{"id":5667,"date":"2023-03-03T21:29:36","date_gmt":"2023-03-03T15:59:36","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=5667"},"modified":"2023-03-04T17:26:41","modified_gmt":"2023-03-04T11:56:41","slug":"go-math-grade-6-answer-key-chapter-13-variability-and-data-distributions","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/go-math-grade-6-answer-key-chapter-13-variability-and-data-distributions\/","title":{"rendered":"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions"},"content":{"rendered":"<p>Go Math Grade 6 Answer Key Chapter 13 deals with Variability and Data Distributions. The HMH Go Math 6th Grade Answer Key is a very helpful resource for students to prepare for the exams. The solutions are mentioned topic-wise to all the questions for chapter 13 Variability and Data Distributions. You can understand the problem-solving methods in a better way by using <a href=\"https:\/\/ccssanswers.com\/go-math-grade-6-answer-key\/\" target=\"_blank\" rel=\"noopener noreferrer\">Go Math Grade 6 Answer Key<\/a> Chapter 13 Variability and Data Distributions for free.<\/p>\n<h2>Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions<\/h2>\n<p>The main concepts of chapter 13 Variability and Data Distributions are discussed in the below sections. So, tap the links and practice the problems. This Go Math Grade 6 Answer Key Ch 13 Variability and Data Distributions helps you to secure the highest marks in the exams. For better performance, you try to compare the problems with real time.<\/p>\n<p><strong>Chapter 13 &#8211; Lesson: 1<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_709\">Share and Show &#8211; Page No. 709<\/a><\/li>\n<li><a href=\"#Big_Cats_Page_No_710\">Big Cats &#8211; Page No. 710<\/a><\/li>\n<li><a href=\"#Patterns_in_Data_Page_No_711\">Patterns in Data &#8211; Page No. 711<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_712\">Lesson Check &#8211; Page No. 712<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 2<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_715\">Share and Show &#8211; Page No. 715<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_716\">Problem Solving + Applications &#8211; Page No. 716<\/a><\/li>\n<li><a href=\"#Box_Plots_Page_No_717\">Box Plots &#8211; Page No. 717<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_718\">Lesson Check &#8211; Page No. 718<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 3<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_721\">Share and Show &#8211; Page No. 721<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_722\">Problem Solving + Applications &#8211; Page No. 722<\/a><\/li>\n<li><a href=\"#Mean_Absolute_Deviation_Page_No_723\">Mean Absolute Deviation &#8211; Page No. 723<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_724\">Lesson Check &#8211; Page No. 724<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 4<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_727\">Share and Show &#8211; Page No. 727<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_728\">Problem Solving + Applications &#8211; Page No. 728<\/a><\/li>\n<li><a href=\"#Measures_of_Variability_Page_No_729\">Measures of Variability &#8211; Page No. 729<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_730\">Lesson Check &#8211; Page No. 730<\/a><\/li>\n<\/ul>\n<p><strong>Chapter &#8211; 13 &#8211; Mid-Chapter Checkpoint<\/strong><\/p>\n<ul>\n<li><a href=\"#Mid_Chapter_Checkpoint_Page_No_731\">Mid-Chapter Checkpoint &#8211; Vocabulary &#8211; Page No. 731<\/a><\/li>\n<li><a href=\"#Mid_Chapter_Checkpoint_Page_No_732\">Mid-Chapter Checkpoint &#8211; Page No. 732<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 5<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_735\">Share and Show &#8211; Page No. 735<\/a><\/li>\n<li><a href=\"#Unlock_the_Problem_Page_No_736\">Unlock the Problem &#8211; Page No. 736<\/a><\/li>\n<li><a href=\"#Choose_Appropriate_Measures_of_Center_and_Variability_Page_No_737\">Choose Appropriate Measures of Center and Variability &#8211; Page No. 737<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_738\">Lesson Check &#8211; Page No. 738<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 5<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_741\">Share and Show &#8211; Page No. 741<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_742\">Problem Solving + Applications &#8211; Page No. 742<\/a><\/li>\n<li><a href=\"#Apply_Measures_of_Center_and_Variability_Page_No_743\">Apply Measures of Center and Variability &#8211; Page No. 743<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_744\">Lesson Check &#8211; Page No. 744<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 6<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_747\">Share and Show &#8211; Page No. 747<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_748\">Problem Solving + Applications &#8211; Page No. 748<\/a><\/li>\n<li><a href=\"#Describe_Distributions_Page_No_749\">Describe Distributions &#8211; Page No. 749<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_750\">Lesson Check &#8211; Page No. 750<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Lesson: 7<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_753\">Share and Show &#8211; Page No. 753<\/a><\/li>\n<li><a href=\"#On_Your_Own_Page_No_754\">On Your Own &#8211; Page No. 754<\/a><\/li>\n<li><a href=\"#Problem_Solving_Misleading_Statistics_Page_No_755\">Problem Solving Misleading Statistics &#8211; Page No. 755<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_756\">Lesson Check &#8211; Page No. 756<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 13 &#8211; Review\/Test<\/strong><\/p>\n<ul>\n<li><a href=\"#Chapter_13_Review_Test_Page_No_757\">Chapter 13 Review\/Test &#8211; Page No. 757<\/a><\/li>\n<li><a href=\"#Chapter_13_Review_Test_Page_No_758\">Chapter 13 Review\/Test &#8211; Page No. 758<\/a><\/li>\n<li><a href=\"#Chapter_13_Review_Test_Page_No_759\">Chapter 13 Review\/Test &#8211; Page No. 759<\/a><\/li>\n<li><a href=\"#Chapter_13_Review_Test_Page_No_760\">Chapter 13 Review\/Test &#8211; Page No. 760<\/a><\/li>\n<li><a href=\"#Chapter_13_Review_Test_Page_No_761\">Chapter 13 Review\/Test &#8211; Page No. 761<\/a><\/li>\n<li><a href=\"#Chapter_13_Review_Test_Page_No_762\">Chapter 13 Review\/Test &#8211; Page No. 762<\/a><\/li>\n<\/ul>\n<h3><a id=\"Share_and_Show_Page_No_709\"><\/a>Share and Show &#8211; Page No. 709<\/h3>\n<p><strong>For 1\u20133, use the dot plot.<\/strong><\/p>\n<p>Question 1.<br \/>\nThe dot plot shows the number of paintings students in the art club displayed at the art show. Does the dot plot contain any gaps?<br \/>\nIf so, where?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-1.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 1\" width=\"250\" height=\"174\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Between the intervals of 4 &#8211; 7 excluding 4 and 7<\/p>\n<p>Explanation:<br \/>\n<img decoding=\"async\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-1.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 1\" \/><br \/>\nThe dots are filled from 1 &#8211; 4 and 7 but the region between these two intervals is left unfilled so the region containing gaps is 5-6 including 5 and 6<\/p>\n<p>Question 2.<br \/>\nIdentify any clusters in the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 1-4<\/p>\n<p>Explanation:<br \/>\nA group of dots is called a cluster<br \/>\nThe dots form a cluster at 1 &#8211; 4<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169681\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-709-Q3.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 709 Q3\" width=\"714\" height=\"277\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-709-Q3.png 714w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-709-Q3-300x116.png 300w\" sizes=\"(max-width: 714px) 100vw, 714px\" \/><\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p>Question 4.<br \/>\nWhat patterns do you see in the histogram data?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-2.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 2\" width=\"481\" height=\"327\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Identify any peaks in the data.<br \/>\nThe histogram has 6 peaks.<br \/>\nThe interval representing the greatest number of visitors is for ages between 60 and 69 age group.<br \/>\nSTEP 2 The data changes across the intervals.<br \/>\nThe number of visitors increases from 0 to 29 age group and from 40 to 69 age group.<br \/>\nSo, the data values increase to one peak in the interval from 0 to 9 age group and then decrease.<br \/>\nThe visitors of the age group 30 &#8211; 39 did not visit the zoo.<\/p>\n<p>Question 5.<br \/>\nThe dot plot shows the number of errors made by a baseball team in the first 16 games of the season. For numbers 5a-5e, choose Yes or No to indicate whether the statement is correct.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-3.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 3\" width=\"282\" height=\"209\" \/><br \/>\n5a. There is a gap from 4 to 5.<br \/>\n5b. There is a peak at 0.<br \/>\n5c. The dot plot has symmetry.<br \/>\n5d. There are two modes.<br \/>\n5e. There is one cluster.<br \/>\n5a. __________<br \/>\n5b. __________<br \/>\n5c. __________<br \/>\n5d. __________<br \/>\n5e. __________<\/p>\n<p>Answer:<br \/>\n5a. Yes<br \/>\n5b. Yes<br \/>\n5c. No<br \/>\n5d. No<br \/>\n5e. No<\/p>\n<p>Explanation:<br \/>\n5a. There are dots between 4-5 so we can say that there is a gap from 4 to 5.<br \/>\n5b. The number of dots is more at the interval 0 So we can say that there is a peak at 0.<br \/>\n5c. The symmetrical view is nothing but having the same number of dots on both sides of the figure but we cannot observe it in the above figure. Therefore we can say that the dot plot has no symmetry.<br \/>\n5d. The most frequently occurring observation is known as a mode. One dot repeats in all the intervals so we can say that the mode is 1.<br \/>\n5e. A group of observations form a cluster, there are more than 1 group of dots in the figure given above.<\/p>\n<h3><a id=\"Big_Cats_Page_No_710\"><\/a>Big Cats &#8211; Page No. 710<\/h3>\n<p>There are 41 species of cats living in the world today. Wild cats live in places as different as deserts and the cold forests of Siberia, and they come in many sizes. Siberian tigers may be as long as 9 feet and weigh over 2,000 pounds, while bobcats are often just 2 to 3 feet long and weigh between 15 and 30 pounds.<\/p>\n<p>You can find bobcats in many zoos in the United States. The histogram below shows the weights of several bobcats. The weights are rounded to the nearest pound.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-4.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 4\" width=\"496\" height=\"348\" \/><br \/>\n<strong>Use the histogram for 6 and 7.<\/strong><\/p>\n<p>Question 6.<br \/>\nLook for a Pattern Describe the overall shape of the histogram.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The graph starts from a small interval and increases to the highest and then decreases to the smallest interval.<br \/>\nThe histogram has rectangles which are closely packed.<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Identify any peaks in the data.<br \/>\nThe histogram has 1 peak(s).<br \/>\nThe interval representing the greatest number of bobcats is for weights between 18 and 20 pounds.<br \/>\nSTEP 2 Describe how the data changes across the intervals. The number of bobcats increases from 12 to 17 pounds and from 21 to 29 pounds.<br \/>\nSTEP 3 Describe any symmetry the graph has. If I draw a vertical line through the interval for 18 to 20 pounds, the left and right parts of the histogram are very close to being mirror images. The histogram has line symmetry.<\/p>\n<p>So, the data values increase to one peak in the interval for 18 to 20 pounds and then decrease. The data set has a vertical line<br \/>\nsymmetry about the peak.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169682\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-710-Q7.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 710 Q7\" width=\"679\" height=\"347\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-710-Q7.png 679w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-710-Q7-300x153.png 300w\" sizes=\"(max-width: 679px) 100vw, 679px\" \/><\/p>\n<h3><a id=\"Patterns_in_Data_Page_No_711\"><\/a>Patterns in Data &#8211; Page No. 711<\/h3>\n<p><strong>For 1\u20132, use the dot plot.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-5.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 5\" width=\"333\" height=\"162\" \/><\/p>\n<p>Question 1.<br \/>\nThe dot plot shows the number of omelets ordered at Paul\u2019s Restaurant each day. Does the dot plot contain any gaps?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Yes, the dot plot contains gaps<\/p>\n<p>Explanation:<br \/>\nThe dots are filled from 10 &#8211; 11, from 14 &#8211; 16, and from 18 &#8211; 19 but the region between these two intervals is left unfilled so the region containing gaps is 12-13 including 12 and 13, 17 is also left unfilled.<\/p>\n<p>Question 2.<br \/>\nIdentify any clusters in the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 14 &#8211; 16 and 18 &#8211; 19<\/p>\n<p>Explanation:<br \/>\nA group of dots is called a cluster. The dots which form a cluster are 14 &#8211; 16 and from 18 &#8211; 19.<\/p>\n<p><strong>For 3\u20134, use the histogram.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-6.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 6\" width=\"370\" height=\"330\" \/><\/p>\n<p>Question 3.<br \/>\nThe histogram shows the number of people that visited a local shop each day in January. How many peaks does the histogram have?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The histogram has only one peak.<\/p>\n<p>Explanation:<br \/>\nThe rectangle with a tall length represents the highest peak in the graph given above.<br \/>\nThe number of people who visited a local shop each day in January was 0 &#8211; 9\u00a0 visitors and this was the highest frequency having 14 days.<br \/>\nThe highest peak is in the interval of 0 &#8211; 9.<\/p>\n<p>Question 4.<br \/>\nDescribe how the data values change across the intervals.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: They decrease from highest to low values in the given picture above.<\/p>\n<p>Explanation:<br \/>\nThe graph represents the number of visitors in the month of January the visitors of number 0 &#8211; 9 have the highest frequency,<br \/>\n10 &#8211; 19 are the second-highest among the visitors who went to the local shop in the month of January, followed by 20 &#8211; 29,<br \/>\n30 &#8211; 39<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nLook at the dot plot at the right. Does the graph have symmetry? Explain.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-7.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 7\" width=\"311\" height=\"177\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Yes, the graph has a symmetry<\/p>\n<p>Explanation:<br \/>\nIf I draw a vertical line through the interval for _ to_ pounds, the left and right parts of the histogram are very close to being mirror images. The histogram __ line symmetry.<br \/>\nA geometric figure has line symmetry if you can draw a line through it so that the two parts are mirror images of each other.<br \/>\nSo, the data values increase to one peak in the interval for _ to _ pounds and then decrease. The data set __ line symmetry about the peak.<\/p>\n<p>Question 6.<br \/>\nA histogram that shows the ages of students at a library has intervals 1\u20135, 6\u201310, 11\u201315, 16\u201320, and 21\u201325. There is a peak at 11\u201315 years and the graph is symmetric. Sketch what the histogram could look like and describe the patterns you see in the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/graph-300x296.png\" \/><\/p>\n<p>The histogram shows the ages of students at a library has intervals 1\u20135, 6\u201310, 11\u201315, 16\u201320, and 21\u201325. There is a peak at 11\u201315 years and the graph is symmetric.<\/p>\n<p>Explanation:<br \/>\n<img decoding=\"async\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/graph-300x296.png\" \/><br \/>\nThe histogram is a graph with continuous rectangles which are closely packed.<br \/>\nThe asymmetric graph is a graph which has a mirror-like view with equal rectangles on each side.<br \/>\nThe graph with the highest peak represents the highest number of students who visit the library in the age group 11 &#8211; 15<\/p>\n<h3><a id=\"Lesson_Check_Page_No_712\"><\/a>Lesson Check &#8211; Page No. 712<\/h3>\n<p>Question 1.<br \/>\nWhat interval in the histogram has the greatest frequency?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-8.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 8\" width=\"396\" height=\"244\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 10 &#8211; 14 interval has highest frequency of 6<\/p>\n<p>Explanation:<br \/>\nThe rectangle with a peak can be said as it has the greatest frequency. The interval with a peak is 11 &#8211; 15 and the frequency of the peak is 6<\/p>\n<p>Question 2.<br \/>\nMeg makes a dot plot for the data 9, 9, 4, 5, 5, 3, 4, 5, 3, 8, 8, 5. Where does a gap occur?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 6 &#8211; 7 including 6 and 7<\/p>\n<p>Explanation:<br \/>\nLet us consider an axis with 3 to 9 numbers on it and plot the dots as given in the question at points 3,4,5,8 and 9 the gap occurs between 6 and 7 including 6 and 7.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169684\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-712-Q3.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 712 Q3\" width=\"684\" height=\"342\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-712-Q3.png 684w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-712-Q3-300x150.png 300w\" sizes=\"(max-width: 684px) 100vw, 684px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169685\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-712-Q3.1.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 712 Q3.1\" width=\"590\" height=\"506\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-712-Q3.1.png 590w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-712-Q3.1-300x257.png 300w\" sizes=\"(max-width: 590px) 100vw, 590px\" \/><\/p>\n<p>Question 4.<br \/>\nLook at the histogram below. How many students scored 81 or higher on the math test?<br \/>\n________ students<\/p>\n<p>Answer: 14<\/p>\n<p>Explanation:<br \/>\nThe interval 81 &#8211; 90 has 10 frequencies and the interval 91 &#8211; 100 has 4 frequencies. So the total number of students = 14<\/p>\n<p>Question 5.<br \/>\nThe Little League coach uses a radar gun to measure the speed of several of Kyle\u2019s baseball pitches. The speeds, in miles per hour, are 52, 48, 63, 47, 47. What is the median of Kyle\u2019s pitch speeds?<br \/>\nThe median is ________ miles.<\/p>\n<p>Answer: Median is 48<\/p>\n<p>Explanation:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is (n+1\/2)th observation, for odd number of observations<br \/>\nn = 5 (odd)<br \/>\nMedian = (5 + 1 \/ 2) = (6\/2) = 3rd observation = 48<br \/>\nTherefore the median is 48.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_715\"><\/a>Share and Show &#8211; Page No. 715<\/h3>\n<p><strong>Find the median, lower quartile, and upper quartile of the data.<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169686\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-715-Q1.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 715 Q1\" width=\"666\" height=\"531\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-715-Q1.png 666w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-715-Q1-300x239.png 300w\" sizes=\"(max-width: 666px) 100vw, 666px\" \/><\/p>\n<p>Question 2.<br \/>\nthe lengths, in seconds, of 9 videos posted online:<br \/>\n50, 46, 51, 60, 62, 50, 65, 48, 53<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Median: 51 Lower quartile: 46 Upper quartile: 65<\/p>\n<p>Explanation:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is (n+1\/2)th observation, for odd number of observations<br \/>\nn = 9 (odd)<br \/>\nMedian = (9 + 1 \/ 2) = (10\/2) = 5th observation = 51<br \/>\nTherefore the median is 51.<\/p>\n<p>Lower quartile: 46 Upper quartile: 65<\/p>\n<p>Question 3.<br \/>\nMake a box plot to display the data set in Exercise 2.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The box plot is drawn on the topic: Lengths of the videos (in seconds) posted in online.<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-6912\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/box-plot-300x78.png\" alt=\"\" width=\"300\" height=\"78\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/box-plot-300x78.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/box-plot-768x199.png 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/box-plot.png 972w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Explanation:<br \/>\nThe box is drawn to understand the clear view of the raw data, in a precise manner.<br \/>\nThis box gives us information about the lengths of the videos posted online. We can directly say the median, lower quartile, and upper quartile by seeing the box plot.<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Find the median, lower quartile, and upper quartile of the data.<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169687\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-715-Q4.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 715 Q4\" width=\"698\" height=\"372\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-715-Q4.png 698w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-715-Q4-300x160.png 300w\" sizes=\"(max-width: 698px) 100vw, 698px\" \/><\/p>\n<p>Question 5.<br \/>\n61, 23, 49, 60, 83, 56, 51, 64, 84, 27<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 58<\/p>\n<p>Explanation:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is mean of (n\/2) and (n\/2+1)th observations, for even number of observations<br \/>\nn = 10 (even)<br \/>\nMedian = Mean of (5)th and (6)th observations = 56 + 60 divided by 2 = 116\/2 = 58<br \/>\nTherefore the median is 58.<\/p>\n<p>Question 6.<br \/>\nThe chart shows the height of trees in a park. Display the data in a box plot.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-9.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 9\" width=\"345\" height=\"61\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/box-300x81.png\" \/><\/p>\n<p>Explanation:<br \/>\nLower limit: 8<br \/>\nUpper limit: 30<br \/>\nMedian:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is mean of (n\/2) and (n\/2+1)th observations, for even number of observations<br \/>\nn = 12 (even)<br \/>\nMedian = Mean of (6)th and (7)th observations = 18 + 20 divided by 2 = 38\/2 = 19<br \/>\nTherefore the median is 19.<\/p>\n<p>Question 7.<br \/>\nAnalyze Eric made this box plot for the data set below. Explain his error.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-10.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 10\" width=\"261\" height=\"62\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-11.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 11\" width=\"392\" height=\"124\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The lower and upper limits are marked wrong.<\/p>\n<p>Explanation:<br \/>\nThe box drew above the number line is wrong.<br \/>\nIt does not show the correct upper and lower limits.<br \/>\nThe lower limit is 5 and the upper limit is 35.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_716\"><\/a>Problem Solving + Applications &#8211; Page No. 716<\/h3>\n<p><strong>Pose a Problem<\/strong><\/p>\n<p>Question 8.<br \/>\nThe box plots show the number of flights delayed per day for two different airlines. Which data set is more spread out?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-12.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 12\" width=\"280\" height=\"249\" \/><br \/>\nAirline A: greatest value \u2212 least value = _____<br \/>\nAirline B: greatest value \u2212 least value = _____<br \/>\nSo, the data for _____ is more spread out.<br \/>\nWrite a new problem that can be solved using the data in the box plots.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\nAirline A: greatest value \u2212 least value = 8<br \/>\nAirline B: greatest value \u2212 least value = 10<br \/>\nThe data for airline B is more spread out.<\/p>\n<p>A problem which can be solved using the box plot can be:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-6947\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/bo-300x81.png\" alt=\"\" width=\"300\" height=\"81\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/bo-300x81.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/bo.png 651w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nFind the median, lower and upper limits.<\/p>\n<p>Explanation:<br \/>\nThe greatest value and lowest value can be identified by seeing the box drew above the number line. The ends represent the lower and upper limits in both the box plots.<\/p>\n<p>The solution to the question framed:<br \/>\nThe start and end of the rectangle represent the lower and upper limits. And the middle line represents the median.<br \/>\nThe lower limit is 5<br \/>\nUpper limit is 35<br \/>\nMedian:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is mean of (n\/2) and (n\/2+1)th observations, for even number of observations<br \/>\nn = 6 (even)<br \/>\nMedian = Mean of (3)th and (4)th observations = 15 + 25 divided by 2 = 40\/2 = 20<br \/>\nTherefore the median is 20.<\/p>\n<p>Question 9.<br \/>\nThe data set shows the cost of the dinner specials at a restaurant on Friday night.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-13.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 13\" width=\"489\" height=\"62\" \/><br \/>\nThe median is _____.<br \/>\nThe lower quartile is _____.<br \/>\nThe upper quartile is _____.<\/p>\n<p>Answer:<br \/>\nMedian: 24<br \/>\nThe lower quartile is 16.<br \/>\nThe upper quartile is 30.<\/p>\n<p>Explanation:<br \/>\nSeeing the data in the box we can identify the lower and upper quartiles.<br \/>\nMedian:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is (n+1\/2)th observation, for odd number of observations<br \/>\nn = 11 (odd)<br \/>\nMedian = (11 + 1 \/ 2) = (12\/2) = 6th observation =24<br \/>\nTherefore the median is 24.<\/p>\n<h3><a id=\"Box_Plots_Page_No_717\"><\/a>Box Plots &#8211; Page No. 717<\/h3>\n<p><strong>Find the median, lower quartile, and upper quartile of the data.<\/strong><\/p>\n<p>Question 1.<br \/>\nthe amounts of juice in 12 glasses, in fluid ounces:<br \/>\n11, 8, 4, 9, 12, 14, 9, 16, 15, 11, 10, 7<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\nMedian: 10.5<br \/>\nLower quartile: 4<br \/>\nUpper quartile: 16<\/p>\n<p>Explanation:<br \/>\nMedian:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is mean of (n\/2) and (n\/2+1)th observations, for even number of observations<br \/>\nn = 12 (even)<br \/>\nMedian = Mean of (6)th and (7)th observations = 10 + 11 divided by 2 = 21\/2 = 10.5<br \/>\nTherefore the median is 10.5.<br \/>\nAfter writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.<br \/>\nThey are:<br \/>\nLower quartile: 4<br \/>\nUpper quartile: 16<\/p>\n<p>Question 2.<br \/>\nthe lengths of 10 pencils, in centimeters:<br \/>\n18, 15, 4, 9, 14, 17, 16, 6, 8, 10<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\nMedian: 12<br \/>\nLower quartile: 4<br \/>\nUpper quartile: 18<\/p>\n<p>Explanation:<br \/>\nMedian:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is mean of (n\/2) and (n\/2+1)th observations, for even number of observations<br \/>\nn = 10 (even)<br \/>\nMedian = Mean of (5)th and (6)th observations = 10 + 14 divided by 2 = 24\/2 = 12<br \/>\nTherefore the median is 12.<br \/>\nAfter writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.<br \/>\nThey are:<br \/>\nLower quartile: 4<br \/>\nUpper quartile: 18<\/p>\n<p>Question 3.<br \/>\nMake a box plot to display the data set in Exercise 2.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-6948\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/101-300x82.png\" alt=\"\" width=\"300\" height=\"82\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/101-300x82.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/101.png 583w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nThe above box plot represents the lower and upper quartiles, the median.<\/p>\n<p>Explanation:<br \/>\nBox plot is drawn using the number line and the rectangle which is drawn above it.<br \/>\nThe ends of the rectangles say about the lower and upper limits and the middle line indicates the median.<\/p>\n<p>Question 4.<br \/>\nThe numbers of students on several teams are 9, 4, 5, 10, 11, 9, 8, and 6. Make a box plot for the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-6949\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/102-300x104.png\" alt=\"\" width=\"300\" height=\"104\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/102-300x104.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/102.png 465w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Explanation:<br \/>\nBox plot is drawn using the number line and the rectangle which is drawn above it.<br \/>\nThe ends of the rectangles say about the lower and upper limits and the middle line indicates the median.<br \/>\nTherefore the lower and upper quartiles are 4 and 11 respectively.<br \/>\nMedian:<br \/>\nFirst, write the observations in ascending order or descending order.<br \/>\nThe formula to calculate the median is mean of (n\/2) and (n\/2+1)th observations, for even number of observations<br \/>\nn = 8 (even)<br \/>\nMedian = Mean of (4)th and (5)th observations = 8 + 9 divided by 2 = 17\/2 = 8.5<br \/>\nTherefore the median is 8.5.<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169688\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-717-Q5.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 717 Q5\" width=\"703\" height=\"609\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-717-Q5.png 703w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-717-Q5-300x260.png 300w\" sizes=\"(max-width: 703px) 100vw, 703px\" \/><\/p>\n<p>Question 6.<br \/>\nThe weights of the six puppies in ounces are 8, 5, 7, 5, 6, and 9. What is the upper quartile of the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Upper quartile: 9<\/p>\n<p>Explanation:<br \/>\nThe highest value in the data is defined as the upper quartile.<br \/>\nThe highest value in the raw data given is 9<\/p>\n<p>Question 7.<br \/>\nDraw a box plot to display this data: 81, 22, 34, 55, 76, 20, 56.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-6950\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/103-300x109.png\" alt=\"\" width=\"300\" height=\"109\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/103-300x109.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/103.png 485w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Explanation:<br \/>\nA box plot gives information about the lower and upper quartiles and about the median.<br \/>\nThe box plot is drawn using a rectangle and the number line.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_718\"><\/a>Lesson Check &#8211; Page No. 718<\/h3>\n<p>Question 1.<br \/>\nThe values in a data set are 15, 7, 11, 12, 6, 3, 10, and 6. Where would you draw the box in a box plot for the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The box is drawn above the number line.<\/p>\n<p>Explanation:<br \/>\nExample:<br \/>\n<img decoding=\"async\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/103-300x109.png\" \/><br \/>\nThe rectangle which can be seen above the number line is the box plot which is drawn.<br \/>\nThe box plot gives information about the lower and upper quartiles and about the median.<\/p>\n<p>Question 2.<br \/>\nWhat is the lower quartile of the following data set?<br \/>\n22, 27, 14, 21, 22, 26, 18<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 14<\/p>\n<p>Explanation:<br \/>\nThe value which is lowest in the given data is called the lowest quartile.<br \/>\nTherefore the lowest quartile in the given data is 14.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nJenn says that \u201cWhat is the average number of school lunches bought per day?\u201d is a statistical question. Lisa says that \u201cHow many lunches did Mark buy this week?\u201d is a statistical question. Who is NOT correct?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Lisa&#8217;s statement is wrong.<\/p>\n<p>Explanation:<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169689\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-718-Q4.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 718 Q4\" width=\"653\" height=\"409\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-718-Q4.png 653w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-718-Q4-300x188.png 300w\" sizes=\"(max-width: 653px) 100vw, 653px\" \/><\/p>\n<p>Question 5.<br \/>\nBy how much does the mean of the following data set change if the outlier is removed?<br \/>\n13, 19, 16, 40, 12<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The mean shows a difference if the lower limit is removed the mean increases and if the upper limit is removed the mean decreases.<\/p>\n<p>Explanation:<br \/>\nOutliers are nothing but both upper and lower limits.<br \/>\nThe actual mean is 20<br \/>\nBut when the lower limit is removed the mean increases to 22 while when the upper limit is removed the mean decreases to 15.<br \/>\nTherefore, we can say that the mean shows a difference when the outliers are removed.<\/p>\n<p>Question 6.<br \/>\nWhere in the dot plot does a cluster occur?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-14.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 14\" width=\"302\" height=\"106\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 52 &#8211; 54<\/p>\n<p>Explanation:<br \/>\nA cluster is nothing but a group of dots.<br \/>\nIn the intervals 52 &#8211; 54 a cluster has occurred.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_721\"><\/a>Share and Show &#8211; Page No. 721<\/h3>\n<p><strong>Use counters, a dot plot, or iTools to find the mean absolute deviation of the data.<\/strong><\/p>\n<p>Question 1.<br \/>\nFind the mean absolute deviation for both data sets. Explain which data set is more spread out.<br \/>\nthe number of laps Shawna swam on 5 different days:<br \/>\n5, 6, 6, 8, 10<br \/>\nmean = 7<\/p>\n<p>the number of laps Lara swam on 5 different days:<br \/>\n1, 3, 7, 11, 13<br \/>\nmean = 7<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Case 2 is more spread out.<\/p>\n<p>Explanation:<br \/>\nCASE1<br \/>\nThe number of laps Shawna swam on 5 different days:<br \/>\n5,6,6,8,10<br \/>\nMean = 7<br \/>\nDeviations:<br \/>\n7 &#8211; 5 = 2<br \/>\n7 &#8211; 6 = 1<br \/>\n7 &#8211; 6 = 1<br \/>\n7 -8 = -1<br \/>\n7 -10=-3<br \/>\nMean of deviations = 2+1+1+1+3\/5 = 8\/5 = 1.6<\/p>\n<p>CASE2<br \/>\nThe number of laps Lara swam on 5 different days:<br \/>\n1, 3, 7, 11, 13<br \/>\nMean = 7<br \/>\nDeviations:<br \/>\n7 &#8211; 1 = 6<br \/>\n7 &#8211; 3 = 4<br \/>\n7 &#8211; 7 = 0<br \/>\n7 -11= -4<br \/>\n7 -13= -6<br \/>\nMean of deviations = 6+ 4 + 0 + 4 + 6 \/ 5 = 20\/5 = 4<\/p>\n<p><strong>Use the dot plot to find the mean absolute deviation of the data.<\/strong><\/p>\n<p>Question 2.<br \/>\nmean = 7 books<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-15.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 15\" width=\"281\" height=\"196\" \/><br \/>\n______ books<\/p>\n<p>Answer: Mean absolute deviation is 2.4<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each dot with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n4: 7-4=3<br \/>\n5: 7-5=2<br \/>\n6: 7-6=1<br \/>\n9: 7-9=-2<br \/>\n10: 7-10=-3<br \/>\n11: 7-11=-4<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n(3) + (2) +(2) +(2) +(2) +(1) + (2) +(3) +(3) +(4) \/ 10 = 24\/10 = 2.4<\/p>\n<p>So, the mean absolute deviation of the data is 2.4<\/p>\n<p>Question 3.<br \/>\nmean = 29 pounds<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-17.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 17\" width=\"346\" height=\"187\" \/><br \/>\n_______ pounds<\/p>\n<p>Answer: Mean Absolute deviation is 3.2<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each dot with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n26: 29-26=03<br \/>\n27: 29-27=02<br \/>\n32: 29-32=-3<br \/>\n33: 29-33=-4<br \/>\n35: 29-35=-6<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n(3) + (2) +(3) +(4) +(6) +(3) + (3) +(2) \/ 8 = 26\/8 = 3.2<\/p>\n<p>So, the mean absolute deviation of the data is 3.2<\/p>\n<p>Question 4.<br \/>\nThe mean absolute deviation of the number of daily visits to Scott\u2019s website for February is 167.7. In March, the absolute mean deviation is 235.9. In which month did the number of visits to Scott\u2019s website vary more? Explain how you know.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: As the mean absolute deviation is more in the month of February we can say that there are more visitors in this month.<\/p>\n<p>Explanation:<br \/>\nAs the mean of the month of February is less it means that the number of observations are more.<br \/>\nSimilarly, as the mean of the month of March is more it means that the number of observations are less.<br \/>\nTherefore we can say that the number of visitors were more in the month of February compared to March.<\/p>\n<p>Question 5.<br \/>\nWrite an Inequality Algebra In April, the data for Scott\u2019s website visits are less spread out than they were in February. Use a to represent the mean absolute deviation for April. Write an inequality to describe the possible values of a.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: a &lt; February<\/p>\n<p>Explanation:<br \/>\nSince the data is more spread out in the month of April than they were in February. Therefore the inequality represents &#8220;less than&#8221; sign.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_722\"><\/a>Problem Solving + Applications &#8211; Page No. 722<\/h3>\n<p>Question 6.<br \/>\nUse the table.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-18.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 18\" width=\"558\" height=\"97\" \/><br \/>\nThe mean of the data is 11. What is the mean absolute deviation of the data?<br \/>\n_______ days<\/p>\n<p>Answer: 3<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n10: 11-10= 1<br \/>\n12: 11-12=-1<br \/>\n13: 11-13=-2<br \/>\n18: 11-18=-7<br \/>\n10: 11-10= 1<br \/>\n08: 11-08= 3<br \/>\n07: 11-07= 4<br \/>\n06: 11-06= 5<br \/>\n16: 11-16=-5<br \/>\n14: 11-14=-3<br \/>\n08: 11-08= 3<br \/>\n10: 11-10= 1<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1+1 +2 +7 +1 +3 +4 +5+5+3+3+1\/ 12<br \/>\n= 36\/12 = 3<\/p>\n<p>So, the mean absolute deviation of the data is 3.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169690\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-722-Q7.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 722 Q7\" width=\"686\" height=\"576\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-722-Q7.png 686w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-722-Q7-300x252.png 300w\" sizes=\"(max-width: 686px) 100vw, 686px\" \/><\/p>\n<p>Question 8.<br \/>\nExplain Tell how an outlier that is much greater than the mean would affect the mean absolute deviation of the data set. Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: An outlier increases the mean absolute deviation of the data set.<\/p>\n<p>Explanation:<br \/>\nThe difference between the outlier and the mean is a greater number when added in the sum of observations the mean absolute deviation increases.<\/p>\n<p>Question 9.<br \/>\nThe data set shows the number of soccer goals scored by players in 3 games.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-19.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 19\" width=\"350\" height=\"122\" \/><br \/>\nFor numbers 9a\u20139c, choose Yes or No to indicate whether the statement is correct.<br \/>\n9a. The mean absolute deviation of Player A is 1.<br \/>\n9b. The mean absolute deviation of Player B is 0.<br \/>\n9c. The mean absolute deviation of Player C is greater than the mean absolute deviation of Player A.<br \/>\n9a. __________<br \/>\n9b. __________<br \/>\n9c. __________<\/p>\n<p>Answer:<br \/>\n9a. No<br \/>\n9b. Yes<br \/>\n9c. No<\/p>\n<p>Explanation:<br \/>\nPlayer A<br \/>\nMean = 1+2+3\/3 = 6\/3 = 2<br \/>\nMean absolute deviation = 1+0+1\/3 = 2\/3 = 0.6<\/p>\n<p>Player B<br \/>\nMean =2+2+2\/3 = 6?3 = 2<br \/>\nMean absolute deviation = 0\/3 = 0<\/p>\n<p>Player C<br \/>\nMean = 1+2+1\/3 = 4\/3 = 1.3<br \/>\nMean absolute deviation = 0.3+0+0.3\/3 = 0.2<\/p>\n<h3><a id=\"Mean_Absolute_Deviation_Page_No_723\"><\/a>Mean Absolute Deviation &#8211; Page No. 723<\/h3>\n<p><strong>Use counters and a dot plot to find the mean absolute deviation of the data.<\/strong><\/p>\n<p>Question 1.<br \/>\nthe number of hours Maggie spent practicing soccer for 4 different weeks:<br \/>\n9, 6, 6, 7<br \/>\nmean = 7 hours<br \/>\n_______ hour<\/p>\n<p>Answer: The mean absolute deviation of the data is 1.<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n9: 7-9=-2<br \/>\n6: 7-6=-1<br \/>\n6: 7-6=-1<br \/>\n7: 7-7= 0<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2 +1 +1+0\/ 4<br \/>\n= 4 \/4 = 1<\/p>\n<p>So, the mean absolute deviation of the data is 1.<\/p>\n<p>Question 2.<br \/>\nthe heights of 7 people in inches:<br \/>\n60, 64, 58, 60, 70, 71, 65<br \/>\nmean = 64 inches<br \/>\n_______ inches<\/p>\n<p>Answer: The mean absolute deviation of the data is 4.<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n60: 64-60= 4<br \/>\n64: 64-64= 0<br \/>\n58: 64-58= 6<br \/>\n60: 64-60= 4<br \/>\n70: 64-70=-6<br \/>\n71: 64-71=-7<br \/>\n65: 64-65=-1<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n4+0+6+ 4+6+7+1\/7<br \/>\n= 28\/7 = 4<\/p>\n<p>So, the mean absolute deviation of the data is 4.<\/p>\n<p><strong>Use the dot plot to find the mean absolute deviation of the data.<\/strong><\/p>\n<p>Question 3.<br \/>\nmean = 10<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-20.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 20\" width=\"374\" height=\"178\" \/><br \/>\n_______ year<\/p>\n<p>Answer: The mean absolute deviation of the data is 1<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each dot with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n08: 10-08=02<br \/>\n09: 10-09=01<br \/>\n10: 10-10= 0<br \/>\n11: 10-11=-1<br \/>\n12: 10-12=-2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n(2) + (1) +(0) +(1) +(2) +(2)+(1)+(0)+(0)+(0)+(1)+(2) \/12 = 12\/12= 1<\/p>\n<p>So, the mean absolute deviation of the data is 1<\/p>\n<p>Question 4.<br \/>\nmean = 8<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-21-1.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 21\" width=\"344\" height=\"162\" \/><br \/>\n_______ hours<\/p>\n<p>Answer: The mean absolute deviation of the data is 2.4<\/p>\n<p>Explanation:<br \/>\nSTEP 1 Label each dot with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n03: 8-03=05<br \/>\n04: 8-04=04<br \/>\n05: 8-05=03<br \/>\n07: 8-07=01<br \/>\n08: 8-08= 0<br \/>\n09: 8-09=-1<br \/>\n10: 8-10=-2<br \/>\n11: 8-11=-3<br \/>\n12: 8-12=-4<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n(5) + (4) +(3) +(1) +(0) +(1) + (2) +(3) +(4)+(5)+(0)+(1)+(1)+(2)+(4)\/ 15 = 36\/15 = 2.4<\/p>\n<p>So, the mean absolute deviation of the data is 2.4<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nIn science class, Troy found the mass, in grams, of 6 samples to be 10, 12, 7, 8, 5, and 6. What is the mean absolute deviation?<br \/>\n_______ grams<\/p>\n<p>Answer: The mean absolute deviation of the data is 2.<\/p>\n<p>Explanation:<br \/>\nMean = 10+12+7+8+5+6\/6 = 48\/6 = 8<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n10: 8-10= -2<br \/>\n12: 8-12= -4<br \/>\n07: 8-07= 01<br \/>\n08: 8-08= 0<br \/>\n05: 8-05=03<br \/>\n06: 8-06=02<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2+4+1+0+3+2\/6<br \/>\n= 12\/6 = 2<\/p>\n<p>So, the mean absolute deviation of the data is 2.<\/p>\n<p>Question 6.<br \/>\nFive recorded temperatures are 71\u00b0F, 64\u00b0F, 72\u00b0F, 81\u00b0F, and 67\u00b0F. What is the mean absolute deviation?<br \/>\n_______ \u00b0F<\/p>\n<p>Answer: The mean absolute deviation of the data is 4.4.<\/p>\n<p>Explanation:<br \/>\nMean = 71+64+72+81+67\/5 = 355\/5 = 71<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n71: 71-71= 0<br \/>\n64: 71-64= 07<br \/>\n72: 71-72= -1<br \/>\n81: 71-81=-10<br \/>\n67: 71-67= 04<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n0+7+1+10+4\/5<br \/>\n= 22\/5 = 4.4<\/p>\n<p>So, the mean absolute deviation of the data is 4.4.<\/p>\n<p>Question 7.<br \/>\nMake a dot plot of the following data: 10, 10, 11, 12, 12, 13, 13, 15. Use the dot plot to find the mean absolute deviation.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The mean absolute deviation of the data is 1.25<\/p>\n<p>Explanation:<br \/>\nMean = 10+10+11+12+12+13+13+15\/8 = 96\/8 = 12<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>Box plot:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7010\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/dot-300x96.png\" alt=\"\" width=\"300\" height=\"96\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/dot-300x96.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/dot.png 619w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>STEP 1 Label each dot with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n10: 12-10=02<br \/>\n11: 12-11=01<br \/>\n12: 12-12=0<br \/>\n13: 12-13=-1<br \/>\n15: 12-15=-3<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n(2) + (2) +(1) +(0) +(0) +(1) + (1) +(3) \/ 8 = 10\/8 = 1.25<\/p>\n<p>So, the mean absolute deviation of the data is 1.25<\/p>\n<h3><a id=\"Lesson_Check_Page_No_724\"><\/a>Lesson Check &#8211; Page No. 724<\/h3>\n<p>Question 1.<br \/>\nThe six test grades are 86, 88, 92, 90, 82, and 84. The mean of the data is 87. What is the mean absolute deviation?<br \/>\n_______<\/p>\n<p>Answer: The mean absolute deviation of the data is 3.5<\/p>\n<p>Explanation:<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n86: 87-86= 01<br \/>\n88: 87-88= -1<br \/>\n92: 87-92= -5<br \/>\n90: 87-81= 06<br \/>\n82: 87-82= 05<br \/>\n84: 87-84= 03<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1+5+1+6+5+3\/6<br \/>\n= 21\/6 = 3.5<\/p>\n<p>So, the mean absolute deviation of the data is 3.5<\/p>\n<p>Question 2.<br \/>\nEight heights in inches are 42, 36, 44, 46, 48, 42, 48, and 46. The mean of the data is 44. What is the mean absolute deviation?<br \/>\n_______ inches<\/p>\n<p>Answer:<\/p>\n<p>Explanation: The mean absolute deviation of the data is 3<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n42: 44-42= 02<br \/>\n36: 44-36= 08<br \/>\n44: 44-44= 0<br \/>\n46: 44-46= -2<br \/>\n48: 44-48= -4<br \/>\n42: 44-42= 02<br \/>\n48: 44-48= -4<br \/>\n46: 44-46= -2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2+8+2+4+0+2+4+2\/8<br \/>\n= 24\/8 = 3<\/p>\n<p>So, the mean absolute deviation of the data is 3<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169691\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-724-Q3.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 724 Q3\" width=\"653\" height=\"276\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-724-Q3.png 653w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-724-Q3-300x127.png 300w\" sizes=\"(max-width: 653px) 100vw, 653px\" \/><\/p>\n<p>Question 4.<br \/>\nCarrie is making a frequency table showing the number of miles she walked each day during the 30 days of September. What value should she write in the Frequency column for 9 to 11 miles?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-22.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 22\" width=\"360\" height=\"169\" \/><br \/>\n_______<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\nTotal number of days in the month of September = 30<br \/>\nNumber of days given in the frequency table = 17+8+4 = 29<br \/>\nFrequency in the interval 9 &#8211; 11 = 30 &#8211; 29 = 1 day<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169692\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-724-Q5.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 724 Q5\" width=\"671\" height=\"335\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-724-Q5.png 671w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-724-Q5-300x150.png 300w\" sizes=\"(max-width: 671px) 100vw, 671px\" \/><\/p>\n<p>Question 6.<br \/>\nWhat is the upper quartile of the following data?<br \/>\n43, 48, 55, 50, 58, 49, 38, 42, 50<br \/>\nThe upper quartile is _______<\/p>\n<p>Answer: The upper quartile is 58<\/p>\n<p>Explanation:<br \/>\nThe highest observation in the data given is known as upper quartile. The upper quartile is 58<\/p>\n<h3><a id=\"Share_and_Show_Page_No_727\"><\/a>Share and Show &#8211; Page No. 727<\/h3>\n<p>Question 1.<br \/>\nFind the range and interquartile range of the data in the box plot.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-23.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 23\" width=\"333\" height=\"128\" \/><br \/>\nThe range is $ __________ .<br \/>\nThe interquartile range is $ __________ .<\/p>\n<p>Answer: $12, $3<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest observation and the lowest observation is called a range.<br \/>\nRange = 19 &#8211; 7 = $12<br \/>\nThe difference and the highest and the lowest dots of the dot plot is called as interquartile range.<br \/>\nInterquartile range = 15 &#8211; 12 = $3<\/p>\n<p><strong>Practice: Copy and Solve Find the mean absolute deviation for the data set.<\/strong><\/p>\n<p>Question 2.<br \/>\nheights in inches of several tomato plants:<br \/>\n16, 18, 18, 20, 17, 20, 18, 17<br \/>\n_______ inch<\/p>\n<p>Answer: The mean absolute deviation of the data is 1<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean = 16+18+18 +20+17+20+18+17\/8 = 144\/8 = 18<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n16: 18-16= 02<br \/>\n18: 18-18= 0<br \/>\n18: 18-18= 0<br \/>\n20: 18-20= -2<br \/>\n17: 18-17= 01<br \/>\n20: 18-20= -2<br \/>\n18: 18-18= 0<br \/>\n17: 18-17= 01<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2+0+0+2+1+2+0+1\/8<br \/>\n= 8\/8 = 1<\/p>\n<p>So, the mean absolute deviation of the data is 1<\/p>\n<p>Question 3.<br \/>\ntimes in seconds for students to run one lap:<br \/>\n68, 60, 52, 40, 64, 40<br \/>\n_______ seconds<\/p>\n<p>Answer: The mean absolute deviation of the data is 10<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean = 68+60+52+40+64+40\/6 = 54<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n68: 54-68= -14<br \/>\n60: 54-60= -6<br \/>\n52: 54-52= 02<br \/>\n40: 54-40= 14<br \/>\n64: 54-64= -10<br \/>\n40: 54-40= 14<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n14+6+2+14+10+14\/6<br \/>\n= 60\/6 = 10<\/p>\n<p>So, the mean absolute deviation of the data is 10<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Use the box plot for 4 and 5.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-24.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 24\" width=\"333\" height=\"141\" \/><\/p>\n<p>Question 4.<br \/>\nWhat is the range of the data?<br \/>\n$ _______<\/p>\n<p>Answer: $24<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest observation and the lowest observation is called a range.<br \/>\nRange = $56 &#8211; $32 = $24<\/p>\n<p>Question 5.<br \/>\nWhat is the interquartile range of the data?<br \/>\n$ _______<\/p>\n<p>Answer: $16<\/p>\n<p>Explanation:<br \/>\nThe difference and the highest and the lowest dots of the dot plot is called as interquartile range.<br \/>\nInterquartile range = $52 &#8211; $36 = $16<\/p>\n<p><strong>Practice: Copy and Solve Find the mean absolute deviation for the data set.<\/strong><\/p>\n<p>Question 6.<br \/>\ntimes in minutes spent on a history quiz:<br \/>\n35, 35, 32, 34, 34, 32, 34, 36<br \/>\n_______ minute<\/p>\n<p>Answer: The mean absolute deviation of the data is 1<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean = 35+ 35+ 32+ 34+34+ 32+ 34+36\/8 = 272\/8 = 34<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n35: 34-35= -1<br \/>\n35: 34-35= -1<br \/>\n32: 34-32= 02<br \/>\n34: 34-34= 0<br \/>\n34: 34-34= 0<br \/>\n32: 34-32=02<br \/>\n34: 34-34=0<br \/>\n36: 34-36=-2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1+1+2+0+0+2+0+2\/8<br \/>\n= 8\/8 = 1<\/p>\n<p>So, the mean absolute deviation of the data is 1<\/p>\n<p>Question 7.<br \/>\nthe number of excused absences for one semester:<br \/>\n1, 2, 1, 10, 9, 9, 10, 6, 1, 1<br \/>\n_______<\/p>\n<p>Answer: The mean absolute deviation of the data is 3.8<\/p>\n<p>Explanation:<\/p>\n<p>Mean:<br \/>\nMean =1+2+1+10+9+9+10+6+1+1 \/10 = 50\/10 = 5<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n1: 5-1= 4<br \/>\n2: 5-2= 3<br \/>\n1: 5-1= 4<br \/>\n10: 5-10= -5<br \/>\n9: 5-9= -4<br \/>\n9: 5-9=-4<br \/>\n10: 5-10=-5<br \/>\n6: 5-6=-1<br \/>\n1: 5-1=4<br \/>\n1: 5-1=4<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n4+3+4+5+4+4+5+1+4+4\/10<br \/>\n=38\/10 = 3.8<\/p>\n<p>So, the mean absolute deviation of the data is 3.8<\/p>\n<p>Question 8.<br \/>\nThe chart shows the price of different varieties of dog food at a pet store. Find the range, interquartile range, and the mean absolute deviation of the data set.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-25.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 25\" width=\"351\" height=\"72\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer:<\/p>\n<p>The mean absolute deviation of the data is 3.6<br \/>\nRange = 32-16 = 16<br \/>\nInterquartile range = 24 &#8211; 20 = 4<\/p>\n<p>Explanation:<\/p>\n<p>Mean:<br \/>\nMean =18+24+20+26+24+20+32+20+16+20 \/10 = 220\/10 = 22<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n18: 22-18= 4<br \/>\n24: 22-24= -2<br \/>\n20: 22-20= 2<br \/>\n26: 22-26= -4<br \/>\n24: 22-24= -2<br \/>\n20: 22-20= 2<br \/>\n32: 22-32=-10<br \/>\n20: 22-20= 2<br \/>\n16: 22-16= 6<br \/>\n20: 22-20= 2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n4+2+2+4+2+2+10+2+6+2\/10<br \/>\n=36\/10 = 3.6<\/p>\n<p>So, the mean absolute deviation of the data is 3.6<br \/>\nThe difference between the highest observation and the lowest observation is called a range.<br \/>\nRange = 32-16 = 16<br \/>\nThe difference and the highest and the lowest dots of the dot plot is called the interquartile range.<br \/>\nInterquartile range = 24 &#8211; 20 = 4<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_728\"><\/a>Problem Solving + Applications &#8211; Page No. 728<\/h3>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169693\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-728-Q9.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 728 Q9\" width=\"668\" height=\"416\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-728-Q9.png 668w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-728-Q9-300x187.png 300w\" sizes=\"(max-width: 668px) 100vw, 668px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169694\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-728-Q9.1.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 728 Q9.1\" width=\"500\" height=\"243\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-728-Q9.1.png 500w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-728-Q9.1-300x146.png 300w\" sizes=\"(max-width: 500px) 100vw, 500px\" \/><\/p>\n<p>Question 10.<br \/>\nCompare Jack recorded the number of minutes his family walked each day for a month. The range of the data is 15. How does this compare to the data for Hyato\u2019s family?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Jack&#8217;s family walked less number of minutes each day compared to Hyato&#8217;s family.<\/p>\n<p>Explanation:<br \/>\nThe range of Hyato&#8217;s family is 20 while the range of Jack&#8217;s family is 15. Therefore we can say that Hyato&#8217;s family walked in more minutes compared to Jack&#8217;s family in a day.<br \/>\nThe range can define the data with large observations and the data with the least observations.<\/p>\n<p>Question 11.<br \/>\nSense or Nonsense? Nathan claims that the interquartile range of a data set can never be greater than its range. Is Nathan\u2019s claim sense or nonsense? Explain.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Nonsense, Interquartile range of a data set can be less than or greater than the range.<\/p>\n<p>Explanation:<br \/>\nThe interquartile range is the difference between the medians of the observations.<br \/>\nNathan&#8217;s claim is nonsense as he said, &#8221; The interquartile range can never be greater than its range.&#8221;<br \/>\nThe range is the difference between the highest observation and the lowest observation.<br \/>\nThe interquartile range can be less or greater than the range.<\/p>\n<p>Example:<br \/>\nAscending order: 25,30,30,35,40,40,45<br \/>\nn=7 (odd)<br \/>\nMedian= Number of (n+1\/2) = 8\/2 = 4th observation = 35<br \/>\nMedian:(four terms of the data)<br \/>\nMedian = 30+30\/2 = 60\/2 = 30<br \/>\nMedian:(last 3 terms of the data)<br \/>\nMedian = (n+1\/2) = 2nd observation = 40<br \/>\nInterquartile range = 30+40\/2 = 70\/2 = 35<\/p>\n<p>Range= 45-25 = 20<\/p>\n<p>In the above case the interquartile range is more than the range proving that the given statement is nonsense.<\/p>\n<p>Question 12.<br \/>\nThe box plot shows the heights of corn stalks from two different farms.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-26.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 26\" width=\"475\" height=\"204\" \/><br \/>\nThe range of Farm A&#8217;s heights is _____ the range of Farm B&#8217;s heights.<\/p>\n<p>Answer: greater than<\/p>\n<p>Explanation:<br \/>\nThe range is the difference between the highest and the lowest observations.<br \/>\nRange of Farm A: 72-58 = 14<br \/>\nRange of Farm B: 70-55 = 15<\/p>\n<p>Therefore, The range of Farm A&#8217;s heights is greater than the range of Farm B&#8217;s heights.<\/p>\n<h3><a id=\"Measures_of_Variability_Page_No_729\"><\/a>Measures of Variability &#8211; Page No. 729<\/h3>\n<p>Question 1.<br \/>\nFind the range and interquartile range of the data in the box plot.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-27.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 27\" width=\"402\" height=\"148\" \/><br \/>\nThe range is __________ miles.<br \/>\nThe interquartile range is __________ miles.<\/p>\n<p>Answer: 16, 8<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest and the lowest observations is range.<br \/>\nRange = 17 &#8211; 1 = 16<br \/>\nThe difference between the highest and lowest observations of the box is the interquartile range.<br \/>\nInterquartile range = 12 &#8211; 4 = 8<\/p>\n<p><strong>Use the box plot for 2 and 3.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-28.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 28\" width=\"401\" height=\"156\" \/><\/p>\n<p>Question 2.<br \/>\nWhat is the range of the data?<br \/>\n_____<\/p>\n<p>Answer: 35<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest and the lowest observations is range.<br \/>\nRange = 95 &#8211; 60 = 35<\/p>\n<p>Question 3.<br \/>\nWhat is the interquartile range of the data?<br \/>\n_____<\/p>\n<p>Answer: 20<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest and lowest observations of the box is the interquartile range.<br \/>\nInterquartile range = 90 &#8211; 70 = 20<\/p>\n<p><strong>Find the mean absolute deviation for the set.<\/strong><\/p>\n<p>Question 4.<br \/>\nheights in centimeters of several flowers:<br \/>\n14, 7, 6, 5, 13<br \/>\n_____ cm<\/p>\n<p>Answer: The mean absolute deviation of the data is 3.6<\/p>\n<p>Explanation:<\/p>\n<p>Mean:<br \/>\nMean =14+7+ 6+5+13\/5= 45\/5 = 9<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n14: 9-14= -5<br \/>\n07: 9-07= 02<br \/>\n06: 9-06= 03<br \/>\n05: 9-05= 04<br \/>\n13: 9-13= -4<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n5+2+3+4+4\/5<br \/>\n= 18\/5 = 3.6<\/p>\n<p>So, the mean absolute deviation of the data is 3.6<\/p>\n<p>Question 5.<br \/>\nages of several children:<br \/>\n5, 7, 4, 6, 3, 5, 3, 7<br \/>\n_____ years<\/p>\n<p>Answer: The mean absolute deviation of the data is 1.25<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean = 5+7+4+6+ 3+5+3+7\/8 = 40\/8 = 5<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n5: 5-5= 0<br \/>\n7: 5-7= -2<br \/>\n4: 5-4= 01<br \/>\n6: 5-6= -1<br \/>\n3: 5-3= 02<br \/>\n5: 5-5= 0<br \/>\n3: 5-3= 02<br \/>\n7: 5-7=-2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n0+2+1+1+2+0+2+2\/8<br \/>\n= 10\/8 = 1.25<\/p>\n<p>So, the mean absolute deviation of the data is 1.25<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 6.<br \/>\nThe following data set gives the amount of time, in minutes, it took five people to cook a recipe. What is the mean absolute deviation for the data?<br \/>\n33, 38, 31, 36, 37<br \/>\n_____ minutes<\/p>\n<p>Answer: The mean absolute deviation of the data is 2.4<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean = 33+38+31+36+37\/5 = 175\/5 = 35<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n33: 35-33= 02<br \/>\n38: 35-38= -3<br \/>\n31: 35-31= 04<br \/>\n36: 35-36= -1<br \/>\n37: 35-37= -2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2+3+4+1+2\/5<br \/>\n= 12\/5 = 2.4<\/p>\n<p>So, the mean absolute deviation of the data is 2.4<\/p>\n<p>Question 7.<br \/>\nThe prices of six food processors are $63, $59, $72, $68, $61, and $67. What are the range, interquartile range, and mean absolute deviation for the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range = $9 The mean absolute deviation of the data is 4<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest and the lowest observations is range.<br \/>\nRange = $68 &#8211; $59 = $9<br \/>\nThe difference between the highest and lowest observations of the box is the interquartile range.<br \/>\nInterquartile range = 12 &#8211; 4 = 8<\/p>\n<p>Mean:<br \/>\nMean = $63+$59+$72+$68+$61+$67\/6 = 390\/6 = 65<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n63: 65-63= 02<br \/>\n59: 65-59= 06<br \/>\n72: 65-72= -7<br \/>\n68: 65-68= -3<br \/>\n61: 65-61= -4<br \/>\n67: 65-67= -2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2+6+7+3+4+2\/6<br \/>\n= 24\/6 = 4<\/p>\n<p>So, the mean absolute deviation of the data is 4<\/p>\n<p>Question 8.<br \/>\nFind the range, interquartile range, and mean absolute deviation for this data set: 41, 45, 60, 61, 61, 72, 80.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The mean absolute deviation of the data is 9.7<\/p>\n<p>Explanation:<\/p>\n<p>Mean:<br \/>\nMean = 41+45+60+61+61+72+80 \/7 = 420\/7 = 60<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n41: 60-41= 19<br \/>\n45: 60-45= 15<br \/>\n60: 60-60= 0<br \/>\n61: 60-61= -1<br \/>\n61: 60-61= -1<br \/>\n72: 60-72= -12<br \/>\n80: 60-80= -20<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n19+15+0+1+1+12+20\/7<br \/>\n= 68\/7 = 9.7<\/p>\n<p>So, the mean absolute deviation of the data is 9.7<\/p>\n<h3><a id=\"Lesson_Check_Page_No_730\"><\/a>Lesson Check &#8211; Page No. 730<\/h3>\n<p>Question 1.<br \/>\nDaily high temperatures recorded in a certain city are 65\u00b0F, 66\u00b0F, 70\u00b0F, 58\u00b0F, and 61\u00b0F. What is the mean absolute deviation for the data?<br \/>\n_____ \u00b0F<\/p>\n<p>Answer: The mean absolute deviation of the data is 3.6<\/p>\n<p>Explanation:<\/p>\n<p>Mean:<br \/>\nMean = 65+66+70+58+61 \/5 = 320\/5 = 64<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n65: 64-65=-1<br \/>\n66: 64-66=-2<br \/>\n70: 64-70=-6<br \/>\n58: 64-58=06<br \/>\n61: 64-61=03<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1+2+6+6+3\/5<br \/>\n= 18\/5 = 3.6<\/p>\n<p>So, the mean absolute deviation of the data is 3.6<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169695\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-730-Q2.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 730 Q2\" width=\"653\" height=\"612\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-730-Q2.png 653w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-730-Q2-300x281.png 300w\" sizes=\"(max-width: 653px) 100vw, 653px\" \/><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nLook at the histogram. How many days did the restaurant sell more than 59 pizzas?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-29.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 29\" width=\"372\" height=\"332\" \/><br \/>\n________<\/p>\n<p>Answer: 20<\/p>\n<p>Explanation:<br \/>\nAfter 59 there is 1 interval 60-79<br \/>\nNumber of days the restaurant sell more than 59 pizzas = 20<\/p>\n<p>Question 4.<br \/>\nLook at the histogram. Where does a peak in the data occur?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-30.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 30\" width=\"372\" height=\"332\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 20 &#8211; 39<\/p>\n<p>Explanation:<br \/>\nNumber of days the restaurant sold the maximum pizzas = 30<br \/>\nNumber of pizzas sold each day = 20 &#8211; 39<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169696\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-730-Q5.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 730 Q5\" width=\"627\" height=\"210\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-730-Q5.png 627w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-730-Q5-300x100.png 300w\" sizes=\"(max-width: 627px) 100vw, 627px\" \/><\/p>\n<p>Question 6.<br \/>\nThe data set below lists the ages of people on a soccer team. The mean of the data is 23. What is the mean absolute deviation?<br \/>\n24, 22, 19, 19, 23, 23, 26, 27, 24<br \/>\n________<\/p>\n<p>Answer: The mean absolute deviation of the data is 2<\/p>\n<p>Explanation:<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n24: 23-24=-1<br \/>\n22: 23-22= 1<br \/>\n19: 23-19= 4<br \/>\n19: 23-19= 4<br \/>\n23: 23-23=0<br \/>\n23: 23-23=0<br \/>\n26: 23-26=-3<br \/>\n27: 23-27=-4<br \/>\n24: 23-24=-1<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1+1+4+4+3+4+1+0+0\/9<br \/>\n= 18\/9 = 2<\/p>\n<p>So, the mean absolute deviation of the data is 2<\/p>\n<h3><a id=\"Mid_Chapter_Checkpoint_Page_No_731\"><\/a>Mid-Chapter Checkpoint &#8211; Vocabulary &#8211; Page No. 731<\/h3>\n<p><strong>Choose the best term from the box to complete the sentence.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-31.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 31\" width=\"271\" height=\"302\" \/><\/p>\n<p>Question 1.<br \/>\nThe _____ is the difference between the upper quartile and the lower quartile of a data set.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range<\/p>\n<p>Explanation:<br \/>\nThe difference between the upper and lower quartiles of the data is known as range.<\/p>\n<p>Question 2.<br \/>\nA graph that shows the median, quartiles and least and greatest values of a data set is called a(n) _____.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Box plot<\/p>\n<p>Explanation:<br \/>\nThe figure which shows the median, quartiles and least and greatest values of a data set is called a box plot, a box plot is a figure which represents median with a horizontal line and the starting and ending line represents the upper and lower quartiles and the end dots represent the upper limit and the lower limit.<\/p>\n<p>Question 3.<br \/>\nThe difference between the greatest value and the least value in a data set is the _____.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range<\/p>\n<p>Explanation:<br \/>\nEach data set consists of upper and lower limits the difference between these limits is called as range.<\/p>\n<p>Question 4.<br \/>\nThe _____ is the mean of the distances between the values of a data set and the mean of the data set.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean absolute<\/p>\n<p>Explanation:<br \/>\nMean absolute deviation is calculated by subtracting each observation from the mean and then the mean is calculated for these observations.<br \/>\nTherefore we can say that the mean absolute is the mean of the distances between the values of a data set and the mean of the data set.<\/p>\n<p><strong>Concepts and Skills<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169697\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q5.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 731 Q5\" width=\"577\" height=\"357\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q5.png 577w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q5-300x186.png 300w\" sizes=\"(max-width: 577px) 100vw, 577px\" \/><\/p>\n<p><strong>Find the mean absolute deviation of the data.<\/strong><\/p>\n<p>Question 6.<br \/>\n43, 46, 48, 40, 38<br \/>\n________<\/p>\n<p>Answer: The mean absolute deviation of the data is 3.2<\/p>\n<p>Explanation:<br \/>\nMean:<\/p>\n<p>Mean = 43+46+48+40+38\/5 = 215\/5 = 43<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n43: 43-43=0<br \/>\n43: 43-46=-3<br \/>\n43: 43-48=-5<br \/>\n43: 43-40= 3<br \/>\n43: 43-38= 5<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n0+3+5+3+5\/5 = 16\/5 = 3.2<\/p>\n<p>So, the mean absolute deviation of the data is 3.2<\/p>\n<p>Question 7.<br \/>\n26, 20, 25, 21, 24, 27, 26, 23<br \/>\n________<\/p>\n<p>Answer: The mean absolute deviation of the data is 2.125<\/p>\n<p>Explanation:<br \/>\nMean:<\/p>\n<p>Mean = 26+20+25+21+24+27+26+23\/8 = 192\/8 = 24<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n26: 24-26=-3<br \/>\n20: 24-20= 4<br \/>\n25: 24-25= -1<br \/>\n21: 24-21= 3<br \/>\n24: 24-24=0<br \/>\n27: 24-27=-3<br \/>\n26: 24-26=-2<br \/>\n23: 24-23=1<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n3+4+1+3+0+3+2+1\/8<br \/>\n= 17\/8 = 2.125<\/p>\n<p>So, the mean absolute deviation of the data is 2.125<\/p>\n<p>Question 8.<br \/>\n99, 70, 78, 85, 76, 81<br \/>\n________<\/p>\n<p>Answer: The mean absolute deviation of the data is 2<\/p>\n<p>Explanation:<br \/>\nMean:<\/p>\n<p>Mean = 99+70+78+85+76+81\/6 = 489\/6 = 81.5<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n24: 23-24=-1<br \/>\n22: 23-22= 1<br \/>\n19: 23-19= 4<br \/>\n19: 23-19= 4<br \/>\n23: 23-23=0<br \/>\n23: 23-23=0<br \/>\n26: 23-26=-3<br \/>\n27: 23-27=-4<br \/>\n24: 23-24=-1<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1+1+4+4+3+4+1+0+0\/9<br \/>\n= 18\/9 = 2<\/p>\n<p>So, the mean absolute deviation of the data is 2<\/p>\n<p><strong>Find the range and interquartile range of the data.<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169698\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q9.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 731 Q9\" width=\"651\" height=\"303\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q9.png 651w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q9-300x140.png 300w\" sizes=\"(max-width: 651px) 100vw, 651px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169699\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q10.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 731 Q10\" width=\"659\" height=\"321\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q10.png 659w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-731-Q10-300x146.png 300w\" sizes=\"(max-width: 659px) 100vw, 659px\" \/><\/p>\n<p>Question 11.<br \/>\n39, 22, 33, 45, 42, 40, 28<br \/>\nThe range is _________.<br \/>\nThe interquartile range is _________.<\/p>\n<p>Answer: 23<\/p>\n<p>Explanation:<br \/>\nThe difference between the upper quartile and lower quartile.<br \/>\nRange = 45 &#8211; 22 = 23<\/p>\n<h3><a id=\"Mid_Chapter_Checkpoint_Page_No_732\"><\/a>Page No. 732<\/h3>\n<p>Question 12.<br \/>\nYasmine keeps track of the number of hockey goals scored by her school\u2019s team at each game. The dot plot shows her data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-32.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 32\" width=\"320\" height=\"152\" \/><br \/>\nWhere is there a gap in the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: There is a gap in the data in the intervals: between 1 and 2<\/p>\n<p>Explanation:<br \/>\nAs shown in the dot plot there is a gap between 1 and 2. This means that Yasmine&#8217;s team did not score only one goal when they played the game.<\/p>\n<p>Question 13.<br \/>\nWhat is the interquartile range of the data shown in the dot plot with Question 12?<br \/>\nThe interquartile range is _________ .<\/p>\n<p>Answer: 2<\/p>\n<p>Explanation:<br \/>\nThe interquartile range is the difference between the lower and upper quartiles.<br \/>\nInterquartile range = 3-1 = 2<\/p>\n<p>Question 14.<br \/>\nRandall\u2019s teacher added up the class scores for the quarter and used a histogram to display the data. How many peaks does the histogram have? Explain how you know.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-33.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 33\" width=\"508\" height=\"340\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The graph has only one peak<\/p>\n<p>Explanation:<br \/>\nIn the given graph there is are rectangles out of which one has a tall rectangle which can be addressed as peak.<\/p>\n<p>Question 15.<br \/>\nIn a box plot of the data below, where would the box be drawn?<br \/>\n55, 37, 41, 62, 50, 49, 64<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The box is drawn above the number line and this represents the median and the lower and upper limits.<\/p>\n<p>Explanation:<br \/>\nA box is drawn to represent the median and the upper and lower limits in a box plot.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_735\"><\/a>Share and Show &#8211; Page No. 735<\/h3>\n<p>Question 1.<br \/>\nThe distances in miles students travel to get to school are 7, 1, 5, 9, 9, and 8. Decide which measure(s) of center best describes the data set. Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean: 6.5<br \/>\nMedian: 7.5<br \/>\nMode: 9<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\n7+1+5+9+9+8\/6 = 39\/6 = 6.5<br \/>\nMedian:<br \/>\nAscending order: 1,5,7,8,9,9<br \/>\nMedian = Mean of 7 and 8 = 7+8\/2 = 15\/2 = 7.5<br \/>\nMode:<br \/>\nThe most frequently occurring observation is known as the mode.<br \/>\nThe mode is 9.<\/p>\n<p>Question 2.<br \/>\nUse Graphs The numbers of different brands of orange juice carried in several stores are 2, 1, 3, 1, 12, 1, 2, 2, and 5. Make a box plot of the data and find the range and interquartile range. Decide which measure better describes the data set and explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range: 11\u00a0 \u00a0 \u00a0 Interquartile: 3 Interquartile range is the best way to represent the data.<\/p>\n<p>Explanation:<br \/>\nRange = 12 &#8211; 1 = 11<br \/>\nInterquartile range :<br \/>\nMedian(of first 4 terms):<br \/>\nMedian = 1+1\/2 = 2\/2 = 1<br \/>\nMedian (of last 4 terms):<br \/>\nMedian = 3+5\/2 = 8\/2 = 4<br \/>\nInterquartile range = 4 &#8211; 1 = 3<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169700\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-735-Q3.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 735 Q3\" width=\"694\" height=\"551\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-735-Q3.png 694w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-735-Q3-300x238.png 300w\" sizes=\"(max-width: 694px) 100vw, 694px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169701\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-735-Q4.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 735 Q4\" width=\"717\" height=\"472\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-735-Q4.png 717w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-735-Q4-300x197.png 300w\" sizes=\"(max-width: 717px) 100vw, 717px\" \/><\/p>\n<h3><a id=\"Unlock_the_Problem_Page_No_736\"><\/a>Unlock the Problem &#8211; Page No. 736<\/h3>\n<p>Question 5.<br \/>\nJaime is on the community swim team. The table shows the team\u2019s results in the last 8 swim meets. Jaime believes they can place in the top 3 at the next swim meet. Which measure of center should Jaime use to persuade her team that she is correct? Explain.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-34.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 34\" width=\"243\" height=\"314\" \/><br \/>\na. What do you need to find?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean, median,mode<\/p>\n<p>Explanation:<br \/>\nMean= 1+2+2+3+3+1+18+2\/8 = 32\/8 = 4<br \/>\nMedian:<br \/>\nAscending order: 1,1,2,2,2,3,3,18<br \/>\nMedian = 2+2\/2 = 2<br \/>\nMode:<br \/>\nThe most frequently occurring observation is called a mode.<br \/>\nMode=2<\/p>\n<p>Question 5.<br \/>\nb. What information do you need to solve the problem?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: We need to have the data to find the centre of tendencies.<\/p>\n<p>Explanation:<br \/>\nThe given data can be used to find the mean, median and mode.<\/p>\n<p>Question 5.<br \/>\nc. What are the measures of center?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean = 4 Median = 2 Mode = 2<\/p>\n<p>Explanation:<br \/>\nThere are three measures to calculate their approximate values.<\/p>\n<p>Question 5.<br \/>\nd. Which measure of center should Jaime use? Explain.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Median or mode<\/p>\n<p>Explanation:<br \/>\nMedian or mode are nearer to the solution, therefore, they can be used.<\/p>\n<p>Question 6.<br \/>\nThe numbers of sit-ups students completed in one minute are 10, 42, 46, 50, 43, and 49. The mean of the data values is 40 and the median is 44.5. Which measure of center better describes the data, the mean or median? Use words and numbers to support your answer.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Median is the better way to represent the data.<\/p>\n<p>Explanation:<br \/>\n44.5 is closer and represents the more number of observations compared to the mean.<\/p>\n<h3><a id=\"Choose_Appropriate_Measures_of_Center_and_Variability_Page_No_737\"><\/a>Choose Appropriate Measures of Center and Variability &#8211; Page No. 737<\/h3>\n<p>Question 1.<br \/>\nThe distances, in miles, that 6 people travel to get to work are 14, 12, 2, 16, 16, and 18. Decide which measure(s) of center best describes the data set. Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean= 13 miles Median= 15 miles Mode= 16 miles<\/p>\n<p>Explanation:<br \/>\nMean is less than the data points.<br \/>\nMedian describes the data in the best way compared to mean and mode.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169702\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-737-Q2.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 737 Q2\" width=\"695\" height=\"677\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-737-Q2.png 695w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-737-Q2-300x292.png 300w\" sizes=\"(max-width: 695px) 100vw, 695px\" \/><\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 3.<br \/>\nBrett\u2019s history quiz scores are 84, 78, 92, 90, 85, 91, and 0. Decide which measure(s) of center best describes the data set. Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean is the best measure of centre to describe the data set.<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean= 84+78+92+90+85+91+0\/7 = 74.2<br \/>\nMedian:<br \/>\nAscending order: 0,78,84,85,90,91,92<br \/>\nMedian = 4th observation = 85<\/p>\n<p>Question 4.<br \/>\nEight students were absent the following number of days in a year: 4, 8, 0, 1, 7, 2, 6, and 3. Decide if the range or interquartile range better describes the data set, and explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 8 represents all the terms range is more preferable compared to the interquartile range.<\/p>\n<p>Explanation:<br \/>\nAscending order: 0,1,2,3,4,6,7,8<br \/>\nRange = 8-0 = 8<br \/>\nMedian = Mean of 3 and 4 = 3+4\/2 = 7\/2 = 3.5<br \/>\nMedian of first 3 terms = 1<br \/>\nMedian of last 3 terms = 7<br \/>\nInterquartile range = 7-1 = 6<br \/>\nSince 8 represents all the terms range is more preferable compared to the interquartile range.<\/p>\n<p>Question 5.<br \/>\nCreate two sets of data that would be best described by two different measures of centre.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The given below are the examples of two sets of data that would be best described by two different measures of centre.<\/p>\n<p>Explanation:<br \/>\nExample 1:<\/p>\n<p>The numbers of pets that several children have are 2, 1, 2, 3, 4, 3, 10, 0, 1, and 0. Make a box plot of the data and find the range and interquartile range. Decide which measure better describes the data set and explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range = 10-0 = 10<br \/>\nInterquartile range = 3.5 &#8211; 0.5 = 3<br \/>\nThe interquartile range is the best way to represent the data.<\/p>\n<p>Explanation:<br \/>\nAscending order: 0,0,1,1,2,2,3,3,4,10<br \/>\nMedian = 2+2\/2 = 2<br \/>\nLower quartile = 0.5<br \/>\nUpper quartile= 7\/2 = 3.5<br \/>\nHighest observation= 10<br \/>\nLowest observation = 0<br \/>\nRange = 10-0 = 10<br \/>\nInterquartile range = 3.5 &#8211; 0.5 = 3<br \/>\nThe interquartile range is the best way to represent the data.<\/p>\n<p>Example 2:<\/p>\n<p>Brett\u2019s history quiz scores are 5,6,7,8,9,10. Decide which measure(s) of centre best describes the data set. Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean and median are the best measure of centre to describe the data set.<\/p>\n<p>Explanation:<br \/>\nMean:<br \/>\nMean= 5+6+7+8+9+10\/6 = 7.5<br \/>\nMedian:<br \/>\nAscending order: 5,6,7,8,9,10<br \/>\nMedian = Mean of 7 and 8 = 15\/2 = 7.5<\/p>\n<h3><a id=\"Lesson_Check_Page_No_738\"><\/a>Lesson Check &#8211; Page No. 738<\/h3>\n<p>Question 1.<br \/>\nChloe used two box plots to display some data. The box in the plot for the first data set is wider than the box for the second data set. What does this say about the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The graphs say that the interquartile range is more for the second graph compared to the first.<\/p>\n<p>Explanation:<br \/>\nThe interquartile range is the difference between the lower and upper quartiles.<br \/>\nIt is more for wider data compared to the compact data.<\/p>\n<p>Question 2.<br \/>\nHector recorded the temperature at noon for 7 days in a row. The temperatures are 20\u00b0F, 20\u00b0F, 20\u00b0F, 23\u00b0F, 23\u00b0F, 23\u00b0F, and 55\u00b0F. Which measure of center would best describe the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mode<\/p>\n<p>Explanation:<br \/>\nThe most frequently occurring observation is known as a mode.<br \/>\nThe mode of the above data describes the data well, the mode of the data is 20\u00b0F<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169703\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-738-Q3.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 738 Q3\" width=\"661\" height=\"355\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-738-Q3.png 661w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-738-Q3-300x161.png 300w\" sizes=\"(max-width: 661px) 100vw, 661px\" \/><\/p>\n<p>Question 4.<br \/>\nWhat percent of the people surveyed spent at least an hour watching television?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-35.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 35\" width=\"425\" height=\"336\" \/><br \/>\n_______ %<\/p>\n<p>Answer: 8 people<\/p>\n<p>Explanation:<br \/>\nTotal number of people= 40<br \/>\nPercentage = 8\/40 x 100 = 20%<\/p>\n<p>Question 5.<br \/>\nWhat is the lower quartile of the following data?<br \/>\n12, 9, 10, 8, 7, 12<br \/>\nThe lower quartile is _______ .<\/p>\n<p>Answer:<\/p>\n<p>Explanation:<br \/>\nAscending order: 7,8,9,10,12,12<br \/>\nMedian = 9+10\/2 = 9.5<br \/>\nLower quartile = 8<\/p>\n<p>Question 6.<br \/>\nWhat is the interquartile range of the data shown in the box plot?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-36.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 36\" width=\"395\" height=\"119\" \/><br \/>\nThe interquartile range is _______ .<\/p>\n<p>Answer: 5<\/p>\n<p>Explanation:<br \/>\nThe difference between the upper and lower quartiles is called as interquartile range.<br \/>\nInterquartile range = 14 &#8211; 9 = 5<\/p>\n<h3><a id=\"Share_and_Show_Page_No_741\"><\/a>Share and Show &#8211; Page No. 741<\/h3>\n<p>Question 1.<br \/>\nZoe collected data on the number of points her favourite basketball players scored in several games. Use the information in the table to compare the data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-37.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 37\" width=\"237\" height=\"142\" \/><br \/>\nThe mean of Player 1\u2019s points is __ the mean of Player 2\u2019s<br \/>\npoints.<br \/>\nThe interquartile range of Player 1\u2019s points is __ the<br \/>\ninterquartile range of Player 2\u2019s points.<br \/>\nSo, Player 2 typically scores __ points than Player 1, but<br \/>\nPlayer 2\u2019s scores typically vary __ Player 1\u2019s scores<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: less than ; less than ; more ; more<\/p>\n<p>Explanation:<br \/>\nThe mean of Player 1\u2019s points is less than the mean of Player 2\u2019s points.<br \/>\nThe interquartile range of Player 1\u2019s points is less than the interquartile range of Player 2\u2019s points.<br \/>\nSo, Player 2 typically scores more points than Player 1, but Player 2\u2019s scores typically vary in more Player 1\u2019s scores<\/p>\n<p>Question 2.<br \/>\nMark collected data on the weights of puppies at two animal shelters. Find the median and range of each data set, and use these measures to compare the data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-38.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 38\" width=\"187\" height=\"125\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: They differ slightly but on average we can say that shelter B is more as compared to shelter A<\/p>\n<p>Explanation:<br \/>\nShelter A<br \/>\nMedian:<br \/>\nAscending order: 5,7,7,7,10,12,15<br \/>\nMedian = 4th observation = 7<br \/>\nRange = 15-5 = 10<br \/>\nShelter B<br \/>\nMedian:<br \/>\nAscending order: 4,5,5,11,11,13,15<br \/>\nMedian = 4th observation = 11<br \/>\nRange = 15-4 = 11<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Kwan analyzed data about the number of hours musicians in her band practice each week. The table shows her results. Use the table for Exercises 3\u20135.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-39.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 39\" width=\"273\" height=\"193\" \/><\/p>\n<p>Question 3.<br \/>\nWhich two students typically practised the same amount each week, with about the same variation in practice times?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Sally and Jennifer<\/p>\n<p>Explanation:<br \/>\nThey are slightly different but on a whole, the average shows no difference and we can say that Sally and Jennifer practised for the same amount each week<\/p>\n<p>Question 4.<br \/>\nWhich two students typically practised the same number of hours, but had very different variations in their practice times?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Tim and Sally<\/p>\n<p>Explanation:<br \/>\nThey are different in range but on a whole, the average shows no difference and we can say that Sally and Tim practised for the same number of hours, but had very different variations in their practice times.<\/p>\n<p>Question 5.<br \/>\nWhich two students had the same variation in practice times, but typically practised a different number of hours per week?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Matthew and Tim<\/p>\n<p>Explanation:<br \/>\nMatthew and Tim practised for the same number of hours but they had a high variation in the range.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_742\"><\/a>Problem Solving + Applications &#8211; Page No. 742<\/h3>\n<p>Question 6.<br \/>\nCompare The table shows the number of miles Johnny ran each day for two weeks. Find the median and the interquartile range of each data set, and use these measures to compare the data sets.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-40.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 40\" width=\"185\" height=\"126\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Interquartile range is the best way to compare the data in the week 1<br \/>\nWhile the median is the best way to compare the data in the week 2<\/p>\n<p>Explanation:<br \/>\nWeek 1<br \/>\nMedian:<br \/>\nAscending order: 1,2,2,3,3,4,5<br \/>\nMedian = 4th observation = 3<br \/>\nLower quartile range= 2<br \/>\nUpper quartile range= 4<br \/>\nInterquartile range = 4-2 = 2<\/p>\n<p>Week 2<br \/>\nMedian:<br \/>\nAscending order: 1,1,1,3,3,8,8<br \/>\nMedian = 4th observation = 3<br \/>\nLower quartile range= 1<br \/>\nUpper quartile range= 8<br \/>\nInterquartile range = 8-1 = 7<\/p>\n<p>Question 7.<br \/>\nSense or Nonsense? Yashi made the box plots at right to show the data he collected on plant growth. He thinks that the variation in bean plant growth was about the same as the variation in tomato plant growth. Does Yashi\u2019s conclusion make sense? Why or why not?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-41.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 41\" width=\"397\" height=\"281\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Sense<\/p>\n<p>Explanation:<br \/>\nYashi said that thinks that the variation in bean plant growth was about the same as the variation in tomato plant growth.<br \/>\nIt is a true statement because the range of both bean and tomato plants growth is the same and they have the same medians.<\/p>\n<p>Question 8.<br \/>\nKylie\u2019s teacher collected data on the heights of boys and girls in a sixth-grade class. Use the information in the table to compare the data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-42.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 42\" width=\"339\" height=\"85\" \/><br \/>\nThe mean of the boys\u2019 heights is _____ the mean of the girls\u2019 heights.<br \/>\nThe range of the boys\u2019 heights is _____ the range of the girls\u2019 heights.<\/p>\n<p>Answer: more than ; more than<\/p>\n<p>Explanation:<br \/>\nMean of boys height:<br \/>\nMean = 72+68+70+56+58+62+64\/7 = 64.2<br \/>\nRange= 72-56 = 16<\/p>\n<p>Mean of girls height:<br \/>\nMean = 55+60+56+51+60+63+65\/7 = 58.5<br \/>\nRange= 65-51 = 14<br \/>\nThe mean of the boys\u2019 heights is _more than____ the mean of the girls\u2019 heights.<br \/>\nThe range of the boys\u2019 heights is _more than____ the range of the girls\u2019 heights.<\/p>\n<h3><a id=\"Apply_Measures_of_Center_and_Variability_Page_No_743\"><\/a>Apply Measures of Center and Variability &#8211; Page No. 743<\/h3>\n<p><strong>Solve.<\/strong><\/p>\n<p>Question 1.<br \/>\nThe table shows temperature data for two cities. Use the information in the table to compare the data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-43.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 43\" width=\"328\" height=\"139\" \/><br \/>\nThe mean of City 1\u2019s temperatures is the &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211; mean of City 2\u2019s temperatures.<br \/>\nThe &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;- of City 1\u2019s temperatures is&#8212;&#8212;&#8212;&#8212;&#8212; the &#8212;&#8212;&#8212;&#8212;&#8212;&#8211;of City 2\u2019s temperatures.<br \/>\nSo, City 2 is typically &#8212;&#8212;&#8212;&#8212;&#8212;-City 1, but City 2\u2019s temperatures<br \/>\nvary &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-City 1\u2019s temperatures.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: less than; interquartile range; less than; interquartile range; warmer than; more than<\/p>\n<p>Explanation:<br \/>\nThe mean of City 1\u2019s temperatures is the &#8212;-less than&#8212;&#8212;&#8212;- mean of City 2\u2019s temperatures.<br \/>\nThe &#8211;interquartile range&#8212;&#8212;&#8212; of City 1\u2019s temperatures is&#8212;less than&#8212;&#8211; the &#8212;-interquartile range&#8212;&#8211;of City 2\u2019s temperatures.<br \/>\nSo, City 2 is typically &#8212;warmer than&#8212;&#8211;City 1, but City 2\u2019s temperatures<br \/>\nvary &#8212;&#8211;more than&#8212;&#8212;-City 1\u2019s temperatures.<\/p>\n<p>Question 2.<br \/>\nThe table shows weights of fish that were caught in two different lakes. Find the median and range of each data set, and use these measures to compare the data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-44.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 44\" width=\"327\" height=\"87\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Lake A&#8217;s average is greater but varies more.<\/p>\n<p>Explanation:<br \/>\nLake A<br \/>\nMedian:<br \/>\nAscending order: 4,6,7,9,10,12<br \/>\nMedian = Mean 3rd and 4th observation = 7+9\/2 = 8<br \/>\nRange = 12 &#8211; 4 = 8<\/p>\n<p>Lake B<br \/>\nMedian:<br \/>\nAscending order: 4,4,5,6,6,7<br \/>\nMedian = Mean 3rd and 4th observation = 5+6\/2 = 5.5<br \/>\nRange = 7 &#8211; 3 = 4<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 3.<br \/>\nMrs. Mack measured the heights of her students in two classes. Class 1 has a median height of 130 cm and an interquartile range of 5 cm. Class 2 has a median height of 134 cm and an interquartile range of 8 cm. Write a statement that compares the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Class 2 is greater but varies more.<\/p>\n<p>Explanation:<br \/>\nThe interquartile range is the difference between the lower and upper quartiles. Since the interquartile range is more for class 2 we can say that the extremes are greater while the interquartile range is less for class 1 which means that the data is compact.<\/p>\n<p>Question 4.<br \/>\nRichard\u2019s science test scores are 76, 80, 78, 84, and 80. His math test scores are 100, 80, 73, 94, and 71. Compare the medians and interquartile ranges.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Medians are equal but the interquartile range varies a large, math test scores are more spread out compared to science test scores.<\/p>\n<p>Explanation:<br \/>\nScience test scores:<br \/>\nMedian:<br \/>\nAscending order: 76,78,80,80,84<br \/>\nMedian = 3rd observation = 80<br \/>\nInterquartile range = 84 &#8211; 76 = 10<\/p>\n<p>Math test scores:<br \/>\nMedian:<br \/>\nAscending order: 71,73,80,94,100<br \/>\nMedian = 3rd observation = 80<br \/>\nInterquartile range = 100 &#8211; 71 = 29<\/p>\n<p>Medians are equal but the interquartile range varies a large, math test scores are more spread out compared to science test scores.<\/p>\n<p>Question 5.<br \/>\nWrite a short paragraph to a new student that explains how you can compare data sets by examining the mean and the interquartile range.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: average and consistency<\/p>\n<p>Explanation:<br \/>\nIf the mean is more it means that the data has more observations or observations with more value.<br \/>\nInterquartile range and median range say about the consistency.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_744\"><\/a>Lesson Check &#8211; Page No. 744<\/h3>\n<p>Question 1.<br \/>\nTeam A has a mean of 35 points and a range of 8 points. Team B has a mean of 30 points and a range of 7 points. Write a statement that compares the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Similar variation but team A average is more than team B<\/p>\n<p>Explanation:<br \/>\nThe range has only a difference of 1 point which can be said as a slight variation but while the average\/ mean has a large variation.<\/p>\n<p>Question 2.<br \/>\nJean\u2019s test scores have a mean of 83 and an interquartile range of 4. Ben\u2019s test scores have a mean of 87 and an interquartile range of 9. Compare the students\u2019 scores.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Ben&#8217;s average is more than Jean&#8217;s but Ben is less consistent compared to Jean.<\/p>\n<p>Explanation:<br \/>\nBen&#8217;s average score is more than the average scores of Jean while the interquartile range<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nLook at the box plots below. What is the difference between the medians for the two groups of data?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-45.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 45\" width=\"408\" height=\"385\" \/><br \/>\n_______ students<\/p>\n<p>Answer: 2 students<\/p>\n<p>Explanation:<br \/>\nMedian of students in a class of school A = 24<br \/>\nMedian of students in a class of school B = 26<br \/>\nDifference between the medians of the schools = 26-24 = 2 students<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169704\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-744-Q4.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 744 Q4\" width=\"672\" height=\"410\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-744-Q4.png 672w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-744-Q4-300x183.png 300w\" sizes=\"(max-width: 672px) 100vw, 672px\" \/><\/p>\n<p>Question 5.<br \/>\nWhich two teams typically practice the same number of hours, but have very different variations in their practice times?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-46.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 46\" width=\"410\" height=\"172\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Team A and C<\/p>\n<p>Explanation:<br \/>\nTeam A and C have medians which are only slightly different but the consistency varies a lot that is range.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_747\"><\/a>Share and Show &#8211; Page No. 747<\/h3>\n<p><strong>Connie asked people their ages as they entered the food court at the mall. Use the histogram of the data she collected for 1\u20135.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-47.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 47\" width=\"489\" height=\"266\" \/><\/p>\n<p>Question 1.<br \/>\nWhat statistical question could Connie ask about her data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean, Median, Mode<\/p>\n<p>Explanation:<br \/>\nThe graph shows the age and number of people. The questions which can be asked can be of mean, median, mode.<\/p>\n<p>Question 2.<br \/>\nDescribe any peak or gap in the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Peak : 21-30\u00a0 \u00a0Gap : 61-70<\/p>\n<p>Explanation:<br \/>\nThere is a peak in the graph at the interval 21-30<br \/>\nThere is a gap in between the bars of the histogram the bar which had a gap before it was 61-70<\/p>\n<p>Question 3.<br \/>\nDoes the graph have symmetry? Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: No the graph doesn&#8217;t have symmetry<\/p>\n<p>Explanation:<br \/>\nThe symmetry of the graph means there must be equal parts of the graph on both the sides of the line of the graph.<br \/>\nThis is not possible in the above situation.<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p>Question 4.<br \/>\nThe lower quartile of the data set is 16.5 years, and the upper quartile is 51.5 years. Find the interquartile range. Is it a better description of the data than the range? Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Interquartile range = 35; The interquartile range is better than the range.<\/p>\n<p>Explanation:<br \/>\nThe interquartile range is the difference between the upper quartile and the lower quartile.<br \/>\nInterquartile range = 51.5-16.5 = 35<br \/>\nThe interquartile range is better than the range because if we take the example of the above graph we can see thatthe most of the data fall in the range of the interquartile range ie. 35.<br \/>\nTherefore we can say that the interquartile range is better than the range.<\/p>\n<p>Question 5.<br \/>\nMake Arguments The mode of the data is 16 years old. Is the mode a good description of the center of the data? Explain<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: No mode is not a good description of the data.<\/p>\n<p>Explanation:<br \/>\nThe mode is just a frequently occurring observation.<br \/>\nIt cannot be the best way to describe the data.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_748\"><\/a>Problem Solving + Applications &#8211; Page No. 748<\/h3>\n<p><strong>Use the dot plot for 6\u20138.<\/strong><\/p>\n<p>Question 6.<br \/>\nMake Arguments Jason collected data about the number of songs his classmates bought online over the past 3 weeks. Does the data set have symmetry? Why or why not?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-48.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 48\" width=\"384\" height=\"191\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: No, the data has no symmetry.<\/p>\n<p>Explanation:<br \/>\nNo, the data has no symmetry. Because there are gaps between the dots drawn.<\/p>\n<p>Question 7.<br \/>\nJason claims that the median is a good description of his data set, but the mode is not. Does his statement make sense? Explain.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Median can be a better centre of description. Therefore his statement makes a sense.<\/p>\n<p>Explanation:<br \/>\nMedian = 7+8\/2 = 15\/2 = 7.5<br \/>\nThe number 7.5 represents more number of observations.<\/p>\n<p>Question 8.<br \/>\nTrinni surveyed her classmates about how many siblings they have. A dot plot of her data increases from 0 siblings to a peak at 1 sibling and then decreases steadily as the graph goes to 6 siblings. How is Trinni\u2019s dot plot similar to Jason\u2019s? How is it different?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Trinni graph represents a part of Jason&#8217;s graph<\/p>\n<p>Explanation:<br \/>\nIn Jason&#8217;s graph, there is a peak in the middle and then it decreases on both sides.<br \/>\nBut according to Trinni graph, there is no peak in the middle.<\/p>\n<p>Question 9.<br \/>\nDiego collected data on the number of movies seen last month by a random group of students.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-49.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 49\" width=\"520\" height=\"49\" \/><br \/>\nDraw a box plot of the data and use it to find the interquartile range and range.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range = 12\u00a0 Interquartile range = 2<\/p>\n<p>Explanation:<br \/>\nThe range is the difference between the highest and lowest observations.<br \/>\nRange = 12-0 = 12<br \/>\nThe interquartile range is the difference between the upper and lower quartiles.<br \/>\nAscending order: 0,0,1,1,2,2,2,2,3,3,3,5,12<br \/>\nLower quartile = 1+1\/2 = 2\/2 = 1<br \/>\nUpper quartile = 3+3\/2 = 6\/2 = 3<br \/>\nInterquartile range = 3-1 = 2<\/p>\n<h3><a id=\"Describe_Distributions_Page_No_749\"><\/a>Describe Distributions &#8211; Page No. 749<\/h3>\n<p><strong>Chase asked people how many songs they have bought online in the past month. Use the histogram of the data he collected for 1\u20134.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-50.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 50\" width=\"377\" height=\"305\" \/><\/p>\n<p>Question 1.<br \/>\nWhat statistical question could Chase ask about the data?<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: What is the median number of songs purchased?<\/p>\n<p>Explanation:<br \/>\nMany questions can be formed from the data given to us<br \/>\nWe can ask about the mean, median, mode.<\/p>\n<p>Question 2.<br \/>\nDescribe any peaks in the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Peak : 0-4<\/p>\n<p>Explanation:<br \/>\nThe peak is a bar in the histogram which has the highest value. The peak of the given graph is 0-4<\/p>\n<p>Question 3.<br \/>\nDescribe any gaps in the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: There are no gaps in the graph.<\/p>\n<p>Explanation:<br \/>\nThe gap is something between a bar of the histogram and all the other adjacent bars.<br \/>\nThere no such case in the graph. Therefore there are no gaps in the graph.<\/p>\n<p>Question 4.<br \/>\nDoes the graph have symmetry? Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: No the graph doesn&#8217;t have symmetry<\/p>\n<p>Explanation:<br \/>\nThe symmetry of the graph means there must be equal parts of the graph on both the sides of the line of the graph.<br \/>\nThis is not possible in the above situation.<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nMr. Carpenter teaches five classes each day. For several days in a row, he kept track of the number of students who were late to class and displayed the results in a dot plot. Describe the data.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-51.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 51\" width=\"294\" height=\"188\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Peaks: At 6 and 8<br \/>\nGaps: Between 3 and 5 , 6 and 8<br \/>\nClusters: Between 0-3 ; 9-11<\/p>\n<p>Explanation:<br \/>\nThe highest points in the graph are known as peaks.<br \/>\nThey are at 6 and 8 in this graph.<br \/>\nThe space between the dots in the dot plot graph is known as gaps.<br \/>\nGaps are between 3 and 5; 6 and 8<br \/>\nThe group of the dots in the dot plot are known as clusters.<br \/>\nThe clusters are at the 0-3; 9-11<\/p>\n<p>Question 6.<br \/>\nDescribe how a graph of a data set can be used to understand the distribution of the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean, median, mode<\/p>\n<p>Explanation:<br \/>\nThere are three measures of centre which can be used to describe the data given in the form of a graph.<br \/>\nThe three measures of centre are mean, median, mode.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_750\"><\/a>Lesson Check &#8211; Page No. 750<\/h3>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169705\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-750-Q1.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 750 Q1\" width=\"655\" height=\"523\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-750-Q1.png 655w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-750-Q1-300x240.png 300w\" sizes=\"(max-width: 655px) 100vw, 655px\" \/><\/p>\n<p>Question 2.<br \/>\nWhat is the median in the dot plot?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-52.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 52\" width=\"274\" height=\"180\" \/><br \/>\n$ ________<\/p>\n<p>Answer: 11<\/p>\n<p>Explanation:<br \/>\nMedian is the middlemost value and it is 11 in the above graph.<br \/>\nWe need to consider the middle value by neglecting the same number on both the sides.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nLook at the dot plot. Where does a gap occur in the data?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-53.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 53\" width=\"292\" height=\"175\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 30-33<\/p>\n<p>Explanation:<br \/>\nThe gap is a space between the intervals.<br \/>\nThe intervals are 30-33.<\/p>\n<p>Question 4.<br \/>\nLook at the dot plot. Where does a peak occur in the data?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-54.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 54\" width=\"292\" height=\"175\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 37<\/p>\n<p>Explanation:<br \/>\nThe highest point in the graph is known as the peak.<br \/>\nThe peak in the dot plot is 37.<\/p>\n<p>Question 5.<br \/>\nWhich two teams had similar variations in points earned, but typically earned a different number of points per game?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-55.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 55\" width=\"348\" height=\"146\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Red and blue<\/p>\n<p>Explanation:<br \/>\nThe difference between the upper and lowest observations is called a range.<br \/>\nThe range (consistency) in the data given is the same but they vary in the mean.<br \/>\nBut we can say that the Red and Blue teams typically earned a different number of points per game.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169706\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-750-Q6.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 750 Q6\" width=\"699\" height=\"462\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-750-Q6.png 699w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-750-Q6-300x198.png 300w\" sizes=\"(max-width: 699px) 100vw, 699px\" \/><\/p>\n<h3><a id=\"Share_and_Show_Page_No_753\"><\/a>Share and Show &#8211; Page No. 753<\/h3>\n<p>Question 1.<br \/>\nJosh is playing a game at the carnival. If his arrow lands on a section marked 25 or higher, he gets a prize. Josh will only play if most of the players win a prize. The carnival worker says that the average (mean) score is 28. The box plot shows other statistics about the game. Should Josh play the game? Explain your reasoning.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-56.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 56\" width=\"356\" height=\"138\" \/><br \/>\nFirst, look at the median. The median is _ points.<br \/>\nNext, work backwards from the statistics.<br \/>\nThe median is the __ value of the data.<br \/>\nSo, at least __ of the values are scores<br \/>\nless than or equal to _.<br \/>\nFinally, use the statistics to draw a conclusion.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: middlemost value; 20; 15<\/p>\n<p>Explanation:<br \/>\nFirst, look at the median. The median is 20 points.<br \/>\nNext, work backwards from the statistics.<br \/>\nThe median is the middlemost value of the data.<br \/>\nSo, at least 20 of the values are scores<br \/>\nless than or equal to 15.<br \/>\nFinally, use the statistics to draw a conclusion.<\/p>\n<p>Question 2.<br \/>\nWhat if a score of 15 or greater resulted in a prize? How would that affect Josh\u2019s decision? Explain.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: It doesn&#8217;t affect his decision.<\/p>\n<p>Explanation:<br \/>\nJosh wanted to play only when most of the prizes were awarded.<br \/>\nTherefore if the minimum score was 15 or greater than it then they would get the prize. So there will be no difference in his decision.<\/p>\n<p>Question 3.<br \/>\nA store collects data on the sales of DVD players each week for 3 months. The manager determines that the data has a range of 62 players and decides that the weekly sales were very inconsistent. Use the statistics in the table to decide if the manager is correct. Explain your answer.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-57.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 57\" width=\"190\" height=\"157\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: No the manager is not correct.<\/p>\n<p>Explanation:<br \/>\nThe range is given to be 62.<br \/>\nThe range is correct when we check it with the help of the given data, therefore, the data is not inconsistent.<\/p>\n<h3><a id=\"On_Your_Own_Page_No_754\"><\/a>On Your Own &#8211; Page No. 754<\/h3>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169707\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-754-Q4.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 754 Q4\" width=\"682\" height=\"559\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-754-Q4.png 682w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-754-Q4-300x246.png 300w\" sizes=\"(max-width: 682px) 100vw, 682px\" \/><\/p>\n<p>Question 5.<br \/>\nSusanna wants to buy a fish that grows to be about 4 in. long. Mark suggests she buys the same type of fish he has. He has five of these fish with lengths of 1 in., 1 in., 6 in., 6 in., and 6 in., with a mean length of 4 in. Should Susanna buy the type of fish that Mark suggests? Explain.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Yes Susanna buy the type of fish that Mark suggests<\/p>\n<p>Explanation:<br \/>\nThe length of fish suggested by Mark is 4 in. long.<br \/>\nMark has 5 fish with a mean length of 4 in.<br \/>\nTo buy a fish that grows to be about 4 in. long. Susanna should buy the fish suggested by Mark.<\/p>\n<p>Question 6.<br \/>\nLook for a Pattern The graph shows the number of stamps that Luciano collected over several weeks. If the pattern continues, how many stamps will Luciano collect in Week 8? Explain.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-58.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 58\" width=\"479\" height=\"304\" \/><br \/>\n_______ stamps<\/p>\n<p>Answer: 7 stamps<\/p>\n<p>Explanation:<br \/>\nIn week 4 and 6, the number of stamps are 4, 5. Therefore in week 6 and 8, the number of stamps are 5, 7<\/p>\n<p>Question 7.<br \/>\nThe data set shows the number of hours Luke plays the piano each week. Luke says he usually plays the piano 3 hours per week. Why is Luke\u2019s statement misleading?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-59.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 59\" width=\"287\" height=\"72\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: According to the question he should spend 3 hours per week. His statement is correct.<\/p>\n<p>Explanation:<br \/>\nSum of the data = 1+2+1+3+2+10+2 = 21<br \/>\nNumber of days in a week = 7<br \/>\nMean = 21\/7 = 3 hours<\/p>\n<h3><a id=\"Problem_Solving_Misleading_Statistics_Page_No_755\"><\/a>Problem Solving Misleading Statistics &#8211; Page No. 755<\/h3>\n<p><strong>Mr Jackson wants to make dinner reservations at a restaurant that has most meals costing less than $16. The Waterside Inn advertises that they have meals that average $15. The table shows the menu items.<\/strong><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-60.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 60\" width=\"353\" height=\"224\" \/><\/p>\n<p>Question 1.<br \/>\nWhat is the minimum price and the maximum price?<br \/>\nminimum: $ _________<br \/>\nmaximum: $ _________<\/p>\n<p>Answer: minimum: $6<br \/>\nmaximum: $19<\/p>\n<p>Explanation:<br \/>\nThe minimum value is the most minimum price in the given data.<br \/>\nThe maximum value is the most maximum price in the given data.<\/p>\n<p>Question 2.<br \/>\nWhat is the mean of the prices?<br \/>\n$ ________<\/p>\n<p>Answer: $15<\/p>\n<p>Explanation:<br \/>\nMean = sum of all the observations\/ total number of observations = 6+16+18+16+18+19\/6 = 93\/6 = 15.2<br \/>\nApproximately therefore the mean of the observations is $15<\/p>\n<p>Question 3.<br \/>\nConstruct a box plot for the data.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The box plot is a diagram which signifies the information about the data.<\/p>\n<p>Explanation:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7508\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/JBF-300x89.png\" alt=\"\" width=\"300\" height=\"89\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/JBF-300x89.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/JBF.png 589w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nThe box plot represents the range, lower and upper quartiles.<\/p>\n<p>Question 4.<br \/>\nWhat is the range of the prices?<br \/>\n$ ________<\/p>\n<p>Answer: the range is $13<\/p>\n<p>Explanation:<br \/>\nThe difference between the upper and lower observations is known as the range.<br \/>\nRange = 19-6 = $13<\/p>\n<p>Question 5.<br \/>\nWhat is the interquartile range of the prices?<br \/>\n$ ________<\/p>\n<p>Answer: $7.5<\/p>\n<p>Explanation:<br \/>\nAscending order: $6, $16, $16, $18, $18, $19<br \/>\nMedian = 16+18\/2 = 34\/2 = 17<br \/>\nLower quartile = 6+16\/2 = 11<br \/>\nUpper quartile = 18+19\/2 = 18.5<br \/>\nInterquartile range = 18.5-11 = 7.5<\/p>\n<p>Question 6.<br \/>\nDoes the menu match Mr. Jackson\u2019s requirements? Explain your reasoning.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Yes the menu matches Mr Jackson&#8217;s requirements.<\/p>\n<p>Explanation:<br \/>\nMr Jackson wants to make dinner arrangements with cost less than $16.<br \/>\nThe mean of the items in the menu:<br \/>\nMean = $6+$16+$16+$18+$18+$19\/6 = 93\/6 = $15.5<br \/>\nTherefore the requirements of Mr Jackson is satisfied.<\/p>\n<p>Question 7.<br \/>\nGive an example of a misleading statistic. Explain why it is misleading.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: The Waterside Inn advertises a misleading statement.<\/p>\n<p>Explanation:<br \/>\nAccording to the information given in the question, The Waterside Inn advertises that they have meals that average $15. But it is more than that, so this is a misleading statement.<br \/>\nThe mean of the items on the menu:<br \/>\nMean = $6+$16+$16+$18+$18+$19\/6 = 93\/6 = $15.5<br \/>\nTherefore the requirements of Mr. Jackson are satisfied.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_756\"><\/a>Lesson Check &#8211; Page No. 756<\/h3>\n<p>Question 1.<br \/>\nMary\u2019s science test scores are 66, 94, 73, 81, 70, 84, and 88. What is the range of Mary\u2019s science test scores?<br \/>\n________<\/p>\n<p>Answer: 28<\/p>\n<p>Explanation:<br \/>\nThe difference between the highest and the lowest observations is called a range.<br \/>\nRange = 94 &#8211; 66 = 28<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169708\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-756-Q2.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 756 Q2\" width=\"695\" height=\"417\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-756-Q2.png 695w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-756-Q2-300x180.png 300w\" sizes=\"(max-width: 695px) 100vw, 695px\" \/><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-169709\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-756-Q3.png\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions Page 756 Q3\" width=\"671\" height=\"470\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-756-Q3.png 671w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-Page-756-Q3-300x210.png 300w\" sizes=\"(max-width: 671px) 100vw, 671px\" \/><\/p>\n<p>Question 4.<br \/>\nLook at the box plot. What is the interquartile range of the data?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-61.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 61\" width=\"398\" height=\"113\" \/><br \/>\n________<\/p>\n<p>Answer: Interquartile range = 6<\/p>\n<p>Explanation:<br \/>\nThe difference between the lower and upper quartiles is known as the interquartile range.<br \/>\nInterquartile range = 50 &#8211; 44 = 6<\/p>\n<p>Question 5.<br \/>\nErin is on the school trivia team. The table shows the team\u2019s scores in the last 8 games. Erin wants to build confidence in her team so that they will do well in the last game. If a score of 20 is considered a good score, what measure of center would be best for Erin to use to motivate her teammates?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-62.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 62\" width=\"408\" height=\"283\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean and median are the best centre of tendencies to compare the data.<\/p>\n<p>Explanation:<br \/>\nMean = 20+20+18+19+23+40+22+19\/8 = 181\/8 = 22.6<br \/>\nMedian:<br \/>\nAscending order: 18,19,19,20,20,22,23,40<br \/>\nMedian = 40\/2 = 20<\/p>\n<h3><a id=\"Chapter_13_Review_Test_Page_No_757\"><\/a>Chapter 13 Review\/Test &#8211; Page No. 757<\/h3>\n<p>Question 1.<br \/>\nThe dot plot shows the number of chin-ups done by a gym class.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-63.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 63\" width=\"521\" height=\"137\" \/><br \/>\nFor numbers 1a\u20131e, choose Yes or No to indicate whether the statement is correct.<br \/>\n1a. There are two peaks.<br \/>\n1b. There are no clusters.<br \/>\n1c. There is a gap from 6 to 8.<br \/>\n1d. The most chin-ups anyone did was 15.<br \/>\n1e. The modes are 3, 4, and 9.<br \/>\n1a. ____________<br \/>\n1b. ____________<br \/>\n1c. ____________<br \/>\n1d. ____________<br \/>\n1e. ____________<\/p>\n<p>Answer: 1a. Yes<br \/>\n1b. No<br \/>\n1c. Yes<br \/>\n1d. No<br \/>\n1e. Yes<\/p>\n<p>Explanation:<br \/>\n1a. The highest point in the dot plot is called the peak. The peak in the given dot plot is at 5 and 11 the value of the peak is 3<br \/>\n1b. The group of dots form a cluster with 3 or more intervals.<br \/>\n1c. There is a gap between the intervals 6-8<br \/>\n1d. The maximum number of people did 11 chin-ups while only a single person did 15 chin-ups.<br \/>\n1e. The most frequently occurring observation is known as mode.<br \/>\nThe mode of the given data is at the intervals 3,4 and 9.<\/p>\n<p>Question 2.<br \/>\nThe histogram shows the high temperatures in degrees Fahrenheit of various cities for one day in March.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-64.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 64\" width=\"409\" height=\"264\" \/><br \/>\nSelect the best word to complete each sentence.<br \/>\nThe histogram has _____ peak(s).<br \/>\nThe histogram _____ symmetry.<\/p>\n<p>Answer: The histogram has 1 peak(s).<br \/>\nThe histogram is symmetry.<\/p>\n<p>Explanation:<br \/>\nThe is one and only one peak at the interval 41 &#8211; 50<br \/>\nWe can say that the graph is symmetrical because if we draw a line between the graph we can observe that the graph has two parts symmetric to each other.<\/p>\n<h3><a id=\"Chapter_13_Review_Test_Page_No_758\"><\/a>Chapter 13 Review\/Test &#8211; Page No. 758<\/h3>\n<p>Question 3.<br \/>\nThe data set shows the scores of the players on the winning team of a basketball game.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-65.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 65\" width=\"620\" height=\"83\" \/><br \/>\nThe median is _____.<br \/>\nThe lower quartile is _____.<br \/>\nThe upper quartile is _____.<\/p>\n<p>Answer:Median = 6<br \/>\nLower quartile = 1<br \/>\nUpper quartile =19.5<\/p>\n<p>Explanation:<br \/>\nAscending order: 0,0,1,1,4,5,6,9,13,17,22,30,47<br \/>\nMedian = 6<br \/>\nLower quartile = Mean of 1 and 1 = 1+1\/2 = 2\/2 = 1<br \/>\nUpper quartile = Mean of 17 and 22 = 17+22\/2 = 39\/2 = 19.5<\/p>\n<p>Question 4.<br \/>\nThe data set shows the number of desks in 12 different classrooms.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-66.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 66\" width=\"573\" height=\"84\" \/><br \/>\nFind the values of the points on the box plot.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-67.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 67\" width=\"369\" height=\"97\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: A= 16 B=17 C= 20 D= 21 E=24<\/p>\n<p>Explanation:<br \/>\nAscending order: 16,17,17,18,19,20,20,21,21,21,22,24<br \/>\nMedian = 20+20\/2 = 20<br \/>\nLower quartile = 17<br \/>\nUpper quartile = 21<\/p>\n<p>Question 5.<br \/>\nThe box plot shows the number of boxes sold at an office supply store each day for a week.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-68.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 68\" width=\"424\" height=\"132\" \/><br \/>\nFor numbers 5a\u20135d, select True or False for each statement.<br \/>\n5a. The median is 18.<br \/>\n5b. The range is 15.<br \/>\n5c. The interquartile range is 9.<br \/>\n5d. The upper quartile is 18.<br \/>\n5a. ____________<br \/>\n5b. ____________<br \/>\n5c. ____________<br \/>\n5d. ____________<\/p>\n<p>Answer: 5a.\u00a0 false<br \/>\n5b. true<br \/>\n5c. true<br \/>\n5d. true<\/p>\n<p>Explanation:<br \/>\nMedian is the middlemost value of the given data.<br \/>\nMedian of the data is 14<br \/>\nThe range is the difference between the upper and lower observations.<br \/>\nRange = 21-6 = 15<br \/>\nThe interquartile range is the difference between the upper and lower observations.<br \/>\nUpper quartile range: 18<br \/>\nInterquartile range = 18-9 = 9<\/p>\n<h3><a id=\"Chapter_13_Review_Test_Page_No_759\"><\/a>Chapter 13 Review\/Test &#8211; Page No. 759<\/h3>\n<p>Question 6.<br \/>\nThe data set shows the number of glasses of water Dalia drinks each day for a week.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-69.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 69\" width=\"336\" height=\"83\" \/><br \/>\nPart A<br \/>\nWhat is the mean number of glasses of water Dalia drinks each day?<br \/>\n_______ glasses<\/p>\n<p>Answer: The mean number of glasses of water Dalia drinks each day is 8 glasses.<\/p>\n<p>Explanation:<br \/>\nMean = sum of all the observations\/ total number of observations= 6+7+9+9+8+7+10\/7 = 8<\/p>\n<p>Question 6.<br \/>\nPart B<br \/>\nWhat is the mean absolute deviation of the number of glasses of water Dalia drinks each day? Round your answer to the nearest tenth. Use words and numbers to support your answer.<br \/>\n_______<\/p>\n<p>Answer: Mean absolute deviation is 1.14<\/p>\n<p>Explanation:<\/p>\n<p>Mean:<br \/>\nMean = sum of all the observations\/ total number of observations= 6+7+9+9+8+7+10\/7 = 8<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n06: 8-6\u00a0 = 02<br \/>\n07: 8-7\u00a0 = 01<br \/>\n09: 8-9\u00a0 = -1<br \/>\n09: 8-9\u00a0 = -1<br \/>\n08: 8-8\u00a0 =\u00a0 0<br \/>\n07: 8-7\u00a0 = 01<br \/>\n10: 8-10= -2<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n2+1+1+1+0+1+2\/7<br \/>\n= 8\/7 = 1.14<\/p>\n<p>So, the mean absolute deviation of the data is 1.14<\/p>\n<p>Question 7.<br \/>\nThe numbers of emails Megan received each hour are 9, 10, 9, 8, 7, and 2. The mean of the data values is 7.5 and the median is 8.5. Which measure of center better describes the data, the mean or median? Use words and numbers to support your answer.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Mean is the best center of the tendency to represent the data given in the question<\/p>\n<p>Explanation:<br \/>\nAscending order of the data: 2,7,8,9,9,10<br \/>\nMean = 7.5<br \/>\nMean represents the observations 8,9,9,10 which come after 7.5<br \/>\nTherefore mean is the best way to represent the data.<\/p>\n<p>Question 8.<br \/>\nThe number of miles Madelyn drove between stops was 182, 180, 181, 184, 228, and 185. Which measure of center best describes the data?<br \/>\nOptions:<br \/>\na. mean<br \/>\nb. median<br \/>\nc. mode<\/p>\n<p>Answer: b. Median<\/p>\n<p>Explanation:<br \/>\nAscending order: 180,181,182,184,185,228<br \/>\nMedian = 182+184\/2 = 183<br \/>\n183 represents all the observations after 182<br \/>\nSo the median is the best way to represent the data.<\/p>\n<h3><a id=\"Chapter_13_Review_Test_Page_No_760\"><\/a>Chapter 13 Review\/Test &#8211; Page No. 760<\/h3>\n<p>Question 9.<br \/>\nThe histogram shows the weekly earnings of part-time workers. What interval(s) represents the most common weekly earnings?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-70.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 70\" width=\"506\" height=\"395\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: 321-330 ; 341-350<\/p>\n<p>Explanation:<br \/>\nThe histogram has 2 intervals which show equal heights which means that the monthly earnings of these intervals is the same.<\/p>\n<p>Question 10.<br \/>\nJordan surveyed a group of randomly selected smartphone users and asked them how many applications they have downloaded onto their phones. The dot plot shows the results of Jordan&#8217;s survey. Select the statements that describe patterns in the data. Mark all that apply.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-71.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 71\" width=\"350\" height=\"154\" \/><br \/>\nOptions:<br \/>\na. The modes are 37 and 42.<br \/>\nb. There is a gap from 38 to 40.<br \/>\nc. There is a cluster from 41 to 44.<br \/>\nd. There is a cluster from 35 to 36.<\/p>\n<p>Answer: b. There is a gap from 38 to 40.<\/p>\n<p>Explanation:<br \/>\nThe dot plot represents a gap between 38-40. So we can say that there is a gap between intervals 38 to 40.<\/p>\n<h3><a id=\"Chapter_13_Review_Test_Page_No_761\"><\/a>Chapter 13 Review\/Test &#8211; Page No. 761<\/h3>\n<p>Question 11.<br \/>\nMrs. Gutierrez made a histogram of the birth month of the students in her class. Describe the patterns in the histogram by completing the chart.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-72.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 72\" width=\"609\" height=\"365\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-73.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 73\" width=\"675\" height=\"241\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: There are 2 peaks, Yes there is an increase across the intervals, Yes there is a decrease across the intervals<\/p>\n<p>Explanation:<br \/>\nThe highest point in the histogram is called is as a peak.<br \/>\nThere is a peak near the month&#8217;s May and August.<\/p>\n<p>There is an increase between the bars in the bar graph.<br \/>\nAt the months February, March, November there is an increase in the graph.<\/p>\n<p>There is a decrease between the bars in the bar graph.<br \/>\nAt the months September, October, December.<\/p>\n<p>Question 12.<br \/>\nIan collected data on the number of children in 13 different families.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-74.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 74\" width=\"623\" height=\"83\" \/><br \/>\nDraw a box plot of the data and use it to find the interquartile range and range.<br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Range = 8-0 = 8 Interquartile range = 3-1 = 2<\/p>\n<p>Explanation:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7510\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/unnamed-file-300x88.png\" alt=\"\" width=\"300\" height=\"88\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/unnamed-file-300x88.png 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/unnamed-file.png 621w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nAscending order:<br \/>\n0,0,1,1,1,1,2,2,2,3,3,4,8<br \/>\nMedian = 2<br \/>\nLower quartile = 1+1\/2 = 1<br \/>\nUpper quartile = 3+3\/2 = 3<br \/>\nRange = 8-0 = 8<br \/>\nInterquartile range = 3-1 = 2<\/p>\n<h3><a id=\"Chapter_13_Review_Test_Page_No_762\"><\/a>Chapter 13 Review\/Test &#8211; Page No. 762<\/h3>\n<p>Question 13.<br \/>\nGavin wants to move to a county where it rains about 5 inches every month. The data set shows the monthly rainfall in inches for a county. The mean of the data is 5 and the median is 4.35. After analyzing the data, Gavin says that this county would be a good place to move. Do you agree or disagree with Gavin? Use words and numbers to support your answer.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-75.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 75\" width=\"576\" height=\"84\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: Yes I agree that it is a good place to move.<\/p>\n<p>Explanation:<br \/>\nAfter analyzing the data we can say that this country would be a good place to move for Gavin.<br \/>\nGavin wants to move to a place which has an average of 5 cm rainfall. So this country is the best choice because it has a mean equal to 5 and median equal to 4.35<\/p>\n<p>Question 14.<br \/>\nThe data set shows the number of books Peyton reads each month. Peyton says she usually reads 4 books per month. Why is Peyton&#8217;s statement misleading?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-76.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 76\" width=\"338\" height=\"84\" \/><br \/>\nType below:<br \/>\n_________________<\/p>\n<p>Answer: No Peyton&#8217;s statement is not misleading because the mean of the data is 4.<br \/>\nTherefore Peyton says she usually reads 4 books per month.<\/p>\n<p>Explanation:<br \/>\nMean = 2+3+2+4+3+11+3\/7 = 28\/7 = 4<\/p>\n<p>Question 15.<br \/>\nThe data set shows the scores of three players for a board game.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-13-Variability-and-Data-Distributions-img-77.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions img 77\" width=\"332\" height=\"119\" \/><br \/>\nFor numbers 15a\u201315d, choose Yes or No to indicate whether the statement is correct.<br \/>\n15a. The mean absolute deviation of Player B\u2019s scores is 0.<br \/>\n15b. The mean absolute deviation of Player A\u2019s scores is 0.<br \/>\n15c. The mean absolute deviation of Player B\u2019s scores is greater than the mean absolute deviation of Player C\u2019s scores.<br \/>\n15a. ___________<br \/>\n15b. ___________<br \/>\n15c. ___________<\/p>\n<p>Answer:15a. No<br \/>\n15b. Yes<br \/>\n15c.\u00a0 Yes<\/p>\n<p>Explanation:<br \/>\nMean of player A = 90+90+90\/3 = 90<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n90: 90-90\u00a0 = 0<br \/>\n90: 90-90\u00a0 = 0<br \/>\n90: 90-90\u00a0 = 0<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n0+0+0\/3 = 0<br \/>\nSo, the mean absolute deviation of player A is 0<\/p>\n<p>Mean of player B = 110+100+90\/3 = 100<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n100: 100-110\u00a0 = -10<br \/>\n100: 100-100\u00a0 = 0<br \/>\n100: 100-90\u00a0 \u00a0 = 10<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n10+0+10\/3 = 20\/3 = 6.67<br \/>\nSo, the mean absolute deviation of player B is 6.67<\/p>\n<p>Mean of player C = 95+100+95\/3 = 96.67<\/p>\n<p>Mean absolute deviation:<\/p>\n<p>STEP 1 Label each observation with its distance from the mean.<br \/>\nStarting from left to right:<br \/>\n96.67: 96.67-95\u00a0 \u00a0 = 1.67<br \/>\n96.67: 96.67-100\u00a0 = -3.33<br \/>\n96.67: 96.67-95\u00a0 \u00a0 = 1.67<\/p>\n<p>STEP 2 Find the mean of the distances.<br \/>\n1.67+3.33+1.67\/3 = 6.67\/3 = 2.22<br \/>\nSo, the mean absolute deviation of player C is 2.22<\/p>\n<p><em>Conclusion:<\/em><\/p>\n<p>The solutions with explanations to all the questions are prepared by the math experts as per the latest syllabus. So, go through the solutions and overcome your difficulties in this chapter. Keep in touch with this page to get the solutions to all the 6th-grade chapters.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Go Math Grade 6 Answer Key Chapter 13 deals with Variability and Data Distributions. The HMH Go Math 6th Grade Answer Key is a very helpful resource for students to prepare for the exams. The solutions are mentioned topic-wise to all the questions for chapter 13 Variability and Data Distributions. You can understand the problem-solving &#8230; <a title=\"Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions\" class=\"read-more\" href=\"https:\/\/ccssanswers.com\/go-math-grade-6-answer-key-chapter-13-variability-and-data-distributions\/\" aria-label=\"More on Go Math Grade 6 Answer Key Chapter 13 Variability and Data Distributions\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":8830,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/10\/go-math-grade-6-chapter-13-variability-and-data-distributions-answer-key.jpeg","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/5667"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=5667"}],"version-history":[{"count":3,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/5667\/revisions"}],"predecessor-version":[{"id":169710,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/5667\/revisions\/169710"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media\/8830"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=5667"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=5667"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=5667"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}