Practice the questions given in the Worksheet on Word Problems on Division of Mixed Fractions and learn the concept. Test your understanding by answering various problems in the Dividing Mixed Numbers Worksheet and improvise on the areas needed accordingly. Know the Problem Solving Approach used and solve related problems you come across in your exams with utmost confidence. Our Free Worksheets on Mixed Numbers Word Problems are flexible to use and develop excellent study habits among your kids.
Also, Read:
- Worksheet on Word Problems on Addition of Mixed Fractions
- Worksheet on Word Problems on Subtraction of Mixed Fractions
- Worksheet on Word Problems on Multiplication of Mixed Fractions
Dividing Mixed Fractions Worksheets with Answers PDF
Example 1.
Sindhu has 7 mangoes. She wants to share them with her friends. If Sindhu wants to give 1 \(\frac {2}{5} \) of the mango to each of her friends, Find how many friends will get some mango?
Solution:
No. of mangoes Sindhu has=7
Sindhu gives mango to each of her friend=1 \(\frac {2}{5} \)
No. of friends will get Mangoes= 7 ÷1 \(\frac {2}{ 5} \)
=7 ÷ \(\frac {7}{ 5} \)
=\(\frac {7× 5}{ 7 × 1} \)
=\(\frac {35}{7} \)
=5
Therefore, 5 friends will get some mangoes.
Example 2.
Anand bought 10 gallons of green paint for painting the rooms in the office. If each room requires 1 \(\frac {1}{9} \) of a gallon of paint. How many rooms will get painted?
Solution:
No. of gallons of paint bought for painting the rooms=10
No. of gallons of paint required for each room=1 \(\frac {1}{9} \)
No. of rooms will get painted=10 ÷1 \(\frac {1}{9} \)
=10 ÷ \(\frac {10}{9} \)
= \(\frac {10× 9}{ 10 × 1} \)
=\(\frac {90}{ 10} \)
=9
Therefore, 9 rooms will get painted.
Example 3.
If Janaki runs 1 \(\frac {1}{4} \) of a kilometer per hour. How many hours would it take to run 5 km?
Solution:
No. of kilometers Janaki runs per hour=1 \(\frac {1}{4} \)
No. of hours required for running 5 km =5 ÷1 \(\frac {1}{4} \)=5 ÷ \(\frac {5}{4} \)
=5 ×\(\frac {4}{5} \)
=20/5\(\frac {20}{5} \)
=4 hours
Therefore, Janaki requires 4 hours to run 5 km.
Example 4.
Suppose Grishma has 20 apples and you give each of your friends 1 \(\frac {1}{4} \) of an apple. Find how many friends Grishma has?
Solution:
No. of apples Grishma has=20
Each friend will get an apple=1 \(\frac {1}{4} \)
No. of Friends Grishma has=20 ÷1 \(\frac {1}{4} \)
= 20 ÷ \(\frac {5}{4} \)
=20 × \(\frac {4}{5} \)
=\(\frac {180}{5} \)
=36
Therefore, Grishma has 36 friends.
Example 5.
Bhaskar got a plant in the garden. It grows 1 \(\frac {3}{4} \) inches every month, How long it will take time for a plant to grow 9 \(\frac {1}{4} \) inches?
Solution:
The plant grows every month=1 \(\frac {3}{4} \)
Time is taken for the plant to grow 9 \(\frac {1}{4} \) inches = 1 \(\frac {3}{4} \) ÷ 9 \(\frac {1}{4} \)
=\(\frac {7}{4} \)÷\(\frac {37}{4} \)
=\(\frac {7 × 4}{37 × 4} \)
=\(\frac {28}{148} \)
=\(\frac {7}{37} \)
Therefore, the time taken for a plant to grow 9 \(\frac {1}{4} \) inches is \(\frac {7}{37} \).
Example 6.
Priya’s house is under construction, She is going to use tiles for the floor. The tile is in a square shape which is \(\frac {4}{5} \) feet wide. The size of the room is 12 \(\frac {1}{8} \) feet wide, how many tiles are required to cover the width of the room?
Solution:
The width of the tile = \(\frac {4}{5} \)
Size of the room=12 \(\frac {1}{8} \)
Tiles required to cover the width of the room= \(\frac {4}{5} \) ÷12 \(\frac {1}{8} \)
=\(\frac {4}{5} \) ÷ \(\frac {97}{8} \)
=\(\frac {4 × 8}{5 × 97} \)
=\(\frac {32}{485} \)
Therefore, \(\frac {32}{485} \) tiles required to cover the width of the room.
Example 7.
Rithu has a material which is of length 1 \(\frac {2}{8} \) m, she wants to cut pieces that are \(\frac {1}{4} \) m long. How many pieces can she cut?
Solution:
Ritu has a material which is of length= 1 \(\frac {2}{8} \)
The length of pieces=\(\frac {1}{4} \)
Total no. of pieces Ritu can cut= 1 \(\frac {2}{8} \) ÷\(\frac {1}{4} \)
= \(\frac {10}{8} \) ÷ \(\frac {1}{4} \)
=\(\frac {5}{4} \) ÷ \(\frac {1}{4} \)
=\(\frac {5 × 4}{4× 1} \)
=\(\frac {20}{4} \)
=5
Therefore, the total no. of pieces Ritu can cut is 5.
Example 8.
Prasanti has 1 \(\frac {1}{3} \) of an hour to answer the problems in the maths examination. If it takes Prasanti \(\frac {1}{3} \) of an hour to answer one problem, How many problems she can answer in the exam in the time left?
Solution:
Prasanti has the time to answer the exam= 1 \(\frac {1}{3} \)
Time is taken by Prasanti to answer one problem= \(\frac {1}{3} \)
No. of Problems Prasanti can answer = 1 \(\frac {1}{3} \) ÷ \(\frac {1}{3} \)
=\(\frac {4}{3} \) ÷ \(\frac {1}{3} \)
=\(\frac {4 × 3}{3 × 1} \)
=\(\frac {12}{3} \)
=4
Therefore, Prasanti can answer 4 problems in the time left.
Example 9.
A wood that is 14 \(\frac {1}{3} \) feet long is cut into 5 pieces. Find how many feet long is each piece?
Solution:
Length of the wood = 14 \(\frac {1}{3} \)
No. of pieces of wood=5
Each piece is of length= 14 \(\frac {1}{3} \) ÷ 5
=\(\frac {44}{3} \) ÷ 5
=\(\frac {44 × 1}{3 × 5} \)
=\(\frac {44}{15} \)
=2 \(\frac {14}{15} \)
Therefore, the length of each piece is 2 \(\frac {14}{15} \) .
Example 10.
Anusha completes \(\frac {1}{4} \) part of the shopping in 1 \(\frac {1}{6} \) hours. How much time she will take to complete the shopping?
Solution:
Time is taken by Anusha to complete the \(\frac {1}{4} \) part of shopping = 1 \(\frac {1}{6} \)
Time is taken by Anusha to complete the shopping =1 \(\frac {1}{6} \) ÷ \(\frac {1}{4} \)
= \(\frac {7}{6} \) ÷ \(\frac {1}{4} \)
=\(\frac {7 × 4}{6 × 1} \) =\(\frac {28}{6} \)=4 \(\frac {2}{3} \).
Therefore, Anusha takes 4 \(\frac {2}{3} \) hours to complete the shopping.