{"id":70066,"date":"2022-05-12T16:27:03","date_gmt":"2022-05-12T10:57:03","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=70066"},"modified":"2022-05-10T14:23:27","modified_gmt":"2022-05-10T08:53:27","slug":"eureka-math-grade-2-module-6-lesson-12","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-2-module-6-lesson-12\/","title":{"rendered":"Eureka Math Grade 2 Module 6 Lesson 12 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 2nd Grade Module 6 Lesson 12 Answer Key<\/h2>\n

Eureka Math Grade 2 Module 6 Lesson 12 Core Fluency Practice Set A Answer Key<\/h3>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-12-Core-Fluency-Practice-Set-A-Answer-Key-1\"<\/p>\n

Question 1.
\n10 + 2 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together. So the <\/span>sum of 10 and 2 is 12.<\/span><\/p>\n

Question 2.
\n10 + 7 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together. So the <\/span>sum of 10 and 7 is 17.<\/span><\/p>\n

Question 3.
\n10 + 5 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 10 and 5 is 15.<\/span><\/p>\n

Question 4.
\n4 + 10 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 10 and 5 is 15.<\/span><\/p>\n

Question 5.
\n6 + 11 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 11 is 17.<\/span><\/p>\n

Question 6.
\n12 + 2 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 11 is 17.<\/span><\/p>\n

Question 7.
\n14 + 3 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 14 and 3 is 17.<\/span><\/p>\n

Question 8.
\n13 + 5 =
\nAnswer:
\n18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 13 and 5 is 18.<\/span><\/p>\n

Question 9.
\n17 + 2 =
\nAnswer:
\n19<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 17 and 2 is 19.<\/span><\/p>\n

Question 10.
\n12 + 6 =
\nAnswer:
\n18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 12 and 6 is 18.<\/span><\/p>\n

Question 11.
\n11 + 9 =
\nAnswer:
\n20<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 11 and 9 is 20.<\/span><\/p>\n

Question 12.
\n2 + 16 =
\nAnswer:
\n18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 2 and 16 is 18.<\/span><\/p>\n

Question 13.
\n15 + 4 =
\nAnswer:
\n19<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 15 and 4 is 19.<\/span><\/p>\n

Question 14.
\n5 + 9 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 9 is 14.<\/span><\/p>\n

Question 15.
\n9 + 2 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 2 is 11.<\/span><\/p>\n

Question 16.
\n4 + 9 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 4 and 9 is 13.<\/span><\/p>\n

Question 17.
\n9 + 6 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 6 is 16.<\/span><\/p>\n

Question 18.
\n8 + 9 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 9 is 17.<\/span><\/p>\n

Question 19.
\n7 + 8 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 8 is 15.<\/span><\/p>\n

Question 20.
\n8 + 8 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 8 is 8.<\/span><\/p>\n

Question 21.
\n7 + 9 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 9 is 16.<\/span><\/p>\n

Question 22.
\n5 + 8 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 8 is 13.<\/span><\/p>\n

Question 23.
\n3 + 9 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 3 and 9 is 12.<\/span><\/p>\n

Question 24.
\n8 + 6 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 6 is 14.<\/span><\/p>\n

Question 25.
\n7 + 4 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 4 is 11.<\/span><\/p>\n

Question 26.
\n9 + 5 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 5 is 14.<\/span><\/p>\n

Question 27.
\n6 + 6 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 6 is 12.<\/span><\/p>\n

Question 28.
\n8 + 3 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 3 is 11.<\/span><\/p>\n

Question 29.
\n7 + 6 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 6 is 13.<\/span><\/p>\n

Question 30.
\n6 + 9 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 9 is 15.<\/span><\/p>\n

Question 31.
\n8 + 7 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 7 is 15.<\/span><\/p>\n

Question 32.
\n9 + 9 =
\nAnswer:
\n18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 9 is 18.<\/span><\/p>\n

Question 33.
\n5 + 7 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 7 is 12.<\/span><\/p>\n

Question 34.
\n8 + 4 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 4 is 12.<\/span><\/p>\n

Question 35.
\n6 + 5 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 5 is 11.<\/span><\/p>\n

Question 36.
\n9 + 7 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 7 is 16.<\/span><\/p>\n

Question 37.
\n6 + 8 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 8 is 14.<\/span><\/p>\n

Question 38.
\n2 + 9 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 2 and 9 is 11.<\/span><\/p>\n

Question 39.
\n9 + 8 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 8 is 17.<\/span><\/p>\n

Question 40.
\n7 + 7 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 7 is 14.<\/span><\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Core Fluency Practice Set B Answer Key<\/h3>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-12-Core-Fluency-Practice-Set-B-Answer-Key-2\"<\/p>\n

Question 1.
\n10 + 6 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 10 and 6 is 16.<\/span><\/p>\n

Question 2.
\n10 + 9 =
\nAnswer:
\n19<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 10 and 9 is 19.<\/span><\/p>\n

Question 3.
\n7 + 10 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 10 is 17.<\/span><\/p>\n

Question 4.
\n3 + 10 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 3 and 10 is 13.<\/span><\/p>\n

Question 5.
\n5 + 11 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 11 is 16.<\/span><\/p>\n

Question 6.
\n12 + 8 =
\nAnswer:
\n20<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 12 and 8 is 20.<\/span><\/p>\n

Question 7.
\n14 + 3 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 14 and 3 is 17.<\/span><\/p>\n

Question 8.
\n13 + ____ = 19
\nAnswer:
\n13 + x = 19
\nx = 19 -13
\nx = 6<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 13 to the right side. Now subtract 19 from 13 to get the resultant answer. Hence by doing so we could value of x i.e. 19 – 13 = 6<\/span><\/p>\n

Question 9.
\n15 + ____ = 18
\nAnswer:
\n15 + x = 18
\nx = 18 – 15
\nx = 3<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 18 to the right side. Now subtract 18 from 15 to get the resultant answer. Hence by doing so we could value of x i.e. 18 – 15 = 3<\/span><\/p>\n

Question 10.
\n12 + 5 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 12 and 5 is 17.<\/span><\/p>\n

Question 11.
\n____ = 2 + 17
\nAnswer:
\nx = 2 + 17
\nx = 19<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 2 and 17 is 19.<\/span><\/p>\n

Question 12.
\n____ = 3 + 13
\nAnswer:
\nx = 3 + 13
\nx = 16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 3 and 13 is 16.<\/span><\/p>\n

Question 13.
\n____ = 16 + 2
\nAnswer:
\nx = 16 + 2
\nx = 18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 16 and 2 is 18.<\/span><\/p>\n

Question 14.
\n9 + 3 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 3 is 12.<\/span><\/p>\n

Question 15.
\n6 + 9 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 9 is 15.<\/span><\/p>\n

Question 16.
\n____ + 5 = 14
\nAnswer:
\nx + 5 = 14
\nx = 14 – 5
\nx = 9<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 14 to the right side. Now subtract 14 from 5 to get the resultant answer. Hence by doing so we could value of x i.e 14 – 5 = 9<\/span><\/p>\n

Question 17.
\n____ + 7 = 13
\nAnswer:
\nx + 7 = 13
\nx = 13 – 7
\nx = 6<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 7 to the right side. Now subtract 13 from 7 to get the resultant answer. Hence by doing so we could value of x i.e. 13 – 7 = 6<\/span><\/p>\n

Question 18.
\n____ + 8 = 12
\nAnswer:
\nx + 8 = 12
\nx = 12 – 8
\nx = 4<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 8 to the right side. Now subtract 12 from 8 to get the resultant answer. Hence by doing so we could value of x i.e. 12 – 8 = 4<\/span><\/p>\n

Question 19.
\n8 + 7 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 7 is 15.<\/span><\/p>\n

Question 20.
\n7 + 6 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 6 is 13.<\/span><\/p>\n

Question 21.
\n3 + 8 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 3 and 8 is 11.<\/span><\/p>\n

Question 22.
\n9 + 4 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 4 is 13.<\/span><\/p>\n

Question 23.
\n____ + 6 = 11
\nAnswer:
\nx + 6 = 11
\nx = 11 – 6
\nx = 5<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 6 to the right side. Now subtract 11 from 6 to get the resultant answer. Hence by doing so we could value of x i.e. 11 – 6 = 4<\/span><\/p>\n

Question 24.
\n____ + 9 = 13
\nAnswer:
\nx = 13 -9
\nx = 4<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 8 to the right side. Now subtract 13 from 9 to get the resultant answer. Hence by doing so we could value of x i.e. 13 – 9 = 4<\/span><\/p>\n

Question 25.
\n8 + ____ = 14
\nAnswer:
\n8 + x = 14
\nx = 14 – 8
\nx = 6<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 8 to the right side. Now subtract 14 from 8 to get the resultant answer. Hence by doing so we could value of x i.e. 14 – 8 = 6<\/span><\/p>\n

Question 26.
\n7 + ____ = 15
\nAnswer:
\n7 + x = 15
\nx = 15 -7
\nx = 8<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 7 to the right side. Now subtract 15 from 7 to get the resultant answer. Hence by doing so we could value of x i.e. 15 – 7 = 8<\/span><\/p>\n

Question 27.
\n____ = 4 + 8
\nAnswer:
\nx = 4 + 8
\nx = 12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 4 and 8 is 12.<\/span><\/p>\n

Question 28.
\n____ = 8 + 9
\nAnswer:
\nx = 8 + 9
\nx = 17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 9 is 17.<\/span><\/p>\n

Question 29.
\n____ = 6 + 4
\nAnswer:
\nx = 6 + 4
\nx = 10<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 4 is 10.<\/span><\/p>\n

Question 30.
\n3 + 9 =
\nAnswer:
\n3 + 9 =12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 3 and 9 is 12.<\/span><\/p>\n

Question 31.
\n5 + 7 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 7 is 12.<\/span><\/p>\n

Question 32.
\n8 + ____ =14
\nAnswer:
\n8 + x\u00a0 = 14<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 8 to the right side. Now subtract 14 from 7 to get the resultant answer. Hence by doing so we could value of x i.e. 14 – 7 = 6<\/span><\/p>\n

Question 33.
\n____ = 5 + 9
\nAnswer:
\nx = 5 + 9
\nx = 14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 9 is 14.<\/span><\/p>\n

Question 34.
\n8 + 8 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 8 is 16.<\/span><\/p>\n

Question 35.
\n____ = 7 + 9
\nAnswer:
\nx = 16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 9 is 16.<\/span><\/p>\n

Question 36.
\n____ = 8 + 4
\nAnswer:
\nx = 12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 4 is 12.<\/span><\/p>\n

Question 37.
\n17 = 8 + ____
\nAnswer:
\n17 = 8 + x
\n17- 8 = x
\nx = 9<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 8 to the left side. Now subtract 17 from 8 to get the resultant answer. Hence by doing so we could value of x i.e. 17 – 8 = 9<\/span><\/p>\n

Question 38.
\n19 = ____ + 9
\nAnswer:
\n19 = x + 9
\nx = 19 – 9
\nx = 10<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 9 to the left side. Now subtract 19 from 9 to get the resultant answer. Hence by doing so we could value of x i.e. 19 – 9 = 10<\/span><\/p>\n

Question 39.
\n12 = ____ + 7
\nAnswer:
\n12 = x + 7
\n12 – 7 = x
\nx = 5<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring variable 7 to the right side. Now subtract 12 from 7 to get the resultant answer. Hence by doing so we could value of x i.e. 12 – 7 = 5<\/span><\/p>\n

Question 40.
\n15 = 8 + ____
\nAnswer:
\n15 – 8 = x
\nx = 7<\/p>\n

Explanation:
\nFirst, assume x as a variable and then bring the variable 8 to the right side. Now subtract 15 from 8 to get the resultant answer. Hence by doing so we could value of x i.e. 15 – 8 = 7<\/span><\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Core Fluency Practice Set C Answer Key<\/h3>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-12-Core-Fluency-Practice-Set-C-Answer-Key-3\"<\/p>\n

Question 1.
\n13 – 3 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 3 = 6. Hence the answer is 16.<\/p>\n

Question 2.
\n19 – 9 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 19 \u2013 9. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/p>\n

Question 3.
\n15 – 10 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 10. Now we need to subtract the one\u2019s digit i.e.\u00a0 15 \u2013 10 = 5. Hence the answer is 5.<\/p>\n

Question 4.
\n18 – 10 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 10. Now we need to subtract the one\u2019s digit i.e.\u00a0 10 +8 \u2013 10 = 8. Hence the answer is 8.<\/p>\n

Question 5.
\n12 – 2 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 2. Now we need to subtract the one\u2019s digit i.e
\n<\/span>12 – 2 = 10. Hence the answer is 10.<\/span><\/p>\n

Question 6.
\n11 – 10 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 10. Now we need to subtract the one\u2019s digit i.e
\n<\/span>11 – 10 = 1. Hence the answer is 1.<\/span><\/p>\n

Question 7.
\n17 – 13 =
\nAnswer:
\n4<\/p>\n

Explanation:<\/p>\n

To solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 13. Now we need to subtract the one\u2019s digit i.e
\n<\/span>17 – 13 = 4. Hence the answer is 4.<\/span><\/p>\n

Question 8.
\n20 – 10 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/p>\n

Question 9.
\n14 – 11 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 11. Now we need to subtract the one\u2019s digit i.e
\n4 – 1 = 3. Hence the answer is 3.<\/p>\n

Question 10.
\n16 – 12 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 12. Now we need to subtract the one\u2019s digit. Hence the answer is 4.<\/p>\n

Question 11.
\n11 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 3. Now we need to subtract the one\u2019s digit. Hence the answer is 4.<\/p>\n

Question 12.
\n13 – 2 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 2. Now we need to subtract the one\u2019s digit.\u00a0 Hence the answer is 11.<\/p>\n

Question 13.
\n14 – 2 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 2. Now we need to subtract the one\u2019s digit. Hence the answer is 2.<\/p>\n

Question 14.
\n13 – 4 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 4. Now we need to subtract the one\u2019s digit.\u00a0 Hence the answer is 9.<\/p>\n

Question 15.
\n12 – 3 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 3 = 9. Hence the answer is 9.<\/p>\n

Question 16.
\n11 – 4 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 1 = 9. Hence the answer is 9.<\/p>\n

Question 17.
\n12 – 5 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 5 = 7. Hence the answer is 7.<\/p>\n

Question 18.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 5 = 9. Hence the answer is 9.<\/p>\n

Question 19.
\n11 – 2 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 2. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 2 = 9. Hence the answer is 9.<\/p>\n

Question 20.
\n12 – 4 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 \u2013 1. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 4 = 8. Hence the answer is 8.<\/p>\n

Question 21.
\n16 – 8 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 \u2013 1. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 1 = 9. Hence the answer is 9.<\/p>\n

Question 22.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 5 = 9. Hence the answer is 9.<\/p>\n

Question 23.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 7 = 9. Hence the answer is 9.<\/p>\n

Question 24.
\n15 – 7 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 7 = 8. Hence the answer is 8.<\/p>\n

Question 25.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 8 = 9. Hence the answer is 9.<\/p>\n

Question 26.
\n18 – 9 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 9 = 9. Hence the answer is 9.<\/p>\n

Question 27.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 6 = 9. Hence the answer is 9.<\/p>\n

Question 28.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 8 = 5. Hence the answer is 5.<\/p>\n

Question 29.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 6 = 8. Hence the answer is 8.<\/p>\n

Question 30.
\n12 – 5 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 5 = 7. Hence the answer is 7.<\/p>\n

Question 31.
\n11 – 7 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 7 = 4. Hence the answer is 4.<\/p>\n

Question 32.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 8 = 5. Hence the answer is 5.<\/p>\n

Question 33.
\n16 – 9 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 9 = 7. Hence the answer is 7.<\/p>\n

Question 34.
\n12 – 8 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 35.
\n16 – 12 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 12. Now we need to subtract the one\u2019s digit. Hence the answer is 4.<\/p>\n

Question 36.
\n18 – 15 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 15. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 5 = 3. Hence the answer is 3.<\/p>\n

Question 37.
\n15 – 14 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 14. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 4 = 1. Hence the answer is 1.<\/p>\n

Question 38.
\n17 – 11 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 11. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 1 = 6. Hence the answer is 6.<\/p>\n

Question 39.
\n19 – 13 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 19 \u2013 13. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 9 \u2013 13 = 6. Hence the answer is 6.<\/p>\n

Question 40.
\n20 – 12 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 12. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 2 = 8. Hence the answer is 8.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Core Fluency Practice Set D Answer Key<\/h3>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-12-Core-Fluency-Practice-Set-D-Answer-Key-17\"<\/p>\n

Question 1.
\n17 – 7 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 7. Now we need to subtract the one\u2019s digit. Next, bring down the 1 from ten’s digit. Hence the answer is 10.<\/p>\n

Question 2.
\n14 – 10 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 11.<\/p>\n

Question 3.
\n19 – 11 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 2. Now we need to subtract the one\u2019s digit.\u00a0 Hence the answer is 11.<\/p>\n

Question 4.
\n16 – 10 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 6.<\/p>\n

Question 5.
\n17 – 12 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 12. Now we need to subtract the one\u2019s digit. Hence the answer is 5.<\/p>\n

Question 6.
\n15 – 13 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 13. Now we need to subtract the one\u2019s digit. Hence the answer is 2.<\/p>\n

Question 7.
\n12 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 \u2013 1. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 – 3 = 8. Hence the answer is 8.<\/p>\n

Question 8.
\n20 – 11 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 \u2013 1. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 1 = 9. Hence the answer is 9.<\/p>\n

Question 9.
\n18 – 11 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 11. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 1 = 9. Hence the answer is 9.<\/p>\n

Question 10.
\n13 – 5 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 5 = 8. Hence the answer is 8.<\/p>\n

Question 11.
\n____ = 11 – 2
\nAnswer:
\nx = 8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 2. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 2 = 8. Hence the answer is 8.<\/p>\n

Question 12.
\n____ = 12 – 4
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 \u2013 1. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 1 = 9. Hence the answer is 9.<\/p>\n

Question 13.
\n____ = 13 – 5
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 5 = 8. Hence the answer is 8.<\/p>\n

Question 14.
\n____ = 12 – 3
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you
\n10 + 2 \u2013 3 = 9. Hence the answer is 9.<\/p>\n

Question 15.
\n____ = 11 – 4
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 \u2013 1. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 4 = 7. Hence the answer is 7.<\/p>\n

Question 16.
\n____ = 13 – 2
\nAnswer:
\n11<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 2. Now we need to subtract the one\u2019s digit. The answer we get is 1. Now bring down 1 from ten’s digit place. Hence the answer is 11.<\/p>\n

Question 17.
\n____ = 11 – 3
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 3 = 8. Hence the answer is 9.<\/p>\n

Question 18.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 8 = 9. Hence the answer is 9.<\/p>\n

Question 19.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 6 = 8. Hence the answer is 8.<\/p>\n

Question 20.
\n16 – 9 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 9 = 7. Hence the answer is 7.<\/p>\n

Question 21.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 7 = 9. Hence the answer is 9.<\/p>\n

Question 22.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 8 = 9. Hence the answer is 9.<\/p>\n

Question 23.
\n18 – 7 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 7 = 1. Hence the answer is 11.<\/p>\n

Question 24.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 6 = 8. Hence the answer is 8.<\/p>\n

Question 25.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 8 = 9. Hence the answer is 9.<\/p>\n

Question 26.
\n12 – 8 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 27.
\n14 – 7 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 7 = 7. Hence the answer is 7.<\/p>\n

Question 28.
\n15 – 8 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 8 = 7. Hence the answer is 7.<\/p>\n

Question 29.
\n13 – 5 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 5 = 8. Hence the answer is 8.<\/p>\n

Question 30.
\n16 – 8 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 8 = 8. Hence the answer is 8.<\/p>\n

Question 31.
\n14 – 9 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 9 = 5. Hence the answer is 5.<\/p>\n

Question 32.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 6 = 9. Hence the answer is 9.<\/p>\n

Question 33.
\n13 – 6 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 6 = 7. Hence the answer is 7.<\/p>\n

Question 34.
\n____ = 13 – 8
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 8 = 5. Hence the answer is 5.<\/p>\n

Question 35.
\n____ = 15 – 7
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 7 = 8. Hence the answer is 8.<\/p>\n

Question 36.
\n____ = 18 – 9
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 9 = 9. Hence the answer is 9.<\/p>\n

Question 37.
\n____ = 20 – 14
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 14. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 4 = 6. Hence the answer is 6.<\/p>\n

Question 38.
\n____ = 20 – 7
\nAnswer:
\n13<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 7 = 3. Hence the answer is 13.<\/p>\n

Question 39.
\n____ = 20 – 11
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 11. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 1 = 9. Hence the answer is 9.<\/p>\n

Question 40.
\n____ = 20 – 8
\nAnswer:
\n12<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 8 = 2. Hence the answer is 12.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Core Fluency Practice Set E Answer Key<\/h3>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-12-Core-Fluency-Practice-Set-E-Answer-Key-5\"<\/p>\n

Question 1.
\n11 + 9 =
\nAnswer:
\n20<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 11 and 9 is 20.<\/span><\/p>\n

Question 2.
\n13 + 5 =
\nAnswer:
\n18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 13 and 5 is 18.<\/span><\/p>\n

Question 3.
\n14 + 3 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 14 and 3 is 17.<\/span><\/p>\n

Question 4.
\n12 + 7 =
\nAnswer:
\n19<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 12 and 7 is 19.<\/span><\/p>\n

Question 5.
\n5 + 9 =
\nAnswer:
\n14<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 9 is 14.<\/span><\/p>\n

Question 6.
\n8 + 8 =
\nAnswer:
\n16<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 8 is 16.<\/span><\/p>\n

Question 7.
\n14 – 7 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 7 = 7. Hence the answer is 7.<\/p>\n

Question 8.
\n13 – 5 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 5 = 8. Hence the answer is 8.<\/p>\n

Question 9.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 7 = 9. Hence the answer is 9.<\/p>\n

Question 10.
\n17 – 9 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 9 = 8. Hence the answer is 8.<\/p>\n

Question 11.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 6 = 8. Hence the answer is 8.<\/p>\n

Question 12.
\n18 – 5 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 5 = 3. Hence the answer is 13.<\/p>\n

Question 13.
\n9 + 9 =
\nAnswer:
\n18<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 9 and 9 is 18.<\/span><\/p>\n

Question 14.
\n7 + 6 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 6 is 13.<\/span><\/p>\n

Question 15.
\n3 + 9 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 3 and 9 is 12.<\/span><\/p>\n

Question 16.
\n6 + 7 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 6 and 7 is 13.<\/span><\/p>\n

Question 17.
\n8 + 5 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 5 is 13.<\/span><\/p>\n

Question 18.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 8 = 5. Hence the answer is 15.<\/p>\n

Question 19.
\n16 – 9 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 9 = 7. Hence the answer is 7.<\/p>\n

Question 20.
\n14 – 8 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 8 = 6. Hence the answer is 6.<\/p>\n

Question 21.
\n13 – 7 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 7 = 6. Hence the answer is 6.<\/p>\n

Question 22.
\n11 – 8 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 8 = 3. Hence the answer is 3.<\/p>\n

Question 23.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 6 = 9. Hence the answer is 9.<\/p>\n

Question 24.
\n12 + 7 =
\nAnswer:
\n19<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 12 and 7 is 19.<\/span><\/p>\n

Question 25.
\n14 + 3 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 14 and 3 is 17.<\/span><\/p>\n

Question 26.
\n8 + 12 =
\nAnswer:
\n20<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 12 is 20.<\/span><\/p>\n

Question 27.
\n5 + 7 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 5 and 7 is 12.<\/span><\/p>\n

Question 28.
\n8 + 9 =
\nAnswer:
\n17<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 9 is 17.<\/span><\/p>\n

Question 29.
\n7 + 5 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 5 is 12.<\/span><\/p>\n

Question 30.
\n13 – 6 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 6 = 7. Hence the answer is 7.<\/p>\n

Question 31.
\n14 – 8 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 8 = 6. Hence the answer is 6.<\/p>\n

Question 32.
\n12 – 9 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 9 = 3. Hence the answer is 3.<\/p>\n

Question 33.
\n11 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 3 = 8. Hence the answer is 8.<\/p>\n

Question 34.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 5 = 9. Hence the answer is 9.<\/p>\n

Question 35.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 8 = 5. Hence the answer is 5.<\/p>\n

Question 36.
\n8 + 5 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 8 and 5 is 13.<\/span><\/p>\n

Question 37.
\n4 + 7 =
\nAnswer:
\n11<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 4 and 7 is 11.<\/span><\/p>\n

Question 38.
\n7 + 8 =
\nAnswer:
\n15<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 7 and 8 is 15.<\/span><\/p>\n

Question 39.
\n4 + 9 =
\nAnswer:
\n13<\/p>\n

Explanation:
\nAdd both the numbers together to get the resultant sum. So the <\/span>sum of 4 and 9 is 13.<\/span><\/p>\n

Question 40.
\n20 – 8 =
\nAnswer:
\n12<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 \u2013 8 = 2. Now bring down the 1 from ten’s place. Hence the answer is 12.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Problem Set Answer Key<\/h3>\n

Question 1.
\nDraw without using a square tile to make an array with 2 rows of 5.
\n2 rows of 5 = ______<\/p>\n

____ + ____ = ____
\nAnswer:
\n2 rows of 5 are 10
\n5 + 5 =10
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Problem-Set-Answer-Key-6\"<\/p>\n

Explanation:
\nI have drawn an object without using a square tile to make an array with 2 rows of 5<\/p>\n

Question 2.
\nDraw without using a square tile to make an array with 4 columns of 3.
\n4 columns of 3 = ______<\/p>\n

____ + ____ + ____ + ____ = _____
\nAnswer:
\n4 columns of 3 is 12
\n3 + 3 + 3 + 3 = 12
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Problem-Set-Answer-Key-7\"<\/p>\n

Explanation:
\nI have drawn an object without using a square tile to make an array with 4 columns of 3.<\/p>\n

Question 3.
\nComplete the following arrays without gaps or overlaps. The first tile has been drawn for you.<\/p>\n

a. 3 rows of 4
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Problem-Set-Answer-Key-8\"<\/p>\n

Explanation:
\nI have drawn an object without gaps or overlaps and made an array with 3 rows of 4.<\/p>\n

b. 5 columns of 3
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Problem-Set-Answer-Key-9\"<\/p>\n

Explanation:
\nI have drawn an object without gaps or overlaps and made an array with 5 columns of 3.<\/p>\n

c. 5 columns of 4
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Problem-Set-Answer-Key-10\"<\/p>\n

Explanation:
\nI have drawn an object without gaps or overlaps and made an array with 5 columns of 4.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Exit Ticket Answer Key<\/h3>\n

Question 1.
\nDraw an array of 3 columns of 3 starting with the square below without gaps or overlaps.
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Exit-Ticket-Answer-Key-11\"<\/p>\n

Explanation:
\nI have drawn an array of 3 columns of 3 starting with the square given above.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 12 Homework Answer Key<\/h3>\n

Question 1.
\nCut out and trace the square tile to draw an array with 2 rows of 4.
\n\"Eureka
\n2 rows of 4 = ______<\/p>\n

____ + ____ = ____
\nAnswer:
\n2 rows of 4 are 8
\n4 + 4 = 8
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Exit-Ticket-Answer-Key-12\"<\/p>\n

Explanation:
\nAs asked in the question I have drawn an array with 2 rows of 4.<\/p>\n

Question 2.
\nTrace the square tile to make an array with 3 columns of 5.
\n3 columns of 5 = ______<\/p>\n

____ + ____ + ____ = _____
\nAnswer:
\n3 columns of 5 are 15.
\n5 + 5 + 5 = 15
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Exit-Ticket-Answer-Key-13\"<\/p>\n

Explanation:
\nAs asked in the question I have drawn an array with 3 columns of 5.<\/p>\n

Question 3.
\nComplete the following arrays without gaps or overlaps. The first tile has been drawn for you.<\/p>\n

a. 4 rows of 5
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Homework-Answer-Key-14\"<\/p>\n

Explanation:
\nI have drawn an object without gaps or overlaps and made an array with 4 rows of 5.<\/p>\n

b. 5 columns of 2
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Homework-Answer-Key-15\"<\/p>\n

Explanation:
\nI have drawn an object without gaps or overlaps and made an array with 5 columns of 2.<\/p>\n

c. 4 columns of 3
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-12-Homework-Answer-Key-16\"<\/p>\n

Explanation:
\nI have drawn an object without gaps or overlaps and made an array with 4 columns of 3.<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 2nd Grade Module 6 Lesson 12 Answer Key Eureka Math Grade 2 Module 6 Lesson 12 Core Fluency Practice Set A Answer Key Question 1. 10 + 2 = Answer: 12 Explanation: Add both the numbers together. So the sum of 10 and 2 is 12. Question 2. 10 + 7 … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"quote","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70066"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=70066"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70066\/revisions"}],"predecessor-version":[{"id":136044,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70066\/revisions\/136044"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=70066"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=70066"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=70066"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}