{"id":147184,"date":"2023-11-27T00:04:44","date_gmt":"2023-11-26T18:34:44","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=147184"},"modified":"2023-11-28T17:40:05","modified_gmt":"2023-11-28T12:10:05","slug":"spectrum-math-grade-7-chapter-2-posttest-answer-key","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/spectrum-math-grade-7-chapter-2-posttest-answer-key\/","title":{"rendered":"Spectrum Math Grade 7 Chapter 2 Posttest Answer Key"},"content":{"rendered":"

This handy Spectrum Math Grade 7 Answer Key<\/a><\/strong>\u00a0Chapter 2 Posttest<\/strong>\u00a0provides detailed answers for the workbook questions<\/p>\n

Spectrum Math Grade 7 Chapter 2 Posttest Answers Key<\/h2>\n

Check What You Learned<\/strong><\/p>\n

Multiplying and Dividing Rational Numbers<\/strong><\/p>\n

Rewrite each expression using the distributive property.<\/strong><\/p>\n

Question 1.
\na. 7 \u00d7 (10 + a) =
\n_____________
\nAnswer: (7 \u00d7 10) + (7 \u00d7 a)
\n7 \u00d7 (10 + a) = (7 \u00d7 10) + (7 \u00d7 a)
\nThe distributive property states that multiplying the sum of two or more addends by a number yields the same outcome as multiplying each addend separately by the number and combining the resulting products.<\/p>\n

b. (2 \u00d7 c) + (2 \u00d7 d) =
\n_____________
\nAnswer: 2 \u00d7 (c + d)
\n(2 \u00d7 c) + (2 \u00d7 d) = 2 \u00d7 (c + d)
\nThe distributive property states that multiplying the sum of two or more addends by a number yields the same outcome as multiplying each addend separately by the number and combining the resulting products.<\/p>\n

Question 2.
\na. (y \u00d7 2) + (y \u00d7 6) =
\n_____________
\nAnswer: y \u00d7 (2 + 6)
\n(y \u00d7 2) + (y \u00d7 6) = y \u00d7 (2 + 6)
\nThe distributive property states that multiplying the sum of two or more addends by a number yields the same outcome as multiplying each addend separately by the number and combining the resulting products.<\/p>\n

b. 5 \u00d7 (k + 4) =
\n_____________
\nAnswer: (5 \u00d7 k) + (5 \u00d7 4)
\n5 \u00d7 (k + 4) = (5 \u00d7 k) + (5 \u00d7 4)
\nThe distributive property states that multiplying the sum of two or more addends by a number yields the same outcome as multiplying each addend separately by the number and combining the resulting products.<\/p>\n

Identify the property described as commutative, associative, identity, or zero.<\/strong><\/p>\n

Question 3.
\nWhen three or more numbers are multiplied together, the product is the same regardless of how the factors are grouped. _________
\nAnswer: associative property
\nWhen three or more numbers are multiplied together, the product is the same regardless of how the factors are grouped is called associative property.
\nAccording to the associative principle of multiplication, when multiplying three integers, the outcome will always be the same regardless of how the numbers are grouped. If there are three numbers, x, y and z, the associative property of multiplication implies that x \u00d7 (y \u00d7 z) = (x \u00d7 y) \u00d7 z.<\/p>\n

Question 4.
\nWhen zero is divided by any number, the quotient is always 0. _________
\nAnswer: zero property
\nWhen zero is divided by any number, the quotient is always 0 is called zero property.
\nAccording to the zero property of division, if 0(zero) is divided by any other number, the result will be zero. If there is a number, x then the zero property of division implies that 0 \u00f7 x = 0.<\/p>\n

Question 5.
\nThe product of any number and 1 is that number. ___________
\nAnswer: Identity Property
\n<\/strong>The product of any number and 1 is that number is called Identity Property.
\nAccording to the identity property of multiplication, if a number is multiplied by 1 (one), the result will be the original number. This property is applied when numbers are multiplied by 1. If there is a number, x then the identity property implies that x \u00d7 1 = x.<\/p>\n

Question 6.
\nWhen two numbers are multiplied together, the product is the same regardless of the order of the factors. ________
\nAnswer: Commutative Property
\n<\/strong>When two numbers are multiplied together, the product is the same regardless of the order of the factors is called Commutative Property.
\n<\/strong>According to the commutative property of multiplication, changing the order of the numbers we are multiplying does not change the product. If there are two numbers, x and y, the commutative property of multiplication implies that x \u00d7 y = y \u00d7 x.<\/p>\n

Question 7.
\na. y \u00d7 x = x \u00d7 y
\n____________
\nAnswer: Commutative Property
\ny \u00d7 x = x \u00d7 y
\nThe above expression is the example for Commutative Property.
\n<\/strong>When two numbers are multiplied together, the product is the same regardless of the order of the factors is called Commutative Property.
\n<\/strong>According to the commutative property of multiplication, changing the order of the numbers we are multiplying does not change the product. If there are two numbers, x and y, the commutative property of multiplication implies that x \u00d7 y = y \u00d7 x.<\/p>\n

b. (a \u00d7 b) \u00d7 c = a \u00d7 (b \u00d7 c)
\n____________
\nAnswer: associative property
\n(a \u00d7 b) \u00d7 c = a \u00d7 (b \u00d7 c)
\nThe above expression is the example for associative property.
\nAccording to the associative principle of multiplication, when multiplying three integers, the outcome will always be the same regardless of how the numbers are grouped. If there are three numbers, x, y and z, the associative property of multiplication implies that x \u00d7 (y \u00d7 z) = (x \u00d7 y) \u00d7 z.<\/p>\n

Question 8.
\na. 5 \u00d7 1 = 5
\n____________
\nAnswer: Identity Property
\n5 \u00d7 1 = 5
\nThe above expression is the example for Identity Property.
\nAccording to the identity property of multiplication, if a number is multiplied by 1 (one), the result will be the original number. This property is applied when numbers are multiplied by 1. If there is a number, x then the identity property implies that x \u00d7 1 = x.<\/p>\n

b. 0 \u00f7 6 = 0
\n____________
\nAnswer: Zero Property
\n0 \u00f7 6 = 0
\nThe above expression is the example for zero property.
\nWhen zero is divided by any number, the quotient is always 0 is called zero property.
\nAccording to the zero property of division, if 0(zero) is divided by any other number, the result will be zero. If there is a number, x then the zero property of division implies that 0 \u00f7 x = 0.<\/p>\n

Change each rational number into a decimal using long division. Place a line over digits which repeat.<\/strong><\/p>\n

Question 9.
\na. \\(\\frac{2}{9}\\)
\n_________________________
\nAnswer: 0.222
\n\"Spectrum
\nRational numbers can be converted into decimals using long division. All fractions will be turned into decimals that either terminate or repeat. Repeating decimals can be given as a same pattern of numbers will get when we perform division. A line will be placed above the digits which are repeating.
\nHere, If we divide 2 by 9, we will get repeating decimal 0.222, so a line was indicated above 2.
\nTherefore, \\(\\frac{2}{9}\\) = 0.222<\/p>\n

b. \\(\\frac{4}{9}\\) =
\n_______________________________
\nAnswer: 0.444
\n\"Spectrum
\nRational numbers can be converted into decimals using long division. All fractions will be turned into decimals that either terminate or repeat. Repeating decimals can be given as a same pattern of numbers will get when we perform division. A line will be placed above the digits which are repeating.
\nHere, If we divide 4 by 9, we will get repeating decimal 0.444, so a line was indicated above 4.
\nTherefore, \\(\\frac{4}{9}\\) = 0.444<\/p>\n

Question 10.
\na. \\(\\frac{1}{11}\\)
\n_____________________________
\nAnswer: 0.0909
\n\"Spectrum
\nRational numbers can be converted into decimals using long division. All fractions will be turned into decimals that either terminate or repeat. Repeating decimals can be given as a same pattern of numbers will get when we perform division. A line will be placed above the digits which are repeating.
\nHere, If we divide 1 by 11, we will get repeating decimal 0.0909, so a line was indicated above 09.
\nTherefore, \\(\\frac{1}{11}\\) = 0.0909<\/p>\n

b. \\(\\frac{2}{5}\\) =
\n________________
\nAnswer:
\n\"Spectrum
\nRational numbers can be converted into decimals using long division. All fractions will be turned into decimals that either terminate or repeat. Repeating decimals can be given as a same pattern of numbers will get when we perform division. A line will be placed above the digits which are repeating.
\nHere, If we divide 2 by 5, we will get terminating decimal 0.4
\nTherefore, \\(\\frac{2}{5}\\) = 0.4<\/p>\n

Multiply or divide. Write answers in simplest form.<\/strong><\/p>\n

Question 11.
\na. \\(\\frac{3}{4}\\) \u00d7 \\(\\frac{1}{6}\\) = ____
\nAnswer: \\(\\frac{1}{8}\\)
\n\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{1}{6}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{3 \u00d7 1}{4 \u00d7 6}\\)
\nDivide 3 in numerator and 6 in denominator by 3, which is a common factor
\n= \\(\\frac{1 \u00d7 1}{4 \u00d7 2}\\)
\n= \\(\\frac{1}{8}\\)
\nTherefore ,\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{1}{6}\\) = \\(\\frac{1}{8}\\)<\/p>\n

b. \\(\\frac{5}{7}\\) \u00d7 \\(\\frac{2}{3}\\) = ____
\nAnswer: \\(\\frac{10}{21}\\)
\n\\(\\frac{5}{7}\\) \u00d7 \\(\\frac{2}{3}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{5 \u00d7 2}{7 \u00d7 3}\\)
\n= \\(\\frac{10}{21}\\)
\nTherefore, \\(\\frac{5}{7}\\) \u00d7 \\(\\frac{2}{3}\\) = \\(\\frac{10}{21}\\)<\/p>\n

c. 5\\(\\frac{1}{2}\\) \u00d7 1\\(\\frac{1}{4}\\) = ____
\nAnswer:6\\(\\frac{7}{8}\\)
\n5\\(\\frac{1}{2}\\) \u00d7 1\\(\\frac{1}{4}\\)
\nConvert the above numbers into improper fractions to make calculations easy
\n=\\(\\frac{11}{2}\\) \u00d7 \\(\\frac{5}{4}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{11 \u00d7 5}{2 \u00d7 4}\\)
\n= \\(\\frac{55}{8}\\)
\n=\u00a0 6\\(\\frac{7}{8}\\)
\nTherefore, 5\\(\\frac{1}{2}\\) \u00d7 1\\(\\frac{1}{4}\\) =6\\(\\frac{7}{8}\\)<\/p>\n

Question 12.
\na. 5\\(\\frac{1}{4}\\) \u00f7 \\(\\frac{1}{6}\\) = ____
\nAnswer: 31\\(\\frac{1}{2}\\)
\n5\\(\\frac{1}{4}\\) \u00f7 \\(\\frac{1}{6}\\)
\nConvert the above numbers into improper fractions to make calculations easy
\n= \\(\\frac{21}{4}\\) \u00f7 \\(\\frac{1}{6}\\)
\nTo divide by a fraction, multiply by its reciprocal.
\nHere, the reciprocal of \\(\\frac{1}{6}\\) = \\(\\frac{6}{1}\\)
\n\\(\\frac{21}{4}\\) \u00f7 \\(\\frac{1}{6}\\) = \\(\\frac{21}{4}\\) \u00d7 \\(\\frac{6}{1}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{21 \u00d7 6}{4 \u00d7 1}\\)
\nDivide 6 in numerator and 4 in denominator by 2, which is a common factor
\n= \\(\\frac{21 \u00d7 3}{2 \u00d7 1}\\)
\n= \\(\\frac{63}{2}\\)
\n= 31\\(\\frac{1}{2}\\)
\nTherefore, 5\\(\\frac{1}{4}\\) \u00f7 \\(\\frac{1}{6}\\) = 31\\(\\frac{1}{2}\\)<\/p>\n

b. 6\\(\\frac{4}{7}\\) \u00f7 12 = ____
\nAnswer: \\(\\frac{23}{42}\\)
\n6\\(\\frac{4}{7}\\) \u00f7 12
\nConvert the above numbers into improper fractions to make calculations easy
\n= \\(\\frac{46}{7}\\) \u00f7 \\(\\frac{12}{1}\\)
\nTo divide by a fraction, multiply by its reciprocal.
\nHere, the reciprocal of \\(\\frac{12}{1}\\) = \\(\\frac{1}{12}\\)
\nSo, \\(\\frac{46}{7}\\) \u00f7 \\(\\frac{12}{1}\\) = \\(\\frac{46}{7}\\) \u00d7 \\(\\frac{1}{12}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{46 \u00d7 1}{7 \u00d7 12}\\)
\nDivide 46 in numerator and 12 in denominator by 2, which is a common factor
\n= \\(\\frac{23 \u00d7 1}{7 \u00d7 6}\\)
\n= \\(\\frac{23}{42}\\)
\nTherefore, 6\\(\\frac{4}{7}\\) \u00f7 12 = \\(\\frac{23}{42}\\)<\/p>\n

c. 1\\(\\frac{1}{2}\\) \u00f7 \\(\\frac{3}{5}\\) = ____
\nAnswer: 2\\(\\frac{1}{2}\\)
\n1\\(\\frac{1}{2}\\) \u00f7 \\(\\frac{3}{5}\\)
\nConvert the above numbers into improper fractions to make calculations easy
\n= \\(\\frac{3}{2}\\) \u00f7 \\(\\frac{3}{5}\\)
\nTo divide by a fraction, multiply by its reciprocal.
\nHere, the reciprocal of \\(\\frac{3}{5}\\) = \\(\\frac{5}{3}\\)
\nSo, \\(\\frac{3}{2}\\) \u00f7 \\(\\frac{3}{5}\\) = \\(\\frac{3}{2}\\)\u00a0 \u00d7\u00a0 \\(\\frac{5}{3}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{3 \u00d7 5}{2 \u00d7 3}\\)
\nDivide 3 in numerator and 3 in denominator by 3, which is a common factor
\n= \\(\\frac{1 \u00d7 5}{2 \u00d7 1}\\)
\n= \\(\\frac{5}{2}\\)
\n= 2\\(\\frac{1}{2}\\)
\nTherefore, 1\\(\\frac{1}{2}\\) \u00f7 \\(\\frac{3}{5}\\)= 2\\(\\frac{1}{2}\\)<\/p>\n

Question 13.
\na. 7 \u00d7 (-6) = ____
\nAnswer: -42
\n7 \u00d7 (-6) = -42
\nThe product of two positive integers is always positive.
\nThe product of two negative integers is always positive.
\nThe product of one positive and one negative integer is always negative.
\nHere -6 is a negative integer and 7 is a positive integer therefore the result of their product is a negative integer.<\/p>\n

b. 3 \u00d7 (-4) = ____
\nAnswer: -12
\n3 \u00d7 (-4) = -12
\nThe product of two positive integers is always positive.
\nThe product of two negative integers is always positive.
\nThe product of one positive and one negative integer is always negative.
\nHere -4 is a negative integer and 3 is a positive integer therefore the result of their product is a negative integer.<\/p>\n

c. -5 \u00d7 (-2) = ____
\nAnswer: 10
\n-5 \u00d7 (-2) = 10
\nThe product of two positive integers is always positive.
\nThe product of two negative integers is always positive.
\nThe product of one positive and one negative integer is always negative.
\nHere -2 and -5 both are negative integers hence their product is also a negative integer.<\/p>\n

Question 14.
\na. 12 \u00f7 (-4) = ____
\nAnswer: -3
\nlet 12 \u00f7 (-4) = x
\nAs division and multiplication are inverse operations, the above equation can be written as follows
\n12 = x \u00d7 (-4)
\nx = -3
\n12 \u00f7 (-4) = -3
\nTherefore Inverse operation: -3
\nThe quotient of two integers with the same sign is positive and the quotient of two integers with different signs is negative. Here -18 and 9 both are having different sign hence the result would be negative.<\/p>\n

b. -15 \u00f7 (-5) = ____
\nAnswer: 2
\nlet -15 \u00f7 (-5) = x
\nAs division and multiplication are inverse operations, the above equation can be written as follows
\n-15 = x \u00d7 (-5)
\nx = 2
\n-15 \u00f7 (-5) = 2
\nTherefore Inverse operation: 2
\nThe quotient of two integers with the same sign is positive and the quotient of two integers with different signs is negative. Here -40 and -4 both are having same sign hence the result would be positive.<\/p>\n

c. -21 \u00f7 7 = ____
\nAnswer: -3
\nlet -21 \u00f7 7 = x
\nAs division and multiplication are inverse operations, the above equation can be written as follows
\n-21 = x \u00d7 7
\nx = -3
\n-21 \u00f7 7 = -3
\nTherefore Inverse operation: -3
\nThe quotient of two integers with the same sign is positive and the quotient of two integers with different signs is negative. Here -18 and 9 both are having different sign hence the result would be negative.<\/p>\n

Solve each problem.<\/strong><\/p>\n

Question 15.
\nA bucket that holds 5\\(\\frac{1}{4}\\) if gallons of water is being used to fill a tub that can hold 34\\(\\frac{1}{8}\\) gallons. How many buckets will be needed to fill the tub?<\/p>\n

\"How
\nbuckets are needed to fill the tub.
\nAnswer: 6\\(\\frac{1}{2}\\)
\nA bucket that holds 5\\(\\frac{1}{4}\\) if gallons of water is being used to fill a tub that can hold 34\\(\\frac{1}{8}\\) gallons.
\nnumber of buckets needed to fill the tub = 34\\(\\frac{1}{8}\\) \u00f7 5\\(\\frac{1}{4}\\)
\nConvert the above numbers into improper fractions to make the calculations easy.
\n34\\(\\frac{1}{8}\\) = \\(\\frac{273}{8}\\)
\n5\\(\\frac{1}{4}\\) = \\(\\frac{21}{4}\\)
\nSo, 34\\(\\frac{1}{8}\\) \u00f7 5\\(\\frac{1}{4}\\) = \\(\\frac{273}{8}\\) \u00f7 \\(\\frac{21}{4}\\)
\nTo divide by a fraction, multiply by its reciprocal.
\nHere, the reciprocal of \\(\\frac{21}{4}\\) = \\(\\frac{4}{21}\\)
\nHence, \\(\\frac{273}{8}\\) \u00d7 \\(\\frac{4}{21}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{273 \u00d7 4}{8 \u00d7 21}\\)
\nDivide 4 in numerator and 8 in denominator with 4, which is a common factor
\n= \\(\\frac{273 \u00d7 1}{2 \u00d7 21}\\)
\nDivide 273 in numerator and 21 in denominator with 21, which is a common factor
\n= \\(\\frac{13 \u00d7 1}{2 \u00d7 1}\\)
\n= \\(\\frac{13}{2}\\)
\n= 6\\(\\frac{1}{2}\\)
\nTherefore, 6\\(\\frac{1}{2}\\) buckets are needed to fill the tub.<\/p>\n

Question 16.
\nA black piece of pipe is 8\\(\\frac{1}{3}\\) centimeters long. A silver piece of pipe is 2\\(\\frac{3}{5}\\) times longer. How long is the silver piece of pipe?
\nThe silver piece is ______ centimeters long.
\nAnswer: 21\\(\\frac{2}{3}\\)
\nA black piece of pipe is 8\\(\\frac{1}{3}\\) centimeters long. A silver piece of pipe is 2\\(\\frac{3}{5}\\) times longer.
\nThe number of centimeters the silver piece is 8\\(\\frac{1}{3}\\) \u00d7 2\\(\\frac{3}{5}\\)
\nConvert the above numbers into improper fractions to make the calculations easy.
\n8\\(\\frac{1}{3}\\)= \\(\\frac{25}{3}\\)
\n2\\(\\frac{3}{5}\\) = \\(\\frac{13}{5}\\)
\nSo, 8\\(\\frac{1}{3}\\) \u00d7 2\\(\\frac{3}{5}\\) = \\(\\frac{25}{3}\\) \u00d7 \\(\\frac{13}{5}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{25 \u00d7 13}{3 \u00d7 5}\\)
\nDivide 25 in numerator and 5 in denominator with 5, which is a common factor
\n= \\(\\frac{5 \u00d7 13}{3 \u00d7 1}\\)
\n= \\(\\frac{65}{3}\\)
\n= 21\\(\\frac{2}{3}\\)
\nTherefore, The silver piece is21\\(\\frac{2}{3}\\) centimeters long.<\/p>\n

Question 17.
\nOne section of wood is 3\\(\\frac{5}{8}\\) meters long. Another section is twice that long. When the two pieces are put together, how long is the piece of wood that is created?
\nThe piece of wood is _____ meters long.
\nAnswer: 10\\(\\frac{7}{8}\\)
\nOne section of wood is 3\\(\\frac{5}{8}\\) meters long.
\nConvert the above number into improper fraction. Then, 3\\(\\frac{5}{8}\\)\u00a0 = \\(\\frac{29}{8}\\)
\nAnother section is twice that long i.e. 2 \u00d7 3\\(\\frac{5}{8}\\) = 2 \u00d7 \\(\\frac{29}{8}\\)
\n= \\(\\frac{2}{1}\\) \u00d7 \\(\\frac{29}{8}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{2 \u00d7 29}{1 \u00d7 8}\\)
\n= \\(\\frac{58}{8}\\)
\nWhen the two pieces are put together, the piece of wood that is created = \\(\\frac{29}{8}\\) + \\(\\frac{58}{8}\\)
\n= \\(\\frac{29+58}{8}\\)
\n= \\(\\frac{87}{8}\\)
\n= 10\\(\\frac{7}{8}\\)
\nTherefore, The piece of wood is 10\\(\\frac{7}{8}\\) meters long.<\/p>\n

Question 18.
\nDanielle wants to fill a box with dirt to start a garden. If the box is 2\\(\\frac{1}{5}\\) feet long, by 1\\(\\frac{1}{3}\\) feet wide, and 1\\(\\frac{1}{2}\\) feet deep, how much dirt does Danielle need to fill up the box for her garden?<\/p>\n

\"fill
\nDanielle needs ____ cubic feet of dirt.
\nAnswer: 4\\(\\frac{4}{10}\\)
\nIf the box is 2\\(\\frac{1}{5}\\) feet long, by 1\\(\\frac{1}{3}\\) feet wide, and 1\\(\\frac{1}{2}\\) feet deep
\nThe amount of dirt needed to fill the box = 2\\(\\frac{1}{5}\\) \u00d7 1\\(\\frac{1}{3}\\) \u00d7 1\\(\\frac{1}{2}\\)
\nConvert the above number into improper fraction to make calculations easy.
\n= \\(\\frac{11}{5}\\) \u00d7 \\(\\frac{4}{3}\\) \u00d7 \\(\\frac{3}{2}\\)
\nReduce the above fractions into simplest form if possible.
\nThen, multiply the numerators and denominators separately.
\n= \\(\\frac{11 \u00d7 4 \u00d7 3}{5 \u00d7 3 \u00d7 2}\\)
\nDivide 3 in numerator and 3 in denominator with 3, which is a common factor
\n= \\(\\frac{11 \u00d7 4 \u00d7 1}{5 \u00d7 1 \u00d7 2}\\)
\n= \\(\\frac{44}{10}\\)
\n= 4\\(\\frac{4}{10}\\)
\nTherefore, Danielle needs 4\\(\\frac{4}{10}\\) cubic feet of dirt.<\/p>\n","protected":false},"excerpt":{"rendered":"

This handy Spectrum Math Grade 7 Answer Key\u00a0Chapter 2 Posttest\u00a0provides detailed answers for the workbook questions Spectrum Math Grade 7 Chapter 2 Posttest Answers Key Check What You Learned Multiplying and Dividing Rational Numbers Rewrite each expression using the distributive property. Question 1. a. 7 \u00d7 (10 + a) = _____________ Answer: (7 \u00d7 10) … Read more<\/a><\/p>\n","protected":false},"author":14,"featured_media":171241,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[641],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/11\/Spectrum-Math-Grade-7-Chapter-2-Posttest-Answer-Key.png","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/147184"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/14"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=147184"}],"version-history":[{"count":10,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/147184\/revisions"}],"predecessor-version":[{"id":171245,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/147184\/revisions\/171245"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media\/171241"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=147184"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=147184"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=147184"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}