Engage NY Eureka Math 4th Grade Module 3 Lesson 33 Answer Key
Eureka Math Grade 4 Module 3 Lesson 33 Problem Set Answer Key
Question 1.
Ursula solved the following division problem by drawing an area model.
a. What division problem did she solve?
Answer:
Ursula solved division problem of 892 ÷ 4 = 223,
Explanation:
Ursula solved the following division problem by drawing an area model as shown above of (400 + 400 + 80 + 12) ÷ 4 = 892 ÷ 4 as
(100 + 100 +20 +3) = 223.
b. Show a number bond to represent Ursula’s area model and represent the total length using the distributive property.
Answer:
Explanation:
Drawn number bond to represent Ursula’s area model and represented the total length using the distributive property as
= (400 ÷ 4) + (400 ÷ 4) + (80 ÷ 4) + (12 ÷ 4)
= 100 + 100 + 20 + 3
= 223.
Question 2.
a. Solve 960 ÷ 4 using the area model. There is no remainder in this problem.
Answer:
Explanation:
Solved 960 ÷ 4 using the area model as shown above
(960 ÷ 4) = (800 ÷ 4) + (160 ÷ 4) = 200 + 40 = 240.
b. Draw a number bond and use the long division algorithm to record your work from Part (a).
Answer:
Explanation:
Drawn a number bond and used the long division algorithm to record my work from Part (a) as shown above 960 ÷ 4 = 240.
Question 3.
a. Draw an area model to solve 774 ÷ 3.
Answer:
Explanation:
Drawn an area model as shown above for 774 ÷ 3 =
(600 ÷ 3) + (150 ÷ 3) + (24 ÷ 3) = 200 + 50 + 8 = 258.
b. Draw a number bond to represent this problem.
Answer:
Explanation:
Drawn a number bond to represent this problem as shown above (600 ÷ 3) + (150 ÷ 3) + (24 ÷ 3) = 200 + 50 + 8 = 258.
c. Record your work using the long division algorithm.
Answer:
Explanation:
Recorded my work using the long division algorithm as
shown above.
Question 4.
a. Draw an area model to solve 1,584 ÷ 2.
Answer:
Explanation:
Drawn an area model to solve 1,584 ÷ 2 =
(1,400 ÷ 2) + (180 ÷ 2) + (4 ÷ 2) =
700 + 90 + 2 = 792 as shown above.
b. Draw a number bond to represent this problem.
Answer:
Explanation:
Drawn a number bond to represent this problem as shown above 1,584 ÷ 2 = (1,400 ÷ 2) + (180 ÷ 2) + (4 ÷ 2) =
700 + 90 + 2 = 792.
c. Record your work using the long division algorithm.
Answer:
Explanation:
Recorded my work using the long division algorithm as shown above.
Eureka Math Grade 4 Module 3 Lesson 33 Exit Ticket Answer Key
Question 1.
Anna solved the following division problem by drawing an area model.
a. What division problem did she solve?
Answer:
Anna solved division problem of 747 ÷ 3 = 249,
Explanation:
Given Anna solved the following division problem by drawing an area model of 747 ÷ 3 =
(600 ÷ 3) + (120 ÷ 3) + (27 ÷ 3) = 200 + 40 + 9 = 249.
b. Show a number bond to represent Anna’s area model, and represent the total length using the distributive property.
Answer:
Explanation:
Shown a number bond to represent Anna’s problem representing the total length using the distributive property
as 747 ÷ 3 = (600 ÷ 3) + (120 ÷ 3) + (27 ÷ 3) = 200 + 40 + 9 = 249.
Question 2.
a. Draw an area model to solve 1,368 ÷ 2.
Answer:
Explanation:
Drawn an area model to solve 1,368 ÷ 2 =
(1,200 ÷ 2) + (160 ÷ 2) + (8 ÷ 2) = 600 + 80 + 4 = 684 as shown above.
b. Draw a number bond to represent this problem.
Answer:
Explanation:
Drawn a number bond to represent problem as shown above 1,368 ÷ 2 = (1,200 ÷ 2) + (160 ÷ 2) + (8 ÷ 2)
= 600 + 80 + 4 = 684.
c. Record your work using the long division algorithm.
Answer:
Explanation:
Recorded my work using the long division algorithm as shown above.
Eureka Math Grade 4 Module 3 Lesson 33 Homework Answer Key
Question 1.
Arabelle solved the following division problem by drawing an area model.
a. What division problem did she solve?
Answer:
Arabelle solved the division problem as 1,828 ÷ 4 =
(1600 + 200 + 28) ÷ 4 = 400 + 50 + 7 = 457.
b. Show a number bond to represent Arabelle’s area model, and represent the total length using the distributive property.
Answer:
Explanation:
Shown a number bond to represent Arabelle’s problem representing the total length using the distributive property
as 1,828 ÷ 4 = (1600 ÷ 4) + (200 ÷ 4) + (28 ÷ 4)
= 400 + 50 + 7 = 457.
Question 2.
a. Solve 816 ÷ 4 using the area model. There is no remainder in this problem.
Answer:
Explanation:
Solved 816 ÷ 4 using the area model as shown above
(816 ÷ 4) = (800 ÷ 4) + (16 ÷ 4) = 200 + 4 = 204.
b. Draw a number bond and use a written method to record your work from Part (a).
Answer:
Explanation:
Drawn a number bond to represent problem as shown above 816 ÷ 4 = (800 ÷ 4) + (16 ÷ 4) = 200 + 4 = 204.
Question 3.
a. Draw an area model to solve 549 ÷ 3.
Answer:
Explanation:
Drawn an area model to solve 549 ÷ 3 =
(300 ÷ 3) + (240 ÷ 3) + (9 ÷ 3) =
100 + 80 + 3 = 183 as shown above.
b. Draw a number bond to represent this problem.
Answer:
Explanation:
Drawn a number bond to represent problem as shown above 549 ÷ 3 = (300 ÷ 3) + (240 ÷ 3) + (9 ÷ 3)
= 100 + 80 + 3 = 183.
c. Record your work using the long division algorithm.
Answer:
Explanation:
Recorded my work using the long division algorithm as shown above.
Question 4.
a. Draw an area model to solve 2,762 ÷ 2.
Answer:
Explanation:
Drawn an area model to solve 2,762 ÷ 2 =
(2,000 ÷ 2) + (600 ÷ 2) + (160 ÷ 2) + (2 ÷ 2)
= 1,000 + 300 + 80 + 1 = 1,381 as shown above.
b. Draw a number bond to represent this problem.
Answer:
Explanation:
Drawn a number bond to represent problem as shown above
2,762 ÷ 2 = (2,000 ÷ 2) + (600 ÷ 2) + (160 ÷ 2) + (2 ÷ 2)
= 1,000 + 300 + 80 + 1 = 1,381.
c. Record your work using the long division algorithm.
Answer:
Explanation:
Recorded my work using the long division algorithm as shown above.