## Engage NY Eureka Math 1st Grade Module 4 Lesson 12 Answer Key

### Eureka Math Grade 1 Module 4 Lesson 12 Sprint Answer Key

A
Write the missing number. Pay attention to the + and – signs.

Question 1.
3 + ☐ = 4
Given two numbers are 3 and 4
Considering the missing number as x
Then
3+x=4
x=4-3
x=1

Question 2.
1 + ☐ = 4
Given two numbers are 1 and 4
Considering the missing number as x
Then
1+x=4
x=4-1
x=3

Question 3.
4 – 1 = ☐
Given two numbers are 1 and 4
By removing 1 from 4 we get 3
4-1=3

Question 4.
4 – 3 = ☐
Given two numbers are 3 and 4
By removing 3 from 4 we get 1
4-3=1

Question 5.
3 + ☐ = 5
Given two numbers are 3 and 5
Considering the missing number as x
Then
3+x=5
x=5-3
x=2

Question 6.
2 + ☐ = 5
Given two numbers are 2 and 5
Considering the missing number as x
Then
2+x=5
x=5-2
x=3

Question 7.
5 – 2 = ☐
Given two numbers are 5 and 2
5-2=3

Question 8.
5 – 3 = ☐
Given two numbers are 5 and 3
By removing 3 from 5 we get 2
5-3=2

Question 9.
4 + ☐ = 6
Given two numbers are 6 and 4
Considering the missing number as x
Then
4+x=6
x=6-4
x=2

Question 10.
2 + ☐ = 6
Given two numbers are 2 and 6
Considering the missing number as x
Then
2+x=6
x=6-2
x=4

Question 11.
6 – 2 = ☐
Given two numbers are 2 and 6
By removing 2 from 6 we get 4
6-2=4

Question 12.
6 – 4 = ☐
Given two numbers are 6 and 4
By removing 4 from 6 we get 2
6-4=2

Question 13.
6 – 3 = ☐
Given two numbers are 6 and 3
By removing 3 from 6 we get 3
6-3=3

Question 14.
3 + ☐ = 6
Given two numbers are 3 and 6
Considering the missing number as x
Then
3+x=6
x=6-3
x=3

Question 15.
6 – ☐ = 3
Given two numbers are 3 and 6
Considering the missing number as x
Then
6-x=3
x=6-3
x=3

Question 16.
3 + ☐ = 7
Given two numbers are 3 and 7
Considering the missing number as x
Then
3+x=7
x=7-3
x=4

Question 17.
7 = 4 + ☐
Given two numbers are 7 and 4
Considering the missing number as x
Then
7=4+x
x=7-4
x=3

Question 18.
7 – 4 = ☐
Given two numbers are 7 and 4
By removing 4 from 7 we get 3
7-4=3

Question 19.
7 – 3 = ☐
Given two numbers are 7 and 3
By removing 3 from 7 we get 4
7-3=4

Question 20.
3 + ☐ = 8
Given two numbers are 3 and 8
Considering the missing number as x
Then
3+x=8
x=8-3
x=5

Question 21.
8 = 5 + ☐
Given two numbers are 8 and 5
Considering the missing number as x
Then
8=5+x
x=8+5
x=3

Question 22.
☐ = 8 – 5
Given two numbers are 8 and 5
By removing 5 from 8 we get 3
3=8-5

Question 23.
☐ = 8 – 3
Given two numbers are 8 and 3
By removing 3 from 8 we get 5
5=8-3

Question 24.
3 + ☐ = 9
Given two numbers are 3 and 9
Considering the missing number as x
Then
3+x=9
x=9-3
x=6

Question 25.
9 = 6 + ☐
Given two numbers are 9 and 6
Considering the missing number as x
Then
9=6+x
x=9-6
x=3

Question 26.
☐ = 9 – 6
Given two numbers are 9 and 6
By removing 6 from 9  we get 3
3=9-6

Question 27.
☐ = 9 – 3
Given two numbers are 9 and 3
By removing 3 from 9  we get 6
6=9-3

Question 28.
9 – 4 = ☐ + 2
LHS :-
Given two numbers are 9 and 4
By removing 4 from 9 we get 5
9-4=5
RHS:-
Lets consider missing number as x
LHS=x+2
Since LHS=5
5=x+2
x=5-2
x=3
Verification:
9-4=3+2
5=5
LHS=RHS
Hence proved

Question 29.
☐ + 3 = 9 – 3
RHS:-
Given two numbers are 9 and 3
By removing 3 from 9 we get 6
9-3=6
LHS:-
Lets consider missing number as x
x+3=RHS
Since RHS=6
x+3=6
x=6-3
x=3
Verification:
3+3=9-3
6=6
LHS=RHS
Hence proved

Question 30.
☐ – 7 = 8 – 6
RHS:-
Given two numbers are 8 and 6
By removing 6 from 8 we get 2
8-6=2
LHS:-
Lets consider missing number as x
x-7=RHS
Since RHS=2
x-7=2
x=2+7
x=9
Verification:
9- 7 = 8 – 6
2=2
LHS=RHS
Hence proved

B
Write the missing number. Pay attention to the + and – signs.

Question 1.
4 + ☐ = 4
Given two numbers are 4 and 4
Lets consider the missing number as x
4+x=4
x=4-4
x=0

Question 2.
0 + ☐ = 4
Given two numbers are 0 and 4
Lets consider the missing number as x
0+x=4
x=4-0
x=4

Question 3.
4 – 0 = ☐
Given two numbers are 0 and 4
By removing 0 from 4 we get 4
4-0=4

Question 4.
4 – 4 = ☐
Given two numbers are 4 and 4
By removing 4 from 4 we get 0
4-4=0

Question 5.
4 + ☐ = 5
Given two numbers are 5 and 4
Considering the missing number as x
Then
4+x=5
x=5-4
x=1

Question 6.
1 + ☐ = 5
Given two numbers are 1 and 5
Considering the missing number as x
Then
1+x=5
x=5-1
x=4

Question 7.
5 – 1 = ☐
Given two numbers are 1 and 5
By removing 1 from 5 we get 4
5-1=4

Question 8.
5 – 4 = ☐
Given two numbers are 5 and 4
By removing 5 from 4 we get 1
5-4=1

Question 9.
5 + ☐ = 6
Given two numbers are 5 and 6
Considering the missing number as x
Then
5+x=6
x=6-5
x=1

Question 10.
1 + ☐ = 6
Given two numbers are 1 and 6
Considering the missing number as x
Then
1+x=6
x=6-1
x=5

Question 11.
6 – 1 = ☐
Given two numbers are 1 and 6
By removing 1 from 6 we get 5
6-1=5

Question 12.
6 – 5 = ☐
Given two numbers are 6 and 5
By removing 6 from 5 we get 1
6-5=1

Question 13.
2 + ☐ = 6
Given two numbers are 6 and 2
Considering the missing number as x
Then
2+x=6
x=6-2
x=4

Question 14.
4 + ☐ = 6
Given two numbers are 6 and 4
Considering the missing number as x
Then
4+x=6
x=6-4
x=2

Question 15.
6 – 4 = ☐
Given two numbers are 6 and 4
By removing 4 from 6 we get 2
6-4=2

Question 16.
2 + ☐ = 7
Given two numbers are 2 and 7
Considering the missing number as x
Then
2+x=7
x=7-2
x=5

Question 17.
7 = 5 + ☐
Given two numbers are 7 and 5
Considering the missing number as x
Then
7=5+x
x=7-5
x=2

Question 18.
7 – 5 = ☐
Given two numbers are 7 and 5
By removing 5 from 7 we get 2
7-5=2

Question 19.
7 – 2 = ☐
Given two numbers are 7 and 2
By removing 7 from 2 we get 5
7-2=5

Question 20.
2 + ☐ = 8
Given two numbers are 2 and 8
Considering the missing number as x
Then
2+x=8
x=8-2
x=6

Question 21.
8 = 6 + ☐
Given two numbers are 8 and 6
Considering the missing number as x
Then
8=6-x
x=8-6
x=2

Question 22.
☐ = 8 – 6
Given two numbers are 8 and 6
By removing 6 from 8 we get 2
2=8-6

Question 23.
☐ = 8 – 2
Given two numbers are 8 and 2
By removing 2 from 8 we get 6
6=8-2

Question 24.
2 + ☐ = 9
Given two numbers are 2 and 9
Considering the missing number as x
Then
2+x=9
x=9-2
x=7

Question 25.
9 = 7 + ☐
Given two numbers are 9 and 7
Considering the missing number as x
Then
9=7+x
x=9-7
x=2

Question 26.
☐ = 9 – 7
Given two numbers are 9 and 7
By removing 7 from 9 we get 2
2=9-7

Question 27.
☐ = 9 – 2
Given two numbers are 2 and 9
By removing 2 from 9 we get 7
7=9-2

Question 28.
9 – 3 = ☐ + 3
LHS :-
Given two numbers are 9 and 3
By removing 3 from 9 we get 6
9-3=6
RHS:-
Lets consider missing number as x
LHS=x+3
Since LHS=6
6=x+3
x=6-3
x=3
Verification:
9-3=3+3
6=6
LHS=RHS
Hence proved

Question 29.
☐ + 2 = 9 – 4
RHS:-
Given two numbers are 9 and 4
By removing 4 from 9 we get 5
9-4=5
LHS:-
Lets consider missing number as x
x+2=RHS
Since RHS=5
x+2=5
x=5-2
x=3
Verification:
3+2=9-4
5=5
LHS=RHS
Hence proved

Question 30.
☐ – 6 = 8 – 3
RHS:-
Given two numbers are 8 and 3
By removing 3 from 8 we get 5
8-3=5
LHS:-
Lets consider missing number as x
x-6=RHS
Since RHS=5
x-6=5
x=5+6
x=11
Verification:
11-6=8-3
5=5
LHS=RHS
Hence proved

### Eureka Math Grade 1 Module 4 Lesson 12 Problem Set Answer Key

Fill in the missing numbers to match the picture. Write the matching number bond.
Question 1.

12 + 20 = _____
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There are 10 grapes in one bunch and 2 sape
rately in the first image
And in the second image there 2 bunchs of 10 grapes in each
By adding 12 with 20 we get 32
12+20=32

Question 2.

15 + _____ = _____
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There are 10 beads in one bracelet and 5 saperately in the first image
And in the second image there 1 bracelet of 10 beads
By adding 15 with 10 we get 25
15+10=25

Question 3.

______ + _______ = ______
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There are 10 cubes 8 cubes saperately in the first image
And in the second image there 2 sets of 10 cubes
By adding 18 with 20 we get 38
18+20=38

Question 4.

______ + _______ = ______
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There are 2 tens 9 dots saperately in the first image
And in the second image there is 1 ten
By adding 29 with 10 we get 39
29+10=39

Draw using quick tens and ones. Complete the number bond, and write the sum in the place value chart and the number sentence.
Question 5.
19 + 10 = _______

Given two numbers are 19 and 10
19 is equal to 1 ten and 9 ones
10 is equal to 1 ten and 0 ones
By adding 19 with 10 we get 29
19+10=29

Question 6.
20 + 14 = _______

Given two numbers are 20 and 14
20 is equal to 2 ten and 0 ones
14 is equal to 1 ten and 4 ones
By adding 20 with 14 we get 34
20+14=34

Use arrow notation to solve.
Question 7.

10 more than 13 is 23

Question 8.

20 more than 19 is 39

Question 9.

10 more than 16 is 26

Question 10.

20 more than 18 is 38

Use the dimes and pennies to complete the place value charts and the number sentences.
Question 11.

In the first set there are 2 dimes and 3 pennies = 23
In the second set there is 1 dime = 10
By adding 23 with 10 we get 33
23+10=33

Question 12.

In the first set there are 1 dime and 6 pennies = 16
In the second set there is 2 dimes = 20
By adding 20 with 16 we get 36
16+20=36

### Eureka Math Grade 1 Module 4 Lesson 12 Exit Ticket Answer Key

Complete the number sentences. Use quick tens, the arrow way, or coins to show your thinking.
28 + 10 = ________
In the first set there are 2 dimes and 8 pennies = 28
In the second set there is 1 dime = 10
By adding 28 with 10 we get 38
28+10=38

14 + 20 = _________
In the first set there are 1 dimes and 4 pennies = 14
In the second set there is 2 dimes = 20
By adding 20 with 14 we get 24
14+20=24

### Eureka Math Grade 1 Module 4 Lesson 12 Homework Answer Key

Fill in the missing numbers to match the picture. Complete the number bond to match.
Question 1.

20 + 13 = _________
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There are 2 boxes of pencles in the first image
And in the second image there is 1 box od 10 pencles and 3 pencles saperatly
By adding 20 with 13 we get 33
20+13=33

Question 2.

17 + ____ = _______
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There is 1 flowerpot with 10 flowers and 7 flowers sepaterly in the first image
And in the second image there are 2 flowerpots with 10 flowers in each
By adding 17 with 20 we get 37
17+20=37

Question 3.

______ + _______ = _______
A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.
There is 1 bag of apple with 10 apples  in the first image  that is 1 ten and 0 ones
And in the second image there 2 bags with 10 applesand 8 apples saperatly that is 2 tens and 8 ones
By adding 10 with 28 we get 38
10+28=38

Question 4.

______ + _______ = _______
first image has 3 tens and 0 ones which is equal to 30
Second image has 1 tensand 9 ones which is equal to 19
By adding 30 with 19 we get 49
30+19=49

Draw using quick tens and ones. Complete the number bond and the number sentence.
Question 5.

______ + _______ = _______
First image has 1 ten and 7 ones which is equal to 17
Second image has 1ten and 0 ones
By adding 17 with 10 we get 27
17+10=27

Question 6.

First image has 1 ten and 9 ones which is equal to 19
Second image has 2 ten and 0 ones
By adding 19 with 20 we get 39
19+20=39

Use arrow notation to solve.
Question 7.

10 more than 19 is 29

Question 8.

30 more than 9 is 39

Question 9.

10 more than 28 is 388

Question 10.