## Engage NY Eureka Math 6th Grade Module 2 Lesson 10 Answer Key

### Eureka Math Grade 6 Module 2 Lesson 10 Example Answer Key

Example 1.
IntroductIon to Partial Products
Use partial products and the distributive property to calculate the product.
200 × 32.6
200(32) + 200(0.6) = 6,400 + 120 = 6,520

Example 2.
Introduction to Partial Products
Use partial products and the distributive property to calculate the area of the rectangular patio shown below.

500 × 22. 12 = 500(22 + 0. 12) = 500(22) + 500(0. 12) = 11,000 + 60 = 11,060
The area of the patio would be 11,060 square feet.

### Eureka Math Grade 6 Module 2 Lesson 10 Exercise Answer Key

Exercise 1.
Use the boxes below to show your work for each station. Make sure that you are putting the solution for each station in the correct box.

 Station One: Station Two: Station Three: Station Four: Station Five:

### Eureka Math Grade 6 Module 2 Lesson 10 Problem Set Answer Key

Calculate the product using partial products.

Question 1.
400 × 45.2
400(45) + 400(0.2) = 18,000 + 80 = 18,080

Question 2.
149 × 100
100(14) + 100(0. 9) = 1,400 + 90 = 1,490

Question 3.
200 × 38.4
200(38) + 200(0.4) = 7,600 + 80 = 7,680

Question 4.
900 × 20.7
900(20) + 900(0.7) = 18,000 + 630 = 18,630

Question 5.
762 × 200
200(76) + 200(0.2) = 15,200 + 40 = 15,240

### Eureka Math Grade 6 Module 2 Lesson 10 Exit Ticket Answer Key

Complete the problem using partial products.

Question 1.
500 × 12.7