# Worksheet on Area and Perimeter of Squares | Area and Perimeter of Squares Worksheets with Answers

Worksheet on Area and Perimeter of Squares has different questions finding the area and perimeter of squares. Area and Perimeter of Squares Worksheet PDF will help you learn various skills related to squares and evaluate perimeter and area easily. Practice the questions regarding area and perimeter without fail and verify your answers from here. Solve the Area and Perimeter of Squares Questions available in the Area and Perimeter of Square Worksheets with Answers PDF on a regular basis and attempt the exam with confidence.

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## Perimeter and Area of Square Worksheets PDF

I. Find the perimeter and area of the square, whose dimensions are the following.
(i) 15 cm
(ii) 4.8 m
(iii) 3 m 35 cm
(iv) 80 dm
(v) 25 m

Solution:

i. We know that Area of the square=a2
=(15 cm)2
=225 sq cm
Perimeter=4a
=4(15 cm)
=60 cm
Therefore, the Area and perimeter of a square are 225 sq cm and 60 cm.
ii. We know that Area of the square=a2
=(4.8 m)2
=23.04 square meters
Perimeter=4a
=4(4.8 m)
=19.2m
Therefore, the Area and perimeter of a square are 23.04 square m and 19.2m

iii. Given 3 m 35 cm
we know that 1m=100 cm.

3m 35 cm=3(100) cm
=300 cm
3m 35 cm=300 cm + 35 cm
=335 cm
We know that Area of the square=a2
=(335 cm)2
=112225 sq cm
Perimeter=4a
=4(335 cm)
=1340 cm
Hence, the Area and perimeter of a square are 112225 sq cm and 1340 cm.
iv. We know that Area of the square=a2
=(80 dm)2
=6400 dm2
Perimeter=4a
=4(80 dm)
=320 dm
Hence, The area and perimeter of a square are 6400 dm2 and 320 dm.
v. We know that Area of the square=a2
=(25 m)2
=625 m2
Perimeter=4a
=4(25 m)
=100 m
Therefore, The area and perimeter of a square are 625 m2 and 100 m.

II. Find the perimeter of the squares whose side is:
(i) 10 m
(ii) 23 cm
(iii) 15 cm
(iv) 200 m
(v) 23 cm

Solution:

(i)Given side of a square is 10 m
We know that the perimeter of a square is 4a
=4(10 m)
=40 m
(ii) Given side of a square is 23 cm
We know that the perimeter of a square is 4a
=4(23 cm)
=92 cm
(iii) Given side of a square is 15 cm
We know that the perimeter of a square is 4a
=4(15 cm)
=60 cm
(iv) Given side of a square is 200 m
We know that the perimeter of a square is 4a
=4(200 m)
=800 m
(v) Given side of a square is 23 cm
We know that the perimeter of a square is 4a
=4(23 cm)
=92 cm

III. How many square tiles of side 6 cm will be needed to fit in a square floor of a bedroom of side 820 cm. Find the cost of tiling at the rate of Rs50 per tile?

Solution:

Given that,
Side of the square tile=6 cm
Area of the square tile=a2=(6 cm)2=36 cm2
Side of the bedroom=820 cm
Area of the bedroom=(820 cm)2=672400 sq cm.
No. of tiles=672400 sq cm/36 sq cm=18677
Cost of Tiling=18677 * 50=Rs 933850
Therefore, the cost of Tiling the bedroom is Rs 933850.

IV. The area of a square field is 64 hectares. Find the cost of fencing the field with a wire at the rate of Rs 5.20 per meter?

Solution:

Given that,
The area of a square field is 64 hectares.
1 hectare = 10000 sq.m.
So, 64 hectare = 640000 sq.m.
So, the Area of square field = 640000 sq.m.
Area of square=side2
side2=640000
side=$$\sqrt{ 640000 }$$
=800
The Perimeter of the square=4 × side
=4 × 800
=3200 m
Cost of fencing for 1m=Rs 5.20
Cost of fencing for 3200 m=3200 × 5.20
=Rs 16640
Therefore, The cost of fencing the field is Rs 16640.

V. The areas of a square and rectangle are equal. If the side of the square is 10 cm and the breadth of the rectangle 20 cm, find the length of the rectangle and its perimeter?

Solution:

Given that,
The side of the square is 10 cm and the breadth of the rectangle is 20 cm.
The areas of a square and rectangle are equal.
We know that area of square=a2
area of the rectangle=l*b
10 cm*10 cm=l*20 cm
100 sq cm/20 cm=l
l=5 cm
perimeter of the rectangle=2(l+w)
=2(5 cm+20 cm)
=2(25 cm)
=50 cm
Therefore, The length of the rectangle and perimeter of the rectangle is 5 cm and 50 cm.

VI. Raju paid Rs 50,000 to fence his square garden. If the fencing was done at the rate of Rs 20 per meter, what is the length of each side of the square?

Solution:

Given that,
Raju paid Rs 50,000 to fence his square garden.
The fencing was done at the rate of Rs 20 per meter.
we know that cost of fencing is calculated by multiplying the perimeter of the field and the cost per meter.
Therefore, The perimeter of the square garden=50,000/20=2500
we know that perimeter=4a.
4a=2500
a=2500/4=625
side of the square=25 m
Therefore, the length of the side of the square is 25 m.

VII. A square garden has a side of 320 meters. To put a wire fencing around this, what is the length of wire required?

Solution:

Given that,
The side of the square garden =320m
perimeter=fencing the garden.
The wire needed =320×4
=1280
Therefore, the wire needed for fencing is 1280m.

VIII. A rope length of 3600 m is used to fence a square garden. What is the length of the side of the garden?

Solution:

Given that,
Rope length=3600 m
Therefore, the perimeter of the garden P = 3600 m
We know that perimeter of a square = 4* length of a side
So, 4 *length of a side = 3600
The length of a side = 3600/4
Side length = 900 m
Therefore, the length of the side of the garden is 900 m.

IX. A wire is in the shape of a rectangle whose width is 10 cm is bent to form a square of side 15 cm. Find the rectangle length and also find which shape encloses more area.

Solution:

Given that,
rectangle width=10 cm
side of the square=15 cm
The perimeter of rectangle=Perimeter of square
2(l + w) = 4side
2(l + 10) = 4 x 15
2l + 20 = 60
2l=60-20
2l=40
l=40/2=20
Area of square = side²
= 15² = 15 cm x 15 cm
= 225 sq cm
Area of rectangle=20 cm x  10 cm
=20 cm x 10 cm=200 sq cm
Therefore, Square has more area.

X. Find the perimeter of a square whose area is 400 m².

Solution:

Given that,
Area of square=400 m²
We know that area=side2
400 m²=side2
side=$$\sqrt{ 400 m² }$$
=20 m
we know that perimeter of a square=4side
p=4 x 20 m
=80 m
Therefore, the perimeter of a square is 80 m.