\nEach of the following figures is made up of 2 rectangles. Find the total area of each figure.
\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Problem-Set-Answer-Key-1.png\")
<\/p>\nQuestion 1.
\nEach of the following figures is made up of 2 rectangles. Find the total area of each figure.
\n<\/p>\n
Figure 1: Area of A + Area of B: ____18_____ sq units + _____9____ sq units = _____27____ sq units<\/p>\n
Figure 2: Area of C + Area of D: ____18_____ sq units + ___15______ sq units = ___33______ sq units<\/p>\n
Figure 3: Area of E + Area of F: _____9____ sq units + ____21_____ sq units = ____30_____ sq units<\/p>\n
Figure 4: Area of G + Area of H: _____49____ sq units + ___6______ sq units = ____55_____sq units<\/p>\n
Answer:
\nThe total area of figure 1 = 27 sq units.
\nthe total area of figure 2 = 33 sq units.
\nthe total area of figure 3 = 30 sq units.
\nthe total area of figure 4 = 55 sq units.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nthe area of rectangle A + rectangle B = figure 1.
\narea of rectangle A = 18 sq units.
\narea of rectangle B = 9 sq units.
\nso the area of figure 1 = 27 sq units.
\nthe area of rectangle C + rectangle D = figure 2.
\narea of rectangle C = 18 sq units.
\narea of rectangle D = 15 sq units.
\nso the area of figure 2 = 33 sq units.
\nthe area of rectangle E + rectangle F = figure 3.
\narea of rectangle E = 9 sq units.
\narea of rectangle F = 21 sq units.
\nso the area of figure 3 = 30 sq units.
\nthe area of rectangle G + rectangle H = figure 4.
\narea of rectangle G = 49 sq units.
\narea of rectangle H = 6 sq units.
\nso the area of figure 4 = 55 sq units.<\/p>\n
Question 2.
\nThe figure shows a small rectangle cut out of a bigger rectangle. Find the area of the shaded figure.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Problem-Set-Answer-Key-2.png\")
\nArea of the shaded figure: __90____ \u2013 __12____ = ___78___
\nArea of the shaded figure: ___78___ square centimeters<\/p>\n
Answer:
\nThe area of the shaded figure = 78 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\narea of longer rectangle = 90 sq cm.
\narea = l x b.
\narea = 9 x 10.
\narea = 90 sq cm.
\narea of smaller rectangle = 12 sq cm.
\narea = l x b.
\narea = 3 x 4.
\narea = 12 sq cm.
\narea of shaded rectangle = area of longer rectangle – area of smaller rectangle.
\narea of shaded rectangle = 90 – 12.
\narea of shaded rectangle = 78 sq cm.<\/p>\n
Question 3.
\nThe figure shows a small rectangle cut out of a big rectangle.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Problem-Set-Answer-Key-3.png\")
\na. Label the unknown measurements.<\/p>\n
Answer:
\nThe unknown measurements = 4 cm and 5 cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nthe longer rectangle = 9 x 7 = 63 cm.
\n9 – 4 = 3.
\n7 – 3 = 4.
\nso the unknown measurements = 4 cm and 5 cm.
\n![\"Eureka-Math-Grade-3-Module-4-Lesson-13-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Answer-Key-1.png\")
<\/p>\n
b. Area of the big rectangle:
\n___9__ cm \u00d7 __7___ cm = __63___ sq cm<\/p>\n
Answer:
\nThe area of big rectangle = 63 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\narea of the big rectangle = l x b.
\nwhere l = length, and b = breadth.
\narea = 9 x 7 = 63 sq cm.
\nso the area of big rectangle = 63 sq cm.<\/p>\n
c. Area of the small rectangle:
\n___5__ cm \u00d7 __4___ cm = ___20__ sq cm<\/p>\n
Answer:
\nThe area of small rectangle = 20 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\narea of the big rectangle = l x b.
\nwhere l = length, and b = breadth.
\narea = 5 x 4 = 20 sq cm.
\nso the area of big rectangle = 20 sq cm.<\/p>\n
d. Find the area of the shaded figure.<\/p>\n
Answer:
\nThe area of the shaded figure = 43 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nthe area of the longer rectangle = 63 sq cm.
\narea = l x b.
\narea = 9 x 7.
\narea = 63 sq cm.
\narea of smaller rectangle = 20 sq cm.
\narea = l x b.
\narea = 5 x 4.
\narea = 20 sq cm.
\narea of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
\narea of shaded rectangle = 63 – 20.
\narea of shaded rectangle = 43 sq cm.<\/p>\n
The following figure is made up of 2 rectangles. Find the total area of the figure.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Exit-Ticket-Answer-Key-4.png\")
\nArea of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units<\/p>\n
Answer:
\nThe area of rectangle A and B = 52 sq units.
\nExplanation:
\nIn the above-given question,
\ngiven that,
\nthe area of rectangle A + rectangle B = figure 1.
\narea of rectangle A = 32 sq units.
\narea of rectangle B = 20 sq units.
\nso the area of rectangle A and B = 52 sq units.<\/p>\n
Question 1.
\nEach of the following figures is made up of 2 rectangles. Find the total area of each figure.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Homework-Answer-Key-5.png\")
\nFigure 1: Area of A + Area of B: ____15_____ sq units + ____9_____ sq units = ___24______ sq units<\/p>\n
Figure 2: Area of C + Area of D: ___3______ sq units + ____8_____ sq units = ____24_____ sq units<\/p>\n
Figure 3: Area of E + Area of F: ___12______ sq units + ____32_____ sq units = ____44_____ sq units<\/p>\n
Figure 4: Area of G + Area of H: _____15____ sq units + ____25_____ sq units = ___40______ sq units<\/p>\n
Answer:
\nThe total area of figure 1 = 24 sq units.
\nthe total area of figure 2 = 24 sq units.
\nthe total area of figure 3 = 44 sq units.
\nthe total area of figure 4 = 40 sq units.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nthe area of rectangle A + rectangle B = figure 1.
\narea of rectangle A = 15 sq units.
\narea of rectangle B = 9 sq units.
\nso the area of figure 1 = 24 sq units.
\nthe area of rectangle C + rectangle D = figure 2.
\narea of rectangle C = 3 sq units.
\narea of rectangle D = 8 sq units.
\nso the area of figure 2 = 24 sq units.
\nthe area of rectangle E + rectangle F = figure 3.
\narea of rectangle E = 12 sq units.
\narea of rectangle F = 32 sq units.
\nso the area of figure 3 = 44 sq units.
\nthe area of rectangle G + rectangle H = figure 4.
\narea of rectangle G = 15 sq units.
\narea of rectangle H = 25 sq units.
\nso the area of figure 4 = 40 sq units.<\/p>\n
Question 2.
\nThe figure shows a small rectangle cut out of a big rectangle. Find the area of the shaded figure.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Homework-Answer-Key-6.png\")
<\/p>\n
Answer:
\nThe area of the shaded figure = 45 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nthe area of the longer rectangle = 56 sq cm.
\narea = l x b.
\narea = 7 x 8.
\narea = 56 sq cm.
\narea of smaller rectangle = 9 sq cm.
\narea = l x b.
\narea = 3 x 3.
\narea = 9 sq cm.
\narea of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
\narea of shaded rectangle = 56 – 9.
\narea of shaded rectangle = 45 sq cm.<\/p>\n
Question 3.
\nThe figure shows a small rectangle cut out of a big rectangle.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Homework-Answer-Key-7.png\")
\na. Label the unknown measurements.<\/p>\n
Answer:
\nThe unknown measurements = 3 cm and 4 cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nthe longer rectangle = 9 x 8 = 72 cm.
\n9 – 6 = 3.
\n8 – 4 = 4.
\nso the unknown measurements = 3 cm and 4 cm.
\n![\"Eureka-Math-Grade-3-Module-4-Lesson-13-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Answer-Key-2.png\")
<\/p>\n
b. Area of the big rectangle:
\n____9__ cm \u00d7 ___8___ cm = ___72___ sq cm<\/p>\n
Answer:
\nThe area of big rectangle = 72 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\narea of the big rectangle = l x b.
\nwhere l = length, and b = breadth.
\narea = 9 x 8 = 72 sq cm.
\nso the area of big rectangle = 72 sq cm.<\/p>\n
c. Area of the small rectangle:
\n___3___ cm \u00d7 ___4___ cm = __12____ sq cm<\/p>\n
Answer:
\nThe area of small rectangle = 12 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\narea of the big rectangle = l x b.
\nwhere l = length, and b = breadth.
\narea = 3 x 4 = 12 sq cm.
\nso the area of small rectangle = 12 sq cm.<\/p>\n
d. Find the area of the shaded figure.<\/p>\n
Answer:
\nThe area of the shaded figure = 43 sq cm.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\narea of longer rectangle = 72 sq cm.
\narea = l x b.
\narea = 9 x 8.
\narea = 72 sq cm.
\narea of smaller rectangle = 12 sq cm.
\narea = l x b.
\narea = 3 x 4.
\narea = 12 sq cm.
\narea of shaded rectangle = area of longer rectangle – area of smaller rectangle.
\narea of shaded rectangle = 72 – 12.
\narea of shaded rectangle = 60 sq cm.<\/p>\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-3-Module-4-Lesson-13-Template-Answer-Key-8.png\")
<\/p>\n
Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units<\/p>\n
Answer:
\nThe area of rectangle A and B = 52 sq units.
\nExplanation:
\nIn the above-given question,
\ngiven that,
\nthe area of rectangle A + rectangle B = figure 1.
\narea of rectangle A = 32 sq units.
\narea of rectangle B = 20 sq units.
\nso the area of rectangle A and B = 52 sq units.
\n<\/p>\n","protected":false},"excerpt":{"rendered":"
Engage NY Eureka Math 3rd Grade Module 4 Lesson 13 Answer Key Eureka Math Grade 3 Module 4 Lesson 13 Problem Set Answer Key Question 1. Each of the following figures is made up of 2 rectangles. Find the total area of each figure. Figure 1: Area of A + Area of B: ____18_____ sq … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/58652"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=58652"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/58652\/revisions"}],"predecessor-version":[{"id":138055,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/58652\/revisions\/138055"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=58652"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=58652"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=58652"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}