{"id":70168,"date":"2022-05-12T16:27:16","date_gmt":"2022-05-12T10:57:16","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=70168"},"modified":"2022-05-10T14:23:27","modified_gmt":"2022-05-10T08:53:27","slug":"eureka-math-grade-2-module-6-lesson-14","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-2-module-6-lesson-14\/","title":{"rendered":"Eureka Math Grade 2 Module 6 Lesson 14 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 2nd Grade Module 6 Lesson 14 Answer Key<\/h2>\n

Eureka Math Grade 2 Module 6 Lesson 14 Sprint Answer Key<\/h3>\n

A. Subtraction from Teens.<\/p>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-14-Sprint-Answer-Key-1\"<\/p>\n

Question 1.
\n11 – 10 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 10. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 0 = 1. Hence the answer is 1.<\/p>\n

Question 2.
\n12 – 10 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 10. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 0 = 2. Hence the answer is 2.<\/p>\n

Question 3.
\n13 – 10 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 10. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 0 = 3. Hence the answer is 3.<\/p>\n

Question 4.
\n19 – 10 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 19 \u2013 10. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 – 9 = 1. Hence the answer is 9.<\/p>\n

Question 5.
\n11 – 1 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 1. Now we need to subtract the one\u2019s digit. Hence the answer is 1.<\/p>\n

Question 6.
\n12 – 2 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 2. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 7.
\n13 – 3 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 3. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 8.
\n17 – 7 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 7. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 9.
\n11 – 2 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 2. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 2 = 9. Hence the answer is 9.<\/p>\n

Question 10.
\n11 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 3 = 8. Hence the answer is 8.<\/p>\n

Question 11.
\n11 – 4 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 4 = 7. Hence the answer is 7.<\/p>\n

Question 12.
\n11 – 8 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 8 = 3. Hence the answer is 3.<\/p>\n

Question 13.
\n18 – 8 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 8. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 14.
\n13 – 4 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 4 = 9. Hence the answer is 9.<\/p>\n

Question 15.
\n13 – 5 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 5 = 8. Hence the answer is 2.<\/p>\n

Question 16.
\n13 – 6 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 6 = 7. Hence the answer is 7.<\/p>\n

Question 17.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 8 = 5. Hence the answer is 5.<\/p>\n

Question 18.
\n16 – 6 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 6. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 19.
\n12 – 3 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 3 = 9. Hence the answer is 9.<\/p>\n

Question 20.
\n12 – 4 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 4 = 8. Hence the answer is 8.<\/p>\n

Question 21.
\n12 – 5 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 5 = 7. Hence the answer is 7.<\/p>\n

Question 22.
\n12 – 9 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 9 = 3. Hence the answer is 3.<\/p>\n

Question 23.
\n19 – 9 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 19 \u2013 9. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 24.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 6 = 9. Hence the answer is 9.<\/p>\n

Question 25.
\n15 – 7 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 7 = 8. Hence the answer is 8.<\/p>\n

Question 26.
\n15 – 9 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 9 = 6. Hence the answer is 6.<\/p>\n

Question 27.
\n20 – 10 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 28.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 5 = 9. Hence the answer is 9.<\/p>\n

Question 29.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 6 = 8. Hence the answer is 8.<\/p>\n

Question 30.
\n14 – 7 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 7 = 7. Hence the answer is 7.<\/p>\n

Question 31.
\n14 – 9 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 4 \u2013 9 = 5. Hence the answer is 5.<\/p>\n

Question 32.
\n15 – 5 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 5. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 33.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 8 = 9. Hence the answer is 9.<\/p>\n

Question 34.
\n17 – 9 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 7 \u2013 9 = 8. Hence the answer is 8.<\/p>\n

Question 35.
\n18 – 8 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 8. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 36.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 7 = 9. Hence the answer is 9.<\/p>\n

Question 37.
\n16 – 8 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 8 = 8. Hence the answer is 8.<\/p>\n

Question 38.
\n16 – 9 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 9. Now we need to subtract the one\u2019s digit. Hence the answer is 7.<\/span><\/p>\n

Question 39.
\n17 – 10 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 7.<\/span><\/p>\n

Question 40.
\n12 – 8 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 41.
\n18 – 9 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 9 = 9. Hence the answer is 9.<\/p>\n

Question 42.
\n11 – 9 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 2 = 2. Hence the answer is 2.<\/p>\n

Question 43.
\n15 – 8 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 8 = 7. Hence the answer is 7yyyy.<\/p>\n

Question 44.
\n13 – 7 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 7 = 6. Hence the answer is 6.<\/p>\n

B.
\nSubtraction from Teens.<\/p>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-14-Sprint-Answer-Key-2\"<\/p>\n

Question 1.
\n11 – 1 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 1. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 2.
\n12 – 2 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 2. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 3.
\n13 – 3 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 3. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 4.
\n18 – 8 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 8. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 5.
\n11 – 10 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 1.<\/span><\/p>\n

Question 6.
\n12 – 10 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 2.<\/span><\/p>\n

Question 7.
\n13 – 10 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 3.<\/span><\/p>\n

Question 8.
\n18 – 10 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 8.<\/span><\/p>\n

Question 9.
\n11 – 2 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 2. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 2 = 6. Hence the answer is 9.<\/p>\n

Question 10.
\n11 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 – 3= 8. Hence the answer is 8.<\/p>\n

Question 11.
\n11 – 4 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 4 = 7. Hence the answer is 7.<\/p>\n

Question 12.
\n11 – 7 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 7 = 4. Hence the answer is 4.<\/p>\n

Question 13.
\n19 – 9 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 19 \u2013 9. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 14.
\n12 – 3 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 3. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 3 = 9. Hence the answer is 9.<\/p>\n

Question 15.
\n12 – 4 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 4 = 8. Hence the answer is 8.<\/p>\n

Question 16.
\n12 – 5 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 5 = 7. Hence the answer is 7.<\/p>\n

Question 17.
\n12 – 8 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 18.
\n17 – 7 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 \u2013 7. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 19.
\n13 – 4 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 4. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 4 = 9. Hence the answer is 9.<\/p>\n

Question 20.
\n13 – 5 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 5. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 5 = 8. Hence the answer is 8.<\/p>\n

Question 21.
\n13 – 6 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 6 = 7. Hence the answer is 7.<\/p>\n

Question 22.
\n13 – 9 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 9 = 5. Hence the answer is 5.<\/p>\n

Question 23.
\n16 – 6 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 6. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 24.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 25.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 26.
\n14 – 7 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 27.
\n14 – 9 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 28.
\n20 – 10 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 29.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 6. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 6 = 9. Hence the answer is 9.<\/p>\n

Question 30.
\n15 – 7 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 7 = 8. Hence the answer is 8.<\/p>\n

Question 31.
\n15 – 9 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 9 = 6. Hence the answer is 6.<\/p>\n

Question 32.
\n14 – 4 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 \u2013 4. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 33.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 7 = 9. Hence the answer is 9.<\/p>\n

Question 34.
\n16 – 8 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 6 \u2013 8 = 8. Hence the answer is 8.<\/p>\n

Question 35.
\n16 – 9 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 36.
\n20 – 10 =
\nAnswer:
\n10<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 20 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 37.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 38.
\n17 – 9 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 8 = 4. Hence the answer is 4.<\/p>\n

Question 39.
\n16 – 10 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 \u2013 10. Now we need to subtract the one\u2019s digit. Hence the answer is 10.<\/span><\/p>\n

Question 40.
\n18 – 9 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 8 \u2013 9 = 9. Hence the answer is 9.<\/p>\n

Question 41.
\n12 – 9 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 \u2013 9. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 2 \u2013 9 = 3. Hence the answer is 3.<\/p>\n

Question 42.
\n13 – 7 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 \u2013 7. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 3 \u2013 7 = 6. Hence the answer is 6.<\/p>\n

Question 43.
\n11 – 8 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 1 \u2013 8 = 2. Hence the answer is 2.<\/p>\n

Question 44.
\n15 – 8 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 \u2013 8. Now we need to subtract the one\u2019s digit. In this case, the subtrahend one\u2019s digit is larger than the minuend one\u2019s digit. Therefore, we need to \u201cborrow\u201d 10 from the minuend ten\u2019s digit which gives you 10 + 5 \u2013 8 = 7. Hence the answer is 7.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 14 Problem Set Answer Key<\/h3>\n

Cut out Rectangles A, B, and C. Then, cut according to directions. Answer each of the following using Rectangles A, B, and C.<\/p>\n

Question 1.
\nCut out each row of Rectangle A.1<\/p>\n

a. Rectangle A has _____ rows.
\nAnswer:
\nRectangle A has 2 rows.<\/p>\n

Explanation:
\nAs given in the question I had cut out each row of rectangle A. So rectangle A has 2 rows.<\/p>\n

b. Each row has ______ squares.
\nAnswer:
\nEach row has 4 squares<\/p>\n

Explanation:
\nAs given in the question I had cut out each row of rectangle A. So each row has 4 squares.<\/p>\n

c. _____ rows of _____ = _____
\nAnswer:
\n2 rows of 4 = 8<\/p>\n

Explanation:
\nAfter cutting out each row of rectangle A we have 2 rows of 4 that is 8 boxes.<\/p>\n

d. Rectangle A has ______ squares.
\nAnswer:
\nRectangle A has 8 squares.<\/p>\n

Explanation:
\nAs given in the question I had cut out each row of rectangle A. So the rectangle A has 8 squares.<\/p>\n

Question 2.
\nCut out each column of Rectangle B.<\/p>\n

a. Rectangle B has _____ columns.
\nAnswer:
\nRectangle A has 2 rows.<\/p>\n

Explanation:
\nAs given in the question I had cut out each row of rectangle A. So rectangle A has 2 rows.<\/p>\n

b. Each column has ______ squares.
\nAnswer:
\nEach column has 2 squares.<\/p>\n

Explanation:
\nIn the given question each column has 2 squares.<\/p>\n

c. _____ columns of _____ = _____
\nAnswer:
\n4 columns of 2 = 8<\/p>\n

Explanation:
\nAfter cutting out each row of the rectangle B we have 4 columns of 2 that are 8.<\/p>\n

d. Rectangle B has ______ squares.
\nAnswer:
\nRectangle B has 8 sqaures.<\/p>\n

Explanation:
\nIn this question, rectangle B has 8 squares.<\/p>\n

Question 3.
\nCut out each square from both Rectangles A and B.<\/p>\n

a. Construct a new rectangle using all 16 squares.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-9\"<\/p>\n

Explanation:
\nAs asked in the question I have constructed a new rectangle using all 16 squares.<\/p>\n

b. My rectangle has ______ rows of ______.
\nAnswer:
\nMy rectangle has 2 rows of 8<\/p>\n

Explanation:
\nIn this, my rectangle has 2 rows of 8.<\/p>\n

c. My rectangle also has _____ columns of ______.
\nAnswer:
\nMy rectangle also has 8 columns of 2.<\/p>\n

Explanation:
\nIn this, my rectangle has 8 columns of 2.<\/p>\n

d. Write two repeated addition number sentences to match your rectangle.
\nAnswer:
\n2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 16
\n8 + 8 = 16<\/p>\n

Explanation:
\nThe two repeated addition number sentences to match your rectangle is\u00a0 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 16. Another one is 8 + 8 = 16<\/p>\n

Question 4.
\nConstruct a new array using the 24 squares from Rectangles A, B, and C.<\/p>\n

a. My rectangle has ______ rows of ______.
\nAnswer:
\nMy rectangle has 4 rows of 6.<\/p>\n

Explanation:
\nI have constructed a new array using the 24 squares from my rectangle has 4 rows of 6.<\/p>\n

b. My rectangle also has _____ columns of ______.
\nAnswer:
\nMy rectangle also has 6 columns of 4.<\/p>\n

Explanation:
\nIn this, my rectangle also has 6 columns of 4.<\/span><\/p>\n

c. Write two repeated addition number sentences to match your rectangle.
\nAnswer:
\n4 + 4 + 4 + 4 + 4 + 4 = 24
\n6 + 6 + 6 + 6 = 24<\/p>\n

Explanation:
\nI have written two repeated addition number sentences to match your rectangle is 4 + 4 + 4 + 4 + 4 + 4 = 24. Another addition number sentence is 6 + 6 + 6 + 6 =24.<\/p>\n

Extension:
\nConstruct another array using the squares from Rectangles A, B, and C.<\/p>\n

a. My rectangle has ______ rows of ______.
\nAnswer:
\nMy rectangle has 3 rows of 8.<\/p>\n

Explanation:
\nI have constructed another array using the squares from the rectangle that has 3 rows of 8.<\/p>\n

b. My rectangle also has _____ columns of ______.
\nAnswer:
\nMy rectangle also has 8 columns of 3<\/p>\n

Explanation:
\nIn this question, my rectangle also has 8 columns of 3.<\/p>\n

c. Write two repeated addition number sentences to match your rectangle.
\nAnswer:
\n8 + 8 + 8 =24
\n3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 =24<\/p>\n

Explanation:
\nThe two repeated addition number sentences to match the rectangle is 8 + 8 + 8 =24. Another addition number sentence is 3 +3 + 3 + 3 + 3 + 3 + 3 + 3 +3 = 24<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 14 Exit Ticket Answer Key<\/h3>\n

Question 1.
\nWith your tiles, show 1 rectangle with 12 squares. Complete the sentences below.<\/p>\n

I see _____ rows of ____.
\nAnswer:
\nI see 2 rows of 6<\/p>\n

Explanation:
\nWith your tiles, I see 2 rows of 6.<\/p>\n

In the exact same rectangle, I see _____ columns of _____.
\nAnswer:
\nIn the exact same rectangle, I see 6 columns of 2.<\/p>\n

Explanation:
\nI have seen 6 columns of 2 in the exact same rectangle.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 14 Homework Answer Key<\/h3>\n

Question 1.
\nImagine that you have just cut this rectangle into rows.
\n\"Eureka<\/p>\n

a. What do you see? Draw a picture.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-3\"<\/p>\n

How many squares are in each row?
\nAnswer:
\nThere are 4 squares in each row.<\/p>\n

Explanation:
\nBy observing the picture we can tell that there are 4 squares in each row.<\/p>\n

b. Imagine that you have just cut this rectangle into columns. What do you see? Draw a picture.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-4\"<\/p>\n

How many squares are in each column?
\nAnswer:
\n3<\/p>\n

Explanation:
\nBy observing the picture we can tell that there are 3 squares in each column.<\/p>\n

Question 2.
\nCreate another rectangle using the same number of squares.<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-5\"<\/p>\n

How many squares are in each row?
\nAnswer:
\n6<\/p>\n

Explanation:
\nThere are 6 squares in each row.<\/p>\n

How many squares are in each column?
\nAnswer:
\n2<\/p>\n

Explanation:
\nThere are 2 squares in each column.<\/p>\n

Question 3.
\nImagine that you have just cut this rectangle into rows.
\n\"Eureka<\/p>\n

a. What do you see? Draw a picture.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-6\"<\/p>\n

How many squares are in each row?
\nAnswer:
\n5<\/p>\n

Explanation:
\nI have drawn a picture of cutting the rectangle into 2 rows. And there are 5 squares in each row.<\/p>\n

b. Imagine that you have just cut this rectangle into columns. What do you see? Draw a picture.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-7\"<\/p>\n

How many squares are in each column? _______
\nAnswer:
\n4<\/p>\n

Explanation:
\nQuestion 4.
\nCreate another rectangle using the same number of squares.<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-14-Homework-Answer-Key-8\"<\/p>\n

How many squares are in each row?
\nAnswer:
\n10<\/p>\n

Explanation:
\nThere are 10 squares in each row.<\/p>\n

How many squares are in each column?
\nAnswer:
\n2<\/p>\n

Explanation:
\nThere are 2 squares in each column.<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 2nd Grade Module 6 Lesson 14 Answer Key Eureka Math Grade 2 Module 6 Lesson 14 Sprint Answer Key A. Subtraction from Teens. Question 1. 11 – 10 = Answer: 1 Explanation: To solve the problem we must put the largest number on top and the smallest number at the bottom … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70168"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=70168"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70168\/revisions"}],"predecessor-version":[{"id":136042,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70168\/revisions\/136042"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=70168"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=70168"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=70168"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}