{"id":5878,"date":"2023-02-14T16:07:07","date_gmt":"2023-02-14T10:37:07","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=5878"},"modified":"2023-02-15T12:39:46","modified_gmt":"2023-02-15T07:09:46","slug":"go-math-grade-7-answer-key-chapter-5-percent-increase-and-decrease","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/go-math-grade-7-answer-key-chapter-5-percent-increase-and-decrease\/","title":{"rendered":"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease"},"content":{"rendered":"<p>Download <a href=\"https:\/\/ccssanswers.com\/go-math-grade-7-answer-key\/\" target=\"_blank\" rel=\"noopener noreferrer\">Go Math Grade 7 Answer Key<\/a> for Chapter 5 Percent Increase and Decrease pdf for free. Quick and easy learning is possible with Go Math 7th Grade Answer Key Chapter 5 Percent Increase and Decrease. So, we suggest the students of 7th standard to go through the HMH Go Math Grade 7 Key Chapter 5 Percent Increase and Decrease. Our team of Go Math Answer Key will help the Grade 7 students to score the highest marks.<\/p>\n<h2>Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease<\/h2>\n<p>Get a brief explanation for all the questions in Chapter 5 Percent Increase and Decrease Go Math Answer Key Grade 7. Tap on the links provided below and get the solutions according to the topics. So, utilize the time in the proper way and practice Go Math 7th Grade Solution Key Chapter 5 Percent Increase and Decrease.<\/p>\n<p><strong>Chapter 5 &#8211; Percent Increase and Decrease<\/strong><\/p>\n<ul>\n<li><a href=\"#Percent_Increase_and_Decrease_Guided_Practice_Page_No_144\">Percent Increase and Decrease &#8211; Guided Practice &#8211; Page No. 144<\/a><\/li>\n<li><a href=\"#Percent_Increase_and_Decrease_Independent_Practice_Page_No_145\">Percent Increase and Decrease &#8211; Independent Practice &#8211; Page No. 145<\/a><\/li>\n<li><a href=\"#Percent_Increase_and_Decrease_Page_No_146\">Percent Increase and Decrease &#8211; Page No. 146<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 5 &#8211; Rewriting Percent Expressions<\/strong><\/p>\n<ul>\n<li><a href=\"#Rewriting_Percent_Expressions_Guided_Practice_Page_No_150\">Rewriting Percent Expressions &#8211; Guided Practice &#8211; Page No. 150<\/a><\/li>\n<li><a href=\"#Rewriting_Percent_Expressions_Independent_Practice_Page_No_151\">Rewriting Percent Expressions &#8211; Independent Practice &#8211; Page No. 151<\/a><\/li>\n<li><a href=\"#Rewriting_Percent_Expressions_Page_No_152\">Rewriting Percent Expressions &#8211; Page No. 152<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 5 &#8211; Applications of Percent<\/strong><\/p>\n<ul>\n<li><a href=\"#Applications_of_Percent_Guided_Practice_Page_No_156\">Applications of Percent &#8211; Guided Practice &#8211; Page No. 156<\/a><\/li>\n<li><a href=\"#Applications_of_Percent_Independent_Practice_Page_No_157\">Applications of Percent &#8211; Independent Practice &#8211; Page No. 157<\/a><\/li>\n<li><a href=\"#Applications_of_Percent_Page_No_158\">Applications of Percent &#8211; Page No. 158<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 5<\/strong><\/p>\n<ul>\n<li><a href=\"#MODULE_QUIZ_5.1_Percent_Increase_and_Decrease_Page_No_159\">MODULE QUIZ &#8211; 5.1 Percent Increase and Decrease &#8211; Page No. 159<\/a><\/li>\n<li><a href=\"#Selected_Response_Page_No_160\">Selected Response &#8211; Page No. 160<\/a><\/li>\n<li><a href=\"#Module_5_Page_No_162\">Module 5 &#8211; Page No. 162<\/a><\/li>\n<li><a href=\"#Unit_2_Performance_Tasks_Page_No_163\">Unit 2 Performance Tasks &#8211; Page No. 163<\/a><\/li>\n<li><a href=\"#Unit_2_Performance_Tasks_Page_No_164\">Unit 2 Performance Tasks (con&#8217;td) &#8211; Page No. 164<\/a><\/li>\n<li><a href=\"#Selected_Response_Page_No_165\">Selected Response &#8211; Page No. 165<\/a><\/li>\n<li><a href=\"#Page_No_166\">Page No. 166<\/a><\/li>\n<\/ul>\n<h3><a id=\"Percent_Increase_and_Decrease_Guided_Practice_Page_No_144\"><\/a>Percent Increase and Decrease &#8211; Guided Practice &#8211; Page No. 144<\/h3>\n<p><strong>Find each percent increase. Round to the nearest percent.<\/strong><\/p>\n<p>Question 1.<br \/>\nFrom $5 to $8<br \/>\n______ %<\/p>\n<p>Answer: 60%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 5<br \/>\nFinal amount = 8<br \/>\n8 &#8211; 5 = 3<br \/>\nPercent change = 3\/5 = 0.6 = 60%<\/p>\n<p>Question 2.<br \/>\nFrom 20 students to 30 students<br \/>\n______ %<\/p>\n<p>Answer: 50%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 20<br \/>\nFinal amount = 30<br \/>\nWe find the amount of change<br \/>\n30 &#8211; 20 = 10<br \/>\nWe determine the percent of the increase<br \/>\nPercent change = 10\/20 = 0.5 = 50%<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168860\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q3.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q3\" width=\"514\" height=\"442\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q3.png 514w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q3-300x258.png 300w\" sizes=\"(max-width: 514px) 100vw, 514px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168861\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q4.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q4\" width=\"527\" height=\"558\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q4.png 527w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q4-283x300.png 283w\" sizes=\"(max-width: 527px) 100vw, 527px\" \/><\/p>\n<p>Question 5.<br \/>\nFrom 13 friends to 14 friends<br \/>\n______ %<\/p>\n<p>Answer: 8%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 13<br \/>\nFinal amount = 14<br \/>\nWe find the amount of change<br \/>\n14 &#8211; 13 = 1<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 1\/13 \u2248 0.08 = 8%<\/p>\n<p>Question 6.<br \/>\nFrom 5 miles to 16 miles<br \/>\n______ %<\/p>\n<p>Answer: 220%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 5<br \/>\nFinal amount = 16<br \/>\nWe find the amount of change<br \/>\n16 &#8211; 5 = 11<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 11\/5 = 2.2 = 220%<\/p>\n<p>Question 7.<br \/>\nNathan usually drinks 36 ounces of water per day. He read that he should drink 64 ounces of water per day. If he starts drinking 64 ounces, what is the percent increase? Round to the nearest percent.<br \/>\n______ %<\/p>\n<p>Answer: 78%<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nNathan usually drinks 36 ounces of water per day. He read that he should drink 64 ounces of water per day.<br \/>\nOriginal Amount: 36<br \/>\nFinal Amount: 64<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nWe find the amount of change<br \/>\n64 &#8211; 36 = 28<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 28\/36 \u2248 0.78 = 78%<br \/>\nThus the nearest percent is 78%<\/p>\n<p><strong>Find each percent decrease. Round to the nearest percent.<\/strong><\/p>\n<p>Question 8.<br \/>\nFrom $80 to $64<br \/>\n______ %<\/p>\n<p>Answer: 20%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 80<br \/>\nFinal amount = 64<br \/>\nWe find the amount of change<br \/>\nAmount of change = Greater value &#8211; Lesser value<br \/>\n= 80 &#8211; 64 = 16<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 16\/80 = 0.20 = 20%<br \/>\nThus the nearest percent is 20%<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168863\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q9.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q9\" width=\"387\" height=\"425\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q9.png 387w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q9-273x300.png 273w\" sizes=\"(max-width: 387px) 100vw, 387px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168864\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q10.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q10\" width=\"470\" height=\"508\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q10.png 470w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q10-278x300.png 278w\" sizes=\"(max-width: 470px) 100vw, 470px\" \/><\/p>\n<p>Question 11.<br \/>\nFrom 145 pounds to 132 pounds<br \/>\n______ %<\/p>\n<p>Answer: 9%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 145<br \/>\nFinal amount = 132<br \/>\nWe find the amount of change<br \/>\nAmount of change = Greater value &#8211; Lesser value<br \/>\n145 &#8211; 132 = 13<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 13\/145 \u2248 0.09 = 9%<br \/>\nThe nearest percent is 9%<\/p>\n<p>Question 12.<br \/>\nFrom 64 photos to 21 photos<br \/>\n______ %<\/p>\n<p>Answer: 67%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 64<br \/>\nFinal amount = 21<br \/>\nWe find the amount of change<br \/>\nAmount of change = Greater value &#8211; Lesser value<br \/>\n64 &#8211; 21 = 43<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 43\/64 \u2248 0.67 = 67%<br \/>\nTherefore the nearest percent is 67%<\/p>\n<p>Question 13.<br \/>\nFrom 16 bagels to 0 bagels<br \/>\n______ %<\/p>\n<p>Answer: 100%<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 16<br \/>\nFinal amount = 0<br \/>\nWe find the amount of change<br \/>\nAmount of change = Greater value &#8211; Lesser value<br \/>\n16 &#8211; 0 = 16<br \/>\nWe determine the percent of increase and round it to the nearest percent<br \/>\nPercent Change = 16\/16 = 1.0% = 100%<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168865\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q14.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q14\" width=\"644\" height=\"465\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q14.png 644w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q14-300x217.png 300w\" sizes=\"(max-width: 644px) 100vw, 644px\" \/><\/p>\n<p><strong>Find the new amount given the original amount and the percent of change.<\/strong><\/p>\n<p>Question 15.<br \/>\n$9; 10% increase<br \/>\n$ ______<\/p>\n<p>Answer: $9.90<\/p>\n<p>Explanation:<br \/>\nPercent Charge = Amount of Change\/Original Amount<br \/>\nOriginal amount = 9<br \/>\nIncrease = 10%<br \/>\nWe find the amount of change<br \/>\n0.1 \u00d7 9 = 0.90<br \/>\nNew Amount = Original Amount + Amount of Change<br \/>\n9 + 0.90 = 9.90<\/p>\n<p>Question 16.<br \/>\n48 cookies; 25% decrease<br \/>\n______ cookies<\/p>\n<p>Answer: 36 cookies<\/p>\n<p>Explanation:<br \/>\nOriginal amount = 48<br \/>\nDecrease = 25%<br \/>\nWe find the amount of change<br \/>\n0.25 \u00d7 48 = 12<br \/>\nNew Amount = Original Amount &#8211; Amount of Change<br \/>\n48 &#8211; 12 = 36<br \/>\nThus the answer is 36 cookies.<\/p>\n<p>Question 17.<br \/>\n340 pages; 20% decrease<br \/>\n______ pages<\/p>\n<p>Answer: 272 pages<\/p>\n<p>Explanation:<br \/>\nOriginal Amount: 340 pages<br \/>\nDecrease: 20%<br \/>\nWe find the amount of change<br \/>\n0.20 \u00d7 340 = 68<br \/>\nNew Amount = Original Amount &#8211; Amount of Change<br \/>\n340 &#8211; 68 = 272<br \/>\nThe answer is 272 pages.<\/p>\n<p>Question 18.<br \/>\n28 members; 50% increase<br \/>\n______ members<\/p>\n<p>Answer: 42 members<\/p>\n<p>Explanation:<br \/>\nOriginal Amount: 28<br \/>\nIncrease: 50%<br \/>\nWe find the amount of change<br \/>\n0.5 \u00d7 28 = 14<br \/>\nNew amount = Original Amount + Amount of Change<br \/>\n28 + 14 = 42<br \/>\nThe answer is 42 members<\/p>\n<p>Question 19.<br \/>\n$29,000; 4% decrease<br \/>\n$ ______<\/p>\n<p>Answer: $27,840<\/p>\n<p>Explanation:<br \/>\nOriginal Amount: 29000<br \/>\nDecrease: 4%<br \/>\nWe find the amount of change<br \/>\n0.04 \u00d7 29000 = 1160<br \/>\nNew Amount = Original Amount &#8211; Amount of Change<br \/>\n29000 &#8211; 1160 = 27840<br \/>\nThe answer is $27,840<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168866\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q20.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q20\" width=\"583\" height=\"467\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q20.png 583w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q20-300x240.png 300w\" sizes=\"(max-width: 583px) 100vw, 583px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168867\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q21.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q21\" width=\"664\" height=\"407\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q21.png 664w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q21-300x184.png 300w\" sizes=\"(max-width: 664px) 100vw, 664px\" \/><\/p>\n<p><strong>Essential Question Check-In<\/strong><\/p>\n<p>Question 22.<br \/>\nWhat process do you use to find the percent change of a quantity?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: In order to find the percent change of a quantity, we determine the amount of change in the quantity and divide it by the original amount.<\/p>\n<h3><a id=\"Percent_Increase_and_Decrease_Independent_Practice_Page_No_145\"><\/a>Percent Increase and Decrease &#8211; Independent Practice &#8211; Page No. 145<\/h3>\n<p>Question 23.<br \/>\nComplete the table.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-1.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 1: Percent Increase and Decrease img 1\" width=\"567\" height=\"205\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: bike: 13%, scooter 24%, increase, tennis racket: $83, skis: $435<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7578\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-1-1-300x108.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-1\" width=\"300\" height=\"108\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-1-1-300x108.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-1-1.jpg 567w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Explanation:<br \/>\nSince the new price is less than the original price, it is a percent decrease. percent decreases can be found using the equation percent decrease = (original &#8211; new)\/original<br \/>\nBike: 110 &#8211; 96\/110 = 14\/110 \u2248 13%<br \/>\nScooter: 56 &#8211; 45\/45 = 11\/45 \u2248 24%<br \/>\nUse the equation percent increase = new &#8211; original\/original<br \/>\nlet x be the new price<br \/>\nskis: (580 &#8211; x)\/580 = 0.25<br \/>\n580 &#8211; x = 0.25 \u00d7 580<br \/>\n580 &#8211; x = 145<br \/>\nx = 580 &#8211; 145 = 435<br \/>\nThe new price is $435<\/p>\n<p>Question 24.<br \/>\nMultiple Representations<br \/>\nThe bar graph shows the number of hurricanes in the Atlantic Basin from 2006\u20132011.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-2.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 1: Percent Increase and Decrease img 2\" width=\"320\" height=\"286\" \/><br \/>\na. Find the amount of change and the percent of decrease in the number of hurricanes from 2008 to 2009 and from 2010 to 2011. Compare the amounts of change and percents of decrease.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2008 to 2009 has a smaller amount of change but a larger percent of decrease.<\/p>\n<p>Explanation:<br \/>\n2008 to 2009:<br \/>\namount of change: 8 &#8211; 3 = 5<br \/>\npercent decrease: 5\/8 = 0.625 = 62.5%<br \/>\n2010 to 2011:<br \/>\namount of change: 12 &#8211; 7 = 5<br \/>\npercent decrease: 5\/12 \u2248 0.416 = 41.6%<br \/>\nThe amount of change for 2010 to 2011 was greater than the amount of change for 2008 to 2009 but 2008 to 209 had a greater percent decrease than 2010 to 2011.<\/p>\n<p>Question 24.<br \/>\nb. Between which two years was the percent of change the greatest? What was the percent of change during that period?<br \/>\n_______ %<\/p>\n<p>Answer: 2009 and 2010, 300%<\/p>\n<p>Explanation:<br \/>\nUse the percent change = amount of change\/original amount.<br \/>\nThe biggest change in heights is between 2009 and 2010.<br \/>\nThe percent change is (12-3)\/3 = 9\/3 = 3 = 300%<\/p>\n<p>Question 25.<br \/>\nRepresent Real-World Problems<br \/>\nCheese sticks that were previously priced at \u201c5 for $1\u201d are now \u201c4 for $1\u201d. Find each percent of change and show your work.<br \/>\na. Find the percent decrease in the number of cheese sticks you can buy for $1.<br \/>\n_______ %<\/p>\n<p>Answer: 20% decrease<\/p>\n<p>Explanation:<br \/>\nUse the percent change = amount of change\/original amount.<br \/>\n(5 &#8211; 4)\/5 = 1\/5 = 0.2 = 20% decrease<\/p>\n<p>Question 25.<br \/>\nb. Find the percent increase in the price per cheese stick.<br \/>\n_______ %<\/p>\n<p>Answer: 25% increase<\/p>\n<p>Explanation:<br \/>\nFirst, find the price per cheese stick at each price.<br \/>\nUse the percent change = amount of change\/original amount.<br \/>\n1.00\/5 = 0.20<br \/>\n1\/4 = 0.25<br \/>\n(0.25 &#8211; 0.20)\/0.20 = 0.05\/0.20 = 25% increase<\/p>\n<h3><a id=\"Percent_Increase_and_Decrease_Page_No_146\"><\/a>Percent Increase and Decrease &#8211; Page No. 146<\/h3>\n<p>Question 26.<br \/>\nPercent error calculations are used to determine how close to the true values, or how accurate, experimental values really are. The formula is similar to finding percent of change.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-3.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 1: Percent Increase and Decrease img 3\" width=\"443\" height=\"52\" \/><br \/>\nchemistry class, Charlie records the volume of a liquid as 13.3 milliliters. The actual volume is 13.6 milliliters. What is his percent error? Round to the nearest percent.<br \/>\n_______ %<\/p>\n<p>Answer: 2%<\/p>\n<p>Explanation:<br \/>\nUse the formula<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-3.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 1: Percent Increase and Decrease img 3\" width=\"443\" height=\"52\" \/><br \/>\n|13.3 &#8211; 13.6|\/13.6 = |-0.3|\/13.6 \u2248 0.02 = 2%<\/p>\n<p><strong>H.O.T.<\/strong><\/p>\n<p><strong>Focus on Higher Order Thinking<\/strong><\/p>\n<p>Question 27.<br \/>\nLook for a Pattern<br \/>\nLeroi and Sylvia both put $100 in a savings account. Leroi decides he will put in an additional $10 each week. Sylvia decides to put in an additional 10% of the amount in the account each week.<br \/>\na. Who has more money after the first additional deposit? Explain.<br \/>\n___________<\/p>\n<p>Answer: the same<\/p>\n<p>Explanation:<br \/>\nSince 10% of 100 is 100(0.10) = 10, they both make an additional deposit of 10, so they have the same amount of money after the first additional deposit.<\/p>\n<p>Question 27.<br \/>\nb. Who has more money after the second additional deposit? Explain.<br \/>\n___________<\/p>\n<p>Answer: Sylvia<\/p>\n<p>Explanation:<br \/>\nBoth Lerio and Sylvia have $110 in their account after their first deposits since they both started with $100 and both deposited $10 for their first deposit.<br \/>\nAfter the second deposit, Lerio has 110 + 10 = $120.<br \/>\nSylvia has 110 + 0.10(110) = 110 + 11 = $121<br \/>\nSo she has more money after the second deposit.<\/p>\n<p>Question 27.<br \/>\nc. How do you think the amounts in the two accounts will compare after a month? A year?<br \/>\nType below:<br \/>\n___________<\/p>\n<p>Answer: Sylvia will continue to have more money after a month and a year since 10% of the balance is going to be greater than the 10 deposit that Leroi is making.<\/p>\n<p>Question 28.<br \/>\nCritical Thinking<br \/>\nSuppose an amount increases by 100%, then decreases by 100%. Find the final amount. Would the situation change if the original increase was 150%? Explain your reasoning.<br \/>\nType below:<br \/>\n___________<\/p>\n<p>Answer: If an amount increases by 100%, then it will double. If it then decreases by 100%, it will become 0.<br \/>\nIf you increase a number by 150% and then decrease it by 150%, you will not get to 0. 150% increase of 100 is 100 + 150 = 250.<br \/>\nA decrease of 150% is then 250 &#8211; 1.5(250) = 250 &#8211; 375 = -125<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168868\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q29.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 144 Q29\" width=\"709\" height=\"573\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q29.png 709w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-144-Q29-300x242.png 300w\" sizes=\"(max-width: 709px) 100vw, 709px\" \/><\/p>\n<h3><a id=\"Rewriting_Percent_Expressions_Guided_Practice_Page_No_150\"><\/a>Rewriting Percent Expressions &#8211; Guided Practice &#8211; Page No. 150<\/h3>\n<p>Question 1.<br \/>\nDana buys dress shirts from a clothing manufacturer for s dollars each and then sells the dress shirts in her retail clothing store at a 35% markup.<br \/>\na. Write the markup as a decimal.<br \/>\n______<\/p>\n<p>Answer: To convert a percent to a decimal, move the decimal place two places to the left. Therefore, 35% as a decimal is 0.35.<\/p>\n<p>Question 1.<br \/>\nb. Write an expression for the retail price of the dress shirt.<br \/>\nType below:<br \/>\n___________<\/p>\n<p>Answer:<br \/>\nTo write the expression, use the formula<br \/>\nretail price = original place + markup<br \/>\nSince s is the original place, if the markup is 35% = 0.35, then the markup is 0.35s.<\/p>\n<p>Question 1.<br \/>\nc. What is the retail price of a dress shirt that Dana purchased for $32.00?<br \/>\n$ ______<\/p>\n<p>Answer: Plugging in s = 32 into the expression gives a retail price of 1.35 = 1.35(32) = $43.20<\/p>\n<p>Question 1.<br \/>\nd. How much was added to the original price of the dress shirt?<br \/>\n$ ______<\/p>\n<p>Answer: The amount added to the original price is the amount of the markup. Since the amount of the markup is 0.35s and s = 32, then the amount of the markup was 0.35s = 0.35(32) = $11.20.<br \/>\nYou can also find the amount of markup by subtracting the retail price and the original price. Since the retail price is $43.20 and the original price is $32, then the markup amount is $43.20 &#8211; $32 = $11.20<\/p>\n<p><strong>List the markup and retail price of each item. Round to two decimal places when necessary.<\/strong><\/p>\n<p>Question 2.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-4.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 4\" width=\"702\" height=\"97\" \/><br \/>\nMarkup: $ ______ Retail Price: $ ______<\/p>\n<p>Answer: Markup: $ 2.70 Retail Price: $ 20.70<\/p>\n<p>Explanation:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7595\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-4-1-300x41.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-4\" width=\"300\" height=\"41\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-4-1-300x41.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-4-1-768x106.jpg 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-4-1.jpg 861w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nUse the formula markup = price(markup%)<br \/>\n18(0.15) = 2.70<br \/>\nUse the retail price formula = price + markup<br \/>\n18 + 2.70 = 20.70<\/p>\n<p>Question 3.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-5.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 5\" width=\"700\" height=\"45\" \/><br \/>\nMarkup: $ ______ Retail Price: $ ______<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7597\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-5-1-300x19.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-5\" width=\"300\" height=\"19\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-5-1-300x19.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-5-1-768x50.jpg 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-5-1.jpg 865w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nUse the formula markup = (price)(markup %)<br \/>\n22.50(0.42) = 9.45<br \/>\nUse the retail price formula = price + markup<br \/>\n22.50 + 9.45 = 31.95<\/p>\n<p>Question 4.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-6.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 6\" width=\"636\" height=\"47\" \/><br \/>\nMarkup: $ ______ Retail Price: $ ______<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7598\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-6-1-300x22.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-6\" width=\"300\" height=\"22\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-6-1-300x22.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-6-1-768x57.jpg 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-6-1.jpg 866w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nUse the formula markup = (price)(markup %)<br \/>\n= 33.75(0.75) = 25.31<br \/>\nUse the formula retail price = price + markup<br \/>\n33.75 + 25.31 = 59.06<\/p>\n<p>Question 5.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-7.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 7\" width=\"697\" height=\"49\" \/><br \/>\nMarkup: $ ______ Retail Price: $ ______<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7599\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-7-1-300x21.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-7\" width=\"300\" height=\"21\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-7-1-300x21.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-7-1-768x54.jpg 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-7-1.jpg 865w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nUse the formula markup = (price)(markup %)<br \/>\n= 74.99(0.33) = 24.75<br \/>\nUse the formula retail price = price + markup<br \/>\n74.99 + 24.75 = 99.74<\/p>\n<p>Question 6.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-8.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 8\" width=\"725\" height=\"51\" \/><br \/>\nMarkup: $ ______ Retail Price: $ ______<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7600\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-8-1-300x21.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-8\" width=\"300\" height=\"21\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-8-1-300x21.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-8-1-768x54.jpg 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-8-1.jpg 865w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nUse the formula markup = (price)(markup %)<br \/>\n48.60(1.00) = 48.60<br \/>\nUse the formula retail price = price + markup<br \/>\n48.60 + 48.60 = 97.20<\/p>\n<p>Question 7.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-9.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 9\" width=\"711\" height=\"50\" \/><br \/>\nMarkup: $ ______ Retail Price: $ ______<\/p>\n<p>Answer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-medium wp-image-7602\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-9-1-300x21.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-9\" width=\"300\" height=\"21\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-9-1-300x21.jpg 300w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-9-1-768x54.jpg 768w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-9-1.jpg 865w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nUse the formula markup = (price)(markup %)<br \/>\n= 185 \u00d7 1.25 = 231.25<br \/>\nUse the formula retail price = price + markup<br \/>\n185 + 231.25 = 461.25<\/p>\n<p><strong>Find the sale price of each item. Round to two decimal places when necessary.<\/strong><\/p>\n<p>Question 8.<br \/>\nOriginal price: $45.00; Markdown: 22%<br \/>\n$ ______<\/p>\n<p>Answer:<br \/>\nUse the formula markup = (price)(markup %)<br \/>\n45(0.22) = 9.90<br \/>\nMarkdown is 9.90<br \/>\nUse the formula retail price = price + markup<br \/>\n45 &#8211; 9.90 = 35.10<br \/>\nThe sale price is $35.10<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168869\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q9.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 150 Q9\" width=\"487\" height=\"303\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q9.png 487w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q9-300x187.png 300w\" sizes=\"(max-width: 487px) 100vw, 487px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168870\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q10.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 150 Q10\" width=\"487\" height=\"299\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q10.png 487w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q10-300x184.png 300w\" sizes=\"(max-width: 487px) 100vw, 487px\" \/><\/p>\n<p>Question 11.<br \/>\nOriginal price: $279.99, Markdown: 75%<br \/>\n$ ______<\/p>\n<p>Answer:<br \/>\nUse the formula markup = (price)(markup %)<br \/>\n279.99 \u00d7 0.75 = 209.99<br \/>\nUse the formula retail price = price &#8211; markup<br \/>\n279.99 &#8211; 209.99 = 70<\/p>\n<p><strong>Essential Question Check-In<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168871\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q12.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 150 Q12\" width=\"645\" height=\"266\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q12.png 645w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-150-Q12-300x124.png 300w\" sizes=\"(max-width: 645px) 100vw, 645px\" \/><\/p>\n<h3><a id=\"Rewriting_Percent_Expressions_Independent_Practice_Page_No_151\"><\/a>Rewriting Percent Expressions &#8211; Independent Practice &#8211; Page No. 151<\/h3>\n<p>Question 13.<br \/>\nA bookstore manager marks down the price of older hardcover books, which originally sell for b dollars, by 46%.<br \/>\na. Write the markdown as a decimal.<br \/>\n______<\/p>\n<p>Answer: 0.46<\/p>\n<p>Explanation:<br \/>\nTo convert a percent to decimal form, move the decimal point 2 places to the left and don&#8217;t write the percent symbol. Therefore, 46% as a decimal is 0.46.<\/p>\n<p>Question 13.<br \/>\nb. Write an expression for the sale price of the hardcover book.<br \/>\nType below:<br \/>\n____________<\/p>\n<p>Answer: 0.54b<\/p>\n<p>Explanation:<br \/>\nThe sale price is the original price minus the discount amount. If the original price is discounted 46% and the original price is b dollars, the amount of the discount is 46% of b = 0.46b.<br \/>\nThe sale price is then b &#8211; 0.46b = (1 &#8211; 0.46)b = 0.54b<\/p>\n<p>Question 13.<br \/>\nc. What is the sale price of a hardcover book for which the original retail price was $29.00?<br \/>\n$ ______<\/p>\n<p>Answer: $15.66<\/p>\n<p>Explanation:<br \/>\nFrom part (b), the sale price of an item with an original price of b dollars is 0.54b. If the original price is then b = 29 dollars, the sale price is 0.54b = 0.54 \u00d7 29 = $15.66<\/p>\n<p>Question 13.<br \/>\nd. If you buy the book in part c, how much do you save by paying the sale price?<br \/>\n$ ______<\/p>\n<p>Answer: $13.34<\/p>\n<p>Explanation:<br \/>\nThe amount of savings is the difference between the original price and the sale price. If the original price is $29 and the sale price is $15.66, then the amount of savings is $29.00 &#8211; $15.66 = $13.34<\/p>\n<p>Question 14.<br \/>\nRaquela\u2019s coworker made price tags for several items that are to be marked down by 35%. Match each Regular Price to the correct Sale Price, if possible. Not all sales tags match an item.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-10.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 10\" width=\"727\" height=\"233\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n35% markdown means the expression for the sales price is p &#8211; 0.35p = 0.65p. Plug in the regular prices for p to find the sale prices. Remember the directions stated not all sales tags will match a regular price so you won&#8217;t be able to match every regular price ticket with a sale price ticket.<br \/>\n0.65(3.29) = 2.14<br \/>\n0.65(4.19) = 2.72<br \/>\n0.65(2.79) = 1.81<br \/>\n0.65(3.09) = 2.01<br \/>\n0.65(3.77) = 2.45<\/p>\n<p>Question 15.<br \/>\nCommunicate Mathematical Ideas<br \/>\nFor each situation, give an example that includes the original price and final price after markup or markdown.<br \/>\na. A markdown that is greater than 99% but less than 100%<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nA markdown that is greater than 99% but less than 100% could be 99.5%. If the original price is $100, then the final price is 100 &#8211; 100(0.995) = 100 &#8211; 99.50 = 0.50<\/p>\n<p>Question 15.<br \/>\nb. A markdown that is less than 1%<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nA markdown that is less then 1% could be 0.5%. If the original price is $100, then the final price would be 100 &#8211; 0.005(100) = 100 &#8211; 0.50 = 99.50<\/p>\n<p>Question 15.<br \/>\nc. A markup that is more than 200%<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nA markup that is more than 200% could be 300%. If the original price is $100, then the final price would be 100 + 100 (3.00) = 100 + 300 = 400<\/p>\n<h3><a id=\"Rewriting_Percent_Expressions_Page_No_152\"><\/a>Rewriting Percent Expressions &#8211; Page No. 152<\/h3>\n<p>Question 16.<br \/>\nRepresent Real-World Problems<br \/>\nHarold works at a men\u2019s clothing store, which marks up its retail clothing by 27%. The store purchases pants for $74.00, suit jackets for $325.00, and dress shirts for $48.00. How much will Harold charge a customer for two pairs of pants, three dress shirts, and a suit jacket?<br \/>\n$ __________<\/p>\n<p>Answer: $783.59<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nHarold works at a men\u2019s clothing store, which marks up its retail clothing by 27%.<br \/>\nThe store purchases pants for $74.00, suit jackets for $325.00, and dress shirts for $48.00.<br \/>\nIf the markup is 27%, then the expression for the retail price is p + 0.27p = 1.27p<br \/>\nwhere p is the original price.<br \/>\nThe retail price of the pants is then 1.27(74) = 93.98.<br \/>\nThe retail price of the suit jackets is 1.27(325) = 412.75<br \/>\nThe retail price of the dress shirts is 1.27(48) = 60.96<br \/>\nThe total for two pants, three dress shirts, and one suit jacket would then be 2(93.98) + 3(60.96) + 412.75<br \/>\n= 187.96 + 182.88 + 412.75 = 783.59<\/p>\n<p>Question 17.<br \/>\nAnalyze Relationships<br \/>\nYour family needs a set of 4 tires. Which of the following deals would you prefer? Explain.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-11.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 2: Rewriting Percent Expressions img 11\" width=\"540\" height=\"36\" \/><br \/>\nType below:<br \/>\n____________<\/p>\n<p>Answer: I and III<\/p>\n<p>Explanation:<br \/>\nThe percent discount for buying 3 tires and getting one free is 25% since you are getting 1\/4 of the tires for free and 1\/4 off = 25%.<br \/>\nThis means deal (I) and deal (III) are the same. They are greater than a 20% discount so deals (I) and (III) are preferable.<\/p>\n<p><strong>H.O.T.<\/strong><\/p>\n<p><strong>Focus on Higher Order Thinking<\/strong><\/p>\n<p>Question 18.<br \/>\nCritique Reasoning<br \/>\nMargo purchases bulk teas from a warehouse and marks up those prices by 20% for retail sale. When teas go unsold for more than two months, Margo marks down the retail price by 20%. She says that she is breaking even, that is, she is getting the same price for the tea that she paid for it. Is she correct? Explain.<br \/>\n_______<\/p>\n<p>Answer:<br \/>\nShe is not correct. If she originally purchases the teas for $100 and then marks the price up 20%,<br \/>\nthe retail price would then be 100 + 0.20(100) = 100 + 20 = 120.<br \/>\nThe sales price would then be 120 &#8211; 0.2(120) = 120 &#8211; 24 = 96.<br \/>\nThis is less than the purchase price so she is losing money, and not breaking even.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168872\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-152-Q19.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 152 Q19\" width=\"683\" height=\"797\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-152-Q19.png 683w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-152-Q19-257x300.png 257w\" sizes=\"(max-width: 683px) 100vw, 683px\" \/><\/p>\n<p>Question 20.<br \/>\nPersevere in Problem-Solving<br \/>\nAt Danielle\u2019s clothing boutique, if an item does not sell for eight weeks, she marks it down by 15%. If it remains unsold after that, she marks it down an additional 5% each week until she can no longer make a profit. Then she donates it to charity.<\/p>\n<p>Rafael wants to buy a coat originally priced at $150, but he can\u2019t afford more than $110. If Danielle paid $100 for the coat, during which week(s) could Rafael buy the coat within his budget? Justify your answer.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe expression for the markdown on the 8th week is p &#8211; 0.15p = 0.85p since it will get marked down 15% on the 8th week.<br \/>\nThe expression for the additional markdowns is p &#8211; 0.05p = 0.95p since it will get marked down an additional 5% every week after the 8th week.<br \/>\nOn the 8th week, it will be marked down to 0.85(150) = 127.50. This is more than Rafael can afford.<br \/>\nOn the 9th week, it will be marked down to 0.95(127.50) = 121.13. This is still more than Rafael can afford.<br \/>\nOn the 10th week, it will be marked down to 0.95(121.13) = 115.07. This is still more than Rafael can afford.<br \/>\nOn the 11th week, it will be marked down to 0.95(115.07) = 109.32. Rafael can afford this price so he must wait until the 11th week.<\/p>\n<h3><a id=\"Applications_of_Percent_Guided_Practice_Page_No_156\"><\/a>Applications of Percent &#8211; Guided Practice &#8211; Page No. 156<\/h3>\n<p>Question 1.<br \/>\n5% of $30 =<br \/>\n$ _______<\/p>\n<p>Answer: $1.5<\/p>\n<p>Explanation:<br \/>\nWe have to find:<br \/>\n5% of $30<br \/>\n0.50 \u00d7 30 = $1.5<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168873\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q2.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 156 Q2\" width=\"252\" height=\"267\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168874\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q3.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 156 Q3\" width=\"291\" height=\"277\" \/><\/p>\n<p>Question 4.<br \/>\n150% of $22 =<br \/>\n$ _______<\/p>\n<p>Answer: $33<\/p>\n<p>Explanation:<br \/>\nWe have to find:<br \/>\n150% of $22<br \/>\n1.5 \u00d7 22 = 33<\/p>\n<p>Question 5.<br \/>\n1% of $80 =<br \/>\n$ _______<\/p>\n<p>Answer: $0.8<\/p>\n<p>Explanation:<br \/>\nWe have to find:<br \/>\n1% of $80<br \/>\n0.01 \u00d7 80 = 0.8<\/p>\n<p>Question 6.<br \/>\n200% of $5 =<br \/>\n$ _______<\/p>\n<p>Answer: $10<\/p>\n<p>Explanation:<br \/>\nWe have to find:<br \/>\n200% of $5<br \/>\n2 \u00d7 5 = 10<\/p>\n<p>Question 7.<br \/>\nBrandon buys a radio for $43.99 in a state where the sales tax is 7%.<br \/>\na. How much does he pay in taxes?<br \/>\n$ _______<\/p>\n<p>Answer: 3.08<\/p>\n<p>Explanation:<br \/>\nWe have to find the amount he pays in taxes by multiplying the cost by the sales tax percentage in decimal form remember to round to 2 decimal places.<br \/>\n43.99(0.07) = 3.08<\/p>\n<p>Question 7.<br \/>\nb. What is the total Brandon pays for the radio?<br \/>\n$ _______<\/p>\n<p>Answer: 47.07<\/p>\n<p>Explanation:<br \/>\nTo find the total Brandon pays for the radio we have to add the sales tax amount to the cost to find the total amount he pays.<br \/>\n43.99 + 3.08 = 47.07<br \/>\nThus the total Brandon pays for the radio is $47.07.<\/p>\n<p>Question 8.<br \/>\nLuisa\u2019s restaurant bill comes to $75.50, and she leaves a 15% tip. What is Luisa\u2019s total restaurant bill?<br \/>\n$ _______<\/p>\n<p>Answer: $86.25<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nLuisa\u2019s restaurant bill comes to $75.50, and she leaves a 15% tip.<br \/>\nUse the formula for the total restaurant bill:<br \/>\nT = P + x. P<br \/>\nWhere T represents the total bill, P represents Luisa&#8217;s bill and x represents percents for tip, then the total restaurant bill is:<br \/>\nT = 75 + 0.15 (75)<br \/>\nT = 75 + 11.25<br \/>\nT = $86.25<br \/>\nTherefore Lusia&#8217;s total restaurant bill is $86.25<\/p>\n<p>Question 9.<br \/>\nJoe borrowed $2,000 from the bank at a rate of 7% simple interest per year. How much interest did he pay in 5 years?<br \/>\n$ _______<\/p>\n<p>Answer: 700<\/p>\n<p>Explanation:<br \/>\nJoe borrowed $2,000 from the bank at a rate of 7% simple interest per year.<br \/>\nWe have to find the amount of interest per year<br \/>\n2000(0.07) = 140<br \/>\nFind the amount of interest for 5 years<br \/>\n140(5) = 700<br \/>\nThus Joe pays $700 in 5 years.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168875\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q10.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 156 Q10\" width=\"640\" height=\"474\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q10.png 640w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q10-300x222.png 300w\" sizes=\"(max-width: 640px) 100vw, 640px\" \/><\/p>\n<p>Question 11.<br \/>\nMartin finds a shirt on sale for 10% off at a department store. The original price was $20. Martin must also pay 8.5% sales tax.<br \/>\na. How much is the shirt before taxes are applied?<br \/>\n$ _______<\/p>\n<p>Answer: 18<\/p>\n<p>Explanation:<br \/>\nWe have to find the sales price of the shirt<br \/>\n20 &#8211; 0.1(20) = 20 &#8211; 2 = 18<br \/>\nThe price of the shirt before taxes are applied is $18.<\/p>\n<p>Question 11.<br \/>\nb. How much is the shirt after taxes are applied?<br \/>\n$ _______<\/p>\n<p>Answer: 19.53<\/p>\n<p>Explanation:<br \/>\nWe have to find the price after the sales tax<br \/>\n18 + 0.085(18) = 18 + 1.53 = 19.53<br \/>\nThe price of the shirt after taxes are applied is $19.53<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168876\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q12.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 156 Q12\" width=\"689\" height=\"490\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q12.png 689w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-156-Q12-300x213.png 300w\" sizes=\"(max-width: 689px) 100vw, 689px\" \/><\/p>\n<p><strong>Essential Question Check-In<\/strong><\/p>\n<p>Question 13.<br \/>\nHow can you determine the total cost of an item including tax if you know the price of the item and the tax rate?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: You can find the total cost of an item including tax by first multiplying the price of the item by the tax rate in decimal form to get the amount of sales tax. Then add the amount of sales tax to the price to get the total cost.<\/p>\n<h3><a id=\"Applications_of_Percent_Independent_Practice_Page_No_157\"><\/a>Applications of Percent &#8211; Independent Practice &#8211; Page No. 157<\/h3>\n<p>Question 14.<br \/>\nEmily\u2019s meal costs $32.75 and Darren\u2019s meal costs $39.88. Emily treats Darren by paying for both meals and leaves a 14% tip. Find the total cost.<br \/>\n$ _______<\/p>\n<p>Answer: 82.80<\/p>\n<p>Explanation:<br \/>\nEmily&#8217;s meal costs $32.75 and Darren\u2019s meal costs $39.88.<br \/>\nSo, the total cost of the meals before tip is $32.75 + $39.88 = $72.63<br \/>\nEmily treats Darren by paying for both meals and leaves a 14% tip.<br \/>\n$72.63 = 0.14(72.63) \u2248 $10.17<br \/>\nRound to two decimal places since dollar amounts must be rounded to the nearest cent.<br \/>\nThe total cost that Dareen pays is then cost before tip + amount of tip = $72.63 + $10.17 = $82.80<\/p>\n<p>Question 15.<br \/>\nThe Jayden family eats at a restaurant that is having a 15% discount promotion. Their meal costs $78.65, and they leave a 20% tip. If the tip applies to the cost of the meal before the discount, what is the total cost of the meal?<br \/>\n$ _______<\/p>\n<p>Answer: 82.58<\/p>\n<p>Explanation:<br \/>\nThe Jayden family eats at a restaurant that is having a 15% discount promotion.<br \/>\nThe total cost of the meal = cost of meal + tip amount &#8211; discount amount<br \/>\nTheir meal costs $78.65, and they leave a 20% tip.<br \/>\nWe need to find the tip amount and the discount amount using the given cost of the meal, tip percent, and discount percent.<br \/>\n20% of 78.65 = 0.20 \u00d7 78.65 = $15.73<br \/>\nSince the cost of the meal before the discount is $78.65 and the discount percentage is 15%, then the amount of the discount is<br \/>\n15% of 78365 = 0.15 \u00d7 $78.65 \u2248 $11.80<br \/>\nThe total cost is then<br \/>\n78.65 + 15.73 &#8211; 11.80 = $82.58<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168877\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-157-Q16.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 157 Q16\" width=\"656\" height=\"509\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-157-Q16.png 656w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-157-Q16-300x233.png 300w\" sizes=\"(max-width: 656px) 100vw, 656px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168878\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-157-Q17.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 157 Q17\" width=\"702\" height=\"427\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-157-Q17.png 702w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-157-Q17-300x182.png 300w\" sizes=\"(max-width: 702px) 100vw, 702px\" \/><\/p>\n<p>Question 18.<br \/>\nKedar earns a monthly salary of $2,200 plus a 3.75% commission on the amount of his sales at a men\u2019s clothing store. What would he earn this month if he sold $4,500 in clothing? Round to the nearest cent.<br \/>\n$ _______<\/p>\n<p>Answer: 2368.75<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nKedar earns a monthly salary of $2,200 plus a 3.75% commission on the amount of his sales at a men\u2019s clothing store.<br \/>\n4500 \u00d7 0.0375 = 168.75<br \/>\nThe total earnings can be known by adding his monthly salary and his commission.<br \/>\n2200 + 168.75 = 2368.75<\/p>\n<p>Question 19.<br \/>\nDanielle earns a 7.25% commission on everything she sells at the electronics store where she works. She also earns a base salary of $750 per week. How much did she earn last week if she sold $4,500 in electronics merchandise? Round to the nearest cent.<br \/>\n$ _______<\/p>\n<p>Answer: 1076.25<\/p>\n<p>Explanation:<br \/>\nDanielle earns a 7.25% commission on everything she sells at the electronics store where she works.<br \/>\nShe also earns a base salary of $750 per week.<br \/>\nThe amount she made in the commission is 4500 \u00d7 0.0725 = 326.25<br \/>\nWe can find the total earnings by adding her weekly pay and commission.<br \/>\n750 + 326.25 = 1076.25<br \/>\nThus she earns $1076.25 last week if she sold $4,500 in electronics merchandise.<\/p>\n<p>Question 20.<br \/>\nFrancois earns a weekly salary of $475 plus a 5.5% commission on sales at a gift shop. How much would he earn in a week if he sold $700 in goods? Round to the nearest cent.<br \/>\n$ _______<\/p>\n<p>Answer: 513.50<\/p>\n<p>Explanation:<br \/>\nGiven that, Francois earns a weekly salary of $475 plus a 5.5% commission on sales at a gift shop.<br \/>\nThe amount he made in commission<br \/>\n700 \u00d7 0.055 = 38.50<br \/>\nWe can find the total amount he earned by adding his weekly pay and commission<br \/>\n475 + 38.50 = $513.50<\/p>\n<p>Question 21.<br \/>\nSandra is 4 feet tall. Pablo is 10% taller than Sandra, and Michaela is 8% taller than Pablo<br \/>\na. Explain how to find Michaela\u2019s height with the given information.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nFirst, we have to find 10% of Sandra&#8217;s height: 0.10 \u00d7 4 = 0.4<br \/>\nThis means that Pablo is then 4 + 0.4 = 4.4 feet tall.<br \/>\nNext find 8% of Pablo&#8217;s height: 4.4 \u00d7 0.08 = 0.352<br \/>\nThis means that Michaela is 4.4 + 0.353 = 4.752 feet tall.<\/p>\n<p>Question 21.<br \/>\nb. What is Michaela\u2019s approximate height in feet and inches?<br \/>\n_______ feet _______ inches<\/p>\n<p>Answer:<br \/>\nConvert from feet to inches.<br \/>\n1 feet = 12 inches<br \/>\n4.752 = 4 + 0.752<br \/>\n0.752 = 12 \u00d7 0.752 = 9 inches<br \/>\n4 feet = 12 \u00d7 4 = 48 inches<br \/>\nThus the approximate height of Michaela is 4 feet 9 inches.<\/p>\n<p>Question 22.<br \/>\nEugene wants to buy jeans at a store that is giving $10 off everything. The tag on the jeans is marked 50% off. The original price is $49.98.<br \/>\na. Find the total cost if the 50% discount is applied before the $10 discount.<br \/>\n$ _______<\/p>\n<p>Answer: $14.99<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nEugene wants to buy jeans at a store that is giving $10 off everything.<br \/>\nThe tag on the jeans is marked 50% off. The original price is $49.98.<br \/>\n0.5 \u00d7 49.98 = 24.99<br \/>\nNow subtract $10 discount.<br \/>\n24.99 &#8211; 10 = 14.99<br \/>\nThe total cost if the 50% discount is applied before the $10 discount is $14.99<\/p>\n<p>Question 22.<br \/>\nb. Find the total cost if the $10 discount is applied before the 50% discount.<br \/>\n$ _______<\/p>\n<p>Answer: $19.99<\/p>\n<p>Explanation:<br \/>\nWe have to find the price after the $10 discount and then find 50% of that price to find the discounted price.<br \/>\n49.98 &#8211; 10 = 39.98<br \/>\n0.5 \u00d7 39.98 = 19.99<br \/>\nThus the total cost if the $10 discount is applied before the 50% discount is $19.99<\/p>\n<h3><a id=\"Applications_of_Percent_Page_No_158\"><\/a>Applications of Percent &#8211; Page No. 158<\/h3>\n<p>Question 23.<br \/>\nMultistep<br \/>\nEric downloads the coupon shown and goes shopping at Gadgets Galore, where he buys a digital camera for $95 and an extra battery for $15.99.<br \/>\na. What is the total cost if the coupon is applied to the digital camera?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-12.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 3: Applications of Percent img 12\" width=\"228\" height=\"145\" \/><br \/>\n$ _______<\/p>\n<p>Answer: 101.49<\/p>\n<p>Explanation:<br \/>\nUse the formula for the discount price:<br \/>\nDP = P &#8211; x.P<br \/>\nPrice for the digital camera:<br \/>\nDP = 95 &#8211; 0.1(95)<br \/>\nDP = 95 &#8211; 9.5<br \/>\nDP = $85.5<br \/>\nTotal cost = 85.5 + 15.99 = $101.49<\/p>\n<p>Question 23.<br \/>\nb. What is the total cost if the coupon is applied to the extra battery?<br \/>\n$ _______<\/p>\n<p>Answer: 109.391<\/p>\n<p>Explanation:<br \/>\nUse the formula for the discount price:<br \/>\nDP = P &#8211; x.P<br \/>\nPrice for the digital camera:<br \/>\nDP = 15.99 &#8211; 0.1(15.99)<br \/>\nDP = 15.99 &#8211; 1.599<br \/>\nDP = $14.399<br \/>\nTotal cost = 95 + 14.399 = $109.391<\/p>\n<p>Question 23.<br \/>\nc. To which item should Eric apply the discount? Explain.<br \/>\n____________<\/p>\n<p>Answer: He should apply the discount to the digital camera because then the total cost is lower.<\/p>\n<p>Question 23.<br \/>\nd. Eric has to pay 8% sales tax after the coupon is applied. How much is his total bill?<br \/>\n$ _______<\/p>\n<p>Answer:<br \/>\nUse the formula for Discount price<br \/>\nIf he uses a coupon for the digital camera then his total cost will be<br \/>\nT = DP + 0.08 \u00d7 DP<br \/>\nT = 101.49 + 8.1192<br \/>\nT = $109.6029<br \/>\nIf he uses a coupon for the extra battery his total cost will be<br \/>\nT = DP + 0.08 \u00d7 DP<br \/>\nT = 109.391 + 0.08(109.391)<br \/>\nT = $118.14228<\/p>\n<p>Question 24.<br \/>\nTwo stores are having sales on the same shirts. The sale at Store 1 is \u201c2 shirts for $22\u201d and the sale at Store 2 is \u201cEach $12.99 shirt is 10% off\u201d.<br \/>\na. Explain how much will you save by buying at Store 1.<br \/>\n$ _______<\/p>\n<p>Answer:<br \/>\nFor store 1, the shirts are 2 for $22. Each shirt then costs $22 \u00f7 2 = $11<br \/>\nAt store 2, each shirt is 10% off of $12.99 so each shirt costs:<br \/>\n$12.99 &#8211; 0.1(12.99) = $12.99 &#8211; $1.30 = $11.69<br \/>\nYou will then save $11.69 &#8211; $11.00 = 0.69 per shirt if you buy them from Store 1.<\/p>\n<p>Question 24.<br \/>\nb. If Store 3 has shirts originally priced at $20.98 on sale for 55% off, does it have a better deal than the other stores? Justify your answer.<br \/>\n_______<\/p>\n<p>Answer:<br \/>\nIf Store 3 sells shirts at 55% off of $20.98, then each shirt costs:<br \/>\n$20.98 &#8211; 0.55($20.98) = $20.98 &#8211; $11.54 = $9.44<br \/>\nThis is lower than the costs per shirt of Store 1 and Store 2 so it has a better deal.<\/p>\n<p><strong>H.O.T.<\/strong><\/p>\n<p><strong>Focus on Higher Order Thinking<\/strong><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168879\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-158-Q25.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 158 Q25\" width=\"665\" height=\"484\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-158-Q25.png 665w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-158-Q25-300x218.png 300w\" sizes=\"(max-width: 665px) 100vw, 665px\" \/><\/p>\n<p>Question 26.<br \/>\nMultistep<br \/>\nIn chemistry class, Bob recorded the volume of a liquid as 13.2 mL. The actual volume was 13.7 mL. Use the formula to find the percent error of Bob\u2019s measurement to the nearest tenth of a percent.<br \/>\n_______ %<\/p>\n<p>Answer: 3.6%<\/p>\n<p>Explanation:<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-3.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Lesson 1: Percent Increase and Decrease img 3\" width=\"443\" height=\"52\" \/><br \/>\n|13.2 &#8211; 13.7|\/13.7 = |-0.5|\/13.7<br \/>\n0.5\/13.7 \u2248 0.036 = 3.6%<\/p>\n<h3><a id=\"MODULE_QUIZ_5.1_Percent_Increase_and_Decrease_Page_No_159\"><\/a>MODULE QUIZ &#8211; 5.1 Percent Increase and Decrease &#8211; Page No. 159<\/h3>\n<p><strong>Find the percent change from the first value to the second.<\/strong><\/p>\n<p>Question 1.<br \/>\n36; 63<br \/>\n_______ %<\/p>\n<p>Answer: 75%<\/p>\n<p>Explanation:<br \/>\nUse the formula percent change = amount of change\/first value<br \/>\namount of change = 27<br \/>\nFirst value = 36<br \/>\n(63 &#8211; 36)\/36 = 27\/36 = 0.75 = 75%<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168880\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q2.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 159 Q2\" width=\"422\" height=\"458\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q2.png 422w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q2-276x300.png 276w\" sizes=\"(max-width: 422px) 100vw, 422px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168881\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q3.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 159 Q3\" width=\"380\" height=\"410\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q3.png 380w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q3-278x300.png 278w\" sizes=\"(max-width: 380px) 100vw, 380px\" \/><\/p>\n<p><strong>5.2 Markup and Markdown<\/strong><\/p>\n<p><strong>Use the original price and the markdown or markup to find the retail price.<\/strong><\/p>\n<p>Question 5.<br \/>\nOriginal price: $60; Markup: 15%<br \/>\n$ _______<\/p>\n<p>Answer: $69<\/p>\n<p>Explanation:<br \/>\nUse the formula retail price = original price + markup<br \/>\n60 + 60 \u00d7 0.15 = 60 + 9= 69<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168882\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q6.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 159 Q6\" width=\"425\" height=\"343\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q6.png 425w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q6-300x242.png 300w\" sizes=\"(max-width: 425px) 100vw, 425px\" \/> <img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168883\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q7.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 159 Q7\" width=\"493\" height=\"301\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q7.png 493w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-159-Q7-300x183.png 300w\" sizes=\"(max-width: 493px) 100vw, 493px\" \/><\/p>\n<p>Question 8.<br \/>\nOriginal price: $125; Markdown: 30%<br \/>\n$ _______<\/p>\n<p>Answer: 87.50<\/p>\n<p>Explanation:<\/p>\n<p>Use the formula retail price = original price + markup<\/p>\n<p>125 &#8211; 125 \u00d7 0.3 = 125 &#8211; 37.50 = 87.50<\/p>\n<p><strong>5.3 Applications of Percent<\/strong><\/p>\n<p>Question 9.<br \/>\nMae Ling earns a weekly salary of $325 plus a 6.5% commission on sales at a gift shop. How much would she make in a work week if she sold $4,800 worth of merchandise?<br \/>\n$ _______<\/p>\n<p>Answer: 637<\/p>\n<p>Explanation:<\/p>\n<p>Mae Ling weekly earnings is equal to her weekly salary plus her commission.<\/p>\n<p>Since she earns 6.5 % commission on sales, if she sold $4800 worth of merchandise, her commission earnings\u00a0 would be 6.5 % of 4800 = 0.065 \u00d7 4800 = $312.<\/p>\n<p>Since her weekly salary is 325, then her total weekly earnings is $325 + $312 = $637<\/p>\n<p>Question 10.<br \/>\nRamon earns $1,735 each month and pays $53.10 for electricity. To the nearest tenth of a percent, what percent of Ramon\u2019s earnings are spent on electricity each month?<br \/>\n_______ %<\/p>\n<p>Answer: 3.1%<\/p>\n<p>Explanation:<\/p>\n<p>Divide the electric payment by his monthly pay<\/p>\n<p>53.10\/1735 = 0.031 = 3.1%<\/p>\n<p>Question 11.<br \/>\nJames, Priya, and Siobhan work in a grocery store. James makes $7.00 per hour. Priya makes 20% more than James, and Siobhan makes 5% less than Priya. How much does Siobhan make per hour?<br \/>\n$ _______<\/p>\n<p>Answer: 7.98 per hour<\/p>\n<p>Explanation:<\/p>\n<p>Since James makes $7 per hour and priya makes 20% more than this, find 20% of 7 and then add that to 7 to find the pay per hour for Priya.<\/p>\n<p>7 + 0.2(7) = 7 + 1.40 = 8.40<\/p>\n<p>Since Priya makes $8.40 per hour and Siobhan makes 5% less than this, find 5% of 8.40 and subtract that from 8.40 to find the pay per hour of Siobhan.<\/p>\n<p>8.40 &#8211; 0.05(8.40) = 8.40 &#8211; 0.42 = 7.98<\/p>\n<p>Question 12.<\/p>\n<p>The Hu family goes out for lunch, and the price of the meal is $45. The sales tax on the meal is 6%, and the family also leaves a 20% tip on the pre-tax amount. What is the total cost of the meal?<br \/>\n$ _______<\/p>\n<p>Answer: 56.70<\/p>\n<p>Explanation:<\/p>\n<p>Find the amount of tax<\/p>\n<p>45 \u00d7 0.06 = 2.70<\/p>\n<p>Find the amount of tip<\/p>\n<p>45 \u00d7 0.20 = 9<\/p>\n<p>Find the total cost by adding the cost of the meal, the tax, and the tip.<\/p>\n<p>45 + 2.70 + 9 = $56.70<\/p>\n<p><strong>Essential Question<\/strong><\/p>\n<p>Question 13.<br \/>\nGive three examples of how percents are used in the real-world. Tell whether each situation represents a percent increase or a percent decrease.<br \/>\nType below:<br \/>\n____________<\/p>\n<p>Answer:<\/p>\n<p>One example could be giving a tip when you eat at a restaurant. Since the cost increases, it represents a percent increase.<\/p>\n<p>Second example is tax on purchase. Since the price increases it is a percent increase.<\/p>\n<p>Third example is using a coupon when buying an item. Since the price decreases, it is a percent decrease.<\/p>\n<h3><a id=\"Selected_Response_Page_No_160\"><\/a>Selected Response &#8211; Page No. 160<\/h3>\n<p>Question 1.<br \/>\nZalmon walks \\(\\frac{3}{4}\\) of a mile in \\(\\frac{3}{10}\\) of an hour. What is his speed in miles per hour?<br \/>\nOptions:<br \/>\na. 0.225 miles per hour<br \/>\nb. 2.3 miles per hour<br \/>\nc. 2.5 miles per hour<br \/>\nd. 2.6 miles per hour<\/p>\n<p>Answer: 2.5 miles per hour<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nZalmon walks \\(\\frac{3}{4}\\) of a mile in \\(\\frac{3}{10}\\) of an hour.<br \/>\nDivide the number of miles by the number of hours to get his speed in miles per hour.<br \/>\n\\(\\frac{3}{4}\\) \u00f7 \\(\\frac{3}{10}\\)<br \/>\n\\(\\frac{3}{4}\\) \u00f7 \\(\\frac{10}{3}\\) = \\(\\frac{5}{2}\\)<br \/>\nConvert the fraction into decimal form.<br \/>\n\\(\\frac{5}{2}\\) = 2.5 miles per hour<br \/>\nThus the correct answer is option C.<\/p>\n<p>Question 2.<br \/>\nFind the percent change from 70 to 56.<br \/>\nOptions:<br \/>\na. 20% decrease<br \/>\nb. 20% increase<br \/>\nc. 25% decrease<br \/>\nd. 25% increase<\/p>\n<p>Answer: 20% increase<\/p>\n<p>Explanation:<br \/>\nUse the percent change = amount of change\/original amount.<br \/>\nSince the number decreased from 70 to 56, it is a percent decrease.<br \/>\n= (70 &#8211; 56)\/70 = \\(\\frac{14}{70}\\) = 0.2 = 20%<br \/>\nThus the correct answer is option A.<\/p>\n<p>Question 3.<br \/>\nThe rainfall total two years ago was 10.2 inches. Last year\u2019s total was 20% greater. What was last year\u2019s rainfall total?<br \/>\nOptions:<br \/>\na. 8.16 inches<br \/>\nb. 11.22 inches<br \/>\nc. 12.24 inches<br \/>\nd. 20.4 inches<\/p>\n<p>Answer: 12.24 inches<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nThe rainfall total two years ago was 10.2 inches. Last year\u2019s total was 20% greater.<br \/>\nFind 20% of 10.2<br \/>\n10.2 \u00d7 0.20 = 2.04<br \/>\nAdd the value to the original amount of 10.2<br \/>\n10.2 + 2.04 = 12.24<br \/>\nTherefore the correct answer is option C.<\/p>\n<p>Question 4.<br \/>\nA pair of basketball shoes was originally priced at $80 but was marked up by 37.5%. What was the retail price of the shoes?<br \/>\nOptions:<br \/>\na. $50<br \/>\nb. $83<br \/>\nc. $110<br \/>\nd. $130<\/p>\n<p>Answer: $110<\/p>\n<p>Explanation:<br \/>\nA pair of basketball shoes was originally priced at $80 but was marked up by 37.5%.<br \/>\nUse the formula retail price = original price + markup<br \/>\n80 + 80 \u00d7 0.375 = 80 + 30 = 110<br \/>\nThus the correct answer is option C.<\/p>\n<p>Question 5.<br \/>\nThe sales tax rate in Jan\u2019s town is 7.5%. If she buys 3 lamps for $23.59 each and a sofa for $769.99, how much sales tax does she owe?<br \/>\nOptions:<br \/>\na. $58.85<br \/>\nb. $63.06<br \/>\nc. $67.26<br \/>\nd. $71.46<\/p>\n<p>Answer: $63.06<\/p>\n<p>Explanation:<br \/>\nThe sales tax rate in Jan\u2019s town is 7.5%.<br \/>\nIf she buys 3 lamps for $23.59 each and a sofa for $769.99<br \/>\nTotal cost before tax is 3 \u00d7 23.59 + 769.99<br \/>\n= 70.77 + 769.99 = 840.76<br \/>\nFind the amount of tax by multiplying the tax rate and total cost from the above solution and then round to 2 decimal place.<br \/>\n840.76 \u00d7 0.075 = 63.06<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 6.<br \/>\nThe day after a national holiday, decorations were marked down 40%. Before the holiday, a patriotic banner cost $5.75. How much did the banner cost after the holiday?<br \/>\nOptions:<br \/>\na. $1.15<br \/>\nb. $2.30<br \/>\nc. $3.45<br \/>\nd. $8.05<\/p>\n<p>Answer: $3.45<\/p>\n<p>Explanation:<br \/>\nThe day after a national holiday, decorations were marked down 40%. Before the holiday, a patriotic banner cost $5.75.<br \/>\nuse the formula retail price = original price &#8211; markdown<br \/>\n5.75 &#8211; 5.75 \u00d7 0.4 = 5.75 &#8211; 2.30 = 3.45<br \/>\nThus the correct answer is option C.<\/p>\n<p>Question 7.<br \/>\nDustin makes $2,330 each month and pays $840 for rent. To the nearest tenth of a percent, what percent of Dustin\u2019s earnings are spent on rent?<br \/>\nOptions:<br \/>\na. 84%<br \/>\nb. 63.9%<br \/>\nc. 56.4%<br \/>\nd. 36.1%<\/p>\n<p>Answer: 36.1%<\/p>\n<p>Explanation:<br \/>\nDustin makes $2,330 each month and pays $840 for rent.<br \/>\nDivide his rent by his monthly income. round to three decimal places and then convert to percent form.<br \/>\n840\/2330 = 0.361 = 36.1%<br \/>\nThus the correct answer is option D.<\/p>\n<p>Question 8.<br \/>\nA scuba diver is positioned at -30 feet. How many feet will she have to rise to change her position to -12 feet?<br \/>\nOptions:<br \/>\na. -42 ft<br \/>\nb. -18 ft<br \/>\nc. 18 ft<br \/>\nd. 42 ft<\/p>\n<p>Answer: 18 ft<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nA scuba diver is positioned at -30 feet.<br \/>\n-12 &#8211; (-30) = 12 + 30 = 18 feet<br \/>\nThus the correct answer is option C.<\/p>\n<p>Question 9.<br \/>\nA bank offers an annual simple interest rate of 8% on home improvement loans. Tobias borrowed $17,000 over a period of 2 years. How much did he repay altogether?<br \/>\nOptions:<br \/>\na. $1360<br \/>\nb. $2720<br \/>\nc. $18360<br \/>\nd. $19720<\/p>\n<p>Answer: $19720<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nA bank offers an annual simple interest rate of 8% on home improvement loans.<br \/>\nTobias borrowed $17,000 over a period of 2 years<br \/>\nFind the amount of interest he paid using the formula<br \/>\nI = prt<br \/>\nwhere p is the amount borrowed<br \/>\nr is the interest rate<br \/>\nt is the number of years<br \/>\n17000 \u00d7 0.08 \u00d7 2 = 2720<br \/>\nAdd the amount borrowed and the amount of interest<br \/>\n17000 + 2720 = 19720.<br \/>\nThus the correct answer is option D.<\/p>\n<p><strong>Mini-Task<\/strong><\/p>\n<p>Question 10.<br \/>\nThe granola Summer buys used to cost $6.00 per pound, but it has been marked up 15%.<br \/>\na. How much did it cost Summer to buy 2.6 pounds of granola at the old price?<br \/>\n$ ___________<\/p>\n<p>Answer: $15.60<\/p>\n<p>Explanation:<br \/>\nMultiply 2.6 by the old price of $6<br \/>\n2.6 \u00d7 6 = 15.60<br \/>\nIt costs $15.60 to buy 2.6 pounds of granola at the old price.<\/p>\n<p>Question 10.<br \/>\nb. How much does it cost her to buy 2.6 pounds of granola at the new price?<br \/>\n$ _______<\/p>\n<p>Answer: $17.94<\/p>\n<p>Explanation:<br \/>\nFind the new price using the formula retail price = original price + markup<br \/>\nThen find the total cost by buying 2.6 pounds at the new price.<br \/>\n6 + 6 \u00d7 0.15 = 6 + 0.9 = 6.90<br \/>\n2.6 \u00d7 6.90 = 17.94<br \/>\nThe new price is $17.94<\/p>\n<p>Question 10.<br \/>\nc. Suppose Summer buys 3.5 pounds of granola. How much more does it cost at the new price than at the old price?<br \/>\n$ _______<\/p>\n<p>Answer: $3.15<\/p>\n<p>Explanation:<br \/>\n3.5 \u00d7 6 = 21<br \/>\n3.5 \u00d7 6.90 = 24.15<br \/>\n24.15 &#8211; 21 = 3.15<\/p>\n<h3><a id=\"Module_5_Page_No_162\"><\/a>Module 5 &#8211; Page No. 162<\/h3>\n<p><strong>EXERCISES<\/strong><\/p>\n<p>Question 1.<br \/>\nMichelle purchased 25 audio files in January. In February she purchased 40 audio files. Find the percent increase.<br \/>\n_______ %<\/p>\n<p>Answer: 60%<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nMichelle purchased 25 audio files in January. In February she purchased 40 audio files.<br \/>\nUse the percent change = amount of change\/original amount.<br \/>\n(40 -25)\/25 = 15\/25 = 0.6 = 60%<br \/>\nThus the percent increase is 60%<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168885\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-162-Q2.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 162 Q2\" width=\"687\" height=\"487\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-162-Q2.png 687w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-162-Q2-300x213.png 300w\" sizes=\"(max-width: 687px) 100vw, 687px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-168884\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-162-Q3.png\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease Page 162 Q3\" width=\"647\" height=\"531\" srcset=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-162-Q3.png 647w, https:\/\/ccssanswers.com\/wp-content\/uploads\/2022\/05\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-Page-162-Q3-300x246.png 300w\" sizes=\"(max-width: 647px) 100vw, 647px\" \/><\/p>\n<p>Question 4.<br \/>\nA sporting goods store marks up the cost s of soccer balls by 250%. Write an expression that represents the retail cost of the soccer balls. The store buys soccer balls for $5.00 each. What is the retail price of the soccer balls?<br \/>\n$ _______<\/p>\n<p>Answer: $17.5<\/p>\n<p>Explanation:<br \/>\nUse the formula retail price = original price + markup to find the expression for an original price of s and a markup percentage of 250%<br \/>\ns + 2.5s = 3.5s<br \/>\nsubstitute s = 5 into the expression to find the retail price<br \/>\n3.5 \u00d7 5 = 17.50<br \/>\nThus the retail price of the soccer balls is $17.50<\/p>\n<h3><a id=\"Unit_2_Performance_Tasks_Page_No_163\"><\/a>Unit 2 Performance Tasks &#8211; Page No. 163<\/h3>\n<p>Question 1.<br \/>\nViktor is a bike tour operator and needs to replace two of his touring bikes. He orders two bikes from the sporting goods store for a total of $2,000 and pays using his credit card. When the bill arrives, he reads the following information:<br \/>\nBalance: $2000<br \/>\nAnnual interest rate: 14.9%<br \/>\nMinimum payment due: $40<br \/>\nLate fee: $10 if payment is not received by 3\/1\/2013<br \/>\na. To keep his good credit, Viktor promptly sends in a minimum payment of $40. When the next bill arrives, it looks a lot like the previous bill.<br \/>\nBalance: $1,984.34<br \/>\nAnnual interest rate: 14.9%<br \/>\nMinimum payment due: $40<br \/>\nLate fee: $10 if payment is not received by 4\/1\/2013<br \/>\nExplain how the credit card company calculated the new balance. Notice that the given interest rate is annual, but the payment is monthly.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nWe have to find the balance after the first bill by subtracting the $40 payment from the original balance of $2000.<br \/>\nBalance after first bill: 2000 &#8211; 40 = 1960<br \/>\nThen find the amount of interest charged on the second bill by multiplying the balance of $1960 by the interest rate.<br \/>\nRemember since the interest rate is annually you have to divide it by 12 to get the monthly interest rate.<br \/>\nInterest on the second bill: 1960 \u00d7 0.149\/12 = 24.34<br \/>\nAnd then add this interest amount to the balance of $1960 to get the balance on the second bill.<br \/>\nNew Balance: 1960 + 24.34 = 1984.34<\/p>\n<p>Question 1.<br \/>\nb. Viktor was upset about the new bill, so he decided to send in $150 for his April payment. The minimum payment on his bill is calculated as 2% of the balance (rounded to the nearest dollar) or $20, whichever is greater. Fill out the details for Viktor\u2019s new bill.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nFind the balance after the $150 payment. The interest rate hasn&#8217;t changed so the annual interest rate on this new bill is the same as the previous bills.<br \/>\nbalance after payment: 1984.34 &#8211; 150 = 1834.34<br \/>\nannual interest rate: 14\/9%<br \/>\nFind the interest charged on the third bill. find the balance on the third bill by adding the interest charged to the balance of $1834.34.<br \/>\ninterest on the third bill: 1834.34 \u00d7 0.149\/12 = 22.78<br \/>\nbalance: 1834.34 + 22.78 = 1857.12<br \/>\nTo find what the minimum payment will be, first find 2% of the balance.<br \/>\n2% of balance: 0.02 \u00d7 1857.12 = 37.14<br \/>\nMinimum payment due: $37.00<br \/>\nSince this is greater than $20, the minimum payment is 2% of the balance rounded to the nearest dollar giving $37 as the payment.<br \/>\nThe later fee date is one month after the late fee date of 04\/01\/2013 on the previous bill which gives 05\/01\/2013.<\/p>\n<p>Question 1.<br \/>\nc. Viktor\u2019s bank offers a credit card with an introductory annual interest rate of 9.9%. He can transfer his current balance for a fee of $40. After one year, the rate will return to the bank\u2019s normal rate, which is 13.9%. The bank charges a late fee of $15. Give two reasons why Viktor should transfer the balance and two reasons why he should not<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Two reasons he should transfer is that the lower introductory rate would mean less interest charged in the first year and a lower normal rate would mean less interest charged after that first year as well. Two reasons he shouldn&#8217;t transfer the balance is that he would have to pay a transfer fee of $40 and that the late fee is $15 instead of $10 if he transfers the balance.<\/p>\n<h3><a id=\"Unit_2_Performance_Tasks_Page_No_164\"><\/a>Unit 2 Performance Tasks (con&#8217;td) &#8211; Page No. 164<\/h3>\n<p>Question 2.<br \/>\nThe table below shows how far several animals can travel at their maximum speeds in a given time.<br \/>\na. Write each animal\u2019s speed as a unit rate in feet per second.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-13.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease img 13\" width=\"509\" height=\"160\" \/><br \/>\nElk: _________ feet per second<br \/>\nGiraffe: _________ feet per second<br \/>\nZebra: _________ feet per second<\/p>\n<p>Answer:<br \/>\nBy seeing the above table we can find the unit rates by dividing the distance traveled by the time in seconds.<br \/>\nelk: 33 \u00f7 1\/2 = 33 \u00d7\u00a0 2 = 66 feet per second<br \/>\nGiraffe: 115 \u00f7 2 1\/2 = 115 \u00f7 5\/2 = 115 2\/5 = 46 feet per second<br \/>\nZebra: 117 \u00f7 2 = 58.5 feet per second<\/p>\n<p>Question 2.<br \/>\nb. Which animal has the fastest speed?<br \/>\n_____________<\/p>\n<p>Answer: The elk had the greatest unit rate so it has the fastest speed.<\/p>\n<p>Question 2.<br \/>\nc. How many miles could the fastest animal travel in 2 hours if it maintained the speed you calculated in part a? Use the formula d = rt and round your answer to the nearest tenth of a mile. Show your work.<br \/>\nElk: _________ miles<br \/>\nGiraffe: _________ miles<br \/>\nZebra: _________ miles<\/p>\n<p>Answer:<br \/>\nElk: 90 miles<br \/>\nGiraffe: 62 miles<br \/>\nZebra: 72 miles<\/p>\n<p>Explanation:<\/p>\n<p>There are 60 seconds in a minute and 60 minutes in an hour so there are 2 \u00d7 60 \u00d7 60 = 7200 seconds in 2 hours.<br \/>\nMultiply the unit rate of the elk by 7200 seconds to get the distance traveled in feet.<br \/>\nThere are 5280 feet in 1 mile so divide the distance in feet by 5280 to get the distances in miles.<br \/>\nElk:<br \/>\n66 \u00d7 7200 =\u00a0 475200 feet<br \/>\nNow convert from feet to miles<br \/>\n475200 feet = 90 miles<br \/>\nGiraffe: 46 feet per second<br \/>\n62 \u00d7 7200 = 331200 feet<br \/>\nNow convert from feet to miles.<br \/>\n331200 = 62 miles<br \/>\nZebra: 58.5 feet per second<br \/>\n58.5 \u00d7 7200 = 421200 feet<br \/>\nNow convert from feet to miles.<br \/>\n421200 feet = 72 miles<\/p>\n<p>Question 3.<br \/>\nd. The data in the table represents how fast each animal can travel at its maximum speed. Is it reasonable to expect the animal from part b to travel that distance in 2 hours? Explain why or why not.<br \/>\n______<\/p>\n<p>Answer: It is not reasonable. An animal can only travel at its maximum speed for a short amount of time which is usually only for a couple of minutes.<\/p>\n<h3><a id=\"Selected_Response_Page_No_165\"><\/a>Selected Response &#8211; Page No. 165<\/h3>\n<p>Question 1.<br \/>\nIf the relationship between distance y in feet and time x in seconds is proportional, which rate is represented by \\(\\frac{y}{x}\\) = 0.6?<br \/>\nOptions:<br \/>\na. 3 feet in 5 s<br \/>\nb. 3 feet in 9 s<br \/>\nc. 10 feet in 6 s<br \/>\nd. 18 feet in 3 s<\/p>\n<p>Answer: 3 feet in 5 s<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{y}{x}\\) = 0.6<br \/>\n0.6 = \\(\\frac{6}{10}\\)<br \/>\nSince \\(\\frac{6}{10}\\) = \\(\\frac{3}{5}\\), it represents a rate of 3 feet in 5 seconds,<br \/>\nTherefore the correct answer is option A.<\/p>\n<p>Question 2.<br \/>\nThe Baghrams make regular monthly deposits in a savings account. The graph shows the relationship between the number x of months and the amount y in dollars in the account.<br \/>\nWhat is the equation for the deposit?<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-14.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease img 14\" width=\"261\" height=\"214\" \/><br \/>\nOptions:<br \/>\na. \\(\\frac{y}{x}\\) = $25\/month<br \/>\nb. \\(\\frac{y}{x}\\) = $40\/month<br \/>\nc. \\(\\frac{y}{x}\\) = $50\/month<br \/>\nd. \\(\\frac{y}{x}\\) = $75\/month<\/p>\n<p>Answer: \\(\\frac{y}{x}\\) = $50\/month<\/p>\n<p>Explanation:<br \/>\nBy seeing the above graph we can say that the point is (2, 100). This means that \\(\\frac{y}{x}\\) = \\(\\frac{100}{2}\\) = 50.<br \/>\nThus the correct answer is option C.<\/p>\n<p>Question 3.<br \/>\nWhat is the decimal form of \u22124 \\(\\frac{7}{8}\\)?<br \/>\nOptions:<br \/>\na. -4.9375<br \/>\nb. -4.875<br \/>\nc. -4.75<br \/>\nd. -4.625<\/p>\n<p>Answer: -4.875<\/p>\n<p>Explanation:<br \/>\nGiven the fraction<br \/>\n\u22124 \\(\\frac{7}{8}\\)<br \/>\nFirst divide \\(\\frac{7}{8}\\) = 0.875<br \/>\n4 + 0.875 = 4.875<br \/>\nSo, \u22124 \\(\\frac{7}{8}\\) = -4.875<br \/>\nTherefore the answer is option B.<\/p>\n<p>Question 4.<br \/>\nFind the percent change from 72 to 90.<br \/>\nOptions:<br \/>\na. 20% decrease<br \/>\nb. 20% increase<br \/>\nc. 25% decrease<br \/>\nd. 25% increase<\/p>\n<p>Answer: 25% increase<\/p>\n<p>Explanation:<br \/>\nUse the formula percent change = amount of change\/original amount.<br \/>\nthe value increased from 72 to 90 so it is a percent increase.<br \/>\n(90-72)\/72 = 18\/72 = 0.25 = 25%<br \/>\nThus the correct answer is option D.<\/p>\n<p>Question 5.<br \/>\nA store had a sale on art supplies. The price p of each item was marked down by 60%. Which expression represents the new price?<br \/>\nOptions:<br \/>\na. 0.4p<br \/>\nb. 0.6p<br \/>\nc. 1.4p<br \/>\nd. 1.6p<\/p>\n<p>Answer: 0.4p<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nA store had a sale on art supplies.<br \/>\nThe price p of each item was marked down by 60%<br \/>\nUse the formula sale price = original price &#8211; markdown<br \/>\np is the original price and the markdown percent is 40% then combine the like terms.<br \/>\np &#8211; 0.6p = 0.4p<br \/>\nTherefore the correct answer is option A.<\/p>\n<p>Question 6.<br \/>\nClarke borrows $16,000 to buy a car. He pays simple interest at an annual rate of 6% over a period of 3.5 years. How much does he pay altogether?<br \/>\nOptions:<br \/>\na. $18800<br \/>\nb. $19360<br \/>\nc. $19920<br \/>\nd. $20480<\/p>\n<p>Answer: $19360<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nClarke borrows $16,000 to buy a car.<br \/>\nHe pays simple interest at an annual rate of 6% over a period of 3.5 years.<br \/>\nFind the total amount of interest using the formula<br \/>\nI = prt<br \/>\nwhere p is the amount borrowed<br \/>\nr is the rate of interest<br \/>\nt is the number of years<br \/>\n16000 \u00d7 0.06 \u00d7 3.5 = 3360<br \/>\nNow add the amount of interest to the amount borrowed to find the total amount<br \/>\n16000 + 3360 = 19,360<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 7.<br \/>\nTo which set or sets does the number 37 belong?<br \/>\nOptions:<br \/>\na. integers only<br \/>\nb. rational numbers only<br \/>\nc. integers and rational numbers only<br \/>\nd. whole numbers, integers, and rational numbers<\/p>\n<p>Answer: whole numbers, integers, and rational numbers<\/p>\n<p>Explanation:<br \/>\n37 can be written as 37\/1 so it is a rational number. 37 doesn&#8217;t have a decimal or fraction so it is an integer. Since it is a positive integer, it is also a whole number.<br \/>\nThus a suitable answer is option D.<\/p>\n<h3><a id=\"Page_No_166\"><\/a>Page No. 166<\/h3>\n<p>Question 8.<br \/>\nIn which equation is the constant of proportionality 5?<br \/>\nOptions:<br \/>\na. x = 5y<br \/>\nb. y = 5x<br \/>\nc. y = x + 5<br \/>\nd. y = 5 &#8211; x<\/p>\n<p>Answer: y = 5x<\/p>\n<p>Explanation:<br \/>\nDirectly proportional equations are of the form y = kx<br \/>\nwhere k is the constant of proportionality.<br \/>\nIf k = 5, then the equation is y = 5x.<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 9.<br \/>\nSuri earns extra money by dog walking. She charges $6.25 to walk a dog once a day 5 days a week and $8.75 to walk a dog once a day 7 days a week. Which equation represents this relationship?<br \/>\nOptions:<br \/>\na. y = 7x<br \/>\nb. y = 5x<br \/>\nc. y = 2.50x<br \/>\nd. y = 1.25x<\/p>\n<p>Answer: y = 1.25x<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nSuri earns extra money by dog walking. She charges $6.25 to walk a dog once a day 5 days a week and $8.75 to walk a dog once a day 7 days a week.<br \/>\nSince 6.25\/5 = 1.25<br \/>\nSo, the equation is y = 1.25x<br \/>\nwhere x is the number of days and y is the total charge.<br \/>\nSo, the correct answer is option D.<\/p>\n<p>Question 10.<br \/>\nRandy walks \\(\\frac{1}{2}\\) mile in each \\(\\frac{1}{5}\\) hour. How far will Randy walk in one hour?<br \/>\nOptions:<br \/>\na. \\(\\frac{1}{2}\\) miles<br \/>\nb. 2 miles<br \/>\nc. 2 \\(\\frac{1}{2}\\) miles<br \/>\nd. 5 miles<\/p>\n<p>Answer: 2 \\(\\frac{1}{2}\\) miles<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nRandy walks \\(\\frac{1}{2}\\) mile in each \\(\\frac{1}{5}\\) hour.<br \/>\n\\(\\frac{1}{2}\\) \u00f7 \\(\\frac{1}{5}\\)<br \/>\n\\(\\frac{1}{2}\\) \u00d7 \\(\\frac{5}{1}\\) = \\(\\frac{5}{2}\\)<br \/>\nConvert the fraction to the improper fractions.<br \/>\n\\(\\frac{5}{2}\\) = 2 \\(\\frac{1}{2}\\) miles<br \/>\nTherefore the correct answer is option C.<\/p>\n<p>Question 11.<br \/>\nOn a trip to Spain, Sheila bought a piece of jewelry that cost $56.75. She paid for it with her credit card, which charges a foreign transaction fee of 3%. How much was the foreign transaction fee?<br \/>\nOptions:<br \/>\na. $0.17<br \/>\nb. $1.07<br \/>\nc. $1.70<br \/>\nd. $17.00<\/p>\n<p>Answer: $1.70<\/p>\n<p>Explanation:<br \/>\nOn a trip to Spain, Sheila bought a piece of jewelry that cost $56.75.<br \/>\nShe paid for it with her credit card, which charges a foreign transaction fee of 3%<br \/>\nFind the foreign transaction fee amount by multiplying the cost by the foreign transaction fee percentage.<br \/>\n56.75 \u00d7 0.03 = 1.70<br \/>\nThus the correct answer is option C.<\/p>\n<p>Question 12.<br \/>\nA baker is looking for a recipe that has the lowest unit rate for flour per batch of muffins. Which recipe should she use?<br \/>\nOptions:<br \/>\na. \\(\\frac{1}{2}\\) cup flour for \\(\\frac{2}{3}\\) batch<br \/>\nb. \\(\\frac{2}{3}\\) cup flour for \\(\\frac{1}{2}\\) batch<br \/>\nc. \\(\\frac{3}{4}\\) cup flour for \\(\\frac{2}{3}\\) batch<br \/>\nd. \\(\\frac{1}{3}\\) cup flour for \\(\\frac{1}{4}\\) batch<\/p>\n<p>Answer: \\(\\frac{1}{2}\\) cup flour for \\(\\frac{2}{3}\\) batch<\/p>\n<p>Explanation:<br \/>\na. \\(\\frac{1}{2}\\) \u00f7 \\(\\frac{2}{3}\\) = \\(\\frac{1}{2}\\) \u00d7 \\(\\frac{3}{2}\\) = \\(\\frac{3}{4}\\)<br \/>\nb. \\(\\frac{2}{3}\\) \u00f7 \\(\\frac{1}{2}\\) = \\(\\frac{2}{3}\\) \u00d7 \\(\\frac{2}{1}\\) = \\(\\frac{4}{3}\\) = 1 \\(\\frac{1}{3}\\)<br \/>\nc. \\(\\frac{3}{4}\\) \u00f7 \\(\\frac{2}{3}\\) = \\(\\frac{3}{4}\\) \u00d7 \\(\\frac{3}{2}\\) = \\(\\frac{9}{8}\\) = 1 \\(\\frac{1}{8}\\)<br \/>\nd. \\(\\frac{1}{3}\\) \u00f7 \\(\\frac{1}{4}\\) = \\(\\frac{1}{3}\\) \u00f7 \\(\\frac{4}{1}\\) = 1 \\(\\frac{1}{3}\\)<br \/>\nThus the correct answer is option A.<\/p>\n<p><strong>Mini-Task<\/strong><\/p>\n<p>Question 13.<br \/>\nKevin was able to type 2 pages in 5 minutes, 3 pages in 7.5 minutes, and 5 pages in 12.5 minutes.<br \/>\na. Make a table of the data.<br \/>\nType below:<br \/>\n___________<\/p>\n<p>Answer:<\/p>\n<table border=\"2\">\n<tbody>\n<tr>\n<td width=\"104\">Number of Pages<\/td>\n<td width=\"104\">2<\/td>\n<td width=\"104\">3<\/td>\n<td width=\"104\">5<\/td>\n<\/tr>\n<tr>\n<td width=\"104\">Minutes<\/td>\n<td width=\"104\">5<\/td>\n<td width=\"104\">7.5<\/td>\n<td width=\"104\">12.5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Question 13.<br \/>\nb. Graph the relationship between the number of pages typed and the number of minutes.<br \/>\n<img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-15.jpg\" alt=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease img 15\" width=\"199\" height=\"233\" \/><br \/>\nType below:<br \/>\n___________<\/p>\n<p>Answer:<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-7568\" src=\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-15-1.jpg\" alt=\"Go-Math-Grade-7-Answer-Key-Chapter-5-Percent-Increase-and-Decrease-img-15\" width=\"199\" height=\"233\" \/><\/p>\n<p>Question 13.<br \/>\nc. Explain how to use the graph to find the unit rate.<br \/>\nType below:<br \/>\n___________<\/p>\n<p>Answer: The unit rate is 2.5 pages per minute<\/p>\n<p>Explanation:<br \/>\nBy using the graph we need to find the slope of the line.<br \/>\nWe can do this by using the formula of a slope:<br \/>\nm = (y2-y1)\/(x2-x1) = (7.5-5)\/(3-2) = 2.5<br \/>\nThus the unit rate is 2.5 pages per minute.<\/p>\n<p><em>Conclusion:<\/em><\/p>\n<p>Hope the answers provided in Go Math Answer Key Grade 7 Chapter 5 Percent Increase and Decrease are quite satisfactory for all the students. Refer to our Go Math 7th Grade Chapter 5 Percent Increase and Decrease to get the solutions with the best explanations. After your preparation test your math skills by solving the questions in the performance tasks.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Download Go Math Grade 7 Answer Key for Chapter 5 Percent Increase and Decrease pdf for free. Quick and easy learning is possible with Go Math 7th Grade Answer Key Chapter 5 Percent Increase and Decrease. So, we suggest the students of 7th standard to go through the HMH Go Math Grade 7 Key Chapter &#8230; <a title=\"Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease\" class=\"read-more\" href=\"https:\/\/ccssanswers.com\/go-math-grade-7-answer-key-chapter-5-percent-increase-and-decrease\/\" aria-label=\"More on Go Math Grade 7 Answer Key Chapter 5 Percent Increase and Decrease\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":8803,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/ccssanswers.com\/wp-content\/uploads\/2020\/11\/go-math-grade-7-chapter-5-percent-increase-and-decrease-answer-key.jpeg","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/5878"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=5878"}],"version-history":[{"count":3,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/5878\/revisions"}],"predecessor-version":[{"id":168886,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/5878\/revisions\/168886"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media\/8803"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=5878"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=5878"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=5878"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}