## Engage NY Eureka Math 4th Grade Module 3 Lesson 34 Answer Key

### Eureka Math Grade 4 Module 3 Lesson 34 Problem Set Answer Key

Question 1.
Use the associative property to rewrite each expression.
Solve using disks, and then complete the number sentences.
a. 30 × 24
= ( _3___ × 10) × 24
= __3__ × (10 × 24)
= ___720____

30 X 24
= (3 X 10) X 24
= 3 X (10 X 24)
= 720,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 24
= (3 X 10) X 24
= 3 X (10 X 24)
= 720.

b. 40 × 43
= (4 × 10) × __43___
= 4 × (10 × _43__ )
= __1,720_____

40 X 43
= (4 X 10) X 43
= 4 X (10 X 43)
= 1,720,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 40 X 43
= (4 X 10) X 43
= 4 X (10 X 43)
= 1,720.

c. 30 × 37
= (3 × _10___ ) × __37___
= 3 × (10 × __37___ )
= __1,110_____

30 × 37
= (3 × 10) × 37
= 3 × (10 × 37)
= 1,110

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 × 37
= (3 × 10) × 37
= 3 × (10 × 37)
= 1,110

Question 2.
Use the associative property and place value disks to solve.
a. 20 × 27
20 X 27
= (2 X 10) X 27
= 2 X (10 X 27)
= 540,

Explanation:
Used the associative property and placed value
disks to solve 20 X 27
= (2 X 10) X 27
= 2 X (10 X 27)
= 540 as shown above.

b. 40 × 31
40 X 31
= (4 X 10) X 31
= 4 X (10 X 31)
= 1,240,

Explanation:
Used the associative property and placed value
disks to solve 40 X 31
= (4 X 10) X 31
= 4 X (10 X 31)
= 1,240 as shown above.

Question 3.
Use the associative property without place value disks to solve.
a. 40 × 34

Explanation:
Used the associative property and placed value
disks to solve 40 X 34
= (4 X 10) X 34
= 4 X (10 X 34)
= 1,360

b. 50 × 43

Explanation:
Used the associative property and placed value
disks to solve 50 X 43
= (5 X 10) X 43
= 5 X (10 X 43)
= 2,150

Question 4.
Use the distributive property to solve the following problems.
Distribute the second factor.
a. 40 × 34
40 X 34
= (40 X 30 ) + (40 X 4)
= 1,200 + 160
= 1,360,

Explanation:
Used the distributive property and distribute the
second factor as 40 X 34
= (40 X 30 ) + (40 X 4)
= 1,200 + 160
= 1,360.

b. 60 × 25
60 X 25
= (60 X 20) + (60 X 5)
= 1,200 + 300
= 1,500,

Explanation:
Used the distributive property and distribute the
second factor as 60 X 25
= (60 X 20) + (60 X 5)
= 1,200 + 300
= 1,500.

### Eureka Math Grade 4 Module 3 Lesson 34 Exit Ticket Answer Key

Question 1.
Use the associative property to rewrite each expression.
Solve using disks, and then complete the number sentences.
20 × 41
hundreds tens ones
_(2_ × _10)___ × _41___ = _820_

20 X 41
= (2 X 10) X 41
= 2 X (10 X 41)
= 820,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 20 X 41
= (2 X 10) X 41
= 2 X (10 X 41)
= 820.

Question 2.
Distribute 32 as 30 + 2 and solve.
60 × 32
= 60 X 32
= 60 X (30 + 2)
= (60 X 30) + (60 X 2)
= 1,800 + 120
= 1,920,

Explanation:
Distributed 32 as 30 + 2 and solved as
= 60 X 32
= 60 X (30 + 2)
= (60 X 30) + (60 X 2)
= 1,800 + 120
= 1,920.

### Eureka Math Grade 4 Module 3 Lesson 34 Homework Answer Key

Question 1.
Use the associative property to rewrite each expression.
Solve using disks, and then complete the number sentences.
a. 20 × 34
= (__2__ × 10) × 34
= __2__ × (10 × 34)
= ___680____

20 X 34
= (2 X 10) X 34
= 2 X (10 X 34)
= 680,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 20 X 34
= (2 X 10) X 34
= 2 X (10 X 34)
= 680.

b. 30 × 34
= (3 × 10) × __34___
= 3 × (10 × _34__)
= __1,020_____

30 X 34
= (2 X 10) X 34
= 3 X (10 X 34)
=1,020

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 34
= (3 X 10) X 34
= 3 X (10 X 34)
= 1,020

c. 30 × 42
= (3 × _10___) × _42____
= 3 × (10 × __42___)
= __1,260_____

30 X 42
= (3 X 10) X 42
= 3 X (10 X 42)
= 1,260

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 42
= (3 X 10) X 42
= 3 X (10 X 42)
= 1,260

Question 2.
Use the associative property and place value disks to solve.
a. 20 × 16
20 X 16
= (2 X 10) X 16
= 2 X (10 X 16)
= 320,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 20 X 16
= (2 X 10) X 16
= 2 X (10 X 16)
= 320.

b. 40 × 32
40 X 32
= (4 X 10) X 32
= 4 X (10 X 32)
= 1,280,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 40 X 32
= (4 X 10) X 32
= 4 X (10 X 32)
= 1,280.

Question 3.
Use the associative property without place value disks to solve.
a. 30 × 21
30 X 21
= (3 X 10) X 21
= 3 X (10 X 21)
= 630,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 21
= (3 X 10) X 21
= 3 X (10 X 21)
= 630.

b. 60 × 42
60 X 42
= (6 X 10) X 42
= 6 X (10 X 42)
= 2,520,

Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 60 X 42
= (6 X 10) X 42
= 6 X (10 X 42)
= 2,520.

Question 4.
Use the distributive property to solve the following.
Distribute the second factor.
a. 40 × 43
40 X 43
= (40 X 40) + (40 X 3)
= 1,600 + 120
= 1,720,

Explanation:
Used the distributive property and distribute the
second factor as 40 X 43
= (40 X 40) + (40 X 3)
= 1,600 + 120
= 1,720.

b. 70 × 23