Eureka Math Grade 5 Module 1 End of Module Assessment Answer Key

Engage NY Eureka Math 5th Grade Module 1 End of Module Assessment Answer Key

Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key

Question 1.
The following equations involve different quantities and use different operations, yet produce the same result. Use a place value chart and words to explain why this is true.
4.13 × 103 = 4130 413,000 ÷ 102 = 4130
Eureka-Math-Grade-5-Module-1-Lesson-1-Problem-Set-Answer-Key-20
Eureka-Math-Grade-5-Module-1-Lesson-1-Problem-Set-Answer-Key-21
When I multiplied the digits moved 3 places to the left because they got larger. When I divided
the digits moved 2 places to the right, because they decreased.

Question 2.
Use an area model to explain the product of 4.6 and 3. Write the product in standard form, word form, and expanded form.
Answer:-
Eureka-Math-Grade-5-Module-1-Lesson-11-Problem-Set-Answer-Key-1-4

Question 3.
Compare using >, <, or =.
a. 2 tenths + 11 hundredths Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key 1 0.13
Answer:- 2 tenths + 11 hundredths Eureka-Math-Grade-5-Module-1-Mid-Module-Assessment-Task-Answer-Key-1 0.13

b. 13 tenths + 8 tenths + 32 hundredths Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key 1 2.42
Answer:- 13 tenths + 8 tenths + 32 hundredths Eureka-Math-Grade-5-Module-1-Mid-Module-Assessment-Task-Answer-Key-1 2.42

c. 342 hundredths + 7 tenths Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key 1 + 49 hundredths
Answer:- 342 hundredths + 7 tenths Eureka-Math-Grade-5-Module-1-Mid-Module-Assessment-Task-Answer-Key-1 + 49 hundredths

d. 2 + 31 × \(\frac{1}{10}\) + 14 × \(\frac{1}{100}\) Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key 1 2.324
Answer:- 2 + 31 × \(\frac{1}{10}\) + 14 × \(\frac{1}{100}\) Eureka-Math-Grade-5-Module-1-Mid-Module-Assessment-Task-Answer-Key-1 2.324

e. 14 + 72 × \(\frac{1}{10}\) + 4 × \(\frac{1}{1000}\) Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key 1 21.24
Answer:- 14 + 72 × \(\frac{1}{10}\) + 4 × \(\frac{1}{1000}\) Eureka-Math-Grade-5-Module-1-Mid-Module-Assessment-Task-Answer-Key-1 21.24

f. 0.3 × 102 + 0.007 × 103 Eureka Math Grade 5 Module 1 End of Module Assessment Task Answer Key 1 0.3 × 10 + 0.7 × 102
Answer:- 0.3 × 102 + 0.007 × 103 Eureka-Math-Grade-5-Module-1-Mid-Module-Assessment-Task-Answer-Key-1 0.3 × 10 + 0.7 × 102

Question 4.
Dr. Mann mixed 10.357 g of chemical A, 12.062 g of chemical B, and 7.506 g of chemical C to make 5 doses of medicine.
a. About how much medicine did he make in grams? Estimate the amount of each chemical by rounding to the nearest tenth of a gram before finding the sum. Show all your thinking.
Answer:-
A.  10.357g = 10.4g
B.   12.062g = 12.1g
C.   7.506g = 7.5g
10.4g+ 12.g+ 7.5g = 30.0 Dr. Mann made about 30 grams of medicine.

b. Find the actual amount of medicine mixed by Dr. Mann. What is the difference between your estimate and the actual amount?
Answer:- 10.357 + 12.062 + 7.506 = 29.925
30.0 – 29.925 = 0.075. The difference in the estimated and actual amounts is 0.075grams.

c. How many grams are in one dose of medicine? Explain your strategy for solving this problem.
Answer:- I used the algorithm to find my answer.
Eureka-Math-Grade-5-Module-1-Lesson-11-Problem-Set-Answer-Key-1-4
There are 5.985 grams of medicine in one dose.

d. Round the weight of one dose to the nearest gram.
Answer:- 5.985 g = 6 grams. is the nearest gram.

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