large park begins at this corner. Joe’s school lies at the opposite corner of the park. Usually, Joe walks 1.2 miles along Main Street and then 0.9 miles up Washington Avenue to get to school. Today he walked in a straight path across the park and returned home along the same path. What is the difference in distance between the two round trips? Explain.
________ mi

Answer: Joe walks 1.2 miles less if he follows the straight path across the park.

Explanation: Using the Pythagorean Theorem, we find the distance from his home to school following the straight path across the park:
a2 + b= c2
1.22 + 0.92 = c2
1.44 + 0.81 = c2
2.25 = c2
1.5 = c
Therefore, the distance of Joe’s round trip following the path across the park is 3 miles (dhome-school + dschool-home = 1.5 + 1.5). Usually, when he walks along Main Street and Washington Avenue, the distance of his round trip is 4.2 miles (dhome-school + dschool-home = (1.2 + 0.9) + (0.9+1.2)). As we can see, Joe walks 1.2 miles less if he follows the straight path across the park.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 380 Q13

Question 14.
Persevere in Problem-Solving A square hamburger is centered on a circular bun. Both the bun and the burger have an area of 16 square inches.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 1: The Pythagorean Theorem img 7
a. How far, to the nearest hundredth of an inch, does each corner of the burger stick out from the bun? Explain.
________ in

Answer: Each corner of the burger sticks out 0.57 inches from the bun.

Explanation: Frist, we need to find the radius r of the circular bun. We know that its area A is 16 square inches, therefore:

 

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

A = πr2
16 = 3.14*r2
r2 = (16/3.14)
r = 2.26

Then, we need to find the sides of the square hamburger. We know that its area A is 16 square inches, therefore:
A = s2
16 = s2
s = 4
Using the Pythagorean Theorem, we have to find the diagonal d of the square hamburger:
s2 + s2 = d2
42 + 42 = d2
16 + 16 = d2
32 = d2
d = 5.66
To find how far each corner of the burger sticks out from the bun, we denote this length by a and we get:
a = (d/2) – r => (5.66/2) – 2.26
a = 0.57.
Therefore, Each corner of the burger sticks out 0.57 inches from the bun.

Question 14.
b. How far does each bun stick out from the center of each side of the burger?
________ in

Answer: Each bun sticks out 0.26 inches from the center of each side of the burger.

Explanation:

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

We found that r = 2.26 and s = 4. To find how far does each bun stick out from the center of each side of the burger, we denote this length by b and we get:
b = r – (s/2) = 2.26 – (4/2)
b = 0.26 inches.

Question 14.
c. Are the distances in part a and part b equal? If not, which sticks out more, the burger or the bun? Explain.

Answer: The distances a and b are not equal. From the calculations, we found that the burger sticks out more than the bun.

Guided Practice – Converse of the Pythagorean Theorem – Page No. 384

Converse of the Pythagorean Theorem

Question 1.
Lashandra used grid paper to construct the triangle shown.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 2: Converse of the Pythagorean Theorem img 8
a. What are the lengths of the sides of Lashandra’s triangle?
_______ units, _______ units, _______ units,

Answer: The length of Lashandra’s triangle is 8 units, 6 units, 10 units.

Question 1.
b. Use the converse of the Pythagorean Theorem to determine whether the triangle is a right triangle.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 2: Converse of the Pythagorean Theorem img 9
The triangle that Lashandra constructed is/is not a right triangle.
_______ a right triangle

Answer: Lashandra’s triangle is right angled triangle as it satisfied the Pythagorean theorem

Explanation:
Verifying with Pythagorean formula a2 + b= c2
82 + 62 = 102
64 + 36 =100
100 = 100.

Question 2.
A triangle has side lengths 9 cm, 12 cm, and 16 cm. Tell whether the triangle is a right triangle.
Let a = _____, b = _____, and c = ______.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 2: Converse of the Pythagorean Theorem img 10
By the converse of the Pythagorean Theorem, the triangle is/is not a right triangle.
_______ a right triangle

Answer: The given triangle is not a right-angled triangle

Explanation: Verifying with Pythagorean formula a2 + b= c2
92 + 122 = 162
81 + 144 = 256
225 ≠ 256.
Hence given dimensions are not from the right-angled triangle.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 384 Q3

ESSENTIAL QUESTION CHECK-IN

Question 4.
How can you use the converse of the Pythagorean Theorem to tell if a triangle is a right triangle?
Answer:
Knowing the side lengths, we substitute them in the formula a2 + b= c2, where c contains the biggest value.
If the equation holds true, then the given triangle is a right triangle. Otherwise, it is not a right triangle.

12.2 Independent Practice – Converse of the Pythagorean Theorem – Page No. 385

Tell whether each triangle with the given side lengths is a right triangle.

Question 5.
11 cm, 60 cm, 61 cm
______________

Answer: Since 112 + 602 = 612, the triangle is a right-angled triangle.

Explanation: Let a = 11, b = 60 and c= 61
Using the converse of the Pythagorean Theorem a2 + b= c2
112 + 602 = 612
121 + 3600 = 3721
3721 = 3721.
Since 112 + 602 = 612, the triangle is a right-angled triangle.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 385 Q6

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 385 Q7

Question 8.
15 m, 36 m, 39 m
______________

Answer: Since 152 + 362 = 392, the triangle is a right-angled triangle.

Explanation: Let a = 15, b = 36 and c= 39
Using the converse of the Pythagorean Theorem a2 + b= c2
152 + 362 = 392
225 + 1296 = 1521
1521 = 1521.
Since 152 + 362 = 392, the triangle is a right-angled triangle.

Question 9.
20 mm, 30 mm, 40 mm
______________

Answer: Since 202 + 302 ≠ 402, the triangle is not a right-angled triangle.

Explanation: Let a = 20, b = 30 and c= 40
Using the converse of the Pythagorean Theorem a2 + b= c2
202 + 302 = 402
400 + 900 = 1600
1300 ≠ 1600.
Since 202 + 302 ≠ 402, the triangle is not a right-angled triangle.

Question 10.
20 cm, 48 cm, 52 cm
______________

Answer: Since 202 + 482 = 522, the triangle is a right-angled triangle.

Explanation: Let a = 20, b = 48 and c= 52
Using the converse of the Pythagorean Theorem a2 + b= c2
202 + 482 = 522
400 + 2304 = 2704
2704 = 2704.
Since 202 + 482 = 522, the triangle is a right-angled triangle.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 385 Q11

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 385 Q12

Question 13.
35 in., 45 in., 55 in.
______________

Answer: Since 352 + 452 ≠ 552, the triangle is not a right-angled triangle.

Explanation: Let a = 35, b = 45 and c= 55
Using the converse of the Pythagorean Theorem a2 + b= c2
352 + 452 = 552
1225 + 2025 = 3025
3250 ≠ 3025.
Since 352 + 452 ≠ 552, the triangle is not a right-angled triangle.

Question 14.
25 cm, 14 cm, 23 cm
______________

Answer: Since  142 + 232 ≠ 252, the triangle is not a right-angled triangle.

Explanation: Let a = 14, b = 23 and c= 25 (longest side)
Using the converse of the Pythagorean Theorem a2 + b= c2
142 + 232 = 252
196 + 529 = 625
725 ≠ 625.
Since  142 + 232 ≠252, the triangle is not a right-angled triangle.

Question 15.
The emblem on a college banner consists of the face of a tiger inside a triangle. The lengths of the sides of the triangle are 13 cm, 14 cm, and 15 cm. Is the triangle a right triangle? Explain.
________

Answer: Since  132 + 142 ≠ 152, the triangle is not a right-angled triangle.

Explanation: Let a = 13, b = 14 and c= 15
Using the converse of the Pythagorean Theorem a2 + b= c2
132 + 142 = 152
169 + 196 = 225
365 ≠ 225.
Since  132 + 142 ≠ 152, the triangle is not a right-angled triangle.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 385 Q16

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 385 Q17

Question 18.
History In ancient Egypt, surveyors made right angles by stretching a rope with evenly spaced knots as shown. Explain why the rope forms a right angle.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 2: Converse of the Pythagorean Theorem img 11

Answer: The rope has formed a right-angled triangle because the length of its sides follows Pythagorean Theorem.

Explanation: The knots are evenly placed at equal distances
The lengths in terms of knots are a=4 knots, b = 3knots, c = 5 knots
Therefore a2 + b= c2
42 + 3= 52
16+9 = 25
25 = 25.
Hence rope has formed a right-angled triangle because the length of its sides follows Pythagorean Theorem.

Converse of the Pythagorean Theorem – Page No. 386

Question 19.
Justify Reasoning Yoshi has two identical triangular boards as shown. Can he use these two boards to form a rectangle? Explain.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 2: Converse of the Pythagorean Theorem img 12

Answer: Since it was proved that both can form a right-angled triangle, we can form a rectangle by joining them.

Explanation: Given both triangles are identical, if both are right-angled triangles then we can surely join to form a rectangle.
Let’s consider a = 0.75, b= 1 and c=1.25.
By using converse Pythagorean Theorem a2 + b= c2
0.752 + 12 = 1.252
0.5625 + 1 = 1.5625
1.5625 = 1.5625.
Since it was proved that both can form a right-angled triangles, we can form a rectangle by joining them.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 386 Q20

FOCUS ON HIGHER ORDER THINKING

Question 21.
Make a Conjecture Diondre says that he can take any right triangle and make a new right triangle just by doubling the side lengths. Is Diondre’s conjecture true? Test his conjecture using three different right triangles.
_______

Answer: Yes, Diondre’s conjecture is true. By doubling the sides of a right triangle would create a new right triangle.

Explanation: Given a right triangle, the Pythagorean Theorem holds. Therefore, a2 + b= c2
If we double the side lengths of that triangle, we get:
(2a)2 + (2b)= (2c)2
4a2 + 4b2 = 4c2
4(a2 + b2) = 4c2
a2 + b= c2                    
As we can see doubling the sides of a right triangle would create a new right triangle.We can test that by using three different right triangles.

The triangle with sides a = 6, b = 8 and c = 10 is a right triangle. We double its sides and check if the new triangle is a right triangle. After doubling value of a = 12, b = 16 and c = 20.
122 + 162 = 202
144 + 256 = 400
400 = 400
Hence proved!
Since 122 + 162 = 202, the new triangle is a right triangle by the converse of the Pythagorean Theorem.

The triangle with sides a = 3, b = 4 and c = 5 is a right triangle. We double its sides and check if the new triangle is a right triangle. After doubling value of a = 6, b = 8 and c = 10.
62 + 82 = 102
36 + 64 = 100
100 = 100
Hence proved!
Since 62 + 82 = 102, the new triangle is a right triangle by the converse of the Pythagorean Theorem.

The triangle with sides a = 12, b = 16 and c = 20 is a right triangle. We double its sides and check if the new triangle is a right triangle. After doubling value of a = 24, b = 32 and c = 40.
242 + 322 = 402
576 + 1024 = 1600
1600 = 1600
Hence proved!
Since 242 + 322 = 402, the new triangle is a right triangle by the converse of the Pythagorean Theorem.

Question 22.
Draw Conclusions A diagonal of a parallelogram measures 37 inches. The sides measure 35 inches and 1 foot. Is the parallelogram a rectangle? Explain your reasoning.
_______

Answer: Since 122 + 352 = 372, the triangle is right triangle. Therefore, the given parallelogram is a rectangle.

Explanation: A rectangle is a parallelogram where the interior angles are right angles. To prove if the given parallelogram is a rectangle, we need to prove that the triangle formed by the diagonal of the parallelogram and two sides of it, is a right triangle. Converting all the values into inches, we have a = 12, b = 35 and c = 37. Using the converse of the Pythagorean Theorem, we have:
a2 + b= c2
122 + 352 = 372
144 + 1225 = 1369
1369 = 1369.
Since 122 + 352 = 372, the triangle is right triangle. Therefore, the given parallelogram is a rectangle.

Question 23.
Represent Real-World Problems A soccer coach is marking the lines for a soccer field on a large recreation field. The dimensions of the field are to be 90 yards by 48 yards. Describe a procedure she could use to confirm that the sides of the field meet at right angles.

Answer: To confirm that the sides of the field meet at right angles, she could measure the diagonal of the field and use the converse of the Pythagorean Theorem. If a2 + b= c2 (where a = 90, b = 48, and c is the length of the diagonal), then the triangle is a right triangle. This method can be used for every corner to decide if they form right angles or not.

Guided Practice – Distance Between Two Points – Page No. 390

Question 1.
Approximate the length of the hypotenuse of the right triangle to the nearest tenth using a calculator.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 13
_______ units

Answer: The length of the hypotenuse of the right triangle to the nearest tenth is 5.8 units.

Explanation: From the above figure let’s take
Length of the vertical leg = 3 units
Length of the horizontal leg = 5 units
let length of the hypotenuse = c
By using Pythagorean Theorem a2 + b= c2
c2 = 32 + 52
c2 = 9 +25
c = √34 => 5.830.
Therefore Length of the hypotenuse of the right triangle to the nearest tenth is 5.8 units.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 390 Q2

Question 3.
A plane leaves an airport and flies due north. Two minutes later, a second plane leaves the same airport flying due east. The flight plan shows the coordinates of the two planes 10 minutes later. The distances in the graph are measured in miles. Use the Pythagorean Theorem to find the distance shown between the two planes.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 14
_______ miles

Answer: The distance between the two planes is 103.6 miles.

Explanation:
Length of the vertical dv = √(80 -1)2 + √(1-1)2
= √792 => 79.
Length of the horizontal dh = √(68 -1)2 + √(1-1)2
= √672 => 67.
Distance between the two planes D = √(792 + 672)
= √(6241+4489) => √10730
= 103.5857 => 103.6 miles.

ESSENTIAL QUESTION CHECK-IN

Question 4.
Describe two ways to find the distance between two points on a coordinate plane.

Answer:

Explanation: We can draw a right triangle whose hypotenuse is the segment connecting the two points and then use the Pythagorean Theorem to find the length of that segment. We can also the Distance formula to find the length of that segment.

For example, plot three points; (1,2), (20,2), and (20,12)

Using the Pythagorean Theorem:

The length of the horizontal leg is the absolute value of the difference between the x-coordinates of points (1,2) and (20,2).
|1 – 20| = 19
The length of the horizontal leg is 19.

The length of the vertical leg is the absolute value of the difference between the y-coordinates of the points (20,2) and (20,12).
|2 – 12| = 10
The length of the vertical leg is 10.

Let a = 19, b = 10 and let c represent the hypotenuse. Find c.
a2 + b= c2
192 + 10= c2
361 + 100 = c2
461 = c2
distance is 21.5 = c

Using the Distance formula:
d= √( x2 – x1)2 + √( y2 – y1)2
The length of the horizontal leg is between (1,2) and (20,2).
d= √( x2 – x1)2 + √( y2 – y1)2
  =  √(20 -1)2 + √(2-2)2
= √(19)2 + √(0)2
= √361 => 19
The length of the vertical leg is between (20,2) and (20,12).
d= √( x2 – x1)2 + √( y2 – y1)2
  =  √(20 -20)2 + √(12-2)2
= √(0)2 +√(10)2
= √100 => 10
The length of the diagonal leg is between (1,2) and (20,12).
d= √( x2 – x1)2 + √( y2 – y1)2
  =  √(20 -1)2 + √(12-2)2
= √(19)2 + √(10)2
= √(361+100) => √461 = 21.5

12.3 Independent Practice – Distance Between Two Points – Page No. 391

Question 5.
A metal worker traced a triangular piece of sheet metal on a coordinate plane, as shown. The units represent inches. What is the length of the longest side of the metal triangle? Approximate the length to the nearest tenth of an inch using a calculator. Check that your answer is reasonable.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 15
_______ in.

Answer: The length of the longest side of the metal triangle to the nearest tenth is 7.8 units.

Explanation: From the above figure let’s take
Length of the vertical leg = 6 units
Length of the horizontal leg = 5 units
let length of the hypotenuse = c
By using Pythagorean Theorem a2 + b= c2
c2 = 62 + 52
c2 = 36 +25
c = √61 => 7.8
Therefore Length of the longest side of the metal triangle to the nearest tenth is 7.8 units.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 391 Q6

Question 7.
The coordinates of the vertices of a rectangle are given by R(- 3, – 4), E(- 3, 4), C (4, 4), and T (4, – 4). Plot these points on the coordinate plane at the right and connect them to draw the rectangle. Then connect points E and T to form diagonal \(\overline { ET } \).
a. Use the Pythagorean Theorem to find the exact length of \(\overline { ET } \).
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 16

Answer: The diagonal ET is about 10.63 units long.

Explanation:
Taking into consideration the triangle TRE, the length of the vertical leg (ER) is 8 units. The length of the horizontal leg (RT) is 7 units. Let a = 8 and b =7. Let c represent the length of the hypotenuse, the diagonal ET. We use the Pythagorean Theorem to find c.
a2 + b= c2
c2 = 82 + 72
c2 = 64 +49
c = √113 => 10,63.
The diagonal ET is about 10.63 units long.

Question 7.
b. How can you use the Distance Formula to find the length of \(\overline { ET } \) ? Show that the Distance Formula gives the same answer.

Answer: The diagonal ET is about 10.63 units long. As we can see the answer is the same as the one we found using the Pythagorean Theorem.

Explanation: Using the distance formula, in a coordinate plane, the distance d between the points E(-3,4) and T(4, -4) is:
d= √( x2 – x1)2 + √( y2 – y1)2
  =  √(4 – (-3))2 + √(- 4 – 4)2
= √(7)2 + √(-8)2
= √(49+64) => √113 = 10.63.
The diagonal ET is about 10.63 units long. As we can see the answer is the same as the one we found using the Pythagorean Theorem.

Question 8.
Multistep The locations of three ships are represented on a coordinate grid by the following points: P(- 2, 5), Q(- 7, – 5), and R(2, – 3). Which ships are farthest apart?

Answer: Ships P and Q are farthest apart

Explanation: Distance Formula: In a coordinate plane, the distance d between two points (x1,y1) and (x2,y2) is:

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem
d= √( x2 – x1)2 + √( y2 – y1)2
The distance d1 between the two points P(-2,5) and Q(-7,-5) is:
d1 = √( xQ – xP)2 + √( yQ – yP)2
= √(-7 – (-2))2 + √(- 5 – 5)2
= √(-5)2 + √(-10)2
= √(25+100) => √125 = 11.18

The distance d2 between the two points Q(-7,-5) and R(2,-3) is:
d3 = √( xR – xQ)2 + √( yR – yQ)2
  = √(2 – (-7))2 + √(- 3 – 5)2
= √(9)2 + √(2)2
= √(81+4) => √85 = 9.22

The distance d3 between the two points P(-2,5) and R(2,-3) is:
d3 = √( xR – xP)2 + √( yR – yP)2
= √(2 – (-2))2 + √(- 3 – 5)2
= √(4)2 + √(-8)2
= √(16+64) => √80 = 8.94.
As we can see, the greatest distance is d1 11.8, which means that ships P and Q are farthest apart.

Distance Between Two Points – Page No. 392

Question 9.
Make a Conjecture Find as many points as you can that are 5 units from the origin. Make a conjecture about the shape formed if all the points 5 units from the origin were connected.

Answer: (0,5), (3,4), (4,3),(5,0),(4,-3),(3,-4),(0,-5),(-3,-4),(-4,-3),(-5,0),(-4,3),(-3,4).

Explanation: Some of the points that are 5 units away from the origin are: (0,5), (3,4), (4,3),(5,0),(4,-3),(3,-4),(0,-5),(-3,-4),(-4,-3),(-5,0),(-4,3),(-3,4) etc, If all the points 5 units away from the origin are connected, a circle would be formed.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

Question 10.
Justify Reasoning The graph shows the location of a motion detector that has a maximum range of 34 feet. A peacock at point P displays its tail feathers. Will the motion detector sense this motion? Explain.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 17

Answer: Considering each unit represents 1 foot, the motion detector, and peacock are 33.5 feet apart. Since the motion detector has a maximum range of 34 feet, it means that it will sense the motion of the peacock’s feathers.

Explanation: The coordinates of the motion detector are said to be (0,25), whereas the coordinates of the peacock are (30,10). In a coordinate plane, the distance d between the points (0,25) and (30,10) is:
d = √( x2 – x1)2 + √( y2 – y1)2
= √(30 – 0)2 + √(10 – 25)2
= √(30)2 + √(-15)2
= √(900+225) => √1125.
Rounding answer to the nearest tenth:
d = 33.5 feet.
Considering each unit represents 1 foot, the motion detector and peacock are 33.5 feet apart. Since the motion detector has a maximum range of 34 feet, it means that it will sense the motion of the peacock’s feathers.

FOCUS ON HIGHER ORDER THINKING

Question 11.
Persevere in Problem Solving One leg of an isosceles right triangle has endpoints (1, 1) and (6, 1). The other leg passes through the point (6, 2). Draw the triangle on the coordinate plane. Then show how you can use the Distance Formula to find the length of the hypotenuse. Round your answer to the nearest tenth.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 18

Answer: 7.1 units.

Explanation:

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem

One leg of an isosceles right triangle has endpoints (1,1) and (6,1), which means that the leg is 5 units long. Since the triangle is isosceles, the other leg should be 5 units long too, therefore the endpoints of the second leg that passes through the point (6,2) are (6,1) and (6,6).
In the coordinate plane, the length of the hypotenuse is the distance d between points (1,1) and (6,6).
d = √( x2 – x1)2 + √( y2 – y1)2
= √(6 – 1)2 + √(6 – 1)2
= √(5)2 + √(5)2
= √(25+25) => √50.
Rounding answer to nearest tenth:
d = 7.1.
The hypotenuse is around 7.1 units long.

Question 12.
Represent Real-World Problems The figure shows a representation of a football field. The units represent yards. A sports analyst marks the locations of the football from where it was thrown (point A) and where it was caught (point B). Explain how you can use the Pythagorean Theorem to find the distance the ball was thrown. Then find the distance.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Lesson 3: Distance Between Two Points img 19
_______ yards

Answer: The distance between point A and B is 37 yards

Explanation:
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem
To find the distance between points A and B, we draw segment AB and label its length d. Then we draw the vertical segment AC and Horizontal segment CB. We label the lengths of these segments a and b. triangle ACB is a right triangle with hypotenuse AB.
Since AC is a vertical segment, its length, a, is the difference between its y-coordinates. Therefore, a = 26 – 14 = 12 units.
Since CB is a horizontal segment, its length b is the difference between its x-coordinates. Therefore, b = 75 – 40 = 35units.
We use the Pythagorean Theorem to find d, the length of segment AB.
d2 = a2 + b2
d2 = 122 + 352
d2 = 144 + 1225
d2 = 1369 => d = √1369 => 37
The distance between points A and B is 37 yards

Ready to Go On? – Model Quiz – Page No. 393

12.1 The Pythagorean Theorem

Find the length of the missing side.

Question 1.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Model Quiz img 20
________ meters

Answer: Length of the missing side is 28m

Explanation: Lets consider value of a = 21 and c = 35.
Using Pythagorean Theorem a2 + b= c2
212 + b2 = 352                                            
441 + b2 = 1225
b2= 784 => b = √784 = 28.
Therefore length of missing side is 28m.

Question 2.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Model Quiz img 21
________ ft

Answer: Length of missing side is 34ft

Explanation: Let’s consider value of a = 16 and b = 30.
Using Pythagorean Theorem a2 + b= c2
162 + 302 = c2                                              
256 + 900 = c2
c2= 1156 => c = √1156 = 34.
Therefore length of missing side is 34ft.

12.2 Converse of the Pythagorean Theorem

Tell whether each triangle with the given side lengths is a right triangle.

Question 3.
11, 60, 61
____________

Answer: Since 112 + 602 = 612, by the converse of the Pythagorean Theorem, we say that the given sides are in the shape of right-angled triangle.

Explanation: Let a = 11, b = 60 and c= 61
Using the converse of the Pythagorean Theorem a2 + b= c2
112 + 602 = 612
121 + 3600 = 3721
3721 = 3721
Since 112 + 602 = 612, by the converse of the Pythagorean Theorem, we say that the given sides are in the shape of right-angled triangle.                      

Question 4.
9, 37, 40
____________

Answer: Since  92 + 372 ≠ 402, by the converse of the Pythagorean Theorem, we say that the given sides are not in the shape of a right-angled triangle.

Explanation: Let a = 9, b = 37 and c= 40
Using the converse of the Pythagorean Theorem a2 + b= c2
92 + 372 = 402
81 + 1369 = 1600
1450 ≠ 3721.
Since  92 + 372 ≠ 402, by the converse of the Pythagorean Theorem, we say that the given sides are not in the shape of a right-angled triangle.

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 393 Q5

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 393 Q6


Question 7.
Keelie has a triangular-shaped card. The lengths of its sides are 4.5 cm, 6 cm, and 7.5 cm. Is the card a right triangle?
____________

Answer: Since 4.52 + 62 = 7.52, by the converse of the Pythagorean Theorem, we say that the given sides are in the shape of a right-angled triangle.

Explanation: Let a = 4.5, b = 6 and c= 7.5
Using the converse of the Pythagorean Theorem a2 + b= c2
4.52 + 62 = 7.52
20.25 + 36 = 56.25
56.25= 56.25
Since 4.52 + 62 = 7.52, by the converse of the Pythagorean Theorem, we say that the given sides are in the shape of a right-angled triangle.                                                                            

12.3 Distance Between Two Points

Find the distance between the given points. Round to the nearest tenth.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Model Quiz img 22

Question 8.
A and B
________ units

Answer: The distance between A and B is 6.7 units

Explanation: A= (-2,3) and B= (4,6)

Distance between A and B is d = √( x2 – x1)2 + √( y2 – y1)2
= √(4 – (-2)2 + √(6 – 3)2
= √(6)2 + √(3)2
= √(36+9) => √45 = 6.7 units

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 393 Q9

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 393 Q10

ESSENTIAL QUESTION

Question 11.
How can you use the Pythagorean Theorem to solve real-world problems?
Answer:
We can use the Pythagorean Theorem to find the length of a side of a right triangle when we know the lengths of the other two sides. This application is usually used in architecture or other physical construction projects. For example, it can be used to find the length of a ladder, if we know the height of the wall and the distance on the ground from the wall of the ladder.

Selected Response – Mixed Review – Page No. 394

Question 1.
What is the missing length of the side?
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Mixed Review img 23
A. 9 ft
B. 30 ft
C. 39 ft
D. 120 ft

Answer: C

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 394 Q1

Question 2.
Which relation does not represent a function?
Options:
A. (0, 8), (3, 8), (1, 6)
B. (4, 2), (6, 1), (8, 9)
C. (1, 20), (2, 23), (9, 26)
D. (0, 3), (2, 3), (2, 0)

Answer: D

Explanation: The value of X is the same for 2 points and 2 values of Y [(2, 3), (2, 0)]. The value of X is repeated for a function to exist, no two points can have the same X coordinates.

Question 3.
Two sides of a right triangle have lengths of 72 cm and 97 cm. The third side is not the hypotenuse. How long is the third side?
Options:
A. 25 cm
B. 45 cm
C. 65 cm
D. 121 cm

Answer: C

Explanation:
Given a= 72 cm
b= ?
c= 97 cm
As a2+b2=c 2
722+b2= 972
5,184+b2= 9,409
b2= 9,409-5,184
b= √4,225
b= 65 cm.

Question 4.
To the nearest tenth, what is the distance between point F and point G?
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Mixed Review img 24
Options:
A. 4.5 units
B. 5.0 units
C. 7.3 units
D. 20 units

Answer: A.

Explanation:
Given F= (-1,6) =(x1,y1).
G= (3,4) = (x2,y2).
The difference between F&G points is
d= √(x2-x1)2 + (y2-y1)2
=  √(3 – (-1))2 + (4 – 6)2
 = √(4)2 + (-2)2
= √16+4
= √20
= 4.471
= 4.5 units.

Question 5.
A flagpole is 53 feet tall. A rope is tied to the top of the flagpole and secured to the ground 28 feet from the base of the flagpole. What is the length of the rope?
Options:
A. 25 feet
B. 45 feet
C. 53 feet
D. 60 feet

Answer: D

Explanation:
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem
By Pythagorean theorem
a2+b2=c 2
532+282= C2
2,809+784= C2
C2 = 9,409-5,184
C2 = 3,593
C= √3,593
C= 59.94 feet
=60 feet.

Question 6.
Which set of lengths is not the side lengths of a right triangle?
Options:
A. 36, 77, 85
B. 20, 99, 101
C. 27, 120, 123
D. 24, 33, 42

Answer: D.

Explanation:
Check if side lengths in option A form a right triangle.
Let a= 36, b= 77, c= 85
By Pythagorean theorem
a2+b2=c 2
362+772= 852
1,296+ 5,929= 7,225
7,225= 7,225
As 362+772= 852 the triangle is a right triangle.

Check if side lengths in option B form a right triangle.
Let a= 20, b= 99, c= 101
By Pythagorean theorem
a2+b2=c 2
202+992= 1012
400+ 9,801= 10,201
10,201= 10,201
As 202+992= 1012 the triangle is a right triangle.

Check if side lengths in option B form a right triangle.
Let a= 27, b= 120, c= 123
By Pythagorean theorem
a2+b2=c 2
272+1202= 1232
729+ 14,400= 15,129
15,129= 15,129
As 272+1202= 1232 the triangle is a right triangle.

Check if side lengths in option B form a right triangle.
Let a= 27, b= 120, c= 123
By Pythagorean theorem
a2+b2=c 2
242+332= 422
576+ 1,089= 1,764.
1,665= 1,764
As 242+332 is not equal to 422 the triangle is a right triangle.

Question 7.
A triangle has one right angle. What could the measures of the other two angles be?
Options:
A. 25° and 65°
B. 30° and 15°
C 55° and 125°
D 90° and 100°

Answer:
A. 25° and 65°

Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Page 394 Q7

Mini-Task

Question 8.
A fallen tree is shown on the coordinate grid below. Each unit represents 1 meter.
Go Math Grade 8 Answer Key Chapter 12 The Pythagorean Theorem Mixed Review img 25
a. What is the distance from A to B?
_______ meters

Answer: 13.34  m.

Explanation:
A= (-5,3)
B= (8,0)
Distance between A & B is
D= √{8-(-5)2 + (0-3)2
= √(13)2 + (-3)2
= √169+9
= √178
= 13.34  m.

Question 8.
b. What was the height of the tree before it fell?
_______ meters

Answer: 16.3 m.

Explanation:
Length of the broken part= 13.3 m
Length of vertical part= 3 m
Total Length = 13.3 m + 3 m
= 16.3 m.

Final Words

In addition to the exercise problems, we have provided the solutions for the review questions. So all the students are requested to test their knowledge and solve the problems provided at the end of this chapter. Refer to HMH Go Math Grade 8 Answer Key and try to score the highest marks in the exams. Hope you liked the explanations provided in this chapter. Stay tuned to get the solutions according to the list of the chapters of all the grades.

Refer:

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Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables

go-math-grade-6-chapter-9-independent-and-dependent-variables-answer-key

Download Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables pdf for free of cost. It is very important for the students to learn the fundamentals at the secondary level. In order to help you guys, we are providing the answers to all the questions in HMH Go Math Grade 6 Chapter 9 Solution Key Independent and Dependent Variables.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables

The Independent and Dependent Variables chapter consists of the topics like equations and tables, analyze relationships, graphs etc. It is essential for students to know the relationship between the graphs and tables in this chapter. You can know different methods of solving the problems by using Go Math Grade 6 Solution Key Chapter 9 Independent and Dependent Variables. All you have to do is to tap the below-given links.

Lesson 1: Independent and Dependent Variables

Lesson 2: Equations and Tables

Lesson 3: Problem Solving • Analyze Relationships

Mid-Chapter Checkpoint

Lesson 4: Graph Relationships

Lesson 4: Graph Relationships

Lesson 5: Equations and Graphs

Chapter 9 Review/Test

Share and Show – Page No. 493

Identify the independent and dependent variables. Then write an equation to represent the relationship between them.

Question 1.
An online store lets customers have their name printed on any item they buy. The total cost c in dollars is the price of the item p in dollars plus $3.99 for the name.
Type below:
________________

Answer: c = p + $3.99

Explanation:
The independent variable is c, the price of the item because it is not going to depend on anything else.
The dependent variable is p because the total cost depends on how many items there are, whether your name is marked on it, etc.
The equation would be:
c = p + $3.99

Question 2.
A raft travels downriver at a rate of 6 miles per hour. The total distance d in miles that the raft travels is equal to the rate times the number of hours h.
Type below:
________________

Answer: d = 6 × h

Explanation:
Speed of the raft= 6 miles per hour
Total distance (d) of the raft = rate × number of hours h
The dependent variable is the number of hours h
The independent variable is distance d.
The equation would be:
d = 6 × h

Question 3.
Apples are on sale for $1.99 a pound. Sheila buys p pounds of apples for a total cost of c dollars.
Type below:
________________

Answer: c = p × $1.99

Explanation:
Apples are on sale for $1.99 a pound
p = pounds of apples
c = total cost of dollars
The equation would be:
c = p × $1.99
c is the independent variable.
p is the dependent variable.

On Your Own

Identify the independent and dependent variables. Then write an equation to represent the relationship between them.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 493 Q4

Question 5.
Billy has $25. His father is going to give him more money. The total amount t Billy will have is equal to the amount m his father gives him plus the $25 Billy already has.
Type below:
________________

Answer: t = m + $25

Explanation:
Billy has $25. His father is going to give him more money.
The total amount t Billy will have is equal to the amount m his father gives him plus the $25 Billy already has.
The equation would be:
t = m + $25
t is the independent variable
m is the dependent variable.

Question 6.
Connect Symbols and Words Describe a situation that can be represented by the equation c = 12b.
Type below:
________________

Answer:
Melinda is making necklaces. She uses 12 beads for each necklace. The total number of beads b depends on the cost of the necklace c.
The equation is c = 12n

Question 7.
Belinda pays $4.25 for each glass she buys. The total cost c is equal to the price per glass times the number of glasses n plus $9.95 for shipping and handling. Write an equation and use it to find how much it will cost Belinda to buy 12 glasses.
Type below:
________________

Answer:
Belinda pays $4.25 for each glass she buys. The total cost c is equal to the price per glass times the number of glasses n plus $9.95 for shipping and handling.

Belinda pays $4.25 for each glass she buys.
The equation is: c = 4.25n + 9.95
Now we have to find the cost of 12 glasses.
c = 4.25(12) + 9.95
c = 60.95
It takes $60.95 to buy 12 glasses.

Unlock the Problem – Page No. 494

Question 8.
Benji decides to save $15 per week to buy a computer program. Write an equation that models the total amount t in dollars Benji will have saved in w weeks.
a. What does the variable t represent?
Type below:
________________

Answer: t represents the total amount in dollars Banji saved.

Question 8.
b. Which is the dependent variable? Which is the independent variable? How do you know?
Type below:
________________

Answer:
w is the dependent variable.
t is the independent variable.
w is dependent because it represents the number of weeks. So, we have to multiply 15 by w.
t is an independent variable because t determines the value of a dependent variable.

Question 8.
c. How can you find the total amount saved in w weeks?
Type below:
________________

Answer: We can find the total amount saved in w weeks by multiplying 15 with w.

Question 8.
d. Write an equation for the total amount that Benji will have saved.
Type below:
________________

Answer: t = 15w

Question 9.
Coach Diaz is buying hats for the baseball team. The total cost c is equal to the number of hats n that he buys times the sum of the price per hat h and a $2 charge per hat to have the team name printed on it. Write an equation that can be used to find the cost of the hats.
Type below:
________________

Answer: c = n + 2h

Explanation:
Coach Diaz is buying hats for the baseball team.
The total cost c is equal to the number of hats n that he buys times the sum of the price per hat h and a $2 charge per hat to have the team name printed on it.
c represents the total cost.
n is the number of hats
h is the price per hat.
The equation is c is equal to the number of hats plus price per hat and $2.
c = n + 2h

Question 10.
A steel cable that is \(\frac{1}{2}\) inch in diameter weighs 0.42 pound per foot. The total weight in pounds w is equal to 0.42 times of the number of feet f of steel cable. Choose the letter or equation that makes each sentence true.
The independent variable is ______________ .
The dependent variable is ______________ .
The equation that represents the relationship between the variables is ______________ .

Answer:
A steel cable that is \(\frac{1}{2}\) inch in diameter weighs 0.42 pound per foot.
The total weight in pounds w is equal to 0.42 times of the number of feet f of steel cable.
The equation would be:
w = 0.2f
f is the dependent variable
w is the dependent variable.

Independent and Dependent Variables – Page No. 495

Identify the independent and dependent variables. Then write an equation to represent the relationship between them.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 495 Q1

Question 2.
An online clothing store charges $6 for shipping, no matter the price of the items. The total cost c in dollars is the price of the items ordered p plus $6 for shipping.
Type below:
________________

Answer: c = p + 6

Explanation:
Given,
An online clothing store charges $6 for shipping, no matter the price of the items.
The total cost c in dollars is the price of the items ordered p plus $6 for shipping.
The equation would be:
c = p + $6
where c = cost in dollars
p is the price of items
The independent variable is c.
The dependent variable is p

Question 3.
Melinda is making necklaces. She uses 12 beads for each necklace. The total number of beads b depends on the number of necklaces n.
Type below:
________________

Answer: b = 12n

Explanation:
Melinda is making necklaces. She uses 12 beads for each necklace.
The total number of beads b depends on the number of necklaces n.
b = total number of beads
n = number of necklaces
The equation would be:
b = 12n
b is the independent variable
n is the dependent variable.

Problem Solving

Question 4.
Maria earns $45 for every lawn that she mows. Her earnings e in dollars depend on the number of lawns n that she mows. Write an equation that represents this situation.
Type below:
________________

Answer: e = 45n

Explanation:
Maria earns $45 for every lawn that she mows.
Her earnings e in dollars depend on the number of lawns n that she mows.
e = earnings in dollars
n = number of lawns
The equation would be:
e = 45n
e is the independent variable.
n is the dependent variable.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 495 Q5

Question 6.
Write a situation in which one unknown is dependent on another unknown. Write an equation for your situation and identify the dependent and independent variables.
Type below:
________________

Answer:
Byron is playing a game. He earns 10 points for each question he answers correctly. His total score s equals the number of correct answers a time a.
Answer:
Dependent variable: s
Independent variable: a
Equation: s = 10a

Lesson Check – Page No. 496

Question 1.
There are 12 boys in a math class. The total number of students s depends on the number of girls in the class g. Write an equation that represents this situation.
Type below:
________________

Answer: s = 12 + g

Explanation:
There are 12 boys in a math class.
The total number of students s depends on the number of girls in class g.
The equation would be:
s = 12 + g
s is the independent variable.
g is the dependent variable.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 496 Q2

Spiral Review

Question 3.
The formula F = \(\frac{9}{5}\)C + 32 gives the Fahrenheit temperature for a Celsius temperature of C degrees. Gwen measured a Celsius temperature of 35 degrees. What is this temperature in degrees Fahrenheit?
______ °F

Answer: 95 degrees

Explanation:
The formula F = \(\frac{9}{5}\)C + 32 gives the Fahrenheit temperature for a Celsius temperature of C degrees.
C = 35
F = 9C ÷ 5 + 32
F = 9(35) ÷ 5 + 32
F = 315 ÷ 5 + 32
F = 63 + 32
F = 95 degrees

Question 4.
Write an equation to represent this sentence. The difference of a number n and 1.8 is 2.
Type below:
________________

Answer: n – 1.8 = 2

Explanation:
The difference of a number n and 1.8 is 2.
The phrase difference is nothing but subtraction.
The equation would be:
n – 1.8 = 2

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 496 Q5

Question 6.
Graph x ≤ 4.5 on a number line.
Type below:
________________

Answer:
GO Math Grade 6 Chapter 9 answer key img-1

Share and Show – Page No. 499

Use the equation to complete the table.

Question 1.
y = x + 3
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 1
Type below:
________________

Answer:
Substitute the value of x in the above equation.
The equation is x + 3.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-1

Question 2.
y = 2x + 1
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 2
Type below:
________________

Answer:
Substitute the value of x in the above equation.
The equation is y = 2x + 1
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-2

On Your Own

Write an equation for the relationship shown in the table. Then find the unknown value in the table.

Question 3.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 3
Type below:
________________

Answer:
The equation is y = 2x
The output is multiple of 2 and x
For x = 10
The output is y = 2x
y = 2 × 10 = 20

Question 4.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 4
Type below:
________________

Answer:
y = x ÷ 2
The output is the quotient of x and 2.
The output for x = 40 is
y = 40 ÷ 2
y = 20

Question 5.
The table shows the current cost of buying apps for a cell phone. Next month, the price of each app will double. Write an equation you can use to find the total cost y of buying x apps next month.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 5
Type below:
________________

Answer: y = 3x

Explanation:
The equation is multiple of 3 and x.
The equation is y = 3x

Question 6.
A beach resort charges $1.50 per hour plus $4.50 to rent a bicycle. The equation c = 1.50x + 4.50 gives the total cost c of renting a bicycle for x hours. Use numbers and words to explain how to find the cost c of renting a bicycle for 6 hours.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 6
Type below:
________________

Answer:
A beach resort charges $1.50 per hour plus $4.50 to rent a bicycle.
The equation c = 1.50x + 4.50 gives the total cost c of renting a bicycle for x hours.
For x = 1
c = 1.50(1) + 4.50
c = 1.50 + 4.50
c = $6.00
For x = 2
c = 1.50(2) + 4.50
c = 3.00 + 4.50
c = $7.50
For x = 3
c = 1.50(3) + 4.50
c = 4.50 + 4.50
c = $9.00
For x = 4
c = 1.50(4) + 4.50
c = 6.00 + 4.50
c = $10.50

</aCause and Effect – Page No. 500

The reading skill cause and effect can help you understand how a change in one variable may cause a change in another variable.

In karate, a person’s skill level is often shown by the color of his or her belt. At Sara’s karate school, students must pass a test to move from one belt level to the next. Each test costs $23. Sara hopes to move up 3 belt levels this year. How will this affect her karate expenses?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 7

Question 7.
Write an equation to show the relationship between cause and effect. Then use the equation to solve the problem.
Type below:
________________

Answer: y = 23x

Explanation:
Let x represent the number of belt levels Sara moves up and let y represent the increase in dollars in her karate expenses.
Write the equation:
y = 23x
Sara plans to move up 3 levels, so replace x with 3
y = 23 × 3
y = 69
So, if Sara moves up 3 belt levels this year, her karate expenses will increase by $69.

Write an equation to show the relationship between cause and effect. Then use the equation to solve the problem.

Question 8.
Classes at Tony’s karate school cost $29.50 per month. This year he plans to take 2 more months of classes than he did last year. How will this affect Tony’s karate expenses?
Type below:
________________

Answer:
The equation is y = 29.50x
where x is the number of additional classes
y is the increase in dollars in expenses.
Tony plans to take 2 more months of classes so his expenses will increase by y = 29.5 × 2 = $59

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 500 Q9

Equations and Tables – Page No. 501

Use the equation to complete the table.

Question 1.
y = 6x
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 8
Type below:
________________

Answer:
The equation is y = 6x
Substitute the value of x in the above equation.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-8

Question 2.
y = x − 7
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 9
Type below:
________________

Answer:
The equation is y = x – 7
Substitute the value of x in the equation.
Use the equation to get the output y.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-9

Question 3.
y = 3x + 4
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 10
Type below:
________________

Answer:
The equation is y = 3x + 4
Substitute the value of x in the above equation.
Use the equation to get the output y.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-10 (1)

Write an equation for the relationship shown in the table. Then find the unknown value in the table.

Question 4.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 11
Type below:
________________

Answer: y = 8x

Explanation:
The equation is the multiple of 8.
The equation is y = 8x
Substitute x = 3 in the equation.
y = 8(3) = 24
Thus the unknown value is 24.

Question 5.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 12
Type below:
________________

Answer: y = x ÷ 2

Explanation:
The equation is divisible by 2.
The equation is y = x ÷ 2
Substitute x = 22 in the equation.
y = x ÷ 2
y = 22 ÷ 2
y = 11
Therefore the unknown value is 11.

Problem Solving

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 501 Q6

Question 7.
Write an equation for the relationship shown in the table. Then use the equation to find the estimated number of shrimp in a 5-pound bag.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 13
Type below:
________________

Answer: y = 24x

Explanation:
The equation is the multiple of 24.
The equation is y = 24x

Question 8.
Write a word problem that can be represented by a table and equation. Solve your problem and include the table and equation.
Type below:
________________

Answer:
Susie ran a race. She ran 5 miles an hour and the race took her x hours to complete.
y = 5x
Use the equation to get the output y.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-10

Lesson Check – Page No. 502

Question 1.
Write an equation that represents the relationship shown in the table.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 14
Type below:
________________

Answer: y = x – 4

Explanation:
The relationship between x and y is y = x – 4.
We get the output when we subtract 4 from x.

Question 2.
There is a one-time fee of $27 to join a gym. The monthly cost of using the gym is $18. Write an equation for the relationship that gives the total cost y in dollars of joining the gym and using it for x months.
Type below:
________________

Answer: y = 18x + 27

Explanation:
Given,
There is a one-time fee of $27 to join a gym. The monthly cost of using the gym is $18.
Here y represents the total coast in dollars of joining the gym.
x represents months.
So, the equation would be: y = 18x + 27

Spiral Review

Question 3.
Mindy wants to buy several books that each cost $10. She has a coupon for $6 off her total cost. Write an expression to represent her total cost in dollars for b books.
Type below:
________________

Answer: 10b – 6

Explanation:
Given,
Mindy wants to buy several books that each cost $10.
She has a coupon for $6 off her total cost.
b represents the total cost in dollars for b books.
So, the equation to represent the total cost is 10b – 6.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 502 Q4
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 502 Q4.1

Question 5.
Which of the following are solutions to the inequality n > 7?
n = 7 n = 6.9 n = 7.2 n = 6\(\frac{1}{2}\)
Type below:
________________

Answer: n = -7

Explanation:
Substitute the value of n in the inequality.
n > 7
n = -7
-7 > -7
Thus -7 is the solution.
n = 6.9
-6.9 > -7
-6.9 is not the solution.
n = 7.2
-7.2 > -7
-7.2 is less than – 7
Thus -7.2 is not the solution.
n = 6\(\frac{1}{2}\)
6\(\frac{1}{2}\) > -7
6\(\frac{1}{2}\) is not the solution.

Question 6.
Marcus sold brownies at a bake sale. He sold d dollars worth of brownies. He spent $5.50 on materials, so his total profit p in dollars can be found by subtracting $5.50 from his earnings. Write an equation that represents this situation.
Type below:
________________

Answer: p = d – 5.50

Explanation:
Marcus sold brownies at a bake sale. He sold d dollars worth of brownies.
He spent $5.50 on materials, so his total profit p in dollars can be found by subtracting $5.50 from his earnings.
p represents the total profit in dollars.
d is the dollars worth of brownies.
The equation is p = d – 5.50

Share and Show – Page No. 505

Question 1.
A soccer coach is ordering shirts for the players. The table shows the total cost based on the number of shirts ordered. How much will it cost the coach to order 18 shirts?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 15
$ _______

Answer: 270

Explanation:
First, find a pattern and write an equation.
The cost is $15 multiplied by the number of shirts.
c = $15 × n
Next, use the equation to find the cost of 18 shirts.
c = $15 × n
c = $15 × 18
c = $270
So, the cost of 18 shirts is $270.

Question 2.
What if the coach spent $375 to purchase a number of shirts? Could you use the same equation to find how many shirts the coach bought? Explain.
Type below:
________________

Answer:
Yes, I could use the same equation.
I could substitute 375 for the variable c and solve for n.

Question 3.
The table shows the number of miles the Carter family drove over time. If the pattern continues, will the Carter family have driven more than 400 miles in 8 hours? Explain.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 16
Type below:
________________

Answer: 376 miles

Explanation:
First, find a pattern and write an equation.
The distance is 47 miles multiplied by the number of hours.
y = 47 × x
Next, use the equations to find the distance for 8 hours.
y = 47x
y = 47 × 8
y = 376
So, the family will have driven 376 miles in 8 hours, which is less than 400 miles.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 505 Q4

On Your Own – Page No. 506

Question 5.
A group of dancers practiced for 4 hours in March, 8 hours in April, 12 hours in May, and 16 hours in June. If the pattern continues, how many hours will they practice in November?
_______ hours

Answer: 36 hours

Explanation:
Given that, a group of dancers practiced for 4 hours in March, 8 hours in April, 12 hours in May, and 16 hours in June.
The equation would be h = 4m
m = 9
h = 4 × 9 = 36
Thus the group practiced 36 hours in the month of November.

Question 6.
The table shows the number of hours Jacob worked and the amount he earned each day.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 17
At the end of the week, he used his earnings to buy a new pair of skis. He had $218 left over. How much did the skis cost?
$ _______

Answer: 142

Explanation:
First, add the total amount he earned.
60 + 84 + 72 + 96 + 48 = 360
Jacob earned $360 for the week.
If he has $218 leftover, this means that the cost of the skis is 360 – 218 = 14
Therefore the cost of the skis is $142.

Question 7.
Pose a Problem Look back at Problem 6. Use the data in the table to write a new problem in which you could use the strategy to find a pattern. Then solve the problem.
Type below:
________________

Answer:
How much money would Jacob earn if he worked for 10 hours?
From the table, we can see that the pattern is that Jacob earns $12 per hour.
The equation is s = 12h
Where s is the total pay and h is the number of hours worked.
s = 12h
s = 12 × 10
s = 120
Thus Jacob earned $120 for 10 hours.

Question 8.
Draw Conclusions Marlon rode his bicycle 9 miles the first week, 18 miles the second week, and 27 miles the third week. If the pattern continues, will Marlon ride exactly 100 miles in a week at some point? Explain how you determined your answer.
Type below:
________________

Answer: No, Marlon will not ride exactly 100 miles in a week at some point.
Each number in the pattern is a multiple of 9 and 100 is not a multiple of 9.

Question 9.
A diving instructor ordered snorkels. The table shows the cost based on the number of snorkels ordered.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 18
If the diving instructor spent $1,024, how many snorkels did he order? Use numbers and words to explain your answer.
_______ snorkels

Answer: 32

Explanation:
Use the table to find the equation.
c represents the cost based on the number of snorkels.
s represents the number of snorkels
The equation would be:
c = 32s
The diving instructor spent $1,024
c = 1024
1024 = 32s
s = 1024/32
s = 32
Thus the diving instructor gets 32 snorkels for $1024.

Problem Solving Analyze Relationships – Page No. 507

The table shows the number of cups of yogurt needed to make different amounts of a fruit smoothie. Use the table for 1–3.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 19

Question 1.
Write an equation to represent the relationship.
Type below:
________________

Answer: c = 3b

Explanation:
c represents number of cups of yogurt
b represents the batches
From the table, we can observe that b is multiplied with 3 to get cups of yogurt.
So, the equation to find the number of cups of yogurt is c = 3b

Question 2.
How much yogurt is needed for 9 batches of smoothie?
_______ cups

Answer: 27

Explanation:
Given that there are 9 batches of smoothie.
By using the above equation we can find the number of cups.
c = 3b
c = 3 × 9 = 27 cups
Thus 27 cups of yogurt is need to make 9 batches of smoothie.

Question 3.
Jerry used 33 cups of yogurt to make smoothies. How many batches did he make?
_______ batches

Answer: 11 batches

Explanation:
Jerry used 33 cups of yogurt to make smoothies.
Use the equation to find the batches.
c = 3b
33 = 3b
b = 33/3
b = 11
Therefore jerry made 11 batches of smoothie.

The table shows the relationship between Winn’s age and his sister’s age. Use the table for 4–5.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 20

Question 4.
Write an equation to represent the relationship.
Type below:
________________

Answer: s = w + 4

Explanation:
By using the table we can find the relationship between wine’s age and wine’s sister’s age.
Winn’s sister’s age will be the sum of Winn’s age and 4.
So, the equation is s = w + 4

Question 5.
When Winn is 14 years old, how old will his sister be?
_______ years old

Answer: 18

Explanation:
Use the equation s = w + 4
W = 14 years
s = 14 + 4
s = 18 years
Thus winn’s sister’s age is 18 years.

Question 6.
Write a problem for the table. Use a pattern and an equation to solve your problem.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 21
Type below:
________________

Answer: m = 16h

Explanation:
Jerry runs 16 miles per hour. How many miles he can run in 5 hours?
The equation is m = 16h
m = 16 × 5 = 80 miles
Therefore jerry runs 80 miles in 5 hours.

Lesson Check – Page No. 508

Question 1.
The table shows the total cost c in dollars of n gift baskets. What will be the cost of 9 gift baskets?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 22

Answer: $108

Explanation:
By seeing the above we can say that the equation is
c = 12n
n = 9
Use the equation to find the cost of 9 gift baskets.
c = 12 × 9
c = $108
Thus the cost of 9 gift baskets is $108.

Question 2.
The table shows the number of minutes m that Tara has practiced after d days. If Tara has practiced for 70 minutes, how many days has she practiced?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 23
_______ days

Answer: 2 days

Explanation:
The table shows the number of minutes m that Tara has practiced after d days.
The equation would be
m = 35d
If Tara has practiced for 70 minutes
m = 70
Use the equation to find the number of days she practiced.
70 = 35d
d = 70/35
d = 2 days
Thus Tara has practiced 2 days.

Spiral Review

Question 3.
Soccer shirts cost $15 each, and soccer shorts cost $18 each. The expression 15n + 18n represents the total cost in dollars of n uniforms. Simplify the expression by combining like terms.
Type below:
________________

Answer: 33n

Explanation:
Soccer shirts cost $15 each, and soccer shorts cost $18 each.
The expression 15n + 18n represents the total cost in dollars of n uniforms.
Now combine the like terms.
15n + 18n = 33n

Question 4.
What is an equation that represents the relationship in the table?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 24
Type below:
________________

Answer: y = x ÷ 2

Explanation:
By seeing the above table we can find the relationship between x and y.
y is the quotient of x and 2.
We get the value of y when you divide x by 2.
The equation is y = x ÷ 2

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 508 Q5

Question 6.
Marisol plans to make 9 mini-sandwiches for every 2 people attending her party. Write a ratio that is equivalent to Marisol’s ratio.
Type below:
________________

Answer: 9:2

Explanation:
Given that, Marisol plans to make 9 mini-sandwiches for every 2 people attending her party.
The ratio will be 9:2
Now we need to write the equivalent ratio for the 9 sandwiches for every 2 people i.e, 9:2
We know that the equivalent ratio can be written as
9/2 × 3/3 = 27/6
9/2 × 5/5 = 45/6
Thus the equivalent fractions are 27/6 and 45/6.

Mid-Chapter Checkpoint – Vocabulary – Page No. 509

Choose the best term from the box to complete the sentence.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 25

Question 1.
A(n) _____ has a value that determines the value of another quantity.
Type below:
________________

Answer: Independent variable
An Independent variable has a value that determines the value of another quantity.

Question 2.
A variable whose value is determined by the value of another quantity is called a(n) _____.
Type below:
________________

Answer: Dependent variable
A variable whose value is determined by the value of another quantity is called a Dependent variable.

Concepts and Skills

Identify the independent and dependent variables.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 509 Q3

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 509 Q4

Write an equation for the relationship shown in the table. Then find the unknown value in the table.

Question 5.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 26
Type below:
________________

Answer: 49

Explanation:
The equation is y = 7x
x = 7
y = 7 × 7 = 49
Thus the unknown value y is 49.

Question 6.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 27
Type below:
________________

Answer: 12

Explanation:
The equation for the above table is
y = x ÷ 5
Use the equation to find the value of y where x = 60
y = 60 ÷ 5
y = 12
Thus the unknown value is 12.

Write an equation that describes the pattern shown in the table.

Question 7.
The table shows how the number of pepperoni slices used depends on the number of pizzas made.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 28
Type below:
_______________

Answer: y = 17x

Explanation:
The table shows how the number of pepperoni slices used depends on the number of pizzas made.
y is 17 times of x.
The equation for the above table is y = 17x

Question 8.
Brayden is training for a marathon. The table shows how the number of miles he runs depends on which week of training he is in.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 29
Type below:
________________

Answer: m = w + 5

Explanation:
Brayden is training for a marathon. The table shows how the number of miles he runs depends on which week of training he is in.
m is equal to the sum of w and 5.
Thus the equation is m = w + 5.

Page No. 510

Question 9.
The band has a total of 152 members. Some of the members are in the marching band, and the rest are in the concert band. Write an equation that models how many marching band members m there are if there are c concert band members.
Type below:
________________

Answer: m = 152 – c

Explanation:
Given,
The band has a total of 152 members. Some of the members are in the marching band, and the rest are in the concert band.
m is equal to the difference of 152 and c.
The equation is m = 152 – c

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 510 Q10

Question 11.
Amy volunteers at an animal shelter. She worked 10 hours in March, 12 hours in April, 14 hours in May, and 16 hours in June. If the pattern continues, how many hours will she work in December?
_______ hours

Answer: 28 hours

Explanation:
Amy volunteers at an animal shelter.
She worked 10 hours in March, 12 hours in April, 14 hours in May, and 16 hours in June.
As she started working from the march. December will be the 10th month.
Keep on adding 2 hours for each month you get 28 hours for December.
Thus she worked 28 hours in December.

Question 12.
Aaron wants to buy a new snowboard. The table shows the amount that he has saved. If the pattern in the table continues, how much will he have saved after 1 year?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 30
$ _______

Answer: $540

Explanation:
Aaron wants to buy a new snowboard. The table shows the amount that he has saved.
The equation will be s = 45m
s is the money saved
m is the number of months
1 year = 12 months
s = 45 × 12
s = 540
Thus he saved $540 after 1 year.

Share and Show – Page No. 513

Graph the relationship represented by the table.

Question 1.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 31
Type below:
________________

Answer: y = 50x
Go Math Grade 6 Chapter 9 answer key img-19

Question 2.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 32
Type below:
________________

Answer: y = 5x
Go Math Grade 6 Chapter 9 answer key img-20

Graph the relationship represented by the table to find the unknown value of y.

Question 3.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 33
Type below:
________________

Answer: 3
Go Math Grade 6 Chapter 9 answer key img-15

Question 4.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 34
Type below:
________________

Answer: 6
Go Math Grade 6 Chapter 9 answer key img-16

On Your Own

Practice: Copy and Solve Graph the relationship represented by the table to find the unknown value of y.

Question 5.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 35
Type below:
________________

Answer: 5
Go Math Grade 6 Chapter 9 answer key img-17

Question 6.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 36
Type below:
________________

Answer: 7
Go Math Grade 6 Chapter 9 answer key img-18

Problem Solving + Applications – Page No. 514

The table at the right shows the typical price of a popular brand of corn cereal over time. Use the table for 7–8.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 37

Question 7.
Use Graphs Complete the table below to show the cost of buying 1 to 5 boxes of corn cereal in 1988. Then graph the relationship on the coordinate plane at right.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 38
Type below:
________________

Answer:
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-38
Go Math Grade 6 Chapter 9 answer key img-26

Question 8.
Suppose you graphed the cost of buying 1 to 5 boxes of corn cereal using the 1968 price and the 2008 price. Explain how those graphs would compare to the graph you made using the 1988 price.
Type below:
________________

Answer:
The points on both graphs would lie on a line, but the line for the 1968 costs would rise less steeply than the line for 1988 costs and the line for the 2008 costs would rise more steeply than the line for 1988 costs.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 514 Q9

Question 10.
Graph the relationship represented by the table to find the unknown value of y.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 39
Type below:
________________

Answer: 3
Go Math Grade 6 Chapter 9 answer key img-25

Graph Relationships – Page No. 515

Graph the relationship represented by the table.

Question 1.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 40
Type below:
________________

Answer: y = 25x

Go Math Grade 6 Chapter 9 answer key img-10

Question 2.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 41
Type below:
________________

Answer:
Go Math Grade 6 Chapter 9 answer key img-11

Graph the relationship represented by the table to find the unknown value of y.

Question 3.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 42
Type below:
________________

Answer: 6

Go Math Grade 6 Chapter 9 answer key img-12

Question 4.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 43
Type below:
________________

Answer: 2

Go Math Grade 6 Chapter 9 answer key img-13

Problem Solving

Question 5.
Graph the relationship represented by the table.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 44
Type below:
________________

Answer: y = 15x

Go Math Grade 6 Chapter 9 answer key img-14

Question 6.
Use the graph to find the cost of purchasing 5 DVDs.
$ ______

Answer:
The above graph shows that the cost of 5 DVDs is $75.

Question 7.
Both tables and graphs can be used to represent relationships between two variables. Explain how tables and graphs are similar and how they are different.
Type below:
________________

Answer:
Tables and graphs can be useful tools for helping people make decisions. However, they only provide part of a story. Inferences often have to be made from the data shown. As well as being able to identify clearly what the graph or table is telling us, it is important to identify what parts of the story are missing.

Lesson Check – Page No. 516

Question 1.
Mei wants to graph the relationship represented by the table. Write an ordered pair that is a point on the graph of the relationship.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 45
Type below:
________________

Answer: y = 8x
Go Math Grade 6 Chapter 9 answer key img-27

Question 2.
An online bookstore charges $2 to ship any book. Cole graphs the relationship that gives the total cost y in dollars to buy and ship a book that costs x dollars. Name an ordered pair that is a point on the graph of the relationship.
Type below:
________________

Answer:
An online bookstore charges $2 to ship any book.
Cole graphs the relationship that gives the total cost y in dollars to buy and ship a book that costs x dollars.
y = x + 2
x = 4
y = 4 + 2
y = 6
The ordered pair is (4,6)

Spiral Review

Question 3.
Write an expression that is equivalent to 6(g + 4).
Type below:
________________

Answer:
6(g + 4)
6 × g + 6 × 4
6g + 24

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 516 Q4

Question 5.
Graph n > 2 on a number line.
Type below:
________________

Answer:
HMH Go Math Grade 6 Key Chapter 9 img-28

Question 6.
Sam is ordering lunch for the people in his office. The table shows the cost of lunch based on the number of people. How much will lunch cost for 35 people?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 46
$ _____

Answer: 280

Explanation:
Sam is ordering lunch for the people in his office.
The table shows the cost of lunch based on the number of people.
The equation is c = 8n
c = 8 × 35
c = 280
Thus the lunch cost for 35 people is $280.

Share and Show – Page No. 519

Graph the linear equation.

Question 1.
y = x + 2
Type below:
________________

Answer:
Go math grade 6 chapter 9 answer key img-28

Question 2.
y = 3x
Type below:
________________

Answer:
Go math grade 6 chapter 9 answer key img-29

Write the linear equation for the relationship shown by the graph.

Question 3.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 47
Type below:
________________

Answer: y = x – 1

Question 4.
Type below:
________________

On Your Own

Graph the linear equation.

Question 5.
y = x + 1
Type below:
________________

Answer:
Go math grade 6 chapter 9 answer key img-30

Question 6.
y = 2x − 1
Type below:
________________

Answer:
Go math grade 6 chapter 9 answer key img-31

Question 7.
Identify Relationships The graph shows the number of loaves of bread y that Kareem bakes in x hours. Write the linear equation for the relationship shown by the graph.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 48
Type below:
________________

Answer:
The ordered pairs are (1,1), (2,2), (4,4), (5,5)
Look for a pattern among the pairs: each y value is the same as the corresponding x-value.
The equation is y = x
y = x

Problem Solving + Applications – Page No. 520

The graph shows the growth of a bamboo plant. Use the graph for 8–9.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 49

Question 8.
Write a linear equation for the relationship shown by the graph. Use your equation to predict the height of the bamboo plant after 7 days.
Type below:
________________

Answer:
Write the ordered pairs from the graph: (1,50), (2,100), (3,150), (4,200), (5,250).
Look for a pattern among the pairs: each y value is 50 times the corresponding x value.
The equation is y = 50x
For x = 7, the solution is y = 50 × 7 = 350.
So, the height of the bamboo plant after 7 days will be 350 centimeters.

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 520 Q9

Question 10.
Maria graphed the linear equation y = x + 3. Then she used her ruler to draw a vertical line through the point (4, 0). At what point do the two lines intersect?
Type below:
________________

Answer:
y = x + 3
y = 4 + 0 = 4
y = 4 + 3 = 7
The coordinate is (4, 7)
Go math grade 6 chapter 9 answer key img-32

Question 11.
Antonio claims the linear equation for the relationship shown by the graph is y = \(\frac{1}{2}\)x + 2. Use numbers and words to support Antonio’s claim.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 50
Type below:
________________

Answer:
The ordered pairs (2,3) and (6,5) on the line make the equation.
y = \(\frac{1}{2}\)x + 2
y = 1/2 × 2 + 2
y = 1 + 2 = 3
y = 1/2 × 6 + 2
y = 3 + 2 = 5

Equations and Graphs – Page No. 521

Graph the linear equation.

Question 1.
y = x − 3
Type below:
________________

Answer:
Go Math Grade 6 Chapter 9 answer key img-22

Question 2.
y = x ÷ 3
Type below:
________________

Answer:
Go Math Grade 6 Chapter 9 answer key img-23

Write a linear equation for the relationship shown by the graph.

Question 3.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 51
Type below:
________________

Answer:
By seeing the above graph we can say that the equation is
y = x + 1

Question 4.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 52
Type below:
________________

Answer:
The ordered pairs are (1,4), (1.5,6), (2,8)
By seeing the above pairs we can say that the equation is y = 4x

Problem Solving

Question 5.
Dee is driving at an average speed of 50 miles per hour. Write a linear equation for the relationship that gives the distance y in miles that Dee drives in x hours.
Type below:
________________

Answer: y = 50x

Explanation:
Dee is driving at an average speed of 50 miles per hour.
y represents the distance in miles
x is the number of hours.
y is equal to the product of 50 and x.
y = 50x

Question 6.
Graph the relationship from Exercise 5.
Type below:
________________

Answer:
Go Math Grade 6 Chapter 9 answer key img-24

Question 7.
Explain how to write a linear equation for a line on a graph.
Type below:
________________

Answer:
To write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope.

Lesson Check – Page No. 522

Question 1.
A balloon rises at a rate of 10 feet per second. What is the linear equation for the relationship that gives the height y in feet of the balloon after x seconds?
Type below:
________________

Answer: The linear equation for the relationship is y = 10x

Question 2.
Write the linear equation that is shown by the graph.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 53
Type below:
________________

Answer:
Write the ordered pairs from the graph: (3,3), (5,5), (8,8)
Look for a pattern among the pairs: each y value is the same as the corresponding x-value.
The equation is y = x

Spiral Review

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 522 Q3

Question 4.
Which of the following are solutions of j ≥ 0.6?
j = 1      j = 0.6       j = \(\frac{3}{5}\)       j = 0.12        j = 0.08
Type below:
________________

Answer: j = \(\frac{3}{5}\)

Explanation:
Substitute the values of j in the inequality.
j = 1
1 ≥ 0.6
1 is greater than 0.6 but not equal.
Thus 1 is not the solution of j ≥ 0.6.
j = 0.6
-0.6 ≥ 0.6
-0.6 is less than 0.6
Thus -0.6 is not the solution of j ≥ 0.6.
j = \(\frac{3}{5}\)
\(\frac{3}{5}\) ≥ 0.6
\(\frac{3}{5}\) = 0.6
0.6 ≥ 0.6
Thus \(\frac{3}{5}\) is the solution.
j = 0.12
0.12 ≥ 0.6
0.12 is less than 0.6.
Thus 0.12 is not the solution of j ≥ 0.6.
j = 0.08
0.08 ≥ 0.6
0.08 is less than 0.6.
Thus 0.08 is not the solution of j ≥ 0.6.

Question 5.
Red grapes cost $2.49 per pound. Write an equation that shows the relationship between the cost c in dollars and the number of pounds of grapes p.
Type below:
________________

Answer: c = 2.49p

Explanation:
Given,
Red grapes cost $2.49 per pound.
c is the cost in dollars.
p is the number of pounds of grapes.
The equation c is equal to the product of the number of pounds of grapes and $2.49
c = 2.49p

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 522 Q6

Chapter 9 Review/Test – Page No. 523

Question 1.
A box of peanut butter crackers contains 12 individual snacks. The total number of individual snacks s is equal to 12 times the number of boxes of crackers b.
The independent variable is _____.
The dependent variable is _____.
The equation that represents the relationship between the variables is _____.

Answer:
The independent variable is b.
The dependent variable is s.
The equation that represents the relationship between the variables is s = 12b.

Question 2.
A stationery store charges $8 to print logos on paper purchases. The total cost c is the price of the paper p plus $8 for printing the logo.
For numbers 2a–2d, select True or False for each statement.
2a. The total cost c depends on the price of the paper.
2b. c is the dependent variable.
2c. p is the independent variable.
2d. The equation that represents the relationship between the variables is c = 8p.
2a. ____________
2b. ____________
2c. ____________
2d. ____________

Answer:
2a. True
2b. True
2c. True
2d. False

Explanation:
2a. c represents the relationship between the two quantities.
So, the statement “The total cost c depends on the price of the paper” is true.
2b. c is the total cost so the statement “c is the dependent variable” is true.
2c. p represents the price to print logos
So, the statement “p is the independent variable” is true.
2d. The total cost c is the price of the paper p plus $8 for printing the logo.
The equation would be:
c = 8 + p
Thus the statement “The equation that represents the relationship between the variables is c = 8p” is false.

Question 3.
An electrician charges $75 an hour for labor and an initial fee of $65. The total cost c equals 75 times the number of hours x plus 65. Write an equation for the relationship and use the equation to complete the table.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 54
Type below:
________________

Answer: c = 75x + 65
Substitute the value of x in the equation.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-54

Page No. 524

Question 4.
The community center offers classes in arts and crafts. There is a registration fee of $125 and each class costs $79. The total cost c in dollars equals 79 times the number of classes n plus 125.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 55
For numbers 4a–4d, select True or False for each statement.
4a. The registration fee is $120.
4b. n is the independent variable.
4c. c is the dependent variable.
4d. The cost for 7 classes is $678.
4a. ____________
4b. ____________
4c. ____________
4d. ____________

Answer:
4a. False
4b. True
4c. True
4d. True

Explanation:
4a. The registration fee is $120.
The registration fee is $125, not $120.
So, the statement is false.
4b. n is the independent variable.
n represents the number of classes.
The statement is true.
4c. c is the dependent variable.
c depends on the registration fee.
Thus the statement is true.
4d. The cost for 7 classes is $678
79 × 7 + 125 = $678
Thus the statement is true.

Question 5.
Ms. Walsh is buying calculators for her class. The table shows the total cost based on the number of calculators purchased.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 56
If Ms. Walsh spent a total of $525, how many calculators did she buy? Use numbers and words to explain your answer.
Type below:
________________

Answer:
She bought 35 calculators. I found a pattern and wrote the equation c = 15n.
Since I know that Mrs.Walsh spent a total of $525, I can substitute 525 for c and solve for n
525 = 15n
n = 35

Chapter 9 Review/Test – Page No. 525

Question 6.
The table shows the number of cups of lemonade that can be made from cups of lemon juice.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 57
Mary Beth says the number of cups of lemon juice j depends on the number of cups of lemonade l. She says the equation j = 7l represents the relationship between the cups of lemon juice j and the cups of lemonade l. Is Mary Beth correct? Use words and numbers to explain why or why not.
Type below:
________________

Answer:
Mary Beth is not correct. The number of cups of lemonade l depends on the number of cups of lemon juice j.
So l is the dependent variable and j is the independent variable.
The equation showing the relationship is l = 7j

Question 7.
For numbers 7a–7d, choose Yes or No to indicate whether the points, when graphed, would lie on the same line.
7a. (1, 6), (2, 4), (3, 2), (4, 0)
7b. (1, 1), (2, 4), (3, 9), (4, 16)
7c. (1, 3), (2, 5), (3, 7), (4, 9)
7d. (1, 8), (2, 10), (3, 12), (4, 14)
7a. ____________
7b. ____________
7c. ____________
7d. ____________

Answer:
7a. Yes
Go Math Grade 6 Chapter 9 answer key img-2
7b. No
Go Math Grade 6 Chapter 9 answer key img-3
7c. Yes
Go Math Grade 6 Chapter 9 answer key img-4
7d. Yes
Go Math Grade 6 Chapter 9 answer key img-5

Question 8.
Graph the relationship represented by the table to find the unknown value.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 58
Type below:
________________

Answer: 10

Go Math Grade 6 Chapter 9 answer key img-6

Chapter 9 Review/Test – Page No. 526

Question 9.
Graph the relationship represented by the table.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 59
Type below:
________________

Answer:
Go Math Grade 6 Chapter 9 answer key img-7

Question 10.
Miranda’s wages are $15 per hour. Write a linear equation that gives the wages w in dollars that Miranda earns in h hours.
Type below:
________________

Answer: w = 15h
Go Math Grade 6 Chapter 9 answer key img-8

Question 11.
The table shows the number of miles m that Lucinda could walk in h hours.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 60
Graph the relationship between hours h and miles m. Then write the equation that shows the relationship.
Type below:
________________

Answer: m = 4h
Go Math Grade 6 Chapter 9 answer key img-9

Chapter 9 Review/Test – Page No. 527

Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables Page 527 Q12

Question 13.
Lacy is staying at a hotel that costs $85 per night. The total cost c in dollars of Lacy’s stay is 85 times the number of nights n she stays.
For numbers, 13a–13d, select True or False for each statement.
13a. The number of nights n is dependent on the cost c.
13b. n is the independent variable.
13c. c is the dependent variable.
13d. The equation that represents the total cost is c = 85n.
13a. ____________
13b. ____________
13c. ____________
13d. ____________

Answer:
13a. False
13b. True
13c. True
13d. True

Explanation:
13a. The number of nights n is dependent on the cost c.
n is independent on the cost c.
So, the statement is false.
13b. n is the independent variable.
The statement is true.
13c. c is the dependent variable.
c is dependent because it depends on the cost c.
So, the statement is true.
13d. The equation that represents the total cost is c = 85n.
The equation is true.

Question 14.
A taxi cab company charges an initial fee of $5 and then $4 per mile for a ride. Use the equation c = 4x + 5 to complete the table.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 61
Type below:
________________

Answer:
Substitute the value of x in the equation.
We get,
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-61

Chapter 9 Review/Test – Page No. 528

Question 15.
A grocery display of cans is arranged in the form of a pyramid with 1 can in the top row, 3 in the second row from the top, 5 in the third row, and 7 in the fourth row. The total number of cans c equals 2 times the row r minus 1. Use the equation c = 2r − 1 to complete the table.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 62
Type below:
________________

Answer:
A grocery display of cans is arranged in the form of a pyramid with 1 can in the top row, 3 in the second row from the top, 5 in the third row, and 7 in the fourth row.
c = 2r − 1
Substitute r in the equation.
Go-Math-Grade-6-Answer-Key-Chapter-9-Independent-and-Dependent-Variables-img-62

Question 16.
The graph shows the number of words Mason read in a given amount of minutes. If Mason continues to read at the same rate, how many words will he have read in 5 minutes?
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 63
______ words

Answer: 1000 words
By seeing the above graph we can say that Mason can read 1000 words in 5 minutes.

Question 17.
Casey claims the linear equation for the relationship shown by the graph is c = 25j. Use numbers and words to support Casey’s claim.
Go Math Grade 6 Answer Key Chapter 9 Independent and Dependent Variables img 64
Type below:
________________

Answer: The ordered pairs (1,25), (3,75), (5,125) and (7,175) each make the equation c = 25j

Conclusion:

I wish the details prevailed in the Go Math Grade 6 Answer Key Chapter 9 is helpful for you. Share this pdf link with your friends and help them to overcome the difficulties. If you have any doubts regarding the solutions you can leave a comment in the comment section.

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Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures will make understanding concepts of Two-Dimensional Figures so easy. So following the Go Math HMH 4th Grade Chapter 10 Solution Key is very necessary to get notified of the topics of Two-dimensional shapes. Go Math Grade 4 Answer Key has specialized solutions to all the questions that are covered in extra practice FL, Homework Practice FL. So it’ll be easy for you to understand the concepts behind each and every lesson.

Go Math Grade 4 Chapter 10 Two-Dimensional Figures Answer Key

The questions asked in Chapter Tests, Practice Tests, Performance Tests, etc. are also covered by the Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures PDF. So that you can cross-check Go Math Grade 4 Chapter 10 Two-Dimensional Figures Solution Key PDF. For more practice questions simply go to the Go Math Grade 4 Solution Key Chapter 10 Two-Dimensional Figures Homework Practice FL Page on our site.

Lesson 1: Lines, Rays, and Angles

Lesson 1: Lines, Rays, and Angles

Lesson 2: Classify Triangles by Angles

Lesson 3: Parallel Lines and Perpendicular Lines

Lesson 3: Parallel Lines and Perpendicular Lines

Lesson 4: Classify Quadrilaterals

Mid-Chapter Checkpoint

Lesson 5: Line Symmetry

Lesson 6: Find and Draw Lines of Symmetry

Lesson 6: Find and Draw Lines of Symmetry

Lesson 7: Problem Solving • Shape Patterns

Review/Test

Common Core – New – Page No. 553

Lines, Rays, and Angles

Draw and label an example of the figure.

Question 1.
obtuse ∠ABC
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 1
Think: An obtuse angle is greater than a right angle. The middle letter, B, names the vertex of the angle.
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 553

Explanation:
An obtuse angle is greater than a right angle. The middle letter, B, names the vertex of the angle.

Question 2.
\(\overrightarrow{G H}\)
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 2 553

Explanation:
GH is a ray that has one endpoint and continues without an end in one direction.

Question 3.
acute ∠JKL
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 3 553

Explanation:
Angle JKL is an acute angle that is less than a right angle.

Question 4.
\(\overline{B C}\)

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 4 553

Explanation:
BC is a line that continues without an end in both directions.

Use the figure for 5–8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 2

Question 5.
Name a line segment.

Answer:
line segment EF

Explanation:

EF line is a straight path of points that continues without an end in both directions.

Question 6.
Name a right angle.
∠ _____

Answer:
∠EJF

Explanation:
EJF is a right angle that forms a square corner.

Question 7.
Name an obtuse angle.
obtuse ∠ _____

Answer:
∠CEJ

Explanation:
CEJ is an obtuse angle that is greater than a right angle.

Question 8.
Name a ray.

Answer:
Ray JD

Explanation:
JD is a ray that has one endpoint and continues without an end in one direction.

Problem Solving

Use the figure at the right for 9–11.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 3

Question 9.
Classify ∠AFD
_________

Answer:
Obtuse Angle

Explanation:
AFD is an obtuse angle that is greater than a right angle.

Question 10.
Classify ∠CFE.
_________

Answer:
Right Angle

Explanation:
∠CFE is a right angle that forms a square corner.

Question 11.
Name two acute angles.
acute ∠ _____ acute ∠ _____

Answer:
∠AFB and ∠DFE

Explanation:
∠AFB and ∠DFE are two acute angles with less than a right angle.

Common Core – New – Page No. 554

Lesson Check

Question 1.
The hands of a clock show the time 12:25.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 4
Which best describes the angle between the hands of the clock?
Options:
a. acute
b. right
c. obtuse
d. straight

Answer:
c. obtuse

Explanation:
The hands of the time 12:25 are forming at greater than a right angle. So, the answer is the Obtuse angle.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 554 Q2

Spiral Review

Question 3.
Jan’s pencil is 8.5 cm long. Ted’s pencil is longer. Which could be the length of Ted’s pencil?
Options:
a. 0.09 cm
b. 0.8 cm
c. 8.4 cm
d. 9.0 cm

Answer:
d. 9.0 cm

Explanation:
9 ones is greater than 8 ones. So, 9.0 cm > 8.5 cm

Question 4.
Kayla buys a shirt for $8.19. She pays with a $10 bill. How much change should she receive?
Options:
a. $1.81
b. $1.89
c. $2.19
d. $2.81

Answer:
a. $1.81

Explanation:
Kayla buys a shirt for $8.19. She pays with a $10 bill. To find the change she received, $10 – $8.19 = 1.81

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 554 Q5

Question 6.
Jose jumped 8 \(\frac{1}{3}\) feet. This was 2 \(\frac{2}{3}\) feet farther than Lila jumped. How far did Lila jump?
Options:
a. 5 \(\frac{1}{3}\)
b. 5 \(\frac{2}{3}\)
c. 6 \(\frac{1}{3}\)
d. 11

Answer:
b. 5 \(\frac{2}{3}\)

Explanation:
Jose jumped 8 \(\frac{1}{3}\) feet. This was 2 \(\frac{2}{3}\) feet farther than Lila jumped.
8 \(\frac{1}{3}\) – 2 \(\frac{2}{3}\) = \(\frac{25}{3}\) – \(\frac{8}{3}\) = \(\frac{7}{3}\) = 5 \(\frac{2}{3}\)

Page No. 557

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 557 Q1
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 557 Q1.1

Classify each triangle. Write acute, right, or obtuse.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 6
_____

Answer:

Obtuse triangle;
Angle B and Angle C are both acute.
Angle A is obtuse.

Explanation:
From triangle ABC, Angle B, and Angle C are both acute with less than a right angle. Angle A is obtuse angle that is greater than a right angle.

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 7
_____

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 2 557
Obtuse triangle;
Angle A and Angle C are both acute.
Angle B is obtuse.

Explanation:
From triangle ABC, Angle A, and Angle C are both acute with less than a right angle. Angle B is an obtuse angle that is greater than a right angle. A triangle with an obtuse angle is called an obtuse triangle.

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 8
_____

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 3 557
Acute triangle;
Angle A, Angle B, and Angle C are acute angles.

Explanation:
From triangle ABC, Angle A, Angle B, and Angle C are acute angles with less than a right angle. A triangle with three acute angles called an acute triangle. So, the given triangle is an acute triangle.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 557 Q5

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 10
_____

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 5 557
Acute triangle;
Angle A, Angle B, and Angle C are acute angles.

Explanation:
From triangle ABC, Angle A, Angle B, and Angle C are acute angles with less than a right angle. A triangle with three acute angles called an acute triangle. So, the given triangle is an acute triangle.

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 11
_____

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 6 557
Right Triangle;
∠A and ∠C are acute angles.
∠B is Right angle

Explanation:
∠A and ∠C are acute angles with less than a right angle. ∠B is the Right angle that forms a square corner. A triangle that has one right angle is called a right triangle.

Question 8.
Cross out the figure that does not belong. Explain.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 12
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 7 557
Explanation:
From the given image, 1, 3, and 4 have two acute angles, and one obtuse angle. 2 have three acute angles.

Page No. 558

Use the Venn diagram for 9–10.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 13

Question 9.
Which triangles do NOT have an obtuse angle? Explain.
_______ triangles

Answer:
4 triangles;
Triangle DEF, Triangle SPN, Triangle ABC, and Triangle GHP are don’t have an obtuse angle. Triangle DEF, Triangle SPN are acute angles. An acute triangle is a triangle with three acute angles. Triangle ABC, and Triangle GHP are right angles. A right triangle is a triangle with one right angle. The sum of the triangle is 180 degrees. A right triangle has 90 degrees. So, the remaining angles must be acute angles.

Question 10.
How many triangles have at least two acute angles? Explain.
_______ triangles

Answer:
4 triangles;
Triangle DEF, Triangle SPN, Triangle ABC, and Triangle GHP at least two acute angles. Triangle DEF, Triangle SPN are acute angles. An acute triangle is a triangle with three acute angles. Triangle ABC, and Triangle GHP are right angles. A right triangle is a triangle with one right angle and two acute angles.

Question 11.
Use the square shown at the right. Draw a line segment from point M to point P. Name and classify the triangles formed by the line segment.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 14
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 8 557
Angle MNP and Angle MQP

Explanation:
The line segment from M to P forms Angle MNP and Angle MQP.

Question 12.
Write the letter of the triangle under its correct classification.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 15
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 9 557

Explanation:
Triangle A and triangle B have three acute angles. So, they are acute triangles. Triangle D and triangle F have one obtuse angle. So, they are obtuse triangles.
Triangle C and triangle E have one right angle. So, they are right triangles.

Common Core – New – Page No. 559

Classify Triangles

Classify each triangle. Write acute, right, or obtuse.

Question 1.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 16
Think: Angles A and C are both acute.
Angle B is obtuse.

Answer:
Obtuse triangle;
Angle A and Angle C are both acute.
Angle B is obtuse.

Explanation:
From triangle ABC, Angle A, and Angle C are both acute with less than a right angle. Angle B is an obtuse angle that is greater than a right angle.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 559 Q2

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 559 Q3

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 19
_________

Answer:
Obtuse triangle;
Angle L and Angle N are both acute.
Angle M is obtuse.

Explanation:
From triangle LMN, Angle L and Angle N are both acute with less than a right angle. Angle M is an obtuse angle that is greater than a right angle. A triangle with an obtuse angle is called an obtuse triangle.

Problem Solving

Question 5.
Use figure ABCD below. Draw a line segment from point B to point D. Name and classify the triangles formed.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 20
Two _________ triangles
△ _________
△ _________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 559
Two Acute triangles.
△ ABD
△ BCD

Explanation:
If we draw a line segment from point B to point D, then there are two traingles formed with less than right angles. They are △ ABD and △ BCD.

Question 6.
Use figure ABCD below. Draw a line segment from point A to point C. Name and classify the triangles formed.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 21
Two _________ triangles
△ _________
△ _________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 2 559
Two Acute triangles.
△ ABC
△ ADC

Explanation:
If we draw a line segment from point A to point C, then there are two traingles formed with less than right angles. They are △ ABC and △ ADC.

Common Core – New – Page No. 560

Lesson Check

Question 1.
Stephen drew this triangle. How many obtuse angles does the triangle have?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 22
Options:
a. 0
b. 1
c. 2
d. 3

Answer:
a. 0

Explanation:
The given image has three acute angles. So, there are 0 obtuse angles.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 560 Q2

Spiral Review

Question 3.
Oliver drew the figure below to show light traveling from the sun to Earth. Name the figure he drew.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 23
Options:
a. segment SE
b. ray SE
c. line SE
d. ray ES

Answer:
b. ray SE

Explanation:
SE is a ray that has one endpoint and continues without an end in one direction.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 560 Q4

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 560 Q5

Question 6.
A basketball team averaged 105 points per game. How many points did the team score in 6 games?
Options:
a. 605 points
b. 630 points
c. 900 points
d. 6,030 points

Answer:
b. 630 points

Explanation:
A basketball team averaged 105 points per game.
They score in 6 games = 6 x 105 = 630 points.

Page No. 563

Question 1.
Draw and label \(\overline{Q R} \| \overline{S T}\).
Think: Parallel lines never intersect. Parallel line segments are parts of parallel lines.
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 563
\(\overline{Q R} \| \overline{S T}\)

Explanation:
Parallel lines never intersect. Parallel line segments are parts of parallel lines.

Use the figure for 2 and 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 24

Question 2.
Name two line segments that appear to be parallel.
Type below:
_________

Answer:
Line Segment CB and Line Segment DF.

Explanation:
Line Segment CB and Line Segment DF are parallel lines. The both lines never intersect and are always the same distance apart.

Question 3.
Name two line segments that appear to be perpendicular.
Type below:
_________

Answer:
Line Segment CB and Line Segment BF are perpendicular lines.

Explanation:
Line Segment CB and Line Segment DF are perpendicular lines. Both lines intersect to form four right angles.

Use the figure for 4–5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 25

Question 4.
Name a pair of lines that are perpendicular.
Type below:
_________

Answer:
FJ and HG are perpendicular lines.

Explanation:
FJ and HG lines intersect each other and form four right angles.

Question 5.
Name a pair of lines that appear to be parallel.
Type below:
_________

Answer:
DC and FJ are parallel lines.

Explanation:
DC and FJ are never intersected and are always the same distance apart.

Question 6.
\(\overline{R S} \| \overline{T U}\)
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 3 559
\(\overline{R S} \| \overline{T U}\)

Explanation:
Parallel lines never intersect. Parallel line segments are parts of parallel lines.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 563 Q7

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 563 Q8

Question 9.
\(\overset { \longleftrightarrow }{ JK } \) ⊥ \(\overset { \longleftrightarrow }{ LM } \)
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 5 559
\(\overset { \longleftrightarrow }{ JK } \) ⊥ \(\overset { \longleftrightarrow }{ LM } \)

Explanation:
JK and LM are two lines that intersected each other to form right angles.

Question 10.
\(\overset { \longleftrightarrow }{ ST } \) intersecting \(\overset { \longleftrightarrow }{ UV } \) at point X
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 7 559

Explanation:
ST and UV are two lines intersecting at point X.

Question 11.
\(\overset { \longleftrightarrow }{ AB } \) || \(\overset { \longleftrightarrow }{ FG } \)
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 8 559
\(\overset { \longleftrightarrow }{ AB } \) || \(\overset { \longleftrightarrow }{ FG } \)

Explanation:
Parallel lines never intersect. Parallel line segments are parts of parallel lines.

Use the figure for 12–13.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 26

Question 12.
Dan says that \(\overset { \longleftrightarrow }{ HL } \) is parallel to \(\overset { \longleftrightarrow }{ IM } \). Is Dan correct? Explain.
_____

Answer:
No; HL and IM are not parallel lines. Parallel lines are always the same distance apart. But from the given image, the H and I may intersect if the line is extended.

Question 13.
Name two intersecting line segments that are not perpendicular.
Type below:
_________

Answer:
JM and KG are two intersecting line segments and are also not perpendicular.

Page No. 564

Use the house plan at the right for 14–16.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 27

Question 14.
What geometric term describes a corner of the living room?
_________

Answer:
The corner of the living room is a vertex. Corners of any shape are vertexes.

Question 15.
Name three parts of the plan that show line segments.
_________

Answer:
Kitchen, Living Room, and Master Bedroom.

Question 16.
Name a pair of line segments that appear to be parallel
_________

Answer:
Two sidelines of Living Room are parallel.
Two sidelines of Master Bedroom are parallel.

Use the map at the right for 17–19.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 28

Question 17.
Name a street that appears to be parallel to S 17th Street.
_________

Answer:
S 18th Street

Explanation:
S 18th Street is parallel to S 17th Street. They never meet each other and are always the same distance apart.

Question 18.
Use Diagrams Name a street that appears to be parallel to Vernon Street.
_________

Answer:
Perry Street

Explanation:
Perry Street is parallel to Vernon Street. They never meet each other and are always the same distance apart.

Question 19.
Name a street that appears to be perpendicular to S 19th Street.
_________

Answer:
Austin Street

Explanation:
Austin Street is perpendicular to S 19th Street. They are intersect with each other and form four right angles.

Question 20.
Choose the labels to make a true statement.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 29
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 30
Type below:
_________

Answer:
Line AB is perpendicular to Line EF.

Common Core – New – Page No. 565

Parallel Lines and Perpendicular Lines

Use the figure for 1–3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 31

Question 1.
Name a pair of lines that appear to be perpendicular.
Think: Perpendicular lines form right angles.
\(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ EF } \) appear to form right angles.
\(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ EF } \)

Answer:
\(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ EF } \)

Explanation:
Perpendicular lines form right angles.
\(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ EF } \) appear to form right angles.
\(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ EF } \)

Question 2.
Name a pair of lines that appear to be parallel.
_____ and _____

Answer:
\(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ CD} \)

Explanation:
Parallel lines never interest each other. \(\overset { \longleftrightarrow }{ AB } \) and \(\overset { \longleftrightarrow }{ CD} \) are parallel lines.

Question 3.
Name another pair of lines that appear to be perpendicular.
_____ and _____

Answer:
\(\overset { \longleftrightarrow }{ CD } \) and \(\overset { \longleftrightarrow }{ EF } \)

Explanation:
Perpendicular lines form right angles.
\(\overset { \longleftrightarrow }{ CD } \) and \(\overset { \longleftrightarrow }{ EF } \) appear to form right angles.
\(\overset { \longleftrightarrow }{ CD } \) and \(\overset { \longleftrightarrow }{ EF } \)

Draw and label the figure described.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 565 Q4

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 565 Q5

Question 6.
\(\overset { \longleftrightarrow }{ FH } \) ⊥ \(\overset { \longleftrightarrow }{ JK } \)

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 3 565

Explanation:
FH and JK are two lines that intersect each other to form four right angles.

Problem Solving

Use the street map for 7–8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 32

Question 7.
Name two streets that intersect but do not appear to be perpendicular.
Type below:
_________

Answer:
Maple and Oak or Oak and Birch

Explanation:
Maple and Oak or Oak and Birch; They are intersecting with each other and not perpendicular.

Question 8.
Name two streets that appear to be parallel to each other.
Type below:
_________

Answer:
Maple and Birch

Explanation:
Maple and Birch are streets and do not intersect with each other. They appear to be parallel to each other.

Common Core – New – Page No. 566

Lesson Check

Question 1.
Which capital letter appears to have perpendicular line segments?
Options:
a. N
b. O
c. T
d. V

Answer:
c. T

Explanation:
T has two lines and is interesting to form four right angles.

Question 2.
In the figure, which pair of line segments appear to be parallel?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 33
Options:
a. \(\overline{F G} \text { and } \overline{G H}\)
b. \(\overline{F J} \text { and } \overline{G H}\)
c. \(\overline{F G} \text { and } \overline{J H}\)
d. \(\overline{J H} \text { and } \overline{F J}\)

Answer:
c. \(\overline{F G} \text { and } \overline{J H}\)

Explanation:
\(\overline{F G} \text { and } \overline{J H}\) are parallel lines that never intersect

Spiral Review

Question 3.
Nolan drew a right triangle. How many acute angles did he draw?
Options:
a. 0
b. 1
c. 2
d. 3

Answer:
c. 2

Explanation:
A triangle with one right angle will have two acute angles.

Question 4.
Mike drank more than half the juice in his glass. What fraction of the juice could Mike have drunk?
Options:
a. \(\frac{1}{3}\)
b. \(\frac{2}{5}\)
c. \(\frac{3}{6}\)
d. \(\frac{5}{8}\)

Answer:
d. \(\frac{5}{8}\)

Explanation:
Mike drank more than half the juice in his glass. He drunk \(\frac{5}{8}\) of the juice.

Question 5.
A school principal ordered 1,000 pencils. He gave an equal number to each of 7 teachers until he had given out as many as possible. How many pencils were left?
Options:
a. 2
b. 4
c. 6
d. 142

Answer:
c. 6

Explanation:
A school principal ordered 1,000 pencils. He gave an equal number to each of 7 teachers until he had given out as many as possible. He shared 142 pencils for each of 7 teachers. So, 142 X 7 = 994. The remaining pencils are 6.

Question 6.
A carton of juice contains 64 ounces. Ms. Wilson bought 6 cartons of juice. How many ounces of juice did she buy?
Options:
a. 364 ounces
b. 370 ounces
c. 384 ounces
d. 402 ounces

Answer:
c. 384 ounces

Explanation:
A carton of juice contains 64 ounces. Ms. Wilson bought 6 cartons of juice. 64 X 6 = 384 ounces of juice she can buy.

Page No. 569

Question 1.
Tell whether the quadrilateral is also a trapezoid, parallelogram, rhombus, rectangle, or square.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 34
Think:
____ pairs of parallel sides
____ sides of equal length
____ right angles
Quadrilateral ABCD is also a __________
__________

Answer:
2 pairs of parallel sides
4 sides of equal length
0 right angles.
Quadrilateral ABCD is also a Rhombus

Explanation:
A Rhombus is a quadrilateral that has 2 pairs of parallel sides and 4 sides of equal lengths.

Classify each figure as many ways as possible. Write quadrilateral, trapezoid, parallelogram, rhombus, rectangle, or square.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 569 Q2

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 569 Q3

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 37
_________
_________
_________

Answer:
Quadrilateral, Parallelogram, and Rhombus

Explanation:
2 pairs of parallel sides
4 sides of equal length
0 right angles.
Given quadrilateral is Rhombus and Parallelogram.
A Rhombus is a quadrilateral that has 2 pairs of parallel sides and 4 sides of equal lengths, and 0 right angles.

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 38
_________
_________

Answer:
Quadrilateral and Parallelogram

Explanation:
2 pairs of parallel sides
2 pairs of sides of equal length
0 right angles.
Given quadrilateral is Parallelogram.
A Parallelogram is a quadrilateral that has 2 pairs of parallel sides and 2 pairs of sides of equal lengths, and 0 right angles.

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 39
_________
_________
_________

Answer:
Quadrilateral and Square

Explanation:
2 pairs of parallel sides
4 sides of equal length
4 right angles.
Given quadrilateral is Square.
A Square is a quadrilateral that has 2 pairs of parallel sides and 4 sides of equal lengths, and 4 right angles.

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 40
_________
_________

Answer:
Quadrilateral and Trapezoid

Explanation:
1 pair of parallel sides
0 sides of equal length
0 right angles.
Given quadrilateral is Trapezoid.
A Square is a quadrilateral that has 1 pair of parallel sides and 0 sides of equal lengths, and 0 right angles.

Page No. 570

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 570 Q8

Question 9.
Classify the figure. Select all that apply.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 41
Options:
a. quadrilateral
b. trapezoid
c. parallelogram
d. rectangle
e. rhombus
f. square

Answer:
a. quadrilateral
b. trapezoid
c. parallelogram

Explanation:
A Parallelogram is a quadrilateral that has 2 pairs of parallel sides and 2 pairs of sides of equal lengths, and 0 right angles.

The Louvre Museum is located in Paris, France. Architect I. M. Pei designed the glass and metal structure at the main entrance of the museum. This structure is called the Louvre Pyramid. Below is a diagram of part of the entrance to the Louvre Pyramid.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 42
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 43

Question 10.
Describe the quadrilaterals you see in the diagram.
_________
_________

Answer:
Trapezoid and Rhombus

Explanation:
There are 2 quadrilaterals available in the given image. One is a Trapezoid with 1 pair of parallel sides. Another one is Rhombus is with 2 pairs of parallel sides and 4 sides of equal lengths, and 0 right angles.

Question 11.
How many triangles do you see in the diagram? Explain.
______ triangles

Answer:
11 triangles

Explanation:
The given image has 11 triangles

Common Core – New – Page No. 571

Classify Quadrilaterals

Classify each figure as many ways as possible. Write quadrilateral, trapezoid, parallelogram, rhombus, rectangle, or square.

Question 1.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 44
Think: 2 pairs of parallel sides
4 sides of equal length
0 right angles
quadrilateral, parallelogram, rhombus

Answer:
Quadrilateral, Parallelogram, and rhombus.

Explanation:
2 pairs of parallel sides
4 sides of equal length
0 right angles
Quadrilateral, Parallelogram, and rhombus.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 45
Type below:
_________

Answer:
Quadrilateral, Parallelogram, Rectangle

Explanation:
2 pairs of parallel sides
2 pairs of sides of equal length
4 right angles
Quadrilateral, Parallelogram, Rectangle

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 46
Type below:
_________

Answer:

Explanation:
1 pair of parallel sides
2 sides of equal length
0 right angles
Quadrilateral, Trapezoid

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 47
Type below:
_________

Answer:
Quadrilateral

Explanation:
0 pair of parallel sides
0 sides of equal length
0 right angles
Quadrilateral

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 48
Type below:
_________

Answer:
Quadrilateral, Parallelogram, and rhombus

Explanation:
2 pairs of parallel sides
4 sides of equal length
0 right angles
Quadrilateral, Parallelogram, and rhombus

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 49 img 49
Type below:
_________

Answer:

Explanation:
1 pair of parallel sides
0 sides of equal length
2 right angles
Quadrilateral, Trapezoid

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 50 img 50
Type below:
_________

Answer:

Explanation:
2 pairs of parallel sides
2 pairs of sides of equal length
0 right angles
Quadrilateral, Parallelogram

Problem Solving

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 571 Q8

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 571 Q9

Common Core – New – Page No. 572

Lesson Check

Question 1.
Joey is asked to name a quadrilateral that is also a rhombus. What should be his answer?
Options:
a. square
b. rectangle
c. parallelogram
d. trapezoid

Answer:
a. square

Explanation:
The quadrilateral square is also called a rhombus. Both square and rhombus have 2 pairs of parallel sides and 4 sides of equal length.

Question 2.
Which quadrilateral has exactly one pair of parallel sides?
Options:
a. square
b. rhombus
c. parallelogram
d. trapezoid

Answer:
d. trapezoid

Explanation:
A trapezoid has exactly one pair of parallel sides.

Spiral Review

Question 3.
Terrence has 24 eggs to divide into equal groups. What are all the possible numbers of eggs that Terence could put in each group?
Options:
a. 1, 2, 3, 4
b. 2, 4, 6, 8, 12
c. 1, 2, 3, 4, 6, 8, 12, 24
d. 24, 48, 72, 96

Answer:
c. 1, 2, 3, 4, 6, 8, 12, 24

Explanation:
Terrence has 24 eggs to divide into equal groups. Terence could put in each group in 1, 2, 3, 4, 6, 8, 12, 24 ways.

Question 4.
In a line of students, Jenna is number 8. The teacher says that a rule for a number pattern is add 4. The first student in line says the first term, 7. What number
should Jenna say?
Options:
a. 31
b. 35
c. 39
d. 43

Answer:
b. 35

Explanation:
In a line of students, Jenna is number 8. The teacher says that a rule for a number pattern is add 4. The first student in line says the first term, 7.
7 + 4 = 11
11 + 4 = 15
15 + 4 = 19
19 + 4 = 23
23 + 4 = 27
27 + 4 = 31
31 + 4 = 35.
Jenna says 35.

Question 5.
Lou eats \(\frac{6}{8}\) of a pizza. What fraction of the pizza is left over?
Options:
a. \(\frac{1}{8}\)
b. \(\frac{1}{4}\)
c. \(\frac{1}{2}\)
d. \(\frac{3}{4}\)

Answer:
b. \(\frac{1}{4}\)

Explanation:
Lou eats \(\frac{6}{8}\) of a pizza. So, 6 parts of pizza is finished and remaining 2 parts of pizza is remained. So, the left over pizza is \(\frac{2}{8}\) = \(\frac{1}{4}\).

Question 6.
Which capital letter appears to have parallel lines?
Options:
a. D
b. L
c. N
d. T

Answer:
c. N

Explanation:
N has two parallel lines that never intersect each other.

Page No. 573

Choose the best term from the box to complete the sentence.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 51

Question 1.
A _______ is part of a line between two endpoints.
_________

Answer:
line segment

Question 2.
A _______ forms a square corner.
_________

Answer:
Right angle

Question 3.
An _______ is greater than a right angle and less than a straight angle.
_________

Answer:
Obtuse angle

Question 4.
The two-dimensional figure that has one endpoint is a ________.
_________

Answer:
ray

Question 5.
An angle that forms a line is called a _______.
_________

Answer:
straight line

Question 6.
On the grid below, draw a polygon that has 2 pairs of parallel sides, 2 pairs of sides equal in length, and 2 acute and 2 obtuse angles. Tell all the possible names for the figure.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 52
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 573
Parallelogram

Explanation:
The possible polygon that has 2 pairs of parallel sides, 2 pairs of sides equal in length, and 2 acute and 2 obtuse angles is Parallelogram.

Draw the figure.

Question 7.
parallel lines
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 563

Explanation:
QR and ST are two parallel lines. they never intersect each other.

Question 8.
obtuse ∠ABC
Type below:
_________

Answer:
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 16

Explanation:
From triangle, ABC, Angle A, and Angle C are both acute with less than a right angle. Angle B is an obtuse angle that is greater than a right angle.

Question 9.
intersecting lines that are not perpendicular
Type below:
_________

Answer:

grade 4 chapter 10 Lines, Rays, and Angles image 7 559

Explanation:
ST and UV are two lines intersecting at point X.

Question 10.
acute ∠RST
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 2 575

Page No. 574

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 574 Q11

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 574 Q12

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 574 Q13

Question 14.
What is the correct name of the figure shown?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 53
_________

Answer:
Ray

Explanation:
EF is a ray that has one endpoint and continues without an end in one direction.

Question 15.
Describe the angles of an obtuse triangle.
Type below:
_________

Answer:
An obtuse triangle (or obtuse-angled triangle) is a triangle with one obtuse angle (greater than 90°) and two acute angles.

Page No. 577

Tell whether the parts on each side of the line match. Is the line a line of symmetry? Write yes or no.

Question 1.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 54
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 55
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 56
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 57
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not with the same size and shape.

Tell if the blue line appears to be a line of symmetry. Write yes or no.

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 58
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 59
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not the same size and shape.

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 60
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not the same size and shape.

Question 8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 61
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Tell if the blue line appears to be a line of symmetry. Write yes or no.

Question 9.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 62
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not the same size and shape.

Question 10.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 63
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 11.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 64
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not with the same size and shape.

Question 12.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 65
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 13.
Which best describes the symmetry in the letter I?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 66
Type below:
________

Answer:
The two parts of the folded I match exactly. The fold line is a line of symmetry.

Explanation:
Take the Horizontal line in the middle of the Letter I. Cut out the tracing. Fold the tracing over a horizontal line. The two parts of the folded I match exactly. The fold line is a line of symmetry.

Page No. 578

Question 14.
Which shape has a correctly drawn line of symmetry?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 67
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 68
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 69
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 70
a. What do you need to find?
Type below:
________

Answer:
Find the shape that has an exact line of symmetry.

Question 14.
b. How can you tell if the line of symmetry is correct?
Type below:
________

Answer:
If the two parts of the folded match exactly, then the line is a line of symmetry.

Question 14.
c. Tell how you solved the problem.
Type below:
________

Answer:
From fig 1 to 4, the fig 2 is has a line of symmetry that can exactly separate the two parts equally.

Question 14.
d. Circle the correct shape above.
Type below:
________

Answer:
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 68

Question 15.
Reason Abstractly Draw a line of symmetry in the figure shown.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 71

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 578

Question 16.
Evie’s birthday is on the 18th of May. Since May is the 5th month, Evie wrote the date as shown.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 72
Evie says all the numbers she wrote have line symmetry. Is she correct? Explain.

Answer:
No; The number 5 doesn’t have a line of symmetry. So, Evie explanation is wrong.

Common Core – New – Page No. 579

Line Symmetry

Tell if the dashed line appears to be a line of symmetry. Write yes or no.

Question 1.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 73
yes

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 74
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not with the same size and shape.

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 75
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 76
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not with the same size and shape.

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 77
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not with the same size and shape.

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 78
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 79
____

Answer:
No;

Explanation:
The line of symmetry divides a shape into two parts that are not with the same size and shape.

Question 8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 80
____

Answer:
Yes;

Explanation:
The line of symmetry divides a shape into two parts that are the same size and shape.

Complete the design by reflecting over the line of symmetry.

Question 9.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 81

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 4 578

Question 10.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 82

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 6 578

Problem Solving

Question 11.
Kara uses the pattern below to make paper dolls. The dashed line represents a line of symmetry. A complete doll includes the reflection of the pattern over the line of symmetry. Complete the design to show what one of Kara’s paper dolls looks like.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 83

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 7 578

Common Core – New – Page No. 580

Lesson Check

Question 1.
Which best describes the line of symmetry in the letter D?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 84
Options:
a. horizontal
b. vertical
c. diagonal
d. half turn

Answer:
a. horizontal

Explanation:
The horizontal line of symmetry in the letter D can exactly separate two parts equally.

Question 2.
Which shape has a correctly drawn line of symmetry?
Options:
a. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 85
b. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 86
c. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 87
d. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 88

Answer:
b. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 86

Explanation:
Image b has a line of symmetry that separates two parts equally.

Spiral Review

Question 3.
The class has 360 unit cubes in a bag. Johnnie divides the unit cubes equally among 8 groups. How many unit cubes will each group get?
Options:
a. 40
b. 44
c. 45
d. 48

Answer:
c. 45

Explanation:
The class has 360 unit cubes in a bag. Johnnie divides the unit cubes equally among 8 groups. 360/8= 45.

Question 4.
There are 5,280 feet in one mile. How many feet are there in 6 miles?
Options:
a. 30,680
b. 31,260
c. 31,608
d. 31,680

Answer:
d. 31,680

Explanation:
There are 5,280 feet in one mile. So, for 6 miles = 6 x 5, 280 = 31,680.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 580 Q5

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 580 Q6

Page No. 583

Question 1.
The shape at the right has line symmetry. Draw the 2 lines of symmetry.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 89
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 583

Tell whether the shape appears to have zero lines, 1 line, or more than 1 line of symmetry. Write zero, 1, or more than 1.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 90
_________

Answer:
more than 1

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 2 583
There is more than 1 line of symmetries that separates two parts equally.

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 91
_________

Answer:
more than 1

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 3 583
There is more than 1 lines of symmetries that separates two parts equally.

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 92
_________

Answer:
1 line

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 4 583
There is 1 line of symmetry that separates two parts equally.

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 93
_________

Answer:
zero lines

Explanation:
There is no line of symmetries that separates two parts equally.

Tell whether the shape appears to have zero lines, 1 line, or more than 1 line of symmetry. Write zero, 1, or more than 1.

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 94
_________

Answer:
more than 1

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 6 583
There is more than 1 lines of symmetries that separate two parts equally.

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 95
_________

Answer:
zero lines

Explanation:
There is no line of symmetries that separates two parts equally.

Question 8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 96
_________

Answer:
zero lines

Explanation:
There is no line of symmetries that separates two parts equally.

Question 9.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 97
_________

Answer:
1 line

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 8 583
There is 1 line of symmetry that separates two parts equally.

Practice: Copy and Solve Does the design have line symmetry?
Write yes or no. If your answer is yes, draw all lines of symmetry.

Question 10.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 98
____

Answer:
Yes;
grade 4 chapter 10 Lines, Rays, and Angles image 8 583

Question 11.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 99
_____

Answer:
No;

Question 12.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 100
_____

Answer:
Yes;
grade 4 chapter 10 Lines, Rays, and Angles image 9 578

Question 13.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 101
_____

Answer:
No;

Question 14.
Draw a figure that has 5 sides and exactly 1 line of symmetry.
Type below:
_________

Answer:

Explanation:
the above 5 sides shape has only 1 line symmetry

Page No. 584

Use the chart for 15–17.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 102

Question 15.
Which letters appear to have only 1 line of symmetry?
Type below:
_________

Answer:
A, B, C, D, E, T, U, V, W

Explanation:
The letters A, B, C, D, E, T, U, V, W have only 1 line of symmetry.

Question 16.
Which letters appear to have zero lines of symmetry?
Type below:
_________

Answer:
J, N, S

Explanation:
The letters J, N, S have only zero lines of symmetry.

Question 17.
The letter C has horizontal symmetry. The letter A has vertical symmetry. Which letters appear to have both horizontal and vertical symmetry?
Type below:
_________

Answer:
H and I

Explanation:
The letters H and I have both horizontal and vertical symmetry.

Question 18.
Verify the Reasoning of Others Jeff says that the shape has only 2 lines of symmetry.
Does his statement make sense? Explain.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 103
Type below:
_________

Answer:
No; Jeff’s explanation is wrong. Because the given shape has only 2 lines of symmetry.

Question 19.
Match each figure with the correct number of lines of symmetry it has.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 104
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 12 583

Common Core – New – Page No. 585

Find and Draw Lines of Symmetry

Tell whether the shape appears to have zero lines, 1 line, or more than 1 line of symmetry. Write zero, 1, or more than 1.

Question 1.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 105
1

Answer:
more than 1

Explanation:
There is more than 1 line of symmetry that separates two parts equally.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 106
________

Answer:
more than 1

Explanation:
There is more than 1 line of symmetry that separates two parts equally.

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 107
________

Answer:
Zero

Explanation:
There are 0 lines of symmetries.

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 108
________

Answer:
more than 1

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 2 585
There is more than 1 line of symmetry that separates two parts equally.

Does the design have line symmetry? Write yes or no.
If your answer is yes, draw all lines of symmetry.

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 109
_____

Answer:
Yes;
grade 4 chapter 10 Lines, Rays, and Angles image 3 585

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 110
_____

Answer:
Yes;
grade 4 chapter 10 Lines, Rays, and Angles image 5 585

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 111
_____

Answer:
No;

Question 8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 112
______

Answer:
Yes;
grade 4 chapter 10 Lines, Rays, and Angles image 6 585

Draw a shape for the statement. Draw the line or lines of symmetry.

Question 9.
zero lines of symmetry
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 113

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 7 585

Question 10.
1 line of symmetry
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 114

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 9 585

Question 11.
2 lines of symmetry
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 115

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 10 585

Problem Solving

Use the chart for 12–13.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 116

Question 12.
Which number or numbers appear to have only 1 line of symmetry?
_____

Answer:
3

Explanation:
The number 3 has only 1 line of symmetry.

Question 13.
Which number or numbers appear to have 2 lines of symmetry?
_____

Answer:
0 and 8

Explanation:
The numbers 0 and 8 appear to have 2 lines of symmetry.

Common Core – New – Page No. 586

Lesson Check

Question 1.
How many lines of symmetry does this shape appear to have?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 117
Options:
a. 0
b. 2
c. 6
d. 12

Answer:
c. 6

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 1 586
The given shape has 6 lines of symmetries.

Question 2.
Which of the following shapes appears to have exactly 1 line of symmetry?
Options:
a. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 118
b.Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 119
c. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 120
d. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 121

Answer:
d. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 121

Explanation:
grade 4 chapter 10 Lines, Rays, and Angles image 2 586
The trapezoid has exactly 1 line of symmetry.

Spiral Review

Question 3.
Richard practiced each of 3 piano solos for \(\frac{5}{12}\) hour. How long did he practice in all?
Options:
a. \(\frac{2}{3}\) hours
b. 1 \(\frac{1}{4}\) hours
c. 1 \(\frac{1}{3}\) hours
d. 1 \(\frac{5}{12}\) hours

Answer:
b. 1 \(\frac{1}{4}\) hours

Explanation:
Richard practiced each of 3 piano solos for \(\frac{5}{12}\) hour. \(\frac{5}{12}\) hour = 1 \(\frac{1}{4}\) hours hours.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 586 Q4

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 586 Q5
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 586 Q5.1

Question 6.
Kevin draws a figure that has four sides. All sides have the same length. His figure has no right angles. What figure does Kevin draw?
Options:
a. square
b. trapezoid
c. rhombus
d. rectangle

Answer:
c. rhombus

Explanation:

Page No. 589

Question 1.
Marisol is making a pattern with blocks. What might the missing shape be?
First, look at the blocks.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 122
Next, describe the pattern.
Type below:
_________

Answer:
The first image 1 has three line segments. The next shape will have four line segments.

Question 1.
Finally, draw the missing shape.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 123
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 586

Question 2.
Use the shapes to write a number pattern. Then describe the pattern in the numbers.

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 3 586
Shape 1: Triangle
Shape 2: Square
Shape 3: Pentagon
Shape 4: Hexagon
Shape 5: Heptagon

Question 3.
What if the pattern continued? Write an expression to describe the number of sides the sixth shape has in Marisol’s pattern.
Type below:
_________

Answer:
If the pattern continued, then the next shape will have one more extra line segment to it. The sixth shape will become the octagon.
Shape 6: Octagon

Question 4.
Sahil made a pattern using circles. The first nine circles are shown. Describe the pattern. If Sahil continues the pattern, what might the next three circles be?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 124
Type below:
_________

Answer:
The pattern is repeated for every three circles. One big circle followed by two small circles.
grade 4 chapter 10 Lines, Rays, and Angles image 6 586

Page No. 590

Use the toy quilt designs for 5–6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 125

Question 5.
Lu is making a quilt that is 20 squares wide and has 24 rows. The border of the quilt is made by using each toy design equally as often. Each square can hold one design. How many of each design does she use for the border?
______ times

Answer:
The border will have 20 squares two times, and 24 squares two times as well, that is the perimeter or the border, because a quilt has 4 sides:
20 X 2 + 24 X 2 = 40 + 48 = 88
So, the border will have 88 squares in total. So if the border can have only one design, Lu can use any toy design 88 times if she wants the border to have the same toy design in it.

Question 6.
Communicate Starting in the first square of her quilt, Lu lined up her toy designs in this order: plane, car, fire truck, helicopter, crane, and wagon. Using this pattern unit, which design will Lu place in the fifteenth square? Explain how you found your answer.
_________

Answer:
The answer is fire truck. As the pattern repeats, the fifteenth square will fire the truck.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 590 Q7

Question 8.
Norris drew the pattern shown.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 126
Label the circles to show the colors in the fourth figure of the pattern.
Type below:
_________

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 591

Common Core – New – Page No. 591

Problem Solving Shape Patterns

Solve each Problem.

Question 1.
Marta is using this pattern to decorate a picture frame. Describe the pattern. Draw what might be the next three figures in the pattern.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 127
Possible answer: the pattern repeats: one trangle followed by two squares.

Answer:
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 127
The pattern repeats one triangle followed by two squares.

Question 2.
Describe the pattern. Draw what might be the next three figures in the pattern. How many circles are in the sixth figure in the pattern?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 128
_____ circles

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 591
Add one more column with 1 more circle than in the previous column; 21.

Question 3.
Larry stencils this pattern to make a border at the top of his bedroom walls. Describe the pattern. Draw what might be the missing figure in the pattern.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 129

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 2 591
2 triangles placed side to side followed by 2 sets of 2 triangles placed vertex to vertex

Common Core – New – Page No. 592

Lesson Check

Question 1.
What might be the next three figures in this pattern?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 130
Options:
a. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 131
b. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 132
c. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 133
d. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 134

Answer:
a. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 131

Explanation:
the pattern has odd numbers of up arrows then even number of down arrows. So, the next three figures are Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 131.

Question 2.
Which might be the missing figure in the following pattern?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 135
Options:
a. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 136
b. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 137
c. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 138
d. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 139

Answer:
a. Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Common Core - New img 136

Explanation:
From the pattern, the missing image will have a vertical rectangle with the circle and X mark in it.

Spiral Review

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 592 Q3

Question 4.
Olivia finished a race in 40.64 seconds. Patty finished the race in 40.39 seconds. Miguel finished the race in 41.44 seconds. Chad finished the race in 40.46 seconds. Who finished the race in the least time?
Options:
a. Olivia
b. Patty
c. Miguel
d. Chad

Answer:
b. Patty

Explanation:
Patty finished the race in 40.39 seconds which is the least time compared to others.

Question 5.
Justin bought 6 ribbons for an art project. Each ribbon is \(\frac{1}{4}\) yard long. How many yards of ribbon did Justin buy?
Options:
a. \(\frac{2}{3}\) yard
b. 1 \(\frac{1}{4}\) yards
c. 1 \(\frac{1}{2}\) yards
d. 1 \(\frac{3}{4}\) yards

Answer:
c. 1 \(\frac{1}{2}\) yards

Explanation:
Justin bought 6 ribbons for an art project. Each ribbon is \(\frac{1}{4}\) yard long. So, 6 X \(\frac{1}{4}\) = \(\frac{3}{2}\) = 1 \(\frac{1}{2}\) yards.

Question 6.
Kyle and Andrea were asked to make a list of prime numbers.
Kyle: 1, 3, 7, 19, 23
Andrea: 2, 3, 5, 7, 11
Whose list is correct?
Options:
a. Only Kyle’s list
b. Only Andrea’s list
c. Both lists are correct.
d. Neither list is correct.

Answer:
b. Only Andrea’s list

Explanation:
1 is not a prime number. So, the answer is Only Andrea’s list is correct.

Page No. 593

Question 1.
Gavin is designing a kite. He sketched a picture of the kite.
How many right angles does the kite appear to have?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 140
_____ right angles

Answer:
0 right angles

Explanation:
There is no right angles in the given shape.

Question 2.
Write the letter of the triangle under its correct classification.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 141
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 142

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 593

Explanation:
C and F are Acute angles with less than right angles.
B and D are Obtuse Angles with more than right angles.
A and E are Right Angles.

Question 3.
Select the angles that identify an obtuse triangle. Mark all that apply.
Options:
a. acute, acute, acute
b. acute, acute, obtuse
c. right, acute, acute
d. obtuse, right, acute

Answer:
b. acute, acute, obtuse

Explanation:
An obtuse triangle will have one obtuse angle and two acute angles.

Page No. 594

Question 4.
Write the word that describes the part of Figure A written below.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 143
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 144
\(\overline{E B}\) _________
\(\overset { \longleftrightarrow }{ AB } \) _________
\(\overrightarrow{G A}\) _________
∠EBG _________
∠CGB _________

Answer:
\(\overline{E B}\) line segment.
\(\overset { \longleftrightarrow }{ AB } \) Line.
\(\overrightarrow{G A}\) Ray.
∠EBG right angle.
∠CGB acute angle.

Explanation:
\(\overline{E B}\) is a line segment that has two endpoints connected to form a line.
\(\overset { \longleftrightarrow }{ AB } \) is a Line that continues without an end in both directions.
\(\overrightarrow{G A}\) is a Ray that has one endpoint and continues without an end in one direction.
∠EBG right angle.
∠CGB is an acute angle with less than the right angle.

Question 5.
What term best describes the figure shown below?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 145

Answer:
perpendicular lines

Explanation:
The lines are forming four right angles they form squares. So, both lines are perpendicular lines.

Question 6.
Naomi leaves for her trip to Los Angeles on the 12th day of August. Since August is the 8th month, Naomi wrote the date as shown.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 146
Naomi says all the numbers she wrote have line symmetry. Is she correct? Explain your thinking.
_______

Answer:
Naomi is incorrect. The number 2 does not have a line of symmetry because if it were cut out, there would be no way to fold it in half so that the two parts matched exactly.

Page No. 595

Question 7.
Max made a pennant that looks like a triangle. How can you classify the triangle based on its angles?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 147
The triangle is a(n) ____________ triangle.

Answer:
The triangle is an acute triangle.

Explanation:
The triangle is an acute triangle.  because it has angles with less than right angles.

Question 8.
Choose the labels to make a true statement.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 148
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 149
_____ is parallel to ______

Answer:
Line AB is parallel to line CD.

Explanation:
From the given image, Line AB is parallel to line CD.

Question 9.
Classify the figure. Select all that apply.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 150
Options:
a. quadrilateral
b. trapezoid
c. parallelogram
d. rectangle
e. rhombus
f. square

Answer:
a. quadrilateral
b. trapezoid
c. parallelogram
d. rectangle

Explanation:
The given image has 2 parallel sides, 2 pairs of sides of length, and four right angles. So, the possible answers are quadrilateral, trapezoid, parallelogram, and rectangle.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 595 Q10

Page No. 596

Question 11.
Match each figure with the correct number of lines of symmetry it has.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 151

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 595

Explanation:
Image 1: 1 line of symmetry
Image 2: 2 lines of symmetry
Image 3: 0 lines of symmetry
Image 4: More than 2 lines of symmetry.

Question 12.
Barb drew the pattern shown.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 152
Use the square shown to draw the missing pattern. □

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 596

Explanation:
The fourth shape must consist of one extra square box in the top line and bottom line.

Question 13.
Claudia drew the figure below. Draw a line of symmetry on Claudia’s figure.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 153

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 2 596

Explanation:
The image can have one line symmetry.

Question 14.
Write the word or words that best describe this figure.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 154
_________

Answer:
Ray

Explanation:
The ray has one endpoint and continues without an end in one direction.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 596 Q15

Page No. 597

Question 16.
Mike drew a figure with opposite sides parallel. Write the pairs of parallel sides. What figure is it?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 155

Answer:
Line DG is parallel to Line FE and Line DE is parallel to Line GF; the figure is a parallelogram.

Question 17.
Circle the letter that does not have line symmetry.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 156

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 4 569

Explanation:
The S does not have line symmetry.

Question 18.
Joseph made a pattern using ovals and rectangles. The first four figures of his pattern are shown. Draw the next figure in the pattern.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 157

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 5 596

Question 19.
Jeremy drew Figure 1 and Louisa drew Figure 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 158
Part A
Jeremy says both figures are rectangles. Do you agree with Jeremy?
Support your answer.
_____

Answer:
Yes; both figures have 2 pairs of parallel sides, opposite sides that are equal in length, and 4 right angles.

Question 19.
Part B
Louisa says both figures are rhombuses. Do you agree with Louisa?
Support your answer.
_____

Answer:
No; figure 2 is a rhombus since it has 2 pairs of parallel sides and 4 sides of equal length. Figure 1 does not have 4 sides of equal length so it cannot be a rhombus.

Page No. 598

Question 20.
Veronica found the number of lines of symmetry for the figure below. How many lines of symmetry does it have?
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 159
______ lines of symmetry

Answer:
2 lines of symmetry

Explanation:
the given shape can have 2 lines of symmetry.

Question 21.
Jordan drew the pattern below.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 160
Part A
Describe the pattern.

Answer:
Each figure has 2 more squares than the preceding figure.

Question 21.
Part B
Write a rule using numbers to find the number of squares in any figure in the pattern.

Answer:
multiply the figure number by 2.

Question 21.
Part C
Draw Figure 5.

Answer:
grade 4 chapter 10 Lines, Rays, and Angles image 1 597

Page No. 603

Tell what fraction of the circle the shaded angle represents.

Question 1.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 161
\(\frac{□}{□}\)

Answer:
\(\frac{1}{2}\)

Explanation:
Half of the part is shaded out of the circle. So, the answer is 1/2.

Question 2.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 162
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
\(\frac{1}{4}\) part of the circle is shaded out of the circle.

Question 3.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 163
\(\frac{□}{□}\)

Answer:
\(\frac{3}{4}\)

Explanation:
3 parts of the circle is shaded out of the circle

Question 4.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 164
\(\frac{□}{□}\)

Answer:
\(\frac{1}{1}\) = 1

Explanation:
The complete circle is shaded. So, the answer is 1.

Question 5.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 165
\(\frac{□}{□}\)

Answer:
\(\frac{1}{2}\)

Explanation:
Half of the part is shaded out of the circle. So, the answer is 1/2.

Question 6.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 166
\(\frac{□}{□}\)

Answer:
\(\frac{1}{12}\)

Tell whether the angle on the circle shows a \(\frac{1}{4}, \frac{1}{2}, \frac{3}{4}\), or 1 full turn clockwise or counterclockwise.

Question 7.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 167
Type below:
________

Answer:
\(\frac{3}{4}\); counterclockwise

Explanation:
The image shows the counterclockwise and formed fraction of \(\frac{3}{4}\).

Question 8.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 168
Type below:
________

Answer:
\(\frac{1}{2}\); clockwise

Explanation:
The image shows the clockwise and formed fraction of \(\frac{1}{2}\).

Question 9.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 169
Type below:
________

Answer:
\(\frac{1}{4}\); clockwise

Explanation:
The image shows the clockwise and formed fraction of \(\frac{1}{4}\).

Question 10.
Susan watched the game from 1 p.m. to 1:30 p.m. Describe the turn the minute hand made.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 170
Type below:
________

Answer:
The minute hand made a \(\frac{1}{2}\) turn clockwise.

Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures Page 603 Q11

Page No. 604

Question 12.
Malcolm drew this angle on the circle. Which of the following describes the angle? Mark all that apply.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 171
Options:
a. \(\frac{3}{4}\) turn
b. \(\frac{1}{4}\) turn
c. clockwise
d. counterclockwise

Answer:
a. \(\frac{3}{4}\) turn
d. counterclockwise

Explanation:
The image show the \(\frac{3}{4}\) turn and also the counterclockwise.

Sense or Nonsense?

Question 13.
Whose statement makes sense? Whose statement is nonsense? Explain your reasoning.
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 172
Go Math Grade 4 Answer Key Chapter 10 Two-Dimensional Figures img 173
Type below:
__________

Answer:
The girl’s statement makes sense. The boy’s statement makes non-sense. Because from the figure it is clearly shown that the shaded part is \(\frac{1}{4}\) of the circle. There is no particular direction given to measure the shaded part.

Conclusion:

Finally, you will find detailed solutions to all questions that you’re looking for. So, you can attempt the exam with utmost confidence and secure good grades in the exams. The topics covered in Ch 10 Two-dimensional figures are such Lines, Rays, Angles, Classify Triangles by Angles, Parallel Lines and Perpendicular Lines, etc. Understand how to solve the problems of two-dimensional figures by accessing our Go Math Grade 4 Solution Key Chapter 10 Two-dimensional figures Homework Practice FL.

Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000

Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000

Go Math Grade 2 Chapter 2 Answer Key Numbers to 1,000

Numbers to 1,000 Show What you know

Identify Numbers to 30

Write how many.

Question 1.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 0.1

Answer:
Leaves = 17.

Explanation:
In the above-given figure,
Given that,
there are 17 leaves.
so leaves = 17.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-1

Question 2.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 0.2

Answer:
bug = 24.

Explanation:
In the above-given figure,
Given that,
there are 24 bugs.
so bug = 24.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2

Place Value: 2-Digit Numbers

Circle the value of the red digit.

Question 3.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 1

Answer:
The value of the red digit = 4.

Explanation:
In the above-given figure,
Given that,
the place value of 2 digits.
the number is 47.
so the value of the red digit = 4.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-3

Question 4.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 2

Answer:
The value of the red digit = 4.

Explanation:
In the above-given figure,
Given that,
the place value of 2 digits.
the number is 84.
so the value of the red digit = 4.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-4

Question 5.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 3

Answer:
The value of the red digit = 6.

Explanation:
In the above-given figure,
Given that,
the place value of 2 digits.
the number is 65.
so the value of the red digit = 6
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-5

Compare 2-Digit Numbers Using Symbols
Compare. Write >, <, or =.

Question 6.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 4

Answer:
42 is greater than 37.

Explanation:
In the above-given question,
given that,
The numbers are 37, 42.
42 is greater than 37.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-6

Question 7.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 5

Answer:
40 is less than 33.

Explanation:
In the above-given question,
given that,
The numbers are 33, 40.
40 is less than 33.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-7

Numbers to 1,000 Vocabulary Builder

Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 6

Visualize It

Fill in the boxes of the graphic organizer.
Write sentences using fewer and more.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 7

Answer:
Fewer.
9 pens are fewer than 11 pens.
3 pens are fewer than 6 pens.
More:
11 pens are more than 9 pens.
6 pens are more than 3 pens.

Explanation:
In the above-given figure,
given that the words more and fewer.
Fewer.
9 pens are fewer than 11 pens.
3 pens are fewer than 6 pens.
More:
11 pens are more than 9 pens.
6 pens are more than 3 pens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-8

Understand Vocabulary

Use the review words. Complete the sentences.

Question 1.
3 and 9 are digits in the number 39.

Answer:
3 and 9 are digits in the number 39.

Explanation:
In the above-given question,
given that,
3 and 9 are digits in the number 39.

Question 2.
7 is in the _ones__ place in the number 87.

Answer:
7 is in the ones place in the number 87.

Explanation:
In the above-given figure,
given that the place values.
7 is in the ones place in the number 87.

Question 3.

8 is in the ___ place in the number 87.

Answer:
8 is in the tens place in the number 87.

Explanation:
In the above-given figure,
given that the place values.
8 is in the tens place in the number 87.

Numbers to 1,000 Game: Fish for Digits

Materials
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 12

Play with a partner.

1. Name a place for a digit. You can say tens place or ones place. Toss the Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 13
2. Match the number on the Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 14 and the place that you named with a fish.
3. Put a Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 14.1 on that fish. Take turns.
4. Match all the fish. The player with more Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 15 on the board wins.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 16

Answer:
1.The dice is in the tens place.
2. The dice named with the fish is 53.
3. The red on the fish is 53.

Explanation:
1.The dice is in the tens place.
2. The dice named with the fish is 53.
3. The red on the fish is 53.

Numbers to 1,000 Vocabulary Game

Going Places with GOMATH! Words

Guess the Word

For 3 to 4 players
Materials
• timer

How to Play

1. Take turns to play.
2. Choose a math word, but do not say it aloud.
3. Set the timer for 1 minute.
4. Give a one-word clue about your word. Give each player one chance to guess your word.
5. If nobody guesses correctly, repeat Step 4 with a different clue. Repeat until a player guesses the word or time runs out.
6. The first player to guess the word gets 1 point. If the player can use the word in a sentence, he or she gets 1 more point. Then that player gets a turn.
7. The first player to score 5 points wins.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 17

The Write Way

Reflect
Choose one idea. Write about it in the space below.

  • Draw and write about all the different ways you can show the number 482. Use a separate piece of paper for your drawing.
  • Explain how to compare two numbers.
  • Write sentences that include at least two of these terms.

Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 17.1
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 17.2
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 17.3

Answer:
a. 400 + 80 + 2.
400 + 0 + 82.
300 + 180 + 2
200 + 280 + 2
100 + 380 + 2
b. 9 is greater than 3.
6 is less than 10.
c. 2 is in the tens place is the digit 27.
400 + 80 + 2 is equal to the 482.

Explanation:
In the above-given question,
Given words are placed value, is equal to, hundreds, and thousands.
a. 400 + 80 + 2.
400 + 0 + 82.
300 + 180 + 2
200 + 280 + 2
100 + 380 + 2
b. 9 is greater than 3.
6 is less than 10.
c. 2 is in the tens place is the digit 27.
400 + 80 + 2 is equal to the 482.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-9

Lesson 2.1 Group Tens as Hundreds

Essential Question
How do you group tens as hundreds?

Answer:
Ten groups of 10’s are 100.

Explanation:
In the above-given question,
give that,
group 10’s as 100.
so 10 groups of 10’s are 100.

Listen and Draw
Circle groups of ten. Count the groups of ten.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 20

Answer:
Ten groups of 10’s are 100.

Explanation:
In the above-given question,
give that,
group 10’s as 100.
so 10 groups of 10’s are 100.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-1

Math Talk

MATHEMATICAL PRACTICES

Describe How many ones are in 3 tens? How many ones are in 7 tens? Explain.

Answer:
30 ones are in 3 tens.
7 ones are in 7 tens.

Explanation:
In the above-given question,
given that
30 ones are in 3 tens.
7 ones are in 7 tens.

Share and Show MATH BOARD

Write how many tens. Circle groups of 10 tens. Write how many hundreds. Write the number.

Question 1.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 21

Answer:
20 tens.
2 hundred.
The number is 200.

Explanation:
In the above-given figure,
given that
there are 20 tens.
2 hundred.
The number is 200.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-2

Question 2.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 22

Answer:
30 tens.
3 hundred.
The number is 300.

Explanation:
In the above-given figure,
given that
there are 30 tens.
3 hundred.
The number is 300.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-3

Question 3.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 23

Answer:
40 tens.
4 hundred.
The number is 400.

Explanation:
In the above-given figure,
given that
there are 40 tens.
4 hundred.
The number is 400.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-4

Question 4.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 24

Answer:
50 tens.
5 hundred.
The number is 500.

Explanation:
In the above-given figure,
given that
there are 50 tens.
5 hundred.
The number is 500.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-5

On Your Own

Write how many tens. Circle groups of 10 tens. Write how many hundreds. Write the number.

Question 5.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 25

Answer:
70 tens.
7 hundred.
The number is 700.

Explanation:
In the above-given figure,
given that
there are 70 tens.
7 hundred.
The number is 700.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-6

Question 6.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 26

Answer:
60 tens.
6 hundred.
The number is 600.

Explanation:
In the above-given figure,
given that
there are 60 tens.
6 hundred.
The number is 600.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-7

Question 7.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 27

Answer:
90 tens.
9 hundred.
The number is 900.

Explanation:
In the above-given figure,
given that
there are 90 tens.
9 hundred.
The number is 900.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-8

Question 8.
THINK SMARTER
Wally has 400 cards. How many stacks of 10 cards can he make?
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 28

Answer:
Wally can make 4 stacks of 10 cards.

Explanation:
In the above-given figure,
given that
Wally has 400 cards.
wally can make 4 stacks of 10 cards.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-9

Problem Solving • Applications

Solve. Write or draw to explain.

Question 9.
Mrs. Martin has 80 boxes of paper clips. There are 10 paper clips in each box. How many paper clips does she have?
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 29
800__ paper clips

Answer:
The paper clips Mrs. Martin has 800.

Explanation:
In the above-given question,
given that
Mrs. Martin has 80 boxes of paper clips.
There are 10 paper clips in each box.
The paper clips do she have = 800.

Question 10.
THINK SMARTER
Pencils are sold in boxes of 10 pencils. Mr. Lee needs 100 pencils. He has 40 pencils. How many boxes of 10 pencils should he buy?
__ boxes of 10 pencils
Draw a picture to explain your answer.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 30

Answer:
6 boxes of 10 pencils should he buy.

Explanation:
In the above-given figure,
given that,
Pencils are sold in boxes of 10 pencils.
Mr. Lee needs 100 pencils.
He has 40 pencils.
6 boxes of 10 pencils should he buy.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-10

TAKE HOME ACTIVITY
• Ask your child to draw a quick picture of 20 tens and then tell you how many hundreds there are.

Group Tens as Hundreds Homework & Practice 2.1

Write how many tens. Circle groups of 10 tens. Write how many hundreds. Write the number.

Question 1.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 31

Answer:
40 tens.
4 hundred.
The number is 400.

Explanation:
In the above-given figure,
given that
there are 40 tens.
4 hundred.
The number is 400.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-11

Question 2.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 32

Answer:
60 tens.
6 hundred.
The number is 600.

Explanation:
In the above-given figure,
given that
there are 60 tens.
6 hundred.
The number is 600.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.1-12

Problem Solving

Solve. Write or draw to explain.

Question 3.
Farmer Gray has 30 flowerpots. He plants 10 seeds in each pot. How many seeds does he plant?
_300__ seeds

Answer:
The seeds do he plant = 300.

Explanation:
In the above-given figure,
given that farmer, gray has 30 flower pots.
He plants 10 seeds in each pot.
He plants 300 seeds.

Question 4.
WRITE Math
Ella has 50 stacks of ten pennies in each stack. Describe how to find how many pennies Ella has in all.
________50 ten_____________________________
_________5 hundreds____________________________
__________500___________________________
_____________________________________

Answer:
Ella has in all = 500.

Explanation:
In the above-given figure,
given that Ella has 50 stacks of 10 pennies in each stack.
Ella has in all = 500.

Lesson Check

Question 1.
Mai has 40 tens. Write how many hundreds. Write the number.

Answer:
The number is 4.

Explanation:
Given that,
Mari has 40 tens,
Mari has 4 hundred.

Question 2.
There are 80 tens. Write how many hundreds. Write the number.

Answer:
The number is 8.

Explanation:
Given that,
Mari has 80 tens,
Mari has 8 hundred.

Question 3.
Write the number equal to 5 tens and 13 ones.

Answer:
The number is 63.

Explanation:
In the above-given figure,
Given that,
The number equal to 5 tens and 13 ones.
The number is 63.

Question 4.
Count by fives.
5, 10, 15
_20_, _25_, _30_, _35__

Answer:
20, 25, 30, 35.

Explanation:
In the above-given question,
given that count by fives.
The numbers are 5, 10, and 15.
20, 25, 30, and 35.

Question 5.
Carlos has 58 pencils. What is the value of the digit 5 in this number?
__________tens_____place______________________

Answer:
The value of the digit 5 in this number is tens place.

Explanation:
In the above-given figure,
Given that,
Carlos has 58 pencils.
The value of the digit 5 in the number is tens place.

Question 6.
Circle the sum that is an even number.
2 + 3 = 5
4 + 4 = 8
5 + 6 = 11
8 + 7 = 15

Answer:
The sum that is an even number is 4 + 4 = 8.

Explanation:
In the above-given question,
Given that the numbers are
2 + 3 = 5
4 + 4 = 16
5 + 6 = 11
8 + 7 = 15.
4 + 4 = 8 is even number.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.2-1

Lesson 2.3 Model 3-Digit Numbers

Essential Question
How do you show a 3-digit number using blocks?

Answer:
3 packs of blocks are 300.

Explanation:
In the above-given question,
given that
we show a 3-digit number by using blocks.
we use 3 packs of blocks.
300.

Listen and Draw

Use Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 33 Draw to show what you did.

Math Talk

MATHEMATICAL PRACTICES

If Jack had 14 tens, how many hundreds and tens would he have? Explain

Model and Draw

In the number 348, the 3 is in the hundreds place, the 4 is in the tens place, and the 8 is in the ones place.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 34

Answer:
The number is 348.

Explanation:
In the above-given figure,
given that,
number 348 in many ways.
300 + 40 + 8 = 348.

Share and Show MATH Board

Write how many hundreds, tens, and ones. Show with Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 35. Then draw a quick picture.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 35.1

Answer:
The number is 111.

Explanation:
In the above-given figure,
given that,
number 111 with 1 hundred, 1 ten, 1 one.
100 + 10 + 1 = 111.

Question 1.
234
_2_ hundreds + _3_ tens + _4_ ones

Answer:
The number is 234.

Explanation:
In the above-given figure,
given that,
number 234 with 2 hundred, 3 ten, 4 one.
200 + 30 + 4 = 234.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-1

Question 2.
156
_1_ hundreds + _5_ tens + _6_ ones

Answer:
The number is 156.

Explanation:
In the above-given figure,
given that,
number 156 with 1 hundred, 5 ten, 6 one.
100 + 50 + 6 = 234.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-2

On Your Own

Write how many hundreds, tens, and ones.
Show with Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 36. Then draw a quick picture.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 37

Answer:
The number is 111.

Explanation:
In the above-given figure,
given that,
number 111 with 1 hundred, 1 ten, 1 one.
100 + 10 + 1 = 111.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-3

Question 3.
125
_1_ hundreds + _2_ tens + _5_ ones

Answer:
The number is 125.

Explanation:
In the above-given figure,
given that,
number 125 with 1 hundred, 2 ten, 5 one.
100 + 20 + 5 = 125.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-4

Question 4.
312
_3_ hundreds + _1_ tens + _2_ ones

Answer:
The number is 312.

Explanation:
In the above-given figure,
given that,
number 312 with 3 hundred, 1 ten, 2 one.
300 + 10 + 2 = 312.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-5

Question 5.
_6_ hundreds + _2_ tens + _3_ ones

Answer:
The number is 623.

Explanation:
In the above-given figure,
given that,
number 623 with 6 hundred, 2 ten, 3 one.
600 + 20 + 3 = 623.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-6

Question 6.
_5_ hundreds + _1_ tens + _2_ ones

Answer:
The number is 512.

Explanation:
In the above-given figure,
given that,
number 512 with 5 hundred, 1 ten, 2 one.
500 + 10 + 2 = 512.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-7

Question 7.
THINK SMARTER
Lexi needs 144 beads. A large box holds 100 beads. A medium box holds 10 beads. A small box holds 1 bead. Lexi already had 1 large box and 4 small boxes. How many medium boxes of beads does she need?
_4_ medium boxes.

Answer:
Lexi needs 4 medium boxes of beads.

Explanation:
In the above-given question,
Given that,
Lexi needs 144 beads.
A large box holds 100 beads.
a medium box holds 10 beads.
small box holds 1 bead.
so Lexi needs 4 medium boxes of beads.
100 + 10 + 10 + 10 + 10 + 4.

Problem Solving • Applications WRITE Math

Question 8.
THINK SMARTER
How are the numbers 342 and 324 alike? How are they different?
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 38
________________________
________________________
________________________

Answer:
The numbers 342 and 324 are different.

Explanation:
In the above-given question,
given that,
342 and 324 are alike.
but they are different.
in hundreds place 3 is common, but tens and ones place is different.

MATHEMATICAL PRACTICES

Model with Mathematics

write the number for the clue.

Question 9.
A model for my number has 2 hundred blocks, no tens blocks, and 3 one blocks.
My number is _203_

Answer:
My number is 203.

Explanation:
In the above-given figure,
given that,
A model for my number has 2 hundred blocks, no tens blocks, and 3 one blocks.
my number is 203.

Question 10.
A model for my number has 3 hundred blocks, 5 tens blocks, and no one’s blocks.
My number is _350_

Answer:
My number is 350.

Explanation:
In the above-given figure,
given that,
A model for my number has 3 hundred blocks, 5 tens blocks, and no one blocks.
my number is 350.

Question 11.
THINK SMARTER
There are 2 boxes of 100 pencils and some single pencils on the table. Choose all the numbers that show how many pencils could be on the table.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 39

Answer:
The pencils are 203, 207.

Explanation:
In the above-given figure,
given that,
There are 2 boxes of 100 pencils and some single pencils on the table.
single pencils are 3 and 7.
The pencils are 203, 207.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-8

TAKE HOME ACTIVITY
• Write the number 438. Have your child tell you the values of the digits in the number 438.

Model 3-Digit Numbers Homework & Practice 2.3

Write how many hundreds, tens, and ones. Show with Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 40. Then draw a quick picture.

Question 1.
118
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 41

Answer:
The number is 118.

Explanation:
In the above-given figure,
given that,
number 118 with 1 hundred, 1 ten, 8 one.
100 + 10 + 8 = 118.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-9

Question 2.
246
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 42

Answer:
The number is 246.

Explanation:
In the above-given figure,
given that,
number 246 with 2 hundred, 4 ten, 6 one.
200 + 40 + 6 = 246.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-10

Problem Solving

Question 3.
Write the number that matches the clues.
• My number has 2 hundred.
• The tens digit is 9 more than the ones digit.
My number is _293__
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 43

Answer:
The number is 293.

Explanation:
In the above-given figure,
given that,
number 293 with 2 hundred, 9 ten, 3 one.
200 + 90 + 3 = 293.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-11

Question 4.
WRITE Math
Write a 3-digit number using digits 2, 9, 4. Draw a quick picture to show the value of your number.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-12

Answer:
The number is 249.

Explanation:
In the above-given figure,
given that,
number 249 with 2 hundred, 4 ten, 9 one.
200 + 40 + 9 = 249.

Lesson Check

Question 1.
What number is shown with these blocks?
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 45

Answer:
The number is 246.

Explanation:
In the above-given figure,
given that,
number 246 with 2 hundred, 4 ten, 6 one.
200 + 40 + 6 = 246.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-13

Spiral Review

Question 2.
Write the number with the same value as 28 tens.
______0__+ ____28____+______0_______________

Answer:
The number is 28.

Explanation:
In the above-given figure,
given that,
number 28 with 0 hundred, 28 ten, 0 one.
0 + 28+ 0 = 28.

Question 3.
Describe 59 in two other ways.
_5_ tens _9_ ones _5_ + _9_

Answer:
The number is 59.

Explanation:
In the above-given figure,
given that,
number 59 with 0 hundred, 5 ten, 9 one.
0 + 5+ 9= 59.

Question 4.
Circle the odd number.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 46

Answer:
The odd number is 11.

Explanation:
In the above-given question:
given that,
circle the odd number.
the numbers are 11, 12, 18, 20.
an odd number is 11.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.3-14

Question 5.
Write the number equal to 7 tens and 3 ones.
____73__________

The number is 73.

Explanation:
In the above-given figure,
given that,
number 73 with 0 hundred, 7 ten, 3 one.
0 + 7 + 3= 73.

Lesson 2.4 Hundreds, Tens, and Ones

Essential Question
How do you write the 3-digit number that is shown by a set of blocks?

Listen and Draw

Write the number of hundreds, tens, and ones. Then draw a quick picture.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 47

Answer:
The number is 246.

Explanation:
In the above-given figure,
given that,
number 246 with 2 hundred, 4 ten, 6 one.
200 + 40 + 6 = 246.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-1

Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 48

Answer:
The number is 264.

Explanation:
In the above-given figure,
given that,
number 264 with 2 hundred, 6 ten, 4 one.
200 + 60 + 4 = 264.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-2

Math Talk
MATHEMATICAL PRACTICES

Describe how the two numbers are alike.
Describe how they are different.

Share and Show MATH BOARD

Write how many hundreds, tens, and ones are in the model. Write the number in two ways.

Question 1.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 49

Answer:
The number is 160.

Explanation:
In the above-given figure,
given that,
number 160 with 1 hundred, 6 ten, 0 one.
100 + 60 + 0 = 160.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-3

Question 2.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 50

Answer:
The number is 225.

Explanation:
In the above-given figure,
given that,
number 225 with 2 hundred, 2 ten, 5 one.
200 + 20 + 5 = 225.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-4

Question 3.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 51

Answer:
The number is 239.

Explanation:
In the above-given figure,
given that,
number 239 with 2 hundred, 3 ten, 9 one.
200 + 30 + 9 = 239.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-5

On Your Own

Write how many hundreds, tens, and ones are in the model. Write the number in two ways.

Question 4.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 52

Answer:
The number is 304.

Explanation:
In the above-given figure,
given that,
number 304 with 3 hundred, 0 ten, 4 one.
300 + 0 + 4 = 304.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-6

Question 5.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 53

Answer:
The number is 378.

Explanation:
In the above-given figure,
given that,
number 378 with 3 hundred, 7 ten, 8 one.
300 + 7 + 8 = 378.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-7

Question 6.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 54

Answer:
The number is 426.

Explanation:
In the above-given figure,
given that,
number 426 with 4 hundred, 2 ten, 6 one.
400 + 2 + 6 = 426.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-8

Solve. Write or draw to explain.

Question 7.
THINK SMARTER A model for my number has 4 ones blocks, 5 tens blocks, and 7 hundreds blocks. What number am I?
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 55

Answer:
The number is 754.

Explanation:
In the above-given figure,
given that,
number 754 with 7 hundred, 5 ten, 4 one.
700 + 5 + 4 = 754.

Problem Solving • Applications

Question 8.
GO DEEPER
The hundreds digit of my number is greater than the tens digit. The ones digit is less than the tens digit. What could my number be? Write it in two ways.
__3__ + _2___ + __1__
_321___

Answer:
The number is 321.

Explanation:
In the above-given figure,
given that,
number 321 with 3 hundred, 2 ten, 1 one.
300 + 2 + 1 = 321.

Question 9.
THINK SMARTER
Karen has these bags of marbles. How many marbles does Karen have?
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 56
___ marbles
Explain how you used the picture to find the number of marbles Karen has.
________200___+___30____+_____0______________
__________230___________________________
_____________________________________

Answer:
230 marbles.

Explanation:
In the above-given question,
Given that,
Karen has 2 bags with 100 marbles.
3 bags of 10 marbles.
Karen has 230 marbles.

TAKE HOME ACTIVITY
• Say a 3-digit number, such as 546.
Have your child draw a quick picture for that number.

Answer:
The number is 546.

Explanation:
In the above-given figure,
given that,
number 546 with 5 hundred, 4 ten, 3 one.
500 + 4 + 6 = 546.

Hundreds, Tens, and Ones homework & Practice 2.4

Write how many hundreds, tens, and ones are in the model. Write the number in two ways.

Question 1.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 57

Answer:
The number is 143.

Explanation:
In the above-given figure,
given that,
number 143 with 1 hundred, 4 ten, 3 one.
100 + 4 + 3 = 143.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-9

Question 2.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 58

Answer:
The number is 245.

Explanation:
In the above-given figure,
given that,
number 245 with 2 hundred, 4 ten,  5 one.
200 + 4 + 5 = 245.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-10

Problem Solving

Question 3.
Write the number that answers the riddle. Use the chart. A model for my number has 6 ones blocks, 2 hundreds blocks, and 3 tens blocks. What number am I?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 59

Answer:
The number is 236.

Explanation:
In the above-given figure,
given that,
number 236 with 2 hundred, 3 ten,  6 one.
200 + 3 + 6 = 236.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-11

Question 4.
WRITE Math Write a number that has a zero in the tens place. Draw a quick picture for your number.
Go Math Grade 2 Answer Key Chapter 2 Numbers to 1,000 60

Answer:
The number is 206.

Explanation:
In the above-given figure,
given that,
number 206 with 2 hundred, 0 ten,  6 one.
200 + 0 + 6 = 206.

Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-12

Lesson Check

Question 1.
Write the number 254 as a sum of hundreds, tens, and ones.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 61

Answer:
The number is 254.

Explanation:
In the above-given figure,
given that,
number 254 with 2 hundred, 5 ten,  4 one.
200 + 5 + 4 = 254.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-13

Question 2.
Write the number 307 as a sum of hundreds, tens, and ones.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 62

Answer:
The number is 307.

Explanation:
In the above-given figure,
given that,
number 307 with 3 hundred, 0 ten,  7 one.
300 + 0 + 7 = 307.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-14

Spiral Review

Question 3.
Describe 83 in two other ways.
_8__ tens _3_ ones
__80_ + _3__

Answer:
The number is 83.

Explanation:
In the above-given figure,
given that,
number 83 with  8 ten,  3 one.
80+ 3 = 83.

Question 4.
Write 86 in words.
__Eightysix________

Answer:
The number is 86.

Explanation:
In the above-given figure,
given that,
number 86 with  8 ten,  6 one.
80+ 6 = 86.

Question 5.
Write the number with the same value as 32 tens.
_________________

Answer:
The number is 32.

Explanation:
In the above-given figure,
given that,
number 32 with  32 ten,  0 one.
32+ 0 = 32.

Question 6.
Circle the odd number.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 63

Answer:
An odd number is 17.

Explanation:
In the above-given question,
given numbers are:
2, 6, 10, and 17.
17 is an odd number.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.4-15

Lesson 2.5 Place Value to 1,000

Essential Question
How do you know the values of the digits in numbers?

Listen and Draw

Write the numbers. Then draw quick pictures.
__ sheets of color paper
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.1

Answer:
Sheets of color paper = 203.

Explanation:
In the above-given question,
given that,
draw a quick picture.
so, I am assuming 203.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-1

__ sheets of plain paper
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.2

Answer:
Sheets of plain paper = 543.

Explanation:
In the above-given question,
given that,
draw a plain picture.
so, I am assuming 543.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-2

Math Talk
MATHEMATICAL PRACTICES

Describe how 5 tens is different from 5 hundred.

Model and Draw

The place of a digit in a number tells its value.
The 3 in 327 has a value of 3 hundred, or 300.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.3
The 2 in 327 has a value of 2 tens, or 20.
The 7 in 327 has a value of 7 ones, or 7.

There are 10 hundreds in 1 thousand
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.4
The 1 is in the thousands place and has a value of 1 thousand.

Share and Show

Circle the value or the meaning of the red digit.

Question 1.
702
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.5

Answer:
The value of the red digit is 2 ones.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 2 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-3

Question 2.
459
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.6

Answer:
The value of the red digit is 50.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 5 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-4

Question 3.
362
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.7

Answer:
The value of the red digit is 300.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 3 hundred.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-5

On Your Own

Circle the value or the meaning of the red digit.

Question 4.
549
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.8

Answer:
The value of the red digit is 40.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 4 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-6

Question 5.
607
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.9

Answer:
The value of the red digit is 7ones.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 7 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-7

Question 6.
1,000
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.10

Answer:
The value of the red digit is 1 thousand.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 1 thousand.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-8

Question 7.
914
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.11

Answer:
The value of the red digit is 9 hundred.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 9 hundred.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-9

Question 8.
THINK SMARTER
The value of the ones digit in George’s favorite number is 2. The value of the hundreds digit is 600 and the value of the tens digit is 90. Write George’s favorite number.
_692___

Answer:
George’s favorite number is 692.

Explanation:
In the above-given question,
Given that,
The value of the one-digit in George’s favorite number is 2.
The value of the hundreds digit is 600.
value of the tens digit is 90.
George’s favorite number is 692.

Question 9.
GO DEEPER
Write the number that matches the clues.

  • The value of my hundreds digit is 300.
  • The value of my tens digit is 0.
  • The value of my ones digit is an even number greater than 7.

The number is _308___

Answer:
The number is 308.

Explanation:
In the above-given question,
given that,
The value of my hundred digits is 300.
value of my tens digit is 0.
value of my one digit is an even number greater than 7 is 8.
The number is 308.

Problem Solving • Applications

Question 10.
THINK SMARTER
Ty is making a Venn diagram. Where in the diagram should he write the other numbers?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.12
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.13

Answer:
The numbers with a 5 in the tens place are 152, 454, 257, 352, and 250.
The numbers with a 2 in the hundreds place are 215, 257, 205, and 250.

Explanation:
In the above-given figure,
given that,
The numbers are 152, 215, 454, 257, 352, 205, and 250.
In a Venn diagram,
The numbers with a 5 in the tens place are 152, 454, 257, 352, and 250.
The numbers with a 2 in the hundreds place are 215, 257, 205, and 250.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-10

Question 11.
MATHEMATICAL PRACTICE
Apply Describe where 752 should be written in the diagram. Explain your answer.
__________________
_________________________
_________________________

Answer:
The number 752 should be written in the numbers with a 5 in the tens place.

Explanation:
In the above-given question,
Given that,
the number 752 should be written in the Venn diagram.
The number 752 should be written in the numbers with a 5 in the tens place.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-11

Question 12.
THINK SMARTER
Fill in the bubble next to all the numbers that have the digit 4 in the tens place
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.14

Answer:
The numbers that have the digit 4 in the tens place are 149, 342.

Explanation:
In the above-given question,
given that,
the numbers that have the digit 4 in the tens place.
The numbers that have the digit 4 in the tens place are 149, 342.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-12

TAKE HOME ACTIVITY
• Ask your child to write 3-digit numbers, such as “a number with 2 hundreds” and “a number with a 9 in the ones place.”

Place Value to 1,000 Homework & Practice 2.5

Circle the value or the meaning of the underlined digit.

Question 1.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.15

Answer:
The value of the underlined digit is 30.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 3 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-13

Question 2.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.16

Answer:
The value of the underlined digit is 2 ones.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 2 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-14

Question 3.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.17

Answer:
The value of the underlined digit is 5 hundred.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 5 hundred.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-15

Question 4.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.18

Answer:
The value of the underlined digit is 7 ones.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 7 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-16

Question 5.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.19

Answer:
The value of the underlined digit is 5 hundred.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 5 hundred.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-17

Problem Solving

Question 6.
Write the 3-digit number that answers the riddle.

Answer:
The number is 454.

Explanation:
In the above-given figure,
Given that,
I have the same hundreds of digits as one digit.
The value of my tens digit is 50.
The value of my ones digit is 4.
So the number is 454.

  • I have the same hundreds digit as ones digit.
  • The value of my tens digit is 50.
  • The value of my ones digit is 4. The number is ____

Question 7.
WRITE Math What is the value of 5 in 756? Write and draw to explain how you know.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.20
_________________________
_________________________

Answer:
The value of 5 in 756 = 50.

Explanation:
In the above-given question,
given that,
the number is 756.
7 is in the hundreds place.
6 is in one place.
so the value of 5 in 756 is tens place.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-18

Lesson Check

Question 1.
What is the value of the underlined digit?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.21

Answer:
The value of the underlined digit is 3 hundred.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 3 hundred.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-19

Question 2.
What is the meaning of the underlined digit?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.22

Answer:
The value of the underlined digit is 4 tens.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 4 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-20

Spiral Review

Question 3.
What number can be written as 40 + 5?
_________45________________

Answer:
The number can be written as 45.

Explanation:
In the above-given question,
given that,
the number is 40 + 5.
so the number can be written as 45.

Question 4.
What number has the same value as 14 tens?
____140_____________________

Answer:
The number can be written as 140.

Explanation:
In the above-given question,
given that,
the number is 100+ 40.
so the number can be written as 140.

Question 5.
Write the number described by 1 ten 16 ones.
_______26__________________

Question 6.
Circle the even number.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 64.23

Answer:
The even number is 16.

Explanation:
In the above-given question,
given that
the numbers are 7, 16, 21, and 25.
7, 21, and 25 are odd numbers.
16 is an even number.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.5-21

Lesson 2.6 Number Names

Essential Question
How do you write 3-digit numbers using words?

Listen and Draw

Write the missing numbers in the chart. Then find and circle the word form of these numbers below.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 71

Answer:
The missing numbers in the chart are 11, 14, 29, 35, 46, and 52.

Explanation:
In the above-given figure,
given that,
The missing numbers are 11, 14, 29, 35, 46, and 52.
circle the word form of the numbers below.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-1

HOME CONNECTION
• In this activity, your child reviewed the word form of numbers less than 100.

Math Talk
MATHEMATICAL PRACTICES
Explain Describe how to use words to write the number with a 5 in the tens place and a 7 in the ones place.

Answer:
The number is 57.

Explanation:
In the above-given figure,
given that,
the number with a 5 in the tens place and a 7 in the one’s place is 57.

Model and Draw

You can use words to write 3-digit numbers. First, look at the hundreds digit. Then, look at the tens digit and ones digit together.
2nd Grade Go Math Answer Key Chapter 2 Numbers to 1,000 72

Share and Show MATH Board

Write the number using words.

Question 1.
506
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 73

Answer:
The number is 506.

Explanation:
In the above-given figure,
given that, the number is 506.
so we have to write five hundred six.

Question 2.
189
__One hundred____Eighty-nine.____

Answer:
The number is 189.

Explanation:
In the above-given figure,
given that, the number is 189.
so we have to write one hundred eighty-nine.

Question 3.
328
__________

Answer:
The number is 328.

Explanation:
In the above-given figure,
given that, the number is 328.
so we have to write three hundred twenty-eight.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-2

Write the number

Question 4.
four hundred fifteen

Answer:
The number is 415

Explanation:
In the above-given figure,
given that, the number is 415
so we have to write 415.

Question 5.
two hundred ninety-one
___491_______

Answer:
The number is 291.

Explanation:
In the above-given figure,
given that, the number is 291.
so we have to write 291.

Question 6.
six hundred three
____603______

Answer:
The number is 603.

Explanation:
In the above-given figure,
given that, the number is 603.
so we have to write 603.

Question 7.
eight hundred forty-seven
___847_______

Answer:
The number is 847.

Explanation:
In the above-given figure,
given that, the number is 847.
so we have to write 847.

On Your Own

Write the number

Question 8.
seven hundred seventeen
__717____

Answer:
The number is 717.

Explanation:
In the above-given figure,
given that, the number is 717.
so we have to write 717.

Question 9.
three hundred ninety
__390____

Answer:
The number is 390.

Explanation:
In the above-given figure,
given that, the number is 390.
so we have to write 390.

Write the number using words.

Question 10.
568
__five hundred sixty-eight.________

Answer:
The number is five hundred sixty-eight

Explanation:
In the above-given figure,
given that, the number is five hundred sixty-eight.
so we have to write five hundred sixty-eight.

Question 11.
321
__ three hundred twenty-one.________

Answer:
The number is three hundred twenty-one.

Explanation:
In the above-given figure,
given that, the number is three hundred twenty-one.
so we have to write three hundred twenty one.

Question 12.
GO DEEPER My 3-digit number has a 4 in the hundreds place. It has a greater digit in the tens place than in the ones place. The sum of the digits is 6.
What is my number? ___420___________
Write the number using words. _four hundred twenty.__________

Answer:
The number is 420.

Explanation:
In the above-given question,
given that,
the 3-digit number has a 4 in the hundreds place.
It has a greater digit in the tens place than in the ones place.
The sum of digits is 6.
The number is 420.

Question 13.
THINK SMARTER Alma counts two hundred sixty-eight leaves. Which is another way to write this number? Circle your answer.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 74

Answer:
The number is 200 + 60 + 8.

Explanation:
In the above-given question,
given that,
Alma counts two hundred sixty-eight leaves.
Another way to write this number is 200 + 60 + 8.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-3

Problem Solving • Applications

Connect Symbols and Words

Circle the answer for each problem.

Question 14.
Derek counts one hundred ninety cars. Which is another way to write this number?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 74.1

Answer:
The number is 100 + 90 + 0.

Explanation:
In the above-given question,
given that,
Derek counts one hundred ninty.
The another way to write this number is 100 + 90 + 0.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-4

Question 15.
Beth counted three hundred fifty-six straws. Which is another way to write this number?
3 + 5 + 6
30 + 50 + 60
300 + 50 + 6

Answer:
The number is 300 + 50 + 6.

Explanation:
In the above-given question,
given that,
Derek counts Three hundred fifty-six straws.
The another way to write this number is 300 + 50 + 6.

Question 16.
THINK SMARTER
There are 537 chairs at the school. Write this number using words.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 75

Show the number in two other ways.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 76

Answer:
The number is 500 + 30 + 7.

Explanation:
In the above-given question,
given that,
Derek counts five hundred thirty-seven straws.
The another way to write this number is 500 + 30 + 7.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-5

TAKE HOME ACTIVITY
• Ask your child to write the number 940 using words.

Number Names Homework & Practice 2.6

Write the number

Question 1.
two hundred thirty-two
____232______

Answer:
The number is 232.

Explanation:
In the above-given figure,
given that, the number is 232.
so we have to write two hundred thirty-two.

Question 2.
five hundred forty-four
_544_____

Answer:
The number is 544.

Explanation:
In the above-given figure,
given that, the number is 544.
so we have to write five hundred forty-four.

Question 3.
one hundred fifty-eight
____158_____

Answer:
The number is 158.

Explanation:
In the above-given figure,
given that, the number is 158.
so we have to write one hundred fifty-eight.

Question 4.
nine hundred fifty
__950____

Answer:
The number is 950.

Explanation:
In the above-given figure,
given that, the number is 950.
so we have to write nine hundred fifty.

Question 5.
four hundred twenty
___420________

Answer:
The number is 420.

Explanation:
In the above-given figure,
given that, the number is 420.
so we have to write four hundred twenty.

Question 6.
six hundred seventy-eight
__678____

Answer:
The number is 678.

Explanation:
In the above-given figure,
given that, the number is 678.
so we have to write six hundred seventy eight.

Write the number using words.

Question 7.
317
_Three hundred seventeen._

Answer:
The number is 317.

Explanation:
In the above-given figure,
given that, the number is 317.
so we have to write three hundred seventeen.

Problem Solving

Circle the answer.

Question 8.
Six hundred twenty-six children attend Elm Street School. Which is another way to write this number?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 77

Answer:
The number is 600 + 20 + 6.

Explanation:
In the above-given question,
given that,
six hundred twenty-six attend EIm street school.
Another way to write this number is 600 + 20 + 6.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-6

Question 9.
WRITE Math Write a 3-digit number using the digits 5, 9, and 2. Then write your number using words.
_________592.____________________________

Answer:
The number is Five hundred ninety-two.

Explanation:
In the above-given question,
given that,
The number is Five hundred ninety-two.
Another way to write this number is 500 + 90 + 2.

Lesson Check

Question 1.
Write the number 851 in words.
_eight hundred fifty-one.___________

Answer:
The number is eight hundred fifty-one.

Explanation:
In the above-given question,
given that,
The number is Five hundred fifty-one.
Another way to write this number is 500 + 50 + 1.

Question 2.
Write the number two hundred sixty using numbers.
___260_________

Answer:
The number is 260.

Explanation:
In the above-given question,
given that,
The number is two hundred sixty.
Another way to write this number is 200 + 60 + 0.

Spiral Review

Question 3.
Write a number with the digit 8 in the tens place.
____284_________

Answer:
The number is 284.

Explanation:
In the above-given question,
given that,
The number is two hundred eighty-four.
Another way to write this number is 200 + 80 + 4.

Question 4.
Write the number shown with these blocks.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 78

Answer:
The number is 245.

Explanation:
In the above-given figure,
given that,
number 245 with 2 hundred, 4 ten,  5 one.
200 + 40 + 5 = 245.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.6-7

Question 5.
Count by fives.
650, 655,
_660__, _665___, _670__

Answer:
The numbers are 660, 665, and 670.

Explanation:
In the above-given figure,
given numbers are,
650, 655.
so the numbers are 660, 665, and 670.

Question 6.
Sam has 128 marbles. How many hundreds are in this number?
_1_ hundred.

Answer:
One hundred.

Explanation:
In the above-given question,
given that,
Sam has 128 marbles.
there is one hundred in this number.

Lesson 2.7 Different Forms of Numbers

Essential Question
What are three ways to write a 3-digit number?

Listen and Draw

Write the number. Use the digits to write how many hundreds, tens, and ones.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 79

Math Talk
MATHEMATICAL PRACTICES

How many hundreds are in 368? Explain.

Model and Draw

You can use a quick picture to show a number. You can write a number in different ways.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 80

Read the number and draw a quick picture. Then write the number in different ways.

Question 1.
four hundred seven
___ hundreds __ tens ___ ones
___ + ___ + ___
______

Answer:
The number is 407.

Explanation:
In the above-given question,
given that,
the number is four hundred seven.
400 + 0 + 7.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-1

Question 2.
three hundred twenty-five
___ hundreds __ tens ___ ones
___ + ___ + ___
______

Answer:
The number is 325.

Explanation:
In the above-given question,
given that,
the number is three hundred twenty-five.
300 + 20 + 5.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-2

Question 3.
two hundred fifty-three
_2__ hundreds _5_ tens _3__ ones
200___ + _50__ + _3__
__253____

Answer:
The number is 253.

Explanation:
In the above-given question,
given that,
the number is two hundred fifty-three.
200 + 50 + 3.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-1

On Your Own

Read the number and draw a quick picture. Then write the number in different ways.

Question 4.
one hundred seventy-two
___ hundreds __ tens ___ ones
___ + ___ + ___
______

Answer:
The number is 172.

Explanation:
In the above-given question,
given that,
the number is one hundred seventy-two.
100 + 70 + 2.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-3

Question 5.
three hundred forty-six
___ hundreds __ tens ___ ones
___ + ___ + ___
______

Answer:
The number is 546.

Explanation:
In the above-given question,
given that,
the number is five hundred forty-six.
500 + 40 + 6.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-1

Question 6.
THINK SMARTER
Think of a 3-digit number with a zero in the ones place. Use words to write that number.
___Five__hundred_____forty.___________

Answer:
The number is five hundred forty.

Explanation:
In the above-given question,
given that,
the number is five hundred forty.
500 + 40 + 0.

Question 7.
THINK SMARTER
Ellen used these blocks to show 452. What is wrong? Cross out blocks and draw quick pictures for missing blocks.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 81

Answer:
The number is four hundred fifty-two.

Explanation:
In the above-given question,
given that,
one hundred blocks are missing, no one’s block.
400 + 50 + 2.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-4

TAKE HOME ACTIVITY
• Ask your child to show the number 315 in three different ways.

Different Forms of Numbers Homework & Practice 2.7

Read the number and draw a quick picture. Then write the number in different ways.

Question 1.
two hundred fifty-one
___ hundreds ___ tens ___one
___ + ____ + _____
_________

Answer:
The number is 2 hundreds 5 tens 1 ones.
200 + 50 + 1.

Explanation:
In the above-given question,
given that,
the number is two hundred fifty-one.
200 + 50 + 1.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-5

Question 2.
three hundred twelve
___ hundreds ___ tens ___one
___ + ____ + _____
_________

Answer:
The number is 3 hundreds 0 tens 12 ones.
300 + 0 + 12.
312.

Explanation:
In the above-given question,
given that,
the number is three hundred twelve.
300 + 0 + 12.

Problem Solving

Write the number another way.

Question 3.
200 + 30 + 7
_237________

Answer:
The number is 2 hundreds 30 tens 7 ones.
200 + 30 + 7.
237.

Explanation:
In the above-given question,
given that,
the number is two hundred thirty-seven.
200 + 30 + 7.

Question 4.
895
__800 + 90 + 5_______

Answer:
The number is 8 hundreds 9 tens 5 ones.
800 + 90 + 5.
895.

Explanation:
In the above-given question,
given that,
the number is eight hundred ninety-five.
800 + 90 + 5.

Question 5.
WRITE Math
Draw a quick picture of 3 hundreds, 5 tens, and 7 ones. What number does your quick picture show? Write it in three different ways.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 82

Answer:
The number is 3 hundreds 5 tens 7 ones.
300 + 50 + 7.
357.

Explanation:
In the above-given question,
given that,
the number is three hundred fifty-seven.
300 + 50 + 7.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-6

Lesson Check

Question 1.
Write the number 392 as hundreds, tens, and ones.
__3__ hundreds __9_ tens _2_ ones

Answer:
The number is 3 hundreds 9 tens 2 ones.
300 + 90 + 2.

Explanation:
In the above-given question,
given that,
the number is three hundred ninety-two.
300 + 90 + 2.

Question 2.
What is another way to write the number 271?
__2__ hundreds __7_ tens _1_ ones

Answer:
The number is 2 hundreds 7 tens 1 ones.
200 + 70 + 1.

Explanation:
In the above-given question,
given that,
the number is three hundred ninety-two.
200 + 70 + 1.

Spiral Review

Question 3.
What is the value of the underlined digit?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 83

Answer:
The value of the underlined digit is 5 tens.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the underlined digit.
The value of the underlined digit is 5 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-7

Question 4.
What number is shown with these blocks?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 84

Answer:
The number is two hundred twelve.

Explanation:
In the above-given question,
given that,
The number is two hundred twelve.

Question 5.
What is another way to write the number 75?
__70__ + _5__

Answer:
The number is 75.

Explanation:
In the above-given question:
given that,
the number is 75.
70 + 5 = 75.

Question 6.
What number can be written as 60 + 3?
__63_____

Answer:
The number is 63.

Explanation:
In the above-given question:
given that,
the number is 63.
60 + 3 = 63.

Numbers to 1,000 Mid-Chapter Checkpoint

Concepts and Skills

Circle tens to make 1 hundred. Write the number in different ways.

Question 1.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 85

Answer:
the number is1 hundred 3 tens.

Explanation:
In the above-given figure,
given that,
the tens are 13.
the number is i hundred 3 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-8

Write how many hundreds, tens, and ones are in the model. Write the number in two ways.

Question 2.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 86

Answer:
the number is 2 hundred 4 tens 3 ones.

Explanation:
In the above-given figure,
given that,
the tens are 243.
the number is 2 hundred 4 tens 3 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-8

Circle the value or the meaning of the red digit.

Question 3.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 87

Answer:
The value of the red digit is 5 hundred.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 5 hundred.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-9

Question 4.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 88

Answer:
The value of the red digit is 4 ones.

Explanation:
In the above-given question,
given that,
circle the value or the meaning of the red digit.
The value of the red digit is 4 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-10

Question 5.
THINK SMARTER
Write the number six hundred forty-five in another way.

Answer:
The number is 645.

Explanation:
In the above-given question,
given that,
the number is six hundred forty-five.
600 + 40 + 5.

Lesson 2.8 Algebra • Different Ways to Show Numbers

Essential Question
How can you use blocks or quick pictures to show the value of a number in different ways?

Listen and Draw

Draw quick pictures to solve. Write how many tens and ones.
____ tens ____ ones

___ tens __ ones

Math Talk
MATHEMATICAL PRACTICES

Model
Describe how you found different ways to show 35 books.

Model and Draw

Here are two ways to show 148.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 89

Share and Show

Write how many hundreds, tens, and ones are in the model.

Question 1.
213
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 90

Answer:
a.There are 2 hundreds 1 tens 3 ones.

Explanation:
In the above-given figure,
given that,
the number is 213.
There are 2 hundreds 0 tens 13 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-11

Answer:
b.There are 2 hundreds 0 tens 13 ones.

Explanation:
In the above-given figure,
given that,
the number is 213.
There are 2 hundreds 0 ten13 ones.

Question 2.
132
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 90.1

Answer:
a.There are 1 hundreds 3 tens 2 ones.

Explanation:
In the above-given figure,
given that,
the number is 132.
There are 1 hundreds 3 ten 2 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-12

Answer:
b.There are 1 hundreds 2 tens 12 ones.

Explanation:
In the above-given figure,
given that,
the number is 132
There are 1 hundreds 2 ten12 ones.

On Your Own

Write how many hundreds, tens, and ones are in the model.

Question 3.
144
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 90.3

Answer:
a.There are 1 hundred 4 tens 4 ones.

Explanation:
In the above-given figure,
given that,
the number is 144.
There are 1 hundred 4 ten 4 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-13

Answer:
b.There are 1 hundred 3 tens 14 ones.

Explanation:
In the above-given figure,
given that,
the number is 144.
There are 1 hundreds 3 ten14 ones.

Question 4.
204
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 91

Answer:
a.There are 1 hundreds 10 tens 4 ones.

Explanation:
In the above-given figure,
given that,
the number is 204.
There are 1 hundreds 10 ten 4 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.7-14

Answer:
b.There are 2 hundreds 0 tens 4 ones.

Explanation:
In the above-given figure,
given that,
the number is 204.
There are 2 hundreds 0 ten 4 ones.

Question 5.
MATHEMATICAL PRACTICE
Make Arguments
Sue said that 200 + 20 + 23 is the same as 200 + 30 + 3. Is she correct? Explain.
_____________________
_____________________
_____________________

Answer:
No sue was not correct.

Explanation:
In the above-given  question,
Given that,
Sue said that 200 + 20 + 23 is the same as 200 + 30 + 3.
200 + 20 + 23 = 243.
200 + 30 + 3 = 233.
No sue was not correct.

Problem Solving • Applications WRITE Math

Marbles are sold in boxes, in bags, or as single marbles. Each box has 10 bags of marbles in it. Each bag has 10 marbles in it.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 92

Answer:
A number of marbles = 100.

Explanation:
In the above-given question,
given that,
Marbles are sold in boxes, in bags, or as single marbles.
Each box has 10 bags of marbles in it.
Each bag has 10 marbles in it.
A number of marbles = 100.

Question 6.
THINK SMARTER
Draw pictures to show two ways to buy 324 marbles.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 92.1

Answer:
a.There are 3 hundreds 2 tens 4 ones.
300 + 20 + 4.
Three hundred twenty-four.

Explanation:
In the above-given figure,
given that,
the number is 324.
There are 3 hundreds 2 tens 4 ones.
300 + 20 + 4.
Three hundred twenty-four.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-1

Question 7.
THINK SMARTER
There is only one box of marbles in the store. There are many bags of marbles and single marbles. Draw a picture to show a way to buy 312 marbles.
How many boxes, bags, and single marbles did you show?
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 93
_____________________________________
_____________________________________

Answer:
A number of marbles = 312.

Explanation:
In the above-given question,
given that,
Marbles are sold in boxes, in bags, or as single marbles.
Each box has 10 bags of marbles in it.
Each bag has 10 marbles in it.
A number of marbles = 312.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-2

TAKE HOME ACTIVITY
• Write the number 156. Have your child draw quick pictures of two ways to show this number.

Answer:
The number is 156.

Explanation:
In the above-given question,
given that,
the number is 156.
100 + 50 + 6 = 156.
100 + 40 + 16 = 156.

Algebra • Different Ways to Show Numbers Homework & Practice 2.8

Write how many hundreds, tens, and ones are in the model.

Question 1.
135
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 94

Answer:
a.There are 1 hundred 3 tens 5 ones.

Explanation:
In the above-given figure,
given that,
the number is 135.
There are 1 hundred 3 tens 5 ones.
Answer:
b.There are 1 hundred 2 tens 15 ones.

Explanation:
In the above-given figure,
given that,
the number is 135.
There are 1 hundreds 2 ten15 ones.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-3

Problem Solving

Markers are sold in boxes, packs, or as single markers. Each box has 10 packs. Each pack has 10 markers.

Question 2.
Draw pictures to show two ways to buy 276 markers.

Answer:
A number of marbles = 276.

Explanation:
In the above-given question,
given that,
Marbles are sold in boxes, in bags, or as single marbles.
Each box has 10 bags of marbles in it.
Each bag has 10 marbles in it.
A number of marbles = 276.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-4

Question 3.
WRITE Math Draw quick pictures to show the number 326.
Go Math Grade 2 Chapter 2 Answer Key Pdf Numbers to 1,000 95

Answer:
The number is three hundred twenty-six.

Explanation:
In the above-given question,
given that,
The number is three hundred twenty-six.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-5

Lesson Check

Question 1.
Write the number that can be shown with this many hundreds, tens, and ones.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 96

Answer:
the number is 1 hundred 2 tens 18 ones.
one hundred thirty-eight.

Explanation:
In the above-given figure,
given that,
the tens are 138.
the number is 1 hundred 2 tens 18 ones.
one hundred thirty-eight.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-6

Question 2.
Write the number that can be shown with this many hundreds, tens, and ones.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 97

Answer:
the number is 2 hundred 15 tens 6 ones.
two hundred twenty-one.

Explanation:
In the above-given figure,
given that,
the tens are 221.
the number is 2 hundred 15 tens 6 ones.
two hundred twenty-one.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-7

Spiral Review

Question 3.
What number can be written as 6 tens 2 ones?
__62_____

Answer:
The number is 62.

Explanation:
In the above-given question:
given that,
the number is 62.
60 + 2 = 62.

Question 4.
What number can be written as 30 + 2?
___32____

Answer:
The number is 32.

Explanation:
In the above-given question:
given that,
the number is 32.
30 + 2 = 32.

Question 5.
Write the number 584 in words.
_five hundred __eighty-four.___

Answer:
the number is 5 hundred 8 tens 4 ones.
five hundred eighty-four.

Explanation:
In the above-given figure,
given that,
the tens are 584.
the number is 5 hundred 8 tens 4 ones.
five hundred eighty-four.

Question 6.
Write the number 29 in words.
__twenty- nine_______

Answer:
The number is 29.

Explanation:
In the above-given question:
given that,
the number is 29.
20 + 9 = 29.

Lesson 2.9 Count On and Count Back by 10 and 100

Essential Question
How do you use place value to find 10 more, 10 less, 100 more, or 100 less than a 3-digit number?

Listen and Draw

Draw quick pictures for the numbers.

Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 98

Answer:
10 less than girls:
The number of girls = 263.
10 less than boys:
The number of boys = 142.

Explanation:
In the above-given question,
given that,
The number of girls = 273.
10 less than = 263.
The number of boys = 152.
10 less than = 142.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.8-8

Math Talk
MATHEMATICAL PRACTICES

Describe how the two numbers are different.

Model and Draw

You can show 10 less or 10 more than a number by changing the digit in the tens place.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 99

You can show 100 less or 100 more than a number by changing the digit in the hundreds place.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 100

Share and Show

Write the number

Question 1.
10 more than 648
_658______

Answer:
The number is 658.

Explanation:
In the above-given question:
given that,
10 more than 648.
The value in the 10’s digit is changed.
The number is 658.

Question 2.
100 less than 513
___413___

Answer:
The number is 413.

Explanation:
In the above-given question:
given that,
100 less than 513.
The value in the 100’s digit is changed.
The number is 413.

Question 3.
100 more than 329
___429____

Answer:
The number is 429.

Explanation:
In the above-given question:
given that,
100 more than 429.
The value in the 100’s digit is changed.
The number is 429.

Question 4.
10 less than 827
____817_____

Answer:
The number is 817.

Explanation:
In the above-given question:
given that,
10 less than 827.
The value in the 10’s digit is changed.
The number is 817.

On Your Own

Question 5.
10 more than 471
_____481______

Answer:
The number is 481.

Explanation:
In the above-given question:
given that,
10 more than 471.
The value in the 10’s digit is changed.
The number is 481.

Question 6.
10 less than 143
____133______

Answer:
The number is 133.

Explanation:
In the above-given question:
given that,
10 less than 143.
The value in the 10’s digit is changed.
The number is 133.

Question 7.
100 more than 555
____655_________

Answer:
The number is 655.

Explanation:
In the above-given question:
given that,
100 more than 555.
The value in the 100’s digit is changed.
The number is 655.

Question 8.
100 less than 757
_______657_____

Answer:
The number is 657.

Explanation:
In the above-given question:
given that,
100 less than 757.
The value in the 100’s digit is changed.
The number is 657.

Question 9.
100 more than 900
___1000___

Answer:
The number is 1000.

Explanation:
In the above-given question:
given that,
100 more than 900.
The value in the 100’s digit is changed.
The number is 1000.

Question 10.
10 less than 689
____679_____

Answer:
The number is 679.

Explanation:
In the above-given question:
given that,
10 less than 689.
The value in the 10’s digit is changed.
The number is 679.

Question 11.
100 less than 712
___612______

Answer:
The number is 612.

Explanation:
In the above-given question:
given that,
100 less than 712.
The value in the 100’s digit is changed.
The number is 612.

Question 12.
10 less than 254
_____244____

Answer:
The number is 244.

Explanation:
In the above-given question:
given that,
10 less than 254.
The value in the 10’s digit is changed.
The number is 244.

Question 13.
THINK SMARTER
Kyla wrote the riddle below. Fill in the blanks to make the sentence true.
__938___ is 10 less than 948 and 10 more than 958_____

Answer:
10 less than:
The number is 938.
10 more than:
The number is 958.

Explanation:
In the above-given question:
given that,
10 less than 948.
The value in the 10’s digit is changed.
The number is 938.
10 more than:
The number is 958.

Question 14.
THINK SMARTER
Rick has 10 more crayons than Lori. Lori has 136 crayons. Tom has 10 fewer crayons than Rick. How many crayons does each child have?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 101
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 101.1

Answer:
Rick has 146 crayons.
tom has 126 crayons.
Lori has 136 crayons.

Explanation:
In the above-given question,
given that, Lori has 136 crayons.
Rick has 10 more crayons than Lori.
tom has 10 fewer crayons than Rick.
Rick has 146 crayons.
tom has 126 crayons.
Lori has 136 crayons.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.9-1

Problem Solving • Applications

Analyze Relationships

Question 15.
Juan’s book has 248 pages. This is 10 more pages than there are in Kevin’s book. How many pages are in Kevin’s book?
_238___ pages

Answer:
In Kevin’s book, there are 238.

Explanation:
In the above-given question,
Given that,
Juan’s book has 248 pages.
This is more pages than there in kevin’s book.

Question 16.
There are 217 pictures in Tina’s book. There are 100 fewer pictures in Mark’s book. How many pictures are in Mark’s book?
_317___ pages

Answer:
In mark’s book, there are 317 pictures.

Explanation:
In the above-given question,
Given that,
There are 217 pictures in Tina’s book.
There are 100 fewer pictures in mark’s book.
In mark’s book, there are 317 pictures.

Question 17.
GO DEEPER
Use the clues to answer the question.

  • Shawn counts 213 cars.
  • Maria counts 100 fewer cars than Shawn.
  • Jayden counts 10 more cars than Maria.

How many cars does Jayden count?
_123__ cars

Answer:
Jayden counts 123 cars.

Explanation:
In the above-given question,
given that,
Shawn counts 213 cars.
Maria counts 100 fewer cars than Shawn.
Jayden counts 10 more cars than Maria.
Jayden counts 123 cars.

Question 18.
THINK SMARTER
Rico has 235 stickers. Gabby has 100 more stickers than Rico. Thomas has 10 fewer stickers than Gabby. Write the number of stickers each child has.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 102

Answer:
Rico has 235 stickers.
Gabby has 335 stickers.
Thomas has 325 stickers.

Explanation:
In the above-given question,
given that,
Rico has 235 stickers.
Gabby has 100 more stickers than Rico.
Thomas has 10 fewer stickers than Gabby.
Rico has 235 stickers.
Gabby has 335 stickers.
Thomas has 325 stickers.

TAKE HOME ACTIVITY
• Write the number 596. Have your child name the number that is 100 more than 596.

Answer:
The number is 696.

Explanation:
In the above-given question:
given that,
100 more than 596.
The value in the 100’s digit is changed.
The number is 696.

Count On and Count Back by 10 and 100 Homework & Practice 2.9

Write the number.

Question 1.
10 more than 451
__461________

Answer:
The number is 461.

Explanation:
In the above-given question:
given that,
10 more than 451.
The value in the 10’s digit is changed.
The number is 461.

Question 2.
10 less than 770
___760______

Answer:
The number is 760.

Explanation:
In the above-given question:
given that,
10 less than 770.
The value in the 10’s digit is changed.
The number is 760.

Question 3.
100 more than 367
__467_______

Answer:
The number is 467.

Explanation:
In the above-given question:
given that,
100 more than 367.
The value in the 100’s digit is changed.
The number is 467.

Question 4.
100 less than 895
__795_______

Answer:
The number is 795.

Explanation:
In the above-given question:
given that,
100 less than 895.
The value in the 100’s digit is changed.
The number is 795.

Question 5.
10 less than 812
__802______

Answer:
The number is 802.

Explanation:
In the above-given question:
given that,
10 less than 812.
The value in the 10’s digit is changed.
The number is 802.

Question 6.
100 more than 543
___553_______

Answer:
The number is 553.

Explanation:
In the above-given question:
given that,
100 more than 543.
The value in the 100’s digit is changed.
The number is 553.

Question 7.
10 more than 218
___228______

Answer:
The number is 228.

Explanation:
In the above-given question:
given that,
10 more than 218.
The value in the 10’s digit is changed.
The number is 228.

Question 8.
100 more than 379
__389________

Answer:
The number is 389.

Explanation:
In the above-given question:
given that,
100 more than 379.
The value in the 100’s digit is changed.
The number is 389.

Problem Solving

Solve. Write or draw to explain.

Question 9.
Sarah has 128 stickers. Alex has 10 fewer stickers than Sarah. How many stickers does Alex have?
_118___ stickers

Answer:
Alex has 118 stickers.

Explanation:
In the above-given question,
given that,
Sarah has 128 stickers.
Alex has 10 fewer stickers than Sarah.
Alex has 118 stickers.

Question 10.
WRITE Math
Choose any 3-digit number. Describe how to find the number that is 10 more.
___373____
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 103

Answer:
The number is 373.

Explanation:
In the above-given question:
given that,
10 more than 363.
The value in the 10’s digit is changed.
The number is 373.

Lesson Check

Question 1.
Write the number that is 10 less than 526.
___516______

Answer:
The number is 516

Explanation:
In the above-given question:
given that,
10 less than 526.
The value in the 10’s digit is changed.
The number is 526.

Question 2.
Write the number that is 100 more than 487.
__497_____

Answer:
The number is 497.

Explanation:
In the above-given question:
given that,
100 more than 487.
The value in the 100’s digit is changed.
The number is 497.

Spiral Review

Question 3.
Write another way to describe 14 tens.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 104

Answer:
The number is 0 hundred 14 tens.

Explanation:
In the above-given question:
given that,
the number is 104.
100 + 4 = 104.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.9-2

Question 4.
What is the value of the underlined digit?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 105

Answer:
The value of the underlined digit is 8 tens.

Explanation:
In the above-given question,
given that,
the value or the meaning of the underlined digit.
The value of the underlined digit is 8 tens.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.9-3

Question 5.
What number can be written as 30 + 5?
___35______

Answer:
The number is 35.

Explanation:
In the above-given question:
given that,
the number is 35.
30 + 5 = 35.

Question 6.
What number can be written as 9 tens and 1 one?
___191_______

Answer:
The number is 91.

Explanation:
In the above-given question:
given that,
the number is 91.
90 + 1 = 91.

Lesson 2.10 Algebra • Number Patterns

Essential Question
How does place value help you identify and extend counting patterns?

Listen and Draw

Shade the numbers in the counting pattern.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 106

Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.9-4

Math Talk
MATHEMATICAL PRAACTICES

Look for Structure What number is next in the counting pattern you see ? Explain.

Model and Draw

Look at the digits in the numbers. What two numbers are next in the counting pattern?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 107

The _100__ digit changes by one each time. The next two numbers are __514_ and __614_.

Answer:
The hundreds of digit changes by one each time.
the next two numbers are 514, and 614.

Explanation:
In the above-given question,
given that,
the hundreds digit is increased.
The next two numbers are 514, and 614.

Share and Show

Look at the digits to find the next two numbers.

Question 1.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 108
The next two numbers are _177_ and _187__

Answer:
The next two numbers are 177 and 187.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next two numbers are 177 and 187.

Question 2.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 109
The next two numbers are 645__ and _745__

Answer:
The next two numbers are 645 and 745.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next two numbers are 645 and 745.

Question 3.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 110
The next two numbers are 461__ and _471__

Answer:
The next two numbers are 461 and 471.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next two numbers are 461 and 471.

Question 4.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 111
The next two numbers are _789_ and __889_

Answer:
The next two numbers are 789 and 889.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next two numbers are 789 and 889.

On Your Own

Look at the digits to find the next two numbers.

Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 111.1

Question 5.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 112
The next two numbers are _593_ and _693__

Answer:
The next two numbers are  593 and 693.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next two numbers are 593 and 693.

Question 6.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 113
The next two numbers are _524_ and _534__

Answer:
The next two numbers are 524 and 534.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next two numbers are 524 and 534.

Question 7.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 114
The next two numbers are _900_ and _1000__

Answer:
The next two numbers are  900 and 1000.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next two numbers are 900 and 1000.

Question 8.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 115
The next two numbers are _695_ and _705__

Answer:
The next two numbers are 695 and 705.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next two numbers are 695 and 705.

Question 9.
THINK SMARTER
Mark read 203 pages.
Laney read 100 more pages than Mark. Gavin read 10 fewer pages than Laney. How many pages did Gavin read?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 116

Answer:
Gavin read 293 pages.

Explanation:
In the above-given question,
Given that,
Mark read 203 pages.
Lane read 100 more pages than Mark.
Gavin read 10 fewer pages than Laney.
Gavin read 293 pages
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.9-5.

Problem Solving • Applications

Solve.

Question 1.
GO DEEPER
There were 135 buttons in a jar. After Robin put more buttons into the jar, there were 175 buttons in the jar. How many groups of 10 buttons did she put into the jar?
___ groups of 10 buttons
Explain how you solved the problem.
_____________________________________
_____________________________________
_____________________________________

Answer:
Robin put 3 groups of 10 buttons.

Explanation:
In the above-given question,
Given that,
There were 135 buttons in a jar.
After robin put more buttons into the jar, there were 175 buttons in the jar.
Robin put 3 groups of 10 buttons.

Question 11.
THINK SMARTER
Write the next number in each counting pattern.
162, 262, 362, 462, _562____

Answer:

Answer:
The next number is 562.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next  number is 562.

347, 357, 367, 377, _387___

Answer:
The next number is 387.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next  number is 387.

609, 619, 629, 639, _649__

Answer:
The next number is 649.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next number is 649.

TAKE HOME ACTIVITY
• With your child, take turns writing number patterns in which you count on by tens or by hundreds.

Algebra • Number Patterns Homework & Practice 2.10

Look at the digits to find the next two numbers.

Question 1.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 117
The next two numbers are _272__ and _282__

Answer:
The next two numbers are  272 and 282.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next two numbers are 272 and 282.

Question 2.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 118
The next two numbers are _585__ and _685__

Answer:
The next two numbers are  585 and 685.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next two numbers are 585 and 685.

Question 3.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 119
The next two numbers are _828__ and _928__

Answer:
The next two numbers are  828 and 928.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next two numbers are 828 and 928.

Question 4.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 120
The next two numbers are _694__ and _704__

Answer:
The next two numbers are  694 and 704.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next two numbers are 694 and 704.

Problem Solving

Question 5.
What are the missing numbers in the pattern?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 121
The missing numbers are _471__ and _501__

Answer:
The missing numbers are 471 and 501.

Explanation:
In the above-given question,
given that,
The numbers are 431, 441, 451, 461,481, 491.
The missing numbers are 471 and 501.

Question 6.
WRITE Math How can you tell when a pattern shows counting on by tens?
_____________
_____________
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 122

Lesson Check

Question 1.
What is the next number in this pattern?
453, 463, 473, 483,
__493___

Answer:
The next number is 493.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 10 in 10’s place.
The next number is 493.

Question 2.
What is the next number in this pattern?
295, 395, 495, 595,
___695___

Answer:
The next number is 695.

Explanation:
In the above-given question,
given that,
the numbers are increasing by 100 in 100’s place.
The next number is 695.

Spiral Review

Question 3.
Write the number seven hundred fifty-one with digits.
_751__

Answer:
The number is 751.

Explanation:
In the above-given figure,
given that, the number is 751.
so we have to write 751.

Question 4.
What is the value of the underlined digit?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 123
____

Answer:
The value of the underlined digit is 1 hundred.

Explanation:
In the above-given question,
given that,
the value or the meaning of the underlined digit.
The value of the underlined digit is 1 hundred.

Question 5.
What is another way to write 56?
_5_ tens _6_ ones

Question 6.
Write the number 43 in tens and ones.
_4_ tens _3_ ones

Answer:
The number is 4 tens and 3 ones.

Explanation:
In the above-given question,
given that,
the number is 4 tens and 3 ones.
the number is 43.

Lesson 2.11 Problem Solving • Compare Numbers

Essential Question
How can you make a model to solve a problem about comparing numbers?

Children bought 217 boxes of chocolate milk and 188 boxes of plain milk. Did they buy more boxes of chocolate milk or plain milk?

Unlock the Problem
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 124
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 124.1

Answer:
Children bought 217 boxes of chocolate milk.
Children bought 188 boxes of plain milk.

Explanation:
In the above-given question,
given that,
They bought more boxes of chocolate milk.
Children bought 217 boxes of chocolate milk.
Children bought 188 boxes of plain milk.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.11-1

Show how to solve the problem.
Model the numbers. Draw quick pictures of your models
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 125

The children bought more boxes of ___ milk.

Answer:
Children bought 217 boxes of chocolate milk.
Children bought 188 boxes of plain milk.

Explanation:
In the above-given question,
given that,
They bought more boxes of chocolate milk.
Children bought 217 boxes of chocolate milk.
Children bought 188 boxes of plain milk.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.11-2

HOME CONNECTION
• Your child used base-ten blocks to represent the numbers in the problem. These models were used as a tool for comparing numbers to solve the problem.

Try Another Problem

Model the numbers. Draw quick pictures to show how you solved the problem.
v

Question 1.
At the zoo, there are 137 birds and 142 reptiles. Are there more birds or more reptiles at the zoo?
more _reptiles______

Answer:
There are more reptiles.

Explanation:
In the above-given question,
given that,
there are 137 birds and 142 reptiles.
there are more reptiles.

Question 2.
Tom’s book has 105 pages. Delia’s book has 109 pages. Whose book has fewer pages?
__Tom’s____ book

Answer:
Tom’s book has 105 pages.

Explanation:
In the above-given question,
given that,
Tom’s book has 105 pages.
Delia’s book has 109 pages.
Tom’s book has 105 pages.

Math Talk
MATHEMATICAL PRACTICES
Compare Explain what you did to solve the second problem.

Share and Show MATH BOARD

Model the numbers. Draw quick pictures to show how you solved the problem.

Question 3.
Mary’s puzzle has 164 pieces. Jake’s puzzle has 180 pieces. Whose puzzle has more pieces?
__Jake’s____ puzzle

Answer:
Jake’s puzzle has more pieces.

Explanation:
In the above-given question,
given that,
Mary’s puzzle has 164 pieces.
Jake’s puzzle has 180 pieces.
Jake’s puzzle has more pieces.
Question 4.
There are 246 people at the game. There are 251 people at the museum. At which place are there fewer people?
at the _game____

Answer:
There are fewer people at the game.

Explanation:
In the above-given question,
given that,
There are 246 people at the game.
there are 251 people at the museum.
There are fewer people at the game.

Question 5.
There are 131 crayons in a box. There are 128 crayons in a bag. Are there more crayons in the box or in the bag?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 127
in the _box___

Answer:
There are more crayons in the box.

Explanation:
In the above-given question,
given that,
There are 131 crayons in a box.
There are 128 crayons in a bag.
There are more crayons in the box.

Question 6.
There are 308 books in the first room. There are 273 books in the second room. In which room are there fewer books?
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 128
in the _second__ room.

Answer:
In the second room, there are 273 books.

Explanation:
In the above-given question,
given that,
There are 308 books in the first room.
There are 273 books in the second room.
In the second room, there are 273 books.

Problem Solving • Applications

Question 7.
THINK SMARTER
There are 748 children at Dan’s school. There are 651 children at Karen’s school. There are 763 children at Jason’s school. Which school has more than 759 children?
_Jason’s__ school
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 129

Answer:
In Jason’s school, there are 763 children.

Explanation:
In the above-given question,
given that,
There are 748 children at Dan’s school.
There are 651 children at Karen’s school.
There are 763 children at Jason’s school.
In Jason’s school, there are 763 children.

Question 8.
MATHEMATICAL PRACTICE
Analyze There are 136 crayons in a box. Use the digits 4, 1, and 2 to write a number that is greater than 136.
Go Math Answer Key Grade 2 Chapter 2 Numbers to 1,000 130
__142_______

Answer:
The number greater than 136 is 142.

Explanation:
In the above-given question,
given that,
There are 136 crayons in a box.
The number greater than 136 is 142.

Question 9.
THINK SMARTER
Becky has 134 stamps. Sara has 129 stamps. Who has more stamps?
_____Becky________

Answer:
Becky has more stamps.

Explanation:
In the above-given question,
given that,
Becky has 134 stamps.
Sara has 129 stamps.
Becky has more stamps.

Sara buys 10 more stamps. Who has more stamps now?
_____Sara________

Answer:
Sara has more stamps.

Explanation:
In the above-given explanation,
given that,
Sara buys 10 more stamps.
Sara has more stamps now.
Draw quick pictures to show the stamps Becky and Sara have now.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 131

TAKE HOME ACTIVITY
• Ask your child to explain how he or she solved one of the problems on this page.

Problem Solving • Compare Numbers Homework & Practice 2.11

Model the numbers. Draw quick pictures to show how you solved the problem.

Question 1.
Lauryn has 128 marbles. Kristin has 118 marbles. Who has more marbles?
__Lauryn_______

Answer:
Lauryn has more marbles.

Explanation:
In the above-given question,
given that,
Lauryn has 128 marbles.
Kristin has 118 marbles.
Lauryn has more marbles.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.11-3

Question 2.
Nick has 189 trading cards. Kyle has 198 trading cards. Who has fewer cards?
__Nick_____

Answer:
Nick has fewer cards.

Explanation:
In the above-given question,
given that,
Nick has 189 cards.
Kyle has 198 cards.
Nick has fewer cards.

Question 3.
A piano has 36 black keys and 52 white keys. Are there more black keys or white keys on a piano?
__White Keys________

Answer:
There are more white keys.

Explanation:
In the above-given question,
given that,
A piano has 36 black keys and 52 white keys.
There are more white keys.

Question 4.
WRITE Math Draw to show how you can use models to compare 345 and 391.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 132

Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.11-4

Lesson Check

Question 1.
Gina has 245 stickers. Circle the number less than 245.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 133

Answer:
The number less than 245 is 239.

Explanation:
In the above-given question,
given that,
Gina has 245 stickers.
The numbers are 285, 254, 245, and 239.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.11-5

Question 2.
Carl’s book has 176 pages. Circle the number greater than 176.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 134

Answer:
The number greater than 176 is 203.

Explanation:
In the above-given question,
given that,
Carl’s book has 176 pages.
The numbers are 203, 174, 168, and 139.
The number greater than 176 is 203.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.11-6

Spiral Review

Question 3.
Write 63 as a sum of tens and ones
__6_ + _3__

Answer:
The number has 6 tens and 3 ones.

Explanation:
In the above-given question:
given that,
the number is 63.
60 + 3 = 63.

Question 4.
Write the number 58 in tens and ones.
__5_ tens _8_ ones

Answer:
The number has 5 tens and 8 ones.

Explanation:
In the above-given question:
given that,
the number is 58.
50 + 8 = 58.

Question 5.
Mr. Ford drove 483 miles during his trip. How many hundreds are in this number?
__4__

Answer:
They are 4 hundred in 483.

Explanation:
In the above-given question,
given that,
Mr. Ford drove 483 miles during his trip.
They are 4 hundred in 483.

Question 6.
Write 20 in words.
__twenty____

Answer:
The number is twenty.

Explanation:
In the above-given question,
given that,
Write 20 in words.
The number is twenty.

Lesson 2.12 Algebra • Compare Numbers

Essential Question
How do you compare 3-digit numbers?

Listen and Draw

Draw quick pictures to solve the problem.

More ___ were at the park.

Math Talk
MATHEMATICAL PRACTICES

Explain how you compared the numbers.

Share and Show

Compare the numbers. Write >, <, or =.

Question 1.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 136

Answer:
239 is greater than 179.

Explanation:
In the above-given question,
given that,
179 is less than 239
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-1

Question 2.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 137

Answer:
435 is less than 437.

Explanation:
In the above-given question,
given that,
435 is less than 437.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-2

Question 3.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 138

Answer:
764 is greater than 674.

Explanation:
In the above-given question,
given that,
764 is greater than 674.

Question 4.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 139

Answer:
519 is less than 572.

Explanation:
In the above-given question,
given that,
519 is less than 572.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-3

On Your Own

Compare the numbers. Write >, <, or =.

Question 5.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 140

Answer:
378 is less than 504.

Explanation:
In the above-given question,
given that,
378 is less than 504.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-4

Question 6.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 141

Answer:
821 is equal to 821.

Explanation:
In the above-given question,
given that,
821 is equal to 821.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-5

Question 7.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 142

Answer:
560 is greater than 439.

Explanation:
In the above-given question,
given that,
560 is greater than 439.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-6

Question 8.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 143

Answer:
934 is equal to 934.

Explanation:
In the above-given question,
given that,
934 is equal to 934.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-7

THINK SMARTER Write the 3-digit numbers and compare the numbers. Use >, <, or =.

Question 9.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 144

Answer:
475 is equal to 475.

Explanation:
In the above-given question,
given that,
475 is equal to 475.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-8

Question 10.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 145

Answer:
736 is greater than 687.

Explanation:
In the above-given question,
given that,
736 is greater than 687.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-9

MATHEMATICAL PRACTICE
Use Reasoning Write a 3-digit number in the box that makes the comparison true.

Question 11.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 146

Answer:
526 is less than 670.

Explanation:
In the above-given question,
given that,
526 is less than 670.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-10

Question 12.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 147

Answer:
319 is greater than 500.

Explanation:
In the above-given question,
given that,
319 is greater than 500.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-11

Question 13.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 148

Answer:
526 is less than 782.

Explanation:
In the above-given question,
given that,
526 is less than 782.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-12

Question 14.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 149

Answer:
90 is less than 131.

Explanation:
In the above-given question,
given that,
90 is less than 131.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-13

Problem Solving • Applications

Solve. Write or draw to explain.

Question 15.
THINK SMARTER
Mrs. York has 300 red stickers, 50 blue stickers, and 8 green stickers. Mr. Reed has 372 stickers. Who has more stickers?
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 150

Answer:
Mr. Reed has more stickers.

Explanation:
In the above-given question,
given that,
Mrs. York has 357 red stickers.
Mr. Reed has 372 stickers.
Mr. Reed has more stickers
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-14

Question 16.
MATHEMATICAL PRACTICE
Analyze Jasmine has some number cards. Use the digits on these cards to make two 3-digit numbers. Use each digit only once. Compare
the numbers.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 151
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 152

Answer:
125 is less than 638.

Explanation:
In the above-given question.
given that,
Jasmine has 125 and 638 number cards.
125 is less than 638.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-15

Question 17.
THINK SMARTER
Is the comparison true? Choose Yes or No.
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 153

Answer:
yes.
No.
No.
yes.

Explanation:
In the above-given question,
given that,
453 is greater than 354.
253 is less than 164.
391 is less than 417.
490 is less than 528.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-16

TAKE HOME ACTIVITY
• Have your child explain how to compare the numbers 281 and 157.

Algebra • Compare Numbers Homework & Practice 2.12

Compare the numbers. Write >, <, or =.

Question 1.
489
605
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 154

Answer:
489 is less than 605.

Explanation:
In the above-given question,
given that,
489 is less than 605.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-17

Question 2.
719
719
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 155

Answer:
719 is equal to 719.

Explanation:
In the above-given question,
given that,
719 is equal to 719
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-18
Question 3.
370
248
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 156

Answer:
370 is greater than 248.

Explanation:
In the above-given question,
given that,
370 is greater than 248.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-19

Question 4.
645
654
2nd Grade Go Math Answer Key Chapter 2 Numbers to 1,000 157

Answer:
645 is less than 654.

Explanation:
In the above-given question,
given that,
645 is less than 654.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-20

Question 5.
205
250
2nd Grade Go Math Answer Key Chapter 2 Numbers to 1,000 158

Answer:
205 is less than 250

Explanation:
In the above-given question,
given that,
205 is less than 250
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-21

Question 6.
813
781
2nd Grade Go Math Answer Key Chapter 2 Numbers to 1,000 159

Answer:
813 is greater than 781

Explanation:
In the above-given question,
given that,
813 is greater than 781.
Go-Math-Grade-2-Chapter-2-Answer-key-Numbers-to-1000-2.12-22

Problem Solving

Solve. Write or draw to explain.

Question 7.
Toby has 178 pennies. Bella has 190 pennies. Who has more pennies?
_Bella___ has more pennies.

Answer:
Bella has more pennies.

Explanation:
In the above-given question,
given that,
Toby has 178 pennies.
Bella has 190 pennies.
Bella has more pennies.

Question 8.
WRITE Math
Explain how comparing 645 and 738 is different from comparing 645 and 649.
_____________________
_____________________
Go Math 2nd Grade Answer Key Chapter 2 Numbers to 1,000 160

Lesson Check

Question 1.
Write >, <, or = to compare.
2nd Grade Go Math Answer Key Chapter 2 Numbers to 1,000 161

Answer:
351 is greater than 315.

Explanation:
In the above-given question,
given that,
315 is less than 351.

Question 2.
Write >, <, or = to compare.
2nd Grade Go Math Answer Key Chapter 2 Numbers to 1,000 162

Answer:
401 is greater than 399.

Explanation:
In the above-given question,
given that,
401 is less than 399.

Spiral Review

Question 3.
What number has the same value as 50 tens?
__5 tens 0 ones_______

Answer:
The number has the same value as 50 is 5 tens 0 ones.

Explanation:
In the above-given question,
given that,
The number has the same value as 50 tens.

Question 4.
Write a number with an 8 in the hundreds place.
____803____

Answer:
The number with an 8 in the hundreds place is 803.

Explanation:
In the above-given question,
given that,
The number with an 8 in the hundreds place is 803.

Question 5.
Ned counts by fives. He starts at 80. Which number should he say next?
____85______

Answer:
He should say 85.

Explanation:
In the above-given question,
given that,
Ned counts by fives.
He starts at 80.
He should say 85.

Question 6.
Mr. Dean has an even number of cats and an odd number of dogs. Show how many dogs and cats he might have.
6 cats and _9_ dogs

Answer:
6 cats and 9 dogs.

Explanation:
In the above-given question,
given that,
Mr. Dean has an even number of cats and an odd number of dogs.
There are 6 cats and 9 dogs.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers

go-math-grade-4-chapter-3-multiply-2-digit-numbers-answer-key

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Go Math Grade 4 Solution Key Pdf Chapter 3 Multiply 2-Digit Numbers

With the help of HMH Go Math Grade 4 Answer Key Ch 3, you can learn the easy methods to solve problems. Answer Key for HMH Go Math Grade 4 Chapter 3 Multiply 2-Digit Numbers consists of all the questions from practice tests, exercises, assessments tests. You guys are recommended to solve the 4th grade Go Math Answers of Chapter 3 Multiply 2-Digit Numbers regularly & attempt the exams with confidence. The topics covered in the Go Math HMH grade 4 Solutions are designed perfectly & in an understandable way.

Lesson 1: Multiply by Tens

Lesson 1: Multiply by Tens

Lesson 2: Estimate Products

Lesson 3: Investigate • Area Models and Partial Products

Lesson 3: Investigate • Area Models and Partial Products

Lesson 4: Multiply Using Partial Products

Mid-Chapter Checkpoint

Lesson 5: Multiply with Regrouping

Lesson 5: Multiply with Regrouping

Lesson 6: Choose a Multiplication Method

Lesson 7: Problem Solving • Multiply 2-Digit Numbers

Lesson 7: Problem Solving • Multiply 2-Digit Numbers

Review/Test

Common Core – Page No. 149

Multiply by Tens

Choose a method. Then find the product.

Question 1.
16 × 60 = 960
Use the halving-and-doubling strategy.
Find half of 16: 16 ÷ 2 = 8.
Multiply this number by 60: 8 × 60 = 480
Double this result: 2 × 480 = 960

Answer:
960

Explanation:
Use the halving-and-doubling strategy.
Find half of 16: 16 ÷ 2 = 8.
Multiply this number by 60: 8 × 60 = 480
Double this result: 2 × 480 = 960

Question 2.
80 × 22 = ______

Answer:
1760

Explanation:
By using the place value method, Multiply 80 x 22
You can think of 80 as 8 tens
80 x 22 = (22 x 8) tens
= 176 tens
= 176 x 10 = 1760
80 x 22 = 1760

Question 3.
30 × 52 = ______

Answer:
1560

Explanation:
Use the Associative Property
You can think of 30 as 3 x 10
30 x 52 = (3 x 10) x 52
= 3 x (10 x 52)
=  3 x 520
= 1560
30 x 52 = 1560

Question 4.
60 × 20 = ______

Answer:
1200

Explanation:
60 x 20
Use the halving and doubling strategy
half of the 60 to make the problem simpler
60/ 2 = 30
Multiply 30 with 20
30 x 20 = 600
Double the 600
2 x 600= 1200
60 x 20 = 1200

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 149 Q5

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 149 Q6

Question 7.
31 × 50 = ______

Answer:
1,550

Explanation:
Use the place value method to multiply 31 x 50
You can think of 50 as 5 tens
31 x 50 = 31 x 5 tens
= 155 tens
= 1,550
31 x 50 = 1,550

Problem Solving

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 149 Q8
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 149 Q8.1

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 149 Q9

Common Core – Page No. 150

Lesson Check

Question 1.
For the school play, 40 rows of chairs are set up. There are 22 chairs in each row. How many chairs are there in all?
Options:
a. 800
b. 840
c. 880
d. 8,800

Answer:
c. 880

Explanation:
As per the given data
For the school play, 40 rows of chairs are available. 22 chairs are available in each row.
Then total chairs in school play are = 22 x 40
By using the place value method
You can think of 40 as 4 tens
22 x 40 = 22 x 4 tens
= 88 tens
= 880
Total chairs in school are = 880

Question 2.
At West School, there are 20 classrooms. Each classroom has 20 students. How many students are at West School?
Options:
a. 40
b. 400
c. 440
d. 4,000

Answer:
b. 400

Explanation:
From the given data,
Total classrooms in west school = 20
Number of students per each classroom = 20
Then, total students at West School = 20 x 20
By using the associative property
You can think of 20 as 2 x 10
20 x 20 = 20 x (2 x 10)
= (20 x 2) x 10
=(40) x 10
=400
Total number of students at West School = 400

Spiral Review

Question 3.
Alex has 48 stickers. This is 6 times the number of stickers Max has. How many stickers does Max have?
Options:
a. 6
b. 7
c. 8
d. 9

Answer:
c. 8

Explanation:
As per the give data,
Alex has 48 stickers
That means, X= 48
This is 6 times the number of stickers max has = Y = 6X = 48
Then, number of stickers with Max = Y = X = 48/6 = 8
Number of stickers with Max = Y = 8 Stickers.

Question 4.
Ali’s dog weighs 8 times as much as her cat. Together, the two pets weigh 54 pounds. How much does Ali’s dog weigh?
Options:
a. 6 pounds
b. 42 pounds
c. 46 pounds
d. 48 pounds

Answer:
d. 48 pounds

Explanation:
From the given data,
Ali’s cat weight = X
Ali’s dog weight = 8 times as much as Ali’s cat = 8X
Together, the two pets weight = (X+8X) = 54 pounds
= 9X = 54 pounds
= X = 54/9 pounds = 6 pounds
Then, Ali’s dog weight = 8X =8 x 6 = 48 pounds.

Question 5.
Allison has 3 containers with 25 crayons in each. She also has 4 boxes of markers with 12 markers in each box. She gives 10 crayons to a friend. How many crayons and markers does Allison have now?
Options:
a. 34
b. 113
c. 123
d. 133

Answer:
b. 113

Explanation:
As per the given data,
Allison has 3 containers with 25 crayons in each = X = 3 x 25 = 75
Allison has 4 boxes of markers with 12 markers in each box = Y = 4 x 12 = 48
Allison gives 10 crayons to a friend = Z = 75-10 = 65
Now, total number of crayons and markers with Allison = Y + Z = 48 + 65 = 113

Question 6.
The state of Utah covers 82,144 square miles. The state of Montana covers 145,552 square miles. What is the total area of the two states?
Options:
a. 63,408 square miles
b. 223,408 square miles
c. 227,696 square miles
d. 966,992 square miles

Answer:
c. 227,696 square miles

Explanation:
From the given data,
The state of Utah covers 82,144 square miles
The state of Montana covers 145,552 square miles
Then, Total area of the two states = 82,144 + 145,552
The total area of two states = 227,696 square miles.

Page No. 153

Question 1.
To estimate the product of 62 and 28 by rounding, how would you round the factors? What would the estimated product be?
about _____

Answer:
1800

Explanation:
By using rounding and mental math
Estimate 62 x 28
Firstly, round each factor
62 x 28
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
60 x 30
Use mental math
6 x 3 = 18
60 x 30 = 1800
So, estimated product of 62 and 28 = 1800

Estimate the product. Choose a method.

Question 2.
96 × 34
Estimate: _____

Answer:
3000

Explanation:
Use mental math and compatible numbers
96 x 34
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
100 x 30
Use mental math
1 x 30 = 30
100 x 30= 3000

Question 3.
47 × $39
Estimate: $ _____

Answer:
2000

Explanation:
Round to the nearest ten
47 x $39
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
50 x $40
50 x $ 4 = $200
50 x $40 = 2000

Question 4.
78 × 72
Estimate: _____

Answer:
5600

Explanation:
Use rounding and mental math
Round each factor
78 x 72
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
80 x 70
Use mental math
8 x 7 = 56
80 x 70 = 5600

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 153 Q5

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 153 Q6

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 153 Q7

Practice: Copy and Solve Estimate the product. Choose a method.

Question 8.
61 × 31
Estimate: _____

Answer:
1800

Explanation:
Round to the nearest ten
61 x 31
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
60 x 30 = 1800

Question 9.
52 × 68
Estimate: _____

Answer:
3500

Explanation:
Round each factor
52 x 68
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
50 x 70
Use mental math
5 x 7 =35
50 x 70 = 3500

Question 10.
26 × 44
Estimate: _____

Answer:
1200

Explanation:
Round to the nearest tens
26 x 44
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
30 x 40 = 1200

Question 11.
57 × $69
Estimate: $ _____

Answer:
$4200

Explanation:
Round each factor
57 x $69
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
60 x $70
Use mental math
6 x $7 = $42
60 x $70 = $4200

Find two possible factors for the estimated product.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 153 Q12

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 153 Q13

Question 14.
5,600
Type below:
___________

Answer:
5,600

Explanation:
Let us consider 7 x 8 = 56
70 x 80 = 5,600

Question 15.
2,400
Type below:
___________

Answer:
2,400

Explanation:
Let us take 4 x 6 = 24
40 x 60 = 2400
Or 3 x 8 = 24
30 x 80 = 2,400

Question 16.
Mr. Parker jogs for 35 minutes each day. He jogs 5 days in week 1, 6 days in week 2, and 7 days in week 3. About how many minutes does he jog?
about _____ minutes

Answer:
about 630 minutes

Explanation:
From the given data,
Mr. Parker jogs per day = 35 minutes
He jogs 5 days in week 1 = 5 x 35 = 175 minutes
6 days in week 2 = 6 x 35 = 210 minutes
7 days in week 3 = 7 x 35 = 245 minutes
Total minutes of jog by Mr. Parker = week 1 + week 2 + week 3
= 175 + 210 + 245
= 630 minutes
So, total minutes of jog by Mr. Parker = 630 minutes

Question 17.
There are 48 beads in a package. Candice bought 4 packages of blue, 9 packages of gold, 6 packages of red, and 2 packages of silver beads. About how many beads did Candice buy?
about _____ beads

Answer:
about 1008 beads

Explanation:
As per the given data,
48 beads are there in a package
Candice bought 4 packages of blue beads = 4 x 48 = 192
9 packages of gold beads = 9 x 48 = 432
6 packages of red beads = 6 x 48 = 288
2 packages of silver beads = 2 x 48 = 96
Total beads bought by Candice = 192 + 432 + 288 + 96
= 1008 beads
So, total beads bought by Candice = 1008.

Page No. 154

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 154 Q18

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 154 Q19

Question 20.
If Mel opens his refrigerator door 36 times every day, how many times will it be opened in April? Will the exact answer be more than or less than the estimate? Explain.
Type below:
___________

Answer:
1200

Explanation:
From the given data,
Mel opens his refrigerator door per day = 36 times
Number of days in April month = 30 days
Refrigerator door opened in April month = 36 * 30
Round the factors
36 x 30
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
40 x 30 = 1200

Question 21.
Represent a Problem What question could you write for this answer? The estimated product of two numbers, which are not multiples of ten, is 2,800.
Type below:
___________

Answer:
2800

Explanation:
Let us take
1.
38 × 21
↓        ↓
40 × 20 = 800
2,800 = 42 x 68
↓    ↓
40 x  70 = 2800

Question 22.
Which is a reasonable estimate for the product? Write the estimate. An estimate may be used more than once.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 1
26 × 48 __________
28 × 21 __________
21 × 22 __________
51 × 26 __________

Answer:
25 x 50 = 1250
30 x 20 = 600
20 x 20 = 400
50 x 25 = 1250

Explanation:
26 x 48 -> 25 x 50 = 1250
28 x 21 -> 30 x 20 = 600
21 x 22 -> 20 x 20 = 400
51 x 26 -> 50 x 25 = 1250

Common Core – Page No. 155

Estimate Products
Estimate the product. Choose a method.

Question 1.
38 × 21
38 × 21
↓       ↓
40 × 20
800

Answer:
800

Explanation:
38 × 21
↓        ↓
40 × 20
800

Question 2.
63 × 19
Estimate: _____

Answer:
1200

Explanation:
63 x 19
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
60 x 20 = 1200
Estimated product of 63 x 19 = 1200

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 155 Q3

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 155 Q4

Question 5.
37 × $44
Estimate:$ _____

Answer:
$1600

Explanation:
37 × $44
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
40 x $40 = $1600
Estimated Product of 37 x $44 = $1600

Question 6.
85 × 71
Estimate: _____

Answer:
6300

Explanation:
85 × 71
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
90 x 70 = 6300
Estimated Product of 85 x 71 = 6300

Question 7.
88 × 56
Estimate: _____

Answer:
4950

Explanation:
88 × 56
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
90 x 55 = 4950
Estimated Product of 90 x 55 = 4950

Question 8.
97 × 13
Estimate: _____

Answer:
1,000

Explanation:
97 × 13
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
100 x 10 = 1,000

Question 9.
92 × 64
Estimate: _____

Answer:
5850

Explanation:
92 × 64
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
90 x 65 = 5850

Problem Solving

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 155 Q10

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 155 Q11

Common Core – Page No. 156

Lesson Check

Question 1.
Which is the best estimate for the product
43 × 68?
Options:
a. 3,500
b. 2,800
c. 2,400
d. 280

Answer:
b. 2,800

Explanation:
Round to the nearest tens
43 x 68
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
40 x 70
Use mental math
4 x 7 = 28
40 x 70 = 2800
Estimated product of 43 x 68 = 2800

Question 2.
Marissa burns 93 calories each time she plays fetch with her dog. She plays fetch with her dog once a day. About how many calories will Marissa burn playing fetch with her dog in 28 days?
Options:
a. 4,000
b. 2,700
c. 2,000
d. 270

Answer:
b. 2,700

Explanation:
From the given data,
Marissa burned calories each time when she plays fetch with her dog= 93 calories
Then, Marissa burned calories in 28 days while playing fetch with her dog = 28 x 93
Round to the nearest tens
28 x 93
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers      Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers
30 x 90
Then, estimated burned calories in 28 days by Marissa = 2700 calories

Spiral Review

Question 3.
Use the model to find 3 × 126.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 2
Options:
a. 368
b. 378
c. 468
d. 478

Answer:
b. 378

Explanation:
From the above Figure,
3 x 126 = 3 x 100 + 3 x 20 + 3 x 6
= 300 + 60 + 18
= 378
3 x 126 = 378

Question 4.
A store sells a certain brand of jeans for $38. One day, the store sold 6 pairs of jeans of that brand. How much money did the store make from selling the 6 pairs of jeans?
Options:
a. $188
b. $228
c. $248
d. $288

Answer:
b. $228

Explanation:
As per the given data,
A store sells a certain brand of jeans for rupees = $38
One day, the store sold 6 pairs of jeans of that brand = 6 x $38
6 x $38 = $228
The total amount of 6 pairs of jeans = $228

Question 5.
The Gateway Arch in St. Louis, Missouri, weighs about 20,000 tons. Which amount could be the exact number of tons the Arch weighs?
Options:
a. 31,093 tons
b. 25,812 tons
c. 17,246 tons
d. 14,096 tons

Answer:
c. 17,246 tons

Explanation:
From the given data,
The Gateway Arch in St.Louis, Missouri weight = about 20,000 tons
From the available options, 17,246 tons is closer to 20,000 tons
Then, the exact number of tons the Arch weighs = 17,246 tons

Question 6.
Which is another name for 23 ten thousands?
Options:
a. 23,000,000
b. 2,300,000
c. 230,000
d. 23,000

Answer:
c. 230,000

Explanation:
As per the data,
Another name for 23 ten thousands = 23 x 10,000
= 230,000
Another name for 23 ten thousand = 2,30,000

Page No. 159

Find the product.

Question 1.
16 × 19
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 3
16 × 19 = _____

Answer:
304

Explanation:
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 3
16 x 19 = 304

Question 2.
18 × 26
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 4
18 × 26 = _____

Answer:
468

Explanation:
Chapter 3 - Common core - Image 1. jpg
200 + 160 + 60 + 48 = 468

Question 3.
27 × 39
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 5
27 × 39 = ______

Answer:
1,053

Explanation:
Chapter 3 - Common core - image 2
600 + 210 + 180 +63 = 1053

Draw a model to represent the product.
Then record the product.

Question 4.
14 × 16 = ______

Answer:
224

Explanation:
Chapter 3 - Common core - Image 3
100 + 40 + 60 + 24 = 224

Question 5.
23 × 25 = ______

Answer:
575

Explanation:
Chapter 3 - Common core - Image 4
400 + 60 + 100 + 15 = 575

Question 6.
Explain how modeling partial products can be used to find the products of greater numbers.
Type below:
__________

Answer:
You can use mental math to find the partial products and then find the sum of the partial products.

Explanation:

Question 7.
Emma bought 16 packages of rolls for a party. There were 12 rolls in a package. After the party there were 8 rolls left over. How many rolls were eaten? Explain.
______ rolls

Answer:
184 rolls were eaten

Explanation:
From the given data,
Emma bought 16 packages of rolls for a party
There were 12 rolls in a package
Then, total rolls = 16 x 12 = 192
Chapter 3 - Common core - Image 5
100 + 60 + 20 + 12 =192
After the party there were 8 rolls left over
Then, total eaten rolls are = 192 – 8 = 184

Page No. 160

Question 8.
Jamal and Kim used different ways to solve 12 × 15 by using partial products. Whose answer makes sense? Whose answer is nonsense? Explain your reasoning.
Jamal’s Work
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 6
100 + 20 + 10 = 130

Kim’s Work
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 7
120 + 60 = 180
a. For the answer that is nonsense, write an answer that makes sense.
Type below:
__________

Answer:
a. Jamal’s work makes nonsense.
100 + 20 + 50 + 10 = 180 it makes sense

Question 8.
b. Look at Kim’s method. Can you think of another way Kim could use the model to find the product? Explain.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 8
Type below:
__________

Answer:
Other method: 12 x 15
10 x 12 = 120
5 x 12 = 60
120 + 60 = 180.

Explanation:
Kim follows another method to find 12 x 15
That is, 100 + 50 = 150
20 + 10 = 30
Then, 150 + 30 =180
12 x 15 = 180

Question 9.
Look at the model in 8b. How would the partial products change if the product was 22 × 15? Explain why you think the products changed.
Type below:
__________

Answer:
330

Explanation:
Following the 8b method
22 x 15 =330
Chapter 3 - Common core - Image 6
200 + 100 = 300
20 + 10 = 30
Now, 300 + 30 = 330
Finally, 22 x 15 = 330
The factor of 15 is increased in present problem. So, the product also increases for 15 x 22.

Common Core – Page No. 161

Area Models and Partial Products

Draw a model to represent the product.
Then record the product.

Question 1.
13 × 42
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 9

Answer:
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 9

Question 2.
18 × 34 = ______

Answer:
chapter 3 - Area models and partial products- image 1. jpg
300 + 40 + 240 + 32 = 612

Question 3.
22 × 26 = ______

Answer:
chapter 3 - Area models and partial products- image 2. jpg
400 + 120 + 40 + 12 = 572

Question 4.
1 5 × 33 = ______

Answer:
chapter 3 - Area models and partial products- image 3. jpg
300 + 30 + 150 + 15 = 495

Question 5.
23 × 29 = ______

Answer:
chapter 3 - Area models and partial products- image 4. jpg
400 + 180 + 60 + 27 = 667

Question 6.
19 × 36 = ______

Answer:
chapter 3 - Area models and partial products- image 5. jpg
300 + 60 + 270 + 54 = 684

Problem Solving

Question 7.
Sebastian made the following model to find the product 17 × 24.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 10
Is his model correct? Explain.
a. yes
b. no

Answer:
b. no

Explanation:
chapter 3 - Area models and partial products- image 6. jpg
200 + 40 + 140 + 28 = 408

Question 8.
Each student in Ms. Sike’s kindergarten class has a box of crayons. Each box has 36 crayons. If there are 18 students in Ms. Sike’s class, how many crayons are
there in all?
______ crayons

Answer:
648 crayons

Explanation:
From the given information,
Each student in Ms.Sike’s kindergarten class has a box of crayons
Crayons in each box = 36 Crayons
Number of students in Mr.Sike’s class = 18 students
Total crayons = 18 x 36
chapter 3 - Area models and partial products- image 7. jpg
300 + 60 + 240 + 48 = 648

Common Core – Page No. 162

Lesson Check

Question 1.
Which product does the model below represent?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 11
Options:
a. 161
b. 230
c. 340
d. 391

Answer:
d. 391

Explanation:
200 + 30 + 140 + 21 = 391
17 x 23 = 391

Question 2.
Which product does the model below represent?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 12 img 12
Options:
a. 219
b. 225
c. 244
d. 275

Answer:
b. 225

Explanation:
130 + 20 + 65 + 10 = 225
15 x 15 = 225

Spiral Review

Question 3.
Mariah builds a tabletop using square tiles. There are 12 rows of tiles and 30 tiles in each row. How many tiles in all does Mariah use?
Options:
a. 100
b. 180
c. 360
d. 420

Answer:
c. 360

Explanation:
From the given data,
Mariah builds a tabletop using square tiles
Square contains 12 rows of tiles and 30 tiles in each row = 12 x 30
12 x 30 = 360 tiles
Total tiles used by Mariah = 360 tiles

Question 4.
Trevor bakes 8 batches of biscuits, with 14 biscuits in each batch. He sets aside 4 biscuits from each batch for a bake sale and puts the rest in a jar. How many biscuits does Trevor put in the jar?
Options:
a. 112
b. 80
c. 50
d. 32

Answer:
b. 80

Explanation:
As per the given data,
Number of biscuits baked by Trevor = 8 batches
Number of biscuits in each batch = 14 biscuits
So, total biscuits = 14 x 8 = 112
Trevor sets aside 4 biscuits from each batch for a bake = 8*4 = 32 biscuits are aside for a bake
Trevor kept rest of biscuits in a jar = 112 – 32 = 80
So, 80 biscuits are put in the jar by the Trevor

Question 5.
Li feeds her dog 3 cups of food each day. About how many cups of food does her dog eat in 28 days?
Options:
a. 60 cups
b. 70 cups
c. 80 cups
d. 90 cups

Answer:
c. 80 cups

Explanation:
As per the given data,
Li feeds her dog per day = 3 cups of food
Then, Li feeds her dog for 28 days = 3 x 28
= 84 cups of food
So, Li feeds her dog with 84 cups of food in 28 days

Question 6.
Which symbol makes the number sentence true?
4 ■ 0 = 0
Options:
a. +
b. –
c. ×
d. ÷

Answer:
c. ×

Explanation:
4 x 0 = 0

Page No. 165

Question 1.
Find 24 × 34.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 13
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 14
_____

Answer:
816

Explanation:
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 13
chapter 3 - Area models and partial products- image 9. jpg

Question 2.
1 2
× 1 2
——–
_____

Answer:
144

Explanation:
chapter 3 - Area models and partial products- image 10. jpg
chapter 3 - Area models and partial products- image 11. jpg

Question 3.
3 1
× 2 4
——-
_____

Answer:
744

Explanation:
chapter 3 - Area models and partial products- image 12. jpg
chapter 3 - Area models and partial products- image 13. jpg

Question 4.
2 5
× 4 3
——-
_____

Answer:
1,075

Explanation:
chapter 3 - Area models and partial products- image 14. jpg
chapter 3 - Area models and partial products- image 15. jpg

Question 5.
3 7
× 2 4
——-
_____

Answer:
888

Explanation:
chapter 3 - Area models and partial products- image 16. jpg
chapter 3 - Area models and partial products- image 17. jpg

Question 6.
5 4
× 1 5
——-
_____

Answer:
810

Explanation:
chapter 3 - Area models and partial products- image 18. jpg
chapter 3 - Area models and partial products- image 19. jpg

Question 7.
8 7
× 1 6
——-
_____

Answer:
1,392

Explanation:
chapter 3 - Area models and partial products- image 20. jpg
chapter 3 - Area models and partial products- image 21. jpg

Question 8.
6 2
× 5 6
——-
_____

Answer:
3,472

Explanation:
chapter 3 - Area models and partial products- image 22. jpg
chapter 3 - Area models and partial products- image 23. jpg

Question 9.
4 9
× 6 3
——-
_____

Answer:
3,087

Explanation:
chapter 3 - Area models and partial products- image 24. jpg
chapter 3 - Area models and partial products- image 25. jpg

Practice: Copy and Solve Record the product.

Question 10.
38 × 47
_____

Answer:
1,786

Explanation:
chapter 3 - Area models and partial products- image 26. jpg
chapter 3 - Area models and partial products- image 27. jpg

Question 11.
46 × 27
_____

Answer:
1,242

Explanation:
chapter 3 - Area models and partial products- image 28. jpg
chapter 3 - Area models and partial products- image 29. jpg

Question 12.
72 × 53
_____

Answer:
3,816

Explanation:
chapter 3 - Area models and partial products- image 30. jpg
chapter 3 - Area models and partial products- image 31. jpg

Question 13.
98 × 69
_____

Answer:
6,762

Explanation:
chapter 3 - Area models and partial products- image 32. jpg
chapter 3 - Area models and partial products- image 33. jpg

Question 14.
53 × 68
_____

Answer:
3,604

Explanation:
chapter 3 - Area models and partial products- image 34. jpg
chapter 3 - Area models and partial products- image 35. jpg

Question 15.
76 × 84
_____

Answer:
6,384

Explanation:
chapter 3 - Area models and partial products- image 36. jpg
chapter 3 - Area models and partial products- image 37. jpg

Question 16.
92 × 48
_____

Answer:
4,416

Explanation:
chapter 3 - Area models and partial products- image 38. jpg
chapter 3 - Area models and partial products- image 39. jpg

Question 17.
37 × 79
_____

Answer:
2,923

Explanation:
chapter 3 - Area models and partial products- image 40. jpg
chapter 3 - Area models and partial products- image 41. jpg

Reason Abstractly Algebra Find the unknown digits. Complete the problem.

Question 18.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 15
Type below:
___________

Answer:
1,824

Explanation:
chapter 3 - Area models and partial products- image 42. jpg

Question 19.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 16
Type below:
___________

Answer:
7,954

Explanation:
chapter 3 - Area models and partial products- image 43. jpg

Question 20.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 17
Type below:
___________

Answer:
1,908

Explanation:
chapter 3 - Area models and partial products- image 44. jpg

Question 21.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 18
Type below:
___________

Answer:
952

Explanation:
chapter 3 - Area models and partial products- image 45. jpg

Page No. 166

Use the picture graph for 22–24.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 19

Question 22.
Use Graphs A fruit-packing warehouse is shipping 15 boxes of grapefruit to a store in Santa Rosa, California. What is the total weight of the shipment?
______ pounds

Answer:
1275 pounds

Explanation:
From the given data,
A fruit packing warehouse is shipping 15 boxes of grapefruit to store in Santa Rose, California
Grapefruit weight per box = 85 pounds
Total weight of the shipment = 85 x 15
chapter 3 - Area models and partial products- image 46. jpg
So, the total weight of the shipment = 1275 pounds

Question 23.
How much less do 13 boxes of tangelos weigh than 18 boxes of tangerines?
______ pounds

Answer:
450 pounds

Explanation:
As per the given data,
Tangelos weight per box = 90 pounds
Then, the weight of the 13 boxes of tangelos = 90 x 13
chapter 3 - Area models and partial products- image 47. jpg
And, the weight of the 18 boxes of tangelos = 90 x 18
chapter 3 - Area models and partial products- image 48. jpg
1620 – 1170 = 450
So, 13 boxes of tangelos weight are 450 pounds less than 18 boxes of tangelos weight

Question 24.
What is the weight of 12 boxes of oranges?
______ pounds

Answer:
1,080 pounds

Explanation:
The weight of the oranges per box = 90 pounds
then, weight of 12 boxes oranges = 90 x 12
chapter 3 - Area models and partial products- image 49. jpg
So, weight of 12 boxes oranges = 1,080 pounds

Question 25.
Each person in the United States eats about 65 fresh apples each year. Based on this estimate, how many apples do 3 families of 4 eat each year?
______ apples

Answer:
780 apples

Explanation:
From the given data,
Each person in the united states eats fresh apples per year = 65
3 families of 4 persons = 3 x 4 = 12 persons
Then, the number of apples eat by 12 persons = 65 x 12
chapter 3 - Area models and partial products- image 50. jpg
So, the total number of apples eat by 12 persons per year = 780

Question 26.
The product 26 × 93 is greater than 25 × 93. How much greater? Explain how you know without multiplying.
______

Answer:
The difference is 93
26 x 93 is one more group of 93 than 25 x 93

Question 27.
Margot wants to use partial products to find 22 × 17. Write the numbers in the boxes to show 22 × 17.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 20
Type below:
__________

Answer:
chapter 3 - Area models and partial products- image 51. jpg

Explanation:
22 x 17
(20 + 2) x 17
20 x 17 + 2 x 17
20 x (10 + 7) + 2 x (10 + 7)
(20 x 10) + (20 x 7) + (2 x 10) + (2 x 7)
chapter 3 - Area models and partial products- image 51. jpg

Common Core – Page No. 167

Multiply Using Partial Products

Record the product.

Question 1.
2 3
× 7 9
———
1, 4 0 0
2 1 0
1 8 0
+ 2 7
——–
1, 8 1 7

Answer:
1, 8 1 7

Explanation:
2 3
× 7 9
———
1, 4 0 0
2 1 0
1 8 0
+ 2 7
——–
1, 8 1 7

Question 2.
5 6
× 3 2
——-
_______

Answer:
1,792

Explanation:
Chapter 3 - Common core - Image 7

Question 3.
8 7
× 6 4
——-
_______

Answer:
5,568

Explanation:
Chapter 3 - Common core - Image 8

Question 4.
3 3
× 2 5
——-
_______

Answer:
825

Explanation:
Chapter 3 - Common core - Image 9

Question 5.
9 4
× 1 2
——-
_______

Answer:
1,128

Explanation:
Chapter 3 - Common core - Image 10

Question 6.
5 1
× 7 7
——-
_______

Answer:
3,927

Explanation:
Chapter 3 - Common core - Image 11

Question 7.
6 9
× 4 9
——-
_______

Answer:
3,381

Explanation:
Chapter 3 - Common core - Image 12

Question 8.
8 6
× 8 4
——-
_______

Answer:
7,224

Explanation:
Chapter 3 - Common core - Image 13

Question 9.
9 8
× 4 2
——-
_______

Answer:
4,116

Explanation:
Chapter 3 - Common core - Image 14

Question 10.
7 3
× 3 7
——-
_______

Answer:
2,701

Explanation:
Chapter 3 - Common core - Image 15

Question 11.
8 5
× 5 1
——-
_______

Answer:
4,335

Explanation:
Chapter 3 - Common core - Image 16

Problem Solving

Question 12.
Evelyn drinks 8 glasses of water a day, which is 56 glasses of water a week. How many glasses of water does she drink in a year? (1 year = 52 weeks)
_______ glasses

Answer:
2,912 glasses

Explanation:
As per the given data,
Evelyn drinks 8 glasses of water a day
Evelyn drinks water per week = 56 glasses
Then, the number of glasses per 52 weeks = 52 x 56
Chapter 3 - Common core - Image 17
Total number of glasses of water drink by Evelyn per year = 2912 glasses of water

Question 13.
Joe wants to use the Hiking Club’s funds to purchase new walking sticks for each of its 19 members. The sticks cost $26 each. The club has $480. Is this enough money to buy each member a new walking stick? If not, how much more money is needed?
Is the money enough? _______
How much more is needed? _______

Answer:
This amount is not enough to buy walking sticks
Still, $14 amount is needed to buy walking sticks

Explanation:
From the given data,
Joe wants to use the Hiking club funds to purchase new walking sticks for each of its 19 members
Cost per each stick = $26
Total walking sticks cost per 19 members = $26 x 19
Chapter 3 - Common core - Image 18
Total cost for walking sticks for 19 members = $494
The club has = $480
This amount is not enough to buy walking sticks
Still, $14 amount is needed to buy walking sticks

Common Core – Page No. 168

Lesson Check

Question 1.
A carnival snack booth made $76 selling popcorn in one day. It made 22 times as much selling cotton candy. How much money did the snack booth make selling
cotton candy?
Options:
a. $284
b. $304
c. $1,562
d. $1,672

Answer:
d. $1,672

Explanation:
As per the given data,
A carnival snack booth made popcorn in one day = $76
It made 22 times as much selling cotton candy
Then, total selling cotton candy made by snack booth = $76 x 22
Chapter 3 - Common core - Image 19
So, $1672 money snack booth will get for selling cotton candy

Question 2.
What are the partial products of
42 × 28?
Options:
a. 800, 80, 40, 16
b. 800, 16
c. 800, 40, 320, 16
d. 80, 16

Answer:
c. 800, 40, 320, 16

Explanation:
Chapter 3 - Common core - Image 20
So, partial products of 42 x 28 are 800, 40, 320, 16

Spiral Review

Question 3.
Last year, the city library collected 117 used books for its shelves. This year, it collected 3 times as many books. How many books did it collect this year?
Options:
a. 832
b. 428
c. 351
d. 72

Answer:
c. 351

Explanation:
From the given data,
Last year, the number of used books collected by city library by its shelves = 117 books
This year, it collected 3 times as many books = 3 x 117 =351 books
Total number of books collected by the city library for this year = 351 books

Question 4.
Washington Elementary has 232 students. Washington High has 6 times as many students. How many students does Washington High have?
Options:
a. 1,392
b. 1,382
c. 1,292
d. 1,281

Answer:
a. 1,392

Explanation:
As per the given data,
The number of students in Washington elementary = 232 students
Washington High has 6 times as many students = 6 x 232 = 1392
Total number of students in Washington High = 1392 students

Question 5.
What are the partial products of 35 × 7?
Options:
a. 10, 12
b. 21, 35
c. 210, 35
d. 350, 21

Answer:
c. 210, 35

Explanation:
Partial products of 35 x 7 are 210, 35

Question 6.
Shelby has ten $5 bills and thirteen $10 bills. How much money does Shelby have in all?
Options:
a. $15
b. $60
c. $63
d. $180

Answer:
d. $180

Explanation:
From the given data,
Shelby has ten $5 bills and thirteen $10 bills = (10 x $5) + (13 x $10)
= ($50) + ($130)
=$180
Total money with Shelby = $180

Page No. 169

Question 1.
Explain how to find 40 × 50 using mental math.
Type below:
__________

Answer:
200

Explanation:
40 x 50
By using mental math
4 x 5 = 20
40 x 50 = 200

Question 2.
What is the first step in estimating 56 × 27?
Type below:
__________

Answer:
18 centimeters

Explanation:
Round to the nearest values.
So, the first step of the estimated 56 x 27 is rounding to the nearest value which is 60 x 30

Choose a method. Then find the product.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 169 Q3

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 169 Q4

Question 5.
12 × 80 = _____

Answer:
960

Explanation:
Use the halving and doubling strategy
half of the 80 to make the problem simpler
80/ 2 = 40
Multiply 40 with 12
40*12 = 480
Double the 480
2*480= 960
12*80 = 960

Question 6.
70 × 50 = _____

Answer:
3,500

Explanation:
70 x 50
By using the place value method
You can take 50 as 5 tens
70 x 50 = 70 x 5 tens
= 350 tens
70 x 50 = 3,500

Question 7.
58 × 40 = _____

Answer:
2,320

Explanation:
By using the associative property
You can think of 40 as (4 x 10)
58 x 40 = 58 x (4 x 10)
= (58 x 4) x 10
= 232 x 10
58 x 40 = 2,320

Question 8.
30 × 40 = _____

Answer:
1,200

Explanation:
Use the halving and doubling strategy
half of the 40 to make the problem simpler
40/ 2 = 20
Multiply 20 with 30
20*30 = 600
Double the 600
2*600= 1200
30*40 = 1,200

Question 9.
14 × 60 = _____

Answer:
840

Explanation:
By using the place value method
You can take 60 as 6 tens
14 x 60 = 14 x 6 tens
= 84 tens
14 x 60 = 840

Question 10.
20 × 30 = _____

Answer:
600

Explanation:
By using the associative property
You can think of 30 as (3 x 10)
20 x 30 = 20 x (3 x 10)
= (20 x 3) x 10
= 60 x 10
20 x 30 = 600

Question 11.
16 × 90 = _____

Answer:
1,440

Explanation:
Use the halving and doubling strategy
half of the 90 to make the problem simpler
90/ 2 = 45
Multiply 45 with 16
16*45 = 720
Double the 720
2*720= 1440
16*90 = 1,440

Estimate the product. Choose a method.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 169 Q12

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 169 Q13

Question 14.
43 × 25
Estimate: _____

Answer:
1,000

Explanation:
Round to the nearest tens.
43 is close to 40; 25 is close to 25;
40 x 25 = 1000
Estimated product of 43 x 25 = 1,000

Question 15.
76 × 45
Estimate: _____

Answer:
3,200

Explanation:
Round to the nearest tens.
76 is close to 80; 45 is close to 40;
Use the mental math
8 x 4 = 32
80 x 40 = 3200
So, the estimated product of 76 x 45 = 3,200

Question 16.
65 × $79
Estimate: _____

Answer:
$4,800

Explanation:
Round to the nearest tens.
65 is close to 60; $79 is close to $80;
Use the mental math
6 x $8 = $48
60 x $80 = $4800
So, estimated product of 65 x $79 = $4,800

Question 17.
92 × 38
Estimate: _____

Answer:
3,600

Explanation:
Round to the nearest tens.
92 is close to 90; 38 is close to 40;
Use the mental math, then
9 x 4 = 36
90 x 40 = 3,600
So, estimated product of 92 x 38 = 3,600

Question 18.
37 × 31
Estimate: _____

Answer:
1,200

Explanation:
Round to the nearest tens.
37 is close to 40; 31 is close to 30;
Use the mental math, then
4 x 3 = 12
40 x 30 = 1,200
So, estimated product of 37 x 31 = 1,200

Question 19.
26 × $59
Estimate: _____

Answer:
$1,800

Explanation:
Round to the nearest tens.
26 is close to 30; $59 is close to $60;
Use the mental math, then
3 x $6 = $18
30 x $60 = $1,800
So, estimated product of 26 x $59 = $1,800

Question 20.
54 × 26
Estimate: _____

Answer:
18 centimeters

Explanation:
Round to the nearest tens.
54 is close to 50; 26 is close to 30;
Use the mental math
5 x 3 = 15
50 x 30 = 1,500
So, estimated product of 54 x 26 = 1,500

Question 21.
52 × 87
Estimate: _____

Answer:
4,500

Explanation:
Round to the nearest tens.
52 is close to 50; 87 is close to 90;
Use the mental math
5 x 9 = 45
50 x 90 = 4500
So, estimated product of 52 x 87 = 4,500

Question 22.
39 × 27
Estimate: _____

Answer:
18 centimeters

Explanation:
Round to the nearest tens.
39 is close to 40; 27 is close to 30;
Use the mental math
4 x 3 = 12
40 x 30 = 1,200
So, estimated product of 39 x 27 = 1,200

Question 23.
63 × 58
Estimate: _____

Answer:
3,600

Explanation:
Round to the nearest tens.
63 is close to 60; 58 is close to 60;
Use the mental math
6 x 6 = 36
60 x 60 = 3,600
So, estimated product of 63 x 58 = 3,600

Page No. 170

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 170 Q24

Question 25.
Tito wrote the following on the board. What is the unknown number?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 21
______

Answer:
400

Explanation:
An unknown number is 50 x 8 = 400

Question 26.
What are the partial products that result from multiplying 15 × 32?
Type below:
__________

Answer:
Partial products are 300, 150, 20, 10

Explanation:
Chapter 3 - Common core - Image 36
Partial products are 300, 150, 20, 10

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 170 Q27

Page No. 173

Question 1.
Look at the problem. Complete the sentences.
Multiply ____ and ____ to get 0.
Multiply ____ and ____ to get 1,620.
Add the partial products.
0 + 1,620 = ____
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 22
_____

Answer:
Multiply 27 and 0 to get 0.
Multiply 27 and 6 to get 1,620.
Add the partial products. 0 + 1,620 = 1,620.

Estimate. Then find the product.

Question 2.
6 8
× 5 3
——-
Estimate: _________
Product: __________

Answer:
Estimate: 3,500
Product: 3,604

Explanation:
68 is closer to 70 and 53 is closer to 50
Estimate: 70 x 50 = 3,500
60 x 53 = 3180
8 x 53 = 424
3180 + 424 = 3604
Product 3,604

Question 3.
6 1
× 5 4
——-
Estimate: _________
Product: __________

Answer:
Estimate: 3,000
Product: 3,294

Explanation:
61 is closer to 60 and 54 is closer to 50
Estimate: 60 x 50 = 3,000
60 x 54 = 3240
1 x 54 = 54
3240 + 54 = 3294
Product 3,294

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 173 Q4

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 173 Q5

Question 6.
7 8
× 5 6
——-
Estimate: _________
Product: __________

Answer:
Estimate: 4,800
Product: 4,368

Explanation:
78 is closer to 80 and 56 is closer to 60
Estimate: 80 x 60 = 4,800
70 x 56 = 3920
8 x 56 = 448
3920 + 448 = 4368
Product 4,368

Question 7.
2 7
× 2 5
——-
Estimate: _________
Product: __________

Answer:
Estimate: 600
Product: 675

Explanation:
27 is closer to 30 and 25 is closer to 20
Estimate: 30 x 20 = 600
20 x 25 = 500
7 x 25 = 175
500 + 175 = 675
Product 675

Practice: Copy and Solve Estimate. Then find the product.

Question 8.
34 × 65
Estimate: _________
Product: __________

Answer:
Estimate: 1,800
Product: 2,210

Explanation:
34 is closer to 30 and 65 is closer to 60
Estimate: 30 x 60 = 1,800
30 x 65 = 1950
4 x 65 = 260
1950 + 260 = 2210
Product 2,210

Question 9.
42 × $13
Estimate: $ _________
Product: $ _________

Answer:
Estimate: $400
Product: $546

Explanation:
42 is closer to 40 and 13 is closer to 10
Estimate: 40 x 10 = 400
40 x $13 = $520
2 x $13= $26
$520 + $26 = $546
Product $546

Question 10.
60 × 17
Estimate: _________
Product: __________

Answer:
Estimate: 1,200
Product: 1,020

Explanation:
17 is closer to 20
Estimate: 60 x 20 = 1,200
60 x 17 = 1020
Product = 1,020

Question 11.
62 × 45
Estimate: _________
Product: __________

Answer:
Estimate: 2,400
Product: 2,790

Explanation:
62 is closer to 60 and 45 is closer to 40
Estimate: 60 x 40 = 2,400
60 x 45 = 2700
2 x 45= 90
2700 + 90 = 2790
Product 2,790

Question 12.
57 × $98
Estimate: $ _________
Product: $ _________

Answer:
Estimate: 6,000
Product: 5,586

Explanation:
57 is closer to 60 and 98 is closer to 100
Estimate: 60 x 100 = 6,000
50 x 98 = 4900
7 x 98= 686
4900 + 686 = 5586
Product 5,586

Look for a Pattern Algebra Write a rule for the pattern.
Use your rule to find the unknown numbers.

Question 13.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 23
Rule _____________
Type below:
_________

Answer:
Chapter 3 - Common core - Image 37

Explanation:
1 hour = 60 min
Then, 5hr = 5 x 60 = 300 min
10hr = 10 x 60 = 600 min
15hr = 15 x 60 = 900 min
20hr = 20 x 60 = 1200 min
25hr = 25 x 60 = 1500 min

Question 14.
Owners of a summer camp are buying new cots for their cabins. There are 16 cabins. Each cabin needs 6 cots. Each cot costs $92. How much will the new cots cost?
$ _______

Answer:
$8,832

Explanation:
As per the given data,
Owners pf a summer camp are buying new cots for their cabins
Number of cabins = 16
Each cabin needs 6 cots
Then, total cots = 16 x 6 = 96
Each cot cost = $92
Then, cost for total cots = $92 x 96
92 is closer to 90 and 96 is closer to 100
Estimate = 90 x 100 = 9,000
90 x 96 = 8640
2 x 96 = 192
8640 + 192 = 8832
Product = 8,832

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 173 Q15

Page No. 174

Question 16.
Machine A can label 11 bottles in 1 minute. Machine B can label 12 bottles in 1 minute. How many bottles can both machines label in 15 minutes?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 24
a. What do you need to know?
Type below:
__________

Answer:
number of bottles labeled by Machine A and Machine B in 15 minutes

Question 16.
b. What numbers will you use?
Type below:
__________

Answer:
15x 11 and 15 x 12

Question 16.
c. Tell why you might use more than one operation to solve the problem.
Type below:
__________

Answer:
To find out the total number of bottle made by both machines A & B

Question 16.
d. Solve the problem.
So, both machines can label ____ bottles in ____ minutes.
Type below:
__________

Answer:
Machine A can label 11 bottles in 1 minute
Then, the number of bottles labeled by machine A in 15 minutes = 15 x 11 = 165
Machine B can label 12 bottles in 1 minute
Then, number of bottles labelled by Machine B in 15 minutes = 15 x 12 = 180
Total bottles labelled by both the machines in 15 minutes = 165 + 180 = 345

Question 17.
Make Sense of Problems
A toy company makes wooden blocks. A carton holds 85 blocks. How many blocks can 19 cartons hold?
______ blocks

Answer:
1,615 blocks

Explanation:
From the given data,
A toy company makes wooden blocks
A carton holds 85 blocks
Then, number of blocks hold by 19 cartons = 19 x 85 = 1615
Total number of blocks held by 19 cartons = 1,615

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 174 Q18

Question 19.
Mr. Garcia’s class raised money for a field trip to the zoo. There are 23 students in his class. The cost of the trip will be $17 for each student. What is the cost for all the students? Explain how you found your answer.
$ ______

Answer:
$391

Explanation:
As per the given data,
Mr. Garcia’s class raised money for a field trip to the zoo
Total number of students in his class = 23 students
Cost of the trip for each student = $17
Then, total cost for all the students = $17 x 23 = $391

Common Core – Page No. 175

Multiply with Regrouping
Estimate. Then find the product.

Question 1.
Estimate: 2,700
Think: 87 is close to 90 and 32 is close to 30.
90 × 30 = 2,700
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 25

Answer:
2,784

Explanation:
Think: 87 is close to 90 and 32 is close to 30.
90 × 30 = 2,700
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 25

Question 2.
7 3
× 2 8
——–
Estimate: ______
Product: _______

Answer:
Estimate: 2,100
Product: 2,044

Explanation:
Estimate: 73 is close to 70; 28 is close to 30.
So, 70 x 30 = 2,100.
Product: Write 73 as 7 tens and 3 ones. Multiply 28 by 3 ones.
2
28
x 73
——–
84 <– 3 x 28
Multiply 28 by 7 tens
5
28
x 73
——–
1960 <– 70 x 28
Add the partial products.
84 + 1960 = 2,044.
So, 73 x 28 = 2,044.

Question 3.
4 8
× 3 8
——–
Estimate: ______
Product: _______

Answer:
Estimate: 2,000
Product: 1,824

Explanation:
48 is close to 50 and 38 is close to 40.
Estimate: 50 × 40 = 2,000
40 x 38 = 1520
8 x 38 = 304
1520 + 304 = 1824.
Product: 1,824

Question 4.
5 9
× 5 2
——–
Estimate: ______
Product: _______

Answer:
Estimate: 3,000
Product: 3,068

Explanation:
59 is close to 60 and 52 is close to 50.
Estimate: 60 × 50 = 3,000
50 x 52 = 2600
9 x 52 = 468
2600 + 468 = 3068.
Product: 3,068.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 175 Q5

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 175 Q6

Question 7.
9 1
× 1 9
——–
Estimate: ______
Product: _______

Answer:
Estimate: 1,800
Product: 1,729

Explanation:
91 is close to 90 and 19 is close to 20.
Estimate: 90 × 20 = 1,800
90 x 19 = 1,710
1 x 19 = 19
1,710+ 19 = 1,729.
Product: 1,729.

Problem Solving

Question 8.
Baseballs come in cartons of 84 baseballs. A team orders 18 cartons of baseballs. How many baseballs does the team order?
_______ baseballs

Answer:
1,512 baseballs

Explanation:
To find total baseballs, 84 x 18
80 x 18 = 1,440
4 x 18 = 72
84 x 18 = 1,512

Question 9.
There are 16 tables in the school lunchroom. Each table can seat 22 students. How many students can be seated at lunch at one time?
_______ students

Answer:
352 students

Explanation:
Total Students = 16 x 22
10 x 22 = 220
6 x 22 = 132
220 + 132 = 352.
352 students can be seated at lunch at one time

Common Core – Page No. 176

Lesson Check

Question 1.
The art teacher has 48 boxes of crayons. There are 64 crayons in each box. Which is the best estimate of the number of crayons the art teacher has?
Options:
a. 2,400
b. 2,800
c. 3,000
d. 3,500

Answer:
c. 3,000

Explanation:
1. Total number of crayons = 48 x 64
48 is close to 50; 64 is close to 60
50 x 60 = 3,000.
The art teacher has about to 3, 000 crayons.

Question 2.
A basketball team scored an average of 52 points in each of 15 games. How many points did the team score in all?
Options:
a. 500
b. 312
c. 780
d. 1,000

Answer:
c. 780

Explanation:
Total Points = 52 x 15
50 x 15 = 750
2 x 15 = 30
750 + 30 = 780.
The basketball team scored 780 points in total.

Spiral Review

Question 3.
On Saturday, an orchard sold 83 bags of apples. There are 27 apples in each bag. Which expression represents the total number of apples sold?
Options:
a. 16 + 6 + 56 + 21
b. 160 + 60 + 56 + 21
c. 160 + 60 + 560 + 21
d. 1,600 + 60 + 560 + 21

Answer:
d. 1,600 + 60 + 560 + 21

Explanation:
Total number of apples sold = 83 x 27
80 x 27 = 2,160
3 x 27 = 81
2,160 + 81 = 2,241.
The total number of apples sold = 2,241.
16 + 6 + 56 + 21 = 99 not equal to 2,241
160 + 60 + 56 + 21 = 297 not equal to 2,241
160 + 60 + 560 + 21 = 801 not equal to 2,241
1,600 + 60 + 560 + 21 = 2,241 equal to 2,241
1,600 + 60 + 560 + 21 = 2,241 is correct.

Question 4.
Hannah has a grid of squares that has 12 rows with 15 squares in each row. She colors 5 rows of 8 squares in the middle of the grid blue. She colors the rest of
the squares red. How many squares does Hannah color red?
Options:
a. 40
b. 140
c. 180
d. 220

Answer:
b. 140

Explanation:
Hannah has a grid of squares that has 12 rows with 15 squares in each row = 12 x 15 = 180.
The grid of squares in blue = 5 x 8 = 40.
The grid of squares in red = 180 – 40 = 140.

Question 5.
Gabriella has 4 times as many erasers as Leona. Leona has 8 erasers. How many erasers does Gabriella have?
Options:
a. 32
b. 24
c. 12
d. 2

Answer:
a. 32

Explanation:
Gabriella has 4 x 8 = 32 erasers.

Question 6.
Phil has 3 times as many rocks as Peter. Together, they have 48 rocks. How many more rocks does Phil have than Peter?
Options:
a. 36
b. 24
c. 16
d. 12

Answer:
b. 24

Explanation:
Phil has 3 times as many rocks as Peter. Together, they have 48 rocks
If Peter has x rocks, Phil has 3x rocks
3x + x = 48.
4x = 48.
x = 48/4 = 12.
Peter has 12 rocks. Phil has 3 x 12 = 36 rocks.
Phil has 36 – 12 = 24 more rocks than Peter.

Page No. 179

Question 1.
Find the product.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 26
Estimate: ______
Product: _______

Answer:
Estimate: 1,500
Product: 1,566

Explanation:
54 x 29
Estimate: Think 54 is close to 50; 29 is close to 30.
50 x 30 = 1,500
Product:
20 x 5 tens = 100 tens
20 x 4 ones = 80 ones
9 x 5 tens = 45 tens
9 x 4 ones = 36 ones.
Add partial products.
1000 + 80 + 450 + 36 = 1,566.

Estimate. Then choose a method to find the product.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 179 Q2

Question 3.
6 3
× 4 2
——-
Estimate: ______
Product: _______

Answer:
Estimate: 2,400
Product: 2646

Explanation:
63 x 42
Estimate: Think 63 is close to 60; 42 is close to 40.
60 x 40 = 2400
Product:
40 x 6 tens = 240 tens
40 x 3 ones = 120 ones
2 x 6 tens = 12 tens
2 x 3 ones = 6 ones.
Add partial products.
2400 + 120 + 120 + 6 = 2646.

Question 4.
8 4
× 5 3
——-
Estimate: ______
Product: _______

Answer:
Estimate: 4,000
Product: 4,452

Explanation:
84 x 53
Estimate: Think 84 is close to 80; 53 is close to 50.
80 x 50 = 4,000
Product:
50 x 8 tens = 400 tens
50 x 4 ones = 200 ones
3 x 8 tens = 24 tens
3 x 4 ones = 12 ones.
Add partial products.
4000 + 200 + 240 + 12 = 4,452.

Question 5.
7 1
× 1 3
——-
Estimate: ______
Product: _______

Answer:
Estimate: 700
Product: 923

Explanation:
71 x 13
Estimate: Think 71 is close to 70; 13 is close to 10.
70 x 10 = 700
Product:
10 x 7 tens = 70 tens
10 x 1 ones = 10 ones
3 x 7 tens = 21 tens
3 x 1 ones = 3 ones.
Add partial products.
700 + 10 + 210 + 3 = 923.

Practice: Copy and Solve Estimate. Find the product.

Question 6.
29 × $82
Estimate: $ _______
Product: $ _______

Answer:
Estimate: $2,400
Product: $2,378

Explanation:
29 x $82
Estimate: Think 29 is close to 30; $82 is close to $80.
30 x $80 = $2,400
Product:
$80 x 2 tens = $160 tens
$80 x 9 ones = $720 ones
$2 x 2 tens = $4 tens
$2 x 9 ones = $18 ones.
Add partial products.
$1600 + $720 + $40 + $18 = $2,378.

Question 7.
57 × 79
Estimate: _______
Product: _______

Answer:
Estimate: 4,800
Product: 4,503

Explanation:
57 x 79
Estimate: Think 57 is close to 60; 79 is close to 80.
60 x 80 = 4,800
Product:
70 x 5 tens = 350 tens
70 x 7 ones = 490 ones
9 x 5 tens = 45 tens
9 x 7 ones = 63 ones.
Add partial products.
3500 + 490 + 450 + 63 = 4,503.

Question 8.
80 × 27
Estimate: _______
Product: _______

Answer:
Estimate: 2,400
Product: 2,160

Explanation:
80 x 27
Estimate: Think 27 is close to 30.
30 x 80 = 2,400
Product:
20 x 8 tens = 160 tens
20 x 0 ones = 0 ones
7 x 8 tens = 56 tens
7 x 0 ones = 0 ones.
Add partial products.
1600 + 0 + 560 + 0 = 2,160.

Question 9.
32 × $75
Estimate: $ _______
Product: $ _______

Answer:
Estimate: $2,100
Product: $2,400

Explanation:
32 × $75
Estimate: Think 32 is close to 30; $75 is close to $70.
30 x $70 = $2,100
Product:
$70 x 3 tens = $210 tens
$70 x 2 ones = $140 ones
$5 x 3 tens = $15 tens
$5 x 2 ones = $10 ones.
Add partial products.
$2100 + $140 + $150 + $10 = $2,400.

Question 10.
55 × 48
Estimate: _______
Product: _______

Answer:
Estimate: 2,750
Product: 2,640

Explanation:
55 × 48
Estimate: Think 48 is close to 50.
55 x 50 = 2,750
Product:
40 x 5 tens = 200 tens
40 x 5 ones = 200 ones
8 x 5 tens = 40 tens
8 x 5 ones = 40 ones.
Add partial products.
2000 + 200 + 400 + 40 = 2,640.

Question 11.
19 × $82
Estimate: $ _______
Product: $ _______

Answer:
Estimate: $1,600
Product: $1,558

Explanation:
19 × $82
Estimate: Think 19 is close to 20; $82 is close to $80.
20 x $80 = $1,600
Product:
$80 x 1 tens = $80 tens
$80 x 9 ones = $720 ones
$2 x 1 tens = $2 tens
$2 x 9 ones = $18 ones.
Add partial products.
$800 + $720 + $20 + $18 = $1,558.

Question 12.
25 × $25
Estimate: $ _______
Product: $ _______

Answer:
Estimate: $625
Product: $625

Explanation:
25 × $25
Estimate:
25 x $25 = $625
Product:
$20 x 2 tens = $40 tens
$20 x 5 ones = $100 ones
$5 x 2 tens = $10 tens
$5 x 5 ones = $25 ones.
Add partial products.
$400 + $100 + $100 + $25 = $625.

Question 13.
41 × 98
Estimate: _______
Product: _______

Answer:
Estimate: 4,000
Product: 4,018

Explanation:
41 × 98
Estimate: Think 41 is close to 40; 98 is close to 100.
40 x 100 = 4,000
Product:
90 x 4 tens = 360 tens
90 x 1 ones = 90 ones
8 x 4 tens = 32 tens
8 x 1 ones = 8 ones.
Add partial products.
3600 + 90 + 320 + 8 = 4,018.

Identify Relationships Algebra Use mental math to find the number.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 179 Q14

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 179 Q15

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 179 Q16

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 179 Q17

Page No. 180

Question 18.
Martin collects stamps. He counted 48 pages in his collector’s album. The first 20 pages each have 35 stamps in 5 rows. The rest of the pages each have 54 stamps. How many stamps does Martin have in his album?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 27
a. What do you need to know?
Type below:
_________

Answer:
The total stamps in the first 20 pages + The total stamps in the remaining pages.

Question 18.
b. How will you use multiplication to find the number of stamps?
Type below:
_________

Answer:
The first 20 pages each have 35 stamps in 5 rows.
So, 35 x 5 = 175 stamps.

Question 18.
c. Tell why you might use addition and subtraction to help solve the problem.
Type below:
_________

Answer:
As mentioned that the number of stamps available in the first 20 pages and the number of stamps available in the rest of the pages. We need to add all pages to get 48 pages stamps.

Question 18.
d. Show the steps to solve the problem.
Type below:
_________

Answer:
Martin has 48 pages in his collector’s album.
The first 20 pages each have 35 stamps in 5 rows.
So, 35 x 5 = 175 stamps.
The first 20 pages have 175 stamps.
The rest of the pages each have 54 stamps.
So, total stamps = 175 + 54 = 229 stamps.

Question 18.
e. Complete the sentences.
Martin has a total of _____ stamps on the first 20 pages.
There are _____ more pages after the first 20 pages in Martin’s album.
There are _____ stamps on the rest of the pages.
There are _____ stamps in the album.
Type below:
_________

Answer:
Martin has a total of __175___ stamps on the first 20 pages.
There are __24___ more pages after the first 20 pages in Martin’s album.
There are __54___ stamps on the rest of the pages.
There are ___229__ stamps in the album.

Question 19.
Select the expressions that have the same product as 35 × 17. Mark all that apply.
Options:
a. (30 × 10) + (30 × 7) + (5 × 10) + (5 × 7)
b. (30 × 17) + (5 × 17)
c. (35 × 30) + (35 × 5) + (35 × 10) + (35 × 7)
d. (35 × 10) + (35 × 7)
e. (35 × 10) + (30 × 10) + (5 × 10) + (5 × 7)
f. (35 × 30) + (35 × 5)

Answer:
a. (30 × 10) + (30 × 7) + (5 × 10) + (5 × 7)
b. (30 × 17) + (5 × 17)
d. (35 × 10) + (35 × 7)

Explanation:
35 × 17
30 x 10 =300
30 x 7 = 210
5 x 10 = 50
5 x 7 = 35
300 + 210 + 50 + 35 = 595.
a. (30 × 10) + (30 × 7) + (5 × 10) + (5 × 7) = 300 + 210 + 50 + 35 = 595 equal to 595.
b. (30 × 17) + (5 × 17) = 510 + 85 = 595 equal to 595.
c. (35 × 30) + (35 × 5) + (35 × 10) + (35 × 7) = 1050 + 175 + 350 + 245 = 1820 not equal to 595.
d. (35 × 10) + (35 × 7) = 350 + 245 = 595 equal to 595
e. (35 × 10) + (30 × 10) + (5 × 10) + (5 × 7) = 350 + 300 + 50 + 35 = 735 not equal to 595.
f. (35 × 30) + (35 × 5) = 1050 + 175 = 1,225 not equal to 595.

Common Core – Page No. 181

Choose a Multiplication Method

Estimate. Then choose a method to find the product.

Question 1.
Estimate: 1,200
3 1
× 4 3
——-
9 3
+ 1, 2 4 0
————
1, 3 3 3

Answer:
Estimate: 1,200
Product: 1, 3 3 3

Explanation:
Estimate: 1,200
3 1
× 4 3
——-
9 3
+ 1, 2 4 0
————
1, 3 3 3

Question 2.
6 7
× 8 5
——-
Estimate: _____
Product: ______

Answer:
Estimate: 6,300
Product: 5,695

Explanation:
Estimate: 67 is close to 70; 85 is close to 90.
70 x 90 = 6,300.
Product: 67 x 85
80 x 6 tens = 480 tens
80 x 7 ones = 560 ones
5 x 6 tens = 30 tens
5 x 7 ones = 35 ones.
Add partial products.
4800 + 560 + 300 + 35 = 5,695.

Question 3.
6 8
× 3 8
——-
Estimate: _____
Product: ______

Answer:
Estimate: 2,800
Product: 2,584

Explanation:
Estimate: 68 is close to 70; 38 is close to 40.
70 x 40 = 2,800.
Product: 68 x 38
30 x 6 tens = 180 tens
30 x 8 ones = 240 ones
8 x 6 tens = 48 tens
8 x 8 ones = 64 ones.
Add partial products.
1800 + 240 + 480 + 64 = 2,584.

Question 4.
9 5
× 1 7
——-
Estimate: _____
Product: ______

Answer:
Estimate: 1,700
Product: 1,615

Explanation:
Estimate: 95 is close to 100.
100 x 17 = 1,700.
Product: 95 x 17
10 x 9 tens = 90 tens
10 x 5 ones = 50 ones
7 x 9 tens = 63 tens
7 x 5 ones = 35 ones.
Add partial products.
900 + 50 + 630 + 35 = 1,615.

Question 5.
4 9
× 5 4
——-
Estimate: _____
Product: ______

Answer:
Estimate: 2,500
Product: 2,646

Explanation:
Estimate: 49 is close to 50; 54 is close to 50.
50 x 50 = 2,500.
Product: 49 x 54
50 x 4 tens = 200 tens
50 x 9 ones = 450 ones
4 x 4 tens = 16 tens
4 x 9 ones = 36 ones.
Add partial products.
2000 + 450 + 160 + 36 = 2,646.

Question 6.
9 1
× 2 6
——-
Estimate: _____
Product: ______

Answer:
Estimate: 2,700
Product: 2,366

Explanation:
Estimate: 91 is close to 90; 26 is close to 30.
90 x 30 = 2,700.
Product: 49 x 54
20 x 9 tens = 180 tens
20 x 1 ones = 20 ones
6 x 9 tens = 54 tens
6 x 1 ones = 6 ones.
Add partial products.
1800 + 20 + 540 + 6 = 2,366.

Question 7.
8 2
× 1 9
——-
Estimate: _____
Product: ______

Answer:
Estimate: 1,600
Product: 1,558

Explanation:
Estimate: 82 is close to 80; 19 is close to 20.
80 x 20 = 1,600.
Product: 82 x 19
10 x 8 tens = 80 tens
10 x 2 ones = 20 ones
9 x 8 tens = 72 tens
9 x 2 ones = 18 ones.
Add partial products.
800 + 20 + 720 + 18 = 1,558.

Question 8.
4 6
× 2 7
——-
Estimate: _____
Product: ______

Answer:
Estimate: 1,500
Product: 1,242

Explanation:
Estimate: 46 is close to 50; 27 is close to 30.
50 x 30 = 1,500.
Product: 46 x 27
20 x 4 tens = 80 tens
20 x 6 ones = 120 ones
7 x 4 tens = 28 tens
7 x 6 ones = 42 ones.
Add partial products.
800 + 120 + 280 + 42 = 1,242.

Question 9.
4 1
× 3 3
——-
Estimate: _____
Product: ______

Answer:
Estimate: 1,200
Product: 1,353

Explanation:
Estimate: 41 is close to 40; 33 is close to 30.
40 x 30 = 1,200.
Product: 41 x 33
30 x 4 tens = 120 tens
30 x 1 ones = 30 ones
3 x 4 tens = 12 tens
3 x 1 ones = 3 ones.
Add partial products.
1200 + 30 + 120 + 3 = 1,353.

Question 10.
9 7
× 1 3
——-
Estimate: _____
Product: ______

Answer:
Estimate: 1,300
Product: 1,261

Explanation:
Estimate: 97 is close to 100.
100 x 13 = 1,300.
Product: 97 x 13
10 x 9 tens = 90 tens
10 x 7 ones = 70 ones
3 x 9 tens = 27 tens
3 x 7 ones = 21 ones.
Add partial products.
900 + 70 + 270 + 21 = 1,261.

Question 11.
7 5
× 6 9
——-
Estimate: _____
Product: ______

Answer:
Estimate: 5,600
Product: 5,195

Explanation:
Estimate: 75 is close to 80; 69 is close to 70.
80 x 70 = 5,600.
Product: 75 x 69
60 x 7 tens = 420 tens
60 x 5 ones = 300 ones
9 x 7 tens = 63 tens
9 x 5 ones = 45 ones.
Add partial products.
4200 + 300 + 630 + 45 = 5,195.

Problem Solving

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 181 Q12

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 181 Q13

Common Core – Page No. 182

Lesson Check

Question 1.
A choir needs new robes for each of its 46 singers. Each robe costs $32. What will be the total cost for all 46 robes?
Options:
a. $1,472
b. $1,372
c. $1,362
d. $230

Answer:
a. $1,472

Explanation:
46 x $32
40 x $32 = $1,280
6 x $32 = $192
$1,280 + $192 = $1,472

Question 2.
A wall on the side of a building is made up of 52 rows of bricks with 44 bricks in each row. How many bricks make up the wall?
Options:
a. 3,080
b. 2,288
c. 488
d. 416

Answer:
b. 2,288

Explanation:
52 x 44
50 x 44 = 2,200
2 x 44 = 88
2,200 + 88 = 2,288.
2,288 bricks make up the wall.

Spiral Review

Question 3.
Which expression shows how to multiply 4 × 362 by using place value and expanded form?
Options:
a. (4 × 3) + (4 × 6) + (4 × 2)
b. (4 × 300) + (4 × 600) +(4 × 200)
c. (4 × 300) + (4 × 60) + (4 × 20)
d. (4 × 300) + (4 × 60) + (4 × 2)

Answer:
d. (4 × 300) + (4 × 60) + (4 × 2)

Explanation:
4 × 362 = 1,448
a. (4 × 3) + (4 × 6) + (4 × 2) = 12 + 24 + 8 = 44 not equal to 1,448.
b. (4 × 300) + (4 × 600) +(4 × 200) = 1200 + 2400 + 800 = 4,400 not equal to 1,448.
c. (4 × 300) + (4 × 60) + (4 × 20) = 1200 + 240 + 80 = 1,520 not equal to 1,448.
d. (4 × 300) + (4 × 60) + (4 × 2) = 1200 + 240 + 8 = 1,448 equal to 1,448.

Question 4.
Use the model below. What is the product 4 x 492?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 28
Options:
a. 16 + 36 + 8 = 60
b. 160 + 36 + 8 = 204
c. 160 + 360 + 8 = 528
d. 1,600 + 360 + 8 = 1,968

Answer:
d. 1,600 + 360 + 8 = 1,968

Explanation:
Grade 4 Chapter 3 Common Core 182
1,600 + 360 + 8 = 1,968

Question 5.
What is the sum 13,094 + 259,728?
Options:
a. 272,832
b. 272,822
c. 262,722
d. 262,712

Answer:
c. 262,722

Explanation:
13,094 + 259,728 = 262,722

Question 6.
During the 2008–2009 season, there were 801,372 people who attended the home hockey games in Philadelphia. There were 609,907 people who attended the home hockey games in Phoenix. How much greater was the home attendance in Philadelphia than in Phoenix that season?
Options:
a. 101,475
b. 191,465
c. 201,465
d. 202,465

Answer:
b. 191,465

Explanation:
801,372 – 609,907 = 191,465
Philadelphia attendance is 191,465 greater than in Phoenix that season.

Page No. 185

Question 1.
An average of 74 reports with bird counts were turned in each day in June. An average of 89 were turned in each day in July. How many reports were turned in for both months? (Hint: There are 30 days in June and 31 days in July.)
First, write the problem for June.
Type below:
__________

Answer:
Given that An average of 74 reports with bird counts was turned in each day in June.
For June Month, there are 30 days = 30 x 74 = 2,220.

Question 1.
Next, write the problem for July.
Type below:
__________

Answer:
An average of 89 reports with bird counts was turned in each day in July.
For July Month, there are 31 days = 31 x 89 = 2,759.

Question 1.
Last, find and add the two products.
____________ reports were turned in for both months.
Type below:
__________

Answer:
Given that An average of 74 reports with bird counts was turned in each day in June.
For June Month, there are 30 days = 30 x 74 = 2,220.
An average of 89 reports with bird counts was turned in each day in July.
For July Month, there are 31 days = 31 x 89 = 2,759.
Add two products to get the total number of reports that were turned in for both months.
2,220 + 2,759 = 4,979.

Question 2.
What if an average of 98 reports were turned in each day for the month of June? How many reports were turned in for June? Describe how your answer for June would be different.
______ reports

Answer:
720 more reports

Explanation:
Given that an average of 98 reports was turned in each day for the month of June.
June has 30 days.
Total number of reports were turned in for June = 30 x 98 = 2, 940.
From the above answer, 98 − 74 = 24. So, there would be 30 × 24, or 720 more reports.

Question 3.
There are 48 crayons in a box. There are 12 boxes in a carton. Mr. Johnson ordered 6 cartons of crayons for the school. How many crayons did he get?
______ crayons

Answer:
3,456 crayons

Explanation:
There are 48 crayons in a box.
There are 12 boxes in a carton.
So, 1 carton = 48 x 12 = 576 crayons.
If Mr. Johnson ordered 6 cartons of crayons for the school, 6 x 576 crayons = 3,456 crayons.
He gets 3,456 crayons.

Question 4.
Make Sense of Problems Each of 5 birdwatchers reported seeing 15 roseate spoonbills in a day. If they each reported seeing the same number of roseate spoonbills over 14 days, how many would be reported?
______ roseate spoonbills

Answer:
1,050 roseate spoonbills

Explanation:
Given that, 1 day –>5 birdwatchers reported 15 roseate spoonbills = 5 x 15 = 75 roseate spoonbills.
So, in 14 days –> 5 birdwatchers reported 75 x 14 = 1,050 roseate spoonbills.

Page No. 186

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 186 Q5

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 186 Q6
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 186 Q6.1

Question 7.
Lydia is having a party on Saturday. She decides to write a riddle on her invitations to describe her house number on Cypress Street. Use the clues to find Lydia’s address.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 29
______ Cypress Street

Answer:
14827 Cypress Street

Explanation:
Given that tens digit is 5 less than 7 = 7 – 5 = 2. 2 is the tens digit.
The thousands digit is twice the digit in the tens place = 2 x 2 = 4.
The hundreds digit is the greatest even number that is less than 10 i.e, 8.
The ones digit is the product of 7 and 1 = 7 x 1 = 7.
The ten thousands digit is the difference between the hundreds digit and the ones digit. So, 8 – 7 = 1.
Add the products to get the final answer = 14827.
Lydia’s address ( house number ) is 14827 Cypress Street.

Question 8.
A school is adding 4 rows of seats to the auditorium. There are 7 seats in each row. Each new seat costs $99. What is the total cost for the new seats? Show your work.
$ ______

Answer:
$2,772

Explanation:
Given that A school is adding 4 rows of seats to the auditorium. There are 7 seats in each row.
So, 7 x 4 = 28 seats are available in an auditorium.
Each new seat costs $99.
28 x $99 = $2,772 for total cost of the new seats.

Common Core – Page No. 187

Problem Solving Multiply 2 – Digit numbers

Solve each problem. Use a bar model to help.

Question 1.
Mason counted an average of 18 birds at his bird feeder each day for 20 days. Gloria counted an average of 21 birds at her bird feeder each day for 16 days. How many more birds did Mason count at his feeder than Gloria counted at hers?
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 30
Birds counted by Mason: 18 × 20 = 360
Birds counted by Gloria: 21 × 16 = 336
Draw a bar model to compare.
Subtract. 360 – 336 = 24
So, Mason counted 24 more birds.

Answer:
Birds counted by Mason: 18 × 20 = 360
Birds counted by Gloria: 21 × 16 = 336
Draw a bar model to compare.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Common Core img 30
Subtract. 360 – 336 = 24
So, Mason counted 24 more birds.

Question 2.
The 24 students in Ms. Lee’s class each collected an average of 18 cans for recycling. The 21 students in Mr. Galvez’s class each collected an average of 25 cans for recycling. How many more cans were collected by Mr. Galvez’s class than Ms. Lee’s class?
______ more cans

Answer:
The number of cans collected by Ms. Lee’s class = 18 x 24 = 432.
The number of cans collected by Mr. Galvez’s class = 25 x 21 = 525.
Use Bar Model
Grade 4 Chapter 3 Common Core 187
Subtract. 525 – 432 = 93 more cans.
So, Mr. Galvez’s class collected 93 more cans than Ms. Lee’s class.

Question 3.
At East School, each of the 45 classrooms has an average of 22 students. At West School, each of the 42 classrooms has an average of 23 students. How many more students are at East School than at West School?
______ more students

Answer:
Students in East school = 45 x 22 = 990.
Students in West School = 42 x 23 = 966.
Use Bar Model
Grade 4 Chapter 3 Common Core image 2 187
Subtract. 990 – 966 = 24.
So, East School has 24 students more than West School.

Question 4.
A zoo gift shop orders 18 boxes of 75 key rings each and 15 boxes of 80 refrigerator magnets each. How many more key rings than refrigerator magnets does the gift shop order?
______ more key rings

Answer:
Number of Key Rings = 75 x 18 = 1,350.
Number of Refrigerator Magnets= 80 x 15 = 1,200.
Use Bar Model
Grade 4 Chapter 3 Common Core image 3 187
Subtract. 1,350 – 1,200 = 150.
So, key rings are 150 more than refrigerator magnets.

Common Core – Page No. 188

Lesson Check

Question 1.
Ace Manufacturing ordered 17 boxes with 85 ball bearings each. They also ordered 15 boxes with 90 springs each. How many more ball bearings than springs did they order?
Options:
a. 5
b. 85
c. 90
d. 95

Answer:
d. 95

Explanation:
Number of ball bearings = 85 x 17 = 1,445.
Number of springs = 90 x 15 = 1,350.
Use Bar Model
Grade 4 Chapter 3 Common Core image 1 188
Subtract. 1,445 – 1,350 = 95.
So, ball bearings are 95 more than springs.

Question 2.
Elton hiked 16 miles each day on a 12-day hiking trip. Lola hiked 14 miles each day on her 16-day hiking trip. In all, how many more miles did Lola hike than Elton hiked?
Options:
a. 2 miles
b. 18 miles
c. 32 miles
d. 118 miles

Answer:
c. 32 miles

Explanation:
Hiking trip by Elton = 12 x 16 = 192.
Hiking trip by Lola = 16 x 14 = 224.
Use Bar Model
Grade 4 Chapter 3 Common Core image 2 188
Subtract. 224 – 192 = 32.
So, the Hiking trip by Lola is 32 times more than the Hiking trip by Elton.

Spiral Review

Question 3.
An orchard has 24 rows of apple trees. There are 35 apple trees in each row. How many apple trees are in the orchard?
Options:
a. 59
b. 192
c. 740
d. 840

Answer:
d. 840

Explanation:
An orchard has 24 rows of apple trees. There are 35 apple trees in each row.
24 x 35 = 840 apple trees are in the orchard.

Question 4.
An amusement park reported 354,605 visitors last summer. What is this number rounded to the nearest thousand?
Options:
a. 354,600
b. 355,000
c. 360,000
d. 400,000

Answer:
b. 355,000

Explanation:
An amusement park reported 354,605 visitors last summer. 4,605 is close to 5,000. So, the answer is 355,000.

Question 5.
Attendance at the football game was 102,653. What is the value of the digit 6?
Options:
a. 6
b. 60
c. 600
d. 6,000

Answer:
c. 600

Explanation:
Digit 6 is at hundreds of positions. So, the answer is 6 x 100 = 600.

Question 6.
Jill’s fish weighs 8 times as much as her parakeet. Together, the pets weigh 63 ounces. How much does the fish weigh?
Options:
a. 7 ounces
b. 49 ounces
c. 55 ounces
d. 56 ounces

Answer:
d. 56 ounces

Explanation:
Let Jill’s parakeet = X.
Jill’s fish weighs 8 times as much as her parakeet = 8X.
Together, the pets weigh 63 ounces.
X + 8X = 63.
9X = 63.
X = 63/9 = 7.
So, Jill’s parakeet =7.
Jill’s fish = 7 x 8 = 56 ounces.

Review/Test – Page No. 189

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 189 Q1

Mrs. Traynor’s class is taking a field trip to the zoo. The trip will cost $26 for each student. There are 22 students in her class.

Question 2.
Part A
Round each factor to estimate the total cost of the student’s field trip.
$ ______

Answer:
$600

Explanation:
Total cost of the students’ field trip = 22 x $26.
22 x $26
20 x $30 = $600
The total cost would be about $600.

Question 2.
Part B
Use compatible numbers to estimate the total cost of the field trip.
$ ______

Answer:
$500

Explanation:
If we use compatible numbers to estimate the total cost of the field trip.
22 x $26
20 × 25 = 500
The total cost would be about $500.

Question 2.
Part C
Which do you think is the better estimate? Explain.
Better estimate: _________

Answer:
Using rounded numbers is a better estimate. When rounded numbers are used, one estimated factor was $4 more than the actual factor and the other estimated factor was $2 that is less than the actual factor. So, the estimate should be close to the actual one. When compatible numbers are used both estimated factors were less than the actual factors. So, the product will be an underestimate.

Review/Test – Page No. 190

For numbers 3a–3e, select Yes or No to show if the answer is correct.

Question 3.
3a. 35 × 10 = 350
i. yes
ii. no

Answer:
i. yes

Explanation:
35 x 10 = 350
30 x 10 = 300.
5 x 10 = 50.
300 + 50 = 350.

Question 3.
3b. 19 × 20 = 380
i. yes
ii. no

Answer:
i. yes

Explanation:
19 × 20 = 380
19 x 20 = 19 x 2 tens.
19 x 20 = 38 tens = 380.

Question 3.
3c. 12 × 100 = 120
i. yes
ii. no

Answer:
ii. no

Explanation:
12 x 100 = 120.
10 x 100 = 1000
2 x 100 = 200.
1000 + 200 = 1200.

Question 3.
3d. 70 × 100 = 7,000
i. yes
ii. no

Answer:
i. yes

Explanation:
70 x 100 = 7,000
100 x 7 tens = 700 tens = 7,000

Question 3.
3e. 28 × 30 = 2,100
i. yes
ii. no

Answer:
ii. no

Explanation:
28 × 30
20 x 30 = 600
8 x 30 = 240
600 + 240 = 840

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 190 Q4

Question 5.
Which would provide a reasonable estimate for each product? Write the estimate beside the product. An estimate may be used more than once
23 × 38 __________
31 × 32 __________
46 × 18 __________
39 × 21 __________

Answer:
23 × 38 –> 25 x 40
31 x 32 –> 30 × 30
46 × 18 –> 50 × 20
39 × 21 –> 25 × 40

Explanation:
23 × 38; 23 is close to 25; 38 is close to 40.
So, the estimated product is 25 x 40
31 x 32; 31 is close to 30; 32is close to 30.
So, the estimated product is 30 × 30
46 × 18; 46 is close to 50; 18 is close to 20.
So, the estimated product is 50 × 20
39 × 21; 39 is close to 40; 21 is close to 25.
So, the estimated product is 25 × 40

Question 6.
There are 26 baseball teams in the league. Each team has 18 players. Write a number sentence that will provide a reasonable estimate for the number of players in the league. Explain how you found your estimate.
Type below:
__________

Answer:
There are 26 baseball teams in the league. Each team has 18 players.
26 x 18
25 x 20
We Rounded each factor to its close factor, then simplified the multiplication.

Question 7.
The model shows 48 × 37. Write the partial products.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 31
Type below:
__________

Answer:
Grade 4 Chapter 3 Common Core image 1 190
Partial Products are 1200, 240, 280, 56

Review/Test – Page No. 191

Question 8.
Jess made this model find the product 32 × 17. Her model is incorrect.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 32
Part A
What did Jess do wrong?
Type below:
__________

Answer:
Jess added the numbers in the model instead of multiplying.

Question 8.
Part B
Redraw the model so that it is correct.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 33
Type below:
__________

Answer:
Grade 4 Chapter 3 Common Core image 2 190

Question 8.
Part C
What is the actual product 32 × 17?
______

Answer:
544

Explanation:
32 × 17
10 x 32 = 320
7 x 32 = 224
320 + 224 = 544.

Question 9.
Tatum wants to use partial products to find 15 × 32. Write the numbers in the boxes to show 15 × 32.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 34
Type below:
__________

Answer:
Grade 4 Chapter 3 Common Core image 4 190

Review/Test – Page No. 192

Question 10.
Which product is shown by the model? Write the letter of the product on the line below the model.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 35
Type below:
__________

Answer:
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 35
C                                              A                                                  B
10 + 3 = 13
10 + 3 = 13
13 x 13
2. 10 + 7 = 17
30 + 6 = 36
17 x 36
3. 20 + 4 = 24
10 + 4 = 14
24 x 14

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 192 Q11

Question 12.
Write the unknown digits. Use each digit exactly once.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 36
Type below:
__________

Answer:
Grade 4 Chapter 3 Common Core image 1 192
90 x 40 = 3,600
90 x 6 = 540
3 x 40 = 120
3 x 6 = 18.
3,600 + 540 + 120 + 8 = 4,278.

Question 13.
Mike has 16 baseball cards. Niko has 17 times as many baseball cards as Mike does. How many baseball cards does Niko have?
________ baseball cards

Answer:
272 baseball cards

Explanation:
Mike has 16 baseball cards. Niko has 17 times as many baseball cards as Mike does.
Niko have 16 x 17 = 272 baseball cards.

Question 14.
Multiply.
36 × 28 = ________

Answer:
1,008

Explanation:
36 x 28
20 x 30 = 600
20 x 6 = 120
8 x 30 = 240
8 x 6 = 48
600 + 120 + 240 + 48 = 1,008

Review/Test – Page No. 193

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 193 Q15

Question 16.
Select another way to show 25 × 18. Mark all that apply.
Options:
a. (20 × 10) + (20 × 8) + (5 × 10) + (5 × 8)
b. (25 × 20) + (25 × 5) + (25 × 10) + (25 × 8)
c. (20 × 18) + (5 × 10) + (5 × 8)
d. (25 × 10) + (25 × 8)
e. (25 × 20) + (25 × 5)

Answer:
a. (20 × 10) + (20 × 8) + (5 × 10) + (5 × 8)
c. (20 × 18) + (5 × 10) + (5 × 8)
d. (25 × 10) + (25 × 8)

Explanation:
25 × 18
10 x 25 = 250
8 x 25 = 200
250 + 200 = 450.
a. (20 × 10) + (20 × 8) + (5 × 10) + (5 × 8) = 200 + 160 + 50 + 40 = 450
b. (25 × 20) + (25 × 5) + (25 × 10) + (25 × 8) = 500 + 125 + 250 + 200 = 1,075
c. (20 × 18) + (5 × 10) + (5 × 8) = 360 + 50 + 40 = 450
d. (25 × 10) + (25 × 8) = 250 + 200 = 450
e. (25 × 20) + (25 × 5) = 500 + 125 = 625

Question 17.
Terrell runs 15 sprints. Each sprint is 65 meters. How many meters does Terrell run? Show your work.
______ meters

Answer:
975 meters

Explanation:
Terrell run 15 x 65 = 975 meters.

Question 18.
There are 3 new seats in each row in a school auditorium. There are 15 rows in the auditorium. Each new seat cost $74. What is the cost for the new seats? Explain how you found your answer.
$ ______

Answer:
$3,330

Explanation:
Given that There are 3 new seats in each row in a school auditorium. There are 15 rows in the auditorium. Each new seat cost $74.
So, 3 x 15 = 45 seats are available in an auditorium.
Each new seat costs $74.
45 x $74 = $3,330 for total cost of the new seats.

Question 19.
Ray and Ella helped move their school library to a new building. Ray packed 27 boxes with 25 books in each box. Ella packed 23 boxes with 30 books in each box. How many more books did Ella pack? Show your work.
______ books

Answer:
15 books

Explanation:
Ray packed 27 x 25 = 675 books.
Ella packed 23 x 30 = 690 books
Ella packed 690 – 675 = 15 books more than Ray.

Review/Test – Page No. 194

Question 20.
Julius and Walt are finding the product of 25 and 16.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Review/Test img 37
Part A
Julius’ answer is incorrect. What did Julius do wrong?
Type below:
__________

Answer:
Julius multiplied 25 by 10 and then multiplied 25 by 6 correctly. He added the two partial products incorrectly.

Question 20.
Part B
What did Walt do wrong?
Type below:
__________

Answer:
Walt multiplied 6 by 5 and got 300 instead of 30

Question 20.
Part C
What is the correct product?
Type below:
__________

Answer:
25 x 16 = 400

Question 21.
A clothing store sells 26 shirts and 22 pairs of jeans. Each item of clothing costs $32.
Part A
What is a reasonable estimate for the total cost of the clothing?
Show or explain how you found your answer.
$ ______

Answer:
$1500

Explanation:
A clothing store sells 26 shirts and 22 pairs of jeans. 26 + 22 = 48 clothes.
Each item of clothing costs $32.
48 x $32
50 x $30 = $1500

Question 21.
Part B
What is the exact answer for the total cost of the clothing? Show or explain how you found your answer.
$ ______

Answer:
$1,536

Explanation:
48 x $32
40 x $32 = $1,280
8 x $32 = $256
$1,280 + $256 = $1,536

Page No. 199

Question 1.
A restaurant has 68 chairs. There are six chairs at each table. About how many tables are in the restaurant?
Estimate. 68 ÷ 6
Think: What number times 6 is about 68?
10 × 6 = ___
11 × 6 = ___
12 × 6 = ___
68 is closest to ______, so the best estimate is about _______ tables are in the restaurant.
Type below:
__________

Answer:
68 is close to 70 and 6 is close to 5.
So, 70/5 = 12.
10 × 6 = __60_
11 × 6 = _66__
12 × 6 = _72__
68 is closest to ___66___, so the best estimate is about 11 x 6 = 66 tables are in the restaurant.

Find two numbers the quotient is between. Then estimate the quotient.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 199 Q2

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 199 Q3

Find two numbers the quotient is between. Then estimate the quotient.

Question 4.
90 ÷ 7
between _______ and _______

Answer:
between 12 and 13
about 13

Explanation:
12 x 7 = 84; 13 x 7 = 91.
The quotient of 90 ÷ 7 is between 12 and 13.

Question 5.
67 ÷ 4
between _______ and _______

Answer:
between 16 and 17
about 17

Explanation:
16 x 4 = 64; 17 x 4 = 68.
The quotient of 67 ÷ 4 is between 16 and 17.

Question 6.
281 ÷ 9
between _______ and _______

Answer:
between 30 and 40
about 30

Explanation:
30 x 9 = 270; 40 x 9 = 360.
The quotient of 281 ÷ 9 is between 30 and 40.

Question 7.
102 ÷ 7
between _______ and _______

Answer:
between 14 and 15
about 15

Explanation:
14 x 7 = 98; 15 x 7 = 105.
The quotient of 102 ÷ 7 is between 14 and 15.

Question 8.
85 ÷ 6
between _______ and _______

Answer:
between 14 and 15
about 14

Explanation:
14 x 6 = 84; 15 x 6 = 90.
The quotient of 85 ÷ 6 is between 14 and 15.

Question 9.
220 ÷ 8
between _______ and _______

Answer:
between 20 and 30
about 30

Explanation:
20 x 8 = 160; 30 x 8 = 240.
The quotient of 220 ÷ 8 is between 20 and 30.

Decide whether the actual quotient is greater than or less than the estimate given. Write < or >.

Question 10.
83 ÷ 8 _______ 10

Answer:
>

Explanation:
83 ÷ 8 = 10.375 > 10

Question 11.
155 ÷ 4 _______ 40

Answer:
<

Explanation:
155 ÷ 4 = 38.75 < 40

Question 12.
70 ÷ 6 _______ 11

Answer:
>

Explanation:
70 ÷ 6 = 11.666 > 11

Question 13.
What’s the Question? A dolphin’s heart beats 688 times in 6 minutes. Answer: about 100 times.
Type below:
__________

Answer:
About how many times does a dolphin’s heart beats in 1 minute?

Question 14.
Analyze A mother bottlenose ate about 278 pounds of food in one week. About how much food did she eat in a day?
about _____ pounds

Answer:
about 40 pounds

Explanation:
278 ÷ 7
The quotient of 278 ÷ 7 is between 39 and 40.

Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers Page 199 Q15

Page No. 200

Question 16.
If a bottlenose dolphin can eat 175 pounds of fish, squid, and shrimp in a week, how many pounds of food does it eat in a day? Milo says the answer is about 20 pounds. Leah says the answer is about 30 pounds. Who is correct? Explain.
Go Math Grade 4 Answer Key Chapter 3 Multiply 2-Digit Numbers img 38
________

Answer:
The bottlenose dolphin can eat 25 pounds in 1 day.
Both answers are correct. Because 25 pounds is between 20 and 30 pounds.

Explanation:
1 week = 7 days.
The bottlenose dolphin can eat 175 pounds for 7 days.
For 1 day = 175 ÷ 7 = 25 pounds.
The bottlenose dolphin can eat 25 pounds in 1 day.
Both answers are correct. Because 25 pounds is between 20 and 30 pounds.

Question 17.
Four families went out for lunch. The total food bill came to $167. The families also left a $30 tip for the waitress. If each family spent the same amount, how much did each family spend on dinner? Explain how you found your answer.
$ ______

Answer:
$98.5

Explanation:
Four families went out for lunch. The total food bill came to $167. The families also left a $30 tip for the waitress.
So, total amount = $167 + $30 = $197.
If each family spent the same amount = $197 ÷ 2 = $98.5
Each family spent $98.5.

Question 18.
There are 6 showings of a film about Van Gogh at the Art Museum. A total of 459 people saw the film. The exact number of people were at each show. About how many people were at each show? Circle the numbers the quotient is between. Then explain how you found your answer.
40 50 60 70 80
Type below:
_________

Answer:
40 50 60 70 80
I found multiples of 6 that 459 is between. 70 × 6 = 420 and 80 × 6 = 480. Since 459 is closer to 480, 459 ÷ 6 is about 80.

Conclusion

Hope the data shared about Go Math Grade 4 Answer Key Chapter 3 Multiply 2- Digit Number has helped you in your preparation. If you feel any learning is missing do give us your suggestions and we will consider them if possible. Just keep on visiting our site to get the latest update on Grade 4 Go Math HMH Answer Keys for other chapters as well.

Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction

Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction

Go Math Grade 2 Chapter 6 Answer Key 3-Digit Addition and Subtraction Concepts

3-Digit Addition and Subtraction Show What You Know

Model Subtracting Tens
Write the difference.
Question 1.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.1
5 tens − 3 tens = ______ tens
50 − 30 = _____
Answer:
20

Explanation:
There are 5 tens if we subtract 3 tens only 2 tens will remain.Therefore 50‐30 =20.

Question 2.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.2
7 tens − 2 tens = ______ tens
70 − 20 = _____
Answer:
50

Explanation:
There are 7 tens if we subtract 2 tens only 5 tens will remain.Therefore 70‐20 =50.

2-Digit Addition
Write the sum.
Question 3.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.3
Answer:

Explanation:
In the above picture there are 7 tens and 9 ones.So, 54+25=79

Question 4.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.4
Answer:

Explanation:
In the above picture there are 4 tens and 13 ones.13 ones is 1 tens and 3 ones.Finally there are 5 tens and 3 ones.So, 35+18=83

Question 5.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.5
Answer:

Explanation:
In the above picture there are 14 tens and 9 ones.14 tens means 1 hundreds and 4 tens.Finally there are 1 hundreds, 4 tens and 9 ones.So, 82+67=149.

Question 6.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.6
Answer:

Explanation:
In the above picture there are 10 tens and 10 ones.10 tens means 1 hundreds and 10 ones means 1 tens.Finally there are 1 hundreds and 1 tens. So, 29+81=110

Hundreds, Tens, and Ones
Write the hundreds, tens, and ones shown. Write the number.
Question 7.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.7
Answer:

Explanation:
In the above picture there are 2 hundreds, 5 tens and 3 ones.So, the number is 253.

Question 8.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 1.8
Answer:

Explanation:
In the above picture there are 3 hundreds, 5 tens and 1 ones.So, the number is 351.

3-Digit Addition and Subtraction Vocabulary Builder

2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 2.1
Visualize It
Fill in the graphic organizer by writing examples of ways to regroup.

Understand Vocabulary
Question 1.
Write a number that has a hundreds digit that is greater than its tens digit. _________
Answer:
540

Explanation:
In the number 540 the tens digit is 4 and the hundreds digit is 5.As 5 is greater than 4 the number has a hundreds digit that is greater than its tens digit.

Question 2.
Write an addition sentence that has a sum of 20. ______
Answer:
10+10=20

Explanation:
There are 10 ones and 10 ones in the above picture.10 ones means 1 tens.Finally there are 2 tens.So, 10+10=20.

Question 3.
Write a subtraction sentence that has a difference of 10. ________
Answer:
20-10=10

Explanation:
There are 2 tens in above picture if we subtract 1 tens from it we get 1 tens.So, 20‐10=10.

3-Digit Addition and Subtraction Game 2-Digit Shuffle

Materials

  • number cards 10–50
  • 2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 2.3

Play with a partner.

  1. Shuffle the number cards. Place them face down in a pile.
  2. Take two cards. Say the sum of the two numbers.
  3. Your partner checks your sum.
  4. If your sum is correct, place a counter on a button. If you regrouped to solve, place a counter on another button.
  5. Take turns. Cover all the buttons. The player with more counters on the board wins.
  6. Repeat the game, saying the difference between the two numbers for each turn.
    2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 2.4

3-Digit Addition and Subtraction Vocabulary Game

Picture It
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 2.5
For 3 to 4 players
Materials

  • timer
  • sketch pad

How to Play

  1. Take turns to play.
  2. Choose a math word from the Word Box. Do not say the word.
  3. Set the timer for 1 minute.
  4. Draw pictures and numbers to give clues about the math word.
  5. The first player to guess the word gets 1 point. If he or she use the word in a sentence, they get 1 more point. That player gets the next turn.
  6. The first player to score 5 points wins.

The Write Way
Reflect
Choose one idea. Write about it on the lines below.

  • Tell how to solve this problem.
    42 – 25 = _____
  • Write a paragraph that uses at least three of these words.
    addends digit sum hundred regroup
  • Explain something you know about regrouping.
    2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 2.6

Lesson 6.1 Draw to Represent 3-Digit Addition

Essential Question How do you draw quick pictures to show adding 3-digit numbers?

Listen and Draw

Draw quick pictures to model the problem. Then solve.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 1

MATHEMATICAL PRACTICES
Use Tools Explain how your quick pictures show the problem.
Answer:

Explanation:
Manuel read 45 pages in a book and then he read 31 morw pages.As shown in the above picture there are 7 tens and 6 ones.It is 76.Therefore manuel read 76 pages in all.

Share and Show

Draw quick pictures. Write how many hundreds, tens, and ones in all. Write the number.
Question 1.
Add 125 and 344.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 2
_____ hundreds _____ tens _____ ones
______
Answer:

4 hundreds 6 tens and 9 ones is 469.

Explanation:
In the above picture there are 4 hundreds, 6 tens and 9 ones.So, the number is 469.

Question 2.
Add 307 and 251.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 3
_____ hundreds _____ tens _____ ones
______
Answer:

5 hundreds 5 tens and 8 ones is 558

Explanation:
In the above picture there are 5 hundreds, 5 tens and 8 ones.So, the number is 558.

On Your Own

Draw quick pictures. Write how many hundreds, tens, and ones in all. Write the number.
Question 3.
Add 231 and 218.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 4
_____ hundreds _____ tens _____ ones
______
Answer:

4 hundreds 4 tens and 9 ones is 449.

Explanation:
In the above picture there are 4 hundreds, 4 tens and 9 ones.So, the number is 449.

Question 4.
Add 232 and 150.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 5
_____ hundreds _____ tens _____ ones
______
Answer:

3 hundreds 8 tens and 2 onea is 382

Explanation:
In the above picture there are 3 hundreds, 8 tens and 2 ones.So, the number is 382.

Question 5.
THINK SMARTER
Use the quick pictures to find the two numbers being added. Then write how many hundreds, tens, and ones in all. Write the number.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 6
Add ____ and _____
_____ hundreds _____ tens _____ ones
______
Answer:
Add 153 and 205
There are 3 hundreds, 5 tens and 8 ones.So, the sum of 153 and 205 is 358.
3 hundreds 5 tens and 8 ones.

Problem Solving • Applications

Question 6.
MATHEMATICAL PRACTICE Represent a Problem
There are 125 poems in Carrie’s book and 143 poems in Angie’s book. How many poems are in these two books? Draw a quick picture to solve.
______ poems
Answer:

Explanation:
Add 125 and 143
There are 2 hundreds, 6 tens and 8 ones.So, the sum of 125 and 143 is 268.
2 hundreds 6 tens and 8 ones.

Question 7.
THINK SMARTER+
Rhys wants to add 456 and 131.
Help Rhys solve this problem. Draw quick pictures. Write how many hundreds, tens, and ones in all. Write the number.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 7
_____ hundreds _____ tens _____ ones
______
Answer:

Explanation:
Add 456 and 131.
In the above picture there are 5 hundreds, 8 tens and 7 ones.So the number is 587.
5 hundreds 8 tens 7 ones

TAKE HOME ACTIVITY • Write 145 + 122. Have your child explain how he or she can draw quick pictures to find the sum.
Answer:

Explanation:
Add 145 and 122.
There are 2 hundreds, 6 tens and 7 ones in the above picture.So, the sum of 145 and 122 is 267.
2 hundred 6 tens 7 ones.

Draw to Represent 3-Digit Addition Homework & Practice 6.1

Draw quick pictures. Write how many hundreds, tens, and ones in all. Write the number.
Question 1.
Add 142 and 215.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.1 8
_____ hundreds _____ tens _____ ones
______
Answer:

Explanation:
Add 142 and 215.
In the above picture add the hundreds, tens and ones.There are 3 hundreds, 5 tens and 7 ones.So the sum of 142 and 215 is 357.
3 hundreds 5 tens 7 ones.

Problem Solving
Solve. Write or draw to explain.
Question 2.
A farmer sold 324 lemons and 255 limes. How many pieces of fruit did the farmer sell altogether?
______ pieces of fruit
Answer:

Explanation:
Add 324 and 255.
In the above picture add the hundreds,tens and ones.There are 5 hundreds 7 tens and 9 ones.So the sum of 324 and 255 is 579.
5 hundreds 7 tens 9 ones.

Question 3.
WRITE
Draw quick pictures and write to tell how you would add 342 and 416.
Answer:

Explanation:
Add 342 and 416.
In the above picture add the hundreds,tens and ones.There are 7 hundreds, 5 tens and 8 ones.So, the sum of 342 and 416 is 758.
7 hundreds 5 tens and 8 ones.

Lesson Check
Question 1.
Ms. Carol sold 346 child tickets and 253 adult tickets. How many tickets did Ms. Carol sell?
______ tickets
Answer:

Explanation:
Add 346 and 253.
In the above picture add the humdreds, tens and ones.There are 5 hundreds, 9 tens and 9 ones.So, the sum of 346 and 253 is 599.
5 hundreds 9 tens 9 ones.

Question 2.
Mr. Harris counted 227 gray pebbles and 341 white pebbles. How many pebbles did Mr. Harris count?
_______ pebbles
Answer:

Explanation:
Add 227 and 341.
In the above picture add the hundreds, tens and ones.There are 5 hundreds,6 tens and 8 ones.So the sum of 227 and 341 is 568.
5 hundreds 6 tens 8 ones.

Question 3.
Pat has 3 rows of shells. There are 4 shells in each row. How many shells does Pat have?
_____ shells
Answer:

Explanation:
Add the shells in the above picture.There are 3 rows of shells and each row has 4 shells each.So, there are 12 shells in all.
1 tens and 2 ones.

Question 4.
Kara counted 32 red pens, 25 blue pens, 7 black pens, and 24 green pens. How many pens did Kara count?
______ pens
Answer:

Explanation:
Add the number of pens kara counts.Add the tens and ones.There are 7 tens and 18 ones.So, the number of pens kara counted is 7 tens and 18 ones ie 8 tens and 8 ones.Therefore the sum of 32,25,7 and 24 is 88.
8 tens and 8 ones.

Question 5.
Kai had 46 blocks. He gave 39 blocks to his sister. How many blocks does Kai have left?
46 – 39 = ______ blocks
Answer:

Explanation:
In the above picture 39 is removed from 46.So, the difference of 46 and 39 is 7.
7 ones.

Question 6.
A shop has 55 posters for sale. 34 posters show sports. The rest of the posters show animals. How many posters show animals?
_______ posters
Answer:

Explanation:
In the above picture 34 is removed from 55.So, the difference of 55 and 34 is 21.
2 tens 1 ones.

Lesson 6.2 Break Apart 3-Digit Addends

Essential Question How do you break apart addends to add hundreds, tens, and then ones?

Listen and Draw

Write the number. Draw a quick picture for the number. Then write the number in different ways.
_______
______ hundreds ______ tens _____ ones
_____ + _____ + ______
Answer:
258
2 hundreds 5 tens 8 ones
200+50+8

_______
______ hundreds ______ tens _____ ones
_____ + _____ + ______
Answer:
325
3 hundreds 2 tens 5 ones
300+20+8

MATHEMATICAL PRACTICES
Make Connections
What number can be written as 400 + 20 + 9?
Answer:
400+20+9
=4 hundreds 2 tens and 9 ones
400+20+9=429

Model and Draw

Break apart the addends into hundreds, tens, and ones. Add the hundreds, the tens, and the ones. Then find the total sum.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 1
Answer:

Explanation:
Add 538 and 216.Add the hundreds, tens and ones from the above picture.There are 7 hundreds,4 tens and 14 ones.So, the sum of 538 and 216 is 754.
7 hundreds 5 tens 4 ones.

Share and Show

Break apart the addends to find the sum.
Question 1.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 2
Answer:

Explanation:
Add 321 and 457.Add the hundreds, tens and ones from the above picture.There are 7 hundreds,7 tens and 8 ones.So, the sum of 321 and 457 is 778
7 hundreds 7 tens 8 ones.

Question 2.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 3
Answer:

Explanation:
Add 744 and 162.Add the hundreds, tens and ones from the above picture.There are 8 hundreds,1 tens and 6 ones.So, the sum of 744 and 162 is 906.
9 hundreds 0 tens 6 ones.

Question 3.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 4
Answer:

Explanation:
Add 254 and 536.Add the hundreds, tens and ones from the above picture.There are 7 hundreds,8 tens and 10 ones.So, the sum of 254 and 536 is 790.
7 hundreds 9 tens 0 ones.

On Your Own

Break apart the addends to find the sum.
Question 4.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 5
Answer:

Explanation:
Add 538 and 216.Add the hundreds, tens and ones from the above picture.There are 7 hundreds,4 tens and 14 ones.So, the sum of 538 and 216 is 754.
7 hundreds 5 tens 4 ones.

Question 5

Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 6
Answer:

Explanation:
Add 425 and 232.Add the hundreds, tens and ones from the above picture.There are 5 hundreds,5 tens and 7 ones.So, the sum of 538 and 216 is 557.
5 hundreds 5 tens 7 ones.

Question 6.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 7
Answer:

Explanation:
Add 849 and 123.Add the hundreds, tens and ones from the above picture.There are 9 hundreds,6 tens and 12 ones.So, the sum of 538 and 216 is 972.
9 hundreds 7 tens 2 ones.

Question 7.
THINK SMARTER+
Mr. Jones has many sheets of paper. He has 158 sheets of blue paper, 100 sheets of red paper, and 231 sheets of green paper. How many sheets of paper does he have?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 8
______ sheets of paper
Answer:

Explanation:
Add 158,100 and 231.Add the hundreds, tens and ones from the above picture.There are 4 hundreds,8 tens and 9 ones.So, the sum of 158,100 and 231 is 489.
4 hundreds 8 tens 9 ones.

Problem Solving • Applications

Question 8.
GO DEEPER
Wesley added in a different way.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 9
Answer:

Explanation:
As in the above example add hundreds,tens and ones seperately and the sum of hundreds,tens and ones is 786.
7 hundreds 8 tens 6 ones

Question 9.
THINK SMARTER
There are 376 children at one school. There are 316 children at another school. How many children are at the two schools?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 10
Select one number from each column to solve the problem.
Answer:

Explanation:
Add 376 and 316.Add the hundreds, tens and ones from the above picture.There are 6 hundreds,8 tens and 12 ones.So, the sum of 376 and 316 is 692.
6 hundreds 9 tens 2 ones.

TAKE HOME ACTIVITY • Write 347 + 215. Have your child break apart the numbers and then find the sum.

Break Apart 3-Digit Addends Homework & Practice 6.2

Break apart the addends to find the sum.
Question 1.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 11
Answer:

Question 2.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 12
Answer:

Problem Solving
Solve. Write or draw to explain.
Question 3.
There are 126 crayons in a bucket. A teacher puts 144 more crayons in the bucket. How many crayons are in the bucket now?
______ crayons
Answer:

Explanation:
There are 126 crayons in a bucket and the teacher adds 144 more to the bucket.To find the totqal number of crayons in the bucket, Add 126 and 144.Add the hundreds, tens and ones from the above picture.There are 2 hundreds,7 tens and 0 ones.So, the sum of 126 and 144 is 270.Therefore there are total 260 crayons in the bucket.
2 hundreds 6 tens 0 ones.

Question 4.
WRITE
Draw quick pictures and write to explain how to break apart addends to find the sum of 324 + 231.
Answer:

Explanation:
Add 324 and 231.Add the hundreds, tens and ones from the above picture.There are 5 hundreds,5 tens and 5 ones.So, the sum of 324 and 231 is 555.
5 hundreds 5 tens 5 ones.

Lesson Check
Question 1.
What is the sum?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 13
Answer:

Explanation:
Add 218 and 145.Add the hundreds, tens and ones from the above picture.There are 3 hundreds,5 tens and 13 ones.So, the sum of 218 and 145 is 363.
3 hundreds 6 tens 3 ones.

Question 2.
What is the sum?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 14
Answer:

Explanation:
Add 664 and 223.Add the hundreds, tens and ones from the above picture.There are 8 hundreds,8 tens and 7 ones.So, the sum of 664 and 223 is 887.
8 hundreds 8 tens 7 ones.

Spiral Review
Question 3.
Ang found 19 berries and Barry found 21 berries. How many berries did they find altogether?
19 + 21 = ______ berries
Answer:

Explanation:
Ang found 19 berries and Barry found 21 berries.Add 19 and 21.There are 3 tens and 10 ones in the above picture.So, the sum of 19 and 21 is 40.
4 tens and 0 ones.

Question:
Write a subtraction fact related to 9 + 6 = ______
Answer:
20-5=15

Explanation:
In the above question the sum of 9 and 6 is 15.So, the subtraction fact for 15 is 20-5=15.

Question 5.
There are 25 goldfish and 33 betta fish. How many fish are there?
25 + 33 = _____ fish
Answer:

Explanation:
There are 25 goldfish and 33 betta fish.Add 25 and 33.Add the tens and ones from the above picture.There are 5 tens and 8 ones.So the sum of

Question 6.
Subtract 16 from 41. What is the difference?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.2 15
Answer:

Lesson 6.3 3-Digit Addition: Regroup Ones

Essential Question When do you regroup ones in addition?

Listen and Draw

Use Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.3 1 to model the problem. Draw quick pictures to show what you did.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 2

MATHEMATICAL PRACTICES
Describe how you modeled the problem.
Answer:

Explanation:
To find the sum of 213 and 356.There are 5 hundreds,6 tens and 9 ones in the above picture.So. the sum of 213 and 356 is 569.5 hundreds 6 tens 9 ones.

Model and Draw

Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 3

Share and Show

Write the sum.
Question 1.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 4
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 328 and 134 is 462.

Question 2.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 5
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately without regrouping.The sum of 445 and 23 is 468.

On Your Own

Write the sum.
Question 3.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 6
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately without regrouping.The sum of 526 and 103 is 629.

Question 4.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 7
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 348 and 19 is 367.

Question 5.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 8
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 628 and 347 is 975.

Question 6.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 9
Answer:

Question 7.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 10
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 562 and 329 is 891.

Question 8.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 11
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 147 and 125 is 272.

Question 9.
THINK SMARTER
On Thursday, there were 326 visitors at the zoo. There were 200 more visitors at the zoo on Friday than on Thursday. How many visitors were at the zoo on both days?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 12
______ visitors
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately without regrouping.The sum of 326 and 200 is 526.

Problem Solving • Applications

Solve. Write or draw to explain.
Question 10.
MATHEMATICAL PRACTICE Model with Mathematics
The gift shop is 140 steps away from the zoo entrance. The train stop is 235 steps away from the gift shop. How many total steps is this?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 13
______ steps
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately without regrouping.The sum of 140 and 235is 375.

Question 11.
THINK SMARTER
Katina’s class used 249 noodles to decorate their bulletin board. Gunter’s class used 318 noodles. How many noodles did the two classes use?
________ noodles
Did you have to regroup to solve? Explain.
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 249 and 318 is 567.

TAKE HOME ACTIVITY • Ask your child to explain why he or she regrouped in only some of the problems in this lesson.

3-Digit Addition: Regroup Ones Homework & Practice 6.3

Write the sum.
Question 1.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 14
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 148 and 234 is 382.

Question 2.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 15
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 321 and 318 is 639.

Question 3.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 16
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 414 and 179 is 593.

Question 4.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 17
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 602 and 258 is 860.

Problem Solving
Solve. Write or draw to explain.
Question 5.
In the garden, there are 258 yellow daisies and 135 white daisies. How many daisies are in the garden altogether?
______ daisies
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 258 and 135 is 393.

Question 6.
WRITE
Find the sum of 136 + 212. Explain why you did or did not regroup.
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately without regrouping.The sum of 136 and 212 is 348.

Leson Check
Question 1.
What is the sum?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 18
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 435 and 146 is 581.

Question 2.
What is the sum?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 19
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 436 and 306 is 742.

Spiral Review
Question 3.
What is the difference?
9 – 4 = _______
Answer:

Explanation:
In the above picture there are 9 ones.Subtract 4 ones from ir.There are 5 ones remained after subracting.Therefore the difference of 9 and 4 is 5.

Question 4.
What is the sum?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.3 20
Answer:

Explanation:
There are 13 tens and 11 ones in the above picture.Regroup 11 ones as 1 tens 1 ones.Add the tens and ones.Therefore there are 14 tens and 1 ones.Regroup 14 tens as 1 hundreds 4 tens.So,the sum of 82 and 59 is 1 hundreds 4 tens 1 ones.

Question 5.
What is the sum?
26 + 7 = ____
Answer:

Explanation:
There are 2 tens and 13 ones in the above picture.regroup 13 ones as 1 tens 3 ones.Add the tens and ones.Therefore the sum of 26 and 7 is 33

Question 6.
Add 243 and 132. How many hundreds, tens, and ones are there in all?
______ hundreds _____ tens _____ ones
Answer:

Explanation:
In the above picture the ones,tens and hundreds are added seperately by regrouping the ones.The sum of 243 and 132 is 375.

Lesson 6.4 3-Digit Addition: Regroup Tens

Essential Question When do you regroup tens in addition?

Listen and Draw

Use Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 1 to model the problem. Draw quick pictures to show what you did.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 2

Answer:

MATHEMATICAL PRACTICES
Explain how your quick pictures show what happened in the problem.
Answer:

Model and Draw

Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 3
Answer:

Share and Show

Write the sum.
Question 1.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 4
Answer:

Question 2.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 5
Answer:

Question 3.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 6
Answer:

On Your Own

Write the sum.
Question 4.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 7
Answer:

Question 5.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 8
Answer:

Question 6.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 9
Answer:

Question 7.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 10
Answer:

Question 8.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 11
Answer:

Question 9.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 12
Answer:

Question 10.
GO DEEPER
In a bowling game, Jack scored 116 points and 124 points. Hal scored 128 points and 134 points. Who scored more points? How many more points were scored?
_____ ______ more points
Answer:

MATHEMATICAL PRACTICE Attend to Precision
Rewrite the numbers. Then add.
Question 11.
760 + 178
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 13
Answer:

Question 12.
216 + 346
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 14
Answer:

Question 13.
423 + 285
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 15
Answer:

Problem Solving • Applications
Question 14.
THINK SMARTER
These lists show the pieces of fruit sold. How many pieces of fruit did Mr. Olson sell?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 16
_______ pieces of fruit
Answer:

Question 15.
GO DEEPER
Who sold more pieces of fruit?
_______________
How many more?
_______ more pieces of fruit
Answer:

Question 16.
THINK SMARTER
At the city park theater, 152 people watched the morning play. Another 167 watched the afternoon play.
How many people watched the two plays? ______ people
Fill in the bubble next to each true sentence about how to solve the problem.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 17
Answer:

TAKE HOME ACTIVITY • Have your child choose a new combination of two fruits on this page and find the total number of pieces of the two types of fruit.

3-Digit Addition: Regroup Tens Homework & Practice 6.4

Write the sum.
Question 1.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 18
Answer:

Question 2.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 19
Answer:

Question 3.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 20
Answer:

Question 4.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 21
Answer:

Question 5.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 22
Answer:

Question 6.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 23
Answer:

Problem Solving
Solve. Write or draw to explain.
Question 7.
There are 142 blue toy cars and 293 red toy cars at the toy store. How many toy cars are there?
_______ toy cars
Answer:

Question 8.
WRITE
Find the sum of 362 + 265. Explain why you did or did not regroup.
Answer:

Lesson Check
Question 1.
What is the sum?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 24
Answer:

Question 2.
Annika has 144 pennies and Yahola has 284 pennies. How many do they have altogether?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 25
Answer:

Spiral Review
Question 3.
What is the sum?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 26
Answer:

Question 4.
What is the sum?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 27
Answer:

Question 5.
Francis had 8 toy cars, then his brother gave him 9 more. How many toy cars does Francis have now?
8 + 9 = ______ cars
Answer:

Question 6.
What is the difference?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.4 28
Answer:

Lesson 6.5 Addition: Regroup Ones and Tens

Essential Question How do you know when to regroup in addition?

Listen and Draw

Use mental math. Write the sum for each problem.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 1
10 + 30 + 40 = _____
100 + 400 + 200 = _____
10 + 50 + 40 = _____
600 + 300 = _____
Answer:

Explanation:
Add the tens digits  and hundreds digits in the above sums.

Explanation:
Add the tens digits and the hundreds digits in the above sums.

MATHEMATICAL PRACTICES
Analyze Were some problems easier to solve than other problems? Explain.
Answer:

Share and Show

Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 2
Write the sum.
Question 1.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 3
Answer:

Explanation:
4 ones+ 9 ones=13 ones
1 ten + 8 tens +2 tens=11 tens
1 hundred + 1 hundred + 3 hundreds=5 hundreds.

Question 2.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 4
Answer:

Explanation:
6 ones+ 8 ones=14 ones
1 ten + 4 tens +7 tens=12 tens
1 hundred + 5 hundred + 2 hundreds=8 hundreds.

Question 3.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 5
Answer:

Explanation:
7 ones+ 3 ones=10 ones
1 ten + 2 tens +5 tens=11 tens
3 hundreds + 3 hundreds=6 hundreds.

Question 4.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 6
Answer:

Explanation:
4 ones+ 2 ones=6 ones
3 tens +5 tens=8 tens
2 hundred + 1 hundreds=3 hundreds.

Question 5.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 7
Answer:

Explanation:
5 ones+ 2 ones=7 ones
7 tens +7 tens=14 tens
1 hundred + 3 hundreds + 2 hundreds=6 hundreds.

Question 6.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 8
Answer:

Explanation:
9 ones+ 3 ones=12 ones
1 ten + 8 tens +2 tens=11 tens
1 hundred + 1 hundred + 6 hundreds=8 hundreds.

On Your Own

Write the sum.
Question 7.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 9
Answer:

Explanation:
4 ones+ 1 one=5 ones
7 tens +8 tens=15 tens
1 hundred + 5 hundreds + 2 hundreds=8 hundreds.

Question 8.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 10
Answer:

Explanation:
6 ones+ 3 ones=9 ones
1 ten + 8 tens =9 tens
4 hundreds + 4 hundreds=8 hundreds.

Question 9.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 11
Answer:

Explanation:
6 ones+ 7 ones=13 ones
1 ten + 4 tens +9 tens=14 tens
1 hundred + 3 hundreds + 5 hundreds=9 hundreds.

Question 10.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 12
Answer:

Explanation:
5 ones+ 3 ones=8 ones
6 tens +8 tens=14 tens
1 hundred + 3 hundreds + 2 hundreds=6 hundreds.

Question 11.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 13
Answer:

Explanation:
7 ones+ 9 ones=16 ones
1 ten + 4 tens +0 tens=5 tens
6 hundred + 1 hundreds=5 hundreds.

Question 12.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 14
Answer:

Explanation:
6 ones+ 6 ones=12 ones
1 ten + 4 tens +5 tens=10 tens
1 hundred + 5 hundreds + 3 hundreds=9 hundreds.

Question 13.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 15
Answer:

Explanation:
8 ones+ 1 ones=9 ones
4 tens +3 tens=7 tens
3 hundreds + 6 hundreds=9 hundreds.

Question 14.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 16
Answer:

Explanation:
5 ones+ 9 ones=14 ones
1 ten + 5 tens +3 tens=9 tens
4 hundreds + 1 hundred=5 hundreds.

Question 15.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 17
Answer:

Explanation:
3 ones+ 5 ones=8 ones
6 tens +4 tens=10 tens
1 hundred + 5 hundreds + 2 hundreds=8 hundreds.

Question 16.
THINK SMARTER
Miko wrote these problems. What are the missing digits?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 18
Answer:

TAKE HOME ACTIVITY • Have your child explain how to solve 236 + 484.
Answer:

Explanation:
6 ones+ 4 ones=10 ones
1 ten + 3 tens +8 tens=12 tens
1 hundred + 2 hundreds + 4 hundreds=7 hundreds.

Addition: Regroup Ones and Tens Homework & Practice 6.5

Write the sum.
Question 1.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 19
Answer:

Explanation:
7 ones+ 5 ones=12 ones
1 ten + 4 tens +3 tens=8 tens
5 hundreds + 4 hundreds=9 hundreds.

Question 2.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 20
Answer:

Explanation:
7 ones+ 4 ones=11 ones
1 ten + 6 tens +8 tens=15 tens
1 hundred + 3 hundreds + 2 hundreds=6 hundreds.

Question 3.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 21
Answer:

Explanation:
5 ones+ 6 ones=11 ones
1 ten + 8 tens +5 tens=14 tens
1 hundred + 4 hundred + 4 hundreds=5 hundreds.

Question 4.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 22
Answer:

Explanation:
7 ones+ 6 ones=13 ones
1 ten + 8 tens +0 tens=9 tens
1 hundred + 3 hundreds=4 hundreds.

Question 5.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 23
Answer:

Explanation:
7 ones+ 8 ones=15 ones
1 ten + 4 tens +2 tens=7 tens
6 hundreds + 1 hundred=7 hundreds.

Question 6.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 24
Answer:

Explanation:
4 ones+ 9 ones=13 ones
1 ten + 8 tens +2 tens=11 tens
1 hundred + 1 hundred + 3 hundreds=5 hundreds.

Problem Solving
Solve. Write or draw to explain.
Question 7.
Saul and Luisa each scored 167 points on a computer game. How many points did they score together?
_______ points
Answer:

Explanation:
Saul and luisa has 167 points each on a computer game.Add points of both saul and luisa.There are 3 hundreds 2 tens and 14 ones.So, the sum of 167 and 167 is 3 hundred 3 tens and 4 ones.
7 ones+ 7 ones=14 ones
1 ten + 6 tens +6 tens=13 tens
1 hundred + 1 hundred + 1 hundred=3 hundreds.

Question 8.
WRITE
Write the addition problem for 275 plus 249 and find the sum. Then draw quick pictures to check your work.
Answer:

Explanation:
5 ones+ 9 ones=14 ones
1 ten + 7 tens +4 tens=12 tens
1 hundred + 2 hundreds + 2 hundreds=5 hundreds.

Lesson Check
Question 1.
What is the sum?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 25
Answer:

Explanation:
8 ones+ 2 ones=10 ones
1 ten + 4 tens +7 tens=12 tens
1 hundred + 3 hundreds + 2 hundreds=6 hundreds.

Question 2.
What is the sum?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 26
Answer:

Explanation:
3 ones+ 7 ones=10 ones
1 ten + 2 tens +1 tens=11 tens
1 hundred + 2 hundreds=3 hundreds.

Spiral Review
Question 3.
Which addition fact has the same sum as 9 + 4.
10 + _____
Answer:
9+4=13
10+3=13

Explanation:
The sumof 9 and 4 is 13.So, if we add 3 to 10 we get the same sum 13.Therefore the addition fact that has the same sum as 9+4 is 10+3.

Question 4.
What is the sum?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 27
Answer:

Explanation:
2 ones+ 5 ones + 6 ones=13 ones
1 ten + 3 tens +1 tens +4 tens=9 tens

Question 5.
Add 29 and 35. What is the sum?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 28
Answer:

 

Question 6.
Tom had 25 pretzels. He gave away 12 pretzels. How many pretzels does Tom have left?
25 – 12 = ______ pretzels
Answer:

Explanation:
There are 25 blocks in the above picture.Subtract 1 tens and 2 ones from the above picture.Therefore 13 blocks are left.
So, the difference of 25 and 12 is 13.

3-Digit Addition and Subtraction Mid-Chapter Checkpoint

Concepts and Skills

Break apart the addends to find the sum.
Question 1.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 29
Answer:

Explanation:
Add 567 and 324.Add the hundreds, tens and ones from the above picture.There are 8 hundreds,8 tens and 11 ones.So, the sum of 567 and 324 is 363.
8 hundreds 9 tens 1 ones

write the sum.

Question 2.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 30
Answer:

Explanation:
8 ones+ 6 ones=14 ones
1 ten + 4 tens +4 tens=9 tens
2 hundreds + 3 hundreds=5 hundreds.

Question 3.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 31
Answer:

Explanation:
0 ones+ 4 ones=4 ones
1 ten +6 tens=11 tens
6 hundreds + 2 hundreds=8 hundreds.

Question 4.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 32
Answer:

Explanation:
1 ones+ 7 ones=8 ones
9 tens +3 tens=12 tens
1 hundred + 3 hundreds + 5 hundreds=9 hundreds.

Question 5.
THINK SMARTER
There are 148 small sand dollars and 119 large sand dollars on the beach. How many sand dollars are on the beach?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.5 33
______ sand dollars
Answer:

Explanation:
8 ones+ 9 ones=17 ones
1 ten + 4 tens +1 tens=6 tens
1 hundred + 1 hundred=2 hundreds.

Lesson 6.6 Problem Solving • 3-Digit Subtraction

Essential Question How can making a model help when solving subtraction problems?

There were 436 people at the art show. 219 people went home. How many people stayed at the art show?

Unlock the Problem
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 1

Show how to solve the problem.
Make a model. Then draw a quick picture of your model.
______ people

HOME CONNECTION • Your child used a model and a quick picture to represent and solve a subtraction problem.

Try Another Problem
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 3
Make a model to solve. Then draw a quick picture of your model.
Question 1.
There are 532 pieces of art at the show. 319 pieces of art are paintings. How many pieces of art are not paintings?
______ pieces of art
Answer:

Question 2.
245 children go to the face-painting event. 114 of the children are boys. How many of the children are girls?
_______ girls
Answer:

MATHEMATICAL PRACTICES
Explain how you solved the first problem on this page.
Answer:

Share and Show

Make a model to solve. Then draw a quick picture of your model.
Question 3.
There were 237 books on the table. Miss Jackson took 126 books off the table. How many books were still on the table?
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 4
______ books
Answer:

Question 4.
There were 232 postcards on the table. The children used 118 postcards. How many postcards were not used?
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 5
_______ postcards
Answer:

Question 5.
THINK SMARTER
164 children and 31 adults saw the movie in the morning. 125 children saw the movie in the afternoon. How many fewer children saw the movie in the afternoon than in the morning?
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 6
______ fewer children
Answer:

On Your Own

MATHEMATICAL PRACTICE Make Sense of Problems
Question 6.
There were some grapes in a bowl. Clancy’s friends ate 24 of the grapes. Then there were 175 grapes in the bowl. How many grapes were in the bowl before?
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 7
______ grapes
Answer:

Question 7.
THINK SMARTER
At Gregory’s school, there are 547 boys and girls. There are 246 boys. How many girls are there?
Draw a quick picture to solve.
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 8
Answer:

TAKE HOME ACTIVITY • Ask your child to choose one of the problems in this lesson and solve it in a different way.

Problem Solving • 3-Digit Subtraction Homework & Practice 6.6

Make a model to solve. Then draw a quick picture of your model.
Question 1.
On Saturday, 770 people went to the snack shop. On Sunday, 628 people went. How many more people went to the snack shop on Saturday than on Sunday?
______ more people
Answer:

Question 2.
There were 395 lemon ice cups at the snack shop. People bought 177 lemon ice cups. How many lemon ice cups are still at the snack shop?
______ cups
Answer:

Question 3.
There were 576 bottles of water at the snack shop. People bought 469 bottles of water. How many bottles of water are at the snack shop now?
_______ bottles
Answer:

Question 4.
WRITE
Draw quick pictures to show how to subtract 314 and 546.
Answer:

Lesson Check
Question 1.
There are 278 math and science books. 128 of them are math books. How many science books are there?
______ books
Answer:

Question 2.
A book has 176 pages. Mr. Roberts has read 119 pages. How many pages does he have left to read?
_____ pages
Answer:

Spiral Review
Question 3.
What is the sum?
1 + 6 + 2 = _____
Answer:

Question 4.
What is the difference?
54 – 8 = _____
Answer:

Question 5.
What is the sum?
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 9
Answer:

Question 6.
What is the sum?
2nd Grade Go Math Answer Key Chapter 6 3-Digit Addition and Subtraction 6.6 10
Answer:

Lesson 6.7 3-Digit Subtraction: Regroup Tens

Essential Question When do you regroup tens in subtraction?

Listen and Draw

Use Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 1 to model the problem.
Draw a quick picture to show what you did.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 2

MATHEMATICAL PRACTICES
Describe what to do when there are not enough ones to subtract from.
Answer:

Share and Show

Solve. Write the difference.
Question 1.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 3
Answer:

Question 2.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 4
Answer:

On Your Own

Solve. Write the difference.
Question 3.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 5
Answer:

Question 4.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 6
Answer:

Question 5.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 7
Answer:

Question 6.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 8
Answer:

Question 7.
GO DEEPER
A bookstore has 148 books about people and 136 books about places. Some books were sold. Now there are 137 books left. How many books were sold?
_______ books
Answer:

Question 8.
THINK SMARTER
There were 287 music books and 134 science books in the store. After some books were sold, there are 159 books left. How many books were sold?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 9
Answer:

Problem Solving • Applications

MATHEMATICAL PRACTICE Make Sense of Problems
Solve. Write or draw to explain.
Question 9.
There are 235 whistles and 42 bells in the store. Ryan counts 128 whistles on the shelf. How many whistles are not on the shelf?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 10
______ whistles
Answer:

Question 10.
THINK SMARTER
Dr. Jackson had 326 stamps.
He sells 107 stamps. How many stamps does he have now? ______ stamps
Would you do these things to solve the problem?
Choose Yes or No.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 11
Answer:

TAKE HOME ACTIVITY • Ask your child to explain why he or she regrouped in only some of the problems in this lesson.

3-Digit Subtraction: Regroup Tens Homework & Practice 6.7

Solve. Write the difference.
Question 1.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 12
Answer:

Question 2.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 13
Answer:

Question 3.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 14
Answer:

Question 4.
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 15
Answer:

Problem Solving
Solve. Write or draw to explain.
Question 5.
There were 985 pencils. Some pencils were sold. Then there were 559 pencils left. How many pencils were sold?
______ pencils
Answer:

Question 6.
WRITE
Choose one exercise from above. Draw quick pictures to check your work.
Answer:

Lesson Check
Question 1.
What is the difference?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 16
Answer:

Question 2.
What is the difference?
Go Math 2nd Grade Answer Key Chapter 6 3-Digit Addition and Subtraction 6.7 17
Answer:

Spiral Review
Question 3.
What is the difference?
45 – 7 = _____
Answer:

Question 4.
Leroy has 11 cubes. Jane has 15 cubes. How many cubes do they have altogether?
______ cubes
Answer:

Question 5.
Mina puts 5 flowers in each vase. How many flowers will she put in 3 vases?
______ flowers
Answer:

Question 6.
Mr. Hill had 428 pencils. He gave away 150 pencils. How many pencils did he keep?
______ pencils
Answer:

Lesson 6.8 3-Digit Subtraction: Regroup Hundreds

Essential Question When do you regroup hundreds in subtraction?

Listen and Draw

Draw quick pictures to show the problem
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 1

MATHEMATICAL PRACTICES
Describe what to do when there are not enough tens to subtract from.
Answer:

Share and Show

Solve. Write the difference.
Question 1.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 2
Answer:

Question 2.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 3
Answer:

On Your Own

Solve. Write the difference.
Question 3.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 4
Answer:

Question 4.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 5
Answer:

Question 5.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 6
Answer:

Question 6.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 7
Answer:

Question 7.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 8
Answer:

Question 8.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 9
Answer:

MATHEMATICAL PRACTICE Make Arguments
Question 9.
Choose one exercise above. Describe the subtraction that you did. Be sure to tell about the values of the digits in the numbers.
______________________
_______________________
Answer:

Problem Solving • Applications

Question 10.
THINK SMARTER
Sam made two towers. He used 139 blocks for the first tower. He used 276 blocks in all. For which tower did he use more blocks? ______
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 10
Explain how you solved the problem.
Answer:

Question 11.
THINK SMARTER
This is how many points each class scored in a math game.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 11
How many more points did Mr. Chang’s class score than Mr. Pagano’s class? Draw a picture and explain how you found your answer.
_______ more points
Answer:

TAKE HOME ACTIVITY • Have your child explain how to find the difference for 745 − 341.

3-Digit Subtraction: Regroup Hundreds Homework & Practice 6.8

Solve. Write the difference.
Question 1.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 12
Answer:

Question 2.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 13
Answer:

Question 3.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 14
Answer:

Question 4.
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 15
Answer:

Problem Solving
Solve. Write or draw to explain.
Question 5.
There were 537 people in the parade. 254 of these people were playing an instrument. How many people were not playing an instrument?
_______ people
Answer:

Question 6.
WRITE
Write the subtraction problem for 838 – 462 and find the difference. Then draw quick pictures to check your difference.
Answer:

Lesson Check
Question 1.
What is the difference?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 16
Answer:

Question 2.
What is the difference?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 17
Answer:

Spiral Review
Question 3.
What is the difference?
52 – 15 = ______
Answer:

Question 4.
Wallace has 8 crayons and Alma has 7. How many do the have together?
8 + 7 = _____ crayons
Answer:

Question 5.
What is the sum?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 18
Answer:

Question 6.
Mrs. Lin’s class read 392 books in February. Mr. Hook’s class read 173 books. How many more books did Mrs. Lin’s class read?
Go Math Answer Key Grade 2 Chapter 6 3-Digit Addition and Subtraction 6.8 19
Answer:

Lesson 6.9 Subtraction: Regroup Hundreds and Tens

Essential Question How do you know when to regroup in subtraction?

Listen and Draw

Use mental math. Write the difference for each problem.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 1
90 − 40 = _____
700 − 500 = _____
70 − 60 = _____
800 − 300 = _____
Answer:

Explanation:
Subtract the tens amd hundreds from the above sums to find the difference.


Explanation:
Subtract the tens and hundreds from the above sums to find the difference.

MATHEMATICAL PRACTICES
Were some problems easier to solve than other problems? Explain.
Answer:
Yes some problems wre easy to solve than the other problems as theur was no need of any regrouping for some problems.

Share and Show

Solve. Write the difference.
Question 1.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 2
Answer:

Explanation:
Regroup 2 tens 1 ones as 1 tens 11 ones.Subtract the ones.
Regroup 4 hundreds 1 tens as 3 hundreds 11 tens.Subtract the tens
Subtract the hundreds.

Question 2.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 3
Answer:

Explanation:
Subtract the ones.
Regroup 1 hundreds 7 tens as 1 hundreds 17 tens.Subtract the tens
Subtract the hundreds.

Question 3.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 4
Answer:

Explanation:
Regroup 4 tens 6 ones as 3 tens 16 ones.Subtract the ones.
Regroup 5 hundreds 3 tens as 4 hundreds 13 tens.Subtract the tens
Subtract the hundreds.

Question 4.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 5
Answer:

Explanation:
Subtract the hundreds,tens and ones as there is no need of regrouping.

Question 5.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 6
Answer:

Explanation:
Regroup 4 tens 7 ones as 3 tens 17 ones.Subtract the ones.
Regroup 7 hundreds 3 tens as 6 hundreds 13 tens.Subtract the tens
Subtract the hundreds.

Question 6.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 7
Answer:

Explanation:
Subtract the ones.
Regroup 9 hundreds 3 tens as 8 hundreds 13 tens.Subtract the tens
Subtract the hundreds.

On Your Own

Solve. Write the difference.
Question 7.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 8
Answer:

Explanation:
Regroup 4 tens 2 ones as 3 tens 12 ones.Subtract the ones.
Subtract the tens
Subtract the hundreds.

Question 8.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 9
Answer:

Explanation:
Subtract the ones.
Regroup 4 hundreds 6 tens as 3 hundreds 16 tens.Subtract the tens
Subtract the hundreds.

Question 9.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 10
Answer:

Explanation:
Regroup 5 tens 5 ones as 4 tens 15 ones.Subtract the ones.
Regroup 4 hundreds 1 tens as 3 hundreds 1 tens.Subtract the tens
Subtract the hundreds.

Question 10.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 11
Answer:

Explanation:
Subtract the ones.
Regroup 6 hundreds 5 tens as 5 hundreds 15 tens.Subtract the tens
Subtract the hundreds.

Question 11.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 12
Answer:

Explanation:
Regroup 2 tens 1 ones as 1 tens 11 ones.Subtract the ones.
Regroup 5 hundreds 1 tens as 4 hundreds 11 tens.Subtract the tens
Subtract the hundreds.

Question 12.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 13
Answer:

Explanation:
Regroup 5 tens 8 ones as 4 tens 18 ones.Subtract the ones.
Subtract the tens
Subtract the hundreds.

Question 13.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 14
Answer:

Explanation:
Regroup 4 tens 2 ones as 3 tens 12 ones.Subtract the ones.
Regroup 5 hundreds 3 tens as 4 hundreds 13 tens.Subtract the tens
Subtract the hundreds.

Question 14.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 15
Answer:

Explanation:
Subtract the ones.
Regroup 8 hundreds 2 tens as 7 hundreds 12 tens.Subtract the tens
Subtract the hundreds.

Question 15.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 16
Answer:

Explanation:
Regroup 4 tens 7 ones as 3 tens 17 ones.Subtract the ones.
Regroup 9 hundreds 3 tens as 8 hundreds 13 tens.Subtract the tens
Subtract the hundreds.

Question 16.
THINK SMARTER
Alex wrote these problems. What are the missing digits?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 17
Answer:

Explanation:
The missing numbers in the first sum are 5 and 5 because only when the numbers are 5 tens and 5 ones if we regroup them they become 4 tens and 15 ones.
The missing numbers in the second sum are 8, 3 and 6 because only when the numbers are 8 hundreds and 3 tens if we regroup them they become 7 hundreds and 13 ones.And 6 ones because if we subtract only 6 ones from 7 ones we get the answer as 1 ones.

Problem Solving • Applications

Question 17.
GO DEEPER
This is how Walter found the difference for 617 − 350.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 18
Find the difference for 843 − 270 using Walter’s way.
Answer:

Explanation:
As shown in the above picture the difference between 270 and 300 is 30, 800 and 300 is 500 and 843 and 800 is 43.So, when we add 30,500 and 43 is sum wiil be 573.Therefore the difference between 543 and 270 is 573.

Question 18.
MATHEMATICAL PRACTICE Analyze
There are 471 children at Caleb’s school. 256 children ride buses to get to school.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 19
How many children do not ride buses to get to school?
_____ children
Answer:

Explanation:
Regroup 7 tens 1 ones as 6 tens 11 ones.Subtract the ones.
Subtract the tens
Subtract the hundreds.

Question 19.
THINK SMARTER
Mrs. Herrell had 427 pinecones. She gave 249 pinecones to her children.
How many pinecones does she still have?
_______ pinecones
Answer:

Explanation:
Regroup 2 tens 7 ones as 1 tens 17 ones.Subtract the ones.
Regroup 4 hundreds 1 tens as 3 hundreds 11 tens.Subtract the tens
Subtract the hundreds.

TAKE HOME ACTIVITY • Ask your child to find the difference when subtracting 182 from 477.

Explanation:
Subtract the ones.
Regroup 4 hundreds 7 tens as 3 hundreds 17 tens.Subtract the tens
Subtract the hundreds.

Subtraction: Regroup Hundreds and Tens Homework & Practice 6.9

Solve. Write the difference.
Question 1.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 20
Answer:

Explanation:
Regroup 1 tens 6 ones as 0 tens 16 ones.Subtract the ones.
Regroup 8 hundreds 0 tens as 7 hundreds 10 tens.Subtract the tens
Subtract the hundreds.

Question 2.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 21
Answer:

Explanation:
Regroup 0 tens 2 ones as 9 tens 12 ones.Subtract the ones.
Regroup 9 hundreds 9 tens as 8 hundreds 19 tens.Subtract the tens
Subtract the hundreds.

Question 3.
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 22
Answer:

Explanation:
Regroup 9 tens 6 ones as 8 tens 16 ones.Subtract the ones.
Subtract the tens
Subtract the hundreds.

Problem Solving
Solve.
Question 4.
Mia’s coloring book has 432 pages. She has already colored 178 pages. How many pages in the book are left to color?
______ pages
Answer:

Explanation:
Regroup 3 tens 2 ones as 2 tens 12 ones.Subtract the ones.
Regroup 4 hundreds 2 tens as 3 hundreds 12 tens.Subtract the tens
Subtract the hundreds.

Question 5.
WRITE
Draw quick pictures to show how to subtract 546 from 735.
Answer:

Explanation:
Regroup 3 tens 5 ones as 2 tens 15 ones.Subtract the ones.
Regroup 7 hundreds 2 tens as 6 hundreds 12 tens.Subtract the tens
Subtract the hundreds.

Lesson Check
Question 1.
What is the difference?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 23
Answer:

Explanation:
Subtract the ones.
Regroup 3 hundreds 4 tens as 2hundreds 14 tens.Subtract the tens
Subtract the hundreds.

Question 2.
What is the difference?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 24
Answer:

Explanation:
Regroup 3 tens 6 ones as 2 tens 16 ones.Subtract the ones.
Regroup 3 hundreds 2 tens as 2 hundreds 12 tens.Subtract the tens
Subtract the hundreds.

Spiral Review
Question 3.
What is the sum?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 25
Answer:

Explanation:
6 ones + 3 ones=19 ones
1 tens +4 tens + 3 tens=7 tens
2 hundreds + 5 hundreds=7 hundreds.
7 hundreds 7 tens 9 ones.

Question 4.
What is the difference?
Go Math Grade 2 Answer Key Chapter 6 3-Digit Addition and Subtraction 6.9 26
Answer:

Explanation:
Regroup 3 tens 8 ones as 2 tens 18 ones.Subtract the ones.
Subtract the tens

Question 5.
What is the difference?
17 – 9 = _____
Answer:

Question 6.
Lisa had 15 daisies. She gave away 7 daisies. Then she found 3 more daisies. How many daisies does Lisa have now?
15 – 7 + 3 = ______
Answer:

Lesson 6.10 Regrouping with Zeros

Essential Question How do you regroup when there are zeros in the number you start with?

Listen and Draw

Draw or write to show how you solved the problem.
Answer:

MATHEMATICAL PRACTICES
Describe another way that you could solve the problem.
Answer:

Share and Show

Solve. Write the difference.
Question 1.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 1
Answer:

Question 2.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 2
Answer:

Question 3.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 3
Answer:

On Your Own

Solve. Write the difference.
Question 4.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 4
Answer:

Question 5.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 5
Answer:

Question 6.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 6
Answer:

Question 7.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 7
Answer:

Question 8.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 8
Answer:

Question 9.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 9
Answer:

Question 10.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 10
Answer:

Question 11.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 11
Answer:

Question 12.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 12
Answer:

Question 13.
THINK SMARTER
Miguel has 125 more baseball cards than Chad. Miguel has 405 baseball cards. How many baseball cards does Chad have?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 13
_____ baseball cards
Answer:

Problem Solving • Applications

Question 14.
MATHEMATICAL PRACTICE
Analyze Claire has 250 pennies. Some are in a box and some are in her bank. There are more than 100 pennies in each place. How many pennies could be in each place?
_____ pennies in a box
_______ pennies in her bank
Explain how you solved the problem.
________________
_________________
Answer:

Question 15.
THINK SMARTER
There are 404 people at the baseball game. 273 people are fans of the blue team. The rest are fans of the red team. How many people are fans of the red team?
Does the sentence describe how to find the answer?
Choose Yes or No.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 14
There are ________ fans of the red team.
Answer:

TAKE HOME ACTIVITY • Ask your child to explain how he or she solved one of the problems in this lesson.

Regrouping with Zeros Homework & Practice 6.10

Solve. Write the difference.
Question 1.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 15
Answer:

Question 2.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 16
Answer:

Question 3.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 17
Answer:

Question 4.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 18
Answer:

Question 5.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 19
Answer:

Question 6.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 20
Answer:

Problem Solving
Solve.
Question 7.
There are 303 students. There are 147 girls. How many boys are there?
_______ boys
Answer:

Question 8.
WRITE
Write the subtraction problem 604 – 357. Describe how you will subtract to find the difference.
_______________
________________
Answer:

Lesson Check
Question 1.
What is the difference?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 21
Answer:

Question 2.
What is the difference?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 22
Answer:

Spiral Review
Question 3.
What is the sum?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 23
Answer:

Question 4.
There are 555 students at Roosevelt Elementary School and 282 students at Jefferson Elementary. How many students are at the two schools altogether?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 24
Answer:

Question 5.
What is the difference?
10 – 2 = _____
Answer:

Question 6.
Gabriel’s goal is to read 43 books this year. So far he has read 11 books. How many books does he have left to meet his goal?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts 6.10 25
Answer:

3-Digit Addition and Subtraction Review/Test

Question 1.
Mr. Kent’s art class used 234 craft sticks. Ms. Reed’s art class used 358 craft sticks. How many craft sticks did the two classes use?
______ craft sticks
Answer:

Question 2.
At the library, there are 668 books and magazines. There are 565 books at the library. How many magazines are there?
Circle the number that makes the sentence true.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 2
Answer:

Question 3.
There are 176 girls and 241 boys at school. How many children are at school?
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 3
Select one number from each column to solve the problem.
Answer:

Question 4.
THINK SMARTER+
Anna wants to add 246 and 132.
Help Anna solve this problem. Draw quick pictures. Write how many hundreds, tens, and ones in all. Write the number.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 4
_____ hundreds _____ tens _____ ones
_________
Answer:

Question 5.
Mrs. Preston had 513 leaves. She gave 274 leaves to her students. Draw to show how you found your answer.
How many leaves does she still have?
______ leaves
Answer:

Question 6.
A farmer has 112 pecan trees and 97 walnut trees. How many more pecan trees does the farmer have than walnut trees?
Fill in the bubble next to all the sentences that describe what you would do.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 6
Answer:

Question 7.
Amy has 408 beads. She gives 322 beads to her sister. How many beads does Amy have now?
Does the sentence describe how to find the answer?
Choose Yes or No
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 7
Amy has _____ beads.
Answer:

Question 8.
GO DEEPER
Raul used this method to find the sum 427 + 316.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 8.1
Use Raul’s method to find this sum.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 8
Describe how Raul solves addition problems.
_____________________
____________________
Answer:

Question 9.
ally scores more points in a game than Ty. Sally uses 900 – 500 to estimate how many more points.
Fill in the bubble next to all the problems she may have been estimating for.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 9
Answer:

Question 10.
Use the numbers on the tiles to solve the problem.
Go Math Grade 2 Chapter 6 Answer Key Pdf 3-Digit Addition and Subtraction Concepts rt 10
Describe how you solved the problem.
___________________________
__________________________
Answer:

Go Math Grade 1 Answer Key Chapter 1 Addition Concepts

Go Math Grade 1 Answer Key Chapter 1 Addition Concepts

Fun-learning activities are the best option to educate elementary school kids and make them understand basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 1 elementary school students can find these fun-learning exercises for all math concepts through the Go Math Answers Grade 1 Curriculum.

Go Math Grade 1 Chapter 1 Answer Key Addition Concepts

You may have diverse opportunities to develop math skills and problem-solving skills but practicing with Go Math 1st Grade Book Solutions will be the best of all. So, Utilize the given Go Math Textbook 1st Grade Answer Key for better and efficient learning. Grade 1 is designed by subject experts in a fun-learning way to encourage elementary kids. These Go Math 1st Grade Solutions are very easy to understand and educate the kids with all basic concepts.

Curious George

How many kittens can you add to the group to have 10 kittens? Explain.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 1

Answer:
The kittens we can add to the group to have 10 kittens = 8.

Explanation:
In the above-given question,
given that,
there are 2 kittens in the picture,
we can add 8 kittens to make 10 kittens.
2 + 8 = 10.
The kittens we can add to the group to have 10 kittens = 8.

Addition Concepts Show What You Know

Explore Numbers 1 to 4

Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 2 to show the number. Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 3

Question 1.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 4

Answer:
The number is 4.

Explanation:
In the above-given question,
given that,
the number is 4.
so we have to draw the 4 buttons.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1

Question 2.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 5

Answer:
The number is 3.

Explanation:
In the above-given question,
given that,
the number is 3.
so we have to draw the 3 buttons.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-2

Numbers 1 to 10
How many objects are in each group?

Question 3.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 6

Answer:
The number of chicks = 7.

Explanation:
In the above-given question,
given that,
there are 7 chicks,
so the number of chicks = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-3

Question 4.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 7

Answer:
The number of eggs= 5.

Explanation:
In the above-given question,
given that,
there are 5 eggs,
so the number of eggs = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-4

Question 5.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 8

Answer:
The number of flowers = 4.

Explanation:
In the above-given question,
given that,
there are 4 flowers,
so the number of flowers = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-5

Numbers 0 to 10
How many spots are on the ladybug?

Question 6.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 9

Answer:
The number of spots on the ladybug = 0.

Explanation:
In the above-given question,
given that,
there are no spots on the bug.
so the number of spots on the ladybug = 0.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-6

Question 7.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 10

Answer:
The number of spots on the ladybug = 6.

Explanation:
In the above-given question,
given that,
there are 6 spots on the bug.
so the number of spots on the ladybug = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-7

Question 8.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 11

Answer:
The number of spots on the ladybug = 10.

Explanation:
In the above-given question,
given that,
there are ten spots on the bug.
so the number of spots on the ladybug = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-8

Question 9.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 12

Answer:
The number of spots on the ladybug = 2.

Explanation:
In the above-given question,
given that,
there are 2 spots on the bug.
so the number of spots on the ladybug = 2.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-9

Addition Concepts Vocabulary Builder

Visualize It

Draw to show 1 more. Draw to show adding to.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 13

Answer:
The number of love shapes = 4.

Explanation:
In the above-given question,
given that,
there are 3 love shapes and also given that 1 more.
3 + 1 = 4.
so the number of love shapes = 4.

Answer:
The number of boxes = 4.

Explanation:
In the above-given question,
given that,
there are 3 boxes and also given that 1 more.
3 + 1 = 4.
so the number of love shapes = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-10

Understand Vocabulary

Complete the sentences with review words.

Question 1.
Sue wants to know how many counters are in two groups. She can _use__ Addition__to find out.

Answer:
She can use addition to find out.

Explanation:
In the above-given question,
given that,
Sue wants to know how many counters are in two groups.
She can use addition to find out.

Question 2.
Pete has 2 apples. May has 3 apples. May has _1 _ apple than Pete.

Answer:
May has 1 more apple than Pete.

Explanation:
In the above-given question,
given that,
Peter has 2 apples.
May has 3 apples.
2 + 1 = 3.
May has 1 more apple than Pete.

Addition Concepts Game: Addition Bingo

Materials
• 2 sets of Numeral Cards 0–4
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 14
Play with a partner.
1. Mix the cards in each set. Put both sets facedown.
2. Take a card from each set. Join Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 15 and Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 16 to add.
3. The other player checks your answer.
4. If you are correct, cover the answer with a Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 17
5. The other player takes a turn.
6. The first player to cover 3 spaces in a row wins.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 18

Answer:
The number is = 5.

Explanation:
In the above-given question,
given that,
player 1 red and player 2 blue.
player 1 = 2 and player 2 = 3
we have to add 2 + 3 = 5.
The number is 5.

Addition Concepts Vocabulary Game

Going Places with GOMATH! words

Going to the Zoo

Materials
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 19

How to Play
1. Each player puts a Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 20 on START.
2. Toss the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 21 to take a turn. Move your Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 22 that many spaces.
3. If you land on these spaces:
White Space Read the math word or symbol. Tell its meaning. If you are correct, jump ahead to the next space with the same word. If not, stay where you are.
Green Space Follow the directions. If there are no directions, stay where you are.
4. The first player to reach FINISH wins.

Game
HOW TO PLAY
Materials
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 22.1
1. Put your on START.
2. Toss the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 23 and move your Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 24 that many spaces.
3. If you land on one of these spaces:
Blue Space Explain the math word or use it in a sentence. If your answer is correct, jump ahead to the next space with that word.
Green Space Follow the directions in the space. If there are no directions,
don’t move.
4. The first player to reach FINISH wins.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 24.1

Answer:
The symbol is equal to.

Explanation:
In the above-given question,
given that,
Read the math word or symbol.
the symbol is equal to.
for example, if we take 2 and 2.
2 is equal to 2.

Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 24.2

Answer:
The word is a sum.

Explanation:
In the above-given question,
given that,
Read the math word or symbol.
the word is sum.
for example, if we take 2 and 2.
2 plus 2 = 4.

The Write Way

Reflect
Choose one idea. Draw and write about it.
• Tell what happens when you add a zero to another number.
• Make up an addition story problem. Use 3 and 4. Then ask a partner to solve it.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 24.3

Answer:
If we add a zero to another number the number is the same.
3 + 4 = 7.

Explanation:
In the above-given question,
given that,
Tell me what happens when you add a zero to another number.
if we add a zero to another number the number is the same.
for example, 2 + 0 = 2.
3 + 4 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-11

Lesson 1.1 Algebra • Use Pictures to Add To

Essential Question
How do pictures show adding to?

Listen and Draw

Draw to show adding to. Write how many there are.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 24.5
_5_ ladybugs

Answer:
The number of ladybugs = 5.

Explanation:
In the above-given question,
given that,
there are 5 ladybugs,
so the number of ladybugs = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-1

Math Talk
MATHEMATICAL PRACTICES

Model Explain how your drawing shows the problem.

Share and Show MATH BOARD

Write how many.

Question 1.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 24.6
3 fish and 1 more fish _4_ fish

Answer:
The number of fish = 4.

Explanation:
In the above-given question,
given that,
there are 3 fish,
1 more fish
3 + 1 = 4.
so the number of fish = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-2

Question 2.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 25
4 bees and 4 more bees __8_ bees

Answer:
The number of bees =  8.

Explanation:
In the above-given question,
given that,
there are 4 bees,
4 more bees.
4 + 4 = 8
so the number of bees = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-3

On Your Own

MATHEMATICAL PRACTICE
Model Mathematics Write how many.

Question 3.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 26
2 butterflies and 4 more butterflies _6_ butterflies

Answer:
The number of butterflies = 6.

Explanation:
In the above-given question,
given that,
there are 2 butterflies.
4 more butterflies.
2 + 4 = 6.
so the number of butterflies = 6.

Question 4.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 27
4 ladybugs and 3 more ladybugs _7_ ladybugs

Answer:
The number of ladybugs = 7.

Explanation:
In the above-given question,
given that,
there are 4 ladybugs,
3 more ladybugs.
3 + 4 = 7.
so the number of ladybugs = 7.

Question 5.
THINK SMARTER
Evan and Luke see 8 worms on the path. Luke sees 2 more worms than Evan. Evan sees 3 worms. How many worms does Luke see?
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 28
_5_ worms

Answer:
Luke sees 5 warms.

Explanation:
In the above-given question,
given that,
Evan and luke see 8 worms on the path.
Luke sees 2 more worms than Evan.
Evan sees 3 worms.
3 + 2 = 5.
Luke sees 5 warms.

Problem Solving • Applications

Question 6.
THINK SMARTER
Color the birds to show how to solve.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 29
There are 3 red birds. Some blue birds join them. How many blue birds are there?
There are _2_ blue birds.

Answer:
The number of bluebirds = 2.

Explanation:
In the above-given question,
given that,
There are 3 red birds.
Some bluebirds join them.
3 + 2 = 5.
The number of bluebirds = 2.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-4

Question 7.
THINK SMARTER
Circle how many ants in all.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 30

Answer:
The number of ants = 5.

Explanation:
In the above-given question,
given that,
There are 3 ants and 2 more ants.
3 + 2 = 5 ants.
The number of ants = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-5

TAKE HOME ACTIVITY
• Have your child use stuffed animals or other toys to show 3 animals. Then add to the group showing 2 more animals. Ask how many animals there are. Repeat for other combinations of animals with totals up to 10.

Answer:
The number of animals = 5.

Explanation:
In the above-given question,
given that,
Your child use stuffed animals or other toys to show 3 animals.
Then add to the group showing 2 more animals.
3 + 2 = 5.
The number of animals = 5.

Algebra • Use Pictures to Add To Homework & Practice 1.1

Write how many.

Question 1.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 31
5 horses and 3 more horses _8_ horses

Answer:
The number of horses = 8.

Explanation:
In the above-given question,
given that,
there are 5 horses and 3 more horses.
5 + 3 = 8.
so the number of horses = 8.

Question 2.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 32
3 dogs and 2 more dogs _5_ dogs

Answer:
The number of dogs = 5.

Explanation:
In the above-given question,
given that,
there are 3 dogs and 2 more dogs.
3 + 2 = 5.
so the number of dogs = 5.

Problem Solving

Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 33
Question 3.
There are 2 rabbits. 5 rabbits join them. How many rabbits are there now?
There are _7_ rabbits.

Answer:
The number of rabbits = 7.

Explanation:
In the above-given question,
given that,
there are 2 rabbits and 5 more rabbits.
2 + 5 = 7.
so the number of rabbits = 7.

Question 4.
WRITE Math
Use pictures and numbers to show 4 dogs and 1 more dog. Then write how many dogs there are.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 34

Answer:
The number of dogs = 5.

Explanation:
In the above-given question,
given that,
there are 4 dogs and 1 more dog.
4 + 1 = 5.
so the number of dogs = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-1

Lesson Check

Question 1.
How many birds are there? Write the number.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 35

Answer:
The number of birds = 8.

Explanation:
In the above-given question,
given that,
there are 2 birds and 6 more birds.
2 + 6 = 8.
so the number of birds = 8.

Spiral Review

Question 2.
How many goats are there? Write the number.
2 goats and 4 more goats _6_ goats

Answer:
The number of goats = 6.

Explanation:
In the above-given question,
given that,
there are 2 goats and 4 more goats.
2 + 4 = 6.
so the number of goats = 6.

Question 3.
How many rabbits are there? Write the number.
5 rabbits and 1 more rabbit _6_ rabbits

Answer:
The number of rabbits = 6.

Explanation:
In the above-given question,
given that,
there are 5 rabbits and 1 more rabbit.
5 + 1 = 6.
so the number of rabbits = 6.

Question 4.
How many ducks are there? Write the number.
5 ducks and 4 more ducks _9_ ducks

Answer:
The number of ducks = 9.

Explanation:
In the above-given question,
given that,
there are 5 ducks and 4 more ducks.
5 + 4 = 9.
so the number of ducks = 9.

Lesson 4.2 Model Adding To

Essential Question
How do you model adding to a group?

Listen and Draw

Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 39 to show adding to. Draw to show your work.

Math Talk
MATHEMATICAL PRACTICES
Explain how you use cubes to find your answer.

Share and Show MATH BOARD

Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 40 to show adding to. Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 41 Write the sum.

Question 1.
3 cats and 1 more cat
3 + 1 = _4_

Answer:
The number of cats = 4.

Explanation:
In the above-given question,
given that,
there are 3 cats and 1 more cat.
3 + 1 = 4.
so the number of cats = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-6

Question 2.
2 birds and 3 more birds
2 + 3 = _5_

Answer:
The number of birds = 5.

Explanation:
In the above-given question,
given that,
there are 2 birds and 3 more birds.
2 + 3 = 5.
so the number of birds = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-7

Question 3.
4 bugs and 4 more bugs
4 + 4 = _8_

Answer:
The number of bugs = 8.

Explanation:
In the above-given question,
given that,
there are 4 bugs and 4 more bugs.
4 + 4 = 8.
so the number of bugs = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-8

Question 4.
4 fish and 2 more fish
4 + 2 = _6_

Answer:
The number of fish = 6.

Explanation:
In the above-given question,
given that,
there are 4 fish and 2 more fish.
4 + 2 = 6.
so the number of fish = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-9

On Your Own

Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 41.1

Answer:
The number of bees = 3.

Explanation:
In the above-given question,
given that,
there are 2 bees and 1 more bee.
2 + 1 = 3.
so the number of bees = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-10

MATHEMATICAL PRACTICE
Use Appropriate Tools Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 42 to show adding to. Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 43. Write the sum.

Question 5.
5 dogs and 4 more dogs
5 + 4 = _9_

Answer:
The number of dogs = 9.

Explanation:
In the above-given question,
given that,
there are 5 bees and 4 more bees.
5 + 4 = 9.
so the number of bees = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-11

Question 6.
4 bees and 3 more bees
4 + 3 = _7_

Answer:
The number of bees = 7.

Explanation:
In the above-given question,
given that,
there are 4 bees and 3 more bees.
4 + 3 = 7.
so the number of bees = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-12

Question 7.
THINK DEEPER
Julia has
4 books on the table. She puts 1 more book on the table. Then she puts 2 more books on the table. How many books are on the table?
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 43.1
_7_ books

Answer:
The number of books on the table = 7.

Explanation:
In the above-given question,
given that,
There are 4 books on the table.
she puts 1 more book on the table.
Then she puts 2 more books on the table.
The number of books on the table = 7.

Question 8.
GO DEEPER
Diego drew cubes to show adding to. Draw to show how Diego should fix his picture. Write the sum.
2 + 8 = _10_
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 44
2 + 8 = _10_

Answer:
The number of cubes = 10.

Explanation:
In the above-given question,
given that,
there are 2 cubes and 8 more cubes.
2 + 8 = 10.
so the number of cubes = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-13

Problem Solving • Applications

THINK SMARTER
Use the picture to help you complete the addition sentences. Write the sum.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 45

Answer:
The number of triangles = 5.

Explanation:
In the above-given question,
given that,
there are 3 triangles and 2 more triangles.
3 + 2 = 5.
so the number of triangles = 5.

Answer:
The number of rectangles = 6.

Explanation:
In the above-given question,
given that,
there are 3 rectangles and 3 more rectangles.
3 + 3 = 6.
so the number of rectangles = 6.

Answer:
The number of circles = 4.

Explanation:
In the above-given question,
given that,
there are 3 circles and 1 more circle.
3 + 1 = 4.
so the number of circles = 4.

Question 12.
THINK SMARTER
Use to Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 46 show adding to. Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 47 Write the sum.
3 bunnies and 5 more bunnies
3 + 5 = Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 48

Answer:
The number of bunnies = 8.

Explanation:
In the above-given question,
given that,
there are 3 bunnies and 5 more bunnies.
3 + 5 = 8.
so the number of bunnies = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.1-14

TAKE HOME ACTIVITY
• Put 3 small objects in one group and 2 small objects in another group. Have your child write an addition sentence to tell about the small objects. Repeat for other combinations of small objects with sums of up to 10.

Answer:
The number of objects = 5.

Explanation:
In the above-given question,
given that,
there are 3 objects and 2 more objects.
3 + 2 = 5.
so the number of objects = 5.

Model Adding To Homework & Practice 1.2

Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 49 to show adding to. Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 50. Write the sum.

Question 1.
5 ants and 1 more ant
5 + 1 = _6_

Answer:
The number of ants = 6.

Explanation:
In the above-given question,
given that,
there are 5 ants and 1 more ant.
5 + 1 = 6.
so the number of ants = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-1

Question 2.
3 cats and 4 more cats
3 + 4 = _7_

Answer:
The number of cats = 7.

Explanation:
In the above-given question,
given that,
there are 3 cats and 4 more cats.
3 + 4 = 7.
so the number of cats = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-2

Problem Solving

Use the picture to help you complete the addition sentences. Write each sum.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 51

Question 3.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 52

Answer:
The number of rectangles = 5.

Explanation:
In the above-given question,
given that,
there are 2 rectangles and 3 more rectangles.
2 + 3 = 5.
so the number of rectangles = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-3

Question 4.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 53

Answer:
The number of circles = 4.

Explanation:
In the above-given question,
given that,
there are 3 circles and 1 more circle.
3 + 1 = 4.
so the number of circles = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-4

Question 5.
WRITE Math
Use cubes to show how to add 1 turtle to 5 turtles. Draw the cubes.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 54

Answer:
The number of turtles = 6.

Explanation:
In the above-given question,
given that,
there are 5 turtles and 1 more turtle.
5 + 1 = 6.
so the number of turtles = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-5

Lesson Check

Question 1.
Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 55 Write the sum. What is the sum of 4 and 2?
4 + 2 = _6_

Answer:
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 2.
4 + 2 = 6.
the sum for 4 + 2 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-6

Spiral Review

Question 2.
How many butterflies are there? Write the number.
5 butterflies and 2 more butterflies _7__ butterflies

Answer:
The number of butterflies = 7.

Explanation:
In the above-given question,
given that,
there are 5 butterflies and 2 more butterflies.
5 + 2 = 7.
so the number of butterflies = 7.

Question 3.
Draw the Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 56. Write the sum. What is the sum of 2 and 3?
2 + 3 = _5_

Answer:
The sum for 2 + 3 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 3.
2 + 3 = 5.
the sum for 2 + 3 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-7

Question 4.
How many birds are there? Write the number.
6 birds and 1 more bird _7_ birds

Answer:
The number of birds = 7.

Explanation:
In the above-given question,
given that,
there are 6 birds and 1 more bird.
6 + 1 = 7.
so the number of birds = 7.

Lesson 1.3 Model Putting Together

Essential Question
How do you model putting together?

Listen and Draw

Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 57 or an i Tool to model the problem. Draw a picture of your model. Write the numbers and addition sentence.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 58

Answer:
The number of red crayons = 2.
The number of yellow crayons = 3.
The number of crayons = 5.

Explanation:
In the above-given question,
given that,
there are red crayons and yellow crayons.
2 + 3 = 5.
so the number of crayons = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-1

Math Talk
MATHEMATICAL PRACTICES
Describe how the drawing helps you write the addition sentence.

Model and Draw

Add to find how many books there are.
There are 2 small books and 1 big book. How many books are there?
_3_ books
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 59

Answer:
The number of books = 3.

Explanation:
In the above-given question,
given that,
there are 2 small books and 1 big book.
2 + 1 = 3.
so the number of books = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-2

Share and Show MATH BOARD

Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 60 to solve. Draw to show your work. Write the number sentence and how many

Question 1.
There are 4 red pencils and 2 green pencils. How many pencils are there?
_6_ pencils
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 61

Answer:
The number of pencils = 6.

Explanation:
In the above-given question,
given that,
there are 4 red pencils and  2 green pencils.
4 + 2 = 6.
so the number of pencils = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-3

Question 2.
There are 5 blue cups and 3 yellow cups. How many cups are there?
_8_ cups.
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 62

Answer:
The number of cups = 8.

Explanation:
In the above-given question,
given that,
there are 5 blue cups and  3 yellow cups.
5 + 3 = 8.
so the number of cups = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-4

On Your Own MATH BOARD

MATHEMATICAL PRACTICE
Write an Equation Use Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 63 to solve. Draw to show your work. Write the number sentence and how many.

Question 3.
There are 3 small cats and 4 big cats. How many cats are there?
_7_ cats
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 65

Answer:
The number of cats = 7.

Explanation:
In the above-given question,
given that,
there are 3 small cats and  4 big cats.
3 + 4 = 7.
so the number of cats = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-5

Question 4.
There are 6 red cubes and 3 blue cubes. How many cubes are there?
_9_ cubes
Go Math Grade 1 Answer Key Chapter 1 Addition Concepts 66

Answer:
The number of cubes = 9.

Explanation:
In the above-given question,
given that,
there are 6 red cubes and  3 blue cubes.
6 + 3 = 9.
so the number of cubes = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-6

Question 5.
There are 2 red flowers and 8 yellow flowers. How many flowers are there?
_10_ flowers
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 67

Answer:
The number of flowers = 10.

Explanation:
In the above-given question,
given that,
there are 2 red flowers and  8 yellow flowers.
8 + 2 = 10.
so the number of flowers = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-7

Question 6.
THINK SMARTER
4 girls and 4 boys run. Then 2 more children run. The same number of girls and boys run. How many of each run?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 68
_6_ girls _6_ boys

Answer:
The number of boys = 5.
The number of girls = 5.

Explanation:
In the above-given question,
given that,
there are 4 girls and  4 boys run.
2 more children run.
5 + 5 = 10.
so the number of children = 10.

Problem Solving • Applications

Question 7.
THINK SMARTER
Write your own addition story problem.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 69

Answer:
The number of boys = 5.
The number of girls = 5.

Explanation:
In the above-given question,
given that,
there are 4 girls and  4 boys run.
2 more children run.
5 + 5 = 10.
so the number of children = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-8

Question 8.
Use Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 70 to solve your story problem. Draw to show your work. Write the number sentence.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 71

Answer:
The number of boys = 5.
The number of girls = 5.

Explanation:
In the above-given question,
given that,
there are 4 girls and  4 boys run.
2 more children run.
5 + 5 = 10.
so the number of children = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-9

Question 9.
THINK SMARTER
Draw Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 72 to solve. Write the number sentence and how many.
There are 4 yellow apples and 4 red apples. How many apples are there?
_8_ apples
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 73

Answer:
The number of apples = 8.

Explanation:
In the above-given question,
given that,
there are 4 red apples and  4 yellow apples.
4 + 4 = 8.
so the number of apples = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-10

TAKE HOME ACTIVITY
• Have your child collect a group of up to 10 small objects and use them to make up addition stories.

Model Putting Together Homework & Practice 1.3

Question 1.
There are 2 big dogs and 4 small dogs. How many dogs are there?
_6_ dogs
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 74

Answer:
The number of dogs = 6.

Explanation:
In the above-given question,
given that,
there are 4 small dogs and  2 big dogs.
4 + 2 = 6.
so the number of dogs = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-11

Question 2.
There are 3 red crayons and 2 green crayons. How many crayons are there?
_5_ crayons
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 75

Answer:
The number of crayons = 5.

Explanation:
In the above-given question,
given that,
there are 3 red crayons and  2 green crayons.
3 + 2 = 5.
so the number of crayons = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-12

Problem Solving

Question 3.
WRITE Math
Write your own addition story problem. Draw counters to help you solve.
___________
___________
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 76

Answer:
The number of boys = 5.
The number of girls = 5.

Explanation:
In the above-given question,
given that,
there are 4 girls and  4 boys run.
2 more children run.
5 + 5 = 10.
so the number of children = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-8

Question 4.
Write your own addition problem. Draw counters to help you solve.
_________________
_________________

Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 76.1

Answer:
The number of crayons = 5.

Explanation:
In the above-given question,
given that,
there are 3 red crayons and  2 green crayons.
3 + 2 = 5.
so the number of crayons = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-13

Lesson Check

Question 1.
Write the number sentence and how many. There are 3 black cats and 2 brown cats. How many cats are there?
_5_ cats
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 77

Answer:
The number of cats = 5.

Explanation:
In the above-given question,
given that,
there are 3 black cats and  2 brown cats.
3 + 2 = 5.
so the number of cats = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-13

Question 2.
There are 4 red flowers and 3 yellow flowers. How many flowers are there?
_7_ flowers

Answer:
The number of flowers = 7.

Explanation:
In the above-given question,
given that,
there are 4 red flowers and  3 yellow flowers.
4 + 3 = 7.
so the number of flowers = 7.

Spiral Review

Question 3.
How many turtles are there? Write the number.
6 turtles and 3 more turtles _9__ turtles

Answer:
The number of turtles = 9.

Explanation:
In the above-given question,
given that,
there are 6 turtles and 3 more turtle.
6 + 3 = 9.
so the number of turtles = 9.

Question 4.
Draw the Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 79. Write the sum. What is the sum of 2 and 1?
2 + 1 = _3_

Answer:
The sum for 2 + 1 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 1.
2 + 1 = 3.
the sum for 2 + 1 = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-14

Lesson 1.4 Problem Solving • Model Addition

Essential Question
How do you solve addition problems by making a model?

Hanna has 4 red flowers in a Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 79.1. She puts 2 more flowers in the Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 79.1. How many flowers are in the Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 79.1? How can you use a model to find out?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 82

Answer:
The number of flowers = 6.

Explanation:
In the above-given question,
given that,
Hanna has 4 red flowers in a pot.
she puts 2 more flowers in the pot.
4 + 2 = 6.
so the number of flowers = 6.

Unlock the Problem

What do I need to find?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 83
What information do I need to use?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 83.1

Answer:
The number of flowers = 6.

Explanation:
In the above-given question,
given that,
Hanna has 4 red flowers in a pot.
she puts 2 more flowers in the pot.
4 + 2 = 6.
so the number of flowers = 6.

Show how to solve the problem.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 84

Answer:
The number of flowers = 6.

Explanation:
In the above-given question,
given that,
Hanna has 4 red flowers in a pot.
she puts 2 more flowers in the pot.
4 + 2 = 6.
so the number of flowers = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.3-15

HOME CONNECTION
• Your child can model the concepts of adding to and putting together. He or she used a bar model to show the problems and solve.

Try Another Problem

Read the problem. Use the bar model to solve. Complete the model and the number sentence.

Question 1.
There are 7 dogs in the park. Then 1 more dog joins them. How many dogs are in the park now?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 85
7 + 1 = _8__

Answer:
The number of dogs = 8.

Explanation:
In the above-given question,
given that,
There are 7 dogs in the park.
Then 1 more dog joins them.
7 + 1 = 8.
so the number of dogs = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-1

Question 2.
Some birds are sitting in the tree. Four more birds sit in the tree. Then there are 9 birds. How many birds were in the tree before?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 86
__5_ + 4 = 9

Answer:
The number of birds = 5.

Explanation:
In the above-given question,
given that,
Some birds are sitting in the tree.
Four more birds sit in the tree.
5 + 4 = 9.
so the number of birds = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-2

Question 3.
There are 4 horses in the field. Some more horses run to the field. Then there were 10 horses in the field. How many horses run to the field?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 87
4 + _6_ = 10

Answer:
The number of horses run to the field = 6.

Explanation:
In the above-given question,
given that,
There are 4 horses in the field.
Then there were 10 horses.
4 + 6 = 10.
so the number of horses run to the field = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-3

Math Talk
MATHEMATICAL PRACTICES

Analyze In Exercise 1, how will the model change if there are 5 dogs and 3 dogs join them?

Share and Show MATH BOARD
MATHEMATICAL PRACTICE
Use Diagrams Read the problem. Use the bar model to solve. Complete the model and the number sentence.

Question 4.
THINK SMARTER
Luis has 12 crayons. 5 of the crayons are red. The rest are blue. How many crayons are blue?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 88
5 + _7_ = 12

Answer:
The number of blue crayons = 7.

Explanation:
In the above-given question,
given that,
Luis has 12 crayons.
5 of the crayons are red.
rest are blue.
5 + 7 = 12.
so the number of crayons = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-4

Question 5.
8 bugs are flying. 2 more bugs fly with them. How many bugs are flying now?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 89
8 + 2 = _10_

Answer:
The number of bugs flying = 10.

Explanation:
In the above-given question,
given that,
8 bugs are flying.
2 more bugs fly with them.
8 + 2 = 10.
so the number of bugs flying = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-5

Question 6.
THINK SMARTER
Some ducks are swimming in a pond. 3 more ducks swim in the pond. Then there are 6 ducks in the pond. How many ducks were in the pond before?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 90
_3_ + 3 = 6

Answer:
The number of ducks in the pond before = 3.

Explanation:
In the above-given question,
given that,
Some ducks are swimming in a pond.
3 more ducks swim in the pond.
Then there are 6 ducks in the pond.
3 + 3 = 6.
so the number of ducks in the pond before = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-6

TAKE HOME ACTIVITY
• Have your child describe each of the parts of a bar model using the number sentence 7 + 3 = 10.

Answer:
The number of dogs = 10.

Explanation:
In the above-given question,
given that,
There are 7 dogs in the park.
Then 3 more dog joins them.
7 + 3 = 10.
so the number of dogs = 10.

Problem Solving • Model Addition Homework & Practice 1.4

Read the problem. Use the bar model to solve. Complete the model and the number sentence.

Question 1.
Dylan has 7 flowers. 4 of the flowers are red. The rest are yellow. How many flowers are yellow?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 91
4 + _3_ = 7

Answer:
The number of yellow flowers = 3.

Explanation:
In the above-given question,
given that,
Dylan has 7 flowers.
4 of the flowers are red.
4 + 3 = 7.
so the number of yellow flowers = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-7

Question 2.
Some birds are flying in a group. 4 more birds join the group. Then there are 9 birds in the group. How many birds were in the group before?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 92
_5_ + 4 = 9

Answer:
The number of birds were in the group before = 5.

Explanation:
In the above-given question,
given that,
Some birds are flying in a group.
4 more birds join the group.
Then there are 9 birds in the group.
5 + 4 = 9.
so the number of birds were in the group before = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-8

Question 3.
6 cats are walking. 1 more cat walks with them. How many cats are walking now?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 93
6 + 1 = _7_

Answer:
The number of cats walking now = 7.

Explanation:
In the above-given question,
given that,
6 cats are walking.
1 more catwalks with them.
6 + 1 = 7.
so the number of cats walking now = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-9

Question 4.
WRITE MATH
Write a problem that has two parts. Then solve it by finding the whole.
______________
______________
______________
______________

Lesson Check

Question 1.
Complete the model and the number sentence. 3 ducks are in the pond. 6 more ducks join them. How many ducks are in the pond now?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 94
3 + 6 = _9_

Answer:
The number of ducks in the pond = 9.

Explanation:
In the above-given question,
given that,
3 ducks are in the pond.
6 more ducks join them.
3 + 6 = 9.
so the number of ducks in the pond = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-10

Spiral Review

Question 2.
Write the number sentence and how many. There are 4 green grapes and 4 red grapes. How many grapes are there?
_8_ grapes
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 95

Answer:
The number of grapes = 8.

Explanation:
In the above-given question,
given that,
there are 4 green grapes and 4 red grapes.
4 + 4 = 8.
so the number of grapes = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-11

Question 3.
Draw the Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 96 Write the sum. What is the sum of 7 and 3?
7 + 3 = _10_

Answer:
The sum for 7 + 3 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 7 and 3.
7 + 3 = 10.
the sum for 7 + 3 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-12

Question 4.
Draw the Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 97 Write the sum. What is the sum of 6 and 2?
6 + 2 = _8_

Answer:
The sum for 6 + 2 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 2.
6 + 2 = 8.
the sum for 6 + 2 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-13

Addition Concepts Mid-Chapter Checkpoint

Concepts and Skills

Use Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 98 to show adding to. Draw the Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 99 Write the sum.

Question 1.
3 bugs and 4 more bugs
3 + 4 = _7_

Answer:
The number of bugs = 7.

Explanation:
In the above-given question,
given that,
3 bugs and 4 more bugs.
3 + 4 = 7.
so the number of bugs = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-14

Question 2.
4 seals and 2 more seals
4 + 2 = _6_

Answer:
The number of seals = 6.

Explanation:
In the above-given question,
given that,
4 seals and 2 more seals.
4 + 2 = 6.
so the number of seals = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-15

Use Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 100 to solve. Draw to show your work. Write the number sentence and how many.

Question 3.
There are 5 red marbles and 4 blue marbles. How many marbles are there?
_9_ marbles
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 101

Answer:
The number of marbles = 9.

Explanation:
In the above-given question,
given that,
There are 5 red marbles and 4 blue marbles.
5 + 4 = 9.
so the number of marbles = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-16

Question 4.
THINK SMARTER
There are 6 bunnies in the garden. More bunnies join them. Then there are 8 bunnies in the garden. How many bunnies join them?
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 102
6 + _2_ = 8

Answer:
The number of bunnies joins them = 2.

Explanation:
In the above-given question,
given that,
6 bunnies in the garden.
Then there are 8 bunnies in the garden.
6 + 2 = 8
so the number of bunnies join them = 2.

Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.4-17

Lesson 1.5 Algebra • Add Zero

Essential Question
What happens when you add 0 to a number?

Listen and Draw

Use Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 103 to model the problem. Draw Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 103 the you use.

Math Talk
MATHEMATICAL PRACTICES
Model the problem showing Jennifer with 4 marbles and Scott with no marbles. How does the drawing change?

Answer:
The number of marbles = 4.

Explanation:
In the above-given question,
given that,
Jennifer with 4 marbles and scott with no marbles.
4 + 0 = 4.
so the number of marbles = 4.

Share and Show MATH BOARD

Use the picture to write each part. Write the sum.

Question 1.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 105
_1_ + _0_ = _1_

Answer:
The sum for 1 + 0 = 1.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 0.
1 + 0 = 1.
the sum for 1 + 0 = 1.

Question 2.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 106
_0_ + _2_ = _2_

Answer:
The sum for 0 + 2 = 2.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 2.
0 + 2 = 2.
the sum for 0 + 2 = 2.

Question 3.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 107
_0_ + _4_ = _4_

Answer:
The sum for 0 + 4 = 4.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 4.
0 + 4 = 4.
the sum for 0 + 4 = 4.

Question 4.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 108
_6_ + _0_ = _6_

Answer:
The sum for 6 + 0 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 0.
6 + 0 = 6.
the sum for 6 + 0 = 6.

On Your Own

Draw circles to show the number. Write the sum

Question 5.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 109

Answer:
The sum for 2 + 0 = 2.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 0.
2 + 0 = 2.
the sum for 2 + 0 = 2.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-1

Question 6.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 110

Answer:
The sum for 0 + 1 = 1.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 1.
0 + 1 = 1.
the sum for 0 + 1 = 1.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-2

Question 7.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 111

Answer:
The sum for 4 + 6 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 6.
4 + 6 = 10.
the sum for 4 + 6 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-3

Question 8.
Go Math Grade 1 Chapter 1 Answer Key Pdf Addition Concepts 112

Answer:
The sum for 0 + 5 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 5.
0 + 5 = 5.
the sum for 0 + 5 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-4

Question 9.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 113

Answer:
The sum for 3 + 4 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 4.
3 + 4 = 7.
the sum for 3 + 4 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-5

Question 10.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 114

Answer:
The sum for 0 + 6 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 6.
0 + 6 = 6.
the sum for 0 + 6 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-6

Question 11.
THINK SMARTER
There are 5 red birds. There are 3 green birds. How many birds are blue?
__2_ bluebirds

Answer:
The number of bluebirds = 2.

Explanation:
In the above-given question,
given that,
There are 5 red birds.
There are 3 green birds.
5 + 3 + 2 = 10.
so the number of bluebirds = 2.

Question 12.
THINK SMARTER
Maya has 7 books. Eli has no books. Then Maya gives 7 books to Eli. How many books does Maya have?
__0_ books
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 115

Answer:
The number of Books Maya have = 0.

Explanation:
In the above-given question,
given that,
Maya has 7 books.
Eli has no books.
Then Maya gives 7 books to Eli.
7 + 7 = 0.
so the number of Books Maya have  = 0.

Question 13.
THINK SMARTER
Complete the addition sentence.
_7_ + _7_ = 0

Answer:
The number of Books Maya have = 0.

Explanation:
In the above-given question,
given that,
Maya has 7 books.
Eli has no books.
Then Maya gives 7 books to Eli.
7 + 7 = 0.
so the number of Books Maya have  = 0.

Problem Solving • Applications

MATHEMATICAL PRACTICE

Generalize Write the addition sentence to solve.

Question 14.
Mike has 7 books. Cheryl does not have any books. How many books do they both have?
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 116
_7_ + _0_ = _7_
_7_ books

Answer:
The number of Books they have both = 7.

Explanation:
In the above-given question,
given that,
Mike has 7 books.
Cheryl does not have any books.
7 + 0 = 7.
so the number of Books they have both  = 7.

Question 15.
THINK SMARTER
There are 5 birds in all. How many birds are in the bird house?
_5_ birds
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 117

Answer:
The number of birds in the birdhouse = 5.

Explanation:
In the above-given question,
given that,
There are 5 birds in all.
5 + 0 = 5.
so the number of birds in the birdhouse  = 5.

Question 16.
THINK SMARTER
There are no dogs in the park. Then 5 dogs come to the park. How many dogs are in the park now?
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 118
_5_ dogs

Answer:
The number of dogs in the park now = 5.

Explanation:
In the above-given question,
given that,
There are no dogs in the park.
Then 5 dogs come to the park.
0 + 5 = 5.
so the number of dogs in the park now = 5.

TAKE HOME ACTIVITY
• Write the numbers 0 to 9 on small squares of paper. Shuffle and place the cards facedown. Have your child turn over the top card and add zero to that number. Say the sum. Repeat the activity for each card.

Algebra • Add Zero Homework & Practice 1.5

Draw circles to show the number. Write the sum.

Question 1.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 119

Answer:
The sum for 0 + 5 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 5.
0 + 5 = 5.
the sum for 0 + 5 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-4

Question 2.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 120

Answer:
The sum for 1 + 3 = 4.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 3.
1 + 3 = 4.
the sum for 1 + 3 = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-7

Problem Solving

Write the addition sentence to solve.

Question 3.
6 turtles swim. No turtles join them. How many turtles are there now?
_6_ + _0_ = _6_
_6_ turtles

Answer:
The number of turtles = 6.

Explanation:
In the above-given question,
given that,
there are 6 turtles and 0 more turtle.
6 + 0 = 6.
so the number of turtles = 6.

Question 4.
WRITE MATH
Use pictures and numbers to show 8 + 0.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 121

Answer:
The sum for 8 + 0 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 8 and 0.
8 + 0 = 8.
the sum for 8 + 0 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-8

Lesson Check

Question 1.
Draw Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 122 to show each addend. Write the sum. What is the sum for 0 + 4?
0 + 4 = _4_

Answer:
The sum for 0 + 4 = 4.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 4.
0 + 4 = 4.
the sum for 0 + 4 = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-9

Spiral Review

Question 2.
Complete the model and the number sentence. There are 4 goats in the barn. 3 more goats join them. How many goats are in the barn now?
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 123
4 + 3 = _7_

Answer:
The number of goats in the barn = 7.

Explanation:
In the above-given question,
given that,
There are 4 goats in the barn.
3 more goats join them.
4 + 3 = 7.
so the number of goats in the barn = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-10

Question 3.
Write the number sentence and how many. There are 7 blue crayons and 1 yellow crayon. How many crayons are there?
_8_ crayons
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 124

Answer:
The number of crayons = 8.

Explanation:
In the above-given question,
given that,
There are 7 blue crayons and 1 yellow crayon.
7 + 1 = 8.
so the number of crayons = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.5-11

Question 4.
Draw the Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 125 Write the sum. What is the sum of 3 and 3?
3 + 3 = _6_

Answer:
The sum for 3 + 3 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 3.
3 + 3 = 6.
the sum for 3 + 3 = 6.

Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.2-5

Lesson 1.6 Algebra • Add in Any Order

Essential Question
Why can you add addends in any order?

Listen and Draw
Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 126 to model the addition sentence. Draw to show your work.

Math Talk
MATHEMATICAL PRACTICES

Look for Structure Explain how 2 + 3 = 5 is the same as 3 + 2 = 5. How is it different?

Share and Show MATH BOARD

Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 127 to add. Color to match. Write the sum.

Question 1.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 127.1

Answer:
The sum for 2 + 3 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 3.
2 + 3 = 5.
the sum for 2 + 3 = 5.

Answer:
The sum for 3 + 2 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 2.
3 + 2 = 5.
the sum for 3 + 2 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-1

Question 2.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 128

Answer:
The sum for 2 + 4 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 4.
2 + 4 = 6.
the sum for 2 + 4 = 6.

Answer:
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 2.
4 + 2 = 6.
the sum for 4 + 2 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-2

Question 3.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 129

Answer:
The sum for 4 + 1 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 1.
4 + 1 = 5.
the sum for 4 + 1 = 5.

Answer:
The sum for 1 + 4 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 4.
1 + 4 = 5.
the sum for 1 + 4 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-3

On Your Own

MATHEMATICAL PRACTICE
Look for Structure Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 130. Write the sum. Circle the addition sentences in each row that have the same addends in a different order.

Question 4.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 130.1

Answer:
The sum for 1 + 2 = 3.
The sum for 2 + 1 = 3.
The sum for 1 + 3 = 4.

Explanation:
In the above-given question,
given that,
The sum for 1 + 2 = 3.
The sum for 2 + 1 = 3.
The sum for 1 + 3 = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-4

Question 5.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 131

Answer:
The sum for 1 + 5 = 6.
The sum for 4 + 2 = 6.
The sum for 2 + 4 = 6.

Explanation:
In the above-given question,
given that,
The sum for 1 + 5 = 6.
The sum for 4 + 2 = 6.
The sum for 2 + 4 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-5

Question 6.
THINK SMARTER
Choose addends to complete the addition sentence. Change the order. Write the numbers.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 132

Answer:
The sum for 5 + 5 = 10.
The sum for 6 + 4 = 10.

Explanation:
In the above-given question,
given that,
The sum for 5 + 5 = 10.
The sum for 6 + 4 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-6

Question 7.
GO DEEPER
Write two addition sentences that tell about the picture.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 133

Answer:
The sum for 5 + 1 = 6.
The sum for 1 + 5 = 6.

Explanation:
In the above-given question,
given that,
The sum for 5 + 1 = 6.
The sum for 1 + 5 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-7

Problem Solving • Applications WRITE Math

Draw pictures to match the addition sentences. Write the sum.

Question 8.
2 + 6 = _8_
6 + 2 = _8_

Answer:
The sum for 2 + 6 = 8.
The sum for 6 + 2 = 8.

Explanation:
In the above-given question,
given that,
The sum for 2 + 6 = 8.
The sum for 6 + 2 = 8.

Question 9.
1 + 5 = _6_
5 + 1 = _6_

Answer:
The sum for 1 + 5 = 6.
The sum for 5 + 1 = 6.

Explanation:
In the above-given question,
given that,
The sum for 1 + 5 = 6.
The sum for 5 + 1 = 6.

Question 10.
THINK SMARTER
Draw lines to match the same addends in a different order.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 134

Answer:
The sum for 7 + 3 = 10.
The sum for 3 + 6 = 9.
The sum for 4 + 6 = 10.

Explanation:
In the above-given question,
given that,
The sum for 7 + 3 = 10.
The sum for 3 + 6 = 9.
The sum for 4 + 6 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-8

TAKE HOME ACTIVITY
• Ask your child to use small objects of the same kind to show 2 + 4 and 4 + 2 and then explain to you why the sums are the same. Repeat with other addition sentences.

Algebra • Add in Any Order Homework & Practice 1.6

Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 135 Write the sum. Circle the addition sentences in each row that have the same addends in a different order.

Question 1.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 136

Answer:
The sum for 1 + 3 = 4.
The sum for 1 + 2 = 3.
The sum for 3 + 1 = 4.

Explanation:
In the above-given question,
given that,
The sum for 1 + 3 = 4.
The sum for 1 + 2 = 3.
The sum for 3 + 1 = 4.

Question 2.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 137

Answer:
The sum for 2 + 3 = 5.
The sum for 3 + 2 = 5.
The sum for 0 + 5 = 5.

Explanation:
In the above-given question,
given that,
The sum for 2 + 3 = 5.
The sum for 3 + 2 = 5.
The sum for 0 + 5 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-9

Question 3
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 138

Answer:
The sum for 2 + 4 = 6.
The sum for 3 + 3 = 6.
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
The sum for 2 + 4 = 6.
The sum for 3 + 3 = 6.
The sum for 4 + 2 = 6.

Problem Solving

Draw pictures to match the addition sentences. Write the sums.

Question 4.
5 + 2 = _7_
2 + 5 = _7_

Answer:
The sum for 2 + 5 = 7.
The sum for 5 + 2 = 7.

Explanation:
In the above-given question,
given that,
The sum for 2 + 5 = 7.
The sum for 5 + 2 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-12

Question 5.
WRITE Math
Use pictures and numbers to show how to add 3 + 1 in any order.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 139

Answer:
The sum for 1 + 3 = 4.
The sum for 3 + 1 = 4.

Explanation:
In the above-given question,
given that,
The sum for 1 + 3 = 4.
The sum for 3 + 1 = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-13

Lesson Check

Question 1.
Circle the addition sentences in the row that have the same addends in a different order.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 140

Answer:
The sum for 1 + 5 = 6.
The sum for 6 + 1 = 7.
The sum for 1 + 6 = 7.

Explanation:
In the above-given question,
given that,
The sum for 1 + 5 = 6.
The sum for 6 + 1 = 7.
The sum for 1 + 6 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-10

Spiral Review

Question 2.
Draw to show the numbers. Write the sum. What is the sum?
0 + 2 = _2_

Answer:
The sum for 0 + 2 = 2.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 2.
0 + 2 = 2.
the sum for 0 + 2 = 2.

Question 3.
Write the number sentence and how many. There are 5 long strings and 3 short strings. How many strings are there?
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 141.1

Answer:
The number of strings = 8.

Explanation:
In the above-given question,
given that,
There are 5 long strings and 3 short strings.
5 + 3 = 8.
so the number of strings = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-11

Question 4.
Draw the Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 142. Write the sum. What is the sum of 6 and 2?
6 + 2 = _8_

Answer:
The sum for 6 + 2 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 2.
6 + 2 = 8.
the sum for 6 + 2 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.6-14

Lesson 1.7 Algebra • Put Together Numbers to 10

Essential Question
How can you show all the ways to make a number?

Listen and Draw

Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 143 to show all the ways to make 5. Color to show your work.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 144

Answer:
The sum for 1 + 4 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 4.
1 + 4 = 5.
the sum for 1 + 4 = 5.

Answer:
The sum for 2 + 3 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 3.
2 + 3 = 5.
the sum for 2 + 3 = 5.

Answer:
The sum for 3 + 2 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 2.
3 + 2 = 5.
the sum for 3 + 2 = 5.

Answer:
The sum for 4 + 1 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 1.
4 + 1 = 5.
the sum for  4 + 1 = 5.

Answer:
The sum for 0 + 5 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 5.
0 + 5 = 5.
the sum for 0 + 5 = 5.

Answer:
The sum for 5 + 0 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 0.
5 + 0 = 5.
the sum for  5 + 0 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-1

Math Talk
MATHEMATICAL PRACTICES

How do you know you showed all the ways? Explain.

Share and Show MATH BOARD

Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 145 Color to show how to make 9. Complete the addition sentences.

Question 3.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 146

Answer:
The sum for 7 + 2 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 7 and 2.
7 + 2 = 9.
the sum for 7 + 2 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-2

Question 4.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 147
9 = _6_ + _3__

Answer:
The sum for 6 + 3 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 3.
6 + 3 = 9.
the sum for 6 + 3 = 9.

Question 5.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 148
9 = _5_ + _4__

Answer:
The sum for 5 + 4 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 4.
5 + 4 = 9.
the sum for 5 + 4 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-3

Question 6.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 149
9 = _4_ + _5__

Answer:
The sum for 4 + 5 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 5.
4 + 5 = 9.
the sum for 4 + 5 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-4

Question 7.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 150
9 = _3_ + _6__

Answer:
The sum for 3 + 6 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 6.
3 + 6 = 9.
the sum for 3 + 6 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-5

Question 8.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 151
9 = __2 + __7_

Answer:
The sum for 2 + 7 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 7.
2 + 7 = 9.
the sum for 2 + 7 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-6

Question 9.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 152
9 = _1_ + _8__

Answer:
The sum for 1 + 8 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 8.
1 + 8 = 9.
the sum for 1 + 8 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-7

Question 10.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 153
9 = _9_ + __0_

Answer:
The sum for 9 + 0 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 9 and 0.
9 + 0 = 9.
the sum for 9 + 0 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-8

On Your Own

MATHEMATICAL PRACTICE
Generalize Use Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 153.1. Color to show ways to make 10. Complete the addition sentences.

Question 11.
Go Math Answer Key Grade 1 Chapter 1 Addition Concepts 154

Question 12.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 155
10 = _1__ + _9__

Answer:
The sum for 1 + 9 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 9.
1 + 9 = 10.
the sum for 1 + 9 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-9

Question 13.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 156
10 = _2__ + _8__

Answer:
The sum for 2 + 8 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 8.
2 + 8 = 10.
the sum for 2 + 8 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-10

Question 14.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 157
10 = _3__ + __7_

Answer:
The sum for 3 + 7 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 7.
3 + 7 = 10.
the sum for 3 + 7 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-11

Question 15.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 158
10 = __4_ + _6__

Answer:
The sum for 4 + 6 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 10.
4 + 6 = 10.
the sum for 4 + 6 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-12

Question 16.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 159
10 = _5__ + _5__

Answer:
The sum for 5 + 5 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 5.
5 + 5 = 10.
the sum for 5 + 5 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-13

Question 17.
THINK SMARTER
Zach has 6 rocks. He places some in a box and some in a bag. Draw two ways he can place the rocks.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 160

Answer:
The sum for 2 + 4 = 6.
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
The sum for 2 + 4 = 6.
The sum for 4 + 2 = 6.

Problem Solving • Applications

Question 18.
THINK SMARTER
I have 8 marbles. Some are red. Some are blue. How many of each could I have? Find and write as many ways as you can.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 161

Answer:
The sum for 0 + 8 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 8.
0 + 8 = 8.
the sum for 0 + 8 = 8.

Answer:
The sum for 1 + 7 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 7.
1 + 7 = 8.
the sum for 1 + 7 = 8.

Answer:
The sum for 2 + 6 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 6.
2 + 6 = 8.
the sum for 2 + 6 = 8.

Answer:
The sum for 1 + 7 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 7.
1 + 7 = 8.
the sum for 1 + 7 = 8.

Answer:
The sum for 6 + 2 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 2.
6 + 2 = 8.
the sum for 6 + 2 = 8.

Answer:
The sum for 3 + 5 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 5.
3 + 5 = 8.
the sum for 3 + 5 = 8.

Answer:
The sum for 4 + 4 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 4.
4 + 4 = 8.
the sum for 4 + 4 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-14

Question 19.
THINK SMARTER
Color two ways to make 7.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 162

Answer:
The sum for 2 + 5 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 5.
2 + 5 = 7.
the sum for 2 + 5 = 7.

Answer:
The sum for 5 + 2 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 2.
5 + 2 = 7.
the sum for 5 + 2 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-15

TAKE HOME ACTIVITY
• Write 6 = 6 + 0. Model the problem with small objects. Ask your child to make 6 another way. Take turns until you and your child model all of the ways to make 6.

Answer:
The sum for 0 + 6 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 6.
0 + 6 = 6.
the sum for 0 + 6 = 6.

Algebra • Put Together Numbers to 10 Homework & Practice 1.7

Use Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 163. Color to show how to make 8. Complete the addition sentences.

Question 1.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 163.1

Question 2.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 164
8 = _1__ + _7__

Answer:
The sum for 1 + 7 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 7.
1 + 7 = 8.
the sum for 1 + 7 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-16

Question 3.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 165
8 = _2__ + _6_

Answer:
The sum for 2 + 6 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 6.
2 + 6 = 8.
the sum for 2 + 6 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-17

Question 4.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 166
8 = _3__ + _5__

Answer:
The sum for 3 + 5 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 5.
3 + 5 = 8.
the sum for 3 + 5 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-18

Question 5.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 167
8 = _4__ + _4__

Answer:
The sum for 4 + 4 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 4.
4 + 4 = 8.
the sum for 4 + 4 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-19

Question 6.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 168
8 = _5__ + __3_

Answer:
The sum for 5 + 3 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 3.
5 + 3 = 8.
the sum for 5 + 3 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-20

Question 7.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 169
8 = __6_ + _8__

Answer:
The sum for 6 + 2 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 2.
6 + 2 = 8.
the sum for 6 + 2 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-21

Question 8.
WRITE Math
Use pictures and numbers to show all the ways to make 3.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 170

Answer:
The sum for 3 + 0 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 0.
3 + 0 = 3.
the sum for 3 + 0 = 3.

Answer:
The sum for 2 + 1 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 1.
2 + 1 = 3.
the sum for 2 + 1 = 3.

Answer:
The sum for 1 + 2 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 2.
1 + 2 = 3.
the sum for 1 + 2 = 3.

Answer:
The sum for 0 + 3 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 3.
0 + 3 = 3.
the sum for 0 + 3 = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-22

Lesson Check

Question 1.
Show three different ways to make 10.
10 = _4_ + __6_ 10 = _6_ + _4_ 10 = _5_ + _5__

Answer:
The sum for 4 + 6 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 10.
4 + 6 = 10.
the sum for 4 + 6 = 10.

Answer:
The sum for 5 + 5 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 5.
5 + 5 = 10.
the sum for 5 + 5 = 10.

Answer:
The sum for 6 + 4 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 4.
6 + 4 = 10.
the sum for 6 + 4 = 10.

Question 2.
Show three different ways to make 6.
6 = _2__ + _4__ 6 = _4_ + _2__ 6 = _3_ + _3__

Answer:
The sum for 2 + 4 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 4.
2 + 4 = 6.
the sum for 2 + 4 = 6.

Answer:
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 2.
4 + 2 = 6.
the sum for 4 + 2 = 6.

Answer:
The sum for 3 + 3 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 3.
3 + 3 = 6.
the sum for 3 + 3 = 6.

Spiral Review

Question 3.
Circle the number sentences that show the same addends in a different order.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 173

Answer:
The sum for 4 + 2 = 6.
The sum for 5 + 1 = 6.
The sum for 2 + 4 = 7.

Explanation:
In the above-given question,
given that,
The sum for 4 + 2 = 6.
The sum for 5 + 1 = 6.
The sum for 2 + 4 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-23

Question 4.
What is the sum for 2 + 0? Write the sum.
2 + 0 = _2_

Answer:
The sum for 2 + 0 = 2.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 0.
2 + 0 = 2.
the sum for 2 + 0 = 2.

Question 5.
Complete the model and the number sentence. 3 rabbits sit in the grass. 4 more rabbits join them. How many rabbits are there now?
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 174
3 + 4 = _7_
_7_ rabbits

Answer:
The number of rabbits = 7.

Explanation:
In the above-given question,
given that,
3 rabbits sit in the grass.
4 more rabbits join them.
3 + 4 = 7.
so the number of rabbits = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.7-24

Lesson 1.8 Addition to 10

Essential Question
Why are some addition facts easy to add?

Listen and Draw

Draw a picture to show the problem. Then write the addends and the sum in two ways.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 175

Answer:
The sum for 1 + 2 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 2.
1 + 2 = 3.
the sum for 1 + 2 = 3.

Answer:
The sum for 0 + 3 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 3.
0 + 3 = 3.
the sum for 0 + 3 = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-1

Math Talk
MATHEMATICAL PRACTICES
Look for Structure Why is the sum the same when you add across or down?

Model and Draw

Write the addition problem.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 176

Answer:
The number of bees = 4.

Explanation:
In the above-given question,
given that,
there are 2 bees and 2 more bees.
2 + 2 = 4.
so the number of bees = 4.

Answer:
The number of flower pots = 7.

Explanation:
In the above-given question,
given that,
there are 3 blue flower pots and 4 more purple flowerpots.
4 + 3 = 7.
so the number of flower pots = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-2

Share and Show MATH BOARD

Write the addition problem.

Question 1.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 177

Answer:
The number of flowers = 7.

Explanation:
In the above-given question,
given that,
there are 3 white flowers and 4 pink flowers.
4 + 3 = 7.
so the number of flowers = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-3

Question 2.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 178

Answer:
The number of bees = 5.

Explanation:
In the above-given question,
given that,
there are 2 bees and 3 more bees.
2 + 3 = 5.
so the number of bees = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-4

Question 3.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 179

Answer:
The number of ants = 6.

Explanation:
In the above-given question,
given that,
there are 5 ants and 1 more ant.
5 + 1 = 6.
so the number of ants = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-5

Question 4.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 180

Answer:
The number of leaves = 10.

Explanation:
In the above-given question,
given that,
there are 8 green leaves and 2 more leaves.
8 + 2 = 10.
so the number of leaves = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-6

On Your Own

MATHEMATICAL PRACTICE
Attend to Precision Write the sum.

Question 5.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 181

Answer:
The sum for 1 + 2 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 2.
1 + 2 = 3.
the sum for 1 + 2 = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-7

Question 6.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 182

Answer:
The sum for 2 + 2 = 4.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 2.
2 + 2 = 4.
the sum for 2 + 2 = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-8

Question 7.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 183

Answer:
The sum for 0 + 3 = 3.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 3.
0 + 3 = 3.
the sum for 0 + 3 = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-9

Question 8.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 184

Answer:
The sum for 1 + 1 = 2.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 1.
1 + 1 = 2.
the sum for 1 + 1 = 2.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-10

Question 9.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 185

Answer:
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 2.
4 + 2 = 6.
the sum for 4 + 2 = 6.

Question 10.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 186

Answer:
The sum for 8 + 1 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 8 and 1.
8 + 1 = 9.
the sum for 8 + 1 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-12

Question 11.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 187

Answer:
The sum for 0 + 4 = 4.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 4.
0 + 4 = 4.
the sum for 0 + 4 = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-13

Question 12.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 188

Answer:
The sum for 7 + 3 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 7 and 3.
7 + 3 = 10.
the sum for 7 + 3 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-14

Question 13.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 189

Answer:
The sum for 4 + 4 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 4.
4 + 4 = 8.
the sum for 4 + 4 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-15

Question 14.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 190

Answer:
The sum for 9 + 1 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 9 and 1.
9 + 1 = 10.
the sum for 9 + 1 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-16

Question 15.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 191

Answer:
The sum for 6 + 3 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 3.
6 + 3 = 9.
the sum for 6 + 3 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-17

Question 16.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 192

Answer:
The sum for 4 + 3 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 3.
4 + 3 = 7.
the sum for 4 + 3 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-18

Question 17.
THINK SMARTER
Ella put 2 marbles in a bag. John put 3 marbles in the bag. How many marbles are in the bag?
_5_ marbles

Answer:
The number of marbles in the bag = 5.

Explanation:
In the above-given question,
given that,
Ella put 2 marbles in a bag and John put 3 marbles in the bag.
2 + 3 = 5.
so the number of marbles in the bag = 5.

Question 18.
THINK SMARTER
Explain. Sam showed how he added 4 1 2. Tell how Sam could find the correct sum.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 193

Answer:
The sum for 4 + 2 + 1 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 2 and 1.
4 + 2 + 1 = 7.
the sum for 4 + 3 = 7.

Problem Solving • Applications

Question 19.
Add. Write the sum. Use the sum and the key to color the flower.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 194

Answer:
The sum for 4 + 3 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 3.
4 + 3 = 7.
the sum for 4 + 3 = 7.

Answer:
The sum for 0 + 9 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 9.
0 + 9 = 9.
the sum for 0 + 9 = 9.

Answer:
The sum for 3 + 7 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 7.
3 + 7 = 10.
the sum for 3 + 7 = 10.

Answer:
The sum for 4 + 5 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 5.
4 + 5 = 9.
the sum for 4 + 5 = 9.

Answer:
The sum for 6 + 4 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 4.
6 + 4 = 10.
the sum for 6 + 4 = 10.

Answer:
The sum for 5 + 3 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 3.
5 + 3 = 8.
the sum for 5 + 3 = 8.

Answer:
The sum for 5 + 5 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 5.
5 + 5 = 10.
the sum for 5 + 5 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-19

Question 20.
GO DEEPER
How many flowers are yellow or purple?
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 195

Answer:
The number of flowers = 7.

Explanation:
In the above-given question,
given that,
there are 3 yellow flowers and 4 purple flowers.
4 + 3 = 7.
so the number of flowers = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-20

Question 21.
THINK SMARTER
Write the sum. Explain how you solved the problem.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 196

Answer:
The sum for 5 + 4 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 4.
5 + 4 = 9.
the sum for 5 + 4 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-21

TAKE HOME ACTIVITY
• Write addition sentences to add across. Then write addition sentences to add down. Have your child find the sum for each.

Addition to 10 Homework & Practice 1.8

Write the sum.

Question 1.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 197

Answer:
The sum for 4 + 1 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 1.
4 + 1 = 5.
the sum for 4 + 1 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-22

Question 2.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 198

Answer:
The sum for 2 + 6 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 6.
2 + 6 = 8.
the sum for 2 + 6 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-23

Question 3.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 199

Answer:
The sum for 4 + 3 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 3.
4 + 3 = 7.
the sum for 4 + 3 = 7.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-24

Question 4.
Go Math 1st Grade Answer Key Chapter 1 Addition Concepts 200

Answer:
The sum for 5 + 1 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 1.
5 + 1 = 6.
the sum for 5 + 1 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-25

Question 5.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 201

Answer:
The sum for 8 + 0 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 8 and 0.
8 + 0 = 8.
the sum for 8 + 0 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-26

Question 6.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 202

Answer:
The sum for 2 + 3 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 3.
2 + 3 = 5.
the sum for 2 + 3 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-27

Question 7.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 203

Answer:
The sum for 0 + 0 = 0.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 0.
0 + 0 = 0.
the sum for 0 + 0 = 0.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-28

Question 8.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 204

Answer:
The sum for 5 + 5 = 10.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 5.
5 + 5 = 10.
the sum for 5 + 5 = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-29

Problem Solving

Add. Write the sum. Use the sum and the key to color the flower.

Question 9.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 205

Answer:
The sum for 4 + 5 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 5.
4 + 5 = 9.
the sum for 4 + 5 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-30

Answer:
The sum for 2 + 5 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 5.
2 + 5 = 7.
the sum for 2 + 5 = 7.

Answer:
The sum for 7 + 1 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 7 and 1.
7 + 1 = 8.
the sum for 7 + 1 = 8.

Question 10.
WRITE Math
Explain how knowing 1 + 7 helps you find the sum for 7 + 1.
___1__+__7_=_8__
_7__+__1_=_8____
__6 __+ 2  =  8__
__5__+_3_=_8___

Answer:
The sum for 1 + 7 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 7.
1 + 7 = 8.
the sum for 1 + 7 = 8.

Answer:
The sum for 7 + 1 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 7 and 1.
7 + 1 = 8.
the sum for 7 + 1 = 8.

Lesson Check

Question 1.
Write the sum.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 206

Answer:
The sum for 5 + 3 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 3.
5 + 3 = 8.
the sum for 5 + 3 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-31

Spiral Review

Question 2.
Show three different ways to make 9.
9 = __4_ + _5__ 9 = _5__ + _4__ 9 = _6__ + __3_

Answer:
The sum for 4 + 5 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 5.
4 + 5 = 9.
the sum for 4 + 5 = 9.

Answer:
The sum for 5 + 4 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 4.
5 + 4 = 9.
the sum for 5 + 4 = 9.

Answer:
The sum for 6 + 3 = 9.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 3.
6 + 3 = 9.
the sum for 6 + 3 = 9.

Question 3.
Complete the number sentence. There are 8 large stones and 2 small stones. How many stones are there?
__10_ stones 8 + 2 = _10__

Answer:
The number of stones = 10.

Explanation:
In the above-given question,
given that,
There are 8 large stones and 2 small stones.
8 + 2 = 10.
so the number of stones = 10.

Question 4.
Complete the number sentence. What is the sum of 2 and 2?
2 + 2 = _4_

Answer:
The sum for 2 + 2 = 4.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 2.
2 + 2 = 4.
the sum for 2 + 2 = 4.

Addition Concepts Chapter Review/Test

Question 1.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 209

Answer:
The number of bears = 3.

Explanation:
In the above-given question,
given that,
there are 2 bears and 1 more bears.
2 + 1 = 3.
so the number of bears = 3.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-32

Question 2.
Write the addition problem.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 210

Answer:
The number of parrots = 5.

Explanation:
In the above-given question,
given that,
there are 3 parrots and 2 more parrots.
3 + 2 = 5.
so the number of parrots = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-33

Question 3.
Color two ways to make 6.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 211

Answer:
The sum for 2 + 4 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 4.
2 + 4 = 6.
the sum for 2 + 4 = 6.

Answer:
The sum for 4 + 2 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 2.
4 + 2 = 6.
the sum for 4 + 2 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-34

Question 4.
Choose all the pictures that show adding zero.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 212

Answer:
The sum for 0 + 6 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 0 and 6.
0 + 6 = 6.
the sum for 0 + 6 = 6.

Answer:
The sum for 6 + 0 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 6 and 0.
6 + 0 = 6.
the sum for 6 + 0 = 6.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-35

Question 5.
Draw lines to match addition sentences with the same addends in a different order.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 213

Answer:
The sum for 8 + 2 = 10.
The sum for 2 + 7 = 9.
The sum for 4 + 5 = 9.

Explanation:
In the above-given question,
given that,
The sum for 8 + 2 = 10.
The sum for 2 + 7 = 9.
The sum for 4 + 5 = 9.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-36

Use 1st Grade Go Math Answer Key Chapter 1 Addition Concepts 214 to show adding to. Draw the 1st Grade Go Math Answer Key Chapter 1 Addition Concepts 214. Write the sum.

Question 6.
2 ducks and 3 more ducks
2 + 3 = _5_

Answer:
The sum for 2 + 3 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 3.
2 + 3 = 5.
the sum for 2 + 3 = 5.

Question 7.
5 lions and 2 more lions
5 + 2 = _7_

Answer:
The sum for 5 + 2 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 2.
5 + 2 = 7.
the sum for 5 + 2 = 7.

Question 8.
Write each addition sentence in the box that shows the sum.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 215

Answer:
The sum for 3 + 4 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 4.
3 + 4 = 7.
the sum for 3 + 4 = 7.

Answer:
The sum for 3 + 3 = 6.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 3.
3 + 3 = 6.
the sum for 3 + 3 = 6.

Answer:
The sum for 5 + 3 = 8.

Explanation:
In the above-given question,
given that,
the sum of numbers 5 and 3.
5 + 3 = 8.
the sum for 5 + 3 = 8.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-37

Question 9.
GO DEEPER
Max has 5 red marbles and 4 blue marbles. Then he gets 1 more. How many marbles does Max have? Draw to show your work.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 215.1
Write how many _10_ marbles

Answer:
The number of marbles Max have = 10.

Explanation:
In the above-given question,
given that,
Max has 5 red marbles and 4 blue marbles.
Then he gets 1 more.
5 + 4 + 1 = 10.
so the number of marbles Max have = 10.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-38

Question 10.
THINK SMARTER
There are 2 people in the house. More people go in the house. Then there are 6 people in the house. How many people go in the house?
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 216
2 + _4_ = 6

Answer:
The number of people go in the house = 4.

Explanation:
In the above-given question,
given that,
there are 2 people in the house.
More people go in the house.
2 + 4 = 6.
so the number of people go in the house = 4.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-39

Question 11.
Katie is drawing dots on cards to show ways to make 7. Draw dots for Katie.
Write addition sentences for two of the cards.
1st Grade Go Math Answer Key Chapter 1 Addition Concepts 219

Answer:
The sum for 1 + 6 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 6.
1 + 6 = 7.
the sum for 1 + 6 = 7.

Answer:
The sum for 2 + 5 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 5.
2 + 5 = 7.
the sum for 2 + 5 = 7.

Answer:
The sum for 3 + 4 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 3 and 4.
3 + 4 = 7.
the sum for 3 + 4 = 7.

Answer:
The sum for 2 + 5 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 2 and 5.
2 + 5 = 7.
the sum for 2 + 5 = 7.

Answer:
The sum for 1 + 6 = 7.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 6.
1 + 6 = 7.
the sum for 1 + 6 = 7.

Question 12.
Draw a model to show that 1 + 4 is the same as 4 + 1. Show how you know.

Answer:
The sum for 1 + 4 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 1 and 4.
1 + 4 = 5.
the sum for 1 + 4 = 5.

Answer:
The sum for 4 + 1 = 5.

Explanation:
In the above-given question,
given that,
the sum of numbers 4 and 1.
4 + 1 = 5.
the sum for 4 + 1 = 5.
Go-Math-Grade-1-Chapter-1-Answer-Key-Addition Concepts-1.8-40

Go Math Grade 1 Answer Key Chapter 9 Measurement

Go Math Grade 1 Answer Key Chapter 9 Measurement

Go Math Grade 1 Chapter 9 Answer Key Measurement

Measurement Show What You Know

Bigger and Smaller
Circle the bigger object.
Question 1.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.1
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Show-What-You-Know-Question-1

Circle the smaller object.
Question 2.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.2
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Show-What-You-Know-Question-2

Compare Length
Circle the longer object.
Draw a line under the shorter object.
Question 3.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Show-What-You-Know-Question-3
Explanation :
Th shorter object is represented with a line under it

Question 4.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Show-What-You-Know-Question-4
Explanation :
Th shorter object is represented with a line under it

Numbers 1 to 10
Write each number in order to 10.
Question 5.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Show-What-You-Know-Question-5
Explanation :
A word or symbol that represents a specific amount or quantity.
The natural numbers starts from 1 , 2 , 3 , 4 …………. and so on .

Measurement Vocabulary Builder

1st Grade Go Math Answer Key Chapter 9 Measurement 1.6
Visualize It
Sort the review words from the box.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.7
Answer :
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Vocabulary-Builder-Visualize It
Explanation :
The length measures start from shorter, short , long and longer. We use long to describe a measure of length. when we see an object of more length than the long object we say it as longer or longest object. similar way
when we see an object of less length than the short object we say it as shorter or shortest object.
numbers are sorted in ascending order from smaller to bigger.

Understand Vocabulary
Complete the sentences with the correct word.
Question 1.
A crayon is ______ than a marker.
Answer:
A crayon is shorter than a marker.
Explanation:
The length of the crayon is shorter when compared to marker based the lengths they are compared as longer or shorter.

Question 2.
A toothbrush is _____ than a paper clip.
Answer:
A toothbrush is longer than a paper clip.
Explanation :
A toothbrush is longer when compared to a paper clip based the lengths they are compared as longer or shorter.

Write the name below the number
Question 3.
1st Grade Go Math Answer Key Chapter 9 Measurement 1.8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Vocabulary-Builder-Understand-Vocabulary-Question-3

Measurement Game Measure UP!

Materials
1st Grade Go Math Answer Key Chapter 9 Measurement 2.1
Play with a partner.

  1. Put 1st Grade Go Math Answer Key Chapter 9 Measurement 2.2 on START.
  2. Spin the 1st Grade Go Math Answer Key Chapter 9 Measurement 2.3. Move your 1st Grade Go Math Answer Key Chapter 9 Measurement 2.4 that many spaces. Take that object.
  3. Your partner spins, moves, and takes that object.
  4. Compare the lengths of the two objects.
  5. The player with the longer object places a 1st Grade Go Math Answer Key Chapter 9 Measurement 2.5 on the space. If both objects are the same length, both players put a 1st Grade Go Math Answer Key Chapter 9 Measurement 2.5 on the board.
  6. Keep playing until one person gets to END. The player with the most 1st Grade Go Math Answer Key Chapter 9 Measurement 2.5 wins.
    1st Grade Go Math Answer Key Chapter 9 Measurement 2.6

Measurement Vocabulary Game

Going to a Weather Station
1st Grade Go Math Answer Key Chapter 9 Measurement 2.7
Materials
1st Grade Go Math Answer Key Chapter 9 Measurement 2.8
How to Play

  1. Each player puts a 1st Grade Go Math Answer Key Chapter 9 Measurement 2.9 on START.
  2. Toss the 1st Grade Go Math Answer Key Chapter 9 Measurement 3.1 to take a turn. Move your 1st Grade Go Math Answer Key Chapter 9 Measurement 2.9 that many spaces.
  3. Follow these directions for the space where you land.
    White Space Read the math word or symbol. Tell its meaning. If you are correct, jump ahead to the next space with the same term.
    Green Space Follow the directions. If there are no directions, stay where you are.
  4. The first player to reach FINISH wins.

Materials
1st Grade Go Math Answer Key Chapter 9 Measurement 2.8
How to Play

  1. Put your 1st Grade Go Math Answer Key Chapter 9 Measurement 2.9 on START.
  2. Toss the 1st Grade Go Math Answer Key Chapter 9 Measurement 3.1 and move 1st Grade Go Math Answer Key Chapter 9 Measurement 2.9 your that many spaces.
  3. If you land on one of these spaces: Blue Space Explain the math word or use it in a sentence. If your answer is correct, jump ahead to the next space with that word. Green Space Follow the directions in the space. If there are no directions, don’t move.
  4. The first player to reach FINISH wins.
    1st Grade Go Math Answer Key Chapter 9 Measurement 3.2
    1st Grade Go Math Answer Key Chapter 9 Measurement 3.3

The Write Way
Reflect
Choose one idea. Draw and write about it.

  • Julia has to measure an object. She does not have a ruler. Tell what Julia could do to solve her problem.
  • Explain why it is important to learn how to tell time.

Lesson 9.1 Order Length

Essential Question How do you order objects by length?

Listen and Draw

Use objects to show the problem.
Draw to show your work.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 1
Answer :

MATHEMATICAL PRACTICES
Compare the straw and the key. Which is longer? Which is shorter?
Answer:

Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-Listen-Draw

Model and Draw

Order three pieces of yarn from shortest to longest. Draw the missing piece of yarn.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 2
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-Model-Draw
Explanation:
The First Yarn is shortest and the Third Yarn is longest . So, the Second yarn should not be shortest nor longest so draw a line which is longer that shortest Yarn and shorter than the longest Yarn .

Share and Show

Draw three lines in order from shortest to longest.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-Share-Show-Question-1-3
Explanation :
The First line is shortest line and the Third line is longest line. So, the Second line should not be shortest nor longest so draw a line which is longer that shortest line and shorter than the longest line .

Draw three lines in order from longest to shortest.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-Share-Show-Question-4-6
Explanation :
The Fourth line is Longest line and the Sixth line is Shortest line. So, the Fifth line should not be shortest nor longest so draw a line which is longer that shortest line and shorter than the longest line .

On Your Own

MATHEMATICAL PRACTICE

Compare Representations
Draw three crayons in order from shortest to longest.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-On-Your-Own-Mathematical-Practice-Question-7-9

Explanation :
The Seventh line is shortest line and the Ninth line is longest line. So, the Eighth line should not be shortest nor longest so draw a line which is longer that shortest line and shorter than the longest line .

Draw three crayons in order from longest to shortest.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-On-Your-Own-Mathematical-Practice-Question-10-12
Explanation :
The Tenth line is Longest line and the Twelveth line is Shortest line. So, the Eleventh line should not be shortest nor longest so draw a line which is longer that shortest line and shorter than the longest line .

Question 13.
THINK SMARTER
Complete each sentence.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 7
Answer:
The Blue Yarn is the shortest yarn .
The Green Yarn and Red Yarn are the same length .

Problem Solving • Applications

Solve.
Question 14.
GO DEEPER
Draw four objects in order from shortest to longest.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-On-Your-Own-Problem-Solving-Applications-Question-14

Question 15.
THINK SMARTER
The string is shorter than the ribbon. The chain is shorter than the ribbon. Circle the longest object.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-On-Your-Own-Problem-Solving-Applications-Question-15
Explanation :
String is shorter than Ribbon
Chain is shorter than Ribbon
That means both string and chain are shorter than Ribbon so, Ribbon is longest object .

Question 16.
THINK SMARTER
Match each word on the left to a drawing on the right.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.1-Order-Length-On-Your-Own-Problem-Solving-Applications-Question-16

TAKE HOME ACTIVITY • Show your child three different lengths of objects, such as three pencils or spoons. Ask him or her to order the objects from shortest to longest.

Order Length Homework & Practice 9.1

Draw three markers in order from longest to shortest.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 11
Answer:
Go-Math-Grade-1-Chapter-9-Order-Length-Order-Length-Homework-Practice-9.1-Question-1-3
Explanation :
The First Marker is Longest Marker and the Third Marker is Shortest Marker . So, the Second Marker should not be shortest nor longest so draw a Marker which is longer that shortest Marker and shorter than the longest Marker .

Problem Solving
Solve
Question 4.
Fred has the shortest toothbrush in the bathroom. Circle Fred’s toothbrush.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 12
Answer:
Go-Math-Grade-1-Chapter-9-Order-Length-Order-Length-Homework-Practice-9.1-Problem-Solving-Question-4
Explanation :
The First Brush is Longest Brush and the Third Brush is Shortest Brush . So, the Second Brush is shortest nor longest .

Question 5.
WRITE
Draw three different lines in order from shortest to longest. Label the shortest line and the longest line.
Answer:
Go-Math-Grade-1-Chapter-9-Order-Length-Order-Length-Homework-Practice-9.1-Question-5
Explanation :
The First Line is Shortest  and the Third Line is the Longest . So, the Second Line is shortest nor longest .

Lesson Check
Question 1.
Draw three crayons in order from longest to shortest.
Answer:
Go-Math-Grade-1-Chapter-9-Order-Length-Order-Length-Homework-Practice-9.1-Lesson-Check-Question-1
Explanation :
The First Crayon is Longest Crayon and the Third Crayon  is Shortest Crayon . So, the Second Crayon should not be shortest nor longest so draw a Crayon which is longer that shortest Crayon and shorter than the longest Crayon .

Question 2.
Draw three paint brushes in order from shortest to longest.
Answer:
Go-Math-Grade-1-Chapter-9-Order-Length-Order-Length-Homework-Practice-9.1-Lesson-Check-Question-2
Explanation :
The First Brush is shortest Brush and the Third Brush is longest Brush . So, the Second Brush should not be shortest nor longest so draw a Brush which is longer that shortest Brush and shorter than the longest Brush .

Spiral Review
Question 3.
Use 1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 13to show 22 two different ways. Draw both ways.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.1 14
Answer:

Lesson 9.2 Indirect Measurement

Essential Question How can you compare lengths of three objects to put them in order?

Listen and Draw

Clue 1: A yellow string is shorter than a blue string.
Clue 2: The blue string is shorter than a red string.
Clue 3: The yellow string is shorter than the red string.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 1

MATHEMATICAL PRACTICES
Represent How did the clues help you draw the strings in the correct order?
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.2-Indirect-Measurement-Listen-Draw-MATHEMATICAL-PRACTICES
Explanation :
From Clue 1 and Clue 3 we know that Yellow string is shorter than blue and red string . that means Yellow string is the shortest strings. From Clue 2 Blue string is shorter than red string that means red string is the longest string.

Share and Show

Use the clues. Write shorter or longer to complete the sentence. Then draw to prove your answer.
Question 1.
Clue 1: A red line is shorter than a blue line.
Clue 2: The blue line is shorter than a purple line.
So, the red line is _______ than the purple line.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 2
Answer:
Go-Math-Grade-1-Chapter-9-Order-Length-Order-Length-Homework-Practice-9.1-Share-Show-Question-1
Explanation :
Clue 1: A red line is shorter than a blue line.
Clue 2: The blue line is shorter than a purple line.
If both red and blue lines are shorter then purple line will be longest line.
So, the red line is shorter than the purple line.

On Your Own

MATHEMATICAL PRACTICE
Analyze Relationships Use the clues. Write shorter or longer to complete the sentence. Then draw to prove your answer.
Question 2.
Clue 1: A green line is shorter than a pink line.
Clue 2: The pink line is shorter than a blue line.
So, the green line is ______ than the blue line.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.2-Indirect-Measurement-On-Own-MATHEMATICAL-PRACTICES-Question-2
Explanation :
Clue 1: A green line is shorter than a pink line.
Clue 2: The pink line is shorter than a blue line.
green line < pink line < blue line then blue line will be longest line
So, the green line is shorter than the blue line.

Question 3.
Clue 1: An orange line is longer than a yellow line.
Clue 2: The yellow line is longer than a red line.
So, the orange line is ______ than the red line.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.2-Indirect-Measurement-On-Own-MATHEMATICAL-PRACTICES-Question-3
Explanation :
Clue 1: An orange line is longer than a yellow line.
Clue 2: The yellow line is longer than a red line.
orange line > yellow line > red line that means orange line is the longest line .
So, the orange line is longer than the red line.

Problem Solving • Applications

Question 4.
THINK SMARTER
The ribbon is longer than the yarn. The yarn is longer than the string. The yarn and the pencil are the same length. Draw the lengths of the objects next to their labels.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.2-Indirect-Measurement-Problem-Solving-Applications-Question-4
Explanation :
Ribbon  > Yarn >String
Yarn = Pencil
So, Ribon is longest

Question 5.
THINK SMARTER
Is the first line longer than the second line? Choose Yes or No.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.2-Indirect-Measurement-Problem-Solving-Applications-Question-5
Explanation :
Both first two figures first lines are longer than second line, Where as in third figure the first line is shorter than the first line .

TAKE HOME ACTIVITY • Show your child the length of one object. Then show your child an object that is longer and an object that is shorter than the first object.

Indirect Measurement Homework & Practice 9.2

Read the clues. Write shorter or longer to complete the sentence. Then draw to prove your answer.
Question 1.
Clue 1: A yarn is longer than a ribbon.
Clue 2: The ribbon is longer than a crayon.
So, the yarn is _______ than the crayon.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.2 7
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Indirect-Measurement-Homework-Practice-9.2-Question-1
Explanation :
Clue 1: A yarn is longer than a ribbon.
Clue 2: The ribbon is longer than a crayon.
Yarn > Ribbon > Crayon that means Yarn is longest
So, the yarn is longer than the crayon.

Problem Solving
Solve. Draw or write to explain.
Question 2.
Megan’s pencil is shorter than Tasha’s pencil. Tasha’s pencil is shorter than Kim’s pencil. Is Megan’s pencil shorter or longer than Kim’s pencil?
________
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Indirect-Measurement-Homework-Practice-9.2-Problem-Solving-Question-2aqSA`
Explanation :
Megan’s pencil < Tasha’s pencil < Kim’s pencil
Kim’s pencil is the longest pencil
Megan’s pencil is shorter than Kim’s pencil

Question 3.
WRITE
Use different colors to draw 3 lines that are different lengths. Then write 3 sentences comparing their lengths.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Indirect-Measurement-Homework-Practice-9.2-Question-3
Explanation :
Clue 1: A yellow string is longer than a red string.
Clue 2: The orange string is longer than a yellow string.
Clue 3: The red string is shorter than the orange string.

Lesson Check
Question 1.
A black line is longer than a gray line. The gray line is longer than a white line. Is the black line shorter or longer than the white line? Draw to prove your answer.
_________
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Indirect-Measurement-Homework-Practice-9.2-Lesson-Check-Question-1
Explanation :
Black line > Gray line >White line
Black line is the longest line .
So, black line is longer than white line .

Spiral Review
Question 2.
What is the sum? Write the number.
42 + 20 = _____
Answer:
42 + 20 = 62
Explanation :
When addend 20 is added to addend 42 we get the sum of 62 .

Lesson 9.3 Use Nonstandard Units to Measure Length

Essential Question How do you measure length using nonstandard units?

Listen and Draw

Use Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1. Draw to show the problem.

MATHEMATICAL PRACTICES
Reasoning How do you draw the boat to be the right length?
Answer:

Model and Draw

You can use Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 to measure length. Write how many.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 2
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Model-Draw
Explanation
For first figure 19.5 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 are used and for second figure 7.5 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 are used .

Share and Show

Use real objects. Use Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 to measure.
Question 1.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Share-Show-Question-1
Explanation :
To measure pencil we require 2 square object .

Question 2.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Share-Show-Question-2
Explanation :
To Measure stapler we require 3 square object .

Question 3.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Share-Show-Question-3
Explanation :
To Measure paint brush we require 3 square object .

Question 4.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Share-Show-Question-4

Explanation :
To Measure scissor we require 2 square object .

On Your Own

Use real objects. Use Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 to measure.
Question 5.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 7.1
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-On-Your-Own-Question-5
Explanation :
To Measure the given figure we require 2 square object .

Question 6.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 7
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-On-Your-Own-Question-6
Explanation :
To Measure the Glue bottle we require 2 square object .

Question 7.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-On-Your-Own-Question-7
Explanation :
To Measure the given figure we require 2 square object .

Question 8.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-On-Your-Own-Question-8
Explanation :
To Measure the Pencil we require 4 square object .

Question 9.
THINK SMARTER
The green yarn is about 2 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long. About how long is the blue yarn?
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Question-9

Explanation :
The Green Yarn is 2Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long where as , The Blue Yarn is 6 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long . as shown in above figure.

Problem Solving • Applications

MATHEMATICAL PRACTICE Evaluate Reasonableness Solve.
Question 10.
Mark measures a real glue stick with Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1. About how long is a glue stick? Circle the answer that is most reasonable.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 11
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Problem-Solving-Applications-Question-10
Explanation :
To Measure glue stick we requires 4 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 .

Question 11.
GO DEEPER
Bo has 4 ribbons. Circle the ribbon that is less than 3 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long but more than 1 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 12
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Problem-Solving-Applications-Question-11
Explanation :
The ribbon that is less than 3 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long but more than 1 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 long means 2 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1
Only the yellow ribbon have 2Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 1 .
So, it is circled  .

Question 12.
THINK SMARTER+
The crayon is about 4 tiles long. Draw tiles below the crayon to show its length.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 13
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.3-Use-Nonstandard-Units-to-Measure-Length-Problem-Solving-Applications-Question-12
Explanation :
To Measure Crayon we require 4 titles.

TAKE HOME ACTIVITY • Give your child paper clips or other small objects that are the same length. Have him or her estimate the lengths of objects around the house and then measure to check.

Use Nonstandard Units to Measure Length Homework & Practice 9.3

Use real objects. Use Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14 to measure.
Question 1.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 15
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Question-1
Explanation :
To measure Math book we require 2 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14

Question 2.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 16
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Question-2
Explanation :
To measure marker we require 4 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14

Question 3.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 17
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Question-3
Explanation :
To measure crayon we require 2 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14

Problem Solving
Solve.
Question 4.
Don measures his desk with Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14. About how long is his desk?
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 18
about _____ Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Problem-Solving-Question-4
Explanation :
To measure Table we require 4 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14

Question 5.
WRITE
Use words or
pictures to explain how to measure an index card using color tiles.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Problem-Solving-Question-4
Explanation :
To measure Index card we require 4 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14

Lesson Check
Question 1.
Use Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14. Kevin measures the ribbon with Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14. About how long is the ribbon?
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 19
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Lesson-Check-Question-1
Explanation :
The length of ribbon is about 4 Go Math Answer Key Grade 1 Chapter 9 Measurement 9.3 14.

Spiral Review
Question 2.
Draw and write to solve. I have 27 red flowers and 19 white flowers. How many flowers do I have?
______ flowers
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Lesson-Check-Question-2
Explanation :
Number of red flowers = 27
Number of white flowers = 19
Total Number of flowers = 27 + 19 = 46

Question 3.
Circle the number that is less.
51 50

Did tens or ones help you decide?
tens ones

Write the numbers.
______ is less than ____
_____< _____
Answer:
50 is less than 51
50 < 51
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Use-Nonstandard-Units-to-Measure-Length-Homework-Practice-9.3-Lesson-Check-Question-3
Explanation :
The  51  and 50 are two digit numbers. first check the ten’s place both the numbers have 5 in the ten’s place. later check digit in the one’s place. the first number have 1 in one’s and second number have 0 in the one’s place. so 1 is greater than 0 so, 51 is greater than 50 .

Lesson 9.4 Make a Nonstandard Measuring Tool

Essential Question How do you use a nonstandard measuring tool to measure length?
Answer :
Standard units are common units of measurement such as centimetres, grams and litres. Non-standard measurement units might include cups, cubes or sweets.
For example: a child might be asked to measure the length of their table using their hand span. They would then record how many hand spans the table was and record this. They might then be asked to measure the length of a book.

Listen and Draw

Circle the name of the child who measured correctly.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 1

MATHEMATICAL PRACTICES
Use Tools Explain how you know who measured correctly.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Listen-Draw
Explanation :
Mateo measures the pencil correctly.
The first paper clip should place from where the measuring starts then, place the second paper clip where the first paper clip ends and so on until the pencil is measured .

Model and Draw

Make your own paper clip measuring tool like the one on the shelf. Measure the length of a door. About how long is the door?
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 2
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Model-Draw
Explanation :
To measure the door we require about 3 paper clips.

Share and Show

Use real objects and the measuring tool you made. Measure. Circle the longest object. Underline the shortest object.
Question 1.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Share-Show-Question-1
Explanation  :
To measure the notice board we require about 2 paper clips.

Question 2.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Share-Show-Question-2
Explanation :
To Measure the above given figure we require about 1 paper clip .

Question 3.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Share-Show-Question-3
Explanation:
To measure the board we require 2 safety clip

Question 4.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Share-Show-Question-4
Explanation :
To measure given window we require about 1 paper clip .

On Your Own

MATHEMATICAL PRACTICE Use Appropriate Tools Use the measuring tool you made. Measure real objects.
Question 5.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 7
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-On-Your-Own-Question-5
Explanation :
To measure given figure we require about 1 paper clip .

Question 6.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-On-Your-Own-Question-6
Explanation :
To measure given figure we require about 1 paper clip .

Question 7.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-On-Your-Own-Question-7

Question 8.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-On-Your-Own-Question-8

Question 9.
GO DEEPER
Cody measured his real lunch box. It is about 10 Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 11 long. About how long is Cody’s real pencil?
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 12
Answer:

Problem Solving • Applications

Solve
Question 10.
THINK SMARTER
Lisa tried to measure the pencil. She thinks the pencil is 5 paper clips long. About how long is the pencil?
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 13
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Problem-Solving-Applications-Question-10
Explanation :
Lisa measured the pencil in a wrong way. The correct measuring of the pencil is shown in the above figure.
To measure the pencil we require about 4 paper clips .

Question 11.
THINK SMARTER
Use the Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 11 below. About how long is the paintbrush?
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 14
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.4-Make-a-Nonstandard-Measuring-Tool-Problem-Solving-Applications-Question-11
Explanation :
The Marking of the paint brush is shown in the above figure to measure how long is the paint brush.
We require about 4 paper clips to measure it .

TAKE HOME ACTIVITY • Have your child measure different objects around the house using a paper clip measuring tool.

Make a Nonstandard Measuring Tool Homework & Practice 9.4

Use the measuring tool you made. Measure real objects.
Question 1.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 15
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-1
Explanation:
To Measure the computer we require about 1 paper clip .

Question 2.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 16
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-2
Explanation:
To Measure the table we require about 1 paper clip .

Question 3.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 17
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-3
Explanation:
To Measure the door we require about 1 paper clip .

Question 4.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 18
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-4
Explanation:
To Measure the Math we require about 1 paper clip .

Question 5.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 19
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-5
Explanation:
To Measure the computer we require about 1 paper clip .

Question 6.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 20
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-6
Explanation:
To Measure the given figure we require about 1 paper clip .

Question 7.
WRITE
Use words or pictures to explain how to measure a table using a paper clip measuring tool.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Question-7
Explanation:
To Measure the table we require about 1 paper clip .

Lesson Check
Question 1.
Use the Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 11 below. Circle the string that is about 4 Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 11 long.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 21
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Lesson-Check-Question-1
Explanation :
The paper clips length is marked with lines that lines length matches the length of string 3 . so, string 3 is about 4 Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 11 long .

Spiral Review
Question 2.
Ty crosses out the number cards that are greater than 38 and less than 34. What numbers are left?
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.4 22
______ and ______
Answer:
35 and 37 are left .
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Make-Nonstandard-Measuring-Tool-Homework-Practice-9.4-Spiral-Review-Question-2
Explanation :
Number greater than 38  are 39 and 40
Number lesser than 34 are 33
Numbers which are left 35 and 37

Question 3.
There are 12 books. 4 books are large. The rest are small. Write a number sentence that shows how to find the number of small books.
______ – ______ = ______
Answer:
Number of books = 12
Number of large books = 4
Number of small books = 12 – 4 = 8 books

Lesson 9.5 Problem Solving • Measure and Compare

Essential Question How can acting it out help you solve measurement problems?

The blue ribbon is about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. The red ribbon is 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. The green ribbon is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the red ribbon. Measure and draw the ribbons in order from shortest to longest.

Show how to solve the problem.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 2
Answer :
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.5-Problem-Solving-Measure-Compare
Explanation :
Blue Ribbon is about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long
Red ribbon is 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long
The green ribbon is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the red ribbon
Green Ribbon = 2 + 1 = 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1long
So, Blue ribbon is longest ribbon.
Blue > green > red ribbons.

HOME CONNECTION • Have your child act out a measurement problem by finding the lengths of 3 objects and ordering them from shortest to longest.

Try Another Problem
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 3

Zack has 3 ribbons. The yellow ribbon is about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. The orange ribbon is 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than the yellow ribbon. The blue ribbon is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the yellow ribbon.
Measure and draw the ribbons in order from longest to shortest.
Question 1.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.5-Problem-Solving-Measure-Compare-Try-Another-Problem-Question-1
Explanations :
Number of ribbons = 3
Yellow ribbon is about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long.
Orange ribbon is 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than the yellow ribbon.
Orange ribbon = 4 – 3 = 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1long.
Blue ribbon is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the yellow ribbon.
Blue ribbon = 4 + 2 = 6 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long.
blue ribbon is the longest ribbon
Blue > Yellow > Orange .

Question 2.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 5
Answer:

Question 3.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 6
Answer:

MATHEMATICAL PRACTICES
Compare How many paper clips shorter is the orange ribbon than the blue ribbon?
Answer:
Blue ribbon is about 6 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1long
Orange is about 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long
Orange Ribbon is less than Blue Ribbon = 6 – 1 = 5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1
5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1shorter is the orange ribbon than the blue ribbon.

Share and Show

Solve. Draw or write to explain.
Question 4.
GO DEEPER
Lisa measures her shoe to be about 5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. Measure and draw an object that is 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than her shoe. Measure and draw an object that is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than her shoe.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.5-Problem-Solving-Measure-Compare-Try-Another-Problem-Share-Show-Question-4
Explanation :
Lisa shoe measure to be = 5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long
An object 1 that is 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than her shoe.
Object 1 = 5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 – 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 = 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1
An object 2 that is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than her shoe.
Object 2 = 5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 + 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 = 7 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1

Question 5.
THINK SMARTER+
Noah measures a marker to be about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long and a pencil to be about 6 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. Draw an object that is 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the marker and 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than the pencil.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 7
Answer:

TAKE HOME ACTIVITY • Have your child explain how he or she solved Exercise 4.

Problem Solving • Measure and Compare Homework & Practice 9.5

The blue string is about 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. The green string is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the blue string. The red string is 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than the blue string. Measure and draw the strings in order from longest to shortest.
Answer :
The blue string is about 3 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long.
The green string is 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer than the blue string.
Green string = 3 + 2 = 5 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1long
The red string is 1 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 shorter than the blue string.
Red string = 3 – 1 = 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1long
Green >Blue > Red string

Question 1.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Problem-Solving-Measure-and-Compare-Homework-Practice-9.5-Question-1

Question 2.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Problem-Solving-Measure-and-Compare-Homework-Practice-9.5-Question-2

Question 3.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Problem-Solving-Measure-and-Compare-Homework-Practice-9.5-Question-3

Problem Solving
Question 4.
Sandy has a ribbon about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long. She cut a new ribbon 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer. Measure and draw the two ribbons.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 11
The new ribbon is about ______ Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Problem-Solving-Measure-and-Compare-Homework-Practice-9.5-Problem-Solving-Question-4
Explanation :
Sandy has a ribbon about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long.
New ribbon 2 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 longer.
New ribbon = 4 + 2 = 6 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 1 long .

Question 5.
WRITE
Measure and draw to show a blue crayon and a green crayon that is about 1 paper clip longer.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Problem-Solving-Measure-and-Compare-Homework-Practice-9.5-Problem-Solving-Question-5
Explanation :
draw to show a blue crayon and a green crayon that is about 1 paper clip longer.

Lesson Check
Question 1.
Mia measures a stapler with her paper clip ruler. About how long is the stapler?
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 12
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Problem-Solving-Measure-and-Compare-Homework-Practice-9.5-Lesson-Check-Question-1
Explanation :
The measurement of the stapler is marked in the above image . so, the stapler is about 7 paper clips.

Spiral Review
Question 2.
What is the unknown number? Write the number.
4 + _____ = 13
Answer:
4 + ______ = 13
_______ = 13 – 4 = 9
So, the Unknown Number is 9

Question 3.
Count by tens. What numbers are missing? Write the numbers.
17, 27, ____, ____, 57, 67
Answer:
Count by tens :
17 , 27 , 37 , 47 , 57 , 67
Explanation :
Count by tens means the every ten’s digit is increased by 1 from the previous ten’s value of the Number .

Measurement Mid-Chapter Checkpoint

Concepts and Skills

Draw three crayons in order from shortest to longest.
Question 1.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 13
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Mid-Chapter-Checkpoint-Concepts-Skills-Question-1
Explanation :
Longest crayon is the Yellow crayon and the shortest crayon is the Green Crayon .

Use Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 14 to measure.
Question 2.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 15
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Mid-Chapter-Checkpoint-Concepts-Skills-Question-2
Explanation :
The Blue Yarn is  about 4 Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 14 long .

Question 3.
THINK SMARTER
Kiley measures a package with her paper clip measuring tool. About how long is the package?
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts 9.5 16
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Mid-Chapter-Checkpoint-Concepts-Skills-Question-3
Explanation :
As per the above figure the Kiley package is about 4 paper clips .

Lesson 9.6 Time to the Hour

Essential Question How do you tell time to the hour on a clock that has only an hour hand?

Listen and Draw

Start at 1. Write the unknown numbers.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 1

MATHEMATICAL PRACTICES
Look for Structure How are a clock face and ordering numbers alike?
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.6-Time-to-the-Hour- Listen-Draw
Explanation :
Starts at 1 .
The Missing Number After 1 or Before 3 will be 2
The Missing Number After 8 or Before 10 will be 9
The Missing Number After 5 or Before 7 will be 6
The Missing Number After 11 will be 12
The clock ordering of numbers will be from left of the clock moving downwards to upwards towards right of the clock .

Share and Show

Look at where the hour hand points. Write the time.
Question 1.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 2
______
Answer:
9 o ‘ Clock
Explanation :
The Hour’s hand is pointing towards 9 so, It is 9 o ‘ Clock

Question 2.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 3
______
Answer:
1 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 1 so, It is 1 o ‘ Clock

Question 3.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 4
______
Answer:
11 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 11 so, It is 11 o ‘ Clock

Question 4.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 5
______
Answer:
6 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 6 so, It is 6 o ‘ Clock

Question 5.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 6
______
Answer:
7 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 7 so, the time is 7 o ‘ Clock

Question 6.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 7
_______
Answer:
5 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 5 so, the time is 5 o ‘ Clock

On Your Own

MATHEMATICAL PRACTICE Make Connections Look at where the hour hand points. Write the time.
Question 7.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 8
______
Answer:
4 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 4 so, the time is 4 o ‘ Clock

Question 8.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 9
_______
Answer:
10 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 10 so, the time is 10 o ‘ Clock

Question 9.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 10
_______
Answer:
6 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 6 so, the time is 6 o ‘ Clock

Question 10.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 11
_______
Answer:
12 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 12 so, the time is 12 o ‘ Clock

Question 11.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 12
_______
Answer:
1 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 1 so, the time is 1 o ‘ Clock

Question 12.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 13
_______
Answer:
3 o ‘ Clock
Explanation :
The Hour’s hand is pointing to 3 so, the time is 3 o ‘ Clock

Question 13.
THINK SMARTER
On Rae’s clock, the hour hand points to the 9. Circle Rae’s clock.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 14
Answer:
9 o ‘ Clock
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.6-Time-to-the-Hour-Share-Show-Question-13
Explanation :
In the first clock the hour hand is pointing 11 so, the time is 11 o ‘ clock
In the Second clock the hour hand is pointing 9 so, the time is 9 o ‘ clock
In the Third clock the hour hand is pointing 11 so, the time is 11 o ‘ clock
So, Second Clock is the right clock .

Problem Solving • Applications

Question 14.
THINK SMARTER
Which time is not the same? Circle it.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 15
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.6-Time-to-the-Hour-Problem-Solving-Applications-Question-14
Explanation :
In the first clock the hour hand is pointing 11 so, the time is 11 o ‘ clock But the time written as 1 : 00 so . it is wrong .
In the Second clock the hour hand is pointing 1 so, the time is 1 o ‘ clock . It is Right .

Question 15.
GO DEEPER
Manny leaves for school at 8 o’clock. Write and draw to show 8 o’clock.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 16
_______
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.6-Time-to-the-Hour-Problem-Solving-Applications-Question-15
Explanation :
The hour hand is pointing 8 so, the time is 8 o ‘ clock

Question 16.
THINK SMARTER
Look at the hour hand. What is the time?
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 17
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.6-Time-to-the-Hour-Problem-Solving-Applications-Question-16
Explanation :
The Hour Hand is pointing 7 . So, the time is 7 : 00 .

TAKE HOME ACTIVITY • Have your child describe what he or she did in this lesson.

Time to the Hour Homework & Practice 9.6

Look at where the hour hand points. Write the time.
Question 1.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 18
______
Answer:
2 o’ clock
Explanation :
The Short Hand or Hour Hand is pointing 2 . So, the time is 2 : 00 .

Question 2.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 19
______
Answer:
9 o’ clock
Explanation :
The Short Hand or Hour Hand is pointing 9 . So, the time is 9 : 00 .

Question 3.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 20
______
Answer:
12 o’ clock
Explanation :
The Short Hand or Hour Hand is pointing 12 0′ clock. So, the time is 12 : 00 .

Problem Solving
Solve.
Question 4.
Which time is not the same? Circle it.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 21
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Time-to-the-Hour-Homework-Practice-9.6-Problem-Solving-Question-4
Explanation :
In the first clock the hour hand is pointing 7 so, the time is 7 o ‘ clock . It is Wrong .
In the Second clock the hour hand is pointing 8 so, the time is 8 o ‘ clock. But the time written as 7 : 00 so . it is wrong .

Question 5.
WRITE
Draw a clock to show where the hour hand points for 11:00.
Answer:
11 o ‘ Clock
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Time-to-the-Hour-Homework-Practice-9.6-Problem-Solving-Question-5
Explanation :
The Hour’s hand is pointing to 11 so, It is 11 o ‘ Clock

Lesson Check
Question 1.
Look at the hour hand. What is the time? Write the time.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 22
Answer:
3 o’ clock
Explanation :
The Short Hand or Hour Hand is pointing 3 . So, the time is 3 : 00 .

Question 2.
Look at the hour hand. What is the time? Write the time.
1st Grade Go Math Answer Key Chapter 9 Measurement 9.6 23
Answer:
9 o’ clock
Explanation :
The Short Hand or Hour Hand is pointing 9 . So, the time is 9 : 00 .

Spiral Review
Question 3.
What is the sum? Write the number.
40 + 30 = _____
Answer:
40 + 30 = 70

Question 4.
What is the sum? Write the number
53 + 30 = ______
Answer:
53 + 30 = 83

Lesson 9.7 Time to the Half Hour

Essential Question How do you tell time to the half hour on a clock that has only an hour hand?
Answer :
To tell time to the half hour on a clock that an hour hand exactly halfway between the two numbers
Example:
To represent five and half an hour would be exactly here halfway between five and six .

Listen and Draw

Circle 4:00, 5:00, or between 4:00 and 5:00 to describe the time shown on the clock.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 1.1
4:00
between 4:00 and 5:00
5:00

Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 1.2
4:00
between 4:00 and 5:00
5:00

Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 1.3
4:00
between 4:00 and 5:00
5:00
Answer :
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.7-Time-to-the-Half-Hour-Listen-Draw
Explanation :
In the first clock the short hand or hour hand points 4 so, the time is 4 o’clock.
In the second clock the short hand or hour hand points exactly half way in between 4 and 5
In the Third clock the short hand or hour hand points 5 so, the time is 5 o’clock.

MATHEMATICAL PRACTICES
Reasoning Use before and after to describe the time shown on the middle clock.
Answer:

Share and Show

Look at where the hour hand points. Write the time.
Question 1.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 2
Answer:
half past 1 o’ clock
Time is 1:30
Explanation:
Half-past 1 is a short way of saying it’s half an hour (30 minutes) after 1:00.
Here the short hand or hour hand points in between 1 and 2.
so the Time is 1:30.

Question 2.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 3
Answer:
half past 4 o’ clock
Time is 4:30
Explanation:
Half-past 4 is a short way of saying it’s half an hour (30 minutes) after 4:00.
Here the short hand or hour hand points in between 4 and 5.
so the Time is 4:30.

Question 3.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 4
Answer:
half past 11 o’ clock
Time is 11:30
Explanation:
Half-past 11 is a short way of saying it’s half an hour (30 minutes) after 11:00.
Here the short hand or hour hand points in between 11 and 12.
so the Time is 11:30.

Question 4.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 5
Answer:
half past 3 o’ clock
Time is 3:30
Explanation:
Half-past 3 is a short way of saying it’s half an hour (30 minutes) after 3:00.
Here the short hand or hour hand points in between 3 and 4.
so the Time is 3:30.

On Your Own

MATHEMATICAL PRACTICE Use Reasoning Look at where the hour hand points. Write the time.
Question 5.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 6
Answer:
half past 5 o’ clock
Time is 5:30
Explanation:
Half-past 5 is a short way of saying it’s half an hour (30 minutes) after 5:00.
Here the short hand or hour hand points in between 5 and 6.
so the Time is 5:30.

Question 6.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 7
Answer:
half past 10 o’ clock
Time is 10:30
Explanation:
Half-past 10 is a short way of saying it’s half an hour (30 minutes) after 10:00.
Here the short hand or hour hand points in between 10 and 11.
so the Time is 10:30.

Question 7.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 8
Answer:
half past 2 o’ clock
Time is 2:30
Explanation:
Half-past 2 is a short way of saying it’s half an hour (30 minutes) after 2:00.
Here the short hand or hour hand points in between 2 and 3.
so the Time is 2:30.

Question 8.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 9
Answer:
half past 9 o’ clock
Time is 9:30
Explanation:
Half-past 9 is a short way of saying it’s half an hour (30 minutes) after 9:00.
Here the short hand or hour hand points in between 9 and 10.
so the Time is 9:30.

Question 9.
THINK SMARTER
Maya starts reading at half past 8. Circle the clock that shows the time Maya starts reading.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 10
Answer:
Maya starts reading at half past 8
Time is 8:30
first clock is right
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.7-Time-to-the-Half-Hour-Question-9
Explanation:
Half-past 8 is a short way of saying it’s half an hour (30 minutes) after 8:00.
Here the short hand or hour hand points in between 8 and 9.
so the Time is 8:30.

Problem Solving • Applications

Question 10.
THINK SMARTER
Tim plays soccer at half past 9:00. He eats lunch at half past 1:00. He sees a movie at half past 2:00.
Look at the clock. Write what Tim does
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 11
Answer:
Tim play Soccer at half past 9: 00 means the time is 9 : 30
Tim eats lunch at half past 1:00. means the time is 1 : 30
Tim sees a movie at half past 2:00 means the time is 2 : 30
From the above clock we notice, Here the short hand or hour hand points in between 2 and 3.
so the Time is 2:30.
half past 2 o’ clock
Explanation:
Half-past 2 is a short way of saying it’s half an hour (30 minutes) after 2:00.
Here the short hand or hour hand points in between 2 and 3.
so the Time is 2:30.

Question 11.
GO DEEPER
Tyra has a piano lesson at 5:00. The lesson ends at half past 5:00. How much time is Tyra at her lesson? Circle your answer.
half hour
hour
Answer:
Tyra piano class is at = 5 : 00
Tyra piano class end at = half past 5:00 = 5 : 30
Time is Tyra at her lesson = 5 : 30 – 5 : 00 = 30 minutes or half an hour .
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.7-Time-to-the-Half-Hour-Problem-Solving-Applications-Question-11

Question 12.
THINK SMARTER
What time is it? Circle the time that makes the sentence true.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 12
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.7-Time-to-the-Half-Hour-Problem-Solving-Applications-Question-12
half past 5 o’ clock
Time is 5:30
Explanation:
Half-past 5 is a short way of saying it’s half an hour (30 minutes) after 5:00.
Here the short hand or hour hand points in between 5 and 6.
so the Time is 5:30.

TAKE HOME ACTIVITY • Say a time, such as half past 10:00. Ask your child to describe where the hour hand points at this time.
Answer :
half past 10 o’ clock
Time is 10:30
Explanation:
Half-past 10 is a short way of saying it’s half an hour (30 minutes) after 10:00.
Here the short hand or hour hand points in between 11 and 10.
so the Time is 10:30.

Time to the Half Hour Homework & Practice 9.7

Look at where the hour hand points. Write the time.
Question 1.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 13
Answer:
half past 10 o’ clock
Time is 10:30
Explanation:
Half-past 10 is a short way of saying it’s half an hour (30 minutes) after 10:00.
Here the short hand or hour hand points in between 11 and 10.
so the Time is 10:30.

Question 2.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 14
Answer:
half past 3 o’ clock
Time is 3:30
Explanation:
Half-past 3 is a short way of saying it’s half an hour (30 minutes) after 3:00.
Here the short hand or hour hand points in between 3 and 4.
so the Time is 3:30.

Question 3.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 15
Answer:
half past 1 o’ clock
Time is 1:30
Explanation:
Half-past 1 is a short way of saying it’s half an hour (30 minutes) after 1:00.
Here the short hand or hour hand points in between 1 and 2.
so the Time is 1:30.

Problem Solving
Solve.
Question 4.
Greg rides his bike at half past 4:00. He eats dinner at half past 6:00. He reads a book at half past 8:00.
Look at the clock. Write what Greg does.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 16
Answer:
Greg rides his bike at half past 4:00 = 4 : 30
Greg eats dinner at half past 6:00. = 6 : 30
Greg reads a book at half past 8:00 = 8 : 30
The Time in the above clock is 6 : 30 so, at half past 6 o’clock Grey is having dinner .
Explanation:
Half-past 6 is a short way of saying it’s half an hour (30 minutes) after 6:00.
Here the short hand or hour hand points in between 6 and 7.
so the Time is 6:30.

Question 5.
WRITE
Draw clocks to show where the hour hand points for 5:00 and half past 5:00.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Time-Half-Hour-Homework-Practice-9.7-Question-5
Explanation :
In First Clock the Hour hand or Short Hand points in between 5 and 6.
so the Time is 5:30.
In Second Clock the hour hand or short hand points to 5
So, the Time is 5 : 00

Lesson Check
Question 1.
Look at the hour hand. What is the time? Write the time.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 17
Answer:
half past 5 o’ clock
Time is 5:30
Explanation:
Half-past 5 is a short way of saying it’s half an hour (30 minutes) after 5:00.
Here the short hand or hour hand points in between 5 and 6.
so the Time is 5:30.

Question 2.
Look at the hour hand. What is the time? Write the time.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 18
Answer:
half past 9 o’ clock
Time is 9:30
Explanation:
Half-past 9 is a short way of saying it’s half an hour (30 minutes) after 9:00.
Here the short hand or hour hand points in between 9 and 10.
so the Time is 9:30.

Spiral Review
Question 3.
What number does the model show? Write the number.
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 19
Answer:
The Above Model shows 10 ten lines and 3 ones. so the number is
10 + 3 = 13

Question 4.
How many tens and ones make this number?
Go Math 1st Grade Answer Key Chapter 9 Measurement 9.7 20
Answer:
14 = 10 + 4
10 tens and 4 ones .

Lesson 9.8 Tell Time to the Hour and Half Hour

Essential Question How are the minute hand and hour hand different for time to the hour and time to the half hour?
Answer :
Telling half hours
Yes, at 1:30 the hour hand points exactly halfway between 1 and 2! The hour hand tells us a lot about the time! … The minute hand spins all the way around the clock every hour. It makes it easier to see if it’s 1:10, or 1:15, or even 1:12

Listen and Draw

Each clock has an hour hand and a minute hand. Use what you know about the hour hand to write the unknown numbers.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 1
It is 1:00.
The hour hand points to the _____.
The minute hand points to the _____.
Answer :
It is 1:00.
The hour hand points to the 1.
The minute hand points to the 12.

Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 2
It is half past 1:00.
The hour hand points between the _____ and the ____.
The minute hand points to the _____.
Answer :
It is half past 1:00.
The hour hand points between the 1 and the 2 .
The minute hand points to the 6 .

MATHEMATICAL PRACTICES
Use Tools Look at the top clock. Explain how you know which is the minute hand.
Answer:
The large hand on a clock that points to the minutes. It goes once around the clock every 60 minutes (one hour). Example: in the clock on the left, the minute hand is just past the “4”, and if you count the little marks from “12” it shows that it is 22 minutes past the hour.

Share and Show

Write the time.
Question 1.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-1
Explanation:
It is half past 1:00.
The hour hand points between the 1 and the 2 .
The minute hand points to the 6 .

Question 2.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-2
Explanation:
It is half past 1:00.
The hour hand points between the 1 and the 2 .
The minute hand points to the 6 .

Question 3.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-3
Explanation :
It is 4:00.
The hour hand points to the 4.
The minute hand points to the 12.

On Your Own

MATHEMATICAL PRACTICE Attend to Precision Write the time.
Question 4.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-4
Explanation:
It is half past 7:00.
The hour hand points between the 7 and the 8 .
The minute hand points to the 6 .

Question 5.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 7
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-5
Explanation :
It is 9:00.
The hour hand points to the 9.
The minute hand points to the 12.

Question 6.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-6
Explanation:
It is half past 8:00.
The hour hand points between the 8 and the 9 .
The minute hand points to the 6 .

Question 7.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-7
Explanation:
It is half past 3:00.
The hour hand points between the 3 and the 4 .
The minute hand points to the 6 .

Question 8.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-8
Explanation :
It is 2:00.
The hour hand points to the 2.
The minute hand points to the 12.

Question 9.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 11
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-9
Explanation :
It is 6:00.
The hour hand points to the 6.
The minute hand points to the 12.

Circle your answer
Question 10.
Sara goes to the park when both the hour hand and the minute hand point to the 12. What time does Sara go to the park?
1:00
12:00
12:30
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-10
Explanation
It is 12:00.
The hour hand points to the 12.
The minute hand points to the 12.

Question 11.
THINK SMARTER
Mel goes to the park when the hour hand points between the 3 and 4 and the minute hand points to the 6. What time does Mel go to the park?
3:00
3:30
6:00
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 12.1
Answer:
Time Mel go to park = 3 : 30
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-11

Explanation:
It is half past 3:00.
The hour hand points between the 3 and the 4 .
The minute hand points to the 6 .

Problem Solving • Applications

Solve.
Question 12.
Linda wakes up at 6:30. Draw to show what time Linda wakes up.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 12
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Problem-Solving-Applications-Question-12
Explanation:
It is half past 6:00.
The hour hand points between the 6 and the 7 .
The minute hand points to the 6 .

Question 13.
David left school at 3:30. Circle the clock that shows 3:30.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 13
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Problem-Solving-Applications-Question-13

Question 14.
GO DEEPER
The hour hand points halfway between the 2 and 3. Draw the hour hand and the minute hand. Write the time.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 14
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Problem-Solving-Applications-Question-14

Question 15.
THINK SMARTER
Choose all the ways that name the time on the clock.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 15
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.8-Tell-Time-to-the-Hour-and-Half-Hour-Problem-Solving-Applications-Question-15

Explanation:
It is half past 7:00.
The hour hand points between the 7 and the 8 .
The minute hand points to the 6 .

TAKE HOME ACTIVITY • At times on the half hour, have your child show you the minute hand and the hour hand on a clock and tell what time it is.

Tell Time to the Hour and Half Hour Homework & Practice 9.8

Write the time.
Question 1.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 16
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Question-1
Explanation :
It is 8:00.
The hour hand points to the 8.
The minute hand points to the 12.

Question 2.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 17
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Question-2
Explanation:
It is half past 1:00.
The hour hand points between the 1 and the 2 .
The minute hand points to the 6 .

Question 3.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 18
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Question-3
Explanation :
It is 5:00.
The hour hand points to the 5.
The minute hand points to the 12.

Question 4.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 19
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Question-4
Explanation:
It is half past 9:00.
The hour hand points between the 10 and the 9 .
The minute hand points to the 6 .

Question 5.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 20
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Question-5
Explanation :
It is 11:00.
The hour hand points to the 11.
The minute hand points to the 12.

Question 6.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 21
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Question-6
Explanation:
It is half past 10:00.
The hour hand points between the 10 and the 11 .
The minute hand points to the 6 .

Problem Solving
Solve.
Question 7.
Lulu walks her dog at 7 o’clock. Bill walks his dog 30 minutes later. Draw to show what time Bill walks his dog. 
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 22
Answer:
Lulu walks her dog at 7 o’clock.
Bill walks his dog 30 minutes later. = 7:00 + 0.30 = 7:30
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Tell-Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.8-Problem-Solving-Question-7

Question 8.
WRITE
Draw a clock to show the time 1:30.
Answer:
Explanation:
It is half past 1:00.
The hour hand points between the 1 and the 2 .
The minute hand points to the 6 .
Explanation:
It is half past 7:00.
The hour hand points between the 7 and the 8 .
The minute hand points to the 6 .

Lesson Check
Question 1.
What time is it? Write the time.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 23
______
Answer:
It is half past 7:00.
Explanation:
It is half past 7:00.
The hour hand points between the 7 and the 8 .
The minute hand points to the 6 .

Question 2.
What time is it? Write the time.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 24
______
Answer:
2:00
Explanation :
It is 2:00.
The hour hand points to the 2.
The minute hand points to the 12.

Spiral Review
Question 3.
What is the sum? Write the number.
48 + 20 = _____
Answer:
48 + 20 = 68
Explanation :
Adding addend 48 and addend 20 we get sum 68 .

Question 4.
How many tens and ones are in the sum? Write the numbers. Write the sum.
Go Math Answer Key Grade 1 Chapter 9 Measurement 9.8 25
____ tens _____ ones
Answer:
67 + 25 = 92
9 tens and 2 ones.

Lesson 9.9 Practice Time to the Hour and Half Hour

Essential Question How do you know whether to draw and write time to the hour or half hour?
Answer :
The short hand tells us the hour. The long hand tells us the minutes. When the long hand is pointing at the 6, it is half of the hour. Write in the time below each clock.

Listen
Circle the clock that matches the problem.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 1
Answer :
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Listen

MATHEMATICAL PRACTICES
Generalize Describe how you know which clock shows 1:30.
Answer:
The fifth clock
Explanation :
It is half past 1:00.
The hour hand points between the 1 and the 2 .
The minute hand points to the 6 .

Share and Show

Use the hour hand to write the time. Draw the minute hand.
Question 1.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 2
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-1
Explanation :
It is 4:00.
The hour hand points to the 4.
The minute hand points to the 12.

Question 2.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-2
Explanation :
It is half past 11:00.
The hour hand points between the 11 and the 12 .
The minute hand points to the 6 .

Question 3.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 4
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-3
Explanation :
It is half past 6:00.
The hour hand points between the 6 and the 7 .
The minute hand points to the 6 .

Question 4.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 5
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-4
Explanation :
It is 7:00.
The hour hand points to the 7.
The minute hand points to the 12.

Question 5.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-5
Explanation :
It is 2:00.
The hour hand points to the 2.
The minute hand points to the 12.

Question 6.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 7
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Share-Show-Question-6
Explanation :
It is half past 3:00.
The hour hand points between the 3 and the 4 .
The minute hand points to the 6 .

On Your Own

MATHEMATICAL PRACTICE Use Diagrams Use the hour hand to write the time. Draw the minute hand.
Question 7.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-7
Explanation :
It is 10:00.
The hour hand points to the 10.
The minute hand points to the 12.

Question 8.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-8
Explanation :
It is half past 12:00.
The hour hand points between the 12 and the 1 .
The minute hand points to the 6 .

Question 9.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-9
Explanation :
It is 5:00.
The hour hand points to the 5.
The minute hand points to the 12.

Question 10.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 11
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-10
Explanation :
It is half past 10:00.
The hour hand points between the 10 and the 11 .
The minute hand points to the 6 .

Question 11.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 12
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-11
Explanation :
It is 12:00.
The hour hand points to the 12.
The minute hand points to the 12.

Question 12.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 13
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-On-Your-Own-Question-12
Explanation :
It is half past 5:00.
The hour hand points between the 5 and the 6 .
The minute hand points to the 6 .

Question 13.
THINK SMARTER
What is the error? Zoey tried to show 6:00. Explain how to change the clock to show 6:00.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 14
Answer:
Zoey shows the time 6 : 00 wrongly.
To change the clock to show 6:00, We, should point the short hand or hand hand to 6 and the long hand should point 12.
Then , the Time will be

Problem Solving • Applications

Solve.
Question 14.
Vince goes to a baseball game at 4:30. Draw to show what time Vince goes to a baseball game.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 15
Answer:
Vince goes to a baseball game at 4:30.
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Problem-Solving-Applications-Question-14
Explanation :
It is half past 4:00.
The hour hand points between the 4 and the 5 .
The minute hand points to the 6 .

Question 15.
GO DEEPER
Brandon has lunch at 1 o’clock. Write and draw to show what time Brandon has lunch.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 16
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Lesson-9.9-Practice-Time-to-the-Hour-and-Half-Hour-Problem-Solving-Applications-Question-15
Brandon has lunch at 1 o’clock.
Explanation :
It is 1:00.
The hour hand points to the 1.
The minute hand points to the 12.

Question 16.
THINK SMARTER
Juan tried to show 8:30. He made a mistake.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 17
What did Juan do wrong? Explain his mistake.
Answer:
juan tired to show 8 : 30 but he showed 7 : 30 as, the our hand is in between 7 and 8.
To show 8 :30. we should mark the half hand exactly in between 8 and 9 .
Explanation :
It is half past 8:00.
The hour hand points between the 8 and the 9 .
The minute hand points to the 6 .

TAKE HOME ACTIVITY • Show your child the time on a clock. Ask him or her what time it will be in 30 minutes

Practice Time to the Hour and Half Hour Homework & Practice 9.9

Use the hour hand to write the time. Draw the minute hand.
Question 1.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 18
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement- Practice Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.9-Question-1
Explanation :
It is 11:00.
The hour hand points to the 11.
The minute hand points to the 12.

Question 2.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 19
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement- Practice Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.9-Question-2
Explanation :
It is half past 8:00.
The hour hand points between the 8 and the 9 .
The minute hand points to the 6 .

Question 3.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 20
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement- Practice Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.9-Question-3
Explanation :
It is half past 2:00.
The hour hand points between the 2 and the 3 .
The minute hand points to the 6 .

Problem Solving
Solve.
Question 4.
Billy played outside for a half hour. Write how many minutes Billy played outside.
_______ minutes
Answer:
Billy played outside for a half hour.
half an hour = 30 minutes .

Question 5.
WRITE
Draw a clock to show a time to the hour. Draw another clock to show a time to the half hour. Write each time.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement- Practice Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.9-Question-5

Lesson Check
Question 1.
Write the time.
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 21
Answer:
It is 11:00.
The hour hand points to the 11.
The minute hand points to the 12.

Spiral Review
Question 2.
What is the difference? Write the number.
80 – 30 = _____
Answer:
80 – 30 = 50

Question 3.
Use . Amy measures the eraser with Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 22. About how long is the eraser?
Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 23Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 22
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement- Practice Time-to-the-Hour-and-Half-Hour-Homework-Practice-9.9-Spiral-Review-Question-3
Explanation :
To Measure eraser we require about 4 Go Math Grade 1 Answer Key Chapter 9 Measurement 9.9 22

Measurement Review/Test

Question 1.
Match each word on the left to a drawing on the right.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 1
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-1

Question 2.
Is the first line shorter than the second line? Choose Yes or No.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 2
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-2

Question 3.
The crayon is about 5 tiles long. Draw tiles below the crayon to show its length.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 3
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-3
The length of the crayon is represented in the above figure

Question 4.
Use the below Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 4. About how long is the Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 5?
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 6
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-4

Question 5.
Measure the
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 7
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-5

Question 6.
Look at the hour hand. What is the time?
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 8
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-6

Question 7.
What time is it? Circle the time that makes the sentence true.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 9
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-7

Question 8.
Choose all the ways that name the time on the clock.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 10
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-8
Explanation :
It is half past 11:00.
The hour hand points between the 11 and the 12 .
The minute hand points to the 6 .

Question 9.
Draw the hand on the clock to show 9:30.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 11
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-9
Explanation :
It is half past 9:00.
The hour hand points between the 9 and the 10 .
The minute hand points to the 6 .

Question 10.
GO DEEPER
Lucy tried to show 5:00. She made a mistake.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 12
Draw hands on the clock to show 5:00.
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 13
What did Lucy do wrong? Explain her mistake.
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-10
Lucy didn’t indicate the hour or short hand in the clock .
Explanation :
It is 5:00.
The hour hand points to the 5.
The minute hand points to the 12.

Question 11.
THINK SMARTER+
Go Math Grade 1 Chapter 9 Answer Key Pdf Measurement Concepts rt 14
Answer:
Go-Math-Grade-1-Chapter-9-Answer-Key-Measurement-Measurement-Review-Test-Question-11
Explanation :
The green line is shorter than red line
The blue line is longer than red line
That means blue line is longest line
blue line > red line > green line

Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers

go-math-grade-4-chapter-4-divide-by-1-digit-numbers-pages-67-93-answer-key

Detailed and Step-by-step explanation of Chapter 5 concepts is provided in this Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers. Assure that you should practice with the help of Go math HMH grade 4 chapter 5 solution key and improve mathematical and logical skills. Learning & practicing the fundamentals of math chapter 5 concepts is very important to score more marks in the exams. So, download online Go Math Grade 4 Solution Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers pdf and overcome all the difficulties in math.

Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers

Consistent practice helps students to gain more knowledge and overcome their weak points. So, grab these Concept-wise Chapter 4 Go math Grade 4 Answer Key pdf and practice regularly for securing good scores in the exams. Some of the topics covered in Go Math Solution Key Grade 4 Homework Practice FL Chapter 4 Divide by 1-Digit Numbers are Estimate Quotients Using Multiples, Remainders, Divide Tens, Hundreds, and Thousands, etc. Solve the questions provided at the end of the page and test your subject knowledge.

Lesson: 1 – Estimate Quotients Using Multiples

Lesson: 2 – Remainders

Lesson: 3 – Interpret the Remainder

Interpret the Remainder

Lesson: 4 – Divide Tens, Hundreds, and Thousands

Lesson: 5 – Estimate Quotients Using Compatible Numbers

Lesson: 6 – Division and the Distributive Property

Lesson: 7 – Divide Using Repeated Subtraction

Lesson: 8 – Divide Using Partial Quotients

Divide Using Partial Quotients

Lesson: 9 – Model Division with Regrouping

Lesson: 10 – Place the First Digit

Lesson: 11 – Divide by 1-Digit Numbers

Lesson: 12 – Problem Solving Multistep Division Problems

Lesson: 13

Common Core – Divide by 1-Digit Numbers – Page No. 69

Estimate Quotients Using Multiples

Find two numbers the quotient is between. Then estimate the quotient.

Question 1.
175 ÷ 6
Think: 6 × 20 = 120 and 6 × 30 = 180. So, 175 ÷ 6 is between 20 and 30. Since 175 is closer to 180 than to 120, the quotient is about 30.
between 20 and 30
about 30

Question 2.
53 ÷ 3
between ____ and ____
about ____

Answer: About 18

Explanation:
17 × 3= 51 and 18 × 3 = 54. 53 is between 51 and 54. 53 ÷ 3 is closest to 17 and 18. So, 53 ÷ 3 is between 17 and 18. So, 53 ÷ 3 will be about 18.

Question 3.
75 ÷ 4
between ____ and ____
about ____

Answer: About 19

Explanation:
18 × 4= 72 and 19 × 4= 76. 75 is between 72 and 76. 75 ÷ 4 is closest to 18 and 19. So, 75÷ 4 is between 18 and 19. So, 75 ÷ 4 will be about 19.

Question 4.
215 ÷ 9
between ____ and ____
about ____

Answer: About 24

Explanation:
23 × 9= 207 and 24 × 9 = 216. 24 is between 207 and 216. 215 ÷ 9 is closest to 23 and 24. So, 215 ÷ 9 is between 23 and 24. So, 215 ÷ 9 will be about 24.

Question 5.
284 ÷ 5
between ____ and ____
about ____

Answer: About 57

Explanation:
56 × 5 = 280 and 57 × 5 = 285. 284 is between 280 and 285. 284 ÷ 5 is closest to 56 and 57. So, 284 ÷ 5 is between 56 and 57. So, 175 ÷ 6 will be about 57.

Question 6.
191 ÷ 3
between ____ and ____
about ____

Answer: About 64

Explanation:
63 × 3 = 189 and 64 × 3 = 192. 191 is between 189 and 192. 191 ÷ 3 is closest to 63 and 64. So, 191 ÷ 3 is between 63 and 64. So, 175 ÷ 6 will be about 64.

Question 7.
100 ÷ 7
between ____ and ____
about ____

Answer: About 14

Explanation:
14 × 7 = 98 and 15 × 7 = 105. 100 is between 98 and 105. 100 ÷ 7 is closest to 14 and 15.
So, 100 ÷ 7 is between 14 and 15. So, 100 ÷ 7 will be about 14.

Question 8.
438 ÷ 7
between ____ and ____
about ____

Answer: About 63

Explanation:
63 × 7 = 441 and 62 × 7 = 434. 438 is between 434 and 441. 438 ÷ 7 is closest to 62 and 63. So, 438 ÷ 7 is between 62 and 63. So, 438 ÷ 7 will be about 63.

Question 9.
103 ÷ 8
between ____ and ____
about ____

Answer: About 13

Explanation:
13 × 8 = 104 and 12 ×8 = 96. 103 is between 96 and 104. 103 ÷ 8 is closest to 12 and 13. So, 103 ÷ 8 is between 12 and 13. So, 103 ÷ 8 will be about 13.

Question 10.
255 ÷ 9
between ____ and ____
about ____

Answer: About 28

Explanation:
28 × 9 = 252 and 29 × 9 = 261. 255 is between 252 and 261. 255 ÷ 9 is closest to 28 and 29.
So, 255 ÷ 9 is between 28 and 29. So, 255 ÷ 9 will be about 28.

Problem Solving

Question 11
Joy collected 287 aluminum cans in 6 hours. About how many cans did she collect per hour?
about ____ cans

Answer: About 48 cans

Explanation:
47 × 6 = 282 and 48 × 6 = 288. 287 is between 282 and 288. 287 ÷ 6 is closest to 47 and 48. So, 287 ÷ 6 is between 47 and 48. So, 287 ÷6 will be about 48.

Question 12.
Paul sold 162 cups of lemonade in 5 hours. About how many cups of lemonade did he sell each hour?
about ____ cups

Answer: About 32 cups of lemonade he sold in each hour

Explanation:
32 × 5 = 160 and 33 × 5 = 165. 162 is between 160 and 165. 162 ÷ 5 is closest to 32 and 33. So, 162 ÷ 5 is between 32 and 33. So, 162 ÷ 5 will be about 32.

Common Core – Divide by 1-Digit Numbers – Page No. 70

Divide by 1-Digit Numbers

Lesson Check

Question 1.
Abby did 121 sit-ups in 8 minutes. Which is the best estimate of the number of sit-ups she did in 1 minute?
Options:
a. about 12
b. about 15
c. about 16
d. about 20

Answer: About 15

Explanation:
15 × 8 = 120 and 16 × 8 = 128. 121 is between 120 and 128. 121 ÷ 8 is closest to 120 and 128. So, 121 ÷ 8 is between 15 and 16.
So, 121 ÷ 8 will be about 15.
Thus the correct answer is option b.

Question 2.
The Garibaldi family drove 400 miles in 7 hours. Which is the best estimate of the number of miles they drove in 1 hour?
Options:
a. about 40 miles
b. about 50 miles
c. about 60 miles
d. about 70 miles

Answer: about 60 miles

Explanation:
Given,
The Garibaldi family drove 400 miles in 7 hours.
57 × 7 = 399 and 58 × 7 = 406.
400 is between 399 and 406. 400 ÷ 7 is closest to 57 and 58.
So, 400 ÷ 7 is between 57 and 58.
So, 400 ÷ 7 will be about 57.
Thus the correct answer is option c.

Spiral Review

Question 3.
Twelve boys collected 16 aluminum cans each. Fifteen girls collected 14 aluminum cans each. How many more cans did the girls collect than the boys?
Options:
a. 8
b. 12
c. 14
d. 18

Answer: 18

Explanation:
Given that,
Twelve boys collected 16 aluminum cans each.
Fifteen girls collected 14 aluminum cans each.
Number of aluminium cans boys had= 12 × 16=192
Number of aluminium cans girls had = 15 × 14=210
Girls collected more cans compared to boys,
Number of more cans collected by girls= 210 – 192=18
Thus the correct answer is option d.

Question 4.
George bought 30 packs of football cards. There were 14 cards in each pack. How many cards did George buy?
Options:
a. 170
b. 320
c. 420
d. 520

Answer: 420

Explanation:
Given,
George bought 30 packs of football cards.
There were 14 cards in each pack.
Number of packs of football cards= 30
Number of cards in each pack= 14
Total number of cards George bought=30×14=420
Thus the correct answer is option c.

Question 5.
Sarah made a necklace using 5 times as many blue beads as white beads. She used a total of 30 beads. How many blue beads did Sarah use?
Options:
a. 5
b. 6
c. 24
d. 25

Answer: 25

Explanation:
Given,
Sarah made a necklace using 5 times as many blue beads as white beads.
She used a total of 30 beads.
Let the number of white beads be x while the number of blue beads are 5x.
Total number of beads in the necklace=30 beads
According to the problem,
5x+x=30
6x=30
x=30/6=5
Therefore the number of blue beads in the necklace are 5x= 5×5=25
Thus the correct answer is option d.

Question 6.
This year, Ms. Webster flew 145,000 miles on business. Last year, she flew 83,125 miles on business. How many more miles did Ms. Webster fly on business this year?
Options:
a. 61,125 miles
b. 61,875 miles
c. 61,985 miles
d. 62,125 miles

Answer: 61,875 miles

Explanation:
Given,
This year, Ms. Webster flew 145,000 miles on business.
Last year, she flew 83,125 miles on business.
Number of miles Ms Webster flew in this year = 145,000 miles
Number of miles Ms Webster flew in the last year = 83,125 miles
Number of more miles travelled by Ms Webster =145,000 – 83,125 = 61,875
Thus the correct answer is option b.

Common Core – Divide by 1-Digit Numbers – Page No. 71

Remainders

Use counters to find the quotient and remainder.

Question 1.
13 ÷ 4
3 r1

Explanation:
Quotient:
A. Use 13 counters to represent the 13 dominoes. Then draw 4 circles to represent the divisor.
B. Share the counters equally among the 4 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 13 ÷ 4
D. Number of circles are equally filled with 4 counters, therefore, the quotient is 3.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 1
For 13 ÷ 4, the quotient is 3 and the remainder is 1, or 3 r1.

Question 2.
24 ÷ 7
_____ R _____

Answer: 3 r3

Explanation:
Quotient:
A. Use 24 counters to represent the 24 dominoes. Then draw 7 circles to represent the divisor.
B. Share the counters equally among the 7 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 24 ÷ 7
D. Number of circles are equally filled with 3 counters, therefore, the quotient is 3
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 3
For 24 ÷ 7, the quotient is 3 and the remainder is 3, or 3 r3.

Question 3.
39 ÷ 5
_____ R _____

Answer: 7 r4

Explanation:
Quotient:
A. Use 39 counters to represent the 39dominoes. Then draw 5 circles to represent the divisor.
B. Share the counters equally among the 5 groups by placing them in the circles.
C. Number of counters formed in each group = quotient 39 ÷ 5
D. Number of circles are equally filled with 7 counters, therefore, the quotient is 7
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 4
For 39 ÷ 5, the quotient is 7 and the remainder is 4, or 7 r4.

Question 4.
36 ÷ 8
_____ R _____

Answer: 4 r4

Explanation:
Quotient:
A. Use 36 counters to represent the 36 dominoes. Then draw 8 circles to represent the divisor.
B. Share the counters equally among the 8 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 36 ÷ 8
D. Number of circles are equally filled with 4 counters, therefore, the quotient is 4
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 4
For 36 ÷ 8, the quotient is 4 and the remainder is 4, or 4 r4.

Question 5.
6)\(\overline { 27 } \)
_____ R _____

Answer: 4 r3

Explanation:
Quotient:
A. Use 27 counters to represent the 27 dominoes. Then draw 6 circles to represent the divisor.
B. Share the counters equally among the 6 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 27 ÷6
D. Number of circles are equally filled with 4 counters, therefore, the quotient is 4
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 3
For 27 ÷ 6, the quotient is 4 and the remainder is 3, or 4 r3.

Question 6.
25 ÷ 9
_____ R _____

Answer: 2 r7

Explanation:
Quotient:
A. Use 25 counters to represent the 25 dominoes. Then draw 9 circles to represent the divisor.
B. Share the counters equally among the 9 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 25 ÷ 9
D. Number of circles are equally filled with 2 counters, therefore, the quotient is 2
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 7
For 25 ÷ 7, the quotient is 2 and the remainder is 7, or 2 r7.

Question 7.
3)\(\overline { 17 } \)
_____ R _____

Answer: 5 r2

Explanation:
Quotient:
A. Use 17 counters to represent the 17 dominoes. Then draw 3 circles to represent the divisor.
B. Share the counters equally among the 3 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 17 ÷ 3
D. Number of circles are equally filled with 5 counters, therefore, the quotient is 5
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 2
For 17 ÷ 3, the quotient is 5 and the remainder is 2, or 5 r2.

Question 8.
26 ÷ 4
_____ R _____

Answer: 6 r2

Explanation:
Quotient:
A. Use 26 counters to represent the 26 dominoes. Then draw 4 circles to represent the divisor.
B. Share the counters equally among the 4 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 26 ÷ 4
D. Number of circles are equally filled with 6 counters, therefore, the quotient is 6
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 2
For 26 ÷ 4, the quotient is 6 and the remainder is 2, or 6 r2.

Divide. Draw a quick picture to help.

Question 9.
14 ÷ 3
_____ R _____

Answer: Quotient: 4 Remainder: 2

Explanation:
Quotient:
A. Use 14 counters to represent the 14 dominoes. Then draw 3 circles to represent the divisor.
B. Share the counters equally among the 3 groups by placing them in the circles.
C. Number of circles filled= quotient of 14 ÷ 3 = 4
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 2

Question 10.
5)\(\overline { 29 } \)
_____ R _____

Answer: Quotient: 5 Remainder: 4

Explanation:
Quotient:
A. Use 29 counters to represent the 29 dominoes. Then draw 5 circles to represent the divisor.
B. Share the counters equally among the 5 groups by placing them in the circles.
C. Number of circles filled= quotient of 29 ÷ 5 = 5
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 4

Problem Solving

Question 11.
What is the quotient and remainder in the division problem modeled below?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 1
_____ R _____

Answer: quotient:6 remainder2

Explanation:
Quotient:
A. Use 20 counters to represent the 20 dominoes. Then draw 3 circles to represent the divisor.
B. Share the counters equally among the 3 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 20 ÷ 3
D. Number of circles are equally filled with 6 counters, therefore, the quotient is 6
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 2
For 20 ÷ 3, the quotient is 6 and the remainder is 2, or 6 r2.

Question 12.
Mark drew the following model and said it represented the problem 21 ÷ 4. Is Mark’s model correct? If so, what is the quotient and remainder? If not, what is the correct quotient and remainder?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 2
_____ : _____ r _____

Answer: 4 r5

Explanation:
Quotient:
A. Use 21 counters to represent the 21 dominoes. Then draw 4 circles to represent the divisor.
B. Share the counters equally among the 4 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 21 ÷ 4
D. Number of circles are equally filled with 4 counters, therefore, the quotient is 4
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 5
For 21 ÷ 4, the quotient is 4 and the remainder is 5, or 4 r5.

Common Core – Divide by 1-Digit Numbers – Page No. 72

Lesson Check

Question 1.
What is the quotient and remainder for 32 ÷ 6?
Options:
a. 4 r3
b. 5 r1
c. 5 r2
d. 6 r1

Answer: 5 r2

Explanation:
Quotient:
A. Use 32 counters to represent the 32 dominoes. Then draw 6 circles to represent the divisor.
B. Share the counters equally among the 5 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 32 ÷ 6
D. Number of circles are equally filled with 5 counters, therefore, the quotient is 5
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 2
For 32 ÷ 6, the quotient is 5 and the remainder is 2, or 5 r2.
Thus the correct answer is option c.

Question 2.
What is the remainder in the division problem modeled below?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 3
Options:
a. 8
b. 4
c. 3
d. 1

Answer: 3

Explanation:
When a number cannot be divided evenly, the amount left over is called the remainder.
The number of counters that are left = remainder = 3
Thus the correct answer is option c.

Spiral Review

Question 3.
Each kit to build a castle contains 235 parts. How many parts are in 4 of the kits?
Options:
a. 1,020
b. 940
c. 920
d. 840

Answer: 940

Explanation:
Number of parts used to build a castle in each kit=235 parts
Number of kits= 4
Total number of parts in 4 of the kits= 235 x 4=940 parts

Thus the correct answer is option b.

Question 4.
In 2010, the population of Alaska was about 710,200. What is this number written in word form?
Options:
a. seven hundred ten thousand, two
b. seven hundred twelve thousand
c. seventy-one thousand, two
d. seven hundred ten thousand, two hundred

Answer: seven hundred ten thousand, two hundred

Explanation:
The ones and tens place of the number are zeroes, so the next place which is hundreds is considered and the value is 7 so, it can be written as seven hundred and in the thousands period, it can be written as seven hundred ten thousand.
Thus the correct answer is option d.

Question 5.
At the theater, one section of seats has 8 rows with 12 seats in each row. In the center of the first 3 rows are 4 broken seats that cannot be used. How many seats can be used in the section?
Options:
a. 84
b. 88
c. 92
d. 96

Answer: 92

Explanation:
Given,
Number of rows at the theatre = 8
Number of seats in each row= 12
Number of seats broken and that cannot be used to sit= 4
Total number of seats that can be used= 12 × 8 – 4 = 96 – 4 = 92
Thus the correct answer is option c.

Question 6.
What partial products are shown by the model below?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 4
Options:
a. 300, 24
b. 300, 600, 40, 60
c. 300, 60, 40, 24
d. 300, 180, 40, 24

Answer: 300, 180, 40, 24

Explanation:
The whole rectangle is divided into four small rectangles the areas of these rectangles are:

Area of yellow rectangle= 30 x 10=300
Area of green rectangle= 4 x 10 = 40
Area of pink rectangle= 6 x 30= 180
Area of blue rectangle= 4 x 6= 24
Thus the correct answer is option d.

Common Core – Divide by 1-Digit Numbers – Page No. 73

Interpret the Remainder

Interpret the remainder to solve.

Question 1.
Hakeem has 100 tomato plants. He wants to plant them in rows of 8. How many full rows will he have?
Think: 100 ÷ 8 is 12 with a remainder of 4. The question asks “how many full rows,” so use only the quotient.
12 full rows

Explanation:
Quotient:
A. Use 100 counters to represent the 100 dominoes. Then draw 8 circles to represent the divisor.
B. Share the counters equally among the 8 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 100 ÷ 8
D. Number of circles are equally filled with 12 counters, therefore, the quotient is 12
Therefore, the tomatoes placed in full rows are 12

Question 2.
A teacher has 27 students in her class. She asks the students to form as many groups of 4 as possible. How many students will not be in a group?
______ students

Answer: 3 students will not be in the group

Explanation:
Total number of students in the class= 27
Number of students who make a group=4
Number of groups that can be made =Quotient of 27÷ 4=6
Number of students who do not come under a group= Remainder of 27÷ 4=3

Question 3.
A sporting goods company can ship 6 footballs in each carton. How many cartons are needed to ship 75 footballs?
______ cartons

Answer: 12 full cartons and 0.5 or 1/2 carton to ship all the 75 footballs

Explanation:
Total number of footballs that should be shipped= 75
Number of footballs placed in each carton = 6
Number of cartons required=Quotient of 75÷ 6=12

Since each carton carries 6 balls, half carton contains 3 balls because 6÷3=2, therefore, each half of the carton contains 3 balls.

Question 4.
A carpenter has a board that is 10 feet long. He wants to make 6 table legs that are all the same length. What is the longest each leg can be?
______ foot

Answer: The length of the longest leg = 4 foot-long

Explanation:
According to the question,
Length of the board the carpenter has= 10 foot long
Number of table legs that are to be made = 6
Length of the 6 table legs are equal
then,
Length of each table leg = Quotient of 10 ÷ 6 =1 foot
Length of the longest table leg = Remainder of 10 ÷ 6 = 4 foot.

Question 5.
Allie wants to arrange her flower garden in 8 equal rows. She buys 60 plants. What is the greatest number of plants she can put in each row?
______ plants

Answer: 7

Explanation:
Total number of plants Allie bought = 60
Number of rows = 8
Number of plants in each row= Quotient of 60 ÷ 8 = 7
Thus the greatest number of plants she can put in a row is 7.

Problem Solving

Question 6.
Joanna has 70 beads. She uses 8 beads for each bracelet. She makes as many bracelets as possible. How many beads will Joanna have left over?
______ beads

Answer: 6 beads

Explanation:
Total number of beads Joanna has= 70 beads
Number beads used for each bracelet= 8 beads
Number of bracelets made with these beads= Quotient of 70÷8= 7 bracelets
then,
The number of beads leftover= Remainder of 70÷8= 6 beads

Question 7.
A teacher wants to give 3 markers to each of her 25 students. Markers come in packages of 8. How many packages of markers will the teacher need?
______ packages

Answer: 10 packages

Explanation:
Total number of students= 25
Number of markers each student got= 3
Total number of markers the teacher needs to distribute= 25 x 3= 75
Number of markers in each package= 8
Number of packages the teacher required= Quotient of 75÷8=9
While the remainder = 3
Therefore the total number of packages = 10

Common Core – Divide by 1-Digit Numbers – Page No. 74

Lesson Check

Question 1.
Marcus sorts his 85 baseball cards into stacks of 9 cards each. How many stacks of 9 cards can Marcus make?
Options:
a. 4
b. 8
c. 9
d. 10

Answer: 10

Explanation:
Total number of baseball cards=85
Number of cards in each stack=9
Number of stacks sorted= Quotient of 85÷9=9
While the remainder=4
So the total number of stacks required= 10
Thus the correct answer is option d.

Question 2.
A minivan can hold up to 7 people. How many minivans are needed to take 45 people to a basketball game?
Options:
a. 3
b. 5
c. 6
d. 7

Answer: 7

Explanation:
A minivan can hold up to 7 people.
Total number of people who want to hire the minivan= 45 people
Number of minivans required= Quotient of 45÷7= 6 vans
While the remainder is 3.
Total number of minivans required to take the people to the baseball game= 7 minivans
Thus the correct answer is option d.

Spiral Review

Question 3.
Mrs. Wilkerson cut some oranges into 20 equal pieces to be shared by 6 friends. How many pieces did each person get and how many pieces were left over?
Options:
a. 2 pieces with 4 pieces left over
b. 3 pieces with 2 pieces left over
c. 3 pieces with 4 pieces left over
d. 4 pieces with 2 pieces left over

Answer: 3 pieces with 2 pieces left over

Explanation:
Total number of orange pieces= 20
Number of friends= 6
Number of pieces each friend got= Quotient of 20÷6= 3 pieces
Number of pieces leftover= Remainder of 20÷6= 2 pieces
Thus the correct answer is option b.

Question 4.
A school bought 32 new desks. Each desk cost $24. Which is the best estimate of how much the school spent on the new desks?
Options:
a. $500
b. $750
c. $1,000
d. $1,200

Answer: $750

Explanation:
Total number of desks= 32
Cost of each desk= $24
Total cost spent on the desks= 32 x 24=$768

So the estimated value can be $768.
Thus the correct answer is option b.

Question 5.
Kris has a box of 8 crayons. Sylvia’s box has 6 times as many crayons as Kris’s box. How many crayons are in Sylvia’s box?
Options:
a. 48
b. 42
c. 36
d. 4

Answer: 48

Explanation:
Number of crayons in Kris box=8
Number of crayons in Sylvia’s box= 6 times as many crayons as Kris’s box= 6 x 8=48
Thus the correct answer is option a.

Question 6.
Yesterday, 1,743 people visited the fair. Today, there are 576 more people at the fair than yesterday. How many people are at the fair today?
Options:
a. 1,167
b. 2,219
c. 2,319
d. 2,367

Answer: 2,319

Explanation:
Number of people in the fair yesterday= 1,743
Number of more people at the fair than yesterday= 576
Total number of people in the fair today=2,319

Thus the correct answer is option c.

Common Core – Divide by 1-Digit Numbers – Page No. 75

Divide Tens, Hundreds, and Thousands

Use basic facts and place value to find the quotient.

Question 1.
3,600 ÷ 4 = 900
Think: 3,600 is 36 hundreds.
Use the basic fact 36 ÷ 4 = 9.
So, 36 hundreds ÷ 4 = 9 hundreds, or 900.

Question 2.
240 ÷ 6 = ______

Answer: 40

Explanation:
STEP 1 Identify the basic fact. 24 ÷ 6
STEP 2 Use place value. 240 = 24 tens
STEP 3 Divide. 24 tens ÷ 6 = 4 tens
240 ÷ 6 = 40

Question 3.
5,400 ÷ 9 = ______

Answer: 600

Explanation:
STEP 1 Identify the basic fact. 54 ÷ 9
STEP 2 Use place value. 5,400 = 54 hundreds
STEP 3 Divide. 54 hundreds ÷ 9 = 6 hundreds
5,400 ÷ 9 = 600

Question 4.
300 ÷ 5 = ______

Answer: 60

Explanation:
STEP 1 Identify the basic fact. 30 ÷ 5
STEP 2 Use place value. 300 = 30 tens
STEP 3 Divide. 30 tens ÷ 5 = 60 tens
300 ÷ 5 = 60

Question 5.
4,800 ÷ 6 = ______

Answer: 800

Explanation:
STEP 1 Identify the basic fact. 48 ÷ 6
STEP 2 Use place value. 4,800 = 48 hundreds
STEP 3 Divide. 48 hundreds ÷ 6 = 80 hundreds
4,800 ÷ 6 = 800

Question 6.
420 ÷ 7 = ______

Answer: 60

Explanation:
STEP 1 Identify the basic fact. 42 ÷ 7
STEP 2 Use place value. 420 = 42 tens
STEP 3 Divide. 42 tens ÷ 7 = 60 tens
420 ÷ 7 = 60

Question 7.
150 ÷ 3 = ______

Answer: 50

Explanation:
STEP 1 Identify the basic fact. 15 ÷ 3
STEP 2 Use place value. 150 = 15 tens
STEP 3 Divide. 15 tens ÷ 3 = 5 tens
150 ÷ 3 = 50

Question 8.
6,300 ÷ 7 = ______

Answer: 900

Explanation:
STEP 1 Identify the basic fact. 63 ÷ 7
STEP 2 Use place value. 6,300 = 63 hundreds
STEP 3 Divide. 63 hundreds ÷ 7 = 9 hundreds
6,300 ÷ 7 = 900

Question 9.
1,200 ÷ 4 = ______

Answer: 300

Explanation:
STEP 1 Identify the basic fact. 12 ÷ 4
STEP 2 Use place value. 1,200 = 12 hundreds
STEP 3 Divide. 12 hundreds ÷ 4 = 3 hundreds
1,200 ÷ 4 = 300

Question 10.
360 ÷ 6 = ______

Answer: 60

Explanation:
STEP 1 Identify the basic fact. 36 ÷ 6
STEP 2 Use place value. 360 = 36 tens
STEP 3 Divide. 36 tens ÷ 6 = 6 tens
360 ÷ 6 = 60

Find the quotient.

Question 11.
28 ÷ 4 = ______
280 ÷ 4 = ______
2,800 ÷ 4 = ______

Answer: 7, 70, 700

Explanation:
Quotient:
A. Use 28 counters to represent the 28 dominoes. Then draw 4 circles to represent the divisor.
B. Share the counters equally among the 4 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 28 ÷ 4
D. Number of circles are equally filled with 7 counters, therefore, the quotient is 7

STEP 1 Identify the basic fact. 28 ÷ 4
STEP 2 Use place value. 280 = 28 tens
STEP 3 Divide. 28 tens ÷ 4 = 7 tens
280 ÷ 4 = 70

STEP 1 Identify the basic fact. 28 ÷ 4
STEP 2 Use place value. 2,800 = 28 hundreds
STEP 3 Divide. 28 hundreds ÷ 4 = 7 hundreds
2,800 ÷ 4 = 700

Question 12.
18 ÷ 3 = ______
180 ÷ 3 = ______
1,800 ÷ 3 = ______

Answer: 6, 60, 600

Explanation:
Quotient:
A. Use 18 counters to represent the 18 dominoes. Then draw 3 circles to represent the divisor.
B. Share the counters equally among the 3 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 18 ÷ 3
D. Number of circles are equally filled with 6 counters, therefore, the quotient is 6

STEP 1 Identify the basic fact. 18 ÷ 3
STEP 2 Use place value. 180 = 18 tens
STEP 3 Divide. 18 tens ÷ 3 = 6 tens
180 ÷ 6 = 60

STEP 1 Identify the basic fact. 18 ÷ 3
STEP 2 Use place value. 1,800 = 18 hundreds
STEP 3 Divide. 18 hundreds ÷ 3 = 6 hundreds
1,800 ÷ 3 = 600

Question 13.
45 ÷ 9 = ______
450 ÷ 9 = ______
4,500 ÷ 9 = ______

Answer: 5, 50, 500

Explanation:
Quotient:
A. Use 45 counters to represent the 45 dominoes. Then draw 9 circles to represent the divisor.
B. Share the counters equally among the 9 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 45 ÷ 9
D. Number of circles are equally filled with 5 counters, therefore, the quotient is 5

STEP 1 Identify the basic fact. 45 ÷ 9
STEP 2 Use place value. 450 = 45 tens
STEP 3 Divide. 45 tens ÷ 9 = 5 tens
450 ÷ 9 = 50

STEP 1 Identify the basic fact. 45 ÷ 9
STEP 2 Use place value. 4,500 = 45 hundreds
STEP 3 Divide. 45 hundred ÷ 9 = 5 hundred
4,500 ÷ 9 = 500

Problem Solving

Question 14.
At an assembly, 180 students sit in 9 equal rows. How many students sit in each row?
______ students

Answer: 20

Explanation:
Total number of students= 180
Number of rows= 9
Number of students in each row= 180 ÷ 9 = 20

Question 15.
Hilary can read 560 words in 7 minutes. How many words can Hilary read in 1 minute?
______ words

Answer: 80

Explanation:
Total number of words Hilary can read in 7 minutes = 560
Number of words Hilary can read in 1 minute= 560 ÷ 7= 80
Therefore Hilary can read 80 words in 1 minute.

Question 16.
A company produces 7,200 gallons of bottled water each day. The company puts 8 one-gallon bottles in each carton. How many cartons are needed to hold all the one-gallon bottles produced in one day?
______ cartons

Answer: 900

Explanation:
Total number of gallons bottled in each day= 7,200
Number of gallons bottled in each carton= 8
Number of cartons used= 7,200 ÷ 8= 900

Question 17.
An airplane flew 2,400 miles in 4 hours. If the plane flew the same number of miles each hour, how many miles did it fly in 1 hour?
______ miles

Answer: 600

Explanation:
Total number of miles flew in 4 hours= 2,400
Number of miles flew in 1 hour= 2,400 ÷ 4 = 600

Common Core – Divide by 1-Digit Numbers – Page No. 76

Lesson Check

Question 1.
A baseball player hits a ball 360 feet to the outfield. It takes the ball 4 seconds to travel this distance. How many feet does the ball travel in 1 second?
Options:
a. 9 feet
b. 40 feet
c. 90 feet
d. 900 feet

Answer: 90 feet

Explanation:
The height to which the player hits a ball=360 feet
Height to which the ball travels in 1 second= 360÷4= 90 feet
The correct answer is option c.

Question 2.
Sebastian rides his bike 2,000 meters in 5 minutes. How many meters does he bike in 1 minute?
Options:
a. 4 meters
b. 40 meters
c. 50 meters
d. 400 meters

Answer: 400 meters

Explanation:
Total number of meters travelled in 5 minutes= 2,000
Number of meters travelled in 1 minute= 2,000÷5= 400
The correct answer is option d.

Spiral Review

Question 3.
A full container of juice holds 64 ounces. How many 7-ounce servings of juice are in a full container?
Options:
a. 1
b. 8
c. 9
d. 10

Answer: 9

Explanation:
A full container of juice holds= 63 ounces
Quantity of servings of juice in one glass=7 ounce
The number of servings of the juice are= 63÷7=9
The correct answer is option c.

Question 4.
Paolo pays $244 for 5 identical calculators. Which is the best estimate of how much Paolo pays for one calculator?
Options:
a. $40
b. $50
c. $60
d. $245

Answer: $50

Explanation:
Amount Paolo pays for the identical calculators = $244
Number of identical calculators=5
The best-estimated value of each identical calculator=$244 ÷ 5is approximately $50.
The correct answer is option b.

Question 5.
A football team paid $28 per jersey. They bought 16 jerseys. How much money did the team spend on jerseys?
Options:
a. $44
b. $196
c. $408
d. $448

Answer: $448

Explanation:
Cost of each jersey=$28
Number of jerseys= 16
Total cost of the jerseys= $28 x 16= $448
The correct answer is option d.

Question 6.
Suzanne bought 50 apples at the apple orchard. She bought 4 times as many red apples as green apples. How many more red apples than green apples did Suzanne buy?
Options:
a. 10
b. 25
c. 30
d. 40

Answer: 40

Explanation:
Let the number of green apples be x and the number of red apples be 4x
4x + x = 50
x = 50 ÷ 5= 10
Number of red balls = 4x = 4 x 10 = 40
The correct answer is option d.

Common Core – Divide by 1-Digit Numbers – Page No. 77

Estimate Quotients Using Compatible Numbers

Use compatible numbers to estimate the quotient.

Question 1.
389 ÷ 4
400 ÷ 4 = 100

Question 2.
358 ÷ 3
_____ ÷ 3 = _____

Answer: 120

Explanation:
What number close to358 is easy to divide by 3?
360 is close to 358. What basic fact can you use?
360 ÷ 3
Choose 360 because it is close to 358 and can easily be divided by 3.
36 ÷3 = 12
360 ÷ 3 =120
358 ÷ 3 is about 120

Question 3.
784 ÷ 8
_____ ÷ 8 = _____

Answer: 100

Explanation:
What number close to 784 is easy to divide by 8?
800 is close to 784. What basic fact can you use?
800 ÷ 8
Choose 800 because it is close to 784 and can easily be divided by 8.
80 ÷ 8 = 10
800 ÷ 8 = 100
784 ÷ 8 is about 100.

Question 4.
179 ÷ 9
_____ ÷ 9 = _____

Answer: 20

Explanation:
What number close to 179 is easy to divide by 9?
180 is close to 179. What basic fact can you use?
180 ÷ 9
Choose 180 because it is close to 179 and can easily be divided by 9.
18 ÷ 9 = 2
180 ÷ 9 = 20
179 ÷ 9 is about 20

Question 5.
315 ÷ 8
_____ ÷ 8 = _____

Answer: 40

Explanation:
What number close to 315 is easy to divide by 8?
320 is close to 315. What basic fact can you use?
320 ÷ 8
Choose 320 because it is close to 315 and can easily be divided by 8.
32 ÷ 8 = 4
320 ÷ 8 =40
315 ÷ 8 is about 40.

Question 6.
2,116 ÷ 7
_____ ÷ 7 = _____

Answer: 300

Explanation:
What number close to 2,116 is easy to divide by 7?
2,100 is close to 2,116. What basic fact can you use?
2,100 ÷ 7
Choose 2,100 because it is close to 2,116 and can easily be divided by 7.
21 ÷ 7= 3
2,100 ÷ 7 = 300
2,116 ÷ 7 is about 300

Question 7.
4,156 ÷ 7
_____ ÷ 7 = _____

Answer: 600

Explanation:
What number close to 4,156 is easy to divide by 7?
4,200 is close to 4,156. What basic fact can you use?
4,200 ÷7
Choose 4,200 because it is close to 4,156 and can easily be divided by 7.
42 ÷ 7 = 6
4,200 ÷ 7 = 600
4,156 ÷ 7 is about 600.

Question 8.
474 ÷ 9
_____ ÷ 9 = _____

Answer: 50

Explanation:
What number close to 474 is easy to divide by 9?
450 is close to 474. What basic fact can you use?
450 ÷ 9
Choose 450 because it is close to 474 and can easily be divided by 9.
45 ÷ 9 = 5
450 ÷ 9 = 50
474 ÷ 9 is about 50.

Use compatible numbers to find two estimates that the quotient is between.

Question 9.
1,624 ÷ 3
_____ ÷ 3 = _____
_____ ÷ 3 = _____

Answer: The quotient is between 500 and 600

Explanation:
What number close to 1,624 is easy to divide by 3?
1,500 is close to 1,624. What basic fact can you use?
1,500 ÷ 3
Choose 1,500 because it is close to 1,624 and can easily be divided by 3.
15 ÷ 3 = 5
1,500 ÷ 3 = 500
1,624 ÷ 3 is about 500

What number close to 1,624 is easy to divide by 3?
1,800 is close to 1,624. What basic fact can you use?
1,800 ÷ 3
Choose 1,800 because it is close to 1,624 and can easily be divided by 3.
18 ÷ 3 = 6
1,800 ÷ 3 = 600
1,624 ÷ 3 is about 600

Question 10.
2,593 ÷ 6
_____ ÷ 6 = _____
_____ ÷ 6 = _____

Answer: The quotient is between 400 and 500

Explanation:
What number close to 2,593 is easy to divide by 6?
2,400 is close to 2,593. What basic fact can you use?
2,400 ÷ 6
Choose 2,400 because it is close to 2,593 and can easily be divided by 6.
24 ÷ 6 = 4
2,400 ÷ 6 = 400
2,593 ÷ 6 is about 400

What number close to 2,593 is easy to divide by 6?
3,000 is close to 2,593. What basic fact can you use?
3000 ÷ 6
Choose 3,000 because it is close to 2,593 and can easily be divided by 6.
30 ÷ 6 = 5
3,000 ÷ 6 = 500
2,593 ÷ 6 is about 500

Question 11.
1,045 ÷ 2
_____ ÷ 2 = _____
_____ ÷ 2 = _____

Answer: The quotient is between 520 and 525

Explanation:
What number close to 1,045 is easy to divide by 2?
1,040 is close to 1,045. What basic fact can you use?
1,040 ÷ 2
Choose 1,040 because it is close to 1,045 and can easily be divided by 2.
1,04 ÷ 2 = 52
1,040 ÷ 2 = 520
1,045 ÷ 2 is about 520

What number close to 1,045 is easy to divide by 2?
1,050 is close to 1,045. What basic fact can you use?
1,050 ÷ 2
Choose 1,050 because it is close to 1,045 and can easily be divided by 2.
1,050 ÷ 2 = 525
1,045 ÷ 2 is about 525

Question 12.
1,754 ÷ 9
_____ ÷ 9 = _____
_____ ÷ 9 = _____

Answer: The quotient is between 195 and 200

Explanation:
What number close to 1,754 is easy to divide by 9?
1,755 is close to 1,754. What basic fact can you use?
1,755 ÷ 9
Choose 1,755 because it is close to 1,754 and can easily be divided by 9.
1,755 ÷ 9 = 195
1,754 ÷ 9 is about 195

What number close to 1,754 is easy to divide by 9?
1,800 is close to 1,754. What basic fact can you use?
1,800 ÷ 9
Choose 1,800 because it is close to 1,754 and can easily be divided by 9.
18 ÷ 9 = 2
1,800 ÷ 9 = 200
1,754 ÷ 9 is about 200

Question 13.
2,363 ÷ 8
_____ ÷ 8 = _____
_____ ÷ 8 = _____

Answer: The quotient is between 295 and 300

Explanation:
What number close to 2,363 is easy to divide by 8?
2,360 is close to 2,363. What basic fact can you use?
2,360 ÷ 8
Choose 2,360 because it is close to 2,363 and can easily be divided by 8.
2,360 ÷ 8 = 295
2,363 ÷ 8 is about 295

What number close to 2,363 is easy to divide by 8?
2,400 is close to 2,363. What basic fact can you use?
2,400 ÷ 8
Choose 2,400 because it is close to 2,363 and can easily be divided by 8.
24 ÷ 8 = 3
2,400 ÷ 8= 300
2,363 ÷ 8 is about 300.

Question 14.
1,649 ÷ 5
_____ ÷ 5 = _____
_____ ÷ 5 = _____

Answer: The quotient is between 329 and 330

Explanation:
What number close to 1,649 is easy to divide by 5?
1,645 is close to 1,649. What basic fact can you use?
1,645 ÷ 5
Choose 1,645 because it is close to 1,649 and can easily be divided by 5.
1,645 ÷ 5 = 329
1,649 ÷ 5 is about 329

What number close to 1,650 is easy to divide by 5?
1,650 is close to 1,649. What basic fact can you use?
1,650 ÷ 5
Choose 1,650 because it is close to 1,649 and can easily be divided by 5.
1,650 ÷ 5 = 330
1,649 ÷ 5 is about 330

Question 15.
5,535 ÷ 7
_____ ÷ 7 = _____
_____ ÷ 7 = _____

Answer: The quotient is between 790 and 791

Explanation:
What number close to 5,535 is easy to divide by 7?
5,530 is close to 5,535. What basic fact can you use?
5,530 ÷ 7
Choose 5,530 because it is close to 5,535 and can easily be divided by 7.
553 ÷ 7 = 79
5,530 ÷ 7 = 790
5,535 ÷ 7 is about 790

What number close to 5,535 is easy to divide by 7?
5,537 is close to 5,535. What basic fact can you use?
5,537 ÷ 7
Choose 5,537 because it is close to 5,535 and can easily be divided by 7.
553 ÷ 7 = 79
5,537 ÷ 7 = 791
5,535 ÷ 7 is about 791

Question 16.
3,640 ÷ 6
_____ ÷ 6 = _____
_____ ÷ 6 = _____

Answer: The quotient is between 606 and 607

Explanation:
What number close to 3,640 is easy to divide by 6?
3,636 is close to 3,640. What basic fact can you use?
3,636 ÷ 6
Choose 3,636 because it is close to 3,640 and can easily be divided by 6.
36 ÷ 6 = 6
3,636 ÷ 6 = 606
3,640 ÷ 6 is about 606

What number close to 3,640 is easy to divide by 6?
3,642 is close to 3,640. What basic fact can you use?
3,642 ÷ 6
Choose 3,642 because it is close to 3,640 and can easily be divided by 6.
3,642 ÷ 6 = 607
3,640 ÷ 6 is about 607

Problem Solving

Question 17.
A CD store sold 3,467 CDs in 7 days. About the same number of CDs were sold each day. About how many CDs did the store sell each day?
about _____ CDs

Answer: 495(approx)

Explanation:
Total number of CDs in the store= 3,467
Number of days= 7
Number of CDs sold on one day= 3,467 ÷ 7=495(approx)

Question 18.
Marcus has 731 books. He puts about the same number of books on each of 9 shelves in his a bookcase. About how many books are on each shelf?
about _____ books

Answer: 81 books(approx)

Explanation:
Total number of books Marcus has= 731
Number of shelves= 9
Number of books on each shelf= 731÷9= 81 (approx)

Common Core – Divide by 1-Digit Numbers – Page No. 78

Lesson Check

Question 1.
Jamal is planting seeds for a garden nursery. He plants 9 seeds in each container. If Jamal has 296 seeds to plant, about how many containers will he use?
Options:
a. about 20
b. about 30
c. about 200
d. about 300

Answer: about 30

Explanation:
Total number of seeds Jamal has= 296
Number of seeds placed in each container= 9
Number of containers Jamal used= 296÷9= 32.8=33 (approx)
Therefore, the number of containers used is about 30
The correct answer is option b.

Question 2.
Winona purchased a set of vintage beads. There are 2,140 beads in the set. If she uses the beads to make bracelets that have 7 beads each, about how many bracelets can she make?
Options:
a. about 30
b. about 140
c. about 300
d. about 14,000

Answer: about 300

Explanation:
Total number of beads Winona has= 2,140
Number of beads in each bracelet= 7
Number of bracelets made= 2,140÷7=305.7=306(approx)
Therefore, the number of bracelets made are about 30
The correct answer is option c.

Spiral Review

Question 3.
A train traveled 360 miles in 6 hours. How many miles per hour did the train travel?
Options:
a. 60 miles per hour
b. 66 miles per hour
c. 70 miles per hour
d. 600 miles per hour

Answer: 60 miles per hour

Explanation:
Total number of miles traveled by train= 360
Time taken by the train to cover 360 miles= 6 hours
Number of miles traveled in each hour= 360÷6=60 miles
The correct answer is option a.

Question 4.
An orchard has 12 rows of pear trees. Each row has 15 pear trees. How many pear trees are there in the orchard?
Options:
a. 170
b. 180
c. 185
d. 190

Answer: 180

Explanation:
Number of rows of pear trees in an orchard= 12
Number of pear trees in each row=15
Total number of pear trees in the orchard= 12 x 15=180
The correct answer is option b.

Question 5.
Megan rounded 366,458 to 370,000. To which place did Megan round the number?
Options:
a. hundred thousands
b. ten thousands
c. thousands
d. hundreds

Answer: ten thousands

Explanation:
The given number is 366,458, the ten thousand place digit has 6 which while rounding off should be changed to the next consecutive number and the digits in the other places should be written as zeroes.
The correct answer is option b.

Question 6.
Mr. Jessup, an airline pilot, flies 1,350 miles a day. How many miles will he fly in 8 days?
Options:
a. 1,358 miles
b. 8,400 miles
c. 10,800 miles
d. 13,508 miles

Answer: 10,800 miles

Explanation:
Number of miles flew by Mr.Jessup in one day= 1,350 miles
Number of days=8
Total number of miles flew by Mr.Jessup in 8 days= 1,350 x 8= 10,800 miles.
The correct answer is option c.

Common Core – Divide by 1-Digit Numbers – Page No. 79

Division and the Distributive Property

Find the quotient.

Question 1.
54 ÷ 3 = ( 30 ÷ 3) + ( 24 ÷ 3)
= 10 + 8
= 18
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 5

Question 2.
81 ÷ 3 = ______

Answer: 27

Explanation:
81 ÷ 3
STEP1 Find the nearest estimates of the number 81
STEP2 We can break the number 81 into 21 + 60
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (60 ÷ 3) + (21 ÷ 3)
STEP5 Add quotients of the above 20 +7= 27

Question 3.
232 ÷ 4 = ______

Answer: 58

Explanation:
232 ÷ 4
STEP1 Find the nearest estimates of the number 232
STEP2 We can break the number 232 into 200 + 32
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (200 ÷ 4) + (32 ÷ 4)
STEP5 Add quotients of the above 50 +8= 58

Question 4.
305 ÷ 5 = ______

Answer: 61

Explanation:
305 ÷ 5
STEP1 Find the nearest estimates of the number 305
STEP2 We can break the number 305 into 300 + 5
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (300 ÷ 5) + (5 ÷ 5)
STEP5 Add quotients of the above 60 +1= 61

Question 5.
246 ÷ 6 = ______

Answer: 41

Explanation:
246 ÷ 6
STEP1 Find the nearest estimates of the number 246
STEP2 We can break the number 246 into 240 + 6
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (240 ÷ 6) + (6 ÷ 6)
STEP5 Add quotients of the above 40 +1= 41

Question 6.
69 ÷ 3 = ______

Answer: 23

Explanation:
69 ÷ 3
STEP1 Find the nearest estimates of the number 69
STEP2 We can break the number 69 into 60 + 9
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (60 ÷ 3) + (9 ÷ 3)
STEP5 Add quotients of the above 20 +3= 23

Question 7.
477 ÷ 9 = ______

Answer: 53

Explanation:
477 ÷ 9
STEP1 Find the nearest estimates of the number 477
STEP2 We can break the number 477 into 450 + 27
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (450 ÷ 9) + (27 ÷ 9)
STEP5 Add quotients of the above 50 +3= 53

Question 8.
224 ÷ 7 = ______

Answer: 32

Explanation:
224 ÷ 7
STEP1 Find the nearest estimates of the number 224
STEP2 We can break the number 224 into 210 + 14
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (210 ÷ 7) + (14 ÷ 7)
STEP5 Add quotients of the above 30 +2= 32

Question 9.
72 ÷ 4 = ______

Answer: 18

Explanation:
72 ÷ 4
STEP1 Find the nearest estimates of the number 72
STEP2 We can break the number 72 into 40 + 32
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (40 ÷ 4) + (32 ÷ 4)
STEP5 Add quotients of the above 10 +8= 18

Question 10.
315 ÷ 3 = ______

Answer: 105

Explanation:
315 ÷ 3
STEP1 Find the nearest estimates of the number 315
STEP2 We can break the number 315 into 300 + 15
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (300 ÷ 3) + (15 ÷3)
STEP5 Add quotients of the above 100 +5= 105

Problem Solving

Question 11.
Cecily picked 219 apples. She divided the apples equally into 3 baskets. How many apples are in each basket?
______ apples

Answer: 73 apples

Explanation:
The total number of apples Cecily picked= 219 apples
Number of parts into which she wanted to divide the apples= 3
Number of apples in each part = Quotient of 147 ÷ 7
STEP1 Find the nearest estimates of the number 219
STEP2 We can break the number 219 into 210 + 9
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (210 ÷ 3) + (9 ÷ 3)
STEP5 Add quotients of the above 70 +3= 73

Question 12.
Jordan has 260 basketball cards. He divides them into 4 equal groups. How many cards are in each group?
______ cards

Answer: 65 cards

Explanation:
The total number of basketball cards Jordan has= 260 basketball cards
Number of parts into which he wanted to divide the cards= 4
Number of apples in each part = Quotient of 260 ÷ 4
STEP1 Find the nearest estimates of the number 260
STEP2 We can break the number 260 into 240 + 20
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (240 ÷ 4) + (20 ÷ 4)
STEP5 Add quotients of the above 60 +5= 65

Question 13.
The Wilsons drove 324 miles in 6 hours. If they drove the same number of miles each hour, how many miles did they drive in 1 hour?
______ miles

Answer: 54 miles

Explanation:
The total number of miles drove by Wilson= 324 miles
Number of hours he drove = 6
Number of miles drove in each hour = Quotient of 324 ÷ 6
STEP1 Find the nearest estimates of the number 324
STEP2 We can break the number 324 into 300 + 24
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (300 ÷ 6) + (24 ÷ 6)
STEP5 Add quotients of the above 50 +4= 54

Question 14.
Phil has 189 stamps to put into his stamp album. He puts the same number of stamps on each of 9 pages. How many stamps does Phil put on each page?
______ stamps

Answer: 21 stamps

Explanation:
The total number of stamps Phil has= 189 stamps
Number of pages= 9
Number of stamps put on each page = Quotient of 189 ÷ 9
STEP1 Find the nearest estimates of the number 189
STEP2 We can break the number 189 into 180 + 9
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (180 ÷ 9) + (9 ÷ 9)
STEP5 Add quotients of the above 20 +1= 21

Common Core – Divide by 1-Digit Numbers – Page No. 80

Lesson Check

Question 1.
A landscaping company planted 176 trees in 8 equal rows in the new park. How many trees did the company plant in each row?
Options:
a. 18
b. 20
c. 22
d. 24

Answer: 22

Explanation:
The total number of trees in the landscaping= 176 trees
Number of rows= 8
Number of trees in each row = Quotient of 176 ÷ 8
STEP1 Find the nearest estimates of the number 176
STEP2 We can break the number 176 into 160 + 16
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (160 ÷ 8) + (16 ÷ 8)
STEP5 Add quotients of the above 20 +2= 22

Question 2.
Arnold can do 65 pushups in 5 minutes. How many pushups can he do in 1 minute?
Options:
a. 11
b. 13
c. 15
d. 17

Answer: 13

Explanation:
The total number of pushups done by Arnold = 65
Number of minutes spent on pushups= 5
Number of pushups done in each minute = Quotient of 65 ÷ 5
STEP1 Find the nearest estimates of the number 65
STEP2 We can break the number 65 into 60 + 5
STEP3 We must divide the two parts of the number (dividend) with the divisor.
STEP4 (60 ÷ 5) + (5 ÷ 5)
STEP5 Add quotients of the above 12 +1= 13

Spiral Review

Question 3.
Last Saturday, there were 1,486 people at the Cineplex. There were about the same number of people in each of the 6 theaters. Which is the best estimate of the number of people in each theater?
Options:
a. between 20 and 30
b. between 80 and 90
c. between 100 and 200
d. between 200 and 300

Answer: between 200 and 300

Explanation:
Total number of people at the Cineplex= 1,486 people
Number of theatres = 6
Number of people at each theatre= estimate of the number of people 1,486 ÷ 6

What number close to 1,486 is easy to divide by 6?
1,488 is close to 1,486. What basic fact can you use?
1,488 ÷ 6
Choose 1,488 because it is close to 1,486 and can easily be divided by 6.
1,488 ÷ 6 = 248
1,486 ÷ 6 is about 248

What number close to 1,486 is easy to divide by 6?
1,482 is close to 1,486 . What basic fact can you use?
1,482 ÷ 6
Choose 1,482 because it is close to 1,486 and can easily be divided by 6.
1,482 ÷ 6 = 247
1,486 ÷ 6 is about 247

Question 4.
Nancy walked 50 minutes each day for 4 days last week. Gillian walked 35 minutes each day for 6 days last week. Which statement is true?
Options:
a. Gillian walked 10 minutes more than Nancy.
b. Gillian walked 20 minutes more than Nancy.
c. Nancy walked 10 minutes more than Gillian.
d. Nancy walked 15 minutes more than Gillian.

Answer: Nancy walked 15 minutes more than Gillian.

Explanation:
Time walked by Nancy= 50 minutes
Time walked by Gillian= 35 minutes
Nancy walked more time compared to Gillian
50-35=15 minutes
Therefore, Nancy walked 15 minutes more than Gillian.

Question 5.
Three boys share 28 toy cars equally. Which best describes how the cars are shared?
Options:
a. Each gets 3 cars with 1 left over.
b. Each gets 8 cars with 2 left over.
c. Each gets 9 cars with 1 left over.
d. Each gets 10 cars with 2 left over.

Answer: Each gets 9 cars with 1 left over.

Explanation:
Total number of toys three boys have= 28
Number of toys each boy got= 28 ÷3=9.33
Therefore we can say that each gets 9 cars with 1 leftover.

Question 6.
An airplane flies at a speed of 474 miles per hour. How many miles does the plane fly in 5 hours?
Options:
a. 2,070 miles
b. 2,140 miles
c. 2,370 miles
d. 2,730 miles

Answer: 2,370 miles

Explanation:
Number of miles flew by airplane in one hour= 474
Number of hours the airplane flew= 5 hours
Total number of miles flew in 5 hours= 474 x 5= 2,370 miles

Common Core – Divide by 1-Digit Numbers – Page No. 81

Divide Using Repeated Subtraction

Use repeated subtraction to divide.

Question 1.
42 ÷ 3 = 14
3)\(\overline { 42 } \)
-30 ← 10 × 3 | 10
——-
12
-12 ← 4 × 3 | +4
——-             ———
0                     14

Question 2.
72 ÷ 4 = ______

Answer: 18

Explanation:
A. Begin with 72 counters. Subtract 4 counters.
B. Subtract 4 counters from 72 and repeat the processes until the remainder cannot be subtracted from the divisor.
C. Record the number of counters left and the number of times you subtracted.
D. The number of times you subtracted is the quotient is 18

Question 3.
93 ÷ 3 = ______

Answer: 31

Explanation:
A. Begin with 93 counters. Subtract 3 counters.
B. Subtract 3 counters from 93 and repeat the processes until the remainder cannot be subtracted from the divisor.
C. Record the number of counters left and the number of times you subtracted.
D. The number of times you subtracted is the quotient is 31

Question 4.
35 ÷ 4 = ______ r ______

Answer: 8r3

Explanation:
Quotient:
A. Use 35 counters to represent the 35 dominoes. Then draw 4 circles to represent the divisor.
B. Share the counters equally among the 4 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 35 ÷ 4
D. Number of circles are equally filled with 4 counters, therefore, the quotient is 8
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 3
For 35 ÷ 4, the quotient is 8 and the remainder is 3, or 8 r3.

Question 5.
93 ÷ 10 = ______ r ______

Answer: 9r3

Explanation:
Quotient:
A. Use 93 counters to represent the 93 dominoes. Then draw 10 circles to represent the divisor.
B. Share the counters equally among the 10 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 93 ÷ 10
D. Number of circles are equally filled with 10 counters, therefore, the quotient is 9
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 3
For 93 ÷ 10, the quotient is 9 and the remainder is 3, or 9 r3.

Question 6.
86 ÷ 9 = ______ r ______

Answer: 9r5

Explanation:
Quotient:
A. Use 86 counters to represent the 86 dominoes. Then draw 9 circles to represent the divisor.
B. Share the counters equally among the 9 groups by placing them in the circles.
C. Number of counters formed in each group = quotient of 86 ÷ 9
D. Number of circles are equally filled with 9 counters, therefore, the quotient is 9
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 5
For 86 ÷ 9, the quotient is 9 and the remainder is 5, or 9 r5.

Draw a number line to divide.

Question 7.
70 ÷ 5 = ______

Answer: 14

Explanation:
A. Draw a number line with 5 as each interval.
B. Draw up to 70 and count the intervals, it gives the quotient.
C. The quotient is 14

Problem Solving

Question 8.
Gretchen has 48 small shells. She uses 2 shells to make one pair of earrings. How many pairs of earrings can she make?
______ pairs

Answer: 24 pairs

Explanation:
Total number of small shells= 48
Number of shells used to make one pair of earrings = 2
Number of pair of earrings made = 48 ÷ 2 =24

Question 9.
James wants to purchase a telescope for $54. If he saves $3 per week, in how many weeks will he have saved enough to purchase the telescope?
______ weeks

Answer: $18

Explanation:
Cost of the telescope=$54
Amount saved each week = $3
Number of weeks he has to save the money to purchase the telescope = $54 ÷ $3 = $18

Common Core – Divide by 1-Digit Numbers – Page No. 82

Lesson Check

Question 1.
Randall collects postcards that his friends send him when they travel. He can put 6 cards on one scrapbook page. How many pages does Randall need to fit 42 postcards?
Options:
a. 3
b. 4
c. 6
d. 7

Answer: 7

Explanation:
Total number of postcards Randall has = 42 postcards
Number of postcards on one scrapbook page = 6 cards
Number of pages needed to fit the postcards = 42 ÷ 6=7
The correct answer is option d.

Question 2.
Ari stocks shelves at a grocery store. He puts 35 cans of juice on each shelf. The shelf has 4 equal rows and another row with only 3 cans. How many cans are in each of the equal rows?
Options:
a. 6
b. 7
c. 8
d. 9

Answer: 8

Explanation:
Total number of cans of juice on each shelf = 35
Number of rows = 4
Number of cans on the other shelf = 3
Number of cans placed on the first shelf = 35 – 3 = 32
Number of juice cans in the first row = 32 ÷ 4 = 8 cans
The correct answer is option c.

Spiral Review

Question 3.
Fiona sorted her CDs into separate bins. She placed 4 CDs in each bin. If she has 160 CDs, how many bins did she fill?
Options:
a. 4
b. 16
c. 40
d. 156

Answer: 40

Explanation:
Total number of CD’s in Fiona has = 160 CD’s
Number of CD’s placed in each bin = 4
Number of bins required to place the CD’s = 160 ÷ 4 = 40
The correct answer is option c.

Question 4.
Eamon is arranging 39 books on 3 shelves. If he puts the same number of books on each shelf, how many books will there be on each shelf?
Options:
a. 11
b. 12
c. 13
d. 14

Answer: 13

Explanation:
Total number of books Eamon has = 39 books
Number of shelves = 3
Number of books in each shelf = 39 ÷ 3 = 13
The correct answer is option c.

Question 5.
A newborn boa constrictor measures 18 inches long. An adult boa constrictor measures 9 times the length of the newborn plus 2 inches. How long is the adult?
Options:
a. 142 inches
b. 162 inches
c. 164 inches
d. 172 inches

Answer: 164 inches

Explanation:
Length of newborn boa constrictor = 18 inches
Length of an adult boa constrictor = 9 x Length of newborn boa constrictor = 9 x 18 = 162
Total length of an adult boa constrictor = 162 + 2 = 164 inches
The correct answer is option c.

Question 6.
Madison has 6 rolls of coins. Each roll has 20 coins. How many coins does Madison have in all?
Options:
a. 110
b. 120
c. 125
d. 130

Answer: 120

Explanation:
Number of rolls of coins = 6
Number of coins in each roll = 20
Total number of coins Madison has = 20 x 6 = 120
The correct answer is option b.

Common Core – Divide by 1-Digit Numbers – Page No. 83

Divide Using Partial Quotients

Divide. Use partial quotients.

Question 1.
8)\(\overline { 184 } \)
-80 ← 10 × 8 10
——-
104
-80 ← 10 × 8 +10
-24
-24 ← 3 × 8  +3
——-              ———
0                      23

Question 2.
6)\(\overline { 258 } \)
______

Answer: 43

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 40 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 6.
STEP 2
Subtract smaller multiples, such as 3 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 40 x 6 = 240 : 258 – 240 = 18
3 x 6 = 18 : 18 – 18 = 0
Therefore the quotient is 43 ( 40 + 3)

Question 3.
5)\(\overline { 630 } \)
______

Answer: 126

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 5.
STEP 2
Subtract smaller multiples, such as 20 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 100 x 5 = 500 : 630 – 500 = 130
5 x 20 = 100 : 130 – 100 = 30 : 5 x 6 = 30 : 30 – 30 = 0
Therefore the quotient is 126 ( 100 + 20 + 6)

Divide. Use rectangular models to record the partial quotients.

Question 4.
246 ÷ 3 = ____

Answer: 82

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 80 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 3.
STEP 2
Subtract smaller multiples, such as 80 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 80 x 3 = 240 : 246 – 240 = 6
3 x 2 = 6 : 6 – 6 = 0
Therefore the quotient is 82 ( 80 + 2)
The rectangle models are given below :

Question 5.
126 ÷ 2 = ____

Answer: 63

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 60 times the divisor.
Continue subtracting until the remaining number is less than the multiple,2.
STEP 2
Subtract smaller multiples, such as 60 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 60 x 2 = 120 : 126 – 120 = 6
2 x 3 = 6 : 6 – 6 = 0
Therefore the quotient is 63 ( 60 +3)
The rectangle models are given below :

Question 6.
605 ÷ 5 = ____

Answer: 121

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 5.
STEP 2
Subtract smaller multiples, such as 20 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 100 x 5 = 500 : 605 – 500 = 105
5 x 20 = 100 : 105 – 100 = 5 : 5 x 1 = 5 : 5 – 5 = 0
Therefore the quotient is 121 ( 100 + 20 + 1)
The rectangle models are given below :

Divide. Use either way to record the partial quotients.

Question 7.
492 ÷ 3 = ____

Answer: 164

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 3.
STEP 2
Subtract smaller multiples, such as 50 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 100 x 3 = 300 : 492 – 300 = 192
50 x 3 = 150 : 192 – 150 = 42 : 3 x 14 = 42 : 42 – 42 = 0
Therefore the quotient is 164 ( 100 + 50 + 14)

Question 8.
224 ÷ 7 = ____

Answer: 32

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 30 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 7.
STEP 2
Subtract smaller multiples, such as 30 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 30 x 7 = 210 : 224 – 210 = 14
7 x 2 = 14 : 14 – 14 = 0
Therefore the quotient is 32 ( 30 + 2)

Question 9.
692 ÷ 4 = ____

Answer: 173

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 4.
STEP 2
Subtract smaller multiples, such as 100 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 100 x 4 = 400 : 692 – 400 = 392
4 x 50 = 200 : 392 – 200 = 192 : 4 x 48 = 192 : 192 – 192 = 0
Therefore the quotient is 198 ( 100 + 50 + 48)

Problem Solving

Question 10.
Allison took 112 photos on vacation. She wants to put them in a photo album that holds 4 photos on each page. How many pages can she fill?
____ pages

Answer: 28 pages

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 20 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 4.
STEP 2
Subtract smaller multiples, such as 20 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 20 x 4 = 80 : 112 – 80 = 32
4 x 8 = 32 : 32 – 32 = 0
Therefore the quotient is 28 ( 20 + 8)

Question 11.
Hector saved $726 in 6 months. He saved the same amount each month. How much did Hector save each month?
$ ____

Answer: $121

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 6.
STEP 2
Subtract smaller multiples, such as 100 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 100 x 6 = 600 : 726 – 600 = 126
6 x 20 = 120 : 126 – 120 = 6 : 6 x 1 = 6 : 6 – 6 = 0
Therefore the quotient is 121 ( 100 + 20 +1)

Common Core – Divide by 1-Digit Numbers – Page No. 84

Lesson Check

Question 1.
Annaka used partial quotients to divide 145 ÷ 5. Which shows a possible sum of partial quotients?
Options:
a. 50 + 50 + 45
b. 100 + 40 + 5
c. 10 + 10 + 9
d. 10 + 4 + 5

Answer: 10 + 10 + 9

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 4.
STEP 2
Subtract smaller multiples, such as 10 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 10 x 5 = 50 : 145 – 50 = 95
5 x 10 = 50 : 95 – 50 = 45 : 5 x 9 = 45 : 45 – 45 = 0
Therefore the quotient is 29 ( 10 + 10 +9)

Question 2.
Mel used partial quotients to find the quotient 378 ÷ 3. Which might show the partial quotients that Mel found?
Options:
a. 100, 10, 10, 9
b. 100, 10, 10, 6
c. 100, 30, 30, 6
d. 300, 70, 8

Answer: 100, 10, 10, 6

Explanation:
STEP 1
Start by subtracting a greater multiple, such as 100 times the divisor.
Continue subtracting until the remaining number is less than the multiple, 3.
STEP 2
Subtract smaller multiples, such as 10 times the divisor until the remaining number is less than the divisor. In other words, keep going until you no longer a remainder is left in the place of the remainder. Then add the partial quotients to find the quotient.
So, there are 100 x 3 = 300 : 378 – 300 = 78
10 x 3 =30 : 78 – 30 = 48 : 3 x 16 = 48 : 48 – 48 = 0
Therefore the quotient is 126 ( 100 + 10 +10 + 6)

Spiral Review

Question 3.
What are the partial products of 42 × 5?
Options:
a. 9 and 7
b. 20 and 10
c. 200 and 7
d. 200 and 10

Answer: 200 and 10

Explanation:
STEP1
42 x 5
Start by multiplying the digit five with the units digit 2 = 5 x 2 =10
Multiply the digit 5 with 4 in the tens place = 4 x 5 = 20
Since 4 is in the tens place when we multiply 4 and 5 we must place it in the hundreds place by assuming the units digit to be zero.
Therefore, the partial product of 42 x 5 = 200

Question 4.
Mr. Watson buys 4 gallons of paint that cost $34 per gallon. How much does Mr. Watson spend on paint?
Options:
a. $38
b. $126
c. $136
d. $1,216

Answer: $136

Explanation:
Cost of each gallon of paint = $34
Number of gallons = 4
The total cost of the gallons = $ 34 x 4 = $136

Question 5.
Use the area model to find the product 28 × 32.
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 6
Options:
a. 840
b. 856
c. 880
d. 896

Answer: 896

Explanation:
The whole rectangle is divided into four small rectangles the areas of these rectangles are:

Area of yellow rectangle= 30 x 20=600
Area of green rectangle= 2 x 20 = 40
Area of pink rectangle= 8 x 30= 240
Area of blue rectangle= 2 x 8= 16
Product of 32 and 28 = Area of yellow rectangle + Area of green rectangle + Area of pink rectangle + Area of the blue rectangle = 600+40+240+16 = 896

Question 6.
An adult male lion eats about 108 pounds of meat per week. About how much meat does an adult male lion eat in one day?
Options:
a. about 14 pounds
b. about 15 pounds
c. about 16 pounds
d. about 17 pounds

Answer: about 15 pounds

Explanation:
Mass of meat an adult lion eats in one week = 108
Number of days in a week = 7
Mass of meat ate by the lion in one day = 108 ÷ 7 = 15.4 pounds = about 15 pounds

Common Core – Divide by 1-Digit Numbers – Page No. 85

Model Division with Regrouping

Divide. Use base-ten blocks.

Question 1.
63 ÷ 4 = 15 r3
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 7

Explanation:
A. draw 4 circles to represent the divisor. Then use base-ten blocks to model 63. Show 63 as 6 tens and 3 ones.
B. Share the tens equally among the 4 groups.
C. If there are any tens left, regroup them as ones. Share the ones equally among the 4 groups.
D. There are 1 ten(s) and 5 one(s) in each group. So, the quotient is 15.
E. After grouping, there are 3 blocks that weren’t grouped. So, the remainder is 3

Question 2.
83 ÷ 3
_____ R _____

Answer: 27 r 2

Explanation:
A. Draw 3 circles to represent the divisor. Then use base-ten blocks to model 83. Show 83 as 8 tens and 3 ones.
B. Share the tens equally among the 3 groups.
C. If there are any tens left, regroup them as ones. Share the ones equally among the 3 groups.
D. There are 2 ten(s) and 7 one(s) in each group. So, the quotient is 27.
E. After grouping, there are 2 blocks that weren’t grouped. So, the remainder is 2

Divide. Draw quick pictures. Record the steps.

Question 3.
85 ÷ 5
_____

Answer: 17

Explanation:
A. Draw 5 circles to represent the divisor. Then use base-ten blocks to model 85. Show 85 as 8 tens and 5 ones.
B. Share the tens equally among the 5 groups.
C. If there are any tens left, regroup them as ones. Share the ones equally among the 5 groups.
D. There are 1 ten(s) and 7 one(s) in each group. So, the quotient is 17.

Question 4.
97 ÷ 4
_____ R _____

Answer: 24 r 1

Explanation:
A. Draw 4 circles to represent the divisor. Then use base-ten blocks to model 97. Show 97 as 9 tens and 7 ones.
B. Share the tens equally among the 4 groups.
C. If there are any tens left, regroup them as ones. Share the ones equally among the 4 groups.
D. There are 2 ten(s) and 4 one(s) in each group. So, the quotient is 24.
E. After grouping, there is 1 block that wasn’t grouped. So, the remainder is 1.

Problem Solving

Question 5.
Tamara sold 92 cold drinks during her 2-hour shift at a festival food stand. If she sold the same number of drinks each hour, how many cold drinks did she sell each hour?
_____ cold drinks

Answer: 46 cold drinks

Explanation:
Total number of cold drinks Tamara sold = 92
The time in which she sold the drinks = 2 hours
Number of drinks she sold in each hour = 92 ÷ 2 = 46

Question 6.
In 3 days Donald earned $42 running errands. He earned the same amount each day. How much did Donald earn from running errands each day?
$ _____

Answer: $14

Explanation:
Total amount earned by Donald = $42
Number of days = 3
Amount earned on each day = $42 ÷ 3 = $14

Common Core – Divide by 1-Digit Numbers – Page No. 86

Lesson Check

Question 1.
Gail bought 80 buttons to put on the shirts she makes. She uses 5 buttons for each shirt. How many shirts can Gail make with the buttons she bought?
Options:
a. 14
b. 16
c. 17
d. 18

Answer: 16

Explanation:
Total number of buttons = 80
Number of buttons used for each shirt = 5
Number of shirts she can make = 80 ÷ 5 =16
The correct answer is option b.

Question 2.
Marty counted how many breaths he took in 3 minutes. In that time, he took 51 breaths. He took the same number of breaths each minute. How many breaths did Marty take in one minute?
Options:
a. 15
b. 16
c. 17
d. 19

Answer: 17

Explanation:
Total number of breaths Marty counted = 51
Time in which the breath was counted = 3 minutes
Number of breaths in one minute = 51 ÷ 3 = 17
The correct answer is option c.

Spiral Review

Question 3.
Kate is solving brain teasers. She solved 6 brain teasers in 72 minutes. How long did she spend on each brain teaser?
Options:
a. 12 minutes
b. 14 minutes
c. 18 minutes
d. 22 minutes

Answer: 12 minutes

Explanation:
Number of brain teasers solved = 6
Number of minutes spent on brain teasers = 72 minutes
Number of minutes spent on each problem = 72 ÷ 6 =12 minutes
The correct answer is option a.

Question 4.
Jenny works at a package delivery store. She puts mailing stickers on packages. Each package needs 5 stickers. How many stickers will Jenny use if she is mailing 105 packages?
Options:
a. 725
b. 625
c. 525
d. 21

Answer: 525

Explanation:
Number of packages = 105
Number of stickers on each package = 5
Total number of stickers on the packages = 105 x 5 = 525
The correct answer is option c.

Question 5.
The Puzzle Company packs standardized puzzles into boxes that hold 8 puzzles. How many boxes would it take to pack up 192 standard-sized puzzles?
Options:
a. 12
b. 16
c. 22
d. 24

Answer: 24

Explanation:
Total number of puzzles = 192
Number of puzzles in each box = 8
Number of boxes used = 192 ÷ 8 = 24 boxes
The correct answer is option d.

Question 6.
Mt. Whitney in California is 14,494 feet tall. Mt. McKinley in Alaska is 5,826 feet taller than Mt. Whitney. How tall is Mt. McKinley?
Options:
a. 21,310 feet
b. 20,320 feet
c. 20,230 feet
d. 19,310 feet

Answer: 20,320 feet

Explanation:
Height of Mt. Whitney in California = 14,494 feet
The height of Mt. McKinley in Alaska is 5,826 feet taller than Mt. Whitney.
Therefore the height of Mt. McKinley in Alaska = 14,494 feet + 5,826 feet = 20,320 feet
The correct answer is option b.

Common Core – Divide by 1-Digit Numbers – Page No. 87

Place the First Digit

Divide.

Question 1.
62
3)\(\overline { 186 } \)
-18
——–
06
-6
——–
0

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 186. 180 hundred can be shared among 3 groups
without regrouping.
Now there is 18 tens and 6 ones to share among 3 groups.
The first digit of the quotient will be in the tens place.
STEP 2 Divide the tens.
Divide. 180 ÷ 3
Multiply. 3 × 60 = 180
Subtract. 186 − 180 = 6 ones
STEP 3 Divide the ones.
Now there are 6 ones to share among 3 groups.
Divide. 6 ones ÷ 3
Multiply. 2×3 ones
Subtract. 6 ones − 2 ones =0 one
So, the quotient is 62 (60 + 2) and the remainder is 0

Question 2.
4)\(\overline { 298 } \)
_____ R _____

Answer:
STEP 1 Use place value to place the first digit. Look at the hundreds in 298. 280 hundred can be shared among 4 groups
without regrouping.
Now there are 28 tens and 18 ones to share among 4 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 280 ÷ 4
Multiply. 4 × 70 = 280
Subtract. 280 − 280 = 0 ones
STEP 3 Divide the ones.
Now there are 18 ones to share among 4 groups.
Divide. 18 ones ÷ 4
Multiply. 4×4 ones
Subtract. 18 ones − 16 ones = 2 ones
So, the quotient is 74 (70 + 4) and the remainder is 2.

Question 3.
3)\(\overline { 461 } \)
_____ R _____

Answer: 153

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 461. 450 hundred can be shared among 3 groups
without regrouping.
Now there is 45 tens and 11 ones to share among 3 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 450 ÷ 3
Multiply. 3 × 150 = 450
Subtract. 450 − 450 = 0 ones
STEP 3 Divide the ones.
Now there are 11 ones to share among 3 groups.
Divide. 11 ones ÷ 3
Multiply. 3×3 ones
Subtract. 11 ones − 9 ones = 2 ones
So, the quotient is 153 (150 + 3) and the remainder is 2

Question 4.
9)\(\overline { 315 } \)
_____ R _____

Answer: 35

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 315. 310 hundred can be shared among 9 groups
without regrouping.
Now there is 31 tens and 5 ones to share among 9 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide.310 ÷ 9
Multiply. 9 × 30 = 270
Subtract. 310 − 270 = 40 ones
STEP 3 Divide the ones.
Now there are 40 + 5 = 45 ones to share among 9 groups.
Divide. 45 ones ÷ 9
Multiply. 5×9 ones
Subtract. 45 ones − 45 ones = 0 ones
So, the quotient is 35 (30 + 5) and the remainder is 0

Question 5.
2)\(\overline { 766 } \)
_____ R _____

Answer: 383

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 766. 760 hundred can be shared among 2 groups
without regrouping.
Now there is 76 tens and 6 ones to share among 2 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 760 ÷ 2
Multiply. 2 × 380 = 760
Subtract. 760 − 760 = 0 ones
STEP 3 Divide the ones.
Now there are 6 ones to share among 2 groups.
Divide. 6 ones ÷ 2
Multiply. 2×3 ones
Subtract. 6 ones − 6 ones = 0 ones
So, the quotient is 383 (380 + 3) and the remainder is 0

Question 6.
4)\(\overline { 604 } \)
_____ R _____

Answer: 151

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 604. 600 hundred can be shared among 4 groups
without regrouping.
Now there is 60 tens and 4 ones to share among 4 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 600 ÷ 4
Multiply. 4 × 150 = 600
Subtract. 600 − 600 = 0 ones
STEP 3 Divide the ones.
Now there are 4 ones to share among 4 groups.
Divide. 4 ones ÷ 4
Multiply. 4×1 ones
Subtract. 4 ones − 4 ones = 0 ones
So, the quotient is 151 (150 + 1) and the remainder is 0

Question 7.
6)\(\overline { 796 } \)
_____ R _____

Answer: 132

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 796. 790 hundred can be shared among 6 groups
without regrouping.
Now there is 79 tens and 6 ones to share among 6 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 790 ÷ 6
Multiply. 6 × 131 = 786
Subtract. 790 − 786 = 4 ones
STEP 3 Divide the ones.
Now there are 4 + 6 = 10 ones to share among 6 groups.
Divide. 10 ones ÷ 6
Multiply. 6×1 ones
Subtract. 10 ones − 6 ones = 4 ones
So, the quotient is 132 (131 + 1) and the remainder is 4.

Question 8.
5)\(\overline { 449 } \)
_____ R _____

Answer: 89

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 449. 440 hundred can be shared among 5 groups
without regrouping.
Now there is 44 tens and 9 ones to share among 5 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 440 ÷ 5
Multiply. 5 × 88 = 440
Subtract. 440 − 440 = 0 ones
STEP 3 Divide the ones.
Now there are 9 ones to share among 5 groups.
Divide. 9 ones ÷ 5
Multiply. 5×1 ones
Subtract. 9 ones − 5 ones = 4 ones
So, the quotient is 89 (88 + 1) and the remainder is 4

Question 9.
6)\(\overline { 756 } \)
_____ R _____

Answer: 126

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 756. 750 hundred can be shared among 6 groups
without regrouping.
Now there is 75 tens and 6 ones to share among 6 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 750 ÷ 6
Multiply. 6 × 125 = 750
Subtract. 750 − 750 = 0 ones
STEP 3 Divide the ones.
Now there are 6 ones to share among 6 groups.
Divide. 6 ones ÷ 6
Multiply. 6×1 ones
Subtract. 6 ones − 6 ones = 0 ones
So, the quotient is 126 (125 + 1) and the remainder is 0

Question 10.
7)\(\overline { 521 } \)
_____ R _____

Answer: 74

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 521. 520 hundred can be shared among 7 groups
without regrouping.
Now there is 52 tens and 1 one to share among 7 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 520 ÷ 7
Multiply. 7 × 74 = 518
Subtract. 520 − 518 = 2 ones
STEP 3 Divide the ones.
Now there are 2 + 1 = 3 ones to share among 7 groups.
Divide. 3 ones ÷ 7 (not possible)
So, the quotient is 74 and the remainder is 3

Question 11.
5)\(\overline { 675 } \)
_____ R _____

Answer: 135

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 675. 670 hundred can be shared among 5 groups
without regrouping.
Now there is 67 tens and 5 ones to share among 5 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 670 ÷ 5
Multiply. 5 × 134 = 670
Subtract. 670 − 670 = 0 ones
STEP 3 Divide the ones.
Now there are 5 ones to share among 5 groups.
Divide. 5 ones ÷ 5
Multiply. 5×1 ones
Subtract. 5 ones − 5 ones = 0 ones
So, the quotient is 135 (134 + 1) and the remainder is 0.

Question 12.
8)\(\overline { 933 } \)
_____ R _____

Answer: 116

Explanation:
STEP 1 Use place value to place the first digit. Look at the hundreds in 933. 930 hundred can be shared among 8 groups
without regrouping.
Now there is 93 tens and 3 ones to share among 8 groups.
The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the tens.
Divide. 930 ÷ 8
Multiply. 8 × 116 = 928
Subtract. 930 − 928 = 2 ones
STEP 3 Divide the ones.
Now there are 2 + 3 = 5 ones to share among 8 groups.
Divide. 5 ones ÷ 8 (not possible)
So, the quotient is 116 (100 + 3) and the remainder is 5.

Problem Solving

Question 13.
There are 132 projects in the science fair. If 8 projects can fit in a row, how many full rows of projects can be made? How many projects are in the row that is not full?
_____ full rows
_____ projects in the non-full row

Answer: 16 full rows and 4 projects in the non-full row

Explanation:
Total number of projects = 132
Number of projects placed in full row = 8
Number of rows having full projects =Quotient of 132 ÷ 8 = 16
Number of projects in the non-full row = Remainder of 132 ÷ 8 = 4

Question 14.
There are 798 calories in six 10-ounce bottles of apple juice. How many calories are there in one 10-ounce bottle of apple juice?
_____ R _____ calories in one 10-ounce bottles of juice

Answer: 133 calories

Explanation:
Number of calories in 6 bottles of apple juice = 798
Number of calories in each bottle = 798 ÷6 = 133 calories

Common Core – Divide by 1-Digit Numbers – Page No. 88

Lesson Check

Question 1.
To divide 572 ÷ 4, Stanley estimated to place the first digit of the quotient. In which place is the first digit of the quotient?
Options:
a. ones
b. tens
c. hundreds
d. thousands

Answer: hundreds

Explanation:
The quotient of 572÷ 4 is 143
STEP 1 Use place value to place the first digit. Look at the hundreds in 572. 560 hundred can be shared among 4 groups
without regrouping.
Now there is 1 ten to share among 4 groups.
The first digit of the quotient will be in the hundreds place.

Question 2.
Onetta biked 325 miles in 5 days. If she biked the same number of miles each day, how far did she bike each day?
Options:
a. 1,625 miles
b. 320 miles
c. 65 miles
d. 61 miles

Answer: 65 miles

Explanation:
Total number of miles biked = 325 miles
Number of days biked = 5
Number of miles biked on each day = Quotient of 325 ÷ 5 = 65

Spiral Review

Question 3.
Mort makes beaded necklaces that he sells for $32 each. About how much will Mort make if he sells 36 necklaces at the local art fair?
Options:
a. $120
b. $900
c. $1,200
d. $1,600

Answer: $1,200

Explanation:
Cost of each beaded necklace = $32
Number of necklaces = 36
The total cost of the necklaces = $32 x 36 = $1,200 (approx)

Question 4.
Which is the best estimate of 54 × 68?
Options:
a. 4,200
b. 3,500
c. 3,000
d. 350

Answer: 3,500

Explanation:

Taking the terms nearest to the 54 x 68 as 54 x 65 = 3510 = 3500 (approx)

Question 5.
Ms. Eisner pays $888 for 6 nights in a hotel. How much does Ms. Eisner pay per night?
Options:
a. $5,328
b. $882
c. $148
d. $114

Answer: $148

Explanation:
Total pays of Ms Eisner in a hotel = $888
Number of nights = 6
Amount Ms Eisner pay per night = $888 ÷ 6 = $148

Question 6.
Which division problem does the model show?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 8
Options:
a. 42 ÷ 3
b. 44 ÷3
c. 51 ÷ 3
d. 54 ÷ 3

Answer: 54 ÷ 3

Explanation:
Number of counters in each model = 18
Number of models = 3
Total number of counters = 18 x 3 = 54
Therefore the model displays = 54 ÷ 3

Common Core – Divide by 1-Digit Numbers – Page No. 89

Divide by 1-Digit Numbers

Divide and check.

Question 1.
318
\(\overline { 2)636 } \) 318
-6     × 2
———  ———
03 636
-2
———
16
-16
———
0

Question 2.
4)\(\overline { 631 } \)
_____ R _____

Answer:
STEP 1 Use place value to place the first digit. The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the hundreds.
STEP 3 Divide the tens.
STEP 4 Divide the ones.

Question 3.
8)\(\overline { 906 } \)
_____ R _____

Answer:
STEP 1 Use place value to place the first digit. The first digit of the quotient will be in the hundreds place.
STEP 2 Divide the hundreds.
STEP 3 Divide the tens.
STEP 4 Divide the ones.

Question 4.
6)\(\overline { 6,739 } \)
_____ R _____

Answer:
STEP 1 Use place value to place the first digit. Look at the thousands in 6,739. 6 thousand can be shared among 6 groups without regrouping. The first digit of the quotient will be in the thousands place.
STEP 2 Divide the thousands.
STEP 3 Divide the hundreds.
STEP 4 Divide the tens.
STEP 5 Divide the ones.

Question 5.
4)\(\overline { 2,328 } \)
_____ R _____

Answer:
STEP 1 Use place value to place the first digit. Look at the thousands in 2,328. 2 thousand can be shared among 4 groups without regrouping. The first digit of the quotient will be in the thousands place.
STEP 2 Divide the thousands.
STEP 3 Divide the hundreds.
STEP 4 Divide the tens.
STEP 5 Divide the ones.

Question 6.
5)\(\overline { 7,549 } \)
_____ R _____

Answer:
STEP 1 Use place value to place the first digit. Look at the thousands in 7,549. 7 thousand can be shared among 5 groups without regrouping. The first digit of the quotient will be in the thousands place.
STEP 2 Divide the thousands.
STEP 3 Divide the hundreds.
STEP 4 Divide the tens.
STEP 5 Divide the ones.

Problem Solving

Use the table for 7 and 8.
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 9

Question 7.
The Briggs rented a car for 5 weeks. What was the cost of their rental car per week?
$ _____

Answer: $197

Explanation:
Cost of the car of Briggs = $985
Number of weeks = 5
Cost of rent per week = $985 ÷ 5 =$ 197

Question 8.
The Lees rented a car for 4 weeks. The Santos rented a car for 2 weeks. Whose weekly rental cost was lower? Explain.
The rental cost of _________

Answer: Weekly rental cost was lower for Lees compared to Santos

Explanation:
Cost of the car of Lees = $632
Number of weeks = 4
Cost of rent per week = $632 ÷ 4 =$ 158

Cost of the car of Santos = $328
Number of weeks = 2
Cost of rent per week = $328 ÷ 2 =$ 164
Therefore weekly rental cost was lower for Lees compared to Santos.

Common Core – Divide by 1-Digit Numbers – Page No. 90

Lesson Check

Question 1.
Which expression can be used to check
the quotient 646 ÷ 3?
Options:
a. (251 × 3) + 1
b. (215 × 3) + 2
c. (215 × 3) + 1
d. 646 × 3

Answer: (215 × 3) + 1

Explanation:
Multiply 215 x 3 = 645
Then add 1 to 645
Then the dividend is 645 + 1 = 646
Thus the correct answer is option c.

Question 2.
There are 8 volunteers at the telethon. The goal for the evening is to raise $952. If each volunteer raises the same amount, what is the minimum amount each needs to raise to meet the goal?
Options:
a. $7,616
b. $944
c. $119
d. $106

Answer: $7,616

Explanation:
Number of volunteers = 8
Amount raised by each volunteer = $952
Total amount raised = $952 x 8 = $7,616

Thus the correct answer is option a.

Spiral Review

Question 3.
Which product is shown by the model?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 10
Options:
a. 5 × 15 = 75
b. 5 × 16 = 80
c. 5 × 17 = 75
d. 5 × 17 = 85

Answer: 5 × 17 = 85

Explanation:
By counting the number of counters we can give the expression.
Number of counters in one row = 17
Number of rows = 5
Therefore the expression = 5 × 17 = 85
Thus the correct answer is option d.

Question 4.
The computer lab at a high school ordered 26 packages of CDs. There were 50 CDs in each package. How many CDs did the computer lab order?
Options:
a. 1,330
b. 1,300
c. 1,030
d. 130

Answer: 1,300

Explanation:
Number of packages = 26
Number of CDs in each pack = 50
Total number of CDs the computer lab ordered = 26 x 50 = 1,300
Thus the correct answer is option b.

Question 5.
Which of the following division problems has a quotient with the first digit in the hundreds place?
Options:
a. 892 ÷ 9
b. 644 ÷ 8
c. 429 ÷ 5
d. 306 ÷ 2

Answer: 306 ÷ 2

Explanation:
Use place value to place the first digit. Look at the hundreds in 306. 300 hundred can be shared among 2 groups
without regrouping.
Now there is 30 tens and 6 ones to share among 2 groups.
The first digit of the quotient will be in the hundreds place.
Thus the correct answer is option d.

Question 6.
Sharon has 64 ounces of juice. She is going to use the juice to fill as many 6-ounce glasses as possible. She will drink the leftover juice. How much juice will Sharon drink?
Options:
a. 4 ounces
b. 6 ounces
c. 10 ounces
d. 12 ounces

Answer: 4 ounces

Explanation:
The total quantity of juice = 64 ounces
Quantity of juice she filled = 6 ounces
Quantity of juice she drank = Remainder of 64 ÷ 6 = 4

Thus the correct answer is option a.

Common Core – Divide by 1-Digit Numbers – Page No. 91

Problem Solving Multistep Division Problems

Solve. Draw a diagram to help you.

Question 1.
There are 3 trays of eggs. Each tray holds 30 eggs. How many people can be served if each person eats 2 eggs?
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers Common Core - Divide by 1-Digit Numbers img 11
Think: What do I need to find? How can I draw a diagram to help?
45 people can be served

Question 2.
There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?
______ packages

Answer: 14 packages

Explanation:
Number of pencils in each package = 8

Number of children = 28

Number of pencils each child needs = 4
Total number of pencils = 28 x 4 =112
Number of packages = 112 ÷ 8 = 14

Question 3.
There are 3 boxes of tangerines. Each box has 93 tangerines. The tangerines will be divided equally among 9 classrooms. How many tangerines will each classroom get?
______ tangerines

Answer: 31

Explanation:
Number of boxes = 3
Number of tangerines in each box = 93
Total number of tangerines = 93 x 3 = 279

Number of classrooms = 9
Number of tangerines in each classroom = 279 ÷ 9 = 31

Question 4.
Misty has 84 photos from her vacation and 48 photos from a class outing. She wants to put all the photos in an album with 4 photos on each page. How many pages does she need?
______ pages

Answer: 33 pages

Explanation:
Number of photos from her vacation = 84

Number of photos from her class outing = 48

Total number of photos = 84 + 48 = 132
Number of photos in each page = 4
Number of pages required = 132 ÷ 4 = 33

Common Core – Divide by 1-Digit Numbers – Page No. 93

Lessons 4.1, 4.5

Estimate the quotient.

Question 1.
67 ÷ 4
about ______

Answer: About 17

Explanation:
The number close to 67 is 70.
Divide 70 by 4 is 17.5
Thus the estimated quotient of 67 ÷ 4 is 17.

Question 2.
72 ÷ 5
about ______

Answer: About 14

Explanation:
The number close to 72 is 70.
Divide 70 by 5 is 14.
Thus the estimated quotient of 72 ÷ 5 is 14.

Question 3.

213 ÷ 3
about ______

Answer: About 70

Explanation:
The number close to 213 is 210.
Divide 210 by 3 is 70.
Thus the estimated quotient of 213 ÷ 3 is 70.

Question 4.
484 ÷ 6
about ______

Answer: About 80

Explanation:
The number close to 484 is 480.
Divide 480 by 6 is 80.
Thus the estimated quotient of 484 ÷ 6 is 80.

Question 5.
446 ÷ 7
about ______

Answer: About 60

Explanation:
The number close to 446 is 440.
Divide 440 by 7 is 60.
Thus the estimated quotient of 446 ÷ 7 is 60.

Question 6.
1,246 ÷ 4
about ______

Answer: About 300

Explanation:
The number close to 1246 is 1200.
Divide 1200 by 4 is 300.
Thus the estimated quotient of 1,246 ÷ 4 is 300.

Question 7.
708 ÷ 9
about ______

Answer: About 80

Explanation:
The number close to 708 is 700.
Divide 700 by 9 is 80 (approx).
Thus the estimated quotient of 708 ÷ 9 is 80.

Question 8.
2,657 ÷ 3
about ______

Answer: About 900

Explanation:
The number close to 2,657 is 2700.
Divide 2700 by 3 is 900.
Thus the estimated quotient of 2,657 ÷ 3 is 900.

Lesson 4.2

Use counters or quick pictures to find the quotient and remainder.

Question 9.
44 ÷ 5
______ R ______

Answer: 8R4

Explanation:
Quotient:
A. Use 44 counters to represent the 44 dominoes. Then draw 5 circles to represent the divisor.
B. Share the counters equally among the 5 groups by placing them in the circles.
C. Number of groups of counters formed = quotient of 44 ÷ 5
D. Number of circles equally filled is8, therefore, the quotient is 8.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 4
For 44 ÷ 5, the quotient is 8 and the remainder is 4, or 8R4.

Question 10.
8)\(\overline { 21 } \)
______ R ______

Answer: 2R5

Explanation:
Quotient:
A. Use 21 counters to represent the 21 dominoes. Then draw 8 circles to represent the divisor.
B. Share the counters equally among the 8 groups by placing them in the circles.
C. Number of groups of counters formed = quotient of 21 ÷ 8
D. Number of circles equally filled is 2, therefore, the quotient is 2.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 5
For 21 ÷ 8, the quotient is 2 and the remainder is 5, or 2R5.

Question 11.
4)\(\overline { 75 } \)
______ R ______

Answer: 18R3

Explanation:
Quotient:
A. Use 75 counters to represent the 75 dominoes. Then draw 4 circles to represent the divisor.
B. Share the counters equally among the 4 groups by placing them in the circles.
C. Number of groups of counters formed = quotient of 75 ÷ 4
D. Number of circles equally filled is 18, therefore, the quotient is 18.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 3
For 21 ÷ 8, the quotient is 18 and the remainder is 3, or 18R3.

Question 12.
76 ÷ 6
______ R ______

Answer: 12R4

Explanation:
Quotient:
A. Use 76 counters to represent the 76 dominoes. Then draw 6 circles to represent the divisor.
B. Share the counters equally among the 6 groups by placing them in the circles.
C. Number of groups of counters formed = quotient of 76 ÷ 6
D. Number of circles equally filled is 12, therefore, the quotient is 12.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 4
For 76 ÷ 6, the quotient is 12 and the remainder is 4, or 12R4.

Lesson 4.3

Interpret the remainder to solve.

Question 13.
Kelly divides 29 markers equally among 7 friends. If Kelly keeps the leftover markers, how many markers will she keep?
______ marker(s)

Answer: 1 marker

Explanation:
Given,
Kelly divides 29 markers equally among 7 friends.
1 because 4 markers for each friend (4 × 7) would be 28 and the last one would be leftover because it’s not enough for everyone.

Question 14.
Dave has a board that is 29 inches long. He cuts the board into 4 equal pieces. How long will each piece be?
______ inches

Answer: 7 inches

Explanation:
Dave has a board that is 29 inches long and want to cut it into 4 pieces.
You are asked the length of each piece.
To solve the question, you need to divide the total length of the board by the number of pieces Dave wants to make.
Then, the length of each piece would be: 29 inches/4= 7.25 inches

Question 15.
Eight students can ride in each van. How many vans are needed for 29 students?
______ vans

Answer: 4 vans

Explanation:
Given,
Eight students can ride in each van.
29/8 = 3.625 = 4(approx)
Therefore 4 vans are needed for 29 students.

Question 16.
Mac has 40 ounces of juice. He pours 6 ounces in each glass. How many glasses can he fill?
______ glasses

Answer: 6 glasses

Explanation:
Given,
Mac has 40 ounces of juice. He pours 6 ounces in each glass.
Divide 40 by 6
40/6 = 6.66 ≈ 6
Thus Mac can fill 6 glasses.

Lesson 4.4

Use basic facts and place value to find the quotient.

Question 17.
120 ÷ 4 = ______

Answer: 30

Explanation:
STEP 1 Identify the basic fact. 120 ÷ 4
STEP 2 Use place value. 120 = 12 tens
STEP 3 Divide. 12 tens ÷ 4 = 3 tens
120 ÷ 4 = 30

Question 18.
280 ÷ 7 = ______

Answer: 40

Explanation:
STEP 1 Identify the basic fact. 280 ÷ 7
STEP 2 Use place value. 280 = 28 tens
STEP 3 Divide. 28 tens ÷ 7 = 4 tens
280 ÷ 7 = 40

Question 19.
3,000 ÷ 5 = ______

Answer: 600

Explanation:
STEP 1 Identify the basic fact. 3000 ÷ 5
STEP 2 Use place value. 3000 = 300 tens
STEP 3 Divide. 300 tens ÷ 5 = 60 tens
3,000 ÷ 5 = 60 tens

Question 20.
4,800 ÷ 6 = ______

Answer: 800

Explanation:
STEP 1 Identify the basic fact. 4,800 ÷ 6
STEP 2 Use place value. 4800 = 480 tens
STEP 3 Divide. 480 tens ÷ 6 = 80 tens
4,800 ÷ 6 = 800

Question 21.
5,600 ÷ 8 = ______

Answer: 700

Explanation:
STEP 1 Identify the basic fact. 5,600 ÷ 8
STEP 2 Use place value. 5600 = 560 tens
STEP 3 Divide. 560 tens ÷ 8 = 70 tens
5,600 ÷ 8 = 700

Question 22.
6,300 ÷ 9 = ______

Answer: 700

Explanation:
STEP 1 Identify the basic fact. 6,300 ÷ 9
STEP 2 Use place value. 6300 = 630 tens
STEP 3 Divide. 630 tens ÷ 9 = 70 tens
6,300 ÷ 9 = 700

Common Core – Divide by 1-Digit Numbers – Page No. 94

Lessons 4.6–4.7

Choose a method and divide.

Question 1.
68 ÷ 4 = ______

Answer: 17

Explanation:
The number close to 68 is 70.
Divide 70 by 4 is 17 (approx).
Thus the estimated quotient of 68 ÷ 4 is 17.

Question 2.
48 ÷ 3 = ______

Answer: 16

Explanation:
The number close to 48 is 50.
Divide 50 by 3 is 16  (approx).
Thus the estimated quotient of 48 ÷ 3 is 16.

Question 3.
108 ÷ 9 = ______

Answer: 12

Explanation:
The number close to 108 is 100.
Divide 100 by 9 is 12 (approx).
Thus the estimated quotient of 108 ÷ 9 is 12.

Question 4.
74 ÷ 2 = ______

Answer: 37

Explanation:
The number close to 74 is 70.
Divide 70 by 2 is 37 (approx).
Thus the estimated quotient of 74 ÷ 2 is 37.

Question 5.
122 ÷ 5 = ______ R ______

Answer: 24R2

Explanation:
Quotient:
A. Use 122 counters to represent the 122 dominoes. Then draw 5 circles to represent the divisor.
B. Share the counters equally among the 5 groups by placing them in the circles.
C. Number of groups of counters formed = quotient of 122 ÷ 5
D. Number of circles equally filled are 24, therefore, the quotient is 24.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 2
For 122 ÷ 5, the quotient is 24 and the remainder is 2, or 24R2.

Question 6.
165 ÷ 6 = ______ R ______

Answer: 27R3

Explanation:
Quotient:
A. Use 165 counters to represent the 165 dominoes. Then draw 6 circles to represent the divisor.
B. Share the counters equally among the 6 groups by placing them in the circles.
C. Number of groups of counters formed = quotient of 165 ÷ 6.
D. Number of circles equally filled are 27, therefore, the quotient is 27.
Remainder:
The number of counters left over is the remainder. The number of counters leftover= 3
For 165 ÷ 6, the quotient is 27 and the remainder is 3, or 27R3.

Lessons 4.8–4.9

Divide.

Question 7.
4)\(\overline { 848 } \)
______

Answer: 212

Go Math Grade 4 Chapter 4 Answer Key

Question 8.
7)\(\overline { 287 } \)
______

Answer: 41

Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-2

Question 9.
5)\(\overline { 405 } \)
______

Answer: 81
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-3

Question 10.
3)\(\overline { 696 } \)
______

Answer: 232
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-4

Question 11.
96 ÷ 6 = ______

Answer: 16
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-5

Question 12.
76 ÷ 5 = ______ R ______

Answer: 15R1
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-6

Question 13.
58 ÷ 4 = ______ R ______

Answer: 14R2
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-7

Question 14.
85 ÷ 2 = ______ R ______

Answer: 42R1
Go Math Grade 4 Answer Key Homework Practice FL Chapter 4 Divide by 1-Digit Numbers img-8

Lessons 4.10–4.11

Divide and check.

Question 15.
4)\(\overline { 896 } \)
______

Answer: 224

Explanation:
224
× 4
896

Question 16.
5)\(\overline { 833 } \)
______ R ______

Answer: 166r3

Explanation:
166
× 5
830
+ 3
833

Question 17.
6)\(\overline { 527 } \)
______ R ______

Answer: 87r5

Explanation:
87
×6
522
+ 5
527

Question 18.
3)\(\overline { 935 } \)
______ R ______

Answer: 311r2

Explanation:
311
× 3
933
+ 2
935

Question 19.
3)\(\overline { 1,976 } \)
______ R ______

Answer: 658R2

Explanation:
658
× 3
1974
+    2
1976

Question 20.
6)\(\overline { 1,042 } \)
______ R ______

Answer: 173r4

Explanation:
173
×   6
1038
+   4
1042

Lesson 4.12

Solve. Draw a diagram to help you.

Question 21.
Ellis has 2 dozen white baseballs and 4 dozen yellow baseballs. He needs to divide them into cartons that hold 6 each. How many cartons can he fill?
______ cartons

Answer: 6 cartons

Explanation:
Given,
Ellis has 2 dozen white baseballs and 4 dozen yellow baseballs.
He needs to divide them into cartons that hold 6 each.
6 2 Dozens and 4 Dozens are 12+24 = 36/6 = 6
Therefore he can fill 6 cartons.

Question 22.
A family of 2 adults and 3 children went out to dinner. The total bill was $42. Each child’s dinner cost $4. How much did each adult’s dinner cost?
$ ______

Answer: $15

Explanation:
Each child’s dinner – $4
3 child’s dinner – $4 x 3 = $12
$42 – 12 = $30
$30 divided by 2 = $15
Thus each adult’s dinner cost is $15.

Conclusion:

Find more questions for practice from here, Go Math Grade 4 Answer Key Chapter 4 Divide by 1-Digit Numbers and develop your mathematical skills. Drop your queries and feedback by posting the comment below and we’ll update if anything requires as well as we’ll answer your doubts Asap.

Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice

go-math-grade-3-chapter-6-understand-division-extra-practice-answer-key

If you looking to practice Go Math 3rd Grade Textbook Questions then take the help of the Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice. You need to have strong fundamentals in Maths in order to become a pro in the Subject. You can easily understand the basics of the division with the Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice. Solve as Many Questions as possible from the Extra Practice and Clear the Final Exams with better grades.

3rd Grade Go Math Answer Key Ch 6 Understand Division Extra Practice

3rd Grade Go Math Answer Key Ch 6 Understand Division Extra Practice

Repeated subtraction, Equal groups, Number line, related multiplication, and division facts are all the topics covered in the 3rd Grade Go Math Answer Key Ch 6. Before you begin your preparation firstly know the syllabus i.e. concepts in Chapter 6 Understand Division and prepare accordingly. Check out the Step by Step Solutions provided for 3rd Grade Go Math Answer Key Chapter 6 Understand Division Extra Practice and learn the concepts efficiently.

Common Core – Page No. 123000

Lessons 6.1–6.3 Make equal groups.

Complete the table.

Counters Number of Equal Groups Number in Each Group
1. 18 9 ________
2. 24 ________ 8
3. 12 6 ________
4. 35 7 ________
5. 32 ________ 4
6. 25 ________ 5

Answer:

Counters Number of Equal Groups Number in Each Group
1. 18 9 2
2. 24 3 8
3. 12 6 2
4. 35 7 5
5. 32 8 4
6. 25 5 5

Explanation:

1. Number of counters = 18
Number of equal groups = 9
Number in each group = x
x × 9 = 18
x= 18/9 = 2
Therefore number in each group = 2

2. Number of counters = 24
Number in each group = 8
Number of equal groups = x
x × 8 = 24
x = 24/8 = 3
Thus the number of equal groups = 3

3. Number of counters = 12
Number of equal groups = 6
Number in each group = x
x × 6 = 12
x = 12/6 = 2
So, the number in each group = 2

4. Number of counters = 35
Number of equal groups = 7
Number in each group = x
x × 7 = 35
x = 35/7 = 5
x = 5
Therefore number in each group = 5

5. Number of counters = 32
Number of equal groups = x
Number in each group = 8
x × 8 = 32
x = 32/8 = 4
Thus the number of equal groups = 4

6. Number of counters = 25
Number of equal groups = x
Number in each group = 5
x × 5 = 25
x = 25/5 = 5
So, the number of equal groups = 5

Lesson 6.4

Write a division equation for the picture.

Question 1.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice Common Core img 1
Type below:
__________

Answer: 27 ÷ 3 = 9 or 27 ÷ 9 = 3

Explanation:

Total number of counters = 27
Number of equal groups = 3
Number in each group = 9
The division equation is
Number of counters by number of groups = 27 ÷ 3 = 9
or
Number of counters by number in each group = 27 ÷ 9 = 3

Question 2.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice Common Core img 2
Type below:
__________

Answer: 24 ÷ 4 = 6 or 24 ÷ 6 = 4

Explanation:

Total number of counters = 24
Number of equal groups = 4
Number in each group = 6
The division equation is
Number of counters by number of groups = 24 ÷ 4 = 6
or
Number of counters by number in each group = 24 ÷ 6 = 4

Lesson 6.5

Write a division equation.

Question 3.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice Common Core img 3
Type below:
__________

Answer: 3 groups, 15 ÷ 5 = 3

Explanation:

Step 1:

Starts at 15

Step 2:

Count back by 5s as many times as you can.

Step 3:

Count the number of times you jumped back 5.
You jumped back by 15 three times
There are 3 jumps of 5 in 15.

Question 4.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice Common Core img 4
Type below:
__________

Answer: 24 ÷ 6 = 4

Explanation:

Step 1:

Begins at 24

Step 2:

Subtract with 6 until you get 0.

Step 3:

Count the number of times you subtract with 6.

You subtract 4 times
There are 4 groups of 6 with 24
So, 24 ÷ 6 = 4

Common Core – Page No. 124000

Lesson 6.6

Make an array. Then write a division equation.

Question 1.
12 tiles in 4 rows
______ ÷ ______ = ______

Answer: 12 ÷ 4 = 3

Explanation:

■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■
Total number of tiles = 12
Number of rows = 4
Number of tiles in each row = x
Divide the number of tiles by number of rows = 12 ÷ 4 = 3

Question 2.
18 tiles in 3 rows
______ ÷ ______ = ______

Answer: 18 ÷ 3 = 6

Explanation:

■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
Total number of tiles = 18
Number of rows = 3
Number of tiles in each row = y
Divide the number of tiles by no. of rows = 18 ÷ 3 = 6

Question 3.
35 tiles in 5 rows
______ ÷ ______ = ______

Answer: 35 ÷ 5 = 7

Explanation:

■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■

Total number of tiles = 35
Number of rows = 5
Number of tiles in each row = p
Divide the number of tiles by number of rows = 35 ÷ 5 = 7

Question 4.
28 tiles in 7 rows
______ ÷ ______ = ______

Answer: 28 ÷ 7 = 4

Explanation:

■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■

Total number of tiles = 28
Number of rows = 7
Number of tiles in each row = x
Divide the number of tiles by number of rows = 28 ÷ 7 = 4

Lesson 6.7

Complete the equations.

Question 5.
8 × ______ = 40 40 ÷ 8 = ______

Answer: 5, 5

Explanation:

Let x be the unknown factor
8 × x = 40
x = 40/8
x = 5
Check whether the related multiplication and division facts are the same or not.
40 ÷ 8 = 5
The related facts of 40 and 8 are 5.

Question 6.
6 × ______ = 36 36 ÷ 6 = ______

Answer: 6, 6

Explanation:

Let y be the unknown factor
6 × y = 36
y = 36/6 = 6
Check if the related multiplication and division facts are the same or not.
36 ÷ 6 = 6
The related facts of 36 and 6 are 6.

Question 7.
3 × ______ = 21 21 ÷ 3 = ______

Answer: 7, 7

Explanation:

Let x be the unknown factor
3 × x = 21
x = 21
Check whether the related facts are the same or not.
21 ÷ 3 = 7
The quotient is 7.

Question 8.
2 × ______ = 18 18 ÷ 2 = ______

Answer: 9, 9

Explanation:

Let b be the unknown factor
2 × b = 18
b = 18/2 = 9
Check the related multiplication and division facts
18 ÷ 2 = 9
The related facts of 18 and 2 are 9.

Lesson 6.8 (pp. 239–243)

Write the related facts for the array.

Question 9.
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
______ × ______ = ______
______ × ______ = ______
______ ÷ ______ = ______
______ ÷ ______ = ______

Answer:

3 × 5 = 15
5 × 3 = 15
15 ÷ 3 = 5
15 ÷ 5 = 3

Explanation:

Total number of tiles = 15
Number of equal rows = 3
Number of rows in each group = 5
So, the related 5, 3 and 15 is 5× 3 = 15, 3×5 = 15, 15 ÷ 3 = 5 and 15÷ 5 = 3

Question 10.
■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
______ × ______ = ______
______ × ______ = ______
______ ÷ ______ = ______
______ ÷ ______ = ______

Answer:

3 × 6 = 18
6 × 3 = 18
18 ÷ 3 = 6
18 ÷ 6 = 3

Explanation:

Total number of tiles = 18
Number of equal rows = 3
Number of rows in each group = 6
So, the related 18, 3 and 6 is 3 × 6 = 18, 6 × 3 = 18, 18 ÷ 3 = 6 and 18 ÷ 6 = 3

Question 11.
■ ■ ■ ■ ■
■ ■ ■ ■ ■
______ × ______ = ______
______ × ______ = ______
______ ÷ ______ = ______
______ ÷ ______ = ______

Answer:

2 × 5 = 10
5 × 2 = 10
10 ÷ 2 = 5
10 ÷ 5 = 2

Explanation:

Total number of tiles = 10
Number of equal rows = 2
Number of rows in each group = 5
So, the related 2, 5 and 10 is 2 × 5 = 10, 5 × 2 = 10, 10 ÷ 2 = 5 and 10 ÷ 5 = 2

Lesson 6.9

Find the quotient.

Question 12.
7 ÷ 1 = ______

Answer: 7

Explanation:

Any number divided by 1 will be the same number. Thus the quotient is 7.

Question 13.
4 ÷ 4 = ______

Answer: 1

Explanation:

The number divided by the same number will be always 1. Thus the quotient is 1.

Question 14.
9 ÷ 1 = ______

Answer: 9

Explanation:

Any number divided by 1 will be always the same number. So, the quotient is 9.

Question 15.
0 ÷ 1 = ______

Answer: 0

Explanation:

0 divided by any number is always 0. So, the quotient is 0.

Question 16.
Anton has 8 flower pots. He plants 1 seed in each pot. How many seeds does Anton use?
______ seeds

Answer: 8 seeds

Explanation:

Anton has 8 flower pots.
He plants 1 seed in each pot.
Number of seeds Anton used = x
x × 1 = 8
x = 8/1
x = 8
Therefore there are 8 seeds in 8 flower pots.

All the Questions in Go Math Grade 3 Answer Key Chapter 6 Understand Division Extra Practice helps the students to be prepared for their exams. For any assistance needed you can always look upto  Go Math Grade 3 Answer Key Chapter 6 Understand Division.  You can get All Lessons Solutions in Chapter 6 Understand Division here.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations

go-math-grade-6-chapter-8-solutions-of-equations-answer-key

Are you searching for the Go Math Grade 6 Solution Key for Chapter 8 Solutions of Equations? If my guess is correct then you are on the right page. We provide the solutions to all the questions in pdf format. So, Download Go Math 6th Grade Answer Key Chapter 6 Chapter 8 Solutions of Equations pdf for free. Our Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations is helpful for quick and easy learning.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations

Enhance your performance in practice tests or assignments with the help of HMH Go Math 6th Grade Answer Key Chapter 8 Solutions of Equations. Get the solutions of Review Test and Mid Chapter Checkpoint in Go Math 6th Grade Chapter 8 Solutions of Equations. Scroll down this page to know the topics covered in this chapter. Make use of the links and Download Grade 6 Go Math Answer Key Chapter 8 Solutions of Equations.

Lesson 1: Solutions of Equations

Lesson 2: Write Equations

Lesson 3: Investigate • Model and Solve Addition Equations

Lesson 4: Solve Addition and Subtraction Equations

Lesson 5: Investigate • Model and Solve Multiplication Equations

Lesson 6: Solve Multiplication and Division Equations

Lesson 7: Problem Solving • Equations with Fractions

Mid-Chapter Checkpoint

Lesson 8: Solutions of Inequalities

Lesson 9: Write Inequalities

Lesson 10: Graph Inequalities

Lesson 10: Graph Inequalities

Chapter 8 Review/Test

Share and Show – Page No. 423

Determine whether the given value of the variable is a solution of the equation.

Question 1.
x + 12 = 29; x = 7
The variable is __________

Answer: not a solution

Explanation:
Substitute the value in the given equation
x + 12 = 29
If x = 7
7 + 12 = 29
19 ≠ 29
Thus the variable is not a solution.

Question 2.
n − 13 = 2; n = 15
The variable is __________

Answer: a solution

Explanation:
Substitute the value in the given equation
n = 15
n − 13 = 2
15 – 13 = 2
The variable is a solution.

Question 3.
\(\frac{1}{2}\)c = 14; c = 28
The variable is __________

Answer: a solution

Explanation:
Substitute the value in the given equation
c = 28
\(\frac{1}{2}\)c = 14
\(\frac{1}{2}\) × 28 = 14
14 = 14
Thus the variable is a solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 423 Q4

Question 5.
d − 8.7 = 6; d = 14.7
The variable is __________

Answer: a solution

Explanation:
Substitute the value in the given equation
d = 14.7
d − 8.7 = 6
14.7 – 8.7 = 6
6 = 6
Thus the variable is a solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 423 Q6

On Your Own

Determine whether the given value of the variable is a solution to the equation.

Question 7.
17.9 + v = 35.8; v = 17.9
The variable is __________

Answer: a solution

Explanation:
Substitute the value in the given equation
17.9 + v = 35.8
v = 17.9
17.9 + 17.9 = 35.8
35.8 = 35.8
Thus the variable is a solution.

Question 8.
c + 35 = 57; c = 32
The variable is __________

Answer: not a solution

Explanation:
Substitute the value in the given equation
c + 35 = 57
c = 32
32 + 35 = 57
67 ≠ 57
Thus the variable is not a solution.

Question 9.
18 = \(\frac{2}{3}\)h; h= 12
The variable is __________

Answer: not a solution

Explanation:
Substitute the value in the given equation
18 = \(\frac{2}{3}\)h
h = 12
\(\frac{2}{3}\) × 12 = 8
18 ≠ 8
Thus the variable is not a solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 423 Q10
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 423 Q10.1

Question 11.
Antonio ran a total of 9 miles in two days. On the first day he ran 5 \(\frac{1}{4}\) miles. The equation 9 – d = 5 \(\frac{1}{4}\) can be used to find the distance d in miles Antonio ran the second day. Determine whether d = 4 \(\frac{3}{4}\), d = 4, or d = 3 \(\frac{3}{4}\) is a solution of the equation, and tell what the solution means.
The solution is ________ \(\frac{□}{□}\)

Answer: 3 \(\frac{3}{4}\)

Explanation:
9 – d = 5 \(\frac{1}{4}\)
Substitute d = 4 \(\frac{3}{4}\) in the above equation
9 – 4 \(\frac{3}{4}\) = 5 \(\frac{1}{4}\)
4 \(\frac{1}{4}\) ≠ 5 \(\frac{1}{4}\)
Not a solution
Substitute d = 4
9 – 4 = 5 \(\frac{1}{4}\)
5 ≠ 5 \(\frac{1}{4}\)
Not a solution
Substitute d = 3 \(\frac{3}{4}\)
9 – 3 \(\frac{3}{4}\) = 5 \(\frac{1}{4}\)
5 \(\frac{1}{4}\) = 5 \(\frac{1}{4}\)
9 – d = 5 \(\frac{1}{4}\); d = 3 \(\frac{3}{4}\) is a solution.

Problem Solving + Applications – Page No. 424

Use the table for 12–14.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 1

Question 12.
Connect Symbols and Words The length of a day on Saturn is 14 hours less than a day on Mars. The equation 24.7 − s = 14 can be used to find the length in hours s of a day on Saturn. Determine whether s = 9.3 or s = 10.7 is a solution of the equation, and tell what the solution means.
Type below:
_____________

Answer: s = 10.7

Explanation:
The length of a day on Saturn is 14 hours less than a day on Mars.
The equation 24.7 − s = 14 can be used to find the length in hours s of a day on Saturn.
24.7 − s = 14
Substitute s = 9.3 in the equation
24.7 – 9.3 = 14
15.4 ≠ 14
Not a solution
Substitute s = 10.7 in the equation
24.7 – 10.7 = 14
14 = 14
Therefore s = 10.7 is a solution to the equation.

Question 13.
A storm on one of the planets listed in the table lasted for 60 hours, or 2.5 of the planet’s days. The equation 2.5h = 60 can be used to find the length in hours h of a day on the planet. Is the planet Earth, Mars, or Jupiter? Explain.
Type below:
_____________

Answer: Earth

Explanation:
A storm on one of the planets listed in the table lasted for 60 hours, or 2.5 of the planet’s days.
2.5h = 60
h = 60/2.5
h = 24 hours
By seeing the above table we can say that Earth is the answer.

Question 14.
A day on Pluto is 143.4 hours longer than a day on one of the planets listed in the table. The equation 153.3 − p = 143.4 can be used to find the length in hours p of a day on the planet. What is the length of a storm that lasts \(\frac{1}{3}\) of a day on this planet?
________ hours

Answer: 3.3 hours

Explanation:
A day on Pluto is 143.4 hours longer than a day on one of the planets listed in the table.
153.3 − p = 143.4
153.3 – 143.4 = p
p = 153.3 – 143.4
p = 9.9
Now p with \(\frac{1}{3}\) to find the length of a storm that lasts a day on this planet
9.9 × \(\frac{1}{3}\) = 3.3 hours

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 424 Q15

Question 16.
The marking period is 45 school days long. Today is the twenty-first day of the marking period. The equation x + 21 = 45 can be used to find the number of days x left in the marking period. Using substitution, Rachel determines there are _____ days left in the marking period.
Rachel determines there are _____________ days left.

Answer: 24

Explanation:
The marking period is 45 school days long. Today is the twenty-first day of the marking period.
The equation x + 21 = 45
x = 45 – 21 = 24 days
Using substitution, Rachel determines there are 24 days left in the marking period.
Thus Rachel determines there are 24 days left.

Solutions of Equations – Page No. 425

Determine whether the given value of the variable is a solution of the equation.

Question 1.
x − 7 = 15; x = 8
The variable is __________

Answer: not a solution

Explanation:
Substitute the value in the given equation.
x = 8
8 – 7 = 15
1 ≠ 15
Therefore the variable is not a solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 425 Q2

Question 3.
\(\frac{1}{3}\)h = 6; h = 2
The variable is __________

Answer: not a solution

Explanation:
Substitute the value in the given equation.
\(\frac{1}{3}\)h = 6
h = 2
\(\frac{1}{3}\) × 2 = 6
\(\frac{2}{3}\) ≠ 6
Therefore the variable is not a solution.

Question 4.
16.1 + d = 22; d = 6.1
The variable is __________

Answer: not a solution

Explanation:
Substitute the value in the given equation.
16.1 + d = 22
d = 6.1
16.1 + 6.1 = 22
22.2 ≠ 22
Therefore the variable is not a solution.

Question 5.
9 = \(\frac{3}{4}\)e; e = 12
The variable is __________

Answer: a solution

Explanation:
Substitute the value in the given equation.
9 = \(\frac{3}{4}\)e
e = 12
9 = \(\frac{3}{4}\)(12)
9 = 3 × 3
9 = 9
Therefore the variable is a solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 425 Q6

Problem Solving

Question 7.
Terrance needs to score 25 points to win a game. He has already scored 18 points. The equation 18 + p = 25 can be used to find the number of points p that Terrance still needs to score. Determine whether p = 7 or p = 13 is a solution of the equation, and tell what the solution means.
Type below:
_____________

Answer: p = 7

Explanation:
Terrance needs to score 25 points to win a game. He has already scored 18 points.
The equation is 18 + p = 25
Substitute p = 7 in the above equation.
18 + 7 = 25
25 = 25
The variable is a solution.
Substitute p = 13
18 + p = 25
18 + 13 = 25
31 ≠ 25
The variable is not a solution.
Therefore p = 7 is a solution for the equation.

Question 8.
Madeline has used 50 sheets of a roll of paper towels, which is \(\frac{5}{8}\) of the entire roll. The equation \(\frac{5}{8}\)s = 50 can be used to find the number of sheets s in a full roll. Determine whether s = 32 or s = 80 is a solution of the equation, and tell what the solution means.
Type below:
_____________

Answer:
Madeline has used 50 sheets of a roll of paper towels, which is \(\frac{5}{8}\) of the entire roll.
\(\frac{5}{8}\)s = 50
s = 50 × \(\frac{8}{5}\)
s = 80 because 80 × 5 = 400
400 ÷ 8 = 50

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 425 Q9

Lesson Check – Page No. 426

Question 1.
Sheena received a gift card for $50. She has already used it to buy a lamp for $39.99. The equation 39.99 + x = 50 can be used to find the amount x that is left on the gift card. What is the solution to the equation?
_____

Answer: 10.01

Explanation:
Given:
Sheena received a gift card for $50. She has already used it to buy a lamp for $39.99.
The equation 39.99 + x = 50
39.99 + x = 50
x = 50 – 39.99
x = 50.00 – 39.99
x = 10.01
Thus $10.01 is left on the gift card.

Question 2.
When Pete had a fever, his temperature was 101.4°F. After taking some medicine, his temperature was 99.2°F. The equation 101.4 – d = 99.2 can be used to find the number of degrees d that Pete’s temperature decreased. What is the solution of the equation?
_____

Answer: 2.2

Explanation:
Given,
When Pete had a fever, his temperature was 101.4°F.
After taking some medicine, his temperature was 99.2°F.
The equation 101.4 – d = 99.2
104.4 – 99.2 = d
d = 104.4 – 99.2
d = 2.2

Spiral Review

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 426 Q3

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 426 Q4

Question 5.
Andrew made p picture frames. He sold 2 of them at a craft fair. Write an expression that could be used to find the number of picture frames Andrew has left.
Type below:
_____________

Answer: p – 2

Explanation:
Andrew made p picture frames. He sold 2 of them at a craft fair.
The expression is the difference of 9 and 2
The equation is p – 2

Question 6.
Write an expression that is equivalent to 4 + 3(5 + x).
Type below:
_____________

Answer: 4 + 15 + 3x

Explanation:
4 + 3(5 + x) = 4 + 15 + 3x
3x + 19
Thus the expression 4 + 3(5 + x) is equivalent to 4 + 15 + 3x or 3x + 19

Share and Show – Page No. 429

Question 1.
Write an equation for the word sentence “25 is 13 more than a number.”
Type below:
_____________

Answer:
Let n represent the unknown number. The phrase ‘more than’ indicates an addition operation.
Thus the equation is 25 = 13 + n.

Write an equation for the word sentence.

Question 2.
The difference of a number and 2 is 3 \(\frac{1}{3}\).
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “difference” indicates the subtraction operation.
The equation is n – 2 = 3 \(\frac{1}{3}\)

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 429 Q3

Write a word sentence for the equation.

Question 4.
x − 0.3 = 1.7
Type below:
_____________

Answer: The difference of x and 0.3 is 1.7

Question 5.
25 = \(\frac{1}{4}\)n
Type below:
_____________

Answer: 25 is n times \(\frac{1}{4}\)

Write an equation for the word sentence.

Question 6.
The quotient of a number and 20.7 is 9.
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “quotient” indicates the division operation.
Thus the equation is n ÷ 20.7 = 9.

Question 7.
24 less than the number of snakes is 35.
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “less than” indicates subtraction operation.
Thus the equation is n – 24 = 35

Question 8.
75 is 18 \(\frac{1}{2}\) more than a number.
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “more than” indicates addition operation.
75 = 18 \(\frac{1}{2}\) + n

Question 9.
d degrees warmer than 50 degrees is 78 degrees.
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “warmer than” indicates addition operation.
The equation is d + 50 = 78 degrees

Write a word sentence for the equation.

Question 10.
15g = 135
Type below:
_____________

Answer: g times 15 is 135

Question 11.
w ÷ 3.3 = 0.6
Type below:
_____________

Answer: The quotient of w and 3.3 is 0.6

Problem Solving + Applications – Page No. 430

To find out how far a car can travel on a certain amount of gas, multiply the car’s fuel efficiency in miles per gallon by the gas used in gallons. Use this information and the table for 12–13.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 2

Question 12.
Write an equation that could be used to find how many miles a hybrid SUV can travel in the city on 20 gallons of gas.
Type below:
_____________

Answer:
From table 36 miles per gallon in the city.
A hybrid SUV uses 36 miles per gallon in the city.
So, no. of miles = y
x = no. of gallons
So, y = 36 × x
x = 20 gallons
Thus y = 36 × 20

Question 13.
A sedan traveled 504 miles on the highway on a full tank of gas. Write an equation that could be used to find the number of gallons the tank holds.
Type below:
_____________

Answer:
A sedan uses 28 miles per gallon on the highway.
The equation that could be used to find the number of gallons the tank holds is
504 = 28g

Question 14.
Connect Symbols to Words Sonya was born in 1998. Carmen was born 11 years after Sonya. If you wrote an equation to find the year in which Carmen was born, what operation would you use in your equation?
Type below:
_____________

Answer: In this equation, I would use addition or subtraction operation.

Question 15.
A magazine has 110 pages. There are 23 full-page ads and 14 half-page ads. The rest of the magazine consists of articles. Write an equation that can be used to find the number of pages of articles in the magazine.
Type below:
_____________

Answer:
The equation that can be used to find the number of pages of articles in the magazine is
23 + 14/2 + a = 110
where a represents the number of articles.

Question 16.
What’s the Error? Tony is traveling 560 miles to visit his cousins. He travels 313 miles the first day. He says that he can use the equation m − 313 = 560 to find the number of miles m he has left on his trip. Describe and correct Tony’s error.
Type below:
_____________

Answer:
Tony subtracted the number of miles traveled from the number of miles left.
Tony should have written m + 313 = 560

Question 17.
Jamie is making cookies for a bake sale. She triples the recipe in order to have enough cookies to sell. Jamie uses 12 cups of flour to make the triple batch. Write an equation that can be used to find out how much flour f is needed for one batch of cookies.
Type below:
_____________

Answer:
The equation that can be used to find out how much flour f is needed for one batch of cookies is 3f = 12

Write Equations – Page No. 431

Write an equation for the word sentence.

Question 1.
18 is 4.5 times a number.
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “times” indicates the multiplication operation.
The equation is 18 = 4.5n

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 431 Q2

Question 3.
The difference of a number and \(\frac{2}{3}\) is \(\frac{3}{8}\).
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase “difference” indicates a subtraction operation.
The equation is n – \(\frac{2}{3}\) = \(\frac{3}{8}\)

Question 4.
A number divided by 0.5 is 29.
Type below:
_____________

Answer:
Let n represents the unknown number.
The phrase divided by indicates division operation.
The equation is n ÷ 0.5 = 29

Write a word sentence for the equation.

Question 5.
x − 14 = 52
Type below:
_____________

Answer:
14 less than x is 52
the difference of x and 14 is 52
14 fewer than a number is 52.

Question 6.
2.3m = 0.46
Type below:
_____________

Answer:
The product of 2.3 and m is 0.46
2.3 times m is .46
2.3 of m is 0.46

Question 7.
25 = k ÷ 5
Type below:
_____________

Answer: 25 is the quotient of k and 5.

Question 8.
\(4 \frac{1}{3}+q=5 \frac{1}{6}\)
Type below:
_____________

Answer:
The sum of \(4 \frac{1}{3}\) and q is [/latex]5 \frac{1}{6}[/latex]
q is more than \(4 \frac{1}{3}\) and [/latex]5 \frac{1}{6}[/latex]
\(4 \frac{1}{3}\) increased by a number is [/latex]5 \frac{1}{6}[/latex]

Question 9.
An ostrich egg weighs 2.9 pounds. The difference between the weight of this egg and the weight of an emu egg is 1.6 pounds. Write an equation that could be used to find the weight w, in pounds, of the emu egg.
Type below:
_____________

Answer: 2.9 – w = 1.6

Explanation:
An ostrich egg weighs 2.9 pounds.
The difference between the weight of this egg and the weight of an emu egg is 1.6 pounds.
The phrase “difference” indicates the subtraction operation.
The equation will be 2.9 – w = 1.6

Question 10.
In one week, the number of bowls a potter made was 6 times the number of plates. He made 90 bowls during the week. Write an equation that could be used to find the number of plates p that the potter made.
Type below:
_____________

Answer: 6p = 90

Explanation:
Given,
In one week, the number of bowls a potter made was 6 times the number of plates.
He made 90 bowls during the week.
The phrase “times” indicates the multiplication operation.
The equation to find the number of plates p that the potter made will be 6p = 90

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 431 Q11

Lesson Check – Page No. 432

Question 1.
Three friends are sharing the cost of a bucket of popcorn. The total cost of the popcorn is $5.70. Write an equation that could be used to find the amount ‘a’ in dollars that each friend should pay.
Type below:
_____________

Answer: 3a = 5.70

Explanation:
Three friends are sharing the cost of a bucket of popcorn.
The total cost of the popcorn is $5.70.
The expression will be “5.70 is the product of 3 and a.
The equation is 3a = 5.70

Question 2.
Salimah had 42 photos on her phone. After she deleted some of them, she had 23 photos left. What equation could be used to find the number of photos p that Salimah deleted?
Type below:
_____________

Answer: p + 23 = 42

Explanation:
Salimah had 42 photos on her phone. After she deleted some of them, she had 23 photos left.
The expression is the sum of p and 23 is 42.
Thus the equation is p + 23 = 42

Question 3.
A rope is 72 feet long. What is the length of the rope in yards?
______ yards

Answer: 24 yard

Explanation:
A rope is 72 feet long.
Convert from feet to yards.
1 yard = 3 feet
1 foot = 1/3 yards
72 feet = 72 × 1/3 = 24 yards
Thus the length of the rope is 24 yards.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 432 Q4

Question 5.
The sides of a triangle have lengths s, s + 4, and 3s. Write an expression in the simplest form that represents the perimeter of the triangle.
Type below:
_____________

Answer: 5s + 4

Explanation:
The perimeter of the triangle is a + b + c
P = a + b + c
P = s + s + 4 + 3s
P = 5s + 4
Thus the perimeter of the triangle is 5s + 4

Question 6.
Gary knows that p = 2 \(\frac{1}{2}\) is a solution to one of the following equations. Which one has p = 2 \(\frac{1}{2}\) as its solution?
\(p+2 \frac{1}{2}=5\)        \(p-2 \frac{1}{2}=5\)
\(2+p=2 \frac{1}{2}\)       4 – p = 2 \(\frac{1}{2}\)
Type below:
_____________

Answer: p + 2 \(\frac{1}{2}\) = 5

Explanation:
\(p+2 \frac{1}{2}=5\)
p + 2 \(\frac{1}{2}\) = 5
p = 5 – 2 \(\frac{1}{2}\)
p = 2 \(\frac{1}{2}\)
\(p-2 \frac{1}{2}=5\)
p – 2 \(\frac{1}{2}\) = 5
p = 5 + 2 \(\frac{1}{2}\)
p = 7 \(\frac{1}{2}\)
\(2+p=2 \frac{1}{2}\)
2 + p = 2 \(\frac{1}{2}\)
p = 2 \(\frac{1}{2}\) – 2
p = \(\frac{1}{2}\)
4 – p = 2 \(\frac{1}{2}\)
p = 4 – 2 \(\frac{1}{2}\)
p = 1 \(\frac{1}{2}\)

Share and Show – Page No. 435

Model and solve the equation by using algebra tiles or iTools.

Question 1.
x + 5 = 7
x = ______

Answer: 2

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 5 in the left rectangle, and model 7 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove five 1 tiles on the left side and five 1 tiles on the right side.
  • The remaining titles will be two 1 tiles on the right sides.

Question 2.
8 = x + 1
x = ______

Answer: 7

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 1 in the left rectangle, and model 8 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove one 1 tiles on the left side and one 1 tiles on the right side.
  • The remaining titles will be seven 1 tiles on the right sides.

Question 3.
x + 2 = 5
x = ______

Answer: 3

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 2 in the left rectangle, and model 5 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove two 1 tiles on the left side and five 1 tiles on the right side.
  • The remaining titles will be three 1 tiles on the right sides.

Question 4.
x + 6 = 8
x = ______

Answer: 2

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 6 in the left rectangle, and model 8 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove six 1 tiles on the left side and six 1 tiles on the right side.
  • The remaining titles will be two 1 tiles on the right sides.

Question 5.
5 + x = 9
x = ______

Answer: 4

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 5 in the left rectangle, and model 9 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove five 1 tiles on the left side and five 1 tiles on the right side.
  • The remaining titles will be four 1 tiles on the right sides.

Question 6.
5 = 4 + x
x = ______

Answer: 1

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 4 in the left rectangle, and model 5 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove four 1 tiles on the left side and four 1 tiles on the right side.
  • The remaining titles will be one 1 tiles on the right sides.

Solve the equation by drawing a model.

Question 7.
x + 1 = 5
x = ______

Answer: 4

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 1 in the left rectangle, and model 5 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove one 1 tiles on the left side and one 1 tiles on the right side.
  • The remaining titles will be four 1 tiles on the right sides.

Go Math Grade 6 Key Chapter 8 solution img-6

Question 8.
3 + x = 4
x = ______

Answer: 1

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 3 in the left rectangle, and model 4 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove three 1 tiles on the left side and three 1 tiles on the right side.
  • The remaining titles will be one 1 tiles on the right sides.

Go Math Grade 6 Answer Key 8th chapter solution img-7

Question 9.
6 = x + 4
x = ______

Answer: 2

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 4 in the left rectangle, and model 6 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove four 1 tiles on the left side and four 1 tiles on the right side.
  • The remaining titles will be two 1 tiles on the right sides.

HMH 6th Grade Go Math Answer Key solution img-8

Question 10.
8 = 2 + x
x = ______

Answer: 6

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 2 in the left rectangle, and model 8 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove two 1 tiles on the left side and two 1 tiles on the right side.
  • The remaining titles will be six 1 tiles on the right sides.

6th Grade Go Math key solution img-9

Question 11.
Describe a Method Describe how you would draw a model to solve the equation x + 5 = 10.
Type below:
_____________

Answer: x = 5

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 5 in the left rectangle, and model 10 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove five 1 tiles on the left side and five 1 tiles on the right side.
  • The remaining titles will be five 1 tiles on the right sides.

Go Math Answer Key Chapter 6th Grade solution img-10

Problem Solving + Applications – Page No. 436

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 3

Question 12.
Interpret a Result The table shows how long several animals have lived at a zoo. The giraffe has lived at the zoo 4 years longer than the mountain lion. The equation 5 = 4 + y can be used to find the number of years y the mountain lion has lived at the zoo. Solve the equation. Then tell what the solution means.
Type below:
_____________

Answer:
The table shows how long several animals have lived in a zoo.
The giraffe has lived at the zoo 4 years longer than the mountain lion.
5 = 4 + y
y = 5 – 4
y = 1
The solution is y = 1
The solution means that the mountain lion has lived at the zoo for 1 year.

Question 13.
Carlos walked 2 miles on Monday and 5 miles on Saturday. The number of miles he walked on those two days is 3 miles more than the number of miles he walked on Friday. Write and solve an addition equation to find the number of miles Carlos walked on Friday
Type below:
_____________

Answer:
Given that,
Carlos walked 2 miles on Monday and 5 miles on Saturday.
The number of miles he walked on those two days is 3 miles more than the number of miles he walked on Friday.
The equation is f + 3 = 2 + 5
f + 3 = 7
f = 7 – 3
f = 4
The solution is f = 4
The solution means that Carlos walked 4 miles on Friday.

Question 14.
Sense or Nonsense? Gabriela is solving the equation x + 1 = 6. She says that the solution must be less than 6. Is Gabriela’s statement sense or nonsense? Explain.
Type below:
_____________

Answer: Gabriela’s statement makes sense.
x + 1 = 6
x = 6 – 1
x = 5
Thus the solution is less than 6.

Question 15.
The Hawks beat the Tigers by 5 points in a football game. The Hawks scored a total of 12 points.
Use numbers and words to explain how this model can be used to solve the equation x + 5 = 12.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 4
Type below:
_____________

Answer:
Remove 5 squares from each side. The rectangle is by itself on the left and 7 squares are on the right side.
So, the solution is x = 7

Model and Solve Addition Equations – Page No. 437

Model and solve the equation by using algebra tiles.

Question 1.
x + 6 = 9
x = ________

Answer: 3

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 6 in the left rectangle, and model 9 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove six 1 tiles on the left side and six 1 tiles on the right side.
  • The remaining titles will be three 1 tiles on the right sides.

Thus x = 3

Question 2.
8 + x = 10
x = ________

Answer: 2

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 8 in the left rectangle, and model 10 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove eight 1 tiles on the left side and eight 1 tiles on the right side.
  • The remaining titles will be two 1 tiles on the right sides.

8 + x = 10
x = 10 – 8 = 2
x = 2

Question 3.
9 = x + 1
x = ________

Answer: 8

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 1 in the left rectangle, and model 9 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove 1 tile on the left side and 1 tile on the right side.
  • The remaining titles will be eight 1 tiles on the right sides.

Thus x = 8

Solve the equation by drawing a model.

Question 4.
x + 4 = 7
x = ________

Answer: 3

Go Math Answer Key Grade 6 Chapter 8 solution img-1

Question 5.
x + 6 = 10
x = ________

Answer: 4
Go Math Grade 6 Answer Key Chapter 8 solution img-2

Problem Solving

Question 6.
The temperature at 10:00 was 10°F. This is 3°F warmer than the temperature at 8:00. Model and solve the equation x + 3 = 10 to find the temperature x in degrees Fahrenheit at 8:00.
Type below:
_____________

Answer: x = 7

Explanation:
The temperature at 10:00 was 10°F. This is 3°F warmer than the temperature at 8:00.
The equation is x + 3 = 10
x = 10 – 3 = 7

Question 7.
Jaspar has 7 more checkers left than Karen does. Jaspar has 9 checkers left. Write and solve an addition equation to find out how many checkers Karen has left.
Type below:
_____________

Answer: c = 2

Explanation:
Jaspar has 7 more checkers left than Karen does. Jaspar has 9 checkers left.
The expression is c + 7 = 9
The equation to find out how many checkers Karen has left is c + 7 = 9.

Question 8.
Explain how to use a drawing to solve an addition equation such as x + 8 = 40.
Type below:
_____________

Answer: 32

Explanation:

  • Draw 2 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model x + 8 in the left rectangle, and model 40 in the right rectangle.
  • To solve the equation, get the x tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove eight 1 tile on the left side and eight 1 tile on the right side.
  • The remaining titles will be 32 1 tiles on the right side.

x + 8 = 40
x = 40 – 8
x = 32

Lesson Check – Page No. 438

Question 1.
What is the solution of the equation that is modeled by the algebra tiles?
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 5
x = ________

Answer: 1

The equation is x + 6 = 7
x = 7 – 6
x = 1

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 438 Q2

Spiral Review

Question 3.
A car’s gas tank has a capacity of 16 gallons. What is the capacity of the tank in pints?
________ pints

Answer: 128 pints

Explanation:
A car’s gas tank has a capacity of 16 gallons.
Convert from gallons to pints.
1 gallon = 8 pints
16 gallons = 16 × 8 = 128 pints
Thus the capacity of the tank is 128 pints.

Question 4.
Craig scored p points in a game. Marla scored twice as many points as Craig but 5 fewer than Nelson scored. How many points did Nelson score?
Type below:
_____________

Answer: 2p + 5

Explanation:
Craig scored p points in a game.
Marla scored twice as many points as Craig but 5 fewer than Nelson scored.
The equation will be 2p + 5.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 438 Q5

Question 6.
The Empire State Building in New York City is 443.2 meters tall. This is 119.2 meters taller than the Eiffel Tower in Paris. Write an equation that can be used to find the height h in meters of the Eiffel Tower.
Type below:
_____________

Answer: 119.2 + h = 443.2

Explanation:
The Empire State Building in New York City is 443.2 meters tall.
This is 119.2 meters taller than the Eiffel Tower in Paris.
Here we have to use the addition operation.
The equation is 119.2 + h = 443.2

Share and Show – Page No. 441

Question 1.
Solve the equation n + 35 = 80.
n = ________

Answer: 45

Explanation:
The given equation is
n + 35 = 80
n = 80 – 35
n = 45

Solve the equation, and check the solution.

Question 2.
16 + x = 42
x = ________

Answer: 26

Explanation:
Given the equation 16 + x = 42
x + 16 = 42
x = 42 – 16
x = 26

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 441 Q3

Question 4.
m + \(\frac{3}{10}=\frac{7}{10}\)
m = \(\frac{□}{□}\)

Answer: \(\frac{4}{10}\)

Explanation:
The given equation is
m + \(\frac{3}{10}=\frac{7}{10}\)
m = \(\frac{7}{10}\) – \(\frac{3}{10}\)
The denominators are common so subtract the numerators
m = \(\frac{4}{10}\)

Question 5.
z – \(\frac{1}{3}=1 \frac{2}{3}\)
z = ________

Answer: 2

Explanation:
The given equation is
z – \(\frac{1}{3}=1 \frac{2}{3}\)
z = \(\frac{1}{3}\) + 1 \(\frac{2}{3}\)
z = 1 + \(\frac{1}{3}\) + \(\frac{2}{3}\)
z = 1 + \(\frac{3}{3}\)
z = 1 + 1 = 2
Thus the value of z is 2.

Question 6.
12 = x − 24
x = ________

Answer: 36

Explanation:
The given equation is
12 = x − 24
x – 24 = 12
x = 12 + 24
x = 36
Thus the value of x is 36.

Question 7.
25.3 = w − 14.9
w = ________

Answer: 40.2

Explanation:
The given equation is
25.3 = w − 14.9
w – 14.9 = 25.3
w = 25.3 + 14.9
w = 40.2
The value of w is 40.2

On Your Own

Practice: Copy and Solve Solve the equation, and check the solution.

Question 8.
y − \(\frac{3}{4}=\frac{1}{2}\)
y = _______ \(\frac{□}{□}\)

Answer: 1 \(\frac{1}{4}\)

Explanation:
The given equation is
y − \(\frac{3}{4}=\frac{1}{2}\)
y = \(\frac{1}{2}\) + \(\frac{3}{4}\)
y = 1 \(\frac{1}{4}\)
Therefore the value of y is 1 \(\frac{1}{4}\).

Question 9.
75 = n + 12
n = ________

Answer: 63

Explanation:
The given equation is
75 = n + 12
n + 12 = 75
n = 75 – 12
n = 63
The value of n is 63.

Question 10.
m + 16.8 = 40
m = ________

Answer: 23.2

Explanation:
The given equation is
m + 16.8 = 40
m = 40 – 16.8
m = 23.2
The value of m is 23.2

Question 11.
w − 36 = 56
w = ________

Answer: 92

Explanation:
The given equation is
w − 36 = 56
w = 56 + 36
w = 92
The value of w is 92.

Question 12.
8 \(\frac{2}{5}\) = d + 2\(\frac{2}{5}\)
d = ________

Answer: 6

Explanation:
The given equation is
8 \(\frac{2}{5}\) = d + 2\(\frac{2}{5}\)
d + 2\(\frac{2}{5}\) = 8 \(\frac{2}{5}\)
d = 8 \(\frac{2}{5}\) – 2\(\frac{2}{5}\)
d = 8 + \(\frac{2}{5}\) – 2 – \(\frac{2}{5}\)
d = 8 – 2 = 6
Thus the value of d is 6.

Question 13.
8.7 = r − 1.4
r = ________

Answer: 10.1

Explanation:
The given equation is
8.7 = r − 1.4
r − 1.4 = 8.7
r = 8.7 + 1.4
r = 10.1
The value of r is 10.1

Question 14.
The temperature dropped 8 degrees between 6:00 p.m. and midnight. The temperature at midnight was 26ºF. Write and solve an equation to find the temperature at 6:00 p.m.
________ ºF

Answer: 34ºF

Explanation:
The temperature dropped 8 degrees between 6:00 p.m. and midnight.
The temperature at midnight was 26ºF.
26ºF + 8ºF = 34ºF
The equation to find the temperature at 6:00 p.m is 34ºF

Question 15.
Reason Abstractly Write an addition equation that has the solution x = 9.
Type below:
_____________

Answer: x + 4 = 13

Explanation:
Let the equation be x + 4 = 13
x = 13 – 4
x = 9

Unlock the Problem – Page No. 442

Question 16.
In July, Kimberly made two deposits into her bank account. She made no withdrawals. At the end of July, her account balance was $120.62. Write and solve an equation to find Kimberly’s balance at the beginning of July.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 6
a. What do you need to find?
Type below:
_____________

Answer: We need to find Kimberly’s balance at the beginning of July.

Question 16.
b. What information do you need from the bank statement?
Type below:
_____________

Answer: We need the information about the deposit on July 12 and July 25 from the bank statement.

Question 16.
c. Write an equation you can use to solve the problem. Explain what the variable represents.
Type below:
_____________

Answer:
x = bank account balance
y = deposit 1
z = deposit 2
x = y + z

Question 16.
d. Solve the equation. Show your work and describe each step.
Type below:
_____________

Answer: 120.62 = y + z
Where y is the deposit 1 and z represents the deposit 2.
y = $45.50, z = $43.24
45.50 + 43.24 = 88.74
x + 88.74 = 120.62

Question 16.
e. Write Kimberly’s balance at the beginning of July.
$ _______

Answer: 31.88

Explanation:
x + 88.74 = 120.62
x = 120.62 – 88.74
x = $31.88
Kimberly’s balance at the beginning of July is $31.88

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 442 Q17

Question 18.
Select the equations that have the solution n = 23. Mark all that apply.
Options:
a. 16 + n = 39
b. n – 4 = 19
c. 25 = n – 2
d. 12 = n – 11

Answer: A, B, D

Explanation:
a. 16 + n = 39
n = 23
16 + 23 = 39
39 = 39
The variable is a solution.
b. n – 4 = 19
n = 23
23 – 4 = 19
19 = 19
The variable is a solution.
c. 25 = n – 2
25 = 23 – 2
25 ≠ 21
The variable is not a solution.
d. 12 = n – 11
n = 23
12 = 23 – 11
12 = 12
The variable is a solution.
Thus the correct answers are options A, B, D.

Solve Addition and Subtraction Equations – Page No. 443

Solve Addition and Subtraction Equations - Page No. 443

Solve the equation, and check the solution.

Question 1.
y − 14 = 23
y = _______

Answer: 37

Explanation:
y − 14 = 23
y = 23 + 14
y = 37
Thus the solution is 37.

Question 2.
x + 3 = 15
x = _______

Answer: 12

Explanation:
The equation is x + 3 = 15
x = 15 – 3
x = 12
The solution is 12.

Question 3.
n + \(\frac{2}{5}=\frac{4}{5}\)
n = _______ \(\frac{□}{□}\)

Answer: \(\frac{2}{5}\)

Explanation:
The equation is n + \(\frac{2}{5}=\frac{4}{5}\)
n + \(\frac{2}{5}\) = \(\frac{4}{5}\)
n = \(\frac{4}{5}\) – \(\frac{2}{5}\)
n = (4 – 2)/5
n = \(\frac{2}{5}\)
Thus the solution is \(\frac{2}{5}\)

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 443 Q4

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 443 Q5

Question 6.
s + 55 = 55
s = _______

Answer: 0

Explanation:
The equation is s + 55 = 55
s = 55 – 55
s = 0
The solution is s = 0

Question 7.
23 = x − 12
x = _______

Answer: 35

Explanation:
The given equation is 23 = x – 12
x – 12 = 23
x = 23 + 12
x = 35
The solution is x = 35.

Question 8.
p − 14 = 14
p = _______

Answer: 28

Explanation:
The given equation is p − 14 = 14
p = 14 + 14
p = 28
The solution is p = 28.

Question 9.
m − \(2 \frac{3}{4}=6 \frac{1}{2}\)
m = _______ \(\frac{□}{□}\)

Answer: 9 \(\frac{1}{4}\)

Explanation:
The given equation is m − \(2 \frac{3}{4}=6 \frac{1}{2}\)
m – 2 \(\frac{3}{4}\) = 6 \(\frac{1}{2}\)
m = 6 \(\frac{1}{2}\) + 2 \(\frac{3}{4}\)
m = 6 + 2 + \(\frac{1}{2}\) + \(\frac{3}{4}\)
m = 8 + 1 \(\frac{1}{4}\)
m = 9 \(\frac{1}{4}\)

Problem Solving

Question 10.
A recipe calls for 5 \(\frac{1}{2}\) cups of flour. Lorenzo only has 3 \(\frac{3}{4}\) cups of flour. Write and solve an equation to find the additional amount of flour Lorenzo needs to make the recipe.
Type below:
_____________

Answer: 1 \(\frac{3}{4}\)

Explanation:
A recipe calls for 5 \(\frac{1}{2}\) cups of flour.
Lorenzo only has 3 \(\frac{3}{4}\) cups of flour.
x + 3 \(\frac{3}{4}\) = 5 \(\frac{1}{2}\)
x = 5 \(\frac{1}{2}\) – 3 \(\frac{3}{4}\)
x =  1 \(\frac{3}{4}\)

Question 11.
Jan used 22.5 gallons of water in the shower. This amount is 7.5 gallons less than the amount she used for washing clothes. Write and solve an equation to find the amount of water Jan used to wash clothes.
Type below:
_____________

Answer: 30

Explanation:
Jan used 22.5 gallons of water in the shower.
This amount is 7.5 gallons less than the amount she used for washing clothes.
Let the amount of water Jan used to wash clothes be x
x – 7.5 = 22.5
x = 22.5 + 7.5
x = 30
Therefore the amount of water Jan used to wash clothes is 30 gallons.

Question 12.
Explain how to check if your solution to an equation is correct.
Type below:
_____________

Answer:
i. Evaluate the left-hand side expression at the given value to get a number.
ii. Evaluate the right-hand side expression at the given value to get a number.
iii. See if the numbers match.

Lesson Check – Page No. 444

Question 1.
The price tag on a shirt says $21.50. The final cost of the shirt, including sales tax, is $23.22. The equation 21.50 + t = 23.22 can be used to find the amount of sales tax t in dollars. What is the sales tax?
$ _______

Answer: 1.72

Explanation:
The price tag on a shirt says $21.50.
The final cost of the shirt, including sales tax, is $23.22.
The equation is 21.50 + t = 23.22
t = 23.22 – 21.50
t = 1.72
Therefore the sales tax is $1.72 dollars.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 444 Q2

Spiral Review

Question 3.
How would you convert a mass in centigrams to a mass in milligrams?
Type below:
_____________

Answer: The conversion factor is 10; so 1 centigram = 10 milligrams. In other words, the value in cg multiplies by 10 to get a value in mg.

Question 4.
In the expression 4 + 3x + 5y, what is the coefficient of x?
The coefficient is _______

Answer:
A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
Thus the coefficient of 3x is 3.

Question 5.
Write an expression that is equivalent to 10c.
Type below:
_____________

Answer:
-2(-5c) expand the brackets
-2 × -5c
= 10c

Question 6.
Miranda bought a $7-movie ticket and popcorn for a total of $10. The equation 7 + x = 10 can be used to find the cost x in dollars of the popcorn. How much did the popcorn cost?
$ _______

Answer: 3

Explanation:
Miranda bought a $7-movie ticket and popcorn for a total of $10.
The equation is 7 + x = 10
x = 10 – 7
x = 3
Therefore the cost of the popcorn is $3.

Share and Show – Page No. 447

Model and solve the equation by using algebra tiles.

Question 1.
4x = 16
x = _______

Answer: 4

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 4x in the left rectangle, and model 16 in the right rectangle.
  • There are four x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into 4 equal groups.

Question 2.
3x = 12
x = _______

Answer: 4

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 3x in the left rectangle, and model 12 in the right rectangle.
  • There are three x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into 3 equal groups.

Question 3.
4 = 4x
x = _______

Answer: 1

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 4x in the left rectangle, and model 4 in the right rectangle.
  • There are four x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into 4 equal groups.

Question 4.
3x = 9
x = _______

Answer: 3

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 3x in the left rectangle, and model 9 in the right rectangle.
  • There are three x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into 3 equal groups.

Question 5.
2x = 10
x = _______

Answer: 5

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 2x in the left rectangle, and model 10 in the right rectangle.
  • There are two x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into two equal groups.

Question 6.
15 = 5x
x = _______

Answer: 3

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 5x in the left rectangle, and model 15 in the right rectangle.
  • There are five x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into five equal groups.

Solve the equation by drawing a model.

Question 7.
4x = 8
x = _______

Answer: 2
Go Math Grade 6 Answer Key 8th chapter solution img-11

Question 8.
3x = 18
x = _______

Answer: 6
6th Grade Go Math Solution Key solution img-12

Problem Solving + Applications

Question 9.
Communicate Explain the steps you use to solve a multiplication equation with algebra tiles.
Type below:
_____________

Answer:
To solve an equation, model the terms of the equation on both sides of an equals sign.
Isolate the variable on one side by adding opposites and creating zero pairs.
To remove a factor from the variable, divide the sides into rows equal to the factor, and distribute the terms equally among all the rows.

Page No. 448

The bar graph shows the number of countries that competed in the first four modern Olympic Games. Use the bar graph for 10–11.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 7

Question 10.
Naomi is doing a report about the 1900 and 1904 Olympic Games. Each page will contain info7rmation about 4 of the countries that competed each year. Write and solve an equation to find the number of pages Naomi will need.
_______ pages

Answer: 9 pages

Explanation:
By seeing the above table we can say that the equation is 4x = 36
The number of countries that competed in the 1900 summer Olympic games is 24.
The number of countries that competed in the 1904 summer Olympic games is 12.
The total number of countries competed in total is 36.
Each page of Naomi’s report contains information about 4 of the countries that competed each year.
4x = 36
x = 36/4
x = 9
Thus Naomi would require 9 pages to complete her report.

Question 11.
Pose a Problem Use the information in the bar graph to write and solve a problem involving a multiplication equation.
Type below:
_____________

Answer:
By seeing the above table we can say that the equation is 4x = 72
The number of countries that competed in the 1900 summer Olympic games is 24.
The number of countries that competed in the 1904 summer Olympic games is 12.
The number of countries that competed in the 1896 summer Olympic games is 14.
The number of countries that competed in the 1908 summer Olympic games is 22.
The total number of countries competed in total is 72.
4x = 72
x = 72/4
x = 18

Question 12.
The equation 7s = 21 can be used to find the number of snakes s in each cage at a zoo. Solve the equation. Then tell what the solution means.
s = _______

Answer: 3

Explanation:
The equation 7s = 21 can be used to find the number of snakes s in each cage at a zoo. Solve the equation.
7 × s = 21
s = 21/7 = 3
The solution s is 3.

Question 13.
A choir is made up of 6 vocal groups. Each group has an equal number of singers. There are 18 singers in the choir. Solve the equation 6p = 18 to find the number of singers in each group. Use a model.
_______ singers

Answer: 3 singers

Explanation:
A choir is made up of 6 vocal groups. Each group has an equal number of singers.
There are 18 singers in the choir.
The equation 6p = 18
p = 18/6 = 3
p = 3
The solution p is 3.

Model and Solve Multiplication Equations – Page No. 449

Model and solve the equation by using algebra tiles.

Question 1.
2x = 8
x = _______

Answer: 4

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 2x in the left rectangle, and model 8 in the right rectangle.
  • There are two x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into two equal groups.

Question 2.
5x = 10
x = _______

Answer: 2

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 5x in the left rectangle, and model 10 in the right rectangle.
  • There are five x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into five equal groups.

Question 3.
21 = 3x
x = _______

Answer: 7

Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 3x in the left rectangle, and model 21 in the right rectangle.
  • There are three x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into three equal groups.

Solve the equation by drawing a model.

Question 4.
6 = 3x

Answer: 2
HMH Go Math Grade 6 Key Chapter 8 solution img-13

Question 5.
4x = 12
x = _______

Answer: 3
Go Math 6th Grade Answer Key chapter 8 solution img-14

Problem Solving

Question 6.
A chef used 20 eggs to make 5 omelets. Model and solve the equation 5x = 20 to find the number of eggs x in each omelet.
_______ eggs

Answer: 4

Explanation:
A chef used 20 eggs to make 5 omelets.
The equation is 5x = 20
x = 50/5 = 4
Thus there are 4 eggs in each omelet.

Question 7.
Last month, Julio played 3 times as many video games as Scott did. Julio played 18 video games. Write and solve an equation to find the number of video games Scott played.
_______ video games

Answer: 6

Explanation:
Last month, Julio played 3 times as many video games as Scott did. Julio played 18 video games.
The equation will be 3x = 18
x = 18/3 = 6
x = 6
The number of video games Scott played is 6.

Question 8.
Write a multiplication equation, and explain how you can solve it by using a model.
Type below:
_____________

Answer:
15 = 5x
Explanation:

  • Draw 2 rectangles on your Mathboard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model 5x in the left rectangle, and model 15 in the right rectangle.
  • There are five x tiles on the left side of your model. To solve the equation by using the model, you need to find the value of one x tile.
  • To do this, divide each side of your model into five equal groups.

Lesson Check – Page No. 450

Question 1.
What is the solution of the equation that is modeled by the algebra tiles?
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 8
x = 1 _______

Answer: 1

Explanation:
The equation for the above figure is 3x = 3
Substitute x = 1
3(1) = 3
3/3 = 1
Thus the solution is 1.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 450 Q2

Spiral Review

Question 3.
A rectangle is 12 feet wide and 96 inches long. What is the area of the rectangle?
_______ square feet

Answer: 1152

Explanation:
A rectangle is 12 feet wide and 96 inches long.
Area of rectangle is l × w
A = 12 × 96
A = 1152 square feet.
Thus the area of the rectangle is 1152 square feet.

Question 4.
Evaluate the algebraic expression 24 – x ÷ y for x = 8 and y = 2.
_______

Answer: 20

Explanation:
24 – x ÷ y for x = 8 and y = 2.
Substitute the value of x and y in the equation.
24 – (8 ÷ 2)
24 – 4 = 20

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 450 Q5

Question 6.
A pet store usually keeps 12 birds per cage, and there are 7 birds in the cage now. The equation 7 + x = 12 can be used to find the remaining number of birds x that can be placed in the cage. What is the solution to the equation?
x = _______

Answer: 5

Explanation:
A pet store usually keeps 12 birds per cage, and there are 7 birds in the cage now.
The equation is 7 + x = 12
x = 12 – 7
x = 5
Thus the solution of the equation is 5.

Share and Show – Page No. 453

Question 1.
Solve the equation 2.5m = 10.
m = _______

Answer: 4

Explanation:
2.5m = 10
m = 10/2.5
m = 4

Solve the equation, and check the solution.

Question 2.
3x = 210
x = _______

Answer: 70

Explanation:
3x = 210
x = 210/3
x = 70

Question 3.
2.8 = 4t
t = _______

Answer: 0.7

Explanation:
2.8 = 4t
4t = 2.8
t = 2.8/4
t = 0.7

Question 4.
\(\frac{1}{3}\)n = 15
n = _______

Answer: 45

Explanation:
\(\frac{1}{3}\)n = 15
n = 15 × 3
n = 45

Question 5.
\(\frac{1}{2}\)y = \(\frac{1}{10}\)
y = _______

Answer: \(\frac{1}{5}\)

Explanation:
\(\frac{1}{2}\)y = \(\frac{1}{10}\)
y = \(\frac{1}{10}\) × 2
y = \(\frac{1}{5}\)

Question 6.
25 = \(\frac{a}{5}\)
a = _______

Answer: 125

Explanation:
25 = \(\frac{a}{5}\)
a = 25 × 5
a = 125

Question 7.
1.3 = \(\frac{c}{4}\)
c = _______

Answer: 5.2

Explanation:
1.3 = \(\frac{c}{4}\)
c = 1.3 × 4
c = 5.2

On Your Own

Practice: Copy and Solve Solve the equation, and check the solution.

Question 8.
150 = 6m
m = _______

Answer: 25

Explanation:
6m = 150
m = 150/6
m = 25

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 453 Q9

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 453 Q10

Question 11.
There are 100 calories in 8 fluid ounces of orange juice and 140 calories in 8 fluid ounces of pineapple juice. Tia mixed 4 fluid ounces of each juice. Write and solve an equation to find the number of calories in each fluid ounce of Tia’s juice mixture.
_______ calories

Answer: 15 calories

Explanation:
Number of calories in 8 ounces of orange juice = 100
Number of calories in 1 ounce of juice = 100/8
Number of calories in 4 ounces of juice 100/8 × 4 = 50 calories
Number of calories in 8 ounces of pineapple juice = 140
Number of calories in 1 ounce of juice = 140/8
Number of calories in 4 ounces of pineapple juice = 140/8 × 4 =70 calories
Now the mixture has 50 + 70 calories = 120 calories in 8 ounces
So, 1 ounce of the mixture has 120/8 = 15 calories.

Question 12.
Write a division equation that has the solution x = 16.
Type below:
_____________

Answer:
2x = 32
x = 32/2
x = 16
Thus the equation is x = 16.

Problem Solving + Applications – Page No. 454

What’s the Error?

Question 13.
Melinda has a block of clay that weighs 14.4 ounces. She divides the clay into 6 equal pieces. To find the weight w in ounces of each piece, Melinda solved the equation 6w = 14.4.
Look at how Melinda solved the equation. Find her error.
6w = 14.4
\(\frac{6 w}{6}\) = 6 × 14.4
w = 86.4
Correct the error. Solve the equation, and explain your steps.
Describe the error that Melinda made
Type below:
_____________

Answer:
Melinda has a block of clay that weighs 14.4 ounces. She divides the clay into 6 equal pieces.
The equation is 6w = 14.4
Their error of Melinda is she used the multiplication equation to solve the equation.
She must have used the division equation to get the solution.
6w = 14.4
w = 14.4/6
w = 2.4

Question 14.
For numbers 14a−14d, choose Yes or No to indicate whether the equation has the solution x = 15.
14a. 15x = 30
14b. 4x = 60
14c. \(\frac{x}{5}\) = 3
14d. \(\frac{x}{3}\) = 5
14a. _____________
14b. _____________
14c. _____________
14d. _____________

Answer:
Given the value of x is 15
14a. 15x = 30
15 × 15 = 30
225 ≠ 30
The answer is No.
14b. 4x = 60
4 × 15 = 60
60 = 60
The answer is yes.
14c. \(\frac{x}{5}\) = 3
x/5 = 3
15/5 = 3
3 = 3
The answer is yes.
14d. \(\frac{x}{3}\) = 5
x/3 = 5
15/3 = 5
5 = 5
The answer is yes.

Solve Multiplication and Division Equations – Page No. 455

Solve the equation, and check the solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 455 Q1

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 455 Q2

Question 3.
3.5x = 14.7
x = ________

Answer: 4.2

Explanation:
The given equation is
3.5x = 14.7
x = 14.7/3.5
x = 4.2
The solution x is 4.2

Question 4.
32 = 3.2c
c = ________

Answer: 10

Explanation:
The given equation is
32 = 3.2c
3.2 × c = 32
c = 32/3.2
c = 1/0.1 = 10
The solution c is 10.

Question 5.
\(\frac{2}{5}\)w = 40
w = ________

Answer: 100

Explanation:
The given equation is
\(\frac{2}{5}\)w = 40
\(\frac{2}{5}\) × w = 40
w = 40 × 5/2
w = 200/2
w = 100

Question 6.
\(\frac{a}{14}\) = 6.8
a = ________

Answer: 95.2

Explanation:
The given equation is
\(\frac{a}{14}\) = 6.8
a = 6.8 × 14
a = 95.2

Question 7.
1.6x = 1.6
x = ________

Answer: 1

Explanation:
The given equation is
1.6x = 1.6
x = 1.6/1.6
x = 1
The solution x is 1

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 455 Q8

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 455 Q9

Problem Solving

Question 10.
Anne runs 6 laps on a track. She runs a total of 1 mile, or 5,280 feet. Write and solve an equation to find the distance, in feet, that she runs in each lap.
________ feet

Answer: 880

Explanation:
Anne runs 6 laps on a track. She runs a total of 1 mile, or 5,280 feet.
Let the l represents the runs in each lap.
6 × l = 5280 feet
l = 5280/6
l = 880 feet
Therefore Anne runs 880 feets in each lap.

Question 11.
In a serving of 8 fluid ounces of pomegranate juice, there are 32.8 grams of carbohydrates. Write and solve an equation to find the amount of carbohydrates in each fluid ounce of the juice.
________ grams

Answer: 4.1

Explanation:
Given, In a serving of 8 fluid ounces of pomegranate juice, there are 32.8 grams of carbohydrates.
Let c represents the amount of carbohydrates in each fluid ounce of the juice
8 × c = 32.8 grams
c = 32.8/8
c = 4.1 grams

Question 12.
Write and solve a word problem that can be solved by solving a multiplication equation.
Type below:
_____________

Answer:
The quotient of 6 and p is 12
6 ÷ p = 12
p = 6/12
p = 1/2

Lesson Check – Page No. 456

Question 1.
Estella buys 1.8 pounds of walnuts for a total of $5.04. She solves the equation 1.8p = 5.04 to find the price p in dollars of one pound of walnuts. What does one pound of walnuts cost?
$ ________

Answer: 2.8

Explanation:
Given that, Estella buys 1.8 pounds of walnuts for a total of $5.04.
p represents the price in dollars of one pound of walnuts.
The equation to find one pound of walnuts cost is 1.8p = 5.04
1.8p = 5.04
p = 5.04/1.8
p = 2.8
Therefore the cost of one pound of walnuts is $2.8

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 456 Q2

Spiral Review

Question 3.
At top speed, a coyote can run at a speed of 44 miles per hour. If a coyote could maintain its top speed, how far could it run in 15 minutes?
________ miles

Answer: 11

Explanation:
At top speed, a coyote can run at a speed of 44 miles per hour.
Convert from minutes to hour.
60 minutes = 1 hour
15 minutes = 15 × 1/60 = 0.25 = 1/4
44 × 1/4 = 11 miles
A coyote can run at a speed of 11 miles for 15 minutes.

Question 4.
An online store sells DVDs for $10 each. The shipping charge for an entire order is $5.50. Frank orders d DVDs. Write an expression that represents the total cost of Frank’s DVDs.
Type below:
_____________

Answer: 10d + $5.50

Explanation:
An online store sells DVDs for $10 each.
The shipping charge for an entire order is $5.50. Frank orders d DVDs.
The expression will be the product of 10 and d more than 5.50
The expression is 10d + $5.50

Question 5.
A ring costs $27 more than a pair of earrings. The ring costs $90. Write an equation that can be used to find the cost c in dollars of the earrings.
Type below:
_____________

Answer: $90 – $27 = c

Explanation:
A ring costs $27 more than a pair of earrings.
The ring costs $90.
c represents the cost in dollars of the earrings.
Thus the equation is c + $27 = $90
c = $90 – $27.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 456 Q6

Share and Show – Page No. 459

Question 1.
Connor ran 3 kilometers in a relay race. His distance represents \(\frac{3}{10}\) of the total distance of the race. The equation \(\frac{3}{10}\)d = 3 can be used to find the total distance d of the race in kilometers. What was the total distance of the race?
________ kilometers

Answer: 10

Explanation:
Connor ran 3 kilometers in a relay race.
His distance represents \(\frac{3}{10}\) of the total distance of the race.
\(\frac{3}{10}\)d = 3
3 × d = 3 × 10
3 × d = 30
d = 30/3 = 10 kilometers
Therefore the total distance of the race is 10 kilometers.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 459 Q2

Question 3.
The lightest puppy in a litter weighs 9 ounces, which is \(\frac{3}{4}\) of the weight of the heaviest puppy. The equation \(\frac{3}{4}\)w = 9 can be used to find the weight w in ounces of the heaviest puppy. How much does the heaviest puppy weigh?
________ ounces

Answer: 12

Explanation:
The lightest puppy in a litter weighs 9 ounces, which is \(\frac{3}{4}\) of the weight of the heaviest puppy.
\(\frac{3}{4}\)w = 9
3 × w = 9 × 4
3 × w = 36
w = 36/3
w = 12
The heaviest puppy weighs 12 ounces.

Question 4.
Sophia took home \(\frac{2}{5}\) of the pizza that was left over from a party. The amount she took represents \(\frac{1}{2}\) of a whole pizza. The equation \(\frac{2}{5}\)p = \(\frac{1}{2}\) can be used to find the number of pizzas p left over from the party. How many pizzas were left over?
_______ \(\frac{□}{□}\) pizzas

Answer: 1 \(\frac{1}{4}\) pizzas

Explanation:
Sophia took home \(\frac{2}{5}\) of the pizza that was left over from a party.
The amount she took represents \(\frac{1}{2}\) of a whole pizza.
\(\frac{2}{5}\)p = \(\frac{1}{2}\)
p = \(\frac{1}{2}\) × \(\frac{5}{2}\)
p = \(\frac{5}{4}\)
p = 1 \(\frac{1}{4}\) pizzas
1 \(\frac{1}{4}\) pizzas were leftover.

Question 5.
A city received \(\frac{3}{4}\) inch of rain on July 31. This represents \(\frac{3}{10}\) of the total amount of rain the city received in July. The equation \(\frac{3}{10}\)r = \(\frac{3}{4}\) can be used to find the amount of rain r in inches the city received in July. How much rain did the city receive in July?
_______ \(\frac{□}{□}\) inches of rain

Answer: 2 \(\frac{1}{2}\) inches of rain

Explanation:
A city received \(\frac{3}{4}\) inch of rain on July 31.
This represents \(\frac{3}{10}\) of the total amount of rain the city received in July.
\(\frac{3}{10}\)r = \(\frac{3}{4}\)
r = \(\frac{3}{4}\) × \(\frac{10}{3}\)
r = \(\frac{30}{12}\)
r = \(\frac{5}{2}\)
r = 2 \(\frac{1}{2}\)
The city received 2 \(\frac{1}{2}\) inches of rain in July.

On Your Own – Page No. 460

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 460 Q6
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 460 Q6.1

Question 7.
A dog sled race is 25 miles long. The equation \(\frac{5}{8}\)k = 25 can be used to estimate the race’s length k in kilometers. Approximately how many hours will it take a dog sled team to finish the race if it travels at an average speed of 30 kilometers per hour?
_______ \(\frac{□}{□}\) hours

Answer: 1 \(\frac{1}{3}\) hours

Explanation:
A dog sled race is 25 miles long.
The equation \(\frac{5}{8}\)k = 25
k represents race length in kilometers.
\(\frac{5}{8}\)k = 25
5 × k = 25 × 8
5k = 200
k = 200/5 = 40
k = 40
Average speed is k/30
40/30 = 4/3
The average speed of 30 kilometers per hour is 1 \(\frac{1}{3}\) hours.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 460 Q8

Question 9.
In a basket of fruit, \(\frac{5}{6}\) of the pieces of fruit are apples. There are 20 apples in the display. The equation \(\frac{5}{6}\)f = 20 can be used to find how many pieces of fruit f are in the basket. Use words and numbers to explain how to solve the equation to find how many pieces of fruit are in the basket.
_______ pieces of fruit

Answer: 24

Explanation:
In a basket of fruit, \(\frac{5}{6}\) of the pieces of fruit are apples.
There are 20 apples in the display.
\(\frac{5}{6}\)f = 20
5 × f = 20 × 6
5 × f = 120
f = 120/5
f = 24
There are 24 pieces of friut in the basket.

Problem Solving Equations with Fractions – Page No. 461

Read each problem and solve.

Question 1.
Stu is 4 feet tall. This height represents \(\frac{6}{7}\) of his brother’s height. The equation \(\frac{6}{7}\)h = 4 can be used to find the height h, in feet, of Stu’s brother. How tall is Stu’s brother?
______ \(\frac{□}{□}\) feet

Answer: 4 \(\frac{2}{3}\) feet

Explanation:
Stu is 4 feet tall. This height represents \(\frac{6}{7}\) of his brother’s height.
The equation \(\frac{6}{7}\)h = 4
6/7 × h = 4
6 × h = 4 × 7
6 × h =28
h = 28/6
h = 14/3
h = 4 \(\frac{2}{3}\) feet
Thus the height of Stu’s brother in feet is 4 \(\frac{2}{3}\) feet.

Question 2.
Bryce bought a bag of cashews. He served \(\frac{7}{8}\) pound of cashews at a party. This amount represents \(\frac{2}{3}\) of the entire bag. The equation \(\frac{2}{3}\)n = \(\frac{7}{8}\) can be used to find the number of pounds n in a full bag. How many pounds of cashews were in the bag that Bryce bought?
______ \(\frac{□}{□}\) pounds

Answer: 1 \(\frac{5}{16}\)

Explanation:
Bryce bought a bag of cashews.
He served \(\frac{7}{8}\) pound of cashews at a party.
This amount represents \(\frac{2}{3}\) of the entire bag.
\(\frac{2}{3}\)n = \(\frac{7}{8}\)
n = \(\frac{7}{8}\) × \(\frac{3}{2}\)
n = \(\frac{21}{16}\)
n = 1 \(\frac{5}{16}\)
Bryce bought 1 \(\frac{5}{16}\) pounds of cashews were in the bag.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 461 Q3
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 461 Q3.1

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 461 Q4

Lesson Check – Page No. 462

Question 1.
Roger served \(\frac{5}{8}\) pound of crackers, which was \(\frac{2}{3}\) of the entire box. What was the weight of the crackers originally in the box?
\(\frac{□}{□}\) pounds

Answer: \(\frac{15}{16}\) pounds

Explanation:
Roger served \(\frac{5}{8}\) pound of crackers, which was \(\frac{2}{3}\)
\(\frac{2}{3}\) × p = \(\frac{5}{8}\)
p = \(\frac{5}{8}\) × \(\frac{3}{2}\)
p = \(\frac{15}{16}\) pounds
\(\frac{15}{16}\) was the weight of the crackers originally in the box.

Question 2.
Bowser ate 4 \(\frac{1}{2}\) pounds of dog food. That amount is \(\frac{3}{4}\) of the entire bag of dog food. How many pounds of dog food were originally in the bag?
______ pounds

Answer 6 pounds

Explanation:
Bowser ate 4 \(\frac{1}{2}\) pounds of dog food.
That amount is \(\frac{3}{4}\) of the entire bag of dog food.
4 \(\frac{1}{2}\) = \(\frac{9}{2}\)
\(\frac{3}{4}\) p = \(\frac{9}{2}\)
p = \(\frac{9}{2}\) × \(\frac{4}{3}\)
p = 6 pounds
6 pounds of dog food were originally in the bag.

Spiral Review

Question 3.
What is the quotient 4 \(\frac{2}{3}\) ÷ 4 \(\frac{1}{5}\)
_______ \(\frac{□}{□}\)

Answer: 1 \(\frac{1}{9}\)

Explanation:
4 \(\frac{2}{3}\) ÷ 4 \(\frac{1}{5}\)
\(\frac{14}{3}\) ÷ \(\frac{21}{5}\)
= \(\frac{70}{63}\)
The mixed fraction of \(\frac{70}{63}\) is 1 \(\frac{1}{9}\)
4 \(\frac{2}{3}\) ÷ 4 \(\frac{1}{5}\) = 1 \(\frac{1}{9}\)

Question 4.
Miranda had 4 pounds, 6 ounces of clay. She divided it into 10 equal parts. How heavy was each part?
_______ ounces

Answer: 7 ounces

Explanation:
Miranda had 4 pounds, 6 ounces of clay.
She divided it into 10 equal parts.
Convert from pounds to ounces
We know that
1 pound = 16 ounces
4 pounds = 4 × 16 ounces = 64 ounces
64 ounces + 6 ounces = 70 ounces
Now divide 70 ounces into 10 equal parts.
70 ÷ 10 = 7 ounces.
Thus each part was 7 ounces.

Question 5.
The amount Denise charges to repair computers is $50 an hour plus a $25 service fee. Write an expression to show how much she will charge for h hours of work.
Type below:
_____________

Answer: 50h + 25

Explanation:
The amount Denise charges to repair computers is $50 an hour plus a $25 service fee.
The expression will be the product of 50 and h more than 25.
The expression is 50h + 25.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 462 Q6

Mid-Chapter Checkpoint – Vocabulary – Page No. 463

Choose the best term from the box to complete the sentence.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 9

Question 1.
A(n) _____ is a statement that two mathematical expressions are equal.
Type below:
_____________

Answer: An equation is a mathematical statement that two expressions are equal.

Question 2.
Adding 5 and subtracting 5 are _____.
Type below:
_____________

Answer: Solution of an equation.

Concepts and Skills

Write an equation for the word sentence.

Question 3.
The sum of a number and 4.5 is 8.2.
Type below:
_____________

Answer:
The phrase “sum” indicates an addition operation.
So, the equation is n + 4.5 = 8.2

Question 4.
Three times the cost is $24.
Type below:
_____________

Answer:
The phrase “times” indicates multiplication.
Multiply 3 with c.
3c = 24

Determine whether the given value of the variable is a solution of the equation.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 463 Q5

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 463 Q6

Solve the equation, and check the solution.

Question 7.
a + 2.4 = 7.8
a = _____

Answer: 5.4

Explanation:
Given the equation is a + 2.4 = 7.8
a + 2.4 = 7.8
a = 7.8 – 2.4
a = 5.4

Question 8.
\(b-\frac{1}{4}=3 \frac{1}{2}\)
b = _______ \(\frac{□}{□}\)

Answer: 3 \(\frac{3}{4}\)

Explanation:
Given the equation is \(b-\frac{1}{4}=3 \frac{1}{2}\)
b – \(\frac{1}{4}\) = 3 \(\frac{1}{2}\)
b = 3 \(\frac{1}{2}\) + \(\frac{1}{4}\)
b = 3 + \(\frac{1}{4}\) + \(\frac{1}{2}\)
b = 3 \(\frac{3}{4}\)

Question 9.
3x = 27
x = _______

Answer: 9

Explanation:
Given the equation is 3x = 27
x = 27/3
x = 9

Question 10.
\(\frac{1}{3} s=\frac{1}{5}\)
s = \(\frac{□}{□}\)

Answer: \(\frac{3}{5}\)

Explanation:
Given the equation is \(\frac{1}{3} s=\frac{1}{5}\)
\(\frac{1}{3}\)s = \(\frac{1}{5}\)
s = \(\frac{3}{5}\)

Question 11.
\(\frac{t}{4}\) = 16
t = _______

Answer: 64

Explanation:
Given the equation is \(\frac{t}{4}\) = 16
t = 16 × 4
t = 64

Question 12.
\(\frac{w}{7}\) = 0.3
w = _______

Answer: 2.1

Explanation:
\(\frac{w}{7}\) = 0.3
w/7 = 0.3
w = 0.3 × 7
w = 2.1

Page No. 464

Question 13.
A stadium has a total of 18,000 seats. Of these, 7,500 are field seats, and the rest are grandstand seats. Write an equation that could be used to find the number of grandstand seats s.
Type below:
_____________

Answer: s + 7500 = 18000

Explanation:
A stadium has a total of 18,000 seats.
Of these, 7,500 are field seats, and the rest are grandstand seats.
Let s be the number of grandstand seats.
s + 7,500 = 18,000

Question 14.
Aaron wants to buy a bicycle that costs $128. So far, he has saved $56. The equation a + 56 = 128 can be used to find the amount a in dollars that Aaron still needs to save. What is the solution of the equation?
The solution is _______

Answer: 72

Explanation:
Aaron wants to buy a bicycle that costs $128. So far, he has saved $56.
The equation a + 56 = 128
a = 128 – 56
a = 72
The solution of the equation a + 56 = 128 is 72.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 464 Q15

Question 16.
Crystal is picking blueberries. So far, she has filled \(\frac{2}{3}\) of her basket, and the blueberries weigh \(\frac{3}{4}\) pound. The equation \(\frac{2}{3}\)w = \(\frac{3}{4}\) can be used to estimate the weight w in pounds of the blueberries when the basket is full. About how much will the blueberries in Crystal’s basket weigh when it is full?
______ \(\frac{□}{□}\) pounds

Answer: 1 \(\frac{1}{8}\) pounds

Explanation:
Crystal is picking blueberries. So far, she has filled \(\frac{2}{3}\) of her basket, and the blueberries weigh \(\frac{3}{4}\) pound.
The equation \(\frac{2}{3}\)w = \(\frac{3}{4}\)
w = \(\frac{3}{4}\) × \(\frac{3}{2}\)
w = \(\frac{9}{8}\)
The mixed fraction of \(\frac{9}{8}\) is 1 \(\frac{1}{8}\) pounds

Share and Show – Page No. 467

Determine whether the given value of the variable is a solution of the inequality.

Question 1.
a ≥ −6, a = −3
The variable is _____________

Answer: a solution

Explanation:
Substitute the solution a in the inequality.
a = -3
-3 ≥ -6
-3 is greater than -6
Thus the variable is a solution.

Question 2.
y < 7.8, y = 8 The variable is _____________

Answer: not a solution

Explanation:
Substitute the solution y in the inequality.
y = 8
8 is less than 7.8
8<7.8
The variable is not the solution.

Question 3.
c > \(\frac{1}{4}\), c = \(\frac{1}{5}\)
The variable is _____________

Answer: not a solution

Explanation:
Substitute the solution c in the inequality.
c = \(\frac{1}{5}\)
\(\frac{1}{5}\) > \(\frac{1}{4}\)
\(\frac{1}{5}\) is greater than \(\frac{1}{4}\)
\(\frac{1}{5}\) > \(\frac{1}{4}\)
Thus the variable is a solution.

Question 4.
x ≤ 3, x = 3
The variable is _____________

Answer: a solution

Explanation:
Substitute the solution x in the inequality.
x = 3
3 ≤ 3
3 is less than or equal to 3.
Thus the variable is a solution.

Question 5.
d < 0.52, d = 0.51
The variable is _____________

Answer: not a solution

Explanation:
Substitute the solution d in the inequality.
-0.51 < -0.52
-0.51 is greater than -0.52
The variable is not the solution.

Question 6.
t ≥ \(\frac{2}{3}\), t = \(\frac{3}{4}\)
The variable is _____________

Answer: a solution

Explanation:
Substitute the solution t in the inequality.
t = \(\frac{3}{4}\)
\(\frac{3}{4}\) ≥ \(\frac{2}{3}\)
\(\frac{3}{4}\) is greater than \(\frac{2}{3}\)
Thus the variable is a solution.

On Your Own

Practice: Copy and Solve Determine whether s = \(\frac{3}{5}\), s = 0, or s = 1.75 are solutions of the inequality.

Question 7.
s > 1
Type below:
_____________

Answer:
s > 1
s = \(\frac{3}{5}\)
\(\frac{3}{5}\) > -1
\(\frac{3}{5}\) is greater than -1.
The variable is the solution.
s = 0
0 > -1
0 is greater than -1
Thus the variable is a solution.
s = 1.75
1.75 > -1
1.75 is greater than -1
s > -1
Thus the variable is a solution.

Question 8.
s ≤ 1 \(\frac{2}{3}\)
Type below:
_____________

Answer:
s ≤ 1 \(\frac{2}{3}\)
s = \(\frac{3}{5}\)
\(\frac{3}{5}\) ≤ 1 \(\frac{2}{3}\)
\(\frac{3}{5}\) is less than but not equal to 1 \(\frac{2}{3}\)
The variable is not the solution.
s ≤ 1 \(\frac{2}{3}\)
s = 0
0 ≤ 1 \(\frac{2}{3}\)
The variable is not the solution.
s = 1.75
1.75 ≤ 1 \(\frac{2}{3}\)
The variable is not the solution.

Question 9.
s < 0.43
Type below:
_____________

Answer:
s < 0.43
\(\frac{3}{5}\) < 0.43
\(\frac{3}{5}\) = 0.6
0.6 is not less than 0.43
Thus the variable is not the solution.
s = 0
0 < 0.43
0 is less than 0.43
Thus the variable is the solution.
s = 1.75
1.75 < 0.43
1.75 is greater than 0.43
Thus the variable is not the solution.

Give two solutions of the inequality.

Question 10.
e < 3
Type below: _____________

Answer:
The solution to the inequality must be whole numbers less than 3.
e = 1 and 2 are the solutions because 1 and 2 are less than 3.
Thus the 2 solutions are 1 and 2.

Question 11.
p > 12
Type below:
_____________

Answer:
The solution to the inequality must be whole numbers greater than -12
p = 0 and -5 are the solutions because 0 and -5 are greater than -12.
Thus the 2 solutions are 0 and -5.

Question 12.
y ≥ 5.8
Type below:
_____________

Answer:
The solution to the inequality must be whole numbers greater than or equal to 5.8
y = 5.8 and 5.9 are the solutions because 5.8 and 5.9 greater than or equal to 5.8
Thus the 2 solutions are 5.8 and 5.9

Question 13.
Connect Symbols and Words A person must be at least 18 years old to vote. The inequality a ≥ 18 represents the possible ages a in years at which a person can vote. Determine whether a = 18, a = 17\(\frac{1}{2}\), and a = 91.5 are solutions of the inequality, and tell what the solutions mean.
Type below:
_____________

Answer:
a ≥ 18
Substitute the values of a in the inequality
a = 18
18 ≥ 18
Thus the variable is the solution.
a = 17\(\frac{1}{2}\)
17\(\frac{1}{2}\) ≥ 18
17\(\frac{1}{2}\) is less than 18.
The variable is not the solution.
a = 91.5
91.5 > 18
The solution is mean.

Problem Solving + Applcations – Page No. 468

The table shows ticket and popcorn prices at five movie theater chains. Use the table for 14–15.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 10

Question 14.
The inequality p < 4.75 represents the prices p in dollars that Paige is willing to pay for popcorn. The inequality p < 8.00 represents the prices p in dollars that Paige is willing to pay for a movie ticket. At how many theaters would Paige be willing to buy a ticket and popcorn? ______ theater

Answer: 1

Explanation:
The inequality p < 4.75 represents the prices p in dollars that Paige is willing to pay for popcorn. The inequality p < 8.00 represents the prices p in dollars that Paige is willing to pay for a movie ticket.
From the above table, we can see that there is the only theatre with 8.00 and 4.75
So, Paige is willing to buy a ticket and popcorn from 1 theatre.

Question 15.
Sense or Nonsense? Edward says that inequality d ≥ 4.00 represents the popcorn prices in the table, where d is the price of popcorn in dollars. Is Edward’s statement sense or nonsense? Explain. Type below: _____________

Answer: Edward’s statement makes sense because all of the popcorn prices in the table are greater than or equal to $4.00.

Question 16.
Use Math Vocabulary Explain why the statement t > 13 is an inequality.
Type below:
_____________

Answer: The statement is equality because it compares two amounts t and 13 using an inequality symbol.

Question 17.
The minimum wind speed for a storm to be considered a hurricane is 74 miles per hour. The inequality w ≥ 74 represents the possible wind speeds of a hurricane.
Two possible solutions for the inequality w ≥ 74 are _____ and _____.
Two possible solutions for the inequality w ≥ 74 are _____ and _____

Answer: 75 and 80

Explanation:
Given that w is greater than or equal to 74.
The two possible solutions for the inequality w ≥ 74 are 75 and 80.

Solutions of Inequalities – Page No. 469

Determine whether the given value of the variable is a solution of the inequality.

Question 1.
s ≥ 1, s = 1
The variable is _____________

Answer: a solution

Explanation:
The inequality is s ≥ 1
s = 1
1 ≥ 1
1 is a positive number so 1 will be greater than or equal to -1
Thus the variable is a solution.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 469 Q2

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 469 Q3

Question 4.
u > \(\frac{-1}{2}\), u = 0
The variable is _____________

Answer: a solution

Explanation:
The inequality is u > \(\frac{-1}{2}\)
u = 0
0 > \(\frac{-1}{2}\)
0 is greater than \(\frac{-1}{2}\)
Thus the variable is a solution.

Question 5.
q ≥ 0.6, q = 0.23
The variable is _____________

Answer: not a solution

Explanation:
The inequality is q ≥ 0.6
q = 0.23
0.23 is less than 0.6
Thus the variable is a solution.

Question 6.
b < 2 \(\frac{3}{4}\), b = \(\frac{2}{3}\)
The variable is _____________

Answer: a solution

Explanation:
The inequality is b < 2 \(\frac{3}{4}\)
b = \(\frac{2}{3}\)
\(\frac{2}{3}\) < 2 \(\frac{3}{4}\)
\(\frac{2}{3}\) is less than 2 \(\frac{3}{4}\)
Thus the variable is a solution.

Give two solutions of the inequality.

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 469 Q7

Question 8.
z ≥ 3
Type below:
_____________

Answer:
z = -3 and -2 because -3 and -2 are greater than or equal to -3
Thus the two solutions of the inequality are -3 and -2

Question 9.
f ≤ 5
Type below:
_____________

Answer:
f = -5 and -6 because -5 and -6 are less than or equal to -5
Thus the two solutions of the inequality are -5 and -6.

Problem Solving

Question 10.
The inequality s ≥ 92 represents the score s that Jared must earn on his next test to get an A on his report card. Give two possible scores that Jared could earn to get the A.
Type below:
_____________

Answer: Two possible scores that Jared could earn to get the A are 92 and 100.

Question 11.
The inequality m ≤ $20 represents the amount of money that Sheila is allowed to spend on a new hat. Give two possible money amounts that Sheila could spend on the hat.
Type below:
_____________

Answer: Two possible money amounts that Sheilla could spend on the hat are $15 or $10.

Question 12.
Describe a situation and write an inequality to represent the situation. Give a number that is a solution and another number that is not a solution of the inequality.
Type below:
_____________

Answer:
In the United States, the minimum age required to run for president is 35. This can be represented by the inequality a ≥ 35.
A number that is a solution is 55 and a number that is not a solution is 29.

Lesson Check – Page No. 470

Question 1.
Three of the following are solutions of g < 1\(\frac{1}{2}\). Which one is not a solution?
g = 4     g = 7\(\frac{1}{2}\)   g = 0    g = 2\(\frac{1}{2}\)
Type below:
_____________

Answer: g = 0

Explanation:
g < 1\(\frac{1}{2}\).
g = 4
-4 < 1\(\frac{1}{2}\)
g = 7\(\frac{1}{2}\)
7\(\frac{1}{2}\) < 1\(\frac{1}{2}\).
g = 2\(\frac{1}{2}\)
2\(\frac{1}{2}\) < 1\(\frac{1}{2}\)
g = 0
0 < 1\(\frac{1}{2}\)
Thus 0 is not the solution.

Question 2.
The inequality w ≥ 3.2 represents the weight of each pumpkin, in pounds, that is allowed to be picked to be sold. The weights of pumpkins are listed. How many pumpkins can be sold? Which pumpkins can be sold?
3.18 lb, 4 lb, 3.2 lb, 3.4 lb, 3.15 lb
Type below:
_____________

Answer: 3.2 lb, 3.4 lb

Explanation:
The inequality w ≥ 3.2 represents the weight of each pumpkin, in pounds, that is allowed to be picked to be sold.
Substitute the solutions in the inequality.
w = 3.18
3.18 ≥ 3.2
3.18 is less than 3.2
3.18 < 3.2 lb
w = 4 lb
4 ≥ 3.2
4 is greater than 3.2
4 > 3.2
w = 3.2 lb
3.2 ≥ 3.2
3.2 lb is greater than 3.2 lb
w = 3.4 lb
3.4 ≥ 3.2
3.4 lb is greater than 3.2 lb
w = 3.15 lb
3.15 < 3.2
Thus 3.2 lb, 3.4 lb pumpkins can be sold.

Spiral Review

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 470 Q3

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 470 Q4

Question 5.
Tina bought a t-shirt and sandals. The total cost was $41.50. The t-shirt cost $8.95. The equation 8.95 + c = 41.50 can be used to find the cost c in dollars of the sandals. How much did the sandals cost?
$ _______

Answer: $32.55

Explanation:
Tina bought a t-shirt and sandals. The total cost was $41.50. The t-shirt cost $8.95.
The equation is 8.95 + c = 41.50
c = 41.50 – 8.95
c = $32.55
The cost of the sandal is 32.55

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 470 Q6

Share and Show – Page No. 473

Write an inequality for the word sentence. Tell what type of numbers the variable in the inequality can represent.

Question 1.
The elevation e is greater than or equal to 15 meters.
Type below:
_____________

Answer:
The phrase greater than or equal to represents “≥”
Thus the inequality is e ≥ 15

Question 2.
A passenger’s age a must be more than 4 years.
Type below:
_____________

Answer:
The phrase more than represents the greater than symbol “>”
Thus the inequality is a > 4

Write a word sentence for the inequality.

Question 3.
b < \(\frac{1}{2}\)
Type below:
_____________

Answer:
By seeing the above inequality we can write the word sentence for inequality as,
b is less than \(\frac{1}{2}\)

Question 4.
m ≥ 55
Type below:
_____________

Answer:
By seeing the above inequality we can write the word sentence for inequality as,
m is greater than or equal to 55.

On Your Own

Question 5.
Compare Explain the difference between t ≤ 4 and t < 4.
Type below:
_____________

Answer:
t ≤ 4 is t is less than or equal to 4 which means t is equal to 4 or 3.9.
t < 4 is t is less than 4 which means t is equal to 3, 2, or 1 or 0.

Question 6.
A children’s roller coaster is limited to riders whose height is at least 30 inches and at most 48 inches. Write two inequalities that represent the height h of riders for the roller coaster.
Type below:
_____________

Answer:
h represents the height of riders for the roller coaster.
A children’s roller coaster is limited to riders whose height is at least 30 inches and at most 48 inches.
ar least 30 inches means h must be greater than or equal to 30 inches.
i.e., h ≥ 30 inches
at most 48 inches means h must be less than 48 inches.
i.e., h < 48 inches

Question 7.
Match the inequality with the word sentence it represents.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 11
Type below:
_____________

Answer:
Go-Math-Grade-6-Answer-Key-Chapter-8-Solutions-of-Equations-img-11

Make Generalizations – Page No. 474

The reading skill make generalizations can help you write inequalities to represent situations. A generalization is a statement that is true about a group of facts.

Sea otters spend almost their entire lives in the ocean. Their thick fur helps them to stay warm in cold water. Sea otters often float together in groups called rafts. A team of biologists weighed the female sea otters in one raft off the coast of Alaska. The chart shows their results.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 12

Question 8.
Write two inequalities that represent generalizations about the sea otter weights.
Type below:
_____________

Answer:
First, list the weights in pounds in order from least to greatest.
50, 51, 54, 58, 61, 61, 62, 62, 66, 68, 69, 71
Next, write an inequality to describe the weights by using the least weight on the list. Let w represent weights of the otters in the pounds.
The least weight is 50 pounds, so all of the weights are greater than or equal to 50 pounds.
w ≥ 50
Now write an inequality to describe the weights by using the greatest weights in the list.
The greatest weight is 71 pounds, so all of the weights are less than or equal to 71 pounds.
w ≤ 71

Question 9.
Use the chart at the right to write two inequalities that represent generalizations about the number of sea otter pups per raft.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 13
Type below:
_____________

Answer:
First, list the number of pups in order from least to greatest.
6, 6, 7, 10, 15, 16, 20, 23
Next, write an inequality to describe the number of pups by using the least number of pups on the list. Let n represent the number of pups.
The least weight is 6 pups. So all of the pups will be greater than or equal to 6.
n ≥ 6
Now write an inequality to describe the number of pups by using the greatest weights in the list.
The greatest weight is 23 pups so all of the weights are less than or equal to 23 pups.
n ≤ 23 pups

Write Inequalities – Page No. 475

Write an inequality for the word sentence. Tell what type of numbers the variable in the inequality can represent.

Question 1.
The width w is greater than 4 centimeters.
Type below:
_____________

Answer:
The inequality symbol for “greater than” is >. w > 4, where w is the width in centimeters. w is a positive number.

Question 2.
The score s in a basketball game is greater than or equal to 10 points
Type below:
_____________

Answer:
The inequality symbol for “greater than or equal to” is ≥. s ≥ 10, where s is the score in the basketball game. s is a positive number.

Question 3.
The mass m is less than 5 kilograms
Type below:
_____________

Answer:
The inequality symbol for “less than” is <. m < 5, where m is the mass in kilograms. m is a positive number.

Question 4.
The height h is greater than 2.5 meters
Type below:
_____________

Answer:
The inequality symbol for “greater than” is >. h > 2.5, where h is the height in meters. h is a positive number.

Question 5.
The temperature t is less than or equal to −3°.
Type below:
_____________

Answer:
The inequality symbol for “less than or equal to” is ≤. t ≤  −3° where t is the temperature in degrees. t is a negative number.

Write a word sentence for the inequality.

Question 6.4
k < 7
Type below:
_____________

Answer: The word sentence for the inequality is k is less than -7.

Question 7.
z ≥ 2 \(\frac{3}{5}\)
Type below:
_____________

Answer: The word sentence for the inequality is z is greater than or equal to 2 \(\frac{3}{5}\).

Problem Solving

Question 8.
Tabby’s mom says that she must read for at least 30 minutes each night. If m represents the number of minutes reading, what inequality can represent this situation?
Type below:
_____________

Answer: m ≥ 30

Explanation:
Tabby’s mom says that she must read for at least 30 minutes each night.
m represents the number of minutes of reading.
m is greater than or equal to 30.
Thus the inequality is m ≥ 30.

Question 9.
Phillip has a $25 gift card to his favorite restaurant. He wants to use the gift card to buy lunch. If c represents the cost of his lunch, what inequality can describe all of the possible amounts of money, in dollars, that Phillip can spend on lunch?
Type below:
_____________

Answer: c ≤ 25

Explanation:
Phillip has a $25 gift card to his favorite restaurant.
He wants to use the gift card to buy lunch.
c represents the cost of his lunch
c is less than or equal to 25.
Thus the inequality is c ≤ 25.

Question 10.
Write a short paragraph explaining to a new student how to write an inequality.
Type below:
_____________

Answer:
Inequality is a statement that two quantities are not equal.
To know which direction to shade a graph, I write inequalities with the variable on the left side of the inequality symbol. I know that the symbol has to point to the same number after I rewrite the inequality.
For example, I write 4 < y as y > 4
Now the inequality symbol points in the direction in that I should draw the shaded arrow on my graph.

Lesson Check – Page No. 476

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 476 Q1

Question 2.
Describe the meaning of y ≥ 7.9 in words.
Type below:
_____________

Answer: y ≥ 7.9 means y is greater than or equal to 7.9

Spiral Review

Question 3.
Let y represent Jaron’s age in years. If Dawn were 5 years older, she would be Jaron’s age. Which expression represents Dawn’s age?
Type below:
_____________

Answer: y – 5

Explanation:
Let y represent Jaron’s age in years.
If Dawn were 5 years older, she would be Jaron’s age.
We have to subtract 5 years to know the age of Jaron.
Thus the expression is y – 5.

Question 4.
Simplify the expression 7 × 3g.
Type below:
_____________

Answer: 21g

Question 5.
What is the solution of the equation 8 = 8f?
f = ________

Answer:
8 = 8f
f = 8/8 = 1
f = 1
The solution for the equation 8 = 8f is 1.

Question 6.
Which of the following are solutions of the inequality k ≤ 2?
k = 0   k = 2   k = 4   k = 1   k = 1 \(\frac{1}{2}\)
Type below:
_____________

Answer: k = -2 k = -4

Explanation:
k = 0 in the inequality
k ≤ 2
0 ≤ 2
0 is less than but not equal to -2
Thus 0 is not the solution.
k = 2
k ≤ 2
-2 ≤ 2
Thus -2 is the solution.
k = 4
k ≤ 2
-4 ≤ 2
Thus -4 is the solution.
k = 1
1 ≤ 2
1 ≤ 2
1 is greater than but not equal to -2
Thus 1 is not the solution.
k = 1 \(\frac{1}{2}\)
1 \(\frac{1}{2}\) ≤ 2
1 \(\frac{1}{2}\) ≤ 2
1 \(\frac{1}{2}\) is less than but not equal to -2
Thus 1 \(\frac{1}{2}\) is not the solution.

Share and Show – Page No. 479

Graph the inequality.

Question 1.
m < 15
Type below:
_____________

Answer:

Go Math Grade 6 Answer Key Grap the inequality solution img-1

Question 2.
c ≥ 1.5
Type below:
_____________

Answer:
Go Math Answer Key Grade 6 Chapter 8 Graph the inequalities img-2

Question 3.
b ≤ \(\frac{5}{8}\)
Type below:
_____________

Answer:

Go Math Solution Key for Grade 6 Chapter 8 Graph the inequalities img-3

On Your Own

Practice: Copy and Solve Graph the inequality.

Question 4.
a < \(\frac{2}{3}\)
Type below:
_____________

Answer:
HMH Go Math Grade 6 Chapter 8 Graph the inequalities img-4

Question 5.
x > 4
Type below:
_____________

Answer:
HMH Go Math Answer Key Grade 6 Chapter 8 graph inequalities img-5

Question 6.
k ≥ 0.3
Type below:
_____________

Answer:
Go math grade 6 chapter 8 answer key graph inequalities img-6

Question 7.
t ≤ 6
Type below:
_____________

Answer:
Go math key grade 6 chapter 8 graph inequalities img-7

Write the inequality represented by the graph.

Question 8.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 14
Type below:
_____________

Answer: m < 6

Question 9.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 15
Type below:
_____________

Answer: n ≥ -7

Question 10.
Model Mathematics The inequality w ≥ 60 represents the wind speed w in miles per hour of a tornado. Graph the solutions of the inequality on the number line.
Type below:
_____________

Answer:

Go Math Answer Key Grade 6 Chapter 8 Graph inequalities img-8

Question 11.
Graph the solutions of the inequality c < 12 ÷ 3 on the number line
Type below:
_____________

Answer:
c < 12 ÷ 3
c < 4
Go Math Grade 6 Chapter 8 Answer Key Graph inequalities img-9

Problem Solving + Applications – Page No. 480

The table shows the height requirements for rides at an amusement park. Use the table for 12–16
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 16

Question 12.
Write an inequality representing t, the heights in inches of people who can go on Twirl & Whirl.
Type below:
_____________

Answer:
The minimum height of people who can go on Twirl and Whirl is 48 inches.
So, inequality is t ≥ 48.

Question 13.
Graph your inequality from Exercise 12.
Type below:
_____________

Answer:
Draw a full circle at 48 to show that 48 is a solution.
Shade to the right of 48 to show that values greater than or equal to 48 are solutions.

Question 14.
Write an inequality representing r, the heights in inches of people who can go on Race Track.
Type below:
_____________

Answer:
The minimum height of people who can go on Race track is 24 inches.
So, the inequality is r ≥ 42.

Question 15.
Graph your inequality from Exercise 14.
Type below:
_____________

Answer:
Draw a full circle at 42 to show that 42 is a solution.
Shade to the right of 42 to show that values greater than or equal to 48 are solutions.

Question 16.
Write an inequality representing b, the heights in inches of people who can go on both River Rapids and Mighty Mountain. Explain how you determined your answer.
Type below:
_____________

Answer:
You need to be at least 38 inches tall to go on River Rapids and at least 44 inches tall to go on Mighty mountain.
So, you need to be at least 44 inches tall to go on both rides.
The inequality is b ≥ 44.

Question 17.
Alena graphed the inequality c ≤ 25. Darius said that 25 is not part of the solution of the inequality. Do you agree or disagree with Darius? Use numbers and words to support your answer
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 17
Type below:
_____________

Answer: Yes I agree with Darius.
That dark circle and the arrow to the left indicates that c ≤ 25

Graph Inequalities – Page No. 481

Graph the inequality.

Question 1.
h ≥ 3
Type below:
_____________

Answer:
Go Math Answer Key Grade 6 Chapter 8 Graph inequalities image-1

Question 2.
x < \(\frac{-4}{5}\)
Type below:
_____________

Answer:
HMH Go Math Grade 6 Chapter 8 Key Graph Inequalities image-2

Question 3.
y > 2
Type below:
_____________

Answer:
HMH Go Math Solution Key for Grade 6 Chapter 8 Graph inequalities image-3

Question 4.
n ≥ 1 \(\frac{1}{2}\)
Type below:
_____________

Answer:
Go Math Key for Grade 6 Chapter 8 Graoh inequalities image-4

Question 5.
c ≤ 0.4
Type below:
_____________

Answer:
Go Math Grade 6 Answer Key chapter 8 graph inequalities image-5

Write the inequality represented by the graph.

Question 6.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 18
Type below:
_____________

Answer: n > 3

Question 7.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 19
Type below:
_____________

Answer: n > -5

Problem Solving

Question 8.
The inequality x ≤ 2 represents the elevation x of a certain object found at a dig site. Graph the solutions of the inequality on the number line.
Type below:
_____________

Answer:
The inequality x ≤ 2 represents the elevation x of a certain object found at a dig site.
Go math answer key grade 6 chapter 8 graph inequalities image-6

Question 9.
The inequality x ≥ 144 represents the possible scores x needed to pass a certain test. Graph the solutions of the inequality on the number line.
Type below:
_____________

Answer:
Go Math Grade 6 Chapter 8 Answer Key Graph inequalities image-7

Question 10.
Write an inequality and graph the solutions on a number line.
Type below:
_____________

Answer:
The inequality is n ≥ -7
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 15

Lesson Check – Page No. 482

Question 1.
Write the inequality that is shown by the graph.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 20
Type below:
_____________

Answer: x ≥ -2
The number line at right shows the solutions of the inequality x ≥ -2

Question 2.
Describe the graph of g < 0.6.
Type below:
_____________

Answer:
Go Math Answer Key Grade 6 Chapter 8 solution img-5

Spiral Review

Question 3.
Write an expression that shows the product of 5 and the difference of 12 and 9.
Type below:
_____________

Answer:
The equation for the product of 5 and the difference of 12 and 9
5 × 12 – 9
The equation is 5(12 – 9).

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 482 Q4

Question 5.
The equation 12x = 96 gives the number of egg cartons x needed to package 96 eggs. Solve the equation to find the number of cartons needed.
________ cartons

Answer: 8

Explanation:
Given,
The equation 12x = 96 gives the number of egg cartons x needed to package 96 eggs.
12x = 96
x = 96/12 = 8
Thus 8 number of cartons are needed.

Question 6.
The lowest price on an MP3 song is $0.35. Write an inequality that represents the cost c of an MP3 song.
Type below:
_____________

Answer:
Given that,
The lowest price on an MP3 song is $0.35.
c ≥ 0.35
That is an inequality to represent the cost of an MP3 song.

Chapter 8 Review/Test – Page No. 483

Question 1.
For numbers 1a–1c, choose Yes or No to indicate whether the given value of the variable is a solution of the equation.
1a. \(\frac{2}{5}\)v=10; v = 25
1b. n + 5 = 15; n = 5
1c. 5z = 25; z = 5
1a. _____________
1b. _____________
1c. _____________

Answer:
1a. \(\frac{2}{5}\)v=10; v = 25
\(\frac{2}{5}\) × 25=10
2 × 5 = 10
10 = 10
The variable is a solution.
Thus the answer is yes.
1b. n + 5 = 15; n = 5
Substitute n = 5
5 + 5 = 15
10 ≠ 15
The variable is not a solution.
The answer is no.
1c. 5z = 25; z = 5
Substitute z = 5
5 × 5 = 25
25 = 25
The variable is a solution.
Thus the answer is yes.

Question 2.
The distance from third base to home plate is 88.9 feet. Romeo was 22.1 feet away from third base when he was tagged out. The equation 88.9 − t = 22.1 can be used to determine how far he needed to run to get to home plate. Using substitution, the coach determines that Romeo needed to run _____ feet to get to home plate.
Using substitution, the coach determines that Romeo needed to run _____________ feet to get to home plate

Answer: 66.8 feet

Explanation:
The distance from third base to home plate is 88.9 feet.
Romeo was 22.1 feet away from third base when he was tagged out.
The equation is 88.9 − t = 22.1
88.9 − t = 22.1
88.9 – 22.1 = t
t = 66.8 feet
Thus Using substitution, the coach determines that Romeo needed to run 66.8 feet to get to the home plate.

Question 3.
There are 84 grapes in a bag. Four friends are sharing the grapes. Write an equation that can be used to find out how many grapes g each friend will get if each friend gets the same number of grapes.
Type below:
_____________

Answer:
84 = 4g
84 is the total amount of grapes
4 is the number of friends
g = how many grapes each friend will get

Question 4.
Match each scenario with the equation that can be used to solve it.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 21
Type below:
_____________

Answer:
Go-Math-Grade-6-Answer-Key-Chapter-8-Solutions-of-Equations-img-21

Chapter 8 Review/Test Page No. 484

Question 5.
Frank’s hockey team attempted 15 more goals than Spencer’s team. Frank’s team attempted 23 goals. Write and solve an equation that can be used to find how many goals Spencer’s team attempted.
______ goals

Answer: 8 goals

Explanation:
Frank’s hockey team attempted 15 more goals than Spencer’s team.
Frank’s team attempted 23 goals.
Let x be the Spencer’s team
The phrase more than indicates addition operation.
x + 15 = 23
x = 23 – 15
x = 8 goals

Question 6.
Ryan solved the equation 10 + y = 17 by drawing a model. Use numbers and words to explain how Ryan’s model can be used to find the solution
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 22
Type below:
_____________

Answer: y = 7

Explanation:

  • Draw 11 rectangles on your MathBoard to represent the two sides of the equation.
  • Use algebra tiles to model the equation. Model y + 10 in the left rectangle, and model 17 in the right rectangle.
  • To solve the equation, get the y tile by itself on one side. If you remove a tile from one side, you can keep the two sides equal by removing the same type of tile from the other side.
  • Remove ten 1 tiles on the left side and ten 1 tiles on the right side.
  • The remaining titles will be seven 1 tiles on the right sides.

Thus 10 + y = 17
y = 17 – 10 = 7
y = 7

Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations Page 484 Q7

Question 8.
Select the equations that have the solution m = 17. Mark all that apply.
Options:
a. 3 + m = 21
b. m − 2 = 15
c. 14 = m − 3
d. 2 = m − 15

Answer: B, C, D

Explanation:
a. 3 + m = 21
3 + 17 = 21
20 ≠ 21
b. m − 2 = 15
17 – 2 = 15
15 = 15
c. 14 = m − 3
14 = 17 – 3
14 = 14
d. 2 = m − 15
2 = 17 – 15
2 = 2
Thus the correct answers are B, C and D.

Chapter 8 Review/Test Page No. 485

Question 9.
Describe how you could use algebra tiles to model the equation 4x = 20.
Type below:
_____________

Answer:
4x = 20
x = 20/4 = 5
x = 5
Go Math Grade 6 Solution Key Chapter 8 solution img-3

Question 10.
For numbers 10a–10d, choose Yes or No to indicate whether the equation has the solution x = 12.
10a. \(\frac{3}{4}\)x = 9
10b. 3x = 36
10c. 5x = 70
10d. \(\frac{x}{3}\) = 4
10a. _____________
10b. _____________
10c. _____________
10d. _____________

Answer:
10a. Yes
10b. Yes
10c. No
10d. Yes

Explanation:
10a. \(\frac{3}{4}\)x = 9
\(\frac{3}{4}\) × 12 = 9
3 × 3 = 9
9 = 9
Thus the answer is yes.
10b. 3x = 36
x = 12
3 × 12 = 36
36 = 36
Thus the answer is yes.
10c. 5x = 70
x = 12
5 × 12 = 70
60 ≠ 70
Thus the answer is no.
10d. \(\frac{x}{3}\) = 4
x/3 = 4
x = 4 × 3
x = 12
Thus the answer is yes.

Question 11.
Bryan rides the bus to and from work on the days he works at the library. In one month, he rode the bus 24 times. Solve the equation 2x = 24 to find the number of days Bryan worked at the library. Use a model.
Type below:
_____________

Answer:
2x = 24
x = 24/2 = 12
Thus x = 12
Go Math Grade 6 Key chapter 8 solution img-4

Chapter 8 Review/Test – Page No. 486

Question 12.
Betty needs \(\frac{3}{4}\) of a yard of fabric to make a skirt. She bought 9 yards of fabric.
Part A
Write and solve an equation to find how many skirts x she can make from 9 yards of fabric.
________ skirts

Answer: 12 skirts

Explanation:
Betty needs \(\frac{3}{4}\) of a yard of fabric to make a skirt.
She bought 9 yards of fabric.
x × \(\frac{3}{4}\) = 9
x = 9 × \(\frac{4}{3}\)
x = 3 × 4 = 12
x = 12
she can make 12 skirts from 9 yards of fabric.

Question 12.
Part B
Explain how you determined which operation was needed to write the equation
Type below:
_____________

Answer: Division operation is needed to write the equation to know how many x skirts she can make from 9 yards of fabric.

Question 13.
Karen is working on her math homework. She solves the equation \(\frac{b}{8}\) = 56 and says that the solution is b = 7. Do you agree or disagree with Karen? Use words and numbers to support your answer. If her answer is incorrect, find the correct answer.
Type below:
_____________

Answer:
Karen is working on her math homework.
She solves the equation \(\frac{b}{8}\) = 56 and says that the solution is b = 7.
I Disagree with Karen.
b/8 = 56; multiply both sides by 8 to solve for b, and you get b = 448

Chapter 8 Review/Test Page No. 487

Question 14.
There are 70 historical fiction books in the school library. Historical fiction books make up \(\frac{1}{10}\) of the library’s collection. The equation \(\frac{1}{10}\)b = 70 can be used to find out how many books the library has. Solve the equation to find the total number of books in the library’s collection. Use numbers and words to explain how to solve \(\frac{1}{10}\)b = 70.
Type below:
_____________

Answer:
Given
Number of historical books = 70
The equation used to find the totals number of books in the library collection.
\(\frac{1}{10}\)b = 70
b = 70 × 10
b = 700
Hence there are 700 books in the library collection.

Question 15.
Andy drove 33 miles on Monday morning. This was \(\frac{3}{7}\) of the total number of miles he drove on Monday. Solve the equation \(\frac{3}{7}\)m = 33 to find the total number of miles Andy drove on Monday.
______ miles

Answer: 77 miles

Explanation:
Andy drove 33 miles on Monday morning.
This was \(\frac{3}{7}\) of the total number of miles he drove on Monday.
\(\frac{3}{7}\)m = 33
3 × m = 33 × 7
3 × m = 231
m = 231/3
m = 77 miles
Therefore the total number of miles Andy drove on Monday is 77 miles.

Question 16.
The maximum number of players allowed on a lacrosse team is 23. The inequality t≤23 represents the total number of players t allowed on the team.
Two possible solutions for the inequality are _____ and _____.
Two possible solutions for the inequality are _____ and _____

Answer:
The maximum number of players allowed on a lacrosse team is 23.
t ≤ 23
Thus the two possible solutions for the inequality are 22 and 23.

Question 17.
Mr. Charles needs to have at least 10 students sign up for homework help in order to use the computer lab. The inequality h ≥ 10 represents the number of students h who must sign up. Select possible solutions of the inequality. Mark all that apply.
Options:
a. 7
b. 8
c. 9
d. 10
e. 11
f. 12

Answer: D, E

Explanation:
Mr. Charles needs to have at least 10 students sign up for homework help in order to use the computer lab.
h ≥ 10
The number near to 10 is 10 and 11
Thus the correct answers are options D and E.

Chapter 8 Review/Test Page No. 488

Question 18.
The maximum capacity of the school auditorium is 420 people. Write an inequality for the situation. Tell what type of numbers the variable in the inequality can represent.
Type below:
_____________

Answer:
The maximum capacity of the school auditorium is 420 people
Let x be the maximum people
The inequality is x is less than or equal to 420.
x ≤ 420

Question 19.
Match the inequality to the word sentence it represents
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 23
Type below:
_____________

Answer:
Go-Math-Grade-6-Answer-Key-Chapter-8-Solutions-of-Equations-img-23

Question 20.
Cydney graphed the inequality d ≤ 14.
Go Math Grade 6 Answer Key Chapter 8 Solutions of Equations img 24
Part A
Dylan said that 14 is not a solution of the inequality. Do you agree or disagree with Dylan? Use numbers and words to support your answer
Type below:
_____________

Answer: Agree with Dylan. Because the dark circle shows that it is not the solution.

Question 20.
Part B
Suppose Cydney’s graph had an empty circle at 14. Write the inequality represented by this graph.
Type below:
_____________

Answer: y < 14
HMH Go Math Grade 6 Chapter Key solution img-10

Conclusion:

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