## Engage NY Eureka Math 4th Grade Module 5 Lesson 18 Answer Key

### Eureka Math Grade 4 Module 5 Lesson 18 Practice Sheet Answer Key

Answer:

1/8 + 3/8 + 4/8= 1.

Explanation:

In the above-given question,

given that,

1/8 + 3/8.

4/8.

4/8 + 4/8.

8/8 = 1.

Answer:

1/6 + 4/6 + 2/6= 7/6.

Explanation:

In the above-given question,

given that,

1/6 + 4/6.

5/6.

5/6 + 2/6.

7/6.

Answer:

11/10 – 4/10 – 1/10 = 6/10.

Explanation:

In the above-given question,

given that,

11/10 – 4/10.

7/10 – 1/10.

6/10._____________

adding and subt

Answer:

1 – 3/12 – 5/12 = 4/12.

Explanation:

In the above-given question,

given that,

1 – 3/12.

9/12.

9/12 – 5/12.

4/12.

Answer:

5/8 + 4/8 + 1/8= 10/8.

Explanation:

In the above-given question,

given that,

5/8 + 4/8.

9/8.

9/8 + 1/8.

10/8.

Answer:

1(1/5) – 2/5 – 3/5= 1/5.

Explanation:

In the above-given question,

given that,

1(1/5) – 2/5.

6/5 – 2/5.

4/5 – 1/5.

3/5.

### Eureka Math Grade 4 Module 5 Lesson 18 Problem Set Answer Key

Question 1.

Show one way to solve each problem. Express sums and differences as a mixed number when possible. Use number bonds when it helps you. Part (a) is partially completed.

a. \(\frac{2}{5}\) + \(\frac{3}{5}\) + \(\frac{1}{5}\)

= \(\frac{5}{5}\) + \(\frac{1}{5}\) = 1 + \(\frac{1}{5}\)

=1 \(\frac{1}{5}\).

Answer:

1\(\frac{1}{5}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{2}{5}\) + \(\frac{3}{5}\) + \(\frac{1}{5}\)

2/5 + 3/5 = 5/5.

\(\frac{5}{5}\) + \(\frac{1}{5}\).

5/5 = 1.

5/5 + 1/5 = 6/5.

1\(\frac{1}{5}\).

b. \(\frac{3}{6}\) + \(\frac{1}{6}\) + \(\frac{3}{6}\)

Answer:

1\(\frac{1}{6}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{3}{6}\) + \(\frac{1}{6}\) + \(\frac{3}{6}\)

3/6 + 1/6 = 4/6.

\(\frac{4}{6}\) + \(\frac{3}{6}\).

4/6 + 3/6.

7/6.

1\(\frac{1}{6}\).

c. \(\frac{5}{7}\) + \(\frac{7}{7}\) + \(\frac{2}{7}\)

Answer:

\(\frac{14}{7}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{5}{7}\) + \(\frac{7}{7}\) + \(\frac{2}{7}\)

5/7 + 7/7 = 12/7.

\(\frac{12}{7}\) + \(\frac{2}{7}\).

12/7 + 2/7 = 14/7.

1\(\frac{7}{7}\).

d. \(\frac{7}{8}\) – \(\frac{3}{8}\) – \(\frac{1}{8}\)

Answer:

\(\frac{3}{8}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{7}{8}\) – \(\frac{3}{8}\) – \(\frac{1}{8}\)

7/8 – 3/8 = 4/8.

\(\frac{4}{8}\) – \(\frac{1}{8}\).

4/8 – 1/8 = 3/8.

1\(\frac{5}{8}\).

e. \(\frac{7}{9}\) + \(\frac{1}{9}\) + \(\frac{4}{9}\)

Answer:

\(\frac{12}{9}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{7}{9}\) + \(\frac{1}{9}\) + \(\frac{4}{9}\)

7/9 + 1/9 = 8/9.

\(\frac{8}{9}\) + \(\frac{4}{9}\).

8/9 + 4/9 = 12/9.

1\(\frac{3}{9}\).

f. \(\frac{4}{10}\) + \(\frac{11}{10}\) + \(\frac{5}{10}\)

Answer:

\(\frac{20}{10}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{4}{10}\) + \(\frac{11}{10}\) + \(\frac{5}{10}\)

4/10 + 11/10 = 15/10.

\(\frac{15}{10}\) + \(\frac{5}{10}\).

15/10 + 5/10 = 20/10.

1\(\frac{10}{10}\).

g. 1 – \(\frac{3}{12}\) – \(\frac{4}{12}\)

Answer:

\(\frac{5}{12}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{12}{12}\) – \(\frac{3}{12}\) – \(\frac{4}{12}\)

12 – 3/12 = 9/12.

\(\frac{9}{12}\) – \(\frac{4}{12}\).

9/12 – 4/12 = 5/12.

1 – \(\frac{7}{12}\).

h. 1\(\frac{2}{3}\) – \(\frac{1}{3}\) – \(\frac{1}{3}\)

Answer:

\(\frac{0}{3}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{2}{3}\) – \(\frac{1}{3}\) – \(\frac{1}{3}\)

2/3 – 1/3 = 1/3.

\(\frac{1}{3}\) – \(\frac{1}{3}\).

1/3 – 1/3 = 0.

\(\frac{0}{3}\).

i. \(\frac{10}{12}\) + \(\frac{5}{12}\) + \(\frac{2}{12}\) + \(\frac{7}{12}\)

Answer:

\(\frac{24}{12}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{10}{12}\) + \(\frac{5}{12}\) + \(\frac{2}{12}\) + \(\frac{7}{12}\)

10/12 + 5/12 = 15/12.

\(\frac{15}{12}\) + \(\frac{2}{12}\).

15/12 + 2 /12 = 17/12.

\(\frac{17}{12}\) + \(\frac{7}{12}\).

17/12 + 7/12.

24/12.

1\(\frac{12}{12}\).

Question 2.

Monica and Stuart used different strategies to solve \(\frac{5}{8}\) + \(\frac{2}{8}\) + \(\frac{5}{8}\).

Whose strategy do you like best? Why?

Answer:

Stuart’s way is the best.

Explanation:

In the above-given question,

given that,

Monica and Stuart used different strategies to solve \(\frac{5}{8}\) + \(\frac{2}{8}\) + \(\frac{5}{8}\).

Monica explained in detail.

Stuart’s also explained in detail.

he explained in a simple way.

so Stuart’s way is the best.

Question 3.

You gave one solution for each part of Problem 1. Now, for each problem indicated below, give a different solution method.

Answer:

e. 5/7 + 7/7 + 2/7 = 14/7.

Explanation:

In the above-given question,

given that,

5/7 + 7/7.

12/7.

12/7 + 2/7.

14/7.

5/7 + 7/7 + 2/7 = 14/7.

Answer:

f. 4/10 + 11/10 + 5/10 = 20/10.

Explanation:

In the above-given question,

given that,

4/10 + 11/10.

15/10.

15/10 + 5/10.

20/10.

4/10 + 11/10 + 5/10 = 20/10.

### Eureka Math Grade 4 Module 5 Lesson 18 Exit Ticket Answer Key

Solve the following problems. Use number bonds to help you.

Question 1.

\(\frac{5}{9}\) + \(\frac{2}{9}\) + \(\frac{4}{9}\)

Answer:

\(\frac{11}{9}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{5}{9}\) + \(\frac{2}{9}\) + \(\frac{4}{9}\)

5/9 + 2/9 = 7/9.

\(\frac{7}{9}\) + \(\frac{4}{9}\).

7/9 + 4/9 = 11/9.

\(\frac{11}{9}\).

Question 2.

1 – \(\frac{5}{8}\) – \(\frac{1}{8}\)

Answer:

\(\frac{2}{8}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{8}{1}\) – \(\frac{5}{8}\) – \(\frac{1}{8}\)

8 – 5/8 = 3/8.

\(\frac{3}{8}\) – \(\frac{1}{8}\).

3/8 – 1/8 = 2/8.

\(\frac{2}{8}\).

### Eureka Math Grade 4 Module 5 Lesson 18 Homework Answer Key

Question 1.

Show one way to solve each problem. Express sums and differences as a mixed number when possible. Use number bonds when it helps you. Part (a) is partially completed.

a. \(\frac{1}{3}\) + \(\frac{2}{3}\) + \(\frac{1}{3}\)

= \(\frac{3}{3}\) + \(\frac{1}{3}\) = 1 + \(\frac{1}{3}\)

= __4/3______

Answer:

1\(\frac{1}{3}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{3}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)

1 + 1/3 =2 /3.

\(\frac{3}{3}\) + \(\frac{1}{3}\).

2/3 + 2/3 = 4/3.

1\(\frac{1}{3}\).

b. \(\frac{5}{8}\) + \(\frac{5}{8}\) + \(\frac{3}{8}\)

Answer:

1\(\frac{5}{8}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{5}{8}\) + \(\frac{5}{8}\) + \(\frac{3}{8}\)

5/8 + 5/8 = 10/8.

\(\frac{10}{8}\) + \(\frac{3}{8}\).

10/8 + 3/8 = 13/8.

1\(\frac{5}{8}\).

c. \(\frac{4}{6}\) + \(\frac{6}{6}\) + \(\frac{1}{6}\)

Answer:

1\(\frac{5}{6}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{4}{6}\) + \(\frac{6}{6}\) + \(\frac{1}{6}\)

4/6 + 6/6 = 10/6.

\(\frac{10}{6}\) + \(\frac{1}{6}\).

10/6 + 1/6 = 11/6.

1\(\frac{5}{6}\).

d. 1\(\frac{2}{12}\) – \(\frac{2}{12}\) – \(\frac{1}{12}\)

Answer:

1 – \(\frac{1}{12}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

1\(\frac{2}{12}\) – \(\frac{2}{12}\) – \(\frac{1}{12}\)

14/12 – 2/12 = 12/12.

\(\frac{12}{12}\) – \(\frac{1}{12}\).

1 – 1/12 = 11/12.

1 – \(\frac{11}{12}\).

e. \(\frac{5}{7}\) + \(\frac{1}{7}\) + \(\frac{4}{7}\)

Answer:

1\(\frac{3}{7}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{5}{7}\) + \(\frac{1}{7}\) + \(\frac{4}{7}\)

5/7 + 1/7 = 6/7.

\(\frac{6}{7}\) + \(\frac{4}{7}\).

6/7 + 4/7 = 10/7.

1\(\frac{3}{7}\).

f. \(\frac{4}{10}\) + \(\frac{7}{10}\) + \(\frac{9}{10}\)

Answer:

1\(\frac{10}{20}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{4}{10}\) + \(\frac{7}{10}\) + \(\frac{9}{10}\)

4/10 + 7/10 = 11/10.

\(\frac{11}{10}\) + \(\frac{9}{10}\).

11/10 + 9/10 = 20/10.

1\(\frac{10}{20}\).

g. 1 – \(\frac{3}{10}\) – \(\frac{1}{10}\)

Answer:

1 – \(\frac{4}{10}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

1 – \(\frac{3}{10}\) – \(\frac{1}{10}\).

10 – 3/10 = 7/10.

\(\frac{7}{10}\) – \(\frac{1}{10}\).

7/10 – 1/10 = 6/10.

1 – \(\frac{4}{10}\).

h. 1\(\frac{3}{5}\) – \(\frac{4}{5}\) – \(\frac{1}{5}\)

Answer:

1 – \(\frac{2}{5}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

1\(\frac{3}{5}\) – \(\frac{4}{5}\) – \(\frac{1}{5}\)

8/5 – 4/5 = 4/5.

\(\frac{4}{5}\) – \(\frac{1}{5}\).

4/5 – 1/5 = 3/5.

1\(\frac{2}{5}\).

i. \(\frac{10}{15}\) + \(\frac{7}{15}\) + \(\frac{12}{15}\) + \(\frac{1}{15}\)

Answer:

1\(\frac{15}{15}\).

Explanation:

In the above-given question,

given that,

Express sums and differences as a mixed number when possible.

\(\frac{10}{15}\) + \(\frac{7}{15}\) + \(\frac{12}{15}\) + \(\frac{1}{15}\).

10/15 + 7/15 = 17/15.

\(\frac{12}{15}\) + \(\frac{1}{15}\).

12/15 + 1/15 = 13/15.

13/15 + 17/15.

1\(\frac{15}{15}\).

Question 2.

Bonnie used two different strategies to solve \(\frac{5}{10}\) + \(\frac{4}{10}\) + \(\frac{3}{10}\).

Which strategy do you like best? Why?

Answer:

Bonnie’s Second Strategy is the best.

Explanation:

In the above-given question,

given that,

Bonnie’s first and second used different strategies to solve \(\frac{5}{10}\) + \(\frac{4}{10}\) + \(\frac{3}{10}\).

Bonnie’s second strategy explained in detail.

Bonnie’s first strategy also explained in detail.

he explained in a simple way.

so the second way is the best.

Question 3.

You gave one solution for each part of Problem 1. Now, for each problem indicated below, give a different solution method.

Answer:

b. 5/8 + 5/8 + 3/8 = 13/8.

Explanation:

In the above-given question,

given that,

5/8 + 5/8.

10/8.

10/8 + 3/8.

13/8.

5/8 + 5/8 + 3/8 = 13/8.

Answer:

e. 5/7 + 1/7 + 4/7 = 10/7.

Explanation:

In the above-given question,

given that,

5/7 + 1/7.

6/7.

6/7 + 4/7.

10/7.

5/7 + 1/7 + 4/7 = 10/7.

Answer:

h. 1(3/5) – 4/5 – 1/5 = 3/5.

Explanation:

In the above-given question,

given that,

1(3/5) – 4/5.

8/5 – 4/5.

4/5 – 3/5.

1/5.

1(3/5) – 4/5 – 1/5 = 3/5.