{"id":49825,"date":"2023-10-25T11:18:21","date_gmt":"2023-10-25T05:48:21","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=49825"},"modified":"2023-11-10T10:50:36","modified_gmt":"2023-11-10T05:20:36","slug":"square-root-of-number-in-the-fraction-form","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/square-root-of-number-in-the-fraction-form\/","title":{"rendered":"Square Root of Number in the Fraction Form | Simplifying Square Roots of Fractions Examples"},"content":{"rendered":"

Square Root of Number in the Fraction Form is explained clearly in this article. Finding natural numbers is easy but when it comes to fractions it is a little bit difficult to find the Square Root<\/a> of Numbers. So, to make the process easy, we have given the step by step procedure on How do you find the Square Root of a Fraction. Check all the sample problems on finding the square root of numbers in fraction form and get to know the concept involved.<\/p>\n

How to Find the Square Root of a Fraction?<\/h2>\n

If m and n are squares of some numbers then, \u221a(m \u00f7 n) = \u221am \u00f7 \u221an. If you find any problem in mixed form, then convert it into fractions.<\/p>\n

1. Find the square root of \u221a(144 \u00f7 81)?<\/strong><\/p>\n

Solution:
\nGiven the number is \u221a(144 \u00f7 81).
\nFirstly, separate the numerator and denominator.
\n\u221a(144) \u00f7 \u221a(81)
\nFind the separate Square Roots of the numerator and denominator.
\nFind the prime factors of \u221a(144)
\n\u221a(144) = 12 \u00d7 12
\nGrouping the factors into the pairs of equal factors.
\n(12 \u00d7 12)
\nTake one number from each group and multiply them to find the number whose square is 144.
\n12
\nThe square root of 144 is 12.
\nFind the prime factors of \u221a(81)
\n\u221a(81) = 9 \u00d7 9
\nGrouping the factors into the pairs of equal factors.
\n(9 \u00d7 9)
\nTake one number from each group and multiply them to find the number whose square is 81.
\n9.
\nThe square root of 81 is 9.
\nThe final answer is 12 \u00f7 9 = 4\/3<\/p>\n

Therefore, the square root of \u221a(144 \u00f7 81) = 4\/3.<\/p>\n

2. Evaluate \u221a(256 \u00f7 64)?<\/strong><\/p>\n

Solution:
\nGiven the number is \u221a(256 \u00f7 64).
\nFirstly, separate the numerator and denominator.
\n\u221a(256) \u00f7 \u221a(64)
\nFind the separate Square Roots of the numerator and denominator.
\nFind the prime factors of \u221a(256)
\n\u221a(256) = 16 \u00d7 16
\nGrouping the factors into the pairs of equal factors.
\n(16 \u00d7 16)
\nTake one number from each group and multiply them to find the number whose square is 256.
\n16
\nThe square root of 256 is 16.
\nFind the prime factors of \u221a(64)
\n\u221a(64) = 8 \u00d7 8
\nGrouping the factors into the pairs of equal factors.
\n(8 \u00d7 8)
\nTake one number from each group and multiply them to find the number whose square is 64.
\n8.
\nThe square root of 64 is 8.
\nThe final answer is 256 \u00f7 64 = 16\/8<\/p>\n

Therefore, the square root of \u221a(256 \u00f7 64) = 16\/8.<\/p>\n

3. Evaluate \u221a(49 \u00f7 121)?<\/strong><\/p>\n

Solution:
\nGiven the number is \u221a(49 \u00f7 121).
\nFirstly, separate the numerator and denominator.
\n\u221a(49) \u00f7 \u221a(121)
\nFind the separate Square Roots of the numerator and denominator.
\nFind the prime factors of \u221a(49)
\n\u221a(49) = 7 \u00d7 7
\nGrouping the factors into the pairs of equal factors.
\n(7 \u00d7 7)
\nTake one number from each group and multiply them to find the number whose square is 49.
\n7
\nThe square root of 49 is 7.
\nFind the prime factors of \u221a(121)
\n\u221a(121) = 11 \u00d7 11
\nGrouping the factors into the pairs of equal factors.
\n(11 \u00d7 11)
\nTake one number from each group and multiply them to find the number whose square is 121.
\n11.
\nThe square root of 121 is 11.
\nThe final answer is 49 \u00f7 121 = 7\/11<\/p>\n

Therefore, the square root of \u221a(49 \u00f7 121) = 7\/11.<\/p>\n

4. Evaluate \u221a(25 \u00f7 169)?<\/strong><\/p>\n

Solution:
\nGiven the number is \u221a(25 \u00f7 169).
\nFirstly, separate the numerator and denominator.
\n\u221a(25) \u00f7 \u221a(169)
\nFind the separate Square Roots of the numerator and denominator.
\nFind the prime factors of \u221a(25)
\n\u221a(25) = 5 \u00d7 5
\nGrouping the factors into the pairs of equal factors.
\n(5 \u00d7 5)
\nTake one number from each group and multiply them to find the number whose square is 25.
\n5
\nThe square root of 25 is 5.
\nFind the prime factors of \u221a(169)
\n\u221a(169) = 13 \u00d7 13
\nGrouping the factors into the pairs of equal factors.
\n(13 \u00d7 13)
\nTake one number from each group and multiply them to find the number whose square is 169.
\n13.
\nThe square root of 169 is 13.
\nThe final answer is 25 \u00f7 169 = 5\/13<\/p>\n

Therefore, the square root of \u221a(25 \u00f7 169) = 5\/13.<\/p>\n

5. Find the value of \u221a(196 \u00f7 9)?<\/strong><\/p>\n

Solution:
\nGiven the number is \u221a(196 \u00f7 9).
\nFirstly, separate the numerator and denominator.
\n\u221a(196) \u00f7 \u221a(9)
\nFind the separate Square Roots of the numerator and denominator.
\nFind the prime factors of \u221a(196)
\n\u221a(196) = 13 \u00d7 13
\nGrouping the factors into the pairs of equal factors.
\n(13 \u00d7 13)
\nTake one number from each group and multiply them to find the number whose square is 196.
\n13
\nThe square root of 196 is 13.
\nFind the prime factors of \u221a(9)
\n\u221a(9) = 3 \u00d7 3
\nGrouping the factors into the pairs of equal factors.
\n(3 \u00d7 3)
\nTake one number from each group and multiply them to find the number whose square is 9.
\n3.
\nThe square root of 9 is 3.
\nThe final answer is 196 \u00f7 9 = 13\/3<\/p>\n

Therefore, the square root of \u221a(196 \u00f7 9) = 13\/3.<\/p>\n

6. Find out the value of \u221a25 \u00d7 \u221a16?<\/strong><\/p>\n

Solution:
\nGiven that \u221a25 \u00d7 \u221a16.
\nFind the separate Square Roots of the two numbers.
\nFind the prime factors of \u221a(25)
\n\u221a(25) = 5 \u00d7 5
\nGrouping the factors into the pairs of equal factors.
\n(5\u00a0 \u00d7 5)
\nTake one number from each group and multiply them to find the number whose square is 25.
\n5
\nThe square root of 25 is 5.
\nFind the prime factors of \u221a(16)
\n\u221a(16) = 4 \u00d7 4
\nGrouping the factors into the pairs of equal factors.
\n(4 \u00d7 4)
\nTake one number from each group and multiply them to find the number whose square is 16.
\n4.
\nThe square root of 16 is 4.
\nThe final answer is \u221a25 \u00d7 \u221a16 = 5 \u00d7 4 = 20<\/p>\n

Therefore, \u221a25 \u00d7 \u221a16 = 20.<\/p>\n","protected":false},"excerpt":{"rendered":"

Square Root of Number in the Fraction Form is explained clearly in this article. Finding natural numbers is easy but when it comes to fractions it is a little bit difficult to find the Square Root of Numbers. So, to make the process easy, we have given the step by step procedure on How do … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":49827,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/02\/Square-Root-of-Number-in-the-Fraction-Form.png","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/49825"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=49825"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/49825\/revisions"}],"predecessor-version":[{"id":138364,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/49825\/revisions\/138364"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media\/49827"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=49825"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=49825"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=49825"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}