{"id":60234,"date":"2022-05-20T15:34:43","date_gmt":"2022-05-20T10:04:43","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=60234"},"modified":"2022-05-10T14:21:11","modified_gmt":"2022-05-10T08:51:11","slug":"eureka-math-grade-4-module-5-lesson-40","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-4-module-5-lesson-40\/","title":{"rendered":"Eureka Math Grade 4 Module 5 Lesson 40 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 4th Grade Module 5 Lesson 40 Answer Key<\/h2>\n

Eureka Math Grade 4 Module 5 Lesson 40 Problem Set Answer Key<\/h3>\n

Question 1.
\nThe chart to the right shows the height of some football players.<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n
Player<\/strong><\/td>\n\n

Height <\/strong>(in feet)<\/strong><\/p>\n<\/td>\n<\/tr>\n

A<\/td>\n6\\(\\frac{1}{4}\\)<\/td>\n<\/tr>\n
B<\/td>\n5\\(\\frac{7}{8}\\)<\/td>\n<\/tr>\n
C<\/td>\n6\\(\\frac{1}{2}\\)<\/td>\n<\/tr>\n
D<\/td>\n6\\(\\frac{1}{4}\\)<\/td>\n<\/tr>\n
E<\/td>\n6\\(\\frac{2}{8}\\)<\/td>\n<\/tr>\n
F<\/td>\n5\\(\\frac{7}{8}\\)<\/td>\n<\/tr>\n
G<\/td>\n6\\(\\frac{1}{8}\\)<\/td>\n<\/tr>\n
H<\/td>\n6\\(\\frac{5}{8}\\)<\/td>\n<\/tr>\n
I<\/td>\n5\\(\\frac{6}{8}\\)<\/td>\n<\/tr>\n
J<\/td>\n6\\(\\frac{1}{8}\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\nA: 6(1\/4) = 6.2<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football A.
\n6(1\/4) = 6 x 4.
\n6 x 4 = 24.
\n24 + 1\/4 = 25\/4.
\n25\/4 = 6.2.<\/p>\n

Answer:
\nB: 5(7\/8) = 5.8.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football B.
\n5(7\/8) = 5 x 8.
\n5 x 8 = 40.
\n40 + 7\/8 = 47\/8.
\n47\/8 = 5.8.<\/p>\n

Answer:
\nC: 6(1\/2) = 6.5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football A.
\n6(1\/2) = 6 x 2.
\n6 x 2 = 12.
\n12 + 1\/2 = 13\/2.
\n13\/2 = 6.5.<\/p>\n

Answer:
\nD: 6(1\/4) = 6.2<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football D.
\n6(1\/4) = 6 x 4.
\n6 x 4 = 24.
\n24 + 1\/4 = 25\/4.
\n25\/4 = 6.2.<\/p>\n

Answer:
\nE: 6(2\/8) = 6.2<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football A.
\n6(2\/8) = 6 x 8.
\n6 x 8 = 48.
\n48 + 2\/8 = 50\/8.
\n50\/8 = 6.2.<\/p>\n

Answer:
\nF: 5(7\/8) = 5.8<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football F.
\n5(7\/8) = 5 x 8.
\n5 x 8 = 40.
\n40 + 7\/8 = 47\/8.
\n47\/8 = 5.8.<\/p>\n

Answer:
\nG: 6(1\/8) = 6.1<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football G.
\n6(1\/8) = 6 x 8.
\n6 x 8 = 48.
\n48 + 1\/8 = 49\/8.
\n49\/8 = 6.1.<\/p>\n

Answer:
\nH: 6(5\/8) = 6.6.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football H.
\n6(5\/8) = 6 x 8.
\n6 x 8 = 48.
\n48 + 5\/8 = 53\/8.
\n53\/8 = 6.6.<\/p>\n

Answer:
\nI: 5(6\/8) = 5.7<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football I.
\n5(6\/8) = 5 x 8.
\n5 x 8 = 40.
\n40 + 6\/8 = 46\/8.
\n46\/8 = 5.7.<\/p>\n

Answer:
\nJ: 6(1\/8) = 6.1<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe height of the Football J.
\n6(1\/8) = 6 x 8.
\n6 x 8 = 48.
\n48 + 1\/8 = 49\/8.
\n49\/8 = 6.1.<\/p>\n

a. Use the data to create a line plot at the bottom of this page and to answer the questions below.<\/p>\n

Answer:
\nThe points on the co-ordinate plane increase.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe players on the y-axis.
\nthe height of the football on the x-axis.
\nthe points on the graph increases.<\/p>\n

b. What is the difference in height of the tallest and shortest players?<\/p>\n

Answer:
\nThe difference in height of the tallest and shortest players = 0.9.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe height of the tallest player = 6.6,
\nthe height of the shortest player = 5.7.
\n6.6 – 5.7 = 0.9.
\nso the difference in height of the tallest and shortest players = 0.9.<\/p>\n

c. Player I and Player B have a combined height that is 1\\(\\frac{1}{8}\\) feet taller than a school bus. What is the height of a school bus?<\/p>\n

Answer:
\nThe height of the school bus = 10.375.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nplayer I and player B have a combined height that is 1(1\/8) feet.
\n1(1\/8) = 8 + 1\/8.
\n9\/8 = 1.125.
\nPlayer I = 5.7.
\nPlayer H = 5.8.
\n5.7 + 5.8 = 11.5.
\n11.5 – 1.125 = 10.375.
\nso the height of the school bus = 10.375 ft.<\/p>\n

Question 2.
\nOne of the players on the team is now 4 times as tall as he was at birth, when he measured 1\\(\\frac{5}{8}\\) feet. Who is the player?<\/p>\n

Answer:
\nThe Player = C.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nOne of the players on the team is now 4 times as tall as he was at birth.
\n1(5\/8) = 1 x 8 = 8.
\n8 + 5\/8 = 13\/8.
\n13\/8 = 1.6.
\n1.6 x 4 = 2.4.
\nso player C has the 6.4 ft height.<\/p>\n

Question 3.
\nSix of the players on the team weigh over 300 pounds. Doctors recommend that players of this weight drink at least 3\\(\\frac{3}{4}\\) quarts of water each day. At least how much water should be consumed per day by all 6 players?<\/p>\n

Answer:
\nThe water should be consumed per day by all 6 players = 22.2 quarts.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nSix of the players on the team weigh over 300 pounds.
\n3(3\/4) quarts.
\n3 x 4 = 12.
\n12 + 3\/4 = 15\/4.
\n15\/4 = 3.7.
\n3.7 x 6 = 22.2 quarts.<\/p>\n

Question 4.
\nNine of the players on the team weigh about 200 pounds. Doctors recommend that people of this weight each eat about 3\\(\\frac{7}{10}\\) grams of carbohydrates per pound each day. About how many combined grams of carbohydrates should these 9 players eat per pound each day?<\/p>\n

Answer:
\nThe combined grams of carbohydrates should these 9 players eat per pound each day = 33.3 ft.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nNine of the players on the team weigh about 200 pounds.
\n3(7\/10) = 3 x 10.
\n30 + 7\/10 = 37\/10.
\n37\/10 = 3.7.
\n3.7 x 9 = 33.3 ft.<\/p>\n

Eureka Math Grade 4 Module 5 Lesson 40 Exit Ticket Answer Key<\/h3>\n

Coach Taylor asked his team to record the distance they ran during practice. The distances are listed in the table.<\/p>\n\n\n\n\n\n\n\n\n\n\n\n
Team Members<\/strong><\/td>\nDistance<\/strong>
\n(in miles)<\/strong><\/td>\n<\/tr>\n
Alec<\/td>\n1\\(\\frac{3}{4}\\)<\/td>\n<\/tr>\n
Henry<\/td>\n1\\(\\frac{1}{2}\\)<\/td>\n<\/tr>\n
Charles<\/td>\n2\\(\\frac{1}{8}\\)<\/td>\n<\/tr>\n
Steve<\/td>\n1\\(\\frac{3}{4}\\)<\/td>\n<\/tr>\n
Pitch<\/td>\n2\\(\\frac{2}{4}\\)<\/td>\n<\/tr>\n
Raj<\/td>\n1\\(\\frac{6}{8}\\)<\/td>\n<\/tr>\n
Pam<\/td>\n2\\(\\frac{1}{2}\\)<\/td>\n<\/tr>\n
Tony<\/td>\n1\\(\\frac{3}{8}\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\nAlec: 1(3\/4) = 1.7miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n1(3\/4) = 1 x 4.
\n1 x 4 = 4.
\n4 + 3\/4 = 7\/4.
\n25\/4 = 1.75.<\/p>\n

Answer:
\nHenry: 1(1\/2) = 1.5miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n1(1\/2) = 1 x 2.
\n1 x 2 = 2.
\n2 + 1\/2 = 3\/2.
\n3\/2 = 1.5.<\/p>\n

Answer:
\nCharles: 2(1\/8) = 2.1miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n2(1\/8) = 2 x 8.
\n2 x 8 = 16.
\n16 + 1\/8 = 17\/8.
\n17\/8 = 2.1.<\/p>\n

Answer:
\nSteve: 1(3\/4) = 1.7miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n1(3\/4) = 1 x 4.
\n1 x 4 = 4.
\n4 + 3\/4 = 7\/4.
\n25\/4 = 1.75.<\/p>\n

Answer:
\nPitch: 2(2\/4) = 1miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n2(2\/4) = 2 x 4.
\n2 x 4 = 8.
\n2 + 2\/4 = 4\/4.
\n4\/4 = 1.<\/p>\n

Answer:
\nRaj: 1(6\/8) = 1.7miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n1(6\/8) = 1 x 8.
\n1 x 8 = 8.
\n8 + 6\/8 = 14\/8.
\n14\/8 = 1.75.<\/p>\n

Answer:
\nPam: 2(1\/2) = 2.5miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n2(1\/2) = 2 x 2.
\n2 x 2 = 4.
\n4 + 1\/2 = 5\/2.
\n5\/2 = 2.5.<\/p>\n

Answer:
\nTony: 1(3\/8) = 1.37miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nThe distance of Team members in miles.
\n1(3\/8) = 1 x 8.
\n1 x 8 = 8.
\n8 + 3\/8 = 11\/8.
\n11\/8 = 1.37.<\/p>\n

Question 1.
\nUse the table to locate the incorrect data on the line plot.
\nCircle any incorrect points.
\nMark any missing points.<\/p>\n

Answer:
\nThere are no incorrect points.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,<\/p>\n

Question 2.
\nOf the team members who ran 1\\(\\frac{6}{8}\\) miles, how many miles did those team members run combined?<\/p>\n

Answer:
\nThe team members run combined = 5.25 miles.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nOf the team members who ran 1(6\/8) miles.
\n1 x 6\/8 = 8 + 6\/8.
\n14\/8 = 1.75 miles.
\n1.75 + 1.75 + 1.75 = 5.25 miles.<\/p>\n

Eureka Math Grade 4 Module 5 Lesson 40 Homework Answer Key<\/h3>\n

The chart to the right shows the total monthly rainfall for a city.<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

Month<\/strong><\/p>\n<\/td>\n

\n

Rainfall<\/strong><\/p>\n

(in inches)<\/strong><\/p>\n<\/td>\n<\/tr>\n

January<\/td>\n2\\(\\frac{2}{8}\\)<\/td>\n<\/tr>\n
February<\/td>\n1\\(\\frac{3}{8}\\)<\/td>\n<\/tr>\n
March<\/td>\n2\\(\\frac{3}{8}\\)<\/td>\n<\/tr>\n
April<\/td>\n2\\(\\frac{5}{8}\\)<\/td>\n<\/tr>\n
May<\/td>\n4\\(\\frac{1}{4}\\)<\/td>\n<\/tr>\n
June<\/td>\n2\\(\\frac{1}{4}\\)<\/td>\n<\/tr>\n
July<\/td>\n3\\(\\frac{7}{8}\\)<\/td>\n<\/tr>\n
August<\/td>\n3\\(\\frac{1}{4}\\)<\/td>\n<\/tr>\n
September<\/td>\n1\\(\\frac{5}{8}\\)<\/td>\n<\/tr>\n
October<\/td>\n3\\(\\frac{2}{8}\\)<\/td>\n<\/tr>\n
November<\/td>\n1\\(\\frac{3}{4}\\)<\/td>\n<\/tr>\n
December<\/td>\n1\\(\\frac{5}{8}\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\nJanuary:2(2\/8) = 2.2 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n2(2\/8) = 2 x 8.
\n16 + 2\/8 = 18\/8.
\n18\/8 = 2.25 in.<\/p>\n

Answer:
\nFebraury:1(3\/8) = 1.3 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n1(3\/8) = 1 x 8.
\n8 + 3\/8 = 11\/8.
\n11\/8 = 1.3 in.<\/p>\n

Answer:
\nMarch:2(3\/8) = 2.3 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n2(3\/8) = 2 x 8.
\n16 + 3\/8 = 19\/8.
\n19\/8 = 2.3 in.<\/p>\n

Answer:
\nApril:2(5\/8) = 2.6 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n2(5\/8) = 2 x 8.
\n16 + 5\/8 = 21\/8.
\n21\/8 = 2.6 in.<\/p>\n

Answer:
\nMay:4(1\/4) = 4.2 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n4(1\/4) = 4 x 4.
\n16 + 1\/4 = 17\/4.
\n17\/4 = 4.25 in.<\/p>\n

Answer:
\nJune:2(1\/4) = 2.2 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n2(1\/4) = 2 x 4.
\n8 + 1\/4 = 9\/4.
\n9\/4 = 2.25 in.<\/p>\n

Answer:
\nJuly:3(7\/8) = 3.8 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n3(7\/8) = 3 x 8.
\n24 + 7\/8 = 31\/8.
\n31\/8 = 3.8 in.<\/p>\n

Answer:
\nAugust:3(1\/4) = 3.2 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n3(1\/4) = 3 x 4.
\n12 + 1\/4 = 13\/4.
\n13\/4 = 3.25 in.<\/p>\n

Answer:
\nSeptember:1(5\/8) = 1.6 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n1(5\/8) = 1 x 8.
\n8 + 5\/8 = 13\/8.
\n13\/8 = 1.6 in.<\/p>\n

Answer:
\nOctober:3(2\/8) = 3.2 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n3(2\/8) = 3 x 8.
\n24 + 2\/8 = 26\/8.
\n26\/8 = 3.25 in.<\/p>\n

Answer:
\nNovember:1(3\/4) = 1.7 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n1(3\/4) = 1 x 4.
\n4 + 3\/4 = 7\/4.
\n7\/4 = 1.75 in.<\/p>\n

Answer:
\nDecember:1(5\/8) = 1.6 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe monthly rainfall for a city.
\n1(5\/8) = 1 x 8.
\n8 + 5\/8 = 13\/8.
\n13\/8 = 1.625 in.<\/p>\n

Question 1.
\nUse the data to create a line plot at the bottom of this page and to answer the following questions.<\/p>\n

Answer:
\nThe points on the co-ordinate plane increase.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe months on the y-axis.
\nthe rainfall on the x-axis.
\nthe points on the graph increases.<\/p>\n

Question 2.
\nWhat is the difference in rainfall from the wettest and driest months?<\/p>\n

Answer:
\nThe difference in rainfall from the wettest and driest months = 2.95 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe rainfall from the wettest months = 4.25 in.
\nthe rainfall from the driest months = 1.3 in.
\n4.25 – 1.3 = 2.95 in.<\/p>\n

Question 3.
\nHow much more rain fell in May than in April?<\/p>\n

Answer:
\nThe more rain fell in May than April = 1.65 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe rain fell in may = 4.25 in.
\nthe rain fell in April = 2.6 in.
\n4.25 – 2.6 = 1.65in.
\nso the rain fell in may than April = 1.65 in.<\/p>\n

Question 4.
\nWhat is the combined rainfall amount for the summer months of June, July, and August?<\/p>\n

Answer:
\nThe combined rainfall amount for the summer months of June, July, and August = 9.2 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe rainfall in June = 2.2 in.
\nthe rainfall in July = 3.8 in.
\nthe rainfall in August = 3.2 in.
\n2.2 + 3.8 + 3.2 = 9.2 in.
\nso the combined amount for the summer month of June, July, and August = 9.2 in.<\/p>\n

Question 5.
\nHow much more rain fell in the summer months than the combined rainfall for the last 4 months of the year?<\/p>\n

Answer:
\nThe combined rainfall for the last 4 months of the year = 8.1 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe much more rain fell in the summer months = 9.2 in.
\nSeptember = 1.6 in.
\nOctober = 3.2 in.
\nNovember = 1.75 in.
\nDecember = 1.625 in.
\n1.6 + 3.2 + 1.75 + 1.625 = 8.1 in.<\/p>\n

Question 6.
\nIn which months did it rain twice as much as it rained in December?<\/p>\n

Answer:
\nThe two months it rains twice as much as it rained in December = August and October.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nthe rainfall in December = 1.625 in.
\n1.625 + 1.625 = 3.25 in
\nAugust = 3.2 in.
\nOctober = 3.2 in.<\/p>\n

Question 7.
\nEach inch of rain can produce ten times that many inches of snow. If all of the rainfall in January was in the form of snow, how many inches of snow fell in January?<\/p>\n

Answer:
\nThe number of inches of snow fell in January = 22.5 in.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nEach inch of rain can produce ten times that many inches of snow.
\n2.25 x 10 = 22.5 in.<\/p>\n","protected":false},"excerpt":{"rendered":"

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