Eureka Math Grade 3 Module 6 Lesson 6 Answer Key

Engage NY Eureka Math 3rd Grade Module 6 Lesson 6 Answer Key

Eureka Math Grade 3 Module 6 Lesson 6 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 6 Lesson 6 Pattern Sheet Answer Key p 1
multiply by 6 (1–5)
Answer:
Engage-NY-Math-3rd-Grade-Module-6-Lesson-6-Pattern-Sheet-Answer-Key-p-1
Multiplying 6 with x
Hear x= 1 to 5
Multiply 6 with 1
6 x 1=6
Multiply 6 with 2
6 x 2=12
Multiply 6 with 3
6 x 3=18
Multiply 6 with 4
6 x 4=24
Multiply 6 with 5
6 x 5=30

Eureka Math Grade 3 Module 6 Lesson 6 Problem Set Answer Key

Question 1.
Coach Harris measures the heights of the children on his third-grade basketball team in inches. The heights are shown on the line plot below.
Heights of Children on Third-Grade Basketball Team
Engage NY Math Grade 3 Module 6 Lesson 6 Problem Set Answer Key pr 1
a. How many children are on the team? How do you know?
b. How many children are less than 53 inches tall?
c. Coach Harris says that the most common height for the children on his team is 53 \(\frac{1}{2}\)inches. Is he right? Explain your answer.
d. Coach Harris says that the player who does the tip-off in the beginning of the game has to be at least 54 inches tall. How many children could do the tip-off?
Answer:
a. 15 children
Ther are 15 children inthe team, as it is mentioned in the plot that x is equal to 1 child and there are total 15 x’s in the plot .
b. 6 students are less than 53 inches tall
c. 53 \(\frac{1}{2}\)inches and 52 inches are the 2 most common heights in the team as both the heights has the same number of chldren’s.
52=3 children’s
53\(\frac{1}{2}\)= 3 children’s
d. 4 childern’s can do the tip-off as there are 4 children’s with at least 54 inches hight
54 inches = 1
54\(\frac{1}{2}\) = 2
55 inches = 1

Question 2.
Miss Vernier’s class is studying worms. The lengths of the worms in inches are shown in the line plot below.
Lengths of Worms
Engage NY Math Grade 3 Module 6 Lesson 6 Problem Set Answer Key pr 2
a. How many worms did the class measure? How do you know?
b. Cara says that there are more worms 3 \(\frac{3}{4}\) inches long than worms that are 3\(\frac{2}{4}\) and 4\(\frac{1}{4}\) inches long combined. Is she right? Explain your answer.
c. Madeline finds a worm hiding under a leaf. She measures it, and it is 4\(\frac{3}{4}\) inches long. Plot the length of the worm on the line plot.
Answer:
a.There are 30 worms  that aremeasured, as it is mentioned in the plot that x is equal to 1 worm and there are total 30 x’s in the worms .
b.Cara is wrong
3 \(\frac{3}{4}\) = 6
3\(\frac{2}{4}\) and 4\(\frac{1}{4}\) inches long combined = 4 + 4 = 8
8>6
c.Engage-NY-Math-Grade-3-Module-6-Lesson-6-Problem-Set-Answer-Key-pr-2

Eureka Math Grade 3 Module 6 Lesson 6 Exit Ticket Answer Key

Ms. Bravo measures the lengths of her third-grade students’ hands in inches. The lengths are shown on the line plot below.
Lengths of Hands of Third-Grade Students
Eureka Math 3rd Grade Module 6 Lesson 6 Exit Ticket Answer Key t 1
a. How many students are in Ms. Bravo’s class? How do you know?
b. How many students’ hands are longer than 4\(\frac{2}{4}\) inches?
c. Darren says that more students’ hands are 4\(\frac{2}{4}\) inches long than 4 and 5\(\frac{1}{4}\) inches combined. Is he right? Explain your answer.
Answer:
a.There are 24 students are in Ms. Bravo’s class, as it is mentioned in the plot that x is equal to 1 student and there are total 24 x’s in the students .
b. 9 students hads are longer than 4\(\frac{2}{4}\) inches
4\(\frac{3}{4}\) inches=4
5 inches=2
5 \(\frac{1}{4}\) inches=2
5 \(\frac{2}{4}\) inches=1
Total=4+2+2+1=9
c. Darren is right.
4\(\frac{2}{4}\) inches = 6
4 and 5\(\frac{1}{4}\) inches combined = 5
6>5

Eureka Math Grade 3 Module 6 Lesson 6 Homework Answer Key

Question 1.
Ms. Leal measures the heights of the students in her kindergarten class. The heights are shown on the line plot below.
Heights of Students in Ms. Leal’s Kindergarten Class
Eureka Math Grade 3 Module 6 Lesson 6 Homework Answer Key h 1
a. How many students in Ms. Leal’s class are exactly 41 inches tall?
b. How many students are in Ms. Leal’s class? How do you know?
c. How many students in Ms. Leal’s class are more than 42 inches tall?
d.Ms. Leal says that for the class picture students in the back row must be at least 42\(\frac{1}{2}\) inches tall. How many students should be in the back row?
Answer:
a. 4 students in Ms. Leal’s class are exactly 41 inches tall
b. There are 20 students are in Ms. Leal’s class, as it is mentioned in the plot that x is equal to 1 student and there are total 20 x’s in the students .
c. 9 students in Ms. Leal’s class are more than 42 inches tall
42\(\frac{1}{2}\)inches=5
43\(\frac{1}{2}\)inches=3
44inches=1
Total = 5 + 3 + 1 = 9
d.9 students should be in the back row
because 42\(\frac{1}{2}\)inches=5
43\(\frac{1}{2}\)inches=3
44inches=1
Total = 5 + 3 + 1 = 9

Question 2.
Mr. Stein’s class is studying plants. They plant seeds in clear plastic bags and measure the lengths of the roots. The lengths of the roots in inches are shown in the line plot below.
Lengths of Plants’ Roots
Eureka Math Grade 3 Module 6 Lesson 6 Homework Answer Key h 2
a. How many roots did Mr. Stein’s class measure? How do you know?
b. Teresa says that the 3 most frequent measurements in order from shortest to longest are 3\(\frac{1}{4}\) inches, 3\(\frac{2}{4}\) inches, and 3\(\frac{3}{4}\) inches. Do you agree? Explain your answer.
c. Gerald says that the most common measurement is 14 quarter inches. Is he right? Why or why not?
Answer:
a. There are 24 roots Mr. Stein’s class measure, as it is mentioned in the plot that x is equal to 1 plant and one plant has one root there by there are total 20 x’s in the roots .
b. Teresa is wrong
because
3\(\frac{1}{4}\) inches =3 inches
they have the same number of roots that is 4
And
3\(\frac{3}{4}\) inches =2 \(\frac{3}{4}\) inches
they have the same number of roots that is 3
There by n order from shortest to longest
3\(\frac{1}{4}\) inches,3 inches =3
3\(\frac{1}{4}\) inches,3 inches =4
3\(\frac{2}{4}\) =5

Eureka Math Grade 3 Module 6 Answer Key

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