Mixed Fractions are the ones having a Whole Number and a Fraction. Learn how to solve problems on adding mixed fractions by availing our quick resource on Word Problems on Addition of Mixed Fractions. Try to solve the Questions on Adding Mixed Numbers available on your own before you cross-check with the respective Solutions and explanations. For better understanding, we have provided the Examples on Mixed Numbers Addition step by step. Understand the Problem Solving Strategy Used and Solve the Related Problems on your own.<\/p>\n
Also, Refer:<\/p>\n
Example 1.<\/strong> Example 2. Example 3. Example 4. Example 5. Example 6. Example 7. Example 8.\u00a0<\/strong> Example 9. Example 10.<\/strong> Mixed Fractions are the ones having a Whole Number and a Fraction. Learn how to solve problems on adding mixed fractions by availing our quick resource on Word Problems on Addition of Mixed Fractions. Try to solve the Questions on Adding Mixed Numbers available on your own before you cross-check with the respective Solutions and … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":117309,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/06\/Word-Problems-on-Addition-of-Mixed-Fractions.png","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/117211"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=117211"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/117211\/revisions"}],"predecessor-version":[{"id":135463,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/117211\/revisions\/135463"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media\/117309"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=117211"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=117211"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=117211"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nRam walked 1\\(\\frac { 3 }{ 5 } \\)\u00a0 km on Monday, 3 \\(\\frac { 1 }{ 6 } \\) km on Tuesday, and 2 \\(\\frac { 1 }{ 12 } \\) \u00a0km on Wednesday. Find out the distance he walked in all?
\nSolution:
\n<\/b>Ram walked on monday= 1 \\(\\frac { 3 }{ 5 } \\)
\nRam walked on tuesday=3 \\(\\frac { 1 }{ 6 } \\)
\nRam walked on wednesday=2 \\(\\frac { 1 }{ 12 } \\)
\nThe distance he walked in all days= 1 \\(\\frac { 3 }{ 5 } \\) + 3\\(\\frac { 1 }{ 6 } \\) + 2 \\(\\frac { 1 }{ 12 } \\)
\n=\\(\\frac { 8 }{ 5 } \\) +\\(\\frac { 19 }{ 6 } \\) + \\(\\frac { 25 }{ 12 } \\)
\n=\\(\\frac {8 \u00d7 12\u00a0 }{ 5 \u00d712 } \\) +\\(\\frac {19 \u00d7 10\u00a0 }{ 6 \u00d710 } \\)\u00a0+\\(\\frac {25 \u00d75 \u00a0 }{ 12 \u00d75 } \\) ( LCM of 5,6,12 is 60)
\n= \\(\\frac { 96 }{ 60 } \\)+\\(\\frac { 190 }{ 60 } \\)1 +\\(\\frac { 125 }{ 60 } \\)
\n=\\(\\frac { 411 }{ 60 } \\)
\n=\\(\\frac { 137 }{ 20 } \\) =6 \\(\\frac { 17 }{ 20 } \\)
\nHence, Ram walked 6 \\(\\frac { 17 }{ 20 } \\) km.<\/p>\n
\n<\/strong>Laxman bought 2 \\(\\frac { 1 }{ 2 } \\) kg wheat, 4\\(\\frac { 1 }{ 4 } \\)\u00a0 of sugar, 10 \\(\\frac { 1 }{ 2 } \\) kg rice. How many kg of items did he buy?
\nSolution:
\n<\/strong>Laxman bought wheat= 2 \\(\\frac { 1 }{ 2 } \\) kg
\nLaxman bought sugar=4 \\(\\frac { 1 }{ 4 } \\) kg
\nLaxman bought rice=10 \\(\\frac { 1 }{ 2 } \\) kg
\nTotal no. of kg of items Laxman bought\u00a0 = 2 \\(\\frac { 1 }{ 2 } \\)\u00a0 + 4 \\(\\frac { 1 }{ 4 } \\) + 10 \\(\\frac { 1 }{ 2 } \\)
\n=\\(\\frac { 5 }{ 2 } \\) +\\(\\frac { 17 }{ 4 } \\) +\\(\\frac { 21 }{ 2 } \\)
\n=\\(\\frac { 5 \u00d72}{ 2\u00d72 } \\) + \\(\\frac { 17}{ 4 } \\) \u00a0+\\(\\frac { 21 \u00d72 }{ 2\u00d72 } \\)
\n= \\(\\frac { 10 }{ 4 } \\) +\\(\\frac { 17 }{ 4 } \\) + \\(\\frac { 42 }{ 4 } \\)
\n=\u00a0 \\(\\frac { 69 }{ 4 } \\) =17 \\(\\frac { 1 }{ 4 } \\) .
\nTherefore, Laxman bought 17 \\(\\frac { 1 }{ 4 } \\) kg of items.<\/p>\n
\n<\/strong>Rajesh donated 19 \\(\\frac { 1 }{ 2 } \\) kg of rice, 25 \\(\\frac { 1 }{ 4 } \\) kg of wheat, and 11 \\(\\frac { 3 }{ 4 } \\) of oil. Find how many kgs of groceries he donated?
\nSolution:
\n<\/strong>Rajesh donated rice=19 \\(\\frac { 1 }{ 2 } \\)
\nRajesh donated wheat=25 \\(\\frac { 1 }{ 4 } \\)
\nRajesh donated oil=11\\(\\frac { 3}{ 4 } \\)
\nTotal no. of kg of groceries Rajesh donated =19 \\(\\frac { 1 }{ 2 } \\)+ 25 \\(\\frac { 1 }{ 4 } \\) + 11 \\(\\frac { 3 }{ 4 } \\)
\n=\\(\\frac { 39 }{ 2 } \\)+\\(\\frac { 101 }{ 4 } \\)+\\(\\frac { 47 }{ 4 } \\)
\n= \\(\\frac { 39 \u00d7 2 }{ 2 \u00d7 2 } \\)+\\(\\frac { 101 }{ 4 } \\)+ \\(\\frac { 47 }{ 4 } \\)
\n=\\(\\frac { 78 }{ 4 } \\)+\\(\\frac { 101 }{ 4 } \\)+ \\(\\frac { 47 }{ 4 } \\)47\/4
\n=\\(\\frac { 226 }{ 4 } \\)=\\(\\frac { 113 }{ 2 } \\)=56\\(\\frac {1 }{ 2 } \\)
\nHence, Rajesh donated 56 \\(\\frac {1 }{ 2 } \\) kgs of groceries.<\/p>\n
\n<\/strong>Giri went on walking 3 \\(\\frac {1 }{ 2 } \\)\u00a0 km, and then cycling by 4 \\(\\frac {1 }{ 4 } \\) km and then he took a lift and traveled 8 \\(\\frac {3 }{ 8 } \\) km. Find out how much distance he traveled?
\nSolution:
\n<\/strong>Giri went on walking =3 \\(\\frac {1 }{ 2 } \\)\u00a0 km
\nGiri went on cycling=4 \\(\\frac {1 }{ 4 } \\) km
\nGiri took a lift and travelled=8 \\(\\frac {3}{ 8 } \\) km
\nThe total distance he travelled= 3 \\(\\frac {1 }{ 2 } \\)+4 \\(\\frac {1 }{ 4 } \\) + 8 \\(\\frac {3}{ 8 } \\)
\n=\\(\\frac {7}{ 2 } \\)+\\(\\frac {9 }{ 4 } \\)+\\(\\frac {67 }{ 8 } \\)
\n=\\(\\frac {7 \u00d7 4 }{ 2 \u00d74 } \\) + \\(\\frac {9 \u00d7 2 }{ 4 \u00d7 2} \\) \u00a0+ \\(\\frac {67}{ 8 } \\) (LCM of 2,4,8 is 8)
\n=\\(\\frac {28}{ 8 } \\)+\\(\\frac {18}{ 8 } \\)+ \\(\\frac {67}{ 8 } \\)
\n=\\(\\frac {113}{ 8 } \\)=14 \\(\\frac {1}{ 8 } \\)<\/p>\n
\n<\/strong>Sameera went to a market and bought mangoes 3 \\(\\frac {3}{ 4 } \\) and her sister bought 4 \\(\\frac {5}{ 8 } \\) mangoes. Find how many kgs of mangoes bought by Sameera and her sister?
\nSolution:
\n<\/strong>Sameera bought mangoes= 3 \\(\\frac {3}{ 4 } \\)
\nSameera sister bought mangoes=4 \\(\\frac {5}{ 8 } \\)
\nTotal no. of kg of mangoes bought by Sameera and her sister=3 \\(\\frac {3}{ 4 } \\)\u00a0 + 4 \\(\\frac {5}{ 8 } \\)
\n= \\(\\frac {15}{ 4 } \\) + \\(\\frac {29}{ 8 } \\)
\n= \\(\\frac {15 \u00d7 2}{ 4\u00d7 2} \\)+\\(\\frac {29}{ 8 } \\)
\n=\u00a0 \\(\\frac {30}{ 8 } \\)+\\(\\frac {29}{ 8 } \\)=\\(\\frac {59}{ 8 } \\)
\n=7\\(\\frac {3}{ 8 } \\)
\nTherefore, Sameera and her sister bought 7\\(\\frac {3}{ 8 } \\)\u00a0 kg of mangoes.<\/p>\n
\n<\/strong>For a birthday party, Akhil distributed 14 \\(\\frac {1}{ 2 } \\) liters of Pepsi, 10 \\(\\frac {3}{ 4 } \\) liters of sprite, and 12 \\(\\frac {5}{ 8 } \\) liters of thum sup. Find how many liters of cool drinks he distributed at the birthday party?
\nSolution:
\n<\/strong>Akhil distributed pepsi= 14 \\(\\frac {1}{ 2 } \\)
\nAkhil distributed sprite=10 \\(\\frac {3}{ 4 } \\)
\nAkhil distributed thums up=12 \\(\\frac {5}{ 8 } \\)
\nTotal no. of liters of cool drinks Akhil distributed in the party=14 \\(\\frac {1}{ 2 } \\) +10 \\(\\frac {3}{ 4 } \\) +12 \\(\\frac {5}{ 8 } \\)
\n=\\(\\frac {29}{ 2 } \\)+\\(\\frac {43}{ 4 } \\)+\\(\\frac {101}{ 8 } \\)
\n=\\(\\frac {29 \u00d74}{ 2 \u00d74 } \\)+\\(\\frac {43 \u00d72}{ 4 \u00d72 } \\)+\\(\\frac {101}{ 8 } \\)
\n=\\(\\frac {116}{ 8 } \\)+ \\(\\frac {86}{ 8 } \\)+\\(\\frac {101}{ 8 } \\)
\n=\\(\\frac {303}{ 8 } \\)=37 \\(\\frac {7}{ 8 } \\)
\nAkhil distributed 37 \\(\\frac {7}{ 8 } \\) liters of cool drinks at the birthday party.<\/p>\n
\n<\/strong>In a competition between two friends, Anjana prepared 20 \\(\\frac {1}{ 2 } \\) lit of orange juice and Sanjana prepared 22 \\(\\frac {5}{ 8 } \\) of orange juice. Find how many liters of juice are prepared by both of them?
\nSolution:
\n<\/strong>Anjana prepared orange juice= 20 \\(\\frac {1}{ 2 } \\)
\nSanjana prepared orange juice=22 \\(\\frac {5}{ 8} \\)
\nNo. of liters of juice prepared by both of them= 20 \\(\\frac {1}{ 2 } \\) + 22 \\(\\frac {5}{ 8 } \\)
\n= \\(\\frac {41}{ 2 } \\)+ \\(\\frac {181}{ 8 } \\)
\n=\\(\\frac {41 \u00d74}{ 2 \u00d74 } \\) +\\(\\frac {181}{ 8 } \\)
\n=\\(\\frac {164}{ 8 } \\)+\\(\\frac {181}{ 8 } \\)=\\(\\frac {345}{ 8 } \\)
\n=43\\(\\frac {1}{ 8 } \\)
\nAnjana and sanjana both prepared 43 \\(\\frac {1}{ 8 } \\) liters of juice.<\/p>\n
\nSriram has wires of length 6 \\(\\frac {3}{ 4 } \\)\u00a0 m, 10 \\(\\frac {5}{ 8 } \\). Find the length of both the wires?
\nSolution:
\n<\/strong>First wire length= 6 \\(\\frac {3}{ 4 } \\)
\nSecond wire length=10 \\(\\frac {5}{ 8 } \\)
\nLength of both the wires= 6 \\(\\frac {3}{ 4 } \\)\u00a0 +10 \\(\\frac {5}{ 8 } \\)
\n=\\(\\frac {27}{ 4 } \\)\u00a0 +\\(\\frac {85}{ 8 } \\)
\n= \\(\\frac {27 \u00d7 2}{ 4 \u00d7 2 } \\) +\\(\\frac {85}{ 8 } \\)
\n=\\(\\frac {54}{ 8 } \\)\u00a0 +\\(\\frac {85}{ 8 } \\) =\\(\\frac {139}{ 8 } \\)
\n=17 \\(\\frac {3}{ 8 } \\)
\nThe length of both wires is 17 \\(\\frac {3}{ 8 } \\) .<\/p>\n
\n<\/strong>Bhaskar spent 8 \\(\\frac {1}{ 2 } \\) hours on work, 2 \\(\\frac {1}{ 2} \\)\u00a0 hours on the playground. He spent 1 \\(\\frac {3}{ 4 } \\)on\u00a0 walking. Find how much time he spent on the day?
\nSolution:<\/strong>
\nBhaskar spent on work=8 \\(\\frac {1}{ 2 } \\)
\nBhaskar spent on playground=2 \\(\\frac {1}{ 2 } \\)
\nBhaskar spent on walking=1 \\(\\frac {3}{ 4} \\)
\nBhaskar spent on the day= 8 \\(\\frac {1}{ 2 } \\) + 2 \\(\\frac {1}{ 2 } \\) + 1\\(\\frac {3}{ 4 } \\)
\n= \\(\\frac {17}{ 2 } \\) +\\(\\frac {5}{ 2 } \\) +\\(\\frac {7}{ 4 } \\)
\n= \\(\\frac {17 \u00d7 2}{ 2 \u00d72 } \\) + \\(\\frac { 5\u00d7 2}{ 2 \u00d72 } \\) \u00a0+\\(\\frac {7}{ 4 } \\)
\n=\\(\\frac {34}{ 4 } \\) + \\(\\frac {10}{ 4 } \\) +\\(\\frac {7}{ 4 } \\)
\n=\\(\\frac {51}{ 4 } \\) =12 \\(\\frac {3}{ 4 } \\)
\nTherefore, Bhaskar spent 12 \\(\\frac {3}{ 4 } \\)\u00a0 hours a day.<\/p>\n
\nSrikrishna bought 5 \\(\\frac {1}{ 4 } \\) of vegetables, 20 \\(\\frac {3}{ 4 } \\)\u00a0 kg of groceries, and 1 \\(\\frac {1}{ 2} \\)\u00a0 kg of chicken. Find how many kgs he bought?
\nSolution:
\n<\/strong>Srikrishna bought vegetables= 5 \\(\\frac {1}{ 4 } \\) kg
\nSrikrishna bought groceries=20 \\(\\frac {3}{ 4 } \\)\u00a0 \u00a0kg
\nSrikrishna bought chicken= 1 \\(\\frac {1}{ 2 } \\)\u00a0 kg
\nSrikrishna bought all=5 \\(\\frac {1}{ 4 } \\) +20 \\(\\frac {3}{ 4 } \\) +1 \\(\\frac {1}{ 2 } \\)
\n= \\(\\frac {21}{ 4 } \\) +\\(\\frac {83}{ 4 } \\) +\\(\\frac {3}{ 2 } \\)
\n=\\(\\frac {21}{ 4 } \\) +\\(\\frac {83}{ 4 } \\)+ \\(\\frac {3 \u00d72}{ 2 \u00d7 2 } \\)
\n=\\(\\frac {21}{ 4 } \\) +\\(\\frac {83}{ 4 } \\) + \\(\\frac {6}{ 4 } \\)
\n=\\(\\frac {110}{ 4 } \\)=\\(\\frac {55}{ 2 } \\)=27 \\(\\frac {1}{ 2 } \\)
\nSrikrishna bought 27 \\(\\frac {1}{ 2 } \\) kg.<\/p>\n","protected":false},"excerpt":{"rendered":"