{"id":60003,"date":"2022-05-29T09:28:43","date_gmt":"2022-05-29T03:58:43","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=60003"},"modified":"2022-05-10T14:19:56","modified_gmt":"2022-05-10T08:49:56","slug":"eureka-math-grade-4-module-3-lesson-21","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-4-module-3-lesson-21\/","title":{"rendered":"Eureka Math Grade 4 Module 3 Lesson 21 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 4th Grade Module 3 Lesson 21 Answer Key<\/h2>\n

Eureka Math Grade 4 Module 3 Lesson 21 Sprint Answer Key<\/h3>\n

Division with Remainders
\n\"Eureka<\/p>\n

Answer:
\n\"Eureka
\nQuestion 1.
\n8 \u00f7 2 Q = ___4___ R = ___0___
\nAnswer:
\n8 \u00f7 2 = 4
\nquotient = 4 and remainder = 0,<\/p>\n

Explanation:
\nGiven 8 \u00f7 2 when 8 is divided by 2 we get quotient as 4,
\n(2 X 4 = 8) and remainder is 0.<\/p>\n

Question 2.
\n9 \u00f7 2 Q = ___4___ R = ___1___
\nAnswer:
\n9 \u00f7 2 =
\nquotient = 4 and remainder = 1,<\/p>\n

Explanation:
\nGiven 9 \u00f7 2 when 9 is divided by 2 we get quotient as 4,
\n(2 X 4 = 8) and remainder is 1.<\/p>\n

Question 3.
\n4 \u00f7 4 Q = __1____ R = __0____
\nAnswer:
\n4 \u00f7 4 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 4 \u00f7 4 when 4 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 0.<\/p>\n

Question 4.
\n5 \u00f7 4 Q = ___1___ R = ___1___
\nAnswer:
\n5 \u00f7 4 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 5 \u00f7 4 when 5 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 1.<\/p>\n

Question 5.
\n7 \u00f7 5 Q = __1____ R = ___2___
\nAnswer:
\n7 \u00f7 5 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 7 \u00f7 5 when 7 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 2.<\/p>\n

Question 6.
\n8 \u00f7 5 Q = ___1___ R = __3____
\nAnswer:
\n8 \u00f7 5 =
\nquotient = 1 and remainder = 3,<\/p>\n

Explanation:
\nGiven 8 \u00f7 5 when 8 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 3.<\/p>\n

Question 7.
\n5 \u00f7 3 Q = ___1___ R = __2____
\nAnswer:
\n5 \u00f7 3 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 5 \u00f7 3 when 5 is divided by 3 we get quotient as 1,
\n(3 X 1 = 3) and remainder is 2.<\/p>\n

Question 8.
\n6 \u00f7 3 Q = __2____ R = __0__
\nAnswer:
\n6 \u00f7 3 =
\nquotient = 2 and remainder = 0,<\/p>\n

Explanation:
\nGiven 6 \u00f7 3 when 6 is divided by 3 we get quotient as 2,
\n(3 X 2 = 6) and remainder is 0.<\/p>\n

Question 9.
\n8 \u00f7 4 Q = __2____ R = __0____
\nAnswer:
\n8 \u00f7 4 =
\nquotient = 2 and remainder = 0,<\/p>\n

Explanation:
\nGiven 8 \u00f7 4 when 8 is divided by 4 we get quotient as 2,
\n(4 X 2 = 8) and remainder is 0.<\/p>\n

Question 10.
\n9 \u00f7 4 Q = __2____ R = ___1___
\nAnswer:
\n9 \u00f7 4 =
\nquotient = 2 and remainder = 1,<\/p>\n

Explanation:
\nGiven 9 \u00f7 4 when 9 is divided by 4 we get quotient as 2,
\n(4 X 2 = 8) and remainder is 1.<\/p>\n

Question 11.
\n2 \u00f7 2 Q = ___1___ R = __0____
\nAnswer:
\n2 \u00f7 2 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 2 \u00f7 2 when 2 is divided by 2 we get quotient as 1,
\n(2 X 1 = 2) and remainder is 0.<\/p>\n

Question 12.
\n3 \u00f7 2 Q = __1____ R = __1____
\nAnswer:
\n3 \u00f7 2 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 3 \u00f7 2 when 3 is divided by 2 we get quotient as 1,
\n(2 X 1 = 2) and remainder is 1.<\/p>\n

Question 13.
\n7 \u00f7 3 Q = __2____ R = __1____
\nAnswer:
\n7 \u00f7 3 =
\nquotient = 2 and remainder = 1,<\/p>\n

Explanation:
\nGiven 7 \u00f7 3 when 7 is divided by 3 we get quotient as 2,
\n(3 X 2 = 6) and remainder is 1.<\/p>\n

Question 14.
\n8 \u00f7 3 Q = ___2___ R = ___2___
\nAnswer:
\n8 \u00f7 3 =
\nquotient = 2 and remainder = 2,<\/p>\n

Explanation:
\nGiven 8 \u00f7 3 when 8 is divided by 3 we get quotient as 2,
\n(3 X 2 = 6) and remainder is 2.<\/p>\n

Question 15.
\n9 \u00f7 3 Q = __3____ R = __0____
\nAnswer:
\n9 \u00f7 3 =
\nquotient = 3 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 3 when 9 is divided by 3 we get quotient as 3,
\n(3 X 3 = 9) and remainder is 0.<\/p>\n

Question 16.
\n8 \u00f7 6 Q = ___1___ R = __2____
\nAnswer:
\n8 \u00f7 6 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 8 \u00f7 6 when 8 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 2.<\/p>\n

Question 17.
\n9 \u00f7 6 Q = __1____ R = __3____
\nAnswer:
\n9 \u00f7 6 =
\nquotient = 1 and remainder = 3,<\/p>\n

Explanation:
\nGiven 9 \u00f7 6 when 9 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 3.<\/p>\n

Question 18.
\n5 \u00f7 5 Q = ___1___ R = __0____
\nAnswer:
\n5\u00f7 5 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 5 \u00f7 5 when 5 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 0.<\/p>\n

Question 19.
\n6 \u00f7 5 Q = ____1__ R = __1____
\nAnswer:
\n6 \u00f7 5 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 6 \u00f7 5 when 6 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 1.<\/p>\n

Question 20.
\n8 \u00f7 8 Q = __1____ R = __0____
\nAnswer:
\n8 \u00f7 8 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 8 \u00f7 8 when 8 is divided by 8 we get quotient as 1,
\n(8 X 1 = 8) and remainder is 0.<\/p>\n

Question 21.
\n9 \u00f7 8 Q = ___1___ R = __1____
\nAnswer:
\n9 \u00f7 8 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 9 \u00f7 8 when 9 is divided by 8 we get quotient as 1,
\n(8 X 1 = 8) and remainder is 1.<\/p>\n

Question 22.
\n9 \u00f7 9 Q = ___1___ R = __0____
\nAnswer:
\n9 \u00f7 9 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 9 when 9 is divided by 9 we get quotient as 1,
\n(9 X 1 = 9) and remainder is 0.<\/p>\n

Question 23.
\n6 \u00f7 2 Q = ___3___ R = __0____
\nAnswer:
\n6 \u00f7 2 =
\nquotient = 3 and remainder = 0,<\/p>\n

Explanation:
\nGiven 6 \u00f7 2 when 6 is divided by 2 we get quotient as 3,
\n(2 X 3 = 6) and remainder is 0.<\/p>\n

Question 24.
\n7 \u00f7 2 Q = __3____ R = __1____
\nAnswer:
\n7 \u00f7 2 =
\nquotient = 3 and remainder = 1,<\/p>\n

Explanation:
\nGiven 7 \u00f7 2 when 7 is divided by 2 we get quotient as 3,
\n(2 X 3 = 6) and remainder is 1.<\/p>\n

Question 25.
\n3 \u00f7 3 Q = __1____ R = __0____
\nAnswer:
\n3 \u00f7 3 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 3 \u00f7 3 when 3 is divided by 3 we get quotient as 1,
\n(3 X 1 = 3) and remainder is 0.<\/p>\n

Question 26.
\n4 \u00f7 3 Q = ___1___ R = __1____
\nAnswer:
\n4 \u00f7 3 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 4 \u00f7 3 when 4 is divided by 3 we get quotient as 1,
\n(3 X 1 = 3) and remainder is 1.<\/p>\n

Question 27.
\n6 \u00f7 4 Q = ___1___ R = ___2___
\nAnswer:
\n6 \u00f7 4 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 6 \u00f7 4 when 6 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 2.<\/p>\n

Question 28.
\n7 \u00f7 4 Q = __1____ R = __3____
\nAnswer:
\n7 \u00f7 4 =
\nquotient = 1 and remainder = 3,<\/p>\n

Explanation:
\nGiven 7 \u00f7 4 when 7 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 3.<\/p>\n

Question 29.
\n6 \u00f7 6 Q = ___1___ R = __0____
\nAnswer:
\n6 \u00f7 6 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 6 \u00f7 6 when 6 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 0.<\/p>\n

Question 30.
\n7 \u00f7 6 Q = ___1___ R = __1____
\nAnswer:
\n7 \u00f7 6 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 7 \u00f7 6 when 7 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 1.<\/p>\n

Question 31.
\n4 \u00f7 2 Q = ___2___ R = ___0___
\nAnswer:
\n4 \u00f7 2 =
\nquotient = 2 and remainder = 0,<\/p>\n

Explanation:
\nGiven 4 \u00f7 2 when 4 is divided by 2 we get quotient as 2,
\n(2 X 2 = 4) and remainder is 0.<\/p>\n

Question 32.
\n5 \u00f7 2 Q = __2____ R = __1____
\nAnswer:
\n5 \u00f7 2 =
\nquotient = 2 and remainder = 1,<\/p>\n

Explanation:
\nGiven 5 \u00f7 2 when 5 is divided by 2 we get quotient as 2,
\n(2 X 2 = 4) and remainder is 1.<\/p>\n

Question 33.
\n9 \u00f7 3 Q = ___3___ R = __0____
\nAnswer:
\n9 \u00f7 3 =
\nquotient = 3 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 3 when 9 is divided by 3 we get quotient as 3,
\n(3 X 3= 9) and remainder is 0.<\/p>\n

Question 34.
\n9 \u00f7 5 Q = ___1___ R = ___4___
\nAnswer:
\n9 \u00f7 5 =
\nquotient = 1 and remainder = 4,<\/p>\n

Explanation:
\nGiven 9 \u00f7 5 when 9 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 4.<\/p>\n

Question 35.
\n7 \u00f7 7 Q = __1____ R = __0____
\nAnswer:
\n7 \u00f7 7 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 7 \u00f7 7 when 7 is divided by 7 we get quotient as 1,
\n(7 X 1 = 7) and remainder is 0.<\/p>\n

Question 36.
\n9 \u00f7 9 Q = ___1___ R = __0____
\nAnswer:
\n9 \u00f7 9 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 9 when 9 is divided by 9 we get quotient as 1,
\n(9 X 1 = 9) and remainder is 0.<\/p>\n

Question 37.
\n13 \u00f7 4 Q = ___3___ R = __1____
\nAnswer:
\n13 \u00f7 4 =
\nquotient = 3 and remainder = 1,<\/p>\n

Explanation:
\nGiven 13 \u00f7 4 when 13 is divided by 4 we get quotient as 3,
\n(4 X 3 = 12) and remainder is 1.<\/p>\n

Question 38.
\n18 \u00f7 5 Q = ___3___ R = __3____
\nAnswer:
\n18 \u00f7 5 =
\nquotient = 3 and remainder = 3,<\/p>\n

Explanation:
\nGiven 18 \u00f7 5 when 18 is divided by 5 we get quotient as 3,
\n(5 X 3 = 15) and remainder is 3.<\/p>\n

Question 39.
\n21 \u00f7 6 Q = ____3__ R = __3____
\nAnswer:
\n21 \u00f7 6 =
\nquotient = 3 and remainder = 3,<\/p>\n

Explanation:
\nGiven 21 \u00f7 6 when 21 is divided by 6 we get quotient as 3,
\n(6 X 3 = 18) and remainder is 3.<\/p>\n

Question 40.
\n24 \u00f7 7 Q = __3____ R = __3____
\nAnswer:
\n24 \u00f7 7 =
\nquotient = 3 and remainder = 3,<\/p>\n

Explanation:
\nGiven 24 \u00f7 7 when 24 is divided by 7 we get quotient as 3,
\n(7 X 3 = 21) and remainder is 3.<\/p>\n

Question 41.
\n29 \u00f7 8 Q = __3____ R = __5____
\nAnswer:
\n29 \u00f7 8 =
\nquotient = 3 and remainder = 5,<\/p>\n

Explanation:
\nGiven 29 \u00f7 8 when 29 is divided by 8 we get quotient as 3,
\n(8 X 3 = 24) and remainder is 5.<\/p>\n

Question 42.
\n43 \u00f7 6 Q = ___7___ R = __1____
\nAnswer:
\n43 \u00f7 6 =
\nquotient = 7 and remainder = 1,<\/p>\n

Explanation:
\nGiven 43 \u00f7 6 when 43 is divided by 6 we get quotient as 7,
\n(6 X 7 = 42) and remainder is 1.<\/p>\n

Question 43.
\n53 \u00f7 6 Q = __8____ R = ___5___
\nAnswer:
\n53 \u00f7 6 =
\nquotient = 8 and remainder = 5,<\/p>\n

Explanation:
\nGiven 53 \u00f7 6 when 53 is divided by 6 we get quotient as 8,
\n(6 X 8 = 48) and remainder is 5.<\/p>\n

Question 44.
\n82 \u00f7 9 Q = ___9___ R = ___1___
\nAnswer:
\n82 \u00f7 9 =
\nquotient = 9 and remainder = 1,<\/p>\n

Explanation:
\nGiven 82 \u00f7 9 when 82 is divided by 9 we get quotient as 9,
\n(9 X 9 = 81) and remainder is 1.<\/p>\n

Division with Remainders
\n\"Eureka<\/p>\n

Answer:
\n\"\"
\nQuestion 1.
\n9 \u00f7 8 Q = __1____ R = __1____
\nAnswer:
\n9 \u00f7 8 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 9 \u00f7 8 when 9 is divided by 8 we get quotient as 1,
\n(8 X 1 = 8) and remainder is 1.<\/p>\n

Question 2.
\n8 \u00f7 8 Q = __1____ R = ___0___
\nAnswer:
\n8 \u00f7 8 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 8 when 9 is divided by 8 we get quotient as 1,
\n(8 X 1 = 8) and remainder is 1.<\/p>\n

Question 3.
\n9 \u00f7 6 Q = __1____ R = ___2___
\nAnswer:
\n9 \u00f7 6 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 9 \u00f7 6 when 9 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 2.<\/p>\n

Question 4.
\n8 \u00f7 6 Q = __1____ R = __2____
\nAnswer:
\n8 \u00f7 6 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 8 \u00f7 6 when 8 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 2.<\/p>\n

Question 5.
\n5 \u00f7 5 Q = __1____ R = __0____
\nAnswer:
\n5 \u00f7 5 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 5 \u00f7 5 when 5 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 0.<\/p>\n

Question 6.
\n6 \u00f7 5 Q = ___1___ R = __1____
\nAnswer:
\n6 \u00f7 5 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 6 \u00f7 5 when 6 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 1.<\/p>\n

Question 7.
\n7 \u00f7 4 Q = ___1___ R = __3____
\nAnswer:
\n7 \u00f7 4 =
\nquotient = 1 and remainder = 3,<\/p>\n

Explanation:
\nGiven 7 \u00f7 4 when 7 is divided by 4 we get quotient as 3,
\n(4 X 1 = 4) and remainder is 3.<\/p>\n

Question 8.
\n6 \u00f7 4 Q = __1____ R = __2____
\nAnswer:
\n6 \u00f7 4 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 6 \u00f7 4 when 6 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 2.<\/p>\n

Question 9.
\n5 \u00f7 3 Q = __1____ R = __2____
\nAnswer:
\n5 \u00f7 3 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 5 \u00f7 3 when 5 is divided by 3 we get quotient as 1,
\n(3 X 1 = 3) and remainder is 2.<\/p>\n

Question 10.
\n6 \u00f7 3 Q = __2____ R = ___0___
\nAnswer:
\n6 \u00f7 3 =
\nquotient = 2 and remainder = 0,<\/p>\n

Explanation:
\nGiven 6 \u00f7 3 when 6 is divided by 3 we get quotient as 2,
\n(3 X 2 = 6) and remainder is 0.<\/p>\n

Question 11.
\n2 \u00f7 2 Q = __1____ R = __0____
\nAnswer:
\n2 \u00f7 2 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 2 \u00f7 2 when 2 is divided by 2 we get quotient as 1,
\n(2 X 1 = 2) and remainder is 0.<\/p>\n

Question 12.
\n3 \u00f7 2 Q = ___1___ R = ___1___
\nAnswer:
\n3 \u00f7 2 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 3 \u00f7 2 when 3 is divided by 2 we get quotient as 1,
\n(2 X 1 = 2) and remainder is 1.<\/p>\n

Question 13.
\n3 \u00f7 3 Q = ___1___ R = __0____
\nAnswer:
\n3 \u00f7 3 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 3 \u00f7 3 when 3 is divided by 3 we get quotient as 1,
\n(3 X 1 = 3) and remainder is 0.<\/p>\n

Question 14.
\n4 \u00f7 3 Q = __1___ R = ___1___
\nAnswer:
\n4 \u00f7 3 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 4 \u00f7 3 when 4 is divided by 3 we get quotient as 1,
\n(3 X 1 = 3) and remainder is 1.<\/p>\n

Question 15.
\n8 \u00f7 7 Q = __1____ R = ___1__
\nAnswer:
\n8 \u00f7 7 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 8 \u00f7 7 when 8 is divided by 7 we get quotient as 1,
\n(7 X 1 = 7) and remainder is 1.<\/p>\n

Question 16.
\n9 \u00f7 7 Q = ___1___ R = __2____
\nAnswer:<\/p>\n

Question 17.
\n4 \u00f7 4 Q = ___1___ R = ___0___
\nAnswer:
\n4 \u00f7 4 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 4 \u00f7 4 when 4 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 0.<\/p>\n

Question 18.
\n5 \u00f7 4 Q = ___1___ R = __1____
\nAnswer:
\n5 \u00f7 4 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 5 \u00f7 4 when 5 is divided by 4 we get quotient as 1,
\n(4 X 1 = 4) and remainder is 1.<\/p>\n

Question 19.
\n6 \u00f7 2 Q = __3____ R = __0____
\nAnswer:
\n6 \u00f7 2 =
\nquotient = 3 and remainder = 0,<\/p>\n

Explanation:
\nGiven 6\u00f7 2 when 6 is divided by 2 we get quotient as 3,
\n(3 X 1 = 3) and remainder is 0.<\/p>\n

Question 20.
\n7 \u00f7 2 Q = __3____ R = __1____
\nAnswer:
\n7 \u00f7 2 =
\nquotient = 3 and remainder = 1,<\/p>\n

Explanation:
\nGiven 7 \u00f7 2 when 7 is divided by 2 we get quotient as 3,
\n(2 X 3 = 6) and remainder is 1.<\/p>\n

Question 21.
\n8 \u00f7 5 Q = __1____ R = __3____
\nAnswer:
\n8 \u00f7 5 =
\nquotient = 1 and remainder = 3,<\/p>\n

Explanation:
\nGiven 8 \u00f7 5 when 8 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 3.<\/p>\n

Question 22.
\n7 \u00f7 5 Q = ___1___ R = __2____
\nAnswer:
\n7 \u00f7 5 =
\nquotient = 1 and remainder = 2,<\/p>\n

Explanation:
\nGiven 7 \u00f7 5 when 7 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 2.<\/p>\n

Question 23.
\n4 \u00f7 2 Q = __2____ R = __0____
\nAnswer:
\n4 \u00f7 2 =
\nquotient = 2 and remainder = 0,<\/p>\n

Explanation:
\nGiven 4 \u00f7 2 when 4 is divided by 2 we get quotient as 2,
\n(2 X 1 = 2) and remainder is 0.<\/p>\n

Question 24.
\n5 \u00f7 2 Q = __2____ R = __1____
\nAnswer:
\n5 \u00f7 2 =
\nquotient = 2 and remainder = 1,<\/p>\n

Explanation:
\nGiven 5 \u00f7 2 when 5 is divided by 2 we get quotient as 2,
\n(2 X 2 = 4) and remainder is 1.<\/p>\n

Question 25.
\n8 \u00f7 4 Q = ___2___ R = ___0___
\nAnswer:
\n8 \u00f7 4 =
\nquotient = 2 and remainder = 0,<\/p>\n

Explanation:
\nGiven 8 \u00f7 4 when 8 is divided by 4 we get quotient as 2,
\n(4 X 2 = 8) and remainder is 0.<\/p>\n

Question 26.
\n9 \u00f7 4 Q = ___2___ R = __1____
\nAnswer:
\n9 \u00f7 4 =
\nquotient = 2 and remainder = 1,<\/p>\n

Explanation:
\nGiven 9 \u00f7 4 when 9 is divided by 4 we get quotient as 2,
\n(4 X 2 = 8) and remainder is 1.<\/p>\n

Question 27.
\n9 \u00f7 3 Q = ___3___ R = __0____
\nAnswer:
\n9 \u00f7 3 =
\nquotient = 3 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 3 when 9 is divided by 3 we get quotient as 3,
\n(3 X 3 = 9) and remainder is 0.<\/p>\n

Question 28.
\n8 \u00f7 3 Q = ___2___ R = __2____
\nAnswer:
\n8 \u00f7 3 =
\nquotient = 2 and remainder = 2,<\/p>\n

Explanation:
\nGiven 8 \u00f7 3 when 8 is divided by 3 we get quotient as 2,
\n(3 X 2 = 6) and remainder is 2.<\/p>\n

Question 29.
\n9 \u00f7 5 Q = __1____ R = ___4___
\nAnswer:
\n9 \u00f7 5 =
\nquotient = 1 and remainder = 4,<\/p>\n

Explanation:
\nGiven 9 \u00f7 5 when 9 is divided by 5 we get quotient as 1,
\n(5 X 1 = 5) and remainder is 4.<\/p>\n

Question 30.
\n6 \u00f7 6 Q = ___1___ R = ___0___
\nAnswer:
\n6 \u00f7 6 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 6 \u00f7 6 when 6 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 0.<\/p>\n

Question 31.
\n7 \u00f7 6 Q = __1____ R = ___1___
\nAnswer:
\n7 \u00f7 6 =
\nquotient = 1 and remainder = 1,<\/p>\n

Explanation:
\nGiven 7 \u00f7 6 when 7 is divided by 6 we get quotient as 1,
\n(6 X 1 = 6) and remainder is 1.<\/p>\n

Question 32.
\n9 \u00f7 9 Q = __1____ R = ___0___
\nAnswer:
\n9 \u00f7 9 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 9 \u00f7 9 when 9 is divided by 9 we get quotient as 1,
\n(9 X 1 = 9) and remainder is 0.<\/p>\n

Question 33.
\n7 \u00f7 7 Q = ___1___ R = _0_____
\nAnswer:
\n7 \u00f7 7 =
\nquotient = 1 and remainder = 0,<\/p>\n

Explanation:
\nGiven 7 \u00f7 7 when 7 is divided by 7 we get quotient as 1,
\n(7 X 1 = 7) and remainder is 0.<\/p>\n

Question 34.
\n9 \u00f7 2 Q = ___4___ R = ___1___
\nAnswer:
\n9 \u00f7 2 =
\nquotient = 4 and remainder = 1,<\/p>\n

Explanation:
\nGiven 9 \u00f7 2 when 9 is divided by 2 we get quotient as 4,
\n(2 X 4 = 8) and remainder is 1.<\/p>\n

Question 35.
\n8 \u00f7 2 Q = ___4___ R = ___0___
\nAnswer:
\n8 \u00f7 2 =
\nquotient = 4 and remainder = 0,<\/p>\n

Explanation:
\nGiven 8 \u00f7 2 when 8 is divided by 2 we get quotient as 4,
\n(2 X 4 = 8) and remainder is 0.<\/p>\n

Question 36.
\n37 \u00f7 8 Q = ___4___ R = ___5___
\nAnswer:
\n37 \u00f7 8 =
\nquotient = 4 and remainder = 5,<\/p>\n

Explanation:
\nGiven 37 \u00f7 8 when 37 is divided by 8 we get quotient as 4,
\n(8 X 4 = 32) and remainder is 5.<\/p>\n

Question 37.
\n50 \u00f7 9 Q = ___5___ R = __5____
\nAnswer:
\n50 \u00f7 9 =
\nquotient = 5 and remainder = 5,<\/p>\n

Explanation:
\nGiven 50 \u00f7 9 when 50 is divided by 9 we get quotient as 5,
\n(9 X 5 = 45) and remainder is 5.<\/p>\n

Question 38.
\n17 \u00f7 6 Q = ___2___ R = __5____
\nAnswer:
\n17 \u00f7 6 =
\nquotient = 2 and remainder = 5,<\/p>\n

Explanation:
\nGiven 17 \u00f7 6 when 17 is divided by 6 we get quotient as 2,
\n(6 X 2 = 12) and remainder is 5.<\/p>\n

Question 39.
\n48 \u00f7 7 Q = __6____ R = __6____
\nAnswer:
\n48 \u00f7 7 =
\nquotient = 6 and remainder = 6,<\/p>\n

Explanation:
\nGiven 48 \u00f7 7 when 48 is divided by 7 we get quotient as 6,
\n(7 X 6 = 42) and remainder is 6.<\/p>\n

Question 40.
\n51 \u00f7 8 Q = ___6___ R = ___3___
\nAnswer:
\n51 \u00f7 8 =
\nquotient = 6 and remainder = 3,<\/p>\n

Explanation:
\nGiven 51 \u00f7 8 when 51 is divided by 8 we get quotient as 6,
\n(8 X 6 = 48) and remainder is 3.<\/p>\n

Question 41.
\n68 \u00f7 9 Q = __7____ R = ___5___
\nAnswer:
\n68 \u00f7 9 =
\nquotient = 7 and remainder = 5,<\/p>\n

Explanation:
\nGiven 68 \u00f7 9 when 68 is divided by 9 we get quotient as 7,
\n(9 X 7= 63) and remainder is 5.<\/p>\n

Question 42.
\n53 \u00f7 6 Q = __8____ R = __5____
\nAnswer:
\n53 \u00f7 6 =
\nquotient = 8 and remainder = 5,<\/p>\n

Explanation:
\nGiven 53 \u00f7 6 when 53 is divided by 6 we get quotient as 8,
\n(6 X 8 = 48) and remainder is 5.<\/p>\n

Question 43.
\n61 \u00f7 8 Q = ___7___ R = __5____
\nAnswer:
\n61 \u00f7 8 =
\nquotient = 7 and remainder = 5,<\/p>\n

Explanation:
\nGiven 61 \u00f7 8 when 61 is divided by 8 we get quotient as 71,
\n(8 X 7 = 56) and remainder is 5.<\/p>\n

Question 44.
\n70 \u00f7 9 Q = __7____ R = __7____
\nAnswer:
\n70 \u00f7 9 =
\nquotient = 7 and remainder = 7,<\/p>\n

Explanation:
\nGiven 70 \u00f7 9 when 70 is divided by 9 we get quotient as 7,
\n(9 X 7 = 63) and remainder is 7.<\/p>\n

Eureka Math Grade 4 Module 3 Lesson 21 Problem Set Answer Key<\/h3>\n

Question 1.
\nSolve 37 \u00f7 2 using an area model. Use long division and
\nthe distributive property to record your work.
\nAnswer:
\n\"Eureka
\nExplanation:
\nSolved 37 \u00f7 2 using an area model. Using long division and the distributive property to record my work as shown above.<\/p>\n

Question 2.
\nSolve 76 \u00f7 3 using an area model. Use long division and the distributive property to record your work.
\nAnswer:
\n\"Eureka<\/p>\n

Explanation:
\nSolved 76 \u00f7 3 using an area model. Used long division and the distributive property to record your work.<\/p>\n

Question 3.
\nCarolina solved the following division problem by drawing an area model.
\n\"Eureka
\na. What division problem did she solve?
\nAnswer:
\n53 \u00f7 4<\/p>\n

Explanation:
\nCarolina solved the following division problem by using an area model as 40 + 12 + 1 = 53 divided by 4.<\/p>\n

b. Show how Carolina\u2019s model can be represented using the distributive property.
\nAnswer:
\n\"Eureka
\nExplanation:
\nShown how Carolina\u2019s model can be represented using the distributive property above.<\/p>\n

Solved the following problems using the area model. Supported the area model with long division or the distributive property.<\/p>\n

Question 4.
\n48 \u00f7 3
\nAnswer:
\n48 \u00f7 3 =
\nquotient = 16 and remainder = 0,
\n\"Eureka
\nExplanation:
\nGiven 48 \u00f7 3 when 48 is divided by 3 we get quotient as 16,
\n(3 X 16 = 48) and remainder is 0.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 5.
\n49 \u00f7 3
\nAnswer:
\n49 \u00f7 3 =
\nquotient = 16 and remainder = 1,
\n\"Eureka<\/p>\n

Explanation:
\nGiven 49 \u00f7 3 when 49 is divided by 3 we get quotient as 16,
\n(3 X 16 = 48) and remainder is 1.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 6.
\n56 \u00f7 4
\nAnswer:
\n56 \u00f7 4 =
\nquotient = 14 and remainder = 0,
\n\"Eureka<\/p>\n

Explanation:
\nGiven 56 \u00f7 4 when 56 is divided by 4 we get quotient as 14, (4 X 14 = 56) and remainder is 0.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 7.
\n58 \u00f7 4
\nAnswer:
\n58 \u00f7 4 =
\nquotient = 14 and remainder = 2,
\n\"Eureka<\/p>\n

Explanation:
\nGiven\u00a0 58 \u00f7 4 when 58 is divided by 4 we get quotient as 14, (4 X 14 = 58) and remainder is 2.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 8.
\n66 \u00f7 5
\nAnswer:
\n66 \u00f7 5 =
\nquotient = 13 and remainder = 1,
\n\"Eureka<\/p>\n

Explanation:
\nGiven\u00a0 66 \u00f7 5 when 66 is divided by 5 we get quotient as 13, (5 X 13 = 65) and remainder is 1.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 9.
\n79 \u00f7 3
\nAnswer:
\n79 \u00f7 3 =
\nquotient = 26 and remainder = 1,
\n\"Eureka<\/p>\n

Explanation:
\nGiven 79 \u00f7 3 when 79 is divided by 3 we get quotient as 26,
\n(3 X 26 = 78 ) and remainder is 1.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 10.
\nSeventy-three students are divided into groups of 6 students each. How many groups of 6 students are there? How many students will not be in a group of 6?<\/p>\n

Answer:
\nThere are 12 groups of 6 students are there, 1 student will not be in a group of 6,<\/p>\n

Explanation:
\nGiven Seventy-three students are divided into groups of 6 students each.
\nThe number of groups of 6 students are 73 \u00f7 6 = quotient = 12 and remainder = 1 means there are 12 groups of 6 students are there and 1 student will not be in a group of 6.<\/p>\n

Eureka Math Grade 4 Module 3 Lesson 21 Exit Ticket Answer Key<\/h3>\n

Question 1.
\nKyle drew the following area model to find an unknown length. What division equation did he model?
\n\"Eureka
\nAnswer:
\nKyle’s equation is 59 \u00f7 2,<\/p>\n

Explanation:
\nKyle drew the following area model to find an unknown length.
\nThe division equation did he modeled is 59 \u00f7 2 as
\n(40 + 18 + 1) \u00f7 2 = 59 \u00f7 2.<\/p>\n

Question 2.
\nSolve 93 \u00f7 4 using the area model, long division, and the distributive property.
\nAnswer:
\n\"Eureka<\/p>\n

Explanation:
\nSolved 93 \u00f7 4 using the area model, long division, and the distributive property as shown above.<\/p>\n

Eureka Math Grade 4 Module 3 Lesson 22 Homework Answer Key<\/h3>\n

Question 1.
\nSolve 35 \u00f7 2 using an area model. Use long division and the distributive property to record your work.
\nAnswer:
\n\"Eureka<\/p>\n

Explanation:
\nSolved 35 \u00f7 2 using an area model. Used long division and the distributive property to record my work as shown above.<\/p>\n

Question 2.
\nSolve 79 \u00f7 3 using an area model. Use long division and the distributive property to record your work.
\nAnswer:
\n\"Eureka
\nExplanation:
\nSolved 79 \u00f7 3 using an area model. Used long division and the distributive property to record your work.<\/p>\n

Question 3.
\nPaulina solved the following division problem by drawing an
\narea model.
\n\"Eureka
\na. What division problem did she solve?
\nAnswer:
\nPaulina solved the following division problem as 98 \u00f7 4,<\/p>\n

Explanation:
\nPaulina solved the following division problem by drawing an area model as (40 + 40 + 16 + 2) \u00f7 4 = 98 \u00f7 4.<\/p>\n

b. Show how Paulina\u2019s model can be represented using the
\ndistributive property.
\nAnswer:
\n\"EurekaExplanation:
\nShown how Paulina\u2019s model can be represented using the distributive property above.<\/p>\n

Solve the following problems using the area model. Support the area model with long division or the distributive property.<\/p>\n

Question 4.
\n42 \u00f7 3
\nAnswer:
\n42 \u00f7 3 =
\nquotient = 14 and remainder = 0,
\n\"Eureka<\/p>\n

Explanation:
\nGiven 42 \u00f7 3 when 14 is divided by 3 we get quotient as 14,
\n(3 X 14 = 42) and remainder is 0.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 5.
\n43 \u00f7 3
\nAnswer:
\n43 \u00f7 3 =
\nquotient = 14 and remainder = 1,
\n\"Eureka<\/p>\n

Explanation:
\nGiven\u00a0 43 \u00f7 3 when 43 is divided by 3 we get quotient as 14,
\n(3 X 14 = 42) and remainder is 1.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 6.
\n52 \u00f7 4
\nAnswer:
\n52 \u00f7 4 =
\nquotient = 13 and remainder = 0,
\n\"Eureka<\/p>\n

Explanation:
\nGiven\u00a0 52 \u00f7 4 when 52 is divided by 4 we get quotient as 13,
\n(4 X 13 = 52) and remainder is 0.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 7.
\n54 \u00f7 4
\nAnswer:
\n54 \u00f7 4 =
\nquotient = 13 and remainder = 2,
\n\"EurekaExplanation:
\nGiven\u00a0 54 \u00f7 4 when 54 is divided by 4 we get quotient as 13,
\n(4 X 13 = 52) and remainder is 2.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 8.
\n61 \u00f7 5
\nAnswer:
\n61 \u00f7 5 =
\nquotient = 12 and remainder = 1,
\n\"Eureka
\nExplanation:
\nGiven\u00a0 61 \u00f7 5 when 61 is divided by 5 we get quotient as 12,
\n(5 X 12 = 60) and remainder is 1.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n

Question 9.
\n73 \u00f7 3
\nAnswer:
\n73 \u00f7 3 =
\nquotient = 24 and remainder = 1,
\n\"Eureka
\nExplanation:
\nGiven\u00a0 73 \u00f7 3 when 73 is divided by 3 we get quotient as 24,
\n(3 X 24 = 73) and remainder is 1.
\nSolved the following problem using the area model. Supported the area model with long division and the distributive property.<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 4th Grade Module 3 Lesson 21 Answer Key Eureka Math Grade 4 Module 3 Lesson 21 Sprint Answer Key Division with Remainders Answer: Question 1. 8 \u00f7 2 Q = ___4___ R = ___0___ Answer: 8 \u00f7 2 = 4 quotient = 4 and remainder = 0, Explanation: Given 8 \u00f7 … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/60003"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=60003"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/60003\/revisions"}],"predecessor-version":[{"id":137090,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/60003\/revisions\/137090"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=60003"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=60003"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=60003"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}