Worksheet on Dividing Monomials | Free Printable Math Division of Monomials Worksheet PDF

(i) Given monomials are 48xy,4x
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
48xy/4x=6 × 8 × x × y/2 × 2 × x
=24y/2
=12y
Therefore, By dividing (48xy) with (4x) we get 12y.

(ii) Given (12p⁶q⁴) ÷ (-6p²q²)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
(12p⁶q⁴) / (-6p²q²)=2 × 6 × p × p ×p ×p × p ×p × q × q × q × q/-6 × p × p × q × q
=-2p⁴q²
Therefore, By dividing 12p⁶q⁴ with -6p²q² we get -2p⁴q².
(iii) Given (26m²pn²) ÷ (-2mn)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
26m²pn²/-2mn=2 × 13 × m × m × p × n × n/-2 ×m ×n
=-13mpn
Therefore, By dividing 26m²pn² with -2mn we get -13mpn.

(iv) Given (-96x⁴y³) ÷ (-8x²y)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
-96x⁴y³/8x²y=-12 × 8 × x × x × x × x × y × y × y/8 × x × x ×y
=-12 x²y²
Therefore, By dividing -96x⁴y³ with-8x²y we get -12 x²y².
(v) Given (-56 b²x³y⁵) ÷ (4bx²y²)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
-56 b²x³y⁵/4bx²y²= -4 × 14 × b × b × x ×  x × x × y × y × y × y × y/4 × b × x ×  x ×  y ×  y
=-14bxy³
Therefore, By dividing -54b²x³y⁵ with 4bx²y² we get -14bxy³.
(vi) Given (48ab) ÷ (-4)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
48ab/-4=12 × 4 × a × b/-4
=-12ab
Therefore, By dividing 48ab with -4 we get -12ab.
(vii) Given (75m²n) ÷ (5n)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
75m²n/5n= 15 × 5 × m × m × n/5 × n
=15m²
Therefore, By dividing 75m²n with 5n we get 15m² .

(i) Given, 60a² ÷ 5a
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
60a²/5a= 12 × 5 × a × a/5 × a
=12a
Hence, By dividing 60a² with 5a we get 12a.
(ii) Given, 63x²y² ÷ 7xy
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
63x²y²/7xy=7 × 9 × x × x × y× y/7 × x × y
=9xy
Therefore, By dividing 63x²y² with 7xy we get 9xy.
(iii) Given, 48a⁴b⁶ ÷ 12a²b²
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
48a⁴b⁶/12a²b²= 12 × 4 × a × a × a × a × b × b × b × b × b × b/4 × 3 × a × a × b × b
=4a2b4
Therefore, By dividing 48a⁴b⁶ with 12a²b² we get 4a2b4.
(iv) Given, 108m⁴n³ ÷ (-18m²n²)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
108m⁴n³/-18m²n²= 18 × 6 × m × m × m × m  × n × n × n/-6 × 3 × m × m × n × n
=-6m2n
Therefore, By dividing 108m⁴n³  with -18m²n² we get -6m2n.
(v) Given, (-46a⁴b⁵c²) ÷ (-23a²bc)
Now we have to write each term in expanded form and then cancel the terms which are common to both numerator and denominator.
-46a⁴b⁵c²/-23a²bc= -23 × 2 × a × a × a × a × b × b × b × b × b × c × c/-23 × a × a × b × b × c
=2a2b4c
Hence, By dividing -46a⁴b⁵c² with -23a²bc we get 2a2b4c.

(i) Given 30xy, 6x
30xy/6x=5y
Hence, By dividing the first monomial 30xy with the second monomial 6x we get 5y.
(ii) Given 75a⁴, 5b
75a⁴b/5b=15a⁴
Therefore, By dividing the first monomial 75a⁴b with the second monomial 5b we get 15a⁴.
(iii) Given 48ab⁴c, 8b²c
48ab⁴c/8b²c=6ab²
Therefore, By dividing the first monomial 48ab4c with the second monomial 8b2c we get 6ab².
(iv) Given 30a⁵, (-a²)
30a⁵5/-a²=-30a³
Hence, By dividing the first monomial 30a⁵ with the second monomial -a² we get -30a³.
(v) Given 22a²b⁵, 2ab
22a²b⁵/ 2ab=11ab⁴
Therefore, By dividing the first monomial 22a2b5 with the second monomial 2ab we get 11ab⁴.

(i) Given (-18×8) ÷ (-9x²)
-18x⁸/-9x²=2x⁶
Hence, By dividing -18x⁸ with -9x² we get 2x⁶.
(ii) Given (40a⁴b⁸c⁴) ÷ (5a²b²c²)
40a⁴b⁸c⁴/5a²b²c²=8a²b⁶c²
Hence, By dividing 40a⁴4b⁸c⁴ with 5a²b²c² we get 8a²b⁶c².
(iii) Given (14x⁴4y³z²) ÷ (-2x²yz)
14x⁴y³z²/-2x²yz=-7x²y²z
Hence, By dividing 14x⁴y³z² with -2x²yz we get -7x²y²z.
(iv) Given (81a⁷b⁸c³) ÷ (9a⁴b3c³)
81a⁷b⁸c³/9a4b3c³=9a³b⁵
Hence, By dividing 81a⁷b⁸c³ with 9a4b3c³ we get 9a³b⁵.
(v) Given (51x⁶y5z4) ÷ (-3x⁴y²z)
51x⁶y5z4/-3x⁴y²z=-17x²2y³z³
Hence, By dividing 51x⁶y5z4 with -3x⁴y²z we get -17x²2y³z³.