{"id":58962,"date":"2022-06-11T19:40:32","date_gmt":"2022-06-11T14:10:32","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=58962"},"modified":"2022-05-10T14:14:37","modified_gmt":"2022-05-10T08:44:37","slug":"eureka-math-grade-4-module-7-lesson-15","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-4-module-7-lesson-15\/","title":{"rendered":"Eureka Math Grade 4 Module 7 Lesson 15 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 4th Grade Module 7 Lesson 15 Answer Key<\/h2>\n

Eureka Math Grade 4 Module 7 Lesson 15 Problem Set Answer Key<\/h3>\n

Question 1.
\nEmma\u2019s rectangular bedroom is 11 ft long and 12 ft wide with an attached closet that is 4 ft by 5 ft. How many square feet of carpet does Emma need to cover both the bedroom and closet?
\nAnswer:
\nGiven,
\nEmma’s rectangular bedroom measurements :
\nlength = 11 ft
\nand width = 12 ft
\nArea = length x width
\nA = 11 x 12 = 132 sq. ft.
\nAlso given the measurement of attached closet :
\nlength = 4 ft
\nand width = 5 ft
\nArea = 4 x 5 = 20 sq. ft.
\nTotal square feet of carpet Emma need to cover both the bedroom and closet =
\n132+ 20 = 152 square feet.
\nTherefore, Emma needs 152 sq. ft to cover bedroom and closet.<\/p>\n

Question 2.
\nTo save money, Emma is no longer going to carpet her closet. In addition, she wants one 3 ft by 6 ft corner of her bedroom to be wood floor. How many square feet of carpet will she need for the bedroom now?
\nAnswer:
\nThe area of Emma’s bedroom = 132 sq. ft.
\nGiven that,
\nEmma wants to cover her 3 ft by 6 ft corner with wood floor
\nNow, Area = length x width
\nA = 3 x 6 = 18 sq. ft.
\nNow, the square feet of carpet Emma need for her bedroom =
\n132 – 18 = 114
\nTherefore, Emma need 114 sq. ft. of carper for her bedroom.<\/p>\n

Question 3.
\nFind the area of the figure pictured to the right.
\n\"Engage
\nAnswer:
\nArea of rectangle = length x width
\na. Area = length x width
\nA = 15 x 8 = 120 sq. ft
\nb. Area = length x width
\nA= 12 x 5 = 60 sq. ft.
\nc. Area = length x width
\nA = 12 x 5 = 60 sq. ft.
\nTotal area = 120 + 60 +60 = 240
\nTherefore, total area = 240 sq. ft.<\/p>\n

Question 4.
\nLabel the sides of the figure below with measurements that make sense. Find the area of the figure.
\n\"Engage
\nAnswer:-<\/p>\n

\"\"<\/p>\n

Area = length x width
\na. 3 x 2 = 6 sq. inches
\nb. 3 x 1 = 3 sq. inches
\nc. 3 x 2 = 6 sq.inches
\nTotal : 6 sq.in + 3 sq.in + 6 sq. in. = 15 sq. inches<\/p>\n

Question 5.
\nPeterkin Park has a square fountain with a walkway around it. The fountain measures 12 feet on each side. The walkway is 3\\(\\frac{1}{2}\\) feet wide. Find the area of the walkway.
\nAnswer: 217 sq. ft.<\/p>\n

Explanation :
\nGiven that,
\nThe measurement of fountain on each side = 12 sq. ft.
\nArea = length x width
\nA = 12 x 12 = 144 sq. ft.
\nThe measurement of walkway = 3 1\/2 feet wide
\nTotal measurement = 144 + 3 1\/2 +3\u00a0 1\/2 = 19
\nArea = length x width
\nA = 19 x 19
\n= 361 sq. ft
\nNow, the area of walkway =
\n361 – 144 = 217
\nTherefore, the area of walkway = 217 sq. ft.<\/p>\n

Question 6.
\nIf 1 bag of gravel covers 9 square feet, how many bags of gravel will be needed to cover the entire walkway around the fountain in Peterkin Park?
\nAnswer:
\nGiven that,
\n1 bag of gravels covers 9 sq. ft.
\nTotal area of walkway = 217 sq.ft.
\nNow,
\n217 \/ 9 = 24
\n24 and remaining of 1
\nTherefore, 25 bags of graved will be required to cover the walkway.<\/p>\n

Eureka Math Grade 4 Module 7 Lesson 15 Reflection Answer Key<\/h3>\n

In the table below are topics that you learned in Grade 4 and that were used in today\u2019s lesson. Choose 1 topic, and describe how you were successful in using it today.<\/p>\n\n\n\n\n
2-digit by 2-digit multiplication<\/td>\nArea formula<\/td>\nDivision of 3-digit number by 1-digit number<\/td>\n<\/tr>\n
Subtraction of multi-digit numbers<\/td>\nAddition of multi-digit numbers<\/td>\nSolving multi-step word problems<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Eureka Math Grade 4 Module 7 Lesson 15 Homework Answer Key<\/h3>\n

For homework, complete the top portion of each page. This will become an answer key for you to refer to when completing the bottom portion as a mini-personal white board activity during the summer.
\nFind the area of the figure that is shaded.
\nQuestion 1.<\/p>\n

\"Eureka
\nAnswer:<\/p>\n

    \n
  1. <\/li>\n<\/ol>\n

    a. Area of rectangle = length x width
    \nArea = 4 x 16 = 64 sq. ft.
    \nb. area = length x breadth
    \nArea = 16 x 8 = 128
    \nTotal area = 64 + 128 = 192 sq.ft.<\/p>\n

    2. Area of rectangle = length x breadth
    \nThe area of shaded part =
    \n16 x 24 – {( 9 x 7 ) + ( 5 x 4 )}
    \n= 384 – [63 + 20 ]
    \n= 384 – 83
    \n= 301 sq. ft.<\/p>\n

    Find the area of the figure that is shaded.
    \nQuestion 1.
    \n\"Eureka
    \nAnswer:<\/p>\n

    a. Area of rectangle = length x width
    \nArea = 2 x 8 = 16 sq. ft.
    \nb. area = length x breadth
    \nArea = 8 x 4 = 32
    \nTotal area =
    \n16 + 32 = 48 sq.ft.<\/p>\n

    2. Area of rectangle = length x breadth
    \nThe area of shaded part =
    \n16 x 24 – {( 9 x 7 ) + ( 5 x 4 )}
    \n= 384 – [63 + 20 ]
    \n= 384 – 83
    \n= 301 sq. ft.<\/p>\n

    Find the area of the figure that is shaded.
    \nQuestion 1.<\/p>\n

    Challenge: Replace the given dimensions with different measurements, and solve again.<\/p>\n

    Question 3.
    \nA wall is 8 feet tall and 19 feet wide. An opening 7 feet tall and 8 feet wide was cut into the wall for a doorway. Find the area of the remaining portion of the wall.
    \nAnswer:
    \nThe area of remaining portion of wall =
    \n( 8 x 19 ) – ( 7 x 8 )
    \n= 152 – 56
    \n= 96
    \nTherefore, the area of the remaining portion of the wall = 96 sq. ft.<\/p>\n","protected":false},"excerpt":{"rendered":"

    Engage NY Eureka Math 4th Grade Module 7 Lesson 15 Answer Key Eureka Math Grade 4 Module 7 Lesson 15 Problem Set Answer Key Question 1. Emma\u2019s rectangular bedroom is 11 ft long and 12 ft wide with an attached closet that is 4 ft by 5 ft. How many square feet of carpet does … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/58962"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=58962"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/58962\/revisions"}],"predecessor-version":[{"id":137701,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/58962\/revisions\/137701"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=58962"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=58962"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=58962"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}