\nConvert each mixed number to a fraction greater than 1. Draw a number line to model your work.
\na. 3\\(\\frac{1}{4}\\)
\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-4-Module-5-Lesson-25-Problem-Set-Answer-Key-1.png\")
<\/p>\nQuestion 1.
\nConvert each mixed number to a fraction greater than 1. Draw a number line to model your work.
\na. 3\\(\\frac{1}{4}\\)
\n<\/p>\n
Answer:
\n3(1\/4) = 13\/4.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(1\/4).
\n3 + 1\/4.
\n12\/4 + 1\/4.
\n13\/4.<\/p>\n
b. 2\\(\\frac{4}{5}\\)<\/p>\n
Answer:
\n2(4\/5) = 14\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n2(4\/5).
\n2 + 4\/5.
\n10\/5 + 4\/5.
\n14\/5.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-1.png\")
<\/p>\n
c. 3\\(\\frac{5}{8}\\)<\/p>\n
Answer:
\n3(5\/8) = 29\/8.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(5\/8).
\n3 + 5\/8.
\n24\/8 + 5\/8.
\n29\/8.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-2.png\")
<\/p>\n
d. 4\\(\\frac{4}{10}\\)<\/p>\n
Answer:
\n4(4\/10) = 44\/10.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n4(4\/10).
\n4 + 4\/10.
\n40\/10 + 4\/10.
\n44\/10.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-3.png\")
<\/p>\n
e. 4\\(\\frac{7}{9}\\)<\/p>\n
Answer:
\n4(7\/9) = 43\/9.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n4(7\/9).
\n4 + 7\/9.
\n36\/9 + 7\/9.
\n43\/9.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-4.png\")
<\/p>\n
Question 2.
\nConvert each mixed number to a fraction greater than 1. Show your work as in the example.
\n(Note: 3 \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{3 \\times 4}{4}\\))
\na. 3\\(\\frac{3}{4}\\)
\n3\\(\\frac{3}{4}\\) = 3 + \\(\\frac{3}{4}\\) = (3 \u00d7 \\(\\frac{3}{4}\\)) + \\(\\frac{3}{4}\\) = \\(\\frac{12}{4}\\) + \\(\\frac{3}{4}\\) = \\(\\frac{15}{4}\\)<\/p>\n
Answer:
\n3(3\/4) = 15\/4.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n3\\(\\frac{3}{4}\\) = 3 + \\(\\frac{3}{4}\\).
\n(3 \u00d7 \\(\\frac{3}{4}\\)) + \\(\\frac{3}{4}\\) = \\(\\frac{12}{4}\\) + \\(\\frac{3}{4}\\).
\n\\(\\frac{15}{4}\\).<\/p>\n
b. 4\\(\\frac{1}{3}\\)<\/p>\n
Answer:
\n4(1\/3) = 13\/3.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{1}{3}\\) = 4 + \\(\\frac{1}{3}\\).
\n(4 \u00d7 \\(\\frac{1}{3}\\)) + \\(\\frac{1}{3}\\) = \\(\\frac{12}{3}\\) + \\(\\frac{1}{3}\\).
\n\\(\\frac{13}{3}\\).<\/p>\n
c. 4\\(\\frac{3}{5}\\)<\/p>\n
Answer:
\n4(3\/5) = 23\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{3}{5}\\) = 4 + \\(\\frac{3}{5}\\).
\n(4 \u00d7 \\(\\frac{3}{5}\\)) + \\(\\frac{3}{5}\\) = \\(\\frac{20}{5}\\) + \\(\\frac{3}{5}\\).
\n\\(\\frac{23}{5}\\).<\/p>\n
d. 4\\(\\frac{6}{8}\\)<\/p>\n
Answer:
\n4(6\/8) = 38\/8.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{6}{8}\\) = 4 + \\(\\frac{6}{8}\\).
\n(4 \u00d7 \\(\\frac{6}{8}\\)) + \\(\\frac{6}{8}\\) = \\(\\frac{32}{8}\\) + \\(\\frac{6}{8}\\).
\n\\(\\frac{38}{8}\\).<\/p>\n
Question 3.
\nConvert each mixed number to a fraction greater than 1.
\na. 2\\(\\frac{3}{4}\\)<\/p>\n
Answer:
\n2(3\/4) = 11\/4.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n2(3\/4).
\n2 + 3\/4.
\n8\/4 + 3\/4.
\n11\/4.<\/p>\n
b. 2\\(\\frac{2}{5}\\)<\/p>\n
Answer:
\n2(2\/5) = 12\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n2(2\/5).
\n2 + 2\/5.
\n10\/5 + 2\/5.
\n12\/5.<\/p>\n
c. 3\\(\\frac{3}{6}\\)<\/p>\n
Answer:
\n3(3\/6) = 21\/6.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(3\/6).
\n3 + 3\/6.
\n18\/6 + 3\/6.
\n21\/6.<\/p>\n
d. 3\\(\\frac{3}{8}\\)<\/p>\n
Answer:
\n3(3\/8) = 27\/8.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(3\/8).
\n3 + 3\/8.
\n24\/8 + 3\/8.
\n27\/8.<\/p>\n
e. 3\\(\\frac{1}{10}\\)<\/p>\n
Answer:
\n3(1\/10) = 31\/10.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(1\/10).
\n3 + 1\/10.
\n30\/10 + 1\/10.
\n31\/10.<\/p>\n
f. 4\\(\\frac{3}{8}\\)<\/p>\n
Answer:
\n4(3\/8) = 35\/8.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n4(3\/8).
\n4 + 3\/8.
\n32\/8 + 3\/8.
\n35\/8.<\/p>\n
g. 5\\(\\frac{2}{3}\\)<\/p>\n
Answer:
\n5(2\/3) = 17\/3.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n5(2\/3).
\n5 + 2\/3.
\n15\/3 + 2\/3.
\n17\/3.<\/p>\n
h. 6\\(\\frac{1}{2}\\)<\/p>\n
Answer:
\n6(1\/2) = 13\/2.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n6(1\/2).
\n6 + 1\/2.
\n12\/2 + 1\/2.
\n13\/2.<\/p>\n
i. 7\\(\\frac{3}{10}\\)<\/p>\n
Answer:
\n7(3\/10) = 73\/10.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n7(3\/10).
\n7 + 3\/10.
\n70\/10 + 3\/10.
\n73\/10.<\/p>\n
Convert each mixed number to a fraction greater than 1.<\/p>\n
Question 1.
\n3\\(\\frac{1}{5}\\)<\/p>\n
Answer:
\n3(1\/5) = 16\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(1\/5).
\n3 + 1\/5.
\n15\/5 + 1\/5.
\n16\/5.<\/p>\n
Question 2.
\n2\\(\\frac{3}{5}\\)<\/p>\n
Answer:
\n2(3\/5) = 13\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n2(3\/5).
\n2 + 3\/5.
\n10\/5 + 3\/5.
\n13\/5.<\/p>\n
Question 3.
\n4\\(\\frac{2}{9}\\)<\/p>\n
Answer:
\n4(2\/9) = 38\/9.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n4(2\/9).
\n4 + 2\/9.
\n36\/9 + 2\/9.
\n38\/9.<\/p>\n
Question 1.
\nConvert each mixed number to a fraction greater than 1. Draw a number line to model your work.
\na. 3\\(\\frac{1}{4}\\)
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-4th-Grade-Module-5-Lesson-25-Homework-Answer-Key-15.png\")
<\/p>\n
b. 4\\(\\frac{2}{5}\\)<\/p>\n
Answer:
\n4(2\/5) = 22\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n4(2\/5).
\n4 + 2\/5.
\n20\/5 + 2\/5.
\n22\/5.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-5.png\")
<\/p>\n
c. 5\\(\\frac{3}{8}\\)<\/p>\n
Answer:
\n5(3\/8) = 43\/8.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n5(3\/8).
\n5 + 3\/8.
\n40\/8 + 3\/8.
\n43\/8.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-6.png\")
<\/p>\n
d. 3\\(\\frac{7}{10}\\)<\/p>\n
Answer:
\n3(7\/10) = 37\/10.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n3(7\/10).
\n3 + 7\/10.
\n30\/10 + 7\/10.
\n37\/10.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-7.png\")
<\/p>\n
e. 6\\(\\frac{2}{9}\\)<\/p>\n
Answer:
\n6(2\/9) = 56\/9.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\n6(2\/9).
\n6 + 2\/9.
\n54\/9 + 2\/9.
\n56\/9.
\n![\"Eureka-Math-Grade-4-Module-5-Lesson-26-Answer](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-4-Module-5-Lesson-26-Answer-Key-8.png\")
<\/p>\n
Question 2.
\nConvert each mixed number to a fraction greater than 1. Show your work as in the example.
\n(Note: 3 \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{3 \\times 4}{4}\\).)<\/p>\n
a. 3\\(\\frac{3}{4}\\)
\n3\\(\\frac{3}{4}\\) = 3 + \\(\\frac{3}{4}\\) = (3 \u00d7 \\(\\frac{4}{4}\\)) + \\(\\frac{3}{4}\\) = \\(\\frac{12}{4}\\) + \\(\\frac{3}{4}\\) = \\(\\frac{15}{4}\\)<\/p>\n
b. 5\\(\\frac{2}{3}\\)<\/p>\n
Answer:
\n5(2\/3) = 17\/3.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n5\\(\\frac{2}{3}\\) = 5 + \\(\\frac{2}{3}\\).
\n(5 \u00d7 \\(\\frac{2}{3}\\)) + \\(\\frac{2}{3}\\) = \\(\\frac{15}{3}\\) + \\(\\frac{2}{3}\\).
\n\\(\\frac{17}{3}\\).<\/p>\n
c. 4\\(\\frac{1}{5}\\)<\/p>\n
Answer:
\n4(1\/5) = 21\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{1}{5}\\) = 4 + \\(\\frac{1}{5}\\).
\n(4 \u00d7 \\(\\frac{1}{5}\\)) + \\(\\frac{1}{5}\\) = \\(\\frac{20}{5}\\) + \\(\\frac{1}{5}\\).
\n\\(\\frac{21}{5}\\).<\/p>\n
d. 3\\(\\frac{7}{8}\\)<\/p>\n
Answer:
\n3(7\/8) = 31\/8.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n3\\(\\frac{7}{8}\\) = 3 + \\(\\frac{7}{8}\\).
\n(3 \u00d7 \\(\\frac{7}{8}\\)) + \\(\\frac{7}{8}\\) = \\(\\frac{24}{8}\\) + \\(\\frac{7}{8}\\).
\n\\(\\frac{31}{8}\\).<\/p>\n
Question 3.
\nConvert each mixed number to a fraction greater than 1.
\na. 2\\(\\frac{1}{3}\\)<\/p>\n
Answer:
\n2(1\/3) = 7\/3.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n2\\(\\frac{1}{3}\\) = 2 + \\(\\frac{1}{3}\\).
\n(2 \u00d7 \\(\\frac{1}{3}\\)) + \\(\\frac{1}{3}\\) = \\(\\frac{6}{3}\\) + \\(\\frac{1}{3}\\).
\n\\(\\frac{7}{3}\\).<\/p>\n
b. 2\\(\\frac{3}{4}\\)<\/p>\n
Answer:
\n2(3\/4) = 11\/4.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n2\\(\\frac{3}{4}\\) = 2 + \\(\\frac{3}{4}\\).
\n(2 \u00d7 \\(\\frac{3}{4}\\)) + \\(\\frac{3}{4}\\) = \\(\\frac{10}{4}\\) + \\(\\frac{3}{4}\\).
\n\\(\\frac{11}{4}\\).<\/p>\n
c. 3\\(\\frac{2}{5}\\)<\/p>\n
Answer:
\n3(2\/5) = 17\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n3\\(\\frac{2}{5}\\) = 3 + \\(\\frac{2}{5}\\).
\n(3 \u00d7 \\(\\frac{2}{5}\\)) + \\(\\frac{2}{5}\\) = \\(\\frac{15}{5}\\) + \\(\\frac{2}{5}\\).
\n\\(\\frac{17}{5}\\).<\/p>\n
d. 3\\(\\frac{1}{6}\\)<\/p>\n
Answer:
\n3(1\/6) = 19\/6.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n3\\(\\frac{1}{6}\\) = 3 + \\(\\frac{1}{6}\\).
\n(3 \u00d7 \\(\\frac{1}{6}\\)) + \\(\\frac{1}{6}\\) = \\(\\frac{18}{6}\\) + \\(\\frac{1}{6}\\).
\n\\(\\frac{19}{6}\\).<\/p>\n
e. 4\\(\\frac{5}{12}\\)<\/p>\n
Answer:
\n4(5\/12) = 53\/12.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{5}{12}\\) = 4 + \\(\\frac{5}{12}\\).
\n(4 \u00d7 \\(\\frac{5}{12}\\)) + \\(\\frac{5}{12}\\) = \\(\\frac{48}{12}\\) + \\(\\frac{5}{12}\\).
\n\\(\\frac{53}{12}\\).<\/p>\n
f. 4\\(\\frac{2}{5}\\)<\/p>\n
Answer:
\n4(2\/5) = 22\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{2}{5}\\) = 4 + \\(\\frac{2}{5}\\).
\n(4 \u00d7 \\(\\frac{2}{5}\\)) + \\(\\frac{2}{5}\\) = \\(\\frac{20}{5}\\) + \\(\\frac{2}{5}\\).
\n\\(\\frac{22}{5}\\).<\/p>\n
g. 4\\(\\frac{1}{10}\\)<\/p>\n
Answer:
\n4(1\/10) = 41\/10.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n4\\(\\frac{1}{10}\\) = 4 + \\(\\frac{1}{10}\\).
\n(4 \u00d7 \\(\\frac{1}{10}\\)) + \\(\\frac{1}{10}\\) = \\(\\frac{40}{10}\\) + \\(\\frac{1}{10}\\).
\n\\(\\frac{41}{10}\\).<\/p>\n
h. 5\\(\\frac{1}{5}\\)<\/p>\n
Answer:
\n5(1\/5) = 26\/5.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n5\\(\\frac{1}{5}\\) = 5 + \\(\\frac{1}{5}\\).
\n(5 \u00d7 \\(\\frac{1}{5}\\)) + \\(\\frac{1}{5}\\) = \\(\\frac{25}{5}\\) + \\(\\frac{1}{5}\\).
\n\\(\\frac{26}{5}\\).<\/p>\n
i. 5\\(\\frac{5}{6}\\)<\/p>\n
Answer:
\n5(5\/6) = 35\/6.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n5\\(\\frac{5}{6}\\) = 5 + \\(\\frac{5}{6}\\).
\n(5 \u00d7 \\(\\frac{5}{6}\\)) + \\(\\frac{5}{6}\\) = \\(\\frac{30}{6}\\) + \\(\\frac{5}{6}\\).
\n\\(\\frac{35}{6}\\).<\/p>\n
j. 6\\(\\frac{1}{4}\\)<\/p>\n
Answer:
\n6(1\/4) = 25\/4.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n6\\(\\frac{1}{4}\\) = 6 + \\(\\frac{1}{4}\\).
\n(6 \u00d7 \\(\\frac{1}{4}\\)) + \\(\\frac{1}{4}\\) = \\(\\frac{24}{4}\\) + \\(\\frac{1}{4}\\).
\n\\(\\frac{25}{4}\\).<\/p>\n
k. 7\\(\\frac{1}{2}\\)<\/p>\n
Answer:
\n7(1\/2) = 15\/2.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n7\\(\\frac{1}{2}\\) = 7 + \\(\\frac{1}{2}\\).
\n(7 \u00d7 \\(\\frac{1}{2}\\)) + \\(\\frac{1}{2}\\) = \\(\\frac{14}{2}\\) + \\(\\frac{1}{2}\\).
\n\\(\\frac{15}{2}\\).<\/p>\n
l. 7\\(\\frac{11}{12}\\)<\/p>\n
Answer:
\n7(11\/12) = 95\/12.<\/p>\n
Explanation:
\nIn the above-given question,
\ngiven that,
\nconvert each mixed number to a fraction greater than 1.
\n7\\(\\frac{11}{12}\\) = 7 + \\(\\frac{11}{12}\\).
\n(7 \u00d7 \\(\\frac{11}{12}\\)) + \\(\\frac{11}{12}\\) = \\(\\frac{84}{12}\\) + \\(\\frac{11}{12}\\).
\n\\(\\frac{95}{12}\\).<\/p>\n","protected":false},"excerpt":{"rendered":"
Engage NY Eureka Math 4th Grade Module 5 Lesson 25 Answer Key Eureka Math Grade 4 Module 5 Lesson 25 Problem Set Answer Key Question 1. Convert each mixed number to a fraction greater than 1. Draw a number line to model your work. a. 3 Answer: 3(1\/4) = 13\/4. Explanation: In the above-given question, … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/61072"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=61072"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/61072\/revisions"}],"predecessor-version":[{"id":136677,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/61072\/revisions\/136677"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=61072"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=61072"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=61072"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}