\nGeorge decided to paint a wall with two windows. Both windows are 3\\(\\frac{1}{2}\\) -ft by 4\\(\\frac{1}{2}\\)-ft rectangles. Find the area the paint needs to cover.
\n
![\"Engage](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Engage-NY-Math-Grade-5-Module-5-Lesson-14-Problem-Set-Answer-Key-1.png\")
\nAnswer:<\/p>\n
Question 1.
\nGeorge decided to paint a wall with two windows. Both windows are 3\\(\\frac{1}{2}\\) -ft by 4\\(\\frac{1}{2}\\)-ft rectangles. Find the area the paint needs to cover.
\n
\nAnswer:<\/p>\n
Given, the measurements of the window = 3 1\/2 feet by 4 1\/2 feet<\/p>\n
Area = length x width<\/p>\n
A = 3 1\/2 x 4 1\/2<\/p>\n
=\u00a0 7\/2 x 9\/2<\/p>\n
= 63\/4<\/p>\n
= 15 3\/4<\/p>\n
Number of windows = 2<\/p>\n
So, 2 x 15 3\/4<\/p>\n
= 30 6\/4 = 31 1\/2 square feet<\/p>\n
Area of the wall = 12 7\/8 x 8<\/p>\n
= 103 square feet<\/p>\n
Area to paint = 103 – 31 1\/2<\/p>\n
= 71 1\/2 square feet<\/p>\n
Therefore, the area need to paint = 71 1\/2 square feet.<\/p>\n
<\/p>\n
Question 2.
\nJoe uses square tiles, some of which he cuts in half, to make the figure below. If each square tile has a side length of 2\\(\\frac{1}{2}\\) inches, what is the total area of the figure?
\n![\"Engage](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Engage-NY-Math-Grade-5-Module-5-Lesson-14-Problem-Set-Answer-Key-2.png\")
\nAnswer:<\/p>\n
Total number of full tiles = 10<\/p>\n
Number of half tiles = 6 or 3 full tiles<\/p>\n
Total = 10 + 3 = 13 tiles<\/p>\n
Area of the tiles = 2 1\/2 x 21\/2<\/p>\n
A =25\/4 = 6 1\/4 square inches<\/p>\n
Now, 13 x 6 1\/4 = 78 13\/4<\/p>\n
= 81 1\/4 square inches<\/p>\n
Therefore, the area of the figure = 81 1\/4 square inches.<\/p>\n
Question 3.
\nAll-In-One Carpets is installing carpeting in three rooms. How many square feet of carpet are needed to carpet all three rooms?
\n![\"Engage](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Engage-NY-Math-Grade-5-Module-5-Lesson-14-Problem-Set-Answer-Key-3.png\")
\nAnswer:<\/p>\n
Area of the room A =<\/p>\n
25 1\/4 ft x 15 1\/2 ft<\/p>\n
= 25 1\/4 x 15 1\/2<\/p>\n
= 101\/4 x 31\/2<\/p>\n
= 3131\/8<\/p>\n
= 391 3\/8 square feet<\/p>\n
Area of the room B =<\/p>\n
19 x 18 1\/2<\/p>\n
= 352 19\/2<\/p>\n
= 351 1\/2 square feet<\/p>\n
Area of room C =<\/p>\n
25 1\/4 – 4 1\/4<\/p>\n
= 21<\/p>\n
21 x 16 3\/4<\/p>\n
= 336 63\/4<\/p>\n
= 351 3\/4 square feet<\/p>\n
Total area of three rooms =<\/p>\n
391 3\/8 + 351 1\/2 + 351 3\/4<\/p>\n
= 1093 5\/8<\/p>\n
Therefore, 1094 5\/8 square feet of carpet is needed to cover all the three rooms.<\/p>\n
Question 4. Price per Square Foot<\/strong><\/p>\n<\/td>\n<\/tr>\n Answer:<\/p>\n a.<\/p>\n Area = length x width<\/p>\n A= 36 2\/3 x 45 1\/6<\/p>\n = ( 36 x 45 ) + ( 36 x 1\/6) +(45 x 2\/3 ) + ( 2\/3 x 1\/6)<\/p>\n = 1620 + 6 +30 +1\/9<\/p>\n = 1656 1\/9 square feet<\/p>\n Therefore, he need 1656 1\/9 square feet of sod.<\/p>\n b.<\/p>\n According to given table,<\/p>\n 1000 x $0.27 = $270.00<\/p>\n 500 x $ 0.22 = $ 110.00<\/p>\n 157 x $ 0.19 = $ 29.83<\/p>\n Total = $270 + $110 + $29.83 = $409.83<\/p>\n Therefore, he will have to pay $409.83<\/p>\n Question 5. a.<\/p>\n Perimeter =<\/p>\n 8 x 6 1\/2<\/p>\n = 8 x 13\/2 = 52<\/p>\n 3 x 6 1\/2<\/p>\n = 3 x 13 \/2 = 19 1\/2<\/p>\n Perimeter = 52 + 52 + 19 1\/2 + 19 1\/2<\/p>\n = 104 + 39<\/p>\n = 143 inches<\/p>\n Therefore, perimeter of the arrangement = 143 inches’<\/p>\n b.<\/p>\n The area of the quilt =<\/p>\n Each square area = 8 – 1 1\/2<\/p>\n = 6 1\/2<\/p>\n All the squares = 42 1\/4 x 24<\/p>\n = 169\/4 x 24<\/p>\n = 1014 square inches<\/p>\n Therefore, the area of the quilt = 1014 square inches<\/p>\n Mr. Klimek made his wife a rectangular vegetable garden. The width is 5\\(\\frac{3}{4}\\) ft, and the length is 9\\(\\frac{4}{5}\\) ft. What is the area of the garden? Area = length x width<\/p>\n = 5 3\/4 x 9 4\/5<\/p>\n = ( 5 x 9 ) + ( 5 x 4\/5 ) + ( 9 x 3\/4 ) + ( 3\/4 x 4\/5 )<\/p>\n = 45 + 27\/4 + 20\/5 + 12\/20<\/p>\n = 900 + 135 + 80 + 12\/ 20<\/p>\n = 1127\/20<\/p>\n = 56 7\/20 square feet<\/p>\n Therefore, the area of the garden = 56 7\/20 square feet.<\/p>\n Question 1. a.<\/p>\n The measurement of menus = 6 feet wide by 7 1\/2 feet tall<\/p>\n Area = 6 x 7 1\/2<\/p>\n = ( 6 x 7 ) + ( 6 x 1\/2 )<\/p>\n = 42 + 3<\/p>\n = 45 square feet<\/p>\n The number of menus = 4<\/p>\n Total = 4 x 45 = 180<\/p>\n Therefore, the total space for menus = 180 square feet.<\/p>\n b.<\/p>\n The area of big board =<\/p>\n = 25 x 13 2\/3<\/p>\n = ( 25 x 2\/3 ) + ( 25 x 2\/3 )<\/p>\n = 325 + 50\/3<\/p>\n = 341 2\/3 square feet<\/p>\n Now,<\/p>\n The area not covered = 341 2\/3 – 180<\/p>\n = 161 2\/3 square feet<\/p>\n <\/p>\n Question 2. The number of full tiles = 12<\/p>\n The number of half tiles = 5<\/p>\n Total : 12 + 5 = 17<\/p>\n Given, the measurement each square = 4 1\/4<\/p>\n Area = 4 1\/4 x 4 1\/4<\/p>\n = 18 1\/16 square inches<\/p>\n Now,<\/p>\n 17 x 18 1\/16<\/p>\n = ( 17 x 18 ) + ( 17 x 1\/16 )<\/p>\n = 306 + 17\/16<\/p>\n = 306 + 1 1\/16<\/p>\n = 307 1\/16<\/p>\n Therefore, the total area of the figure = 307 1\/16 square inches.<\/p>\n Question 3. The area of 15 windows =<\/p>\n 4 3\/4 x 3 3\/5<\/p>\n = ( 4 x 3 ) + ( 4 x 3\/5 ) + ( 3 x 3\/4 ) + ( 3\/4 x 3\/5 )<\/p>\n = 12 + 12\/5 + 9\/4 + 9\/20<\/p>\n = 16 + 8\/20 + 5\/20 +9\/20<\/p>\n = 16 22\/20<\/p>\n = 17 1\/10 square feet<\/p>\n Now,<\/p>\n 15 x 17 1\/10<\/p>\n = 255 + 15\/10<\/p>\n = 256 1\/2 square feet.<\/p>\n The area of 7 windows =<\/p>\n 2 4\/5 x 6 1\/2<\/p>\n = 17 + 6\/5<\/p>\n = 18 1\/5 square feet<\/p>\n Total :<\/p>\n 17 1\/10 + 18 1\/5<\/p>\n = 35 + 1\/10 + 2\/10<\/p>\n = 35 3\/10<\/p>\n Therefore, they will need 35 3\/10 square feet of glass<\/p>\n Question 4. a.<\/p>\n 40 4\/5 x 50 7\/8<\/p>\n = ( 40 x 50 ) + ( 40 x 7\/8) + ( 50 x 4\/5) + ( 4\/5 x 7\/8)<\/p>\n = 200 +280\/8 +200\/5 + 28\/40<\/p>\n =2075 7\/10 square feet<\/p>\n Therefore, he will need 2075 7\/10 square feet of seed.<\/p>\n b.<\/p>\n For highest setting:<\/p>\n 2075 7\/10 square feet \/ 500 = 4 76\/500<\/p>\n = 5 bags<\/p>\n For lowest selling :<\/p>\n 2075 7\/10 \/ 300<\/p>\n = 6 276\/300<\/p>\n = 7 bags<\/p>\n Therefore, he need 5 bags for highest selling and 7 bags for the lowest selling.<\/p>\n","protected":false},"excerpt":{"rendered":" Engage NY Eureka Math 5th Grade Module 5 Lesson 14 Answer Key Eureka Math Grade 5 Module 5 Lesson 14 Problem Set Answer Key Question 1. George decided to paint a wall with two windows. Both windows are 3 -ft by 4-ft rectangles. Find the area the paint needs to cover. Answer: Given, the measurements … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/63255"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=63255"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/63255\/revisions"}],"predecessor-version":[{"id":136801,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/63255\/revisions\/136801"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=63255"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=63255"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=63255"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nMr. Johnson needs to buy sod for his front lawn.
\na. If the lawn measures 36\\(\\frac{2}{3}\\) ft by 45\\(\\frac{1}{6}\\) ft, how many square feet of sod will he need?
\nb. If sod is only sold in whole square feet, how much will Mr. Johnson have to pay?
\nSod Price<\/strong><\/p>\n\n\n
\n Area<\/strong><\/td>\n \n \n First 1,000 sq ft<\/td>\n $0.27<\/td>\n<\/tr>\n \n Next 500 sq ft<\/td>\n $0.22<\/td>\n<\/tr>\n \n Additional square feet<\/td>\n $0.19<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
\nJennifer\u2019s class decides to make a quilt. Each of the 24 students will make a quilt square that is 8 inches on each side. When they sew the quilt together, every edge of each quilt square will lose \\(\\frac{3}{4}\\) of an inch.
\na. Draw one way the squares could be arranged to make a rectangular quilt. Then, find the perimeter of your arrangement.
\nb. Find the area of the quilt.
\nAnswer:<\/p>\n![\"\"](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-5-Module-5-image73.png\")
<\/p>\nEureka Math Grade 5 Module 5 Lesson 14 Exit Ticket Answer Key<\/h3>\n
\nAnswer:<\/p>\nEureka Math Grade 5 Module 5 Lesson 14 Homework Answer Key<\/h3>\n
\nMr. Albano wants to paint menus on the wall of his caf\u00e9 in chalkboard paint. The gray area below shows where the rectangular menus will be. Each menu will measure 6-ft wide and 7\\(\\frac{1}{2}\\)-ft tall.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-5-Module-5-Lesson-14-Homework-Answer-Key-1.png\")
\n\u2022 How many square feet of menu space will Mr. Albano have?
\n\u2022 What is the area of wall space that is not covered by chalkboard paint?
\nAnswer:<\/p>\n
\nMr. Albano wants to put tiles in the shape of a dinosaur at the front entrance. He will need to cut some tiles in half to make the figure. If each square tile is 4\\(\\frac{1}{4}\\) inches on each side, what is the total area of the dinosaur?
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-5-Module-5-Lesson-14-Homework-Answer-Key-2.png\")
\nAnswer:<\/p>\n
\nA-Plus Glass is making windows for a new house that is being built. The box shows the list of sizes they must make.
\n15 windows 4\\(\\frac{3}{4}\\) -ft long and 3\\(\\frac{3}{5}\\)-ft wide
\n7 windows 2\\(\\frac{4}{5}\\) -ft wide and 6\\(\\frac{1}{2}\\) -ft long
\nHow many square feet of glass will they need?
\nAnswer:<\/p>\n
\nMr. Johnson needs to buy seed for his backyard lawn.
\n\u2022 If the lawn measures 40\\(\\frac{4}{5}\\) ft by 50\\(\\frac{7}{8}\\) ft, how many square feet of seed will he need to cover the entire area?
\n\u2022 One bag of seed will cover 500 square feet if he sets his seed spreader to its highest setting and 300 square feet if he sets the spreader to its lowest setting. How many bags of seed will he need if he uses the highest setting? The lowest setting?
\nAnswer:<\/p>\n