{"id":60791,"date":"2022-05-21T15:33:20","date_gmt":"2022-05-21T10:03:20","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=60791"},"modified":"2022-05-10T14:21:08","modified_gmt":"2022-05-10T08:51:08","slug":"eureka-math-grade-4-module-5-lesson-17","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-4-module-5-lesson-17\/","title":{"rendered":"Eureka Math Grade 4 Module 5 Lesson 17 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 4th Grade Module 5 Lesson 17 Answer Key<\/h2>\n

Eureka Math Grade 4 Module 5 Lesson 17 Problem Set Answer Key<\/h3>\n

Question 1.
\nUse the following three fractions to write two subtraction and two addition number sentences.
\na. \\(\\frac{8}{5}\\), \\(\\frac{2}{5}\\), \\(\\frac{10}{5}\\)<\/p>\n

Answer:
\nSubtraction sentences = 7\/5, 6\/5, 1\/5, -1\/5, 9\/5, 8\/5.
\nAddition sentences = 9\/5,10\/5, 3\/5, 4\/5, 11\/5, 12\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n8\/5, 2\/5, 10\/5.
\n8\/5 + 1 = 9\/5.
\n9\/5 + 1 = 10\/5.
\n2\/5 + 1 = 3\/5.
\n3\/5 + 1 = 4\/5.
\n10\/5 + 1 = 11\/5.
\n11\/5 + 1 = 12\/5.
\n8\/5 – 1 = 7\/5.
\n7\/5 – 1 = 6\/5.
\n2\/5 – 1 = 1\/5.
\n1\/5 – 1 = -1\/5.
\n10\/5 – 1 = 9\/5.
\n9\/5 – 1 = 8\/5.<\/p>\n

b. \\(\\frac{15}{8}\\), \\(\\frac{7}{8}\\), \\(\\frac{8}{8}\\)<\/p>\n

Answer:
\nSubtraction sentences = 14\/8, 13\/8, 6\/8, 5\/8, 7\/8, 6\/8.
\nAddition sentences = 16\/8,17\/8, 8\/8, 9\/8, 9\/8, 10\/8.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n15\/8, 7\/8, 8\/8.
\n15\/8 + 1 = 16\/8.
\n16\/8 + 1 = 17\/8.
\n7\/8 + 1 = 8\/8.
\n8\/8 + 1 = 9\/8.
\n9\/8 + 1 = 10\/8.
\n10\/8 + 1 = 11\/8.
\n15\/8 – 1 = 14\/8.
\n14\/8 – 1 = 13\/8.
\n7\/8 – 1 = 6\/8.
\n6\/8 – 1 = 5\/8.
\n8\/8 – 1 = -7\/8.
\n7\/8 – 1 = 6\/8.<\/p>\n

Question 2.
\nSolve. Model each subtraction problem with a number line, and solve by both counting up and subtracting. Part (a) has been completed for you.
\na. 1 – \\(\\frac{3}{4}\\)
\n\"Eureka<\/p>\n

Answer:
\n1 – 3\/4 = 1\/4.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 3\/4.
\n4 – 3\/4.
\n1\/4.<\/p>\n

b. 1 – \\(\\frac{8}{10}\\)<\/p>\n

Answer:
\n1 – 8\/10 = 2\/10.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 8\/10.
\n10 – 8\/10.
\n2\/10.<\/p>\n

c. 1 – \\(\\frac{3}{5}\\)<\/p>\n

Answer:
\n1 – 3\/5 = 2\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 3\/5.
\n5 – 3\/5.
\n2\/5.<\/p>\n

d. 1 – \\(\\frac{5}{8}\\)<\/p>\n

Answer:
\n1 – 5\/8 = 3\/8.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 5\/8.
\n8 – 5\/8.
\n3\/8.<\/p>\n

e. 1\\(\\frac{2}{10}\\) – \\(\\frac{7}{10}\\)<\/p>\n

Answer:
\n1 – 2\/10 – 7\/10 = 1\/10.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 2\/10.
\n10 – 2\/10.
\n8\/10 – 7\/10.
\n1\/10.<\/p>\n

f. 1\\(\\frac{1}{5}\\) – \\(\\frac{3}{5}\\)<\/p>\n

Answer:
\n1 – 1\/5 – 3\/5 = 1\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 1\/5.
\n5 – 1\/5.
\n4\/5 – 3\/5.
\n1\/5.<\/p>\n

Question 3.
\nFind the difference in two ways. Use number bonds to decompose the total. Part (a) has been completed for you.
\na. \"Eureka<\/p>\n

Answer:
\n5\/5 + 2\/5 = 7\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(2\/5) – 4\/5.
\n7\/5 – 4\/5 = 3\/5.
\n5\/5 + 2\/5 = 7\/5.
\n7\/5 – 4\/5 = 3\/5.
\n5\/5 – 4\/5 = 1\/5.
\n1\/5 + 2\/5 = 3\/5.<\/p>\n

b. 1\\(\\frac{3}{6}\\) – \\(\\frac{4}{6}\\)<\/p>\n

Answer:
\n6\/6 + 3\/6 = 9\/6.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(3\/6) – 4\/6.
\n9\/6 – 4\/6 = 5\/6.
\n6\/6 + 3\/6 = 9\/6.
\n9\/6 – 4\/6 = 5\/6.
\n6\/6 – 4\/6 = 2\/6.
\n2\/6 + 3\/6 = 5\/6.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

c. 1\\(\\frac{6}{8}\\) – \\(\\frac{7}{8}\\)<\/p>\n

Answer:
\n10\/8 + 4\/8 = 14\/8.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(6\/8) – 7\/8.
\n14\/8 – 7\/8 = 7\/8.
\n10\/8 + 4\/8 = 14\/8.
\n14\/8 – 7\/8 = 7\/8.
\n10\/8 – 7\/8 = 3\/8.
\n3\/8 + 4\/8 = 7\/8.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

d. 1\\(\\frac{1}{10}\\) – \\(\\frac{7}{10}\\)<\/p>\n

Answer:
\n8\/10 + 3\/10 = 11\/10.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(1\/10) – 7\/10.
\n11\/10 – 7\/10 = 4\/10.
\n8\/10 + 3\/10 = 11\/10.
\n11\/10 – 7\/10 = 4\/10.
\n8\/10 – 7\/10 = 2\/10.
\n2\/10 + 3\/10 = 5\/10.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

e. 1\\(\\frac{3}{12}\\) – \\(\\frac{6}{12}\\)<\/p>\n

Answer:
\n6\/12 + 3\/12 = 9\/12.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(3\/12) – 9\/12.
\n15\/12 – 9\/12 = 3\/12.
\n7\/12 + 8\/12 = 15\/12.
\n9\/12 – 6\/12 = 3\/12.
\n6\/12 – 6\/12 = 0.
\n6\/12 + 3\/12 = 9\/12.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

Eureka Math Grade 4 Module 5 Lesson 17 Exit Ticket Answer Key<\/h3>\n

Question 1.
\nSolve. Model the problem with a number line, and solve by both counting up and subtracting.
\n1 – \\(\\frac{2}{5}\\)<\/p>\n

Answer:
\n1 – 2\/5 = 3\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 2\/5.
\n5 – 2\/5.
\n3\/5.<\/p>\n

Question 2.
\nFind the difference in two ways. Use a number bond to show the decomposition.
\n1\\(\\frac{2}{7}\\) – \\(\\frac{5}{7}\\)<\/p>\n

Answer:
\n5\/7 + 4\/7 = 9\/7.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(2\/7) – 5\/7.
\n9\/7 – 5\/7 = 4\/7.
\n5\/7 + 4\/7 = 9\/7.
\n9\/7 – 5\/7 = 4\/7.
\n5\/7 – 4\/5 = 1\/7.
\n1\/7 + 2\/7 = 3\/7.<\/p>\n

Eureka Math Grade 4 Module 5 Lesson 17 Homework Answer Key<\/h3>\n

Question 1.
\nUse the following three fractions to write two subtraction and two addition number sentences.<\/p>\n

a. \\(\\frac{5}{6}\\), \\(\\frac{4}{6}\\), \\(\\frac{9}{6}\\)<\/p>\n

Answer:
\nSubtraction sentences = 4\/6, 3\/6, 3\/6, 2\/6, 8\/6, 7\/6.
\nAddition sentences = 6\/6,7\/6, 5\/6, 6\/6, 10\/6, 11\/6.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n5\/6, 4\/6, 9\/6.
\n5\/6 + 1 = 6\/6.
\n6\/6 + 1 = 7\/6.
\n4\/6 + 1 = 5\/6.
\n5\/6 + 1 = 6\/6.
\n9\/6 + 1 = 10\/6.
\n10\/6 + 1 = 11\/6.
\n5\/6 – 1 = 4\/6.
\n4\/6 – 1 = 3\/6.
\n4\/6 – 1 = 3\/6.
\n3\/6 – 1 = 2\/6.
\n9\/6 – 1 = -8\/6.
\n8\/6 – 1 = 7\/6.<\/p>\n

b. \\(\\frac{5}{9}\\), \\(\\frac{13}{9}\\), \\(\\frac{8}{9}\\)<\/p>\n

Answer:
\nSubtraction sentences = 4\/9, 3\/9, 12\/9, 11\/9, 7\/9, 6\/9.
\nAddition sentences = 6\/9,7\/9, 14\/9, 15\/9, 9\/9, 10\/9.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n5\/9, 13\/9, 8\/9.
\n5\/9 + 1 = 6\/9.
\n6\/9 + 1 = 7\/9.
\n13\/9 + 1 = 14\/9.
\n14\/9 + 1 = 15\/9.
\n8\/9 + 1 = 9\/9.
\n9\/9 + 1 = 10\/9.
\n5\/9 – 1 = 4\/9.
\n4\/9 – 1 = 3\/9.
\n13\/9 – 1 = 12\/9.
\n12\/9 – 1 = 11\/9.
\n8\/9 – 1 =\u00a0 7\/9.
\n7\/9 – 1 = 6\/9.<\/p>\n

Question 2.
\nSolve. Model each subtraction problem with a number line, and solve by both counting up and subtracting.<\/p>\n

a. 1 – \\(\\frac{5}{8}\\)<\/p>\n

Answer:
\n1 – 5\/8 = 3\/8.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 5\/8.
\n8 – 5\/8.
\n3\/8.<\/p>\n

b. 1 – \\(\\frac{2}{5}\\)<\/p>\n

Answer:
\n1 – 2\/5 = 3\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 2\/5.
\n5 – 2\/5.
\n3\/5.<\/p>\n

c. 1\\(\\frac{3}{6}\\) – \\(\\frac{5}{6}\\)<\/p>\n

Answer:
\n1 – 3\/6 – 5\/6 = -2\/6.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 3\/6.
\n6 – 3\/6.
\n3\/6 – 5\/6.
\n-2\/6.<\/p>\n

d. 1 – \\(\\frac{1}{4}\\)<\/p>\n

Answer:
\n1 – 1\/4 = 3\/4.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 1\/4.
\n4 – 1\/4.
\n3\/4.<\/p>\n

e. 1\\(\\frac{1}{3}\\) – \\(\\frac{2}{3}\\)<\/p>\n

Answer:
\n1 – 1\/3 – 2\/3 = 0.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 1\/3.
\n3 – 1\/3.
\n2\/3 – 2\/3.
\n0<\/p>\n

f. 1\\(\\frac{1}{5}\\) – \\(\\frac{2}{5}\\)<\/p>\n

Answer:
\n1 – 1\/5 – 2\/5 = 2\/5.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\nModel each subtraction problem with a number line.
\n1 – 1\/5.
\n5 – 1\/5.
\n4\/5 – 2\/5.
\n2\/5.<\/p>\n

Question 3.
\nFind the difference in two ways. Use number bonds to decompose the total. Part (a) has been completed for you.
\na. \"Eureka<\/p>\n

b. 1\\(\\frac{3}{8}\\) – \\(\\frac{7}{8}\\)<\/p>\n

Answer:
\n8\/8 + 3\/8 = 11\/8.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(3\/8) – 7\/8.
\n11\/8 – 7\/8 = 4\/8.
\n8\/8 + 3\/8 = 11\/8.
\n11\/8 – 7\/8 = 4\/8.
\n8\/8 – 7\/8 = 1\/8.
\n1\/8 + 3\/8 = 4\/8.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

c. 1\\(\\frac{1}{4}\\) – \\(\\frac{3}{4}\\)<\/p>\n

Answer:
\n8\/10 + 3\/10 = 11\/10.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(1\/4) – 3\/4.
\n5\/4 – 3\/4 = 2\/4.
\n3\/4 + 2\/4 = 5\/4.
\n5\/4 – 3\/4 = 2\/4.
\n3\/4 – 3\/4 = 0.
\n0 + 2\/4 = 2\/4.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

d. 1\\(\\frac{2}{7}\\) – \\(\\frac{5}{7}\\)<\/p>\n

Answer:
\n6\/7 + 3\/7 = 9\/7.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(2\/7) – 5\/7.
\n9\/7 – 2\/7 = 7\/7.
\n6\/7 + 3\/7 = 9\/7.
\n9\/7 – 2\/7 = 7\/7.
\n6\/7 – 2\/7 = 4\/7.
\n4\/7 + 3\/7 = 7\/7.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n

e. 1\\(\\frac{3}{10}\\) – \\(\\frac{7}{10}\\)<\/p>\n

Answer:
\n8\/10 + 3\/10 = 11\/10.<\/p>\n

Explanation:
\nIn the above-given question,
\ngiven that,
\n1(3\/10) – 7\/10.
\n13\/10 – 7\/10 = 6\/10.
\n7\/10 + 6\/10 = 13\/10.
\n13\/10 – 7\/10 = 6\/10.
\n7\/10 – 7\/10 = 0.
\n0 + 6\/10 = 6\/10.
\n\"Eureka-Math-Grade-4-Module-5-Lesson-17-Answer<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 4th Grade Module 5 Lesson 17 Answer Key Eureka Math Grade 4 Module 5 Lesson 17 Problem Set Answer Key Question 1. Use the following three fractions to write two subtraction and two addition number sentences. a. , , Answer: Subtraction sentences = 7\/5, 6\/5, 1\/5, -1\/5, 9\/5, 8\/5. Addition sentences … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/60791"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=60791"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/60791\/revisions"}],"predecessor-version":[{"id":136686,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/60791\/revisions\/136686"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=60791"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=60791"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=60791"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}