{"id":148852,"date":"2023-11-28T18:11:31","date_gmt":"2023-11-28T12:41:31","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=148852"},"modified":"2023-11-29T17:35:55","modified_gmt":"2023-11-29T12:05:55","slug":"spectrum-math-grade-6-chapter-3-lesson-2-answer-key","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/spectrum-math-grade-6-chapter-3-lesson-2-answer-key\/","title":{"rendered":"Spectrum Math Grade 6 Chapter 3 Lesson 2 Answer Key Solving Ratios"},"content":{"rendered":"

Go through the Spectrum Math Grade 6 Answer Key<\/a> Chapter 3 Lesson 3.2 Solving Ratios<\/b>\u00a0and get the proper assistance needed during your homework.<\/p>\n

Spectrum Math Grade 6 Chapter 3 Lesson 3.2 Solving Ratios Answers Key<\/h2>\n

A proportion can be used in problem solving.
\nThe ratio of apples to oranges is 4 to 5. There are 20 oranges in the basket.
\nHow many apples are there?
\n\\(\\frac{4}{5}\\) = \\(\\frac{n}{20}\\) Set up a proportion, using n for the missing number.
\n4 \u00d7 20 = 5 \u00d7 n Cross-multiply.
\n\\(\\frac{80}{5}\\) = n Solve for n.
\n16 = n There are 16 apples.<\/p>\n

Solve.
\n<\/strong>Question 1.
\na. \\(\\frac{1}{3}\\) = \\(\\frac{n}{24}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{1}{3}\\) = \\(\\frac{n}{24}\\) is 8.<\/p>\n

Explanation:
\n\\(\\frac{1}{3}\\) = \\(\\frac{n}{24}\\)
\n=> 1 \u00d7 24 = n \u00d7 3
\n=> 24 = 3n
\n=> 24 \u00f7 3 = n
\n=> 8 = n.<\/p>\n

b. \\(\\frac{4}{9}\\) = \\(\\frac{n}{36}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{4}{9}\\) = \\(\\frac{n}{36}\\) is 16.<\/p>\n

Explanation:
\n\\(\\frac{4}{9}\\) = \\(\\frac{n}{36}\\)
\n=> 4 \u00d7 36 = n \u00d7 9
\n=>144 = 9n
\n=> 144 \u00f7 9 = n
\n=> 16 = n.<\/p>\n

c. \\(\\frac{5}{45}\\) = \\(\\frac{n}{9}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{5}{45}\\) = \\(\\frac{n}{9}\\) is 1.<\/p>\n

Explanation:
\n\\(\\frac{5}{45}\\) = \\(\\frac{n}{9}\\)
\n=> 5 \u00d7 9 = n \u00d7 45
\n=> 45 = 45n
\n=> 45 \u00f7 45 = n
\n=> 1 = n.<\/p>\n

Question 2.
\na. \\(\\frac{3}{5}\\) = \\(\\frac{n}{15}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{3}{5}\\) = \\(\\frac{n}{15}\\) is 9.<\/p>\n

Explanation:
\n\\(\\frac{3}{5}\\) = \\(\\frac{n}{15}\\)
\n=> 3 \u00d7 15 = n \u00d7 5
\n=> 45 = 5n
\n=> 45 \u00f7 5 = n
\n=> 9 = n.<\/p>\n

b. \\(\\frac{10}{70}\\) = \\(\\frac{n}{7}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{10}{70}\\) = \\(\\frac{n}{7}\\) is 1.<\/p>\n

Explanation:
\n\\(\\frac{10}{70}\\) = \\(\\frac{n}{7}\\)
\n=> 10 \u00d7 7 = n \u00d7 70
\n=> 70 = 70n
\n=> 70 \u00f7 70 = n
\n=> 1 = n.<\/p>\n

c. \\(\\frac{25}{40}\\) = \\(\\frac{n}{16}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{25}{40}\\) = \\(\\frac{n}{16}\\) is 10.<\/p>\n

Explanation:
\n\\(\\frac{25}{40}\\) = \\(\\frac{n}{16}\\)
\n=> 25 \u00d7 16 = n \u00d7 40
\n=> 400 = 40n
\n=> 400 \u00f7 40 = n
\n=> 10 = n.<\/p>\n

Question 3.
\na. \\(\\frac{7}{12}\\) = \\(\\frac{n}{36}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{7}{12}\\) = \\(\\frac{n}{36}\\) is 21.<\/p>\n

Explanation:
\n\\(\\frac{7}{12}\\) = \\(\\frac{n}{36}\\)
\n=> 7 \u00d7 36 = n \u00d7 12
\n=> 252 = 12n
\n=> 252 \u00f7 12 = n
\n=> 21 =n.<\/p>\n

b. \\(\\frac{13}{26}\\) = \\(\\frac{n}{4}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{13}{26}\\) = \\(\\frac{n}{4}\\) is 2.<\/p>\n

Explanation:
\n\\(\\frac{13}{26}\\) = \\(\\frac{n}{4}\\)
\n=> 13 \u00d7 4 = n \u00d7 26
\n=> 52 = 26n
\n=> 52 \u00f7 26 = n
\n=> 2 = n.<\/p>\n

c. \\(\\frac{7}{1}\\) = \\(\\frac{n}{3}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{7}{1}\\) = \\(\\frac{n}{3}\\) is 21.<\/p>\n

Explanation:
\n\\(\\frac{7}{1}\\) = \\(\\frac{n}{3}\\)
\n=> 7 \u00d7 3 = n \u00d7 1
\n=> 21 = 1n
\n=> 21 \u00f7 1 = n
\n=> 21 = n.<\/p>\n

Question 4.
\na. \\(\\frac{8}{5}\\) = \\(\\frac{n}{40}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{8}{5}\\) = \\(\\frac{n}{40}\\) is 64.<\/p>\n

Explanation:
\n\\(\\frac{8}{5}\\) = \\(\\frac{n}{40}\\)
\n=> 8 \u00d7 40 = n \u00d7 5
\n=> 320 = 5n
\n=> 320 \u00f7 5 = n
\n=> 64 = n.<\/p>\n

b. \\(\\frac{2}{6}\\) = \\(\\frac{n}{33}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{2}{6}\\) = \\(\\frac{n}{33}\\) is 11.<\/p>\n

Explanation:
\n\\(\\frac{2}{6}\\) = \\(\\frac{n}{33}\\)
\n=> 2 \u00d7 33 = n \u00d7 6
\n=> 66 = 6n
\n=> 66 \u00f7 6 = n
\n=> 11 = n.<\/p>\n

c. \\(\\frac{5}{13}\\) = \\(\\frac{n}{39}\\) ___________
\nAnswer:
\nThe value of n in latex]\\frac{5}{13}[\/latex] = \\(\\frac{n}{39}\\) is 15.<\/p>\n

Explanation:
\nlatex]\\frac{5}{13}[\/latex] = \\(\\frac{n}{39}\\)
\n=> 5 \u00d7 39 = n \u00d7 13
\n=> 195 = 13n
\n=> 195 \u00f7 13 = n
\n=> 15 = n.<\/p>\n

Question 5.
\na. \\(\\frac{5}{6}\\) = \\(\\frac{n}{18}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{5}{6}\\) = \\(\\frac{n}{18}\\) is 15.<\/p>\n

Explanation:
\n\\(\\frac{5}{6}\\) = \\(\\frac{n}{18}\\)
\n=> 5 \u00d7 18 = n \u00d7 6
\n=> 90 = 6n
\n=> 90 \u00f7 6 = n
\n=> 15 = n.<\/p>\n

b. \\(\\frac{9}{8}\\) = \\(\\frac{n}{32}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{9}{8}\\) = \\(\\frac{n}{32}\\) is 36.<\/p>\n

Explanation:
\n\\(\\frac{9}{8}\\) = \\(\\frac{n}{32}\\)
\n=> 9 \u00d7 32 = n \u00d7 8
\n=> 288 = 8n
\n=> 288 \u00f7 8 = n
\n=> 36 = n.<\/p>\n

c. \\(\\frac{2}{3}\\) = \\(\\frac{n}{15}\\) ___________
\nAnswer:
\nThe value of n in \\(\\frac{2}{3}\\) = \\(\\frac{n}{15}\\) is 10.<\/p>\n

Explanation:
\n\\(\\frac{2}{3}\\) = \\(\\frac{n}{15}\\)
\n=> 2 \u00d7 15 = n \u00d7 3
\n=> 30 = 3n
\n=> 30 \u00f7 3 = n
\n=> 10 = n.<\/p>\n

A proportion can be used in problem-solving.
\nThe ratio of apples to oranges is 4 to 5. There are 20 oranges in the basket. How many apples are there?
\n\\(\\frac{4}{5}\\) = \\(\\frac{4}{20}\\) ___________ Set up a proportion, using n for the missing number.
\n4 \u00d7 20 = 5 \u00d7 n Cross-multiply
\n\\(\\frac{80}{5}\\) =n Solve for n
\n16 = n There are 16 apples.<\/p>\n

Solve.
\n<\/strong>Question 1.
\na. \\(\\frac{1}{3}\\) = \\(\\frac{n}{24}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{1}{3}\\) = \\(\\frac{n}{24}\\) is 8.<\/p>\n

Explanation:
\n\\(\\frac{1}{3}\\) = \\(\\frac{n}{24}\\)
\n=> 1 \u00d7 24 = n \u00d7 3
\n=> 24 = 3n
\n=> 24 \u00f7 3 = n
\n=> 8 = n.<\/p>\n

b. \\(\\frac{4}{9}\\) = \\(\\frac{n}{36}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{4}{9}\\) = \\(\\frac{n}{36}\\) is 16.<\/p>\n

Explanation:
\n\\(\\frac{4}{9}\\) = \\(\\frac{n}{36}\\)
\n=> 4 \u00d7 36 = n \u00d7 9
\n=> 144 = 9n
\n=> 144 \u00f7 9 = n
\n=> 16 = n.<\/p>\n

c. \\(\\frac{5}{45}\\) = \\(\\frac{n}{9}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{5}{45}\\) = \\(\\frac{n}{9}\\) is 1.<\/p>\n

Explanation:
\n\\(\\frac{5}{45}\\) = \\(\\frac{n}{9}\\)
\n= 4 \u00d7 9 = n \u00d7 45
\n=> 45 = 45n
\n=> 45 \u00f7 45 = n
\n=> 1 = n.<\/p>\n

Question 2.
\na. \\(\\frac{3}{5}\\) = \\(\\frac{n}{15}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{3}{5}\\) = \\(\\frac{n}{15}\\) is 9.<\/p>\n

Explanation:
\n\\(\\frac{3}{5}\\) = \\(\\frac{n}{15}\\)
\n=> 3 \u00d7 15 = n \u00d7 5
\n=> 45 = 5n
\n=> 45 \u00f7 5 = n
\n=> 9 = n.<\/p>\n

b. \\(\\frac{10}{70}\\) = \\(\\frac{n}{7}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{10}{70}\\) = \\(\\frac{n}{7}\\) is 1.<\/p>\n

Explanation:
\n\\(\\frac{10}{70}\\) = \\(\\frac{n}{7}\\)
\n=> 10 \u00d7 7 = n \u00d7 70
\n=> 70 = 70n
\n=> 70 \u00f7 70 = n
\n=> 1 = n.<\/p>\n

c. \\(\\frac{25}{40}\\) = \\(\\frac{n}{16}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{25}{40}\\) = \\(\\frac{n}{16}\\) is 10.<\/p>\n

Explanation:
\n\\(\\frac{25}{40}\\) = \\(\\frac{n}{16}\\)
\n=> 25 \u00d7 16 = n \u00d7 40
\n=> 400 = 40n
\n=> 400 \u00f7 40 = n
\n=> 10 = n.<\/p>\n

Question 3.
\na. \\(\\frac{7}{12}\\) = \\(\\frac{n}{36}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{7}{12}\\) = \\(\\frac{n}{36}\\) is 21.<\/p>\n

Explanation:
\n\\(\\frac{7}{12}\\) = \\(\\frac{n}{36}\\)
\n=> 7 \u00d7 36 = n \u00d7 12
\n=> 252 = 12n
\n=> 252 \u00f7 12 = n
\n=> 21 = n.<\/p>\n

b. \\(\\frac{13}{26}\\) = \\(\\frac{n}{4}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{13}{26}\\) = \\(\\frac{n}{4}\\) is 2.<\/p>\n

Explanation:
\n\\(\\frac{13}{26}\\) = \\(\\frac{n}{4}\\)
\n=> 13 \u00d7 4 = n \u00d7 26
\n=> 52 = 26n
\n=> 52 \u00f7 26 = n
\n=> 2 = n.<\/p>\n

c. \\(\\frac{7}{1}\\) = \\(\\frac{n}{3}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{7}{1}\\) = \\(\\frac{n}{3}\\) is 21.<\/p>\n

Explanation:
\n\\(\\frac{7}{1}\\) = \\(\\frac{n}{3}\\)
\n= 7 \u00d7 3 = n \u00d7 1
\n=> 21 = 1n
\n=> 21 \u00f7 1 = n
\n=> 21 = n.<\/p>\n

Question 4.
\na. \\(\\frac{8}{5}\\) = \\(\\frac{n}{40}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{8}{5}\\) = \\(\\frac{n}{40}\\) is 64.<\/p>\n

Explanation:
\n\\(\\frac{8}{5}\\) = \\(\\frac{n}{40}\\)
\n=> 8 \u00d7 40 = n \u00d7 5
\n=> 320 = 5n
\n=> 320 \u00f7 5 = n
\n=> 64 = n.<\/p>\n

b. \\(\\frac{2}{6}\\) = \\(\\frac{n}{33}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{2}{6}\\) = \\(\\frac{n}{33}\\) is 11.<\/p>\n

Explanation:
\n\\(\\frac{2}{6}\\) = \\(\\frac{n}{33}\\)
\n=> 2 \u00d7 33 = n \u00d7 6
\n=> 66 = 6n
\n=> 66 \u00f7 6 = n
\n=> 11 = n.<\/p>\n

c. \\(\\frac{5}{13}\\) = \\(\\frac{n}{39}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{5}{13}\\) = \\(\\frac{n}{39}\\) is 15.<\/p>\n

Explanation:
\n\\(\\frac{5}{13}\\) = \\(\\frac{n}{39}\\)
\n=> 5 \u00d7 39 = n \u00d7 13
\n=> 195 = 13n
\n=> 195 \u00f7 13 = n
\n=> 15 = n.<\/p>\n

Question 5.
\na. \\(\\frac{5}{6}\\) = \\(\\frac{n}{18}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{5}{6}\\) = \\(\\frac{n}{18}\\) is 15.<\/p>\n

Explanation:
\n\\(\\frac{5}{6}\\) = \\(\\frac{n}{18}\\)
\n=> 5 \u00d7 18 = n \u00d7 6
\n=> 90 = 6n
\n=> 90 \u00f7 6 = n
\n=> 15 = n.<\/p>\n

b. \\(\\frac{9}{8}\\) = \\(\\frac{n}{32}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{9}{8}\\) = \\(\\frac{n}{32}\\) is 36.<\/p>\n

Explanation:
\n\\(\\frac{9}{8}\\) = \\(\\frac{n}{32}\\)
\n=> 9 \u00d7 32 = n \u00d7 8
\n=> 288 = 8n
\n=> 288 \u00f7 8 = n
\n=> 36 = n.<\/p>\n

c. \\(\\frac{2}{3}\\) = \\(\\frac{n}{15}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{2}{3}\\) = \\(\\frac{n}{15}\\) is 10.<\/p>\n

Explanation:
\n\\(\\frac{2}{3}\\) = \\(\\frac{n}{15}\\)
\n=> 2 \u00d7 15 = n \u00d7 3
\n=> 30 = 3n
\n=> 30 \u00f7 3 = n
\n=> 10 = n.<\/p>\n

The missing number can appear any place in a proportion. Solve the same way.
\n\\(\\frac{2}{3}\\) = \\(\\frac{6}{n}\\)
\n3 \u00d7 6 = 2 \u00d7 n
\n\\(\\frac{18}{2}\\) = n
\n9 = n<\/p>\n

\\(\\frac{3}{5}\\) = \\(\\frac{n}{10}\\)
\n3 \u00d7 10 = 5 \u00d7 n
\n\\(\\frac{30}{5}\\) = n
\n6 = n<\/p>\n

\\(\\frac{3}{n}\\) = \\(\\frac{6}{8}\\)
\n3 \u00d7 8 = 6 \u00d7 n
\n\\(\\frac{24}{6}\\) = n
\n4 = n<\/p>\n

\\(\\frac{n}{4}\\) = \\(\\frac{3}{6}\\)
\n4 \u00d7 3 = 6 \u00d7 n
\n\\(\\frac{12}{6}\\) = n
\n2 = n<\/p>\n

Solve.
\n<\/strong>Question 1.
\na. \\(\\frac{n}{3}\\) = \\(\\frac{3}{9}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{n}{3}\\) = \\(\\frac{3}{9}\\) is 1.<\/p>\n

Explanation:
\n\\(\\frac{n}{3}\\) = \\(\\frac{3}{9}\\)
\n=> n \u00d7 9 = 3 \u00d7 3
\n=> 9n = 9
\n=> n = 9 \u00f7 9
\n=> n = 1.<\/p>\n

b. \\(\\frac{5}{3}\\) = \\(\\frac{15}{n}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{5}{3}\\) = \\(\\frac{15}{n}\\) is 9.<\/p>\n

Explanation:
\n\\(\\frac{5}{3}\\) = \\(\\frac{15}{n}\\)
\n=> 5 \u00d7 n = 15 \u00d7 3
\n=> 5n = 45
\n=> n = 45 \u00f7 5
\n=> n = 9.<\/p>\n

c. \\(\\frac{2}{n}\\) = \\(\\frac{1}{4}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{2}{n}\\) = \\(\\frac{1}{4}\\) is 8.<\/p>\n

Explanation:
\n\\(\\frac{2}{n}\\) = \\(\\frac{1}{4}\\)
\n= 2 \u00d7 4 = 1 \u00d7 n
\n=> 8 = 1n
\n=> 8 \u00f7 1 = n
\n=> 8 = n.<\/p>\n

Question 2.
\na. \\(\\frac{15}{30}\\) = \\(\\frac{2}{n}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{15}{30}\\) = \\(\\frac{2}{n}\\) is 4.<\/p>\n

Explanation:
\n\\(\\frac{15}{30}\\) = \\(\\frac{2}{n}\\)
\n=> 15 \u00d7 n = 2 \u00d7 30
\n=> 15n = 60
\n=> n = 60 \u00f7 15
\n=> n = 4.<\/p>\n

b. \\(\\frac{4}{6}\\) = \\(\\frac{n}{24}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{4}{6}\\) = \\(\\frac{n}{24}\\) is 16.<\/p>\n

Explanation:
\n\\(\\frac{4}{6}\\) = \\(\\frac{n}{24}\\)
\n=> 4 \u00d7 24 = n \u00d7 6
\n=> 96 = 6n
\n=> 96 \u00f7 6 = n
\n=> 16 = n.<\/p>\n

c. \\(\\frac{n}{7}\\) = \\(\\frac{15}{21}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{n}{7}\\) = \\(\\frac{15}{21}\\) is 5.<\/p>\n

Explanation:
\n\\(\\frac{n}{7}\\) = \\(\\frac{15}{21}\\)
\n=> n \u00d7 21 = 15 \u00d7 7
\n=> 21n = 105
\n=> n = 105 \u00f7 21
\n=> n = 5.<\/p>\n

Question 3.
\na. \\(\\frac{6}{n}\\) = \\(\\frac{15}{20}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{6}{n}\\) = \\(\\frac{15}{20}\\) is 8.<\/p>\n

Explanation:
\n\\(\\frac{6}{n}\\) = \\(\\frac{15}{20}\\)
\n=> 6 \u00d7 20 = 15 \u00d7 n
\n=> 120 = 15n
\n=> 120 \u00f7 15 = n
\n=> 8 = n.<\/p>\n

b. \\(\\frac{n}{12}\\) = \\(\\frac{9}{18}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{n}{12}\\) = \\(\\frac{9}{18}\\) is 6.<\/p>\n

Explanation:
\n\\(\\frac{n}{12}\\) = \\(\\frac{9}{18}\\)
\n=> n \u00d7 18 = 9 \u00d7 12
\n=> 18n = 108
\n=> n = 108 \u00f7 18
\n=> n = 6.<\/p>\n

c. \\(\\frac{9}{2}\\) = \\(\\frac{27}{n}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{9}{2}\\) = \\(\\frac{27}{n}\\) is 6.<\/p>\n

Explanation:
\n\\(\\frac{9}{2}\\) = \\(\\frac{27}{n}\\)
\n=> 9 \u00d7 n = 27 \u00d7 2
\n=> 9n = 54
\n=> n = 54 \u00f7 9
\n=> n = 6.<\/p>\n

Question 4.
\na. \\(\\frac{7}{9}\\) = \\(\\frac{n}{63}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{7}{9}\\) = \\(\\frac{n}{63}\\) is 49.<\/p>\n

Explanation:
\n\\(\\frac{7}{9}\\) = \\(\\frac{n}{63}\\)
\n=> 7 \u00d7 63 = n \u00d7 9
\n=> 441 = 9n
\n=> 441 \u00f7 9 = n
\n=> 49 = n.<\/p>\n

b. \\(\\frac{15}{n}\\) = \\(\\frac{12}{4}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{15}{n}\\) = \\(\\frac{12}{4}\\) is 5.<\/p>\n

Explanation:
\n\\(\\frac{15}{n}\\) = \\(\\frac{12}{4}\\)
\n=> 15 \u00d7 4 = 12 \u00d7 n
\n=> 60 = 12n
\n=> 60 \u00f7 12 = n
\n=> 5 = n.<\/p>\n

c. \\(\\frac{40}{100}\\) = \\(\\frac{n}{25}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{40}{100}\\) = \\(\\frac{n}{25}\\) is 10.<\/p>\n

Explanation:
\n\\(\\frac{40}{100}\\) = \\(\\frac{n}{25}\\)
\n=> 40 \u00d7 25 = n \u00d7 100
\n=> 1000 = 100n
\n=> 1000 \u00f7 100 = n
\n=> 10 = n.<\/p>\n

Question 5.
\na. \\(\\frac{35}{n}\\) = \\(\\frac{4}{8}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{35}{n}\\) = \\(\\frac{4}{8}\\) is 70.<\/p>\n

Explanation:
\n\\(\\frac{35}{n}\\) = \\(\\frac{4}{8}\\)
\n=> 35 \u00d7 8 = 4 \u00d7 n
\n=> 280 = 4n
\n=> 280 \u00f7 4 = n
\n=> 70 = n.<\/p>\n

b. \\(\\frac{16}{4}\\) = \\(\\frac{36}{n}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{16}{4}\\) = \\(\\frac{36}{n}\\) is 9.<\/p>\n

Explanation:
\n\\(\\frac{16}{4}\\) = \\(\\frac{36}{n}\\)
\n=> 16 \u00d7 n = 36 \u00d7 4
\n=>16n = 144
\n=> n = 144 \u00f7 16
\n=> n = 9.<\/p>\n

c. \\(\\frac{n}{12}\\) = \\(\\frac{25}{30}\\) _________
\nAnswer:
\nThe value of n in \\(\\frac{n}{12}\\) = \\(\\frac{25}{30}\\) is 10.<\/p>\n

Explanation:
\n\\(\\frac{n}{12}\\) = \\(\\frac{25}{30}\\)
\n=> n \u00d7 30 = 25 \u00d7 12
\n=> 30n = 300
\n=> n = 300 \u00f7 30
\n=> n = 10.<\/p>\n","protected":false},"excerpt":{"rendered":"

Go through the Spectrum Math Grade 6 Answer Key Chapter 3 Lesson 3.2 Solving Ratios\u00a0and get the proper assistance needed during your homework. Spectrum Math Grade 6 Chapter 3 Lesson 3.2 Solving Ratios Answers Key A proportion can be used in problem solving. The ratio of apples to oranges is 4 to 5. There are … Read more<\/a><\/p>\n","protected":false},"author":14,"featured_media":171339,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[641],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/11\/Spectrum-Math-Grade-6-Chapter-3-Lesson-2-Answer-Key-Solving-Ratios.png","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/148852"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/14"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=148852"}],"version-history":[{"count":7,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/148852\/revisions"}],"predecessor-version":[{"id":171340,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/148852\/revisions\/171340"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media\/171339"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=148852"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=148852"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=148852"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}