## Engage NY Eureka Math 4th Grade Module 5 Lesson 40 Answer Key

### Eureka Math Grade 4 Module 5 Lesson 40 Problem Set Answer Key

Question 1.
The chart to the right shows the height of some football players.

 Player Height (in feet) A 6$$\frac{1}{4}$$ B 5$$\frac{7}{8}$$ C 6$$\frac{1}{2}$$ D 6$$\frac{1}{4}$$ E 6$$\frac{2}{8}$$ F 5$$\frac{7}{8}$$ G 6$$\frac{1}{8}$$ H 6$$\frac{5}{8}$$ I 5$$\frac{6}{8}$$ J 6$$\frac{1}{8}$$

A: 6(1/4) = 6.2

Explanation:
In the above-given question,
given that,
The height of the Football A.
6(1/4) = 6 x 4.
6 x 4 = 24.
24 + 1/4 = 25/4.
25/4 = 6.2.

B: 5(7/8) = 5.8.

Explanation:
In the above-given question,
given that,
The height of the Football B.
5(7/8) = 5 x 8.
5 x 8 = 40.
40 + 7/8 = 47/8.
47/8 = 5.8.

C: 6(1/2) = 6.5.

Explanation:
In the above-given question,
given that,
The height of the Football A.
6(1/2) = 6 x 2.
6 x 2 = 12.
12 + 1/2 = 13/2.
13/2 = 6.5.

D: 6(1/4) = 6.2

Explanation:
In the above-given question,
given that,
The height of the Football D.
6(1/4) = 6 x 4.
6 x 4 = 24.
24 + 1/4 = 25/4.
25/4 = 6.2.

E: 6(2/8) = 6.2

Explanation:
In the above-given question,
given that,
The height of the Football A.
6(2/8) = 6 x 8.
6 x 8 = 48.
48 + 2/8 = 50/8.
50/8 = 6.2.

F: 5(7/8) = 5.8

Explanation:
In the above-given question,
given that,
The height of the Football F.
5(7/8) = 5 x 8.
5 x 8 = 40.
40 + 7/8 = 47/8.
47/8 = 5.8.

G: 6(1/8) = 6.1

Explanation:
In the above-given question,
given that,
The height of the Football G.
6(1/8) = 6 x 8.
6 x 8 = 48.
48 + 1/8 = 49/8.
49/8 = 6.1.

H: 6(5/8) = 6.6.

Explanation:
In the above-given question,
given that,
The height of the Football H.
6(5/8) = 6 x 8.
6 x 8 = 48.
48 + 5/8 = 53/8.
53/8 = 6.6.

I: 5(6/8) = 5.7

Explanation:
In the above-given question,
given that,
The height of the Football I.
5(6/8) = 5 x 8.
5 x 8 = 40.
40 + 6/8 = 46/8.
46/8 = 5.7.

J: 6(1/8) = 6.1

Explanation:
In the above-given question,
given that,
The height of the Football J.
6(1/8) = 6 x 8.
6 x 8 = 48.
48 + 1/8 = 49/8.
49/8 = 6.1.

a. Use the data to create a line plot at the bottom of this page and to answer the questions below.

The points on the co-ordinate plane increase.

Explanation:
In the above-given question,
given that,
the players on the y-axis.
the height of the football on the x-axis.
the points on the graph increases.

b. What is the difference in height of the tallest and shortest players?

The difference in height of the tallest and shortest players = 0.9.

Explanation:
In the above-given question,
given that,
the height of the tallest player = 6.6,
the height of the shortest player = 5.7.
6.6 – 5.7 = 0.9.
so the difference in height of the tallest and shortest players = 0.9.

c. Player I and Player B have a combined height that is 1$$\frac{1}{8}$$ feet taller than a school bus. What is the height of a school bus?

The height of the school bus = 10.375.

Explanation:
In the above-given question,
given that,
player I and player B have a combined height that is 1(1/8) feet.
1(1/8) = 8 + 1/8.
9/8 = 1.125.
Player I = 5.7.
Player H = 5.8.
5.7 + 5.8 = 11.5.
11.5 – 1.125 = 10.375.
so the height of the school bus = 10.375 ft.

Question 2.
One of the players on the team is now 4 times as tall as he was at birth, when he measured 1$$\frac{5}{8}$$ feet. Who is the player?

The Player = C.

Explanation:
In the above-given question,
given that,
One of the players on the team is now 4 times as tall as he was at birth.
1(5/8) = 1 x 8 = 8.
8 + 5/8 = 13/8.
13/8 = 1.6.
1.6 x 4 = 2.4.
so player C has the 6.4 ft height.

Question 3.
Six of the players on the team weigh over 300 pounds. Doctors recommend that players of this weight drink at least 3$$\frac{3}{4}$$ quarts of water each day. At least how much water should be consumed per day by all 6 players?

The water should be consumed per day by all 6 players = 22.2 quarts.

Explanation:
In the above-given question,
given that,
Six of the players on the team weigh over 300 pounds.
3(3/4) quarts.
3 x 4 = 12.
12 + 3/4 = 15/4.
15/4 = 3.7.
3.7 x 6 = 22.2 quarts.

Question 4.
Nine of the players on the team weigh about 200 pounds. Doctors recommend that people of this weight each eat about 3$$\frac{7}{10}$$ grams of carbohydrates per pound each day. About how many combined grams of carbohydrates should these 9 players eat per pound each day?

The combined grams of carbohydrates should these 9 players eat per pound each day = 33.3 ft.

Explanation:
In the above-given question,
given that,
Nine of the players on the team weigh about 200 pounds.
3(7/10) = 3 x 10.
30 + 7/10 = 37/10.
37/10 = 3.7.
3.7 x 9 = 33.3 ft.

### Eureka Math Grade 4 Module 5 Lesson 40 Exit Ticket Answer Key

Coach Taylor asked his team to record the distance they ran during practice. The distances are listed in the table.

 Team Members Distance (in miles) Alec 1$$\frac{3}{4}$$ Henry 1$$\frac{1}{2}$$ Charles 2$$\frac{1}{8}$$ Steve 1$$\frac{3}{4}$$ Pitch 2$$\frac{2}{4}$$ Raj 1$$\frac{6}{8}$$ Pam 2$$\frac{1}{2}$$ Tony 1$$\frac{3}{8}$$

Alec: 1(3/4) = 1.7miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
1(3/4) = 1 x 4.
1 x 4 = 4.
4 + 3/4 = 7/4.
25/4 = 1.75.

Henry: 1(1/2) = 1.5miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
1(1/2) = 1 x 2.
1 x 2 = 2.
2 + 1/2 = 3/2.
3/2 = 1.5.

Charles: 2(1/8) = 2.1miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
2(1/8) = 2 x 8.
2 x 8 = 16.
16 + 1/8 = 17/8.
17/8 = 2.1.

Steve: 1(3/4) = 1.7miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
1(3/4) = 1 x 4.
1 x 4 = 4.
4 + 3/4 = 7/4.
25/4 = 1.75.

Pitch: 2(2/4) = 1miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
2(2/4) = 2 x 4.
2 x 4 = 8.
2 + 2/4 = 4/4.
4/4 = 1.

Raj: 1(6/8) = 1.7miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
1(6/8) = 1 x 8.
1 x 8 = 8.
8 + 6/8 = 14/8.
14/8 = 1.75.

Pam: 2(1/2) = 2.5miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
2(1/2) = 2 x 2.
2 x 2 = 4.
4 + 1/2 = 5/2.
5/2 = 2.5.

Tony: 1(3/8) = 1.37miles.

Explanation:
In the above-given question,
given that,
The distance of Team members in miles.
1(3/8) = 1 x 8.
1 x 8 = 8.
8 + 3/8 = 11/8.
11/8 = 1.37.

Question 1.
Use the table to locate the incorrect data on the line plot.
Circle any incorrect points.
Mark any missing points.

There are no incorrect points.

Explanation:
In the above-given question,
given that,

Question 2.
Of the team members who ran 1$$\frac{6}{8}$$ miles, how many miles did those team members run combined?

The team members run combined = 5.25 miles.

Explanation:
In the above-given question,
given that,
Of the team members who ran 1(6/8) miles.
1 x 6/8 = 8 + 6/8.
14/8 = 1.75 miles.
1.75 + 1.75 + 1.75 = 5.25 miles.

### Eureka Math Grade 4 Module 5 Lesson 40 Homework Answer Key

The chart to the right shows the total monthly rainfall for a city.

 Month Rainfall (in inches) January 2$$\frac{2}{8}$$ February 1$$\frac{3}{8}$$ March 2$$\frac{3}{8}$$ April 2$$\frac{5}{8}$$ May 4$$\frac{1}{4}$$ June 2$$\frac{1}{4}$$ July 3$$\frac{7}{8}$$ August 3$$\frac{1}{4}$$ September 1$$\frac{5}{8}$$ October 3$$\frac{2}{8}$$ November 1$$\frac{3}{4}$$ December 1$$\frac{5}{8}$$

January:2(2/8) = 2.2 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
2(2/8) = 2 x 8.
16 + 2/8 = 18/8.
18/8 = 2.25 in.

Febraury:1(3/8) = 1.3 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
1(3/8) = 1 x 8.
8 + 3/8 = 11/8.
11/8 = 1.3 in.

March:2(3/8) = 2.3 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
2(3/8) = 2 x 8.
16 + 3/8 = 19/8.
19/8 = 2.3 in.

April:2(5/8) = 2.6 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
2(5/8) = 2 x 8.
16 + 5/8 = 21/8.
21/8 = 2.6 in.

May:4(1/4) = 4.2 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
4(1/4) = 4 x 4.
16 + 1/4 = 17/4.
17/4 = 4.25 in.

June:2(1/4) = 2.2 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
2(1/4) = 2 x 4.
8 + 1/4 = 9/4.
9/4 = 2.25 in.

July:3(7/8) = 3.8 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
3(7/8) = 3 x 8.
24 + 7/8 = 31/8.
31/8 = 3.8 in.

August:3(1/4) = 3.2 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
3(1/4) = 3 x 4.
12 + 1/4 = 13/4.
13/4 = 3.25 in.

September:1(5/8) = 1.6 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
1(5/8) = 1 x 8.
8 + 5/8 = 13/8.
13/8 = 1.6 in.

October:3(2/8) = 3.2 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
3(2/8) = 3 x 8.
24 + 2/8 = 26/8.
26/8 = 3.25 in.

November:1(3/4) = 1.7 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
1(3/4) = 1 x 4.
4 + 3/4 = 7/4.
7/4 = 1.75 in.

December:1(5/8) = 1.6 in.

Explanation:
In the above-given question,
given that,
the monthly rainfall for a city.
1(5/8) = 1 x 8.
8 + 5/8 = 13/8.
13/8 = 1.625 in.

Question 1.
Use the data to create a line plot at the bottom of this page and to answer the following questions.

The points on the co-ordinate plane increase.

Explanation:
In the above-given question,
given that,
the months on the y-axis.
the rainfall on the x-axis.
the points on the graph increases.

Question 2.
What is the difference in rainfall from the wettest and driest months?

The difference in rainfall from the wettest and driest months = 2.95 in.

Explanation:
In the above-given question,
given that,
the rainfall from the wettest months = 4.25 in.
the rainfall from the driest months = 1.3 in.
4.25 – 1.3 = 2.95 in.

Question 3.
How much more rain fell in May than in April?

The more rain fell in May than April = 1.65 in.

Explanation:
In the above-given question,
given that,
the rain fell in may = 4.25 in.
the rain fell in April = 2.6 in.
4.25 – 2.6 = 1.65in.
so the rain fell in may than April = 1.65 in.

Question 4.
What is the combined rainfall amount for the summer months of June, July, and August?

The combined rainfall amount for the summer months of June, July, and August = 9.2 in.

Explanation:
In the above-given question,
given that,
the rainfall in June = 2.2 in.
the rainfall in July = 3.8 in.
the rainfall in August = 3.2 in.
2.2 + 3.8 + 3.2 = 9.2 in.
so the combined amount for the summer month of June, July, and August = 9.2 in.

Question 5.
How much more rain fell in the summer months than the combined rainfall for the last 4 months of the year?

The combined rainfall for the last 4 months of the year = 8.1 in.

Explanation:
In the above-given question,
given that,
the much more rain fell in the summer months = 9.2 in.
September = 1.6 in.
October = 3.2 in.
November = 1.75 in.
December = 1.625 in.
1.6 + 3.2 + 1.75 + 1.625 = 8.1 in.

Question 6.
In which months did it rain twice as much as it rained in December?

The two months it rains twice as much as it rained in December = August and October.

Explanation:
In the above-given question,
given that,
the rainfall in December = 1.625 in.
1.625 + 1.625 = 3.25 in
August = 3.2 in.
October = 3.2 in.

Question 7.
Each inch of rain can produce ten times that many inches of snow. If all of the rainfall in January was in the form of snow, how many inches of snow fell in January?