\nSubtract Fractions with Unlike Units
\n
![\"Engage](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Engage-NY-Math-5th-Grade-Module-3-Lesson-12-Sprint-Answer-Key-1.png\")
<\/p>\nA
\nSubtract Fractions with Unlike Units
\n<\/p>\n
Question 1.
\n\\(\\frac{2}{4}\\) \u2013 \\(\\frac{1}{4}\\) =
\nAnswer:
\n\\(\\frac{2}{4}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)<\/p>\n
Question 2.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{4}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{2}{4}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)<\/p>\n
Question 3.
\n\\(\\frac{2}{6}\\) \u2013 \\(\\frac{1}{6}\\) =
\nAnswer:
\n\\(\\frac{2}{6}\\) \u2013 \\(\\frac{1}{6}\\) = \\(\\frac{1}{6}\\)<\/p>\n
Question 4.
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{6}\\) =
\nAnswer:
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{6}\\) = \\(\\frac{1}{6}\\)
\nExplanation :
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{6}\\) =\\(\\frac{2}{6}\\) \u2013 \\(\\frac{1}{6}\\) = \\(\\frac{1}{6}\\)<\/p>\n
Question 5.
\n\\(\\frac{2}{8}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{2}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{1}{8}\\)<\/p>\n
Question 6.
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{1}{8}\\) =\\(\\frac{1}{8}\\)
\nExplanation :
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{2}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{1}{8}\\)<\/p>\n
Question 7.
\n\\(\\frac{6}{8}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{6}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n
Question 8.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{6}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n
Question 9.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{3}{8}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{3}{8}\\) = \\(\\frac{3}{8}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{3}{8}\\) = \\(\\frac{6}{8}\\) \u2013 \\(\\frac{3}{8}\\) =\u00a0\\(\\frac{3}{8}\\)<\/p>\n
Question 10.
\n\\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) =
\nAnswer:
\n\\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 11.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 12.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 13.
\n\\(\\frac{4}{10}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 14.
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{4}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 15.
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{3}{10}\\) =
\nAnswer:
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{4}{10}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n
Question 16.
\n\\(\\frac{6}{10}\\) \u2013 \\(\\frac{3}{10}\\) =
\nAnswer:
\n\\(\\frac{6}{10}\\) \u2013 \\(\\frac{3}{10}\\) =\\(\\frac{3}{10}\\)<\/p>\n
Question 17.
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{3}{10}\\) =
\nAnswer:
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{6}{10}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 18.
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{5}{10}\\) =
\nAnswer:
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{6}{10}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n
Question 19.
\n\\(\\frac{8}{10}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{8}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \u00a0\\(\\frac{7}{10}\\)<\/p>\n
Question 20.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{7}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \u00a0\\(\\frac{7}{10}\\)<\/p>\n
Question 21.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{5}{10}\\) = \u00a0\\(\\frac{4}{10}\\)<\/p>\n
Question 22.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{5}{10}\\) = \u00a0\\(\\frac{4}{10}\\)<\/p>\n
Question 23.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{7}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{7}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{7}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{7}{10}\\) = \u00a0\\(\\frac{1}{10}\\)<\/p>\n
Question 24.
\n\\(\\frac{2}{12}\\) \u2013 \\(\\frac{1}{12}\\) =
\nAnswer:
\n\\(\\frac{2}{12}\\) \u2013 \\(\\frac{1}{12}\\) =\u00a0\\(\\frac{1}{12}\\)<\/p>\n
Question 25.
\n\\(\\frac{1}{6}\\) \u2013 \\(\\frac{1}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{6}\\) \u2013 \\(\\frac{1}{12}\\) =\\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{6}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{2}{12}\\) \u2013 \\(\\frac{1}{12}\\) =\u00a0\\(\\frac{1}{12}\\)<\/p>\n
Question 26.
\n\\(\\frac{6}{12}\\) \u2013 \\(\\frac{1}{12}\\) =
\nAnswer:
\n\\(\\frac{6}{12}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n
Question 27.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{12}\\) = \u00a0\\(\\frac{5}{12}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{6}{12}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n
Question 28.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{5}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{5}{12}\\) = \u00a0\\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{5}{12}\\) = \\(\\frac{6}{12}\\) \u2013 \\(\\frac{5}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 29.
\n\\(\\frac{10}{12}\\) \u2013 \\(\\frac{5}{12}\\) =
\nAnswer:
\n\\(\\frac{10}{12}\\) \u2013 \\(\\frac{5}{12}\\) =\u00a0\\(\\frac{5}{12}\\)<\/p>\n
Question 30.
\n\\(\\frac{5}{6}\\) \u2013 \\(\\frac{5}{12}\\) =
\nAnswer:
\n\\(\\frac{5}{6}\\) \u2013 \\(\\frac{5}{12}\\) =\u00a0\\(\\frac{5}{12}\\)
\nExplanation :
\n\\(\\frac{5}{6}\\) \u2013 \\(\\frac{5}{12}\\) = \\(\\frac{10}{12}\\) \u2013 \\(\\frac{5}{12}\\) =\u00a0\\(\\frac{5}{12}\\)<\/p>\n
Question 31.
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{4}{12}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 32.
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{1}{12}\\) =
\nAnswer:
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{7}{12}\\)
\nExplanation :
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{8}{12}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{7}{12}\\)<\/p>\n
Question 33.
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{3}{12}\\) =
\nAnswer:
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{5}{12}\\)
\nExplanation :
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{8}{12}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n
Question 34.
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{7}{12}\\) =
\nAnswer:
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{7}{12}\\) = \\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{7}{12}\\) = \\(\\frac{8}{12}\\) \u2013 \\(\\frac{7}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 35.
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{2}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \u00a0\\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{3}{12}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 36.
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{15}\\) =
\nAnswer:
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{2}{15}\\)
\nExplanation :
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{3}{15}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{2}{15}\\)<\/p>\n
Question 37.
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{15}\\) =
\nAnswer:
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{15}\\) = \u00a0\\(\\frac{4}{15}\\)
\nExplanation :
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{5}{15}\\) \u2013 \\(\\frac{1}{15}\\) =\u00a0\\(\\frac{4}{15}\\)<\/p>\n
Question 38.
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{3}{15}\\) =
\nAnswer:
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{3}{15}\\) = \u00a0\\(\\frac{7}{15}\\)
\nExplanation :
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{3}{15}\\) = \\(\\frac{10}{15}\\) \u2013 \\(\\frac{3}{15}\\) = \\(\\frac{7}{15}\\)<\/p>\n
Question 39.
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{4}{15}\\) =
\nAnswer:
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{2}{15}\\)
\nExplanation :
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{6}{15}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{2}{15}\\)<\/p>\n
Question 40.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \u00a0\\(\\frac{7}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{7}{12}\\)<\/p>\n
Question 41.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{7}{16}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{12}{16}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{7}{16}\\)<\/p>\n
Question 42.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{15}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{15}\\) = \\(\\frac{7}{15}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{15}\\) = \\(\\frac{12}{15}\\) \u2013 \\(\\frac{5}{15}\\) = \\(\\frac{7}{15}\\)<\/p>\n
Question 43.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) = \u00a0\\(\\frac{5}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{4}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n
Question 44.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{7}{16}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{7}{16}\\) = \\(\\frac{5}{16}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{12}{16}\\) \u2013 \\(\\frac{7}{16}\\) = \\(\\frac{5}{16}\\)<\/p>\n
B
\nSubtract Fractions with Unlike Units
\n![\"Engage](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/03\/Engage-NY-Math-5th-Grade-Module-3-Lesson-12-Sprint-Answer-Key-2.png\")
<\/p>\n
Question 1.
\n\\(\\frac{2}{10}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{2}{10}\\) \u2013 \\(\\frac{1}{10}\\) =\u00a0\\(\\frac{1}{10}\\)<\/p>\n
Question 2.
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{2}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n
Question 3.
\n\\(\\frac{2}{4}\\) \u2013 \\(\\frac{1}{4}\\) =
\nAnswer:
\n\\(\\frac{2}{4}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)<\/p>\n
Question 4.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{4}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{2}{4}\\) \u2013 \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)<\/p>\n
Question 5.
\n\\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) =
\nAnswer:
\n\\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 6.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{5}{10}\\) \u2013 \\(\\frac{2}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 7.
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{4}{10}\\) =
\nAnswer:
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{4}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{1}{2}\\) \u2013 \\(\\frac{4}{10}\\) = \\(\\frac{5}{10}\\) \u2013 \\(\\frac{4}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n
Question 8.
\n\\(\\frac{4}{10}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 9.
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{4}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 10.
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{3}{10}\\) =
\nAnswer:
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{4}{10}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n
Question 11.
\n\\(\\frac{6}{10}\\) \u2013 \\(\\frac{3}{10}\\) =
\nAnswer:
\n\\(\\frac{6}{10}\\) \u2013 \\(\\frac{3}{10}\\) =\\(\\frac{3}{10}\\)<\/p>\n
Question 12.
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{3}{10}\\) =
\nAnswer:
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{6}{10}\\) \u2013 \\(\\frac{3}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n
Question 13.
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{5}{10}\\) =
\nAnswer:
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{3}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{6}{10}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n
Question 14.
\n\\(\\frac{8}{10}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{8}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \u00a0\\(\\frac{7}{10}\\)<\/p>\n
Question 15.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{1}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{7}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{1}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{1}{10}\\) = \u00a0\\(\\frac{7}{10}\\)<\/p>\n
Question 16.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{5}{10}\\) = \u00a0\\(\\frac{4}{10}\\)<\/p>\n
Question 17.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{3}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{5}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{5}{10}\\) = \u00a0\\(\\frac{4}{10}\\)<\/p>\n
Question 18.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{7}{10}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{7}{10}\\) = \\(\\frac{1}{10}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{7}{10}\\) = \\(\\frac{8}{10}\\) \u2013 \\(\\frac{7}{10}\\) = \u00a0\\(\\frac{1}{10}\\)<\/p>\n
Question 19.
\n\\(\\frac{2}{8}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{2}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{1}{8}\\)<\/p>\n
Question 20.
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{1}{8}\\) =\\(\\frac{1}{8}\\)
\nExplanation :
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{2}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{1}{8}\\)<\/p>\n
Question 21.
\n\\(\\frac{6}{8}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{6}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n
Question 22.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{1}{8}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{6}{8}\\) \u2013 \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n
Question 23.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{3}{8}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{3}{8}\\) = \\(\\frac{3}{8}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{3}{8}\\) = \\(\\frac{6}{8}\\) \u2013 \\(\\frac{3}{8}\\) =\u00a0\\(\\frac{3}{8}\\)<\/p>\n
Question 24.
\n\\(\\frac{5}{15}\\) \u2013 \\(\\frac{1}{15}\\) =
\nAnswer:
\n\\(\\frac{5}{15}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{4}{15}\\)<\/p>\n
Question 25.
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{15}\\) =
\nAnswer:
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{15}\\) = \u00a0\\(\\frac{4}{15}\\)
\nExplanation :
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{5}{15}\\) \u2013 \\(\\frac{1}{15}\\) =\u00a0\\(\\frac{4}{15}\\)<\/p>\n
Question 26.
\n\\(\\frac{3}{15}\\) \u2013 \\(\\frac{1}{15}\\) =
\nAnswer:
\n\\(\\frac{3}{15}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{2}{15}\\)<\/p>\n
Question 27.
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{15}\\) =
\nAnswer:
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{2}{15}\\)
\nExplanation :
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{3}{15}\\) \u2013 \\(\\frac{1}{15}\\) = \\(\\frac{2}{15}\\)<\/p>\n
Question 28.
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{2}{15}\\) =
\nAnswer:
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{1}{15}\\)
\nExplanation :
\n\\(\\frac{1}{5}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{3}{15}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{1}{15}\\)<\/p>\n
Question 29.
\n\\(\\frac{12}{15}\\) \u2013 \\(\\frac{4}{15}\\) =
\nAnswer:
\n\\(\\frac{12}{15}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{8}{15}\\)<\/p>\n
Question 30.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{4}{15}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{2}{3}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{12}{15}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{10}{15}\\)= \\(\\frac{2}{3}\\)<\/p>\n
Question 31.
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{2}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \u00a0\\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{3}{12}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 32.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \u00a0\\(\\frac{7}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{7}{12}\\)<\/p>\n
Question 33.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) = \u00a0\\(\\frac{5}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{4}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n
Question 34.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{8}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{8}{12}\\) = \u00a0\\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{8}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{8}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 35.
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{4}{12}\\) \u2013 \\(\\frac{3}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n
Question 36.
\n\\(\\frac{1}{6}\\) \u2013 \\(\\frac{1}{12}\\) =
\nAnswer:
\n\\(\\frac{1}{6}\\) \u2013 \\(\\frac{1}{12}\\) =\\(\\frac{1}{12}\\)
\nExplanation :
\n\\(\\frac{1}{6}\\) \u2013 \\(\\frac{1}{12}\\) = \\(\\frac{2}{12}\\) \u2013 \\(\\frac{1}{12}\\) =\u00a0\\(\\frac{1}{12}\\)<\/p>\n
Question 37.
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{15}\\) =
\nAnswer:
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{15}\\) = \u00a0\\(\\frac{2}{15}\\)
\nExplanation :
\n\\(\\frac{1}{3}\\) \u2013 \\(\\frac{3}{15}\\) = \\(\\frac{5}{15}\\) \u2013 \\(\\frac{3}{15}\\) = \\(\\frac{2}{15}\\)<\/p>\n
Question 38.
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{2}{15}\\) =
\nAnswer:
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{2}{15}\\) = \u00a0\\(\\frac{8}{15}\\)
\nExplanation :
\n\\(\\frac{2}{3}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{10}{15}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{8}{15}\\)<\/p>\n
Question 39.
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{2}{15}\\) =
\nAnswer:
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{4}{15}\\)
\nExplanation :
\n\\(\\frac{2}{5}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{6}{15}\\) \u2013 \\(\\frac{2}{15}\\) = \\(\\frac{4}{15}\\)<\/p>\n
Question 40.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) = \u00a0\\(\\frac{5}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{4}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{4}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n
Question 41.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{7}{16}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{7}{16}\\) = \\(\\frac{5}{16}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{12}{16}\\) \u2013 \\(\\frac{7}{16}\\) = \\(\\frac{5}{16}\\)<\/p>\n
Question 42.
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{4}{15}\\) =
\nAnswer:
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{8}{15}\\)
\nExplanation :
\n\\(\\frac{4}{5}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{12}{15}\\) \u2013 \\(\\frac{4}{15}\\) = \\(\\frac{8}{15}\\)<\/p>\n
Question 43.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \u00a0\\(\\frac{7}{12}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{9}{12}\\) \u2013 \\(\\frac{2}{12}\\) = \\(\\frac{7}{12}\\)<\/p>\n
Question 44.
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) =
\nAnswer:
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{7}{16}\\)
\nExplanation :
\n\\(\\frac{3}{4}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{12}{16}\\) \u2013 \\(\\frac{5}{16}\\) = \\(\\frac{7}{16}\\)<\/p>\n
Question 1.
\nSubtract.
\na. 3\\(\\frac{1}{5}\\) – 2\\(\\frac{1}{4}\\) =
\nb. 4\\(\\frac{2}{5}\\) – 3\\(\\frac{3}{4}\\) =
\nc. 7\\(\\frac{1}{5}\\) – 4\\(\\frac{1}{5}\\) =
\nd. 7\\(\\frac{2}{5}\\) – 5\\(\\frac{2}{3}\\) =
\ne. 4\\(\\frac{2}{7}\\) – 3\\(\\frac{1}{3}\\) =
\nf. 9\\(\\frac{2}{3}\\) – 2\\(\\frac{6}{7}\\) =
\ng. 17\\(\\frac{2}{3}\\) – 5\\(\\frac{5}{6}\\) =
\nh. 18\\(\\frac{1}{3}\\) – 3\\(\\frac{3}{8}\\) =
\nAnswer:
\na. 3\\(\\frac{1}{5}\\) – 2\\(\\frac{1}{4}\\) = \\(\\frac{19}{20}\\)
\nExplanation :
\n3\\(\\frac{1}{5}\\) – 2\\(\\frac{1}{4}\\) = \\(\\frac{16}{5}\\) – \\(\\frac{9}{4}\\)
\nlcm of 5 and 4 is 20 .
\n\\(\\frac{64}{20}\\) – \\(\\frac{45}{20}\\) = \\(\\frac{19}{20}\\)<\/p>\n
b. 4\\(\\frac{2}{5}\\) – 3\\(\\frac{3}{4}\\) = \\(\\frac{13}{20}\\)
\nExplanation :
\n4\\(\\frac{2}{5}\\) – 3\\(\\frac{3}{4}\\) = \\(\\frac{22}{5}\\) – \\(\\frac{15}{4}\\)
\nlcm of 5 and 4 is 20 .
\n\\(\\frac{88}{20}\\) – \\(\\frac{75}{20}\\) = \\(\\frac{13}{20}\\)<\/p>\n
c. 7\\(\\frac{1}{5}\\) – 4\\(\\frac{1}{5}\\) =
\nExplanation :
\n7\\(\\frac{1}{5}\\) – 4\\(\\frac{1}{5}\\) = \\(\\frac{36}{5}\\) – \\(\\frac{21}{5}\\) = \\(\\frac{15}{5}\\) = 3 .<\/p>\n
d. 7\\(\\frac{2}{5}\\) – 5\\(\\frac{2}{3}\\) = 1\\(\\frac{11}{15}\\) .
\nExplanation :
\n7\\(\\frac{2}{5}\\) – 5\\(\\frac{2}{3}\\) = \\(\\frac{37}{5}\\) – \\(\\frac{17}{3}\\)
\nlcm of 5 and 3 is 15 .
\n\\(\\frac{111}{15}\\) – \\(\\frac{85}{15}\\) = \\(\\frac{26}{15}\\) = 1\\(\\frac{11}{15}\\) .<\/p>\n
e. 4\\(\\frac{2}{7}\\) – 3\\(\\frac{1}{3}\\) = \\(\\frac{20}{21}\\)
\nExplanation :
\n4\\(\\frac{2}{7}\\) – 3\\(\\frac{1}{3}\\) = \\(\\frac{30}{7}\\) – \\(\\frac{10}{3}\\)
\nlcm of 7 and 3 is 21.
\n\\(\\frac{90}{21}\\) – \\(\\frac{70}{21}\\) = \\(\\frac{20}{21}\\)<\/p>\n
f. 9\\(\\frac{2}{3}\\) – 2\\(\\frac{6}{7}\\) = 6\\(\\frac{17}{21}\\)
\nExplanation :
\n9\\(\\frac{2}{3}\\) – 2\\(\\frac{6}{7}\\) = \\(\\frac{29}{3}\\) – \\(\\frac{20}{7}\\)
\nlcm of 3 and 7 is 21.
\n\\(\\frac{203}{21}\\) – \\(\\frac{60}{21}\\) = \\(\\frac{143}{21}\\) = 6\\(\\frac{17}{21}\\)<\/p>\n
g. 17\\(\\frac{2}{3}\\) – 5\\(\\frac{5}{6}\\) = 11\\(\\frac{5}{6}\\)
\nExplanation :
\n17\\(\\frac{2}{3}\\) – 5\\(\\frac{5}{6}\\) = \\(\\frac{53}{3}\\) – \\(\\frac{35}{6}\\)
\nlcm of 3 and 6 is 6 .
\n\\(\\frac{106}{6}\\) – \\(\\frac{35}{6}\\) = \\(\\frac{71}{6}\\) = 11\\(\\frac{5}{6}\\)<\/p>\n
h. 18\\(\\frac{1}{3}\\) – 3\\(\\frac{3}{8}\\) = 14\\(\\frac{23}{24}\\)
\nExplanation :
\n18\\(\\frac{1}{3}\\) – 3\\(\\frac{3}{8}\\) = \\(\\frac{55}{3}\\) – \\(\\frac{27}{8}\\)
\nlcm of 3 and 8 is 24 .
\n\\(\\frac{440}{24}\\) – \\(\\frac{81}{24}\\) = \\(\\frac{359}{24}\\) = 14\\(\\frac{23}{24}\\)<\/p>\n
Question 2.
\nToby wrote the following:
\n7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = 4\\(\\frac{2}{4}\\) = 4\\(\\frac{1}{2}\\)
\nIs Toby\u2019s calculation correct? Draw a number line to support your answer.
\nAnswer:
\nTody’s calculation is wrong .
\n7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = 3\\(\\frac{1}{2}\\) .
\nExplanation :
\n7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = \\(\\frac{29}{4}\\) – \\(\\frac{15}{4}\\) = \\(\\frac{14}{4}\\) = \\(\\frac{7}{2}\\) = 3\\(\\frac{1}{2}\\) .
\n![\"Engage-NY-Eureka-Math-5th-Grade-Module-3-Lesson-12-Answer-Key-Eureka-Math-Grade-5-Module-3-Lesson-12-Problem-Set-Answer-Key-Question-2\"](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Engage-NY-Eureka-Math-5th-Grade-Module-3-Lesson-12-Answer-Key-Eureka-Math-Grade-5-Module-3-Lesson-12-Problem-Set-Answer-Key-Question-2.jpg\")
<\/p>\n
Question 3.
\nMr. Neville Iceguy mixed up 12\\(\\frac{3}{5}\\) gallons of chili for a party. If 7\\(\\frac{3}{4}\\)gallons of chili was mild, and the rest was extra spicy, how much extra spicy chili did Mr. Iceguy make?
\nAnswer:
\nFraction of chili mixed up for a party = 12\\(\\frac{3}{5}\\) gallons = \\(\\frac{63}{5}\\) gallons
\nFraction of chilli is mild = 7\\(\\frac{3}{4}\\)gallons = \\(\\frac{31}{4}\\)gallons
\nFraction of chilli is extra spicy = x
\n\\(\\frac{63}{5}\\) =\u00a0 \\(\\frac{31}{4}\\) + x
\nx = \\(\\frac{63}{5}\\) – \\(\\frac{31}{4}\\)
\nlcm of 5 and 4 is 20 .
\nx = \\(\\frac{252}{20}\\) – \\(\\frac{155}{20}\\) = \\(\\frac{97}{20}\\) = 4\\(\\frac{17}{20}\\)
\nTherefore, Fraction of chilli is extra spicy = x = 4\\(\\frac{17}{20}\\) gallons .<\/p>\n
Question 4.
\nJazmyne decided to spend 6\\(\\frac{1}{2}\\) hours studying over the weekend. She spent 1\\(\\frac{1}{4}\\) hours studying on Friday evening and 2\\(\\frac{2}{3}\\) hours on Saturday. How much longer does she need to spend studying on Sunday in order to reach her goal?
\nAnswer:
\nTotal Fraction of time should spend on Studying = 6\\(\\frac{1}{2}\\) hours = \\(\\frac{13}{2}\\) hours
\nFraction of Time spent on Friday for studying = 1\\(\\frac{1}{4}\\) hours = \\(\\frac{5}{4}\\) hours
\nFraction of Time spent on Saturday for studying = 2\\(\\frac{2}{3}\\) hours = \\(\\frac{8}{3}\\) hours
\nFraction of Time should spend on Sunday for studying = x
\n\\(\\frac{13}{2}\\) = \\(\\frac{5}{4}\\) + \\(\\frac{8}{3}\\) + x
\nlcm of 2 , 4 , and 3 is 12 .
\nx = \\(\\frac{13}{2}\\) – \\(\\frac{5}{4}\\) – \\(\\frac{8}{3}\\)
\nx = \\(\\frac{78}{12}\\) – \\(\\frac{15}{12}\\) – \\(\\frac{32}{12}\\)
\nx = \\(\\frac{78}{12}\\) – \\(\\frac{47}{12}\\)
\nx = \\(\\frac{31}{12}\\)
\nx = 2\\(\\frac{7}{12}\\)
\nTherefore, Fraction of Time should spend on Sunday for studying = x = 2\\(\\frac{7}{12}\\) hours .<\/p>\n
Subtract.
\nQuestion 1.
\n5\\(\\frac{1}{2}\\) – 1\\(\\frac{1}{3}\\) =
\nAnswer:
\n5\\(\\frac{1}{2}\\) – 1\\(\\frac{1}{3}\\) = 4\\(\\frac{1}{6}\\) .
\nExplanation :
\n5\\(\\frac{1}{2}\\) – 1\\(\\frac{1}{3}\\) = \\(\\frac{11}{2}\\) – \\(\\frac{4}{3}\\)
\nlcm of 2 and 3 is 6
\n\\(\\frac{33}{6}\\) – \\(\\frac{8}{6}\\) = \\(\\frac{25}{6}\\) = 4\\(\\frac{1}{6}\\) .<\/p>\n
Question 2.
\n8\\(\\frac{3}{4}\\) – 5\\(\\frac{5}{6}\\) =
\nAnswer:
\n8\\(\\frac{3}{4}\\) – 5\\(\\frac{5}{6}\\) = 2\\(\\frac{11}{12}\\)
\nExplanation :
\n8\\(\\frac{3}{4}\\) – 5\\(\\frac{5}{6}\\) = \\(\\frac{35}{4}\\) – \\(\\frac{35}{6}\\)
\nlcm of 4 and 6 is 12 .
\n\\(\\frac{105}{12}\\) – \\(\\frac{70}{12}\\) = \\(\\frac{35}{12}\\) = 2\\(\\frac{11}{12}\\)<\/p>\n
Question 1.
\nSubtract.
\na. 3\\(\\frac{1}{4}\\) – 2\\(\\frac{1}{3}\\) =
\nb. 3\\(\\frac{2}{3}\\) – 2\\(\\frac{3}{4}\\) =
\nc. 6\\(\\frac{1}{5}\\) – 4\\(\\frac{1}{4}\\) =
\nd. 6\\(\\frac{3}{5}\\) – 4\\(\\frac{3}{4}\\) =
\ne. 5\\(\\frac{2}{7}\\) – 4\\(\\frac{1}{3}\\) =
\nf. 8\\(\\frac{2}{3}\\) – 3\\(\\frac{5}{7}\\) =
\ng. 18\\(\\frac{3}{4}\\) – 5\\(\\frac{7}{8}\\) =
\nh. 17\\(\\frac{1}{5}\\) – 2\\(\\frac{5}{8}\\) =
\nAnswer:
\na. 3\\(\\frac{1}{4}\\) – 2\\(\\frac{1}{3}\\) = \\(\\frac{11}{12}\\)
\nExplanation :
\n3\\(\\frac{1}{4}\\) – 2\\(\\frac{1}{3}\\) = \\(\\frac{13}{4}\\) – \\(\\frac{7}{3}\\)
\nlcm of 4 and 3 is 12
\n\\(\\frac{39}{12}\\) – \\(\\frac{28}{12}\\) = \\(\\frac{11}{12}\\)<\/p>\n
b. 3\\(\\frac{2}{3}\\) – 2\\(\\frac{3}{4}\\) = \\(\\frac{11}{12}\\)
\nExplanation :
\n3\\(\\frac{2}{3}\\) – 2\\(\\frac{3}{4}\\) = \\(\\frac{11}{3}\\) – \\(\\frac{11}{4}\\)
\nlcm of 3 and 4 is 12
\n\\(\\frac{44}{12}\\) – \\(\\frac{33}{12}\\) = \\(\\frac{11}{12}\\)<\/p>\n
c. 6\\(\\frac{1}{5}\\) – 4\\(\\frac{1}{4}\\) = 3\\(\\frac{13}{20}\\)
\nExplanation :
\n6\\(\\frac{1}{5}\\) – 4\\(\\frac{1}{4}\\) = \\(\\frac{31}{5}\\) – \\(\\frac{17}{4}\\)
\nlcm of 4 and 5 is 20 .
\n\\(\\frac{124}{20}\\) – \\(\\frac{51}{20}\\) = \\(\\frac{73}{20}\\) = 3\\(\\frac{13}{20}\\) .<\/p>\n
d. 6\\(\\frac{3}{5}\\) – 4\\(\\frac{3}{4}\\) = 1\\(\\frac{17}{20}\\)
\nExplanation :
\n6\\(\\frac{3}{5}\\) – 4\\(\\frac{3}{4}\\) = \\(\\frac{33}{5}\\) – \\(\\frac{19}{4}\\)
\nlcm of 4 and 5 is 20 .
\n\\(\\frac{132}{20}\\) – \\(\\frac{95}{20}\\) = \\(\\frac{37}{20}\\) = 1\\(\\frac{17}{20}\\)<\/p>\n
e. 5\\(\\frac{2}{7}\\) – 4\\(\\frac{1}{3}\\) = \\(\\frac{20}{21}\\)
\nExplanation :
\n5\\(\\frac{2}{7}\\) – 4\\(\\frac{1}{3}\\) = \\(\\frac{37}{7}\\) – \\(\\frac{13}{3}\\)
\nlcm of 3 and 7 is 21.
\n\\(\\frac{111}{21}\\) – \\(\\frac{91}{21}\\) = \\(\\frac{20}{21}\\)<\/p>\n
f. 8\\(\\frac{2}{3}\\) – 3\\(\\frac{5}{7}\\) = 4\\(\\frac{20}{21}\\)
\nExplanation :
\n8\\(\\frac{2}{3}\\) – 3\\(\\frac{5}{7}\\) = \\(\\frac{26}{3}\\) – \\(\\frac{26}{7}\\)
\nlcm of 3 and 7 is 21.
\n\\(\\frac{182}{21}\\) – \\(\\frac{78}{21}\\) = \\(\\frac{104}{21}\\) = 4\\(\\frac{20}{21}\\)<\/p>\n
g. 18\\(\\frac{3}{4}\\) – 5\\(\\frac{7}{8}\\) = 11\\(\\frac{9}{8}\\)
\nExplanation :
\n18\\(\\frac{3}{4}\\) – 5\\(\\frac{7}{8}\\) = \\(\\frac{75}{4}\\) – \\(\\frac{47}{8}\\)
\nlcm of 4 and 8 is 8 .
\n\\(\\frac{130}{8}\\) – \\(\\frac{47}{8}\\) = \\(\\frac{97}{8}\\) = 11\\(\\frac{9}{8}\\)<\/p>\n
h. 17\\(\\frac{1}{5}\\) – 2\\(\\frac{5}{8}\\) = 14\\(\\frac{23}{40}\\)
\nExplanation :
\n17\\(\\frac{1}{5}\\) – 2\\(\\frac{5}{8}\\) = \\(\\frac{86}{5}\\) – \\(\\frac{21}{8}\\)
\nlcm of 5 and 8 is 40 .
\n\\(\\frac{688}{40}\\) – \\(\\frac{105}{40}\\) = \\(\\frac{583}{40}\\) = 14\\(\\frac{23}{40}\\)<\/p>\n
Question 2.
\nTony wrote the following:
\n7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = 4\\(\\frac{1}{4}\\) – \\(\\frac{3}{4}\\)
\nIs Tony\u2019s statement correct? Draw a number line to support your answer.
\nAnswer:
\nYes Tony’s statement is correct .
\n7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = 4\\(\\frac{1}{4}\\) – \\(\\frac{3}{4}\\) = 3\\(\\frac{1}{2}\\) .
\nExplanation :
\n7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = \\(\\frac{29}{4}\\) – \\(\\frac{15}{4}\\) = \\(\\frac{14}{4}\\) = \\(\\frac{7}{2}\\) = 3\\(\\frac{1}{2}\\) .
\n4\\(\\frac{1}{4}\\) – \\(\\frac{3}{4}\\) = \\(\\frac{17}{4}\\) – \\(\\frac{3}{4}\\) = \\(\\frac{14}{4}\\) = \\(\\frac{7}{2}\\) = 3\\(\\frac{1}{2}\\) .
\nTherefore , 7\\(\\frac{1}{4}\\) – 3\\(\\frac{3}{4}\\) = 4\\(\\frac{1}{4}\\) – \\(\\frac{3}{4}\\) = 3\\(\\frac{1}{2}\\) .
\n![\"Engage-NY-Eureka-Math-5th-Grade-Module-3-Lesson-12-Answer-Key-Eureka-Math-Grade-5-Module-3-Lesson-12-Homework-Answer-Key-Question-2\"](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Engage-NY-Eureka-Math-5th-Grade-Module-3-Lesson-12-Answer-Key-Eureka-Math-Grade-5-Module-3-Lesson-12-Homework-Answer-Key-Question-2.jpg\")
<\/p>\n
Question 3.
\nMs. Sanger blended 8\\(\\frac{3}{4}\\) gallons of iced tea with some lemonade for a picnic. If there were 13\\(\\frac{2}{5}\\) gallons of the beverage, how many gallons of lemonade did she use?
\nAnswer:
\nFraction of gallons of iced tea with some lemonade for a picnic = 8\\(\\frac{3}{4}\\) = \\(\\frac{35}{4}\\) gallons .
\nFraction of gallons of the beverage = 13\\(\\frac{2}{5}\\) = \\(\\frac{67}{5}\\) .
\nFraction of gallons of the lemonade = x
\n\\(\\frac{67}{5}\\) = \\(\\frac{35}{4}\\) – x
\nx = \u00a0\\(\\frac{67}{5}\\) – \\(\\frac{35}{4}\\)
\nlcm of 4 and 5 is 20 .
\nx = \\(\\frac{268}{20}\\) – \\(\\frac{175}{20}\\)
\nx = \\(\\frac{93}{20}\\) = 4\\(\\frac{13}{20}\\)
\nTherefore, Fraction of gallons of the lemonade = x = 4\\(\\frac{13}{20}\\) gallons .<\/p>\n
Question 4.
\nA carpenter has 10\\(\\frac{1}{2}\\) feet of wooden plank. He cuts off 4\\(\\frac{1}{4}\\) feet to replace the slat of a deck and 3\\(\\frac{2}{3}\\) feet to repair a bannister. He uses the rest of the plank to fix a stair. How many feet of wood does the carpenter use to fix the stair?
\nAnswer:
\nTotal Fraction of wooden plank = 10\\(\\frac{1}{2}\\) feet = \\(\\frac{21}{2}\\) feet
\nFraction of wooden plank cut off = 4\\(\\frac{1}{4}\\) feet = \\(\\frac{17}{4}\\) feet
\nFraction of wooden plank used to repair a bannister = 3\\(\\frac{2}{3}\\) feet = \\(\\frac{11}{3}\\) feet
\nFraction of wooden plank used for stair = x feet
\n10\\(\\frac{1}{2}\\) = \\(\\frac{17}{4}\\) + \\(\\frac{11}{3}\\) + x
\n\\(\\frac{21}{2}\\) = \\(\\frac{17}{4}\\) + \\(\\frac{11}{3}\\) + x
\nlcm of 2 , 4 and 3 is 12 .
\n\\(\\frac{126}{12}\\) = \\(\\frac{51}{4}\\) + \\(\\frac{44}{3}\\) + x
\nx = \\(\\frac{126}{12}\\) – \\(\\frac{95}{4}\\)
\nx = \\(\\frac{31}{4}\\) = 7\\(\\frac{3}{4}\\) .
\nTherefore, Fraction of wooden plank used for stair = 7\\(\\frac{3}{4}\\) feet .<\/p>\n","protected":false},"excerpt":{"rendered":"
Engage NY Eureka Math 5th Grade Module 3 Lesson 12 Answer Key Eureka Math Grade 5 Module 3 Lesson 12 Sprint Answer Key A Subtract Fractions with Unlike Units Question 1. \u2013 = Answer: \u2013 = Question 2. \u2013 = Answer: \u2013 = Explanation : \u2013 = \u2013 = Question 3. \u2013 = Answer: \u2013 … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/64312"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=64312"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/64312\/revisions"}],"predecessor-version":[{"id":135948,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/64312\/revisions\/135948"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=64312"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=64312"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=64312"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}