{"id":70362,"date":"2022-05-12T16:27:47","date_gmt":"2022-05-12T10:57:47","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=70362"},"modified":"2022-05-10T14:23:26","modified_gmt":"2022-05-10T08:53:26","slug":"eureka-math-grade-2-module-6-lesson-18","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-2-module-6-lesson-18\/","title":{"rendered":"Eureka Math Grade 2 Module 6 Lesson 18 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 2nd Grade Module 6 Lesson 18 Answer Key<\/h2>\n

Eureka Math Grade 2 Module 6 Lesson 18 Sprint Answer Key<\/h3>\n

A. Subtraction from Teens<\/p>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-18-Sprint-Answer-Key-1\"
\nQuestion 1.
\n10 – 3 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 3 = 7. Hence the answer is 7.<\/p>\n

Question 2.
\n11 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 3 = 8. Hence the answer is 8.<\/p>\n

Question 3.
\n12 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 +2 – 3 = 8. Hence the answer is 8.<\/p>\n

Question 4.
\n10 – 2 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 2 = 8. Hence the answer is 8.<\/p>\n

Question 5.
\n11 – 2 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 7 = 9. Hence the answer is 9.<\/p>\n

Question 6.
\n10 – 5 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 5 = 5. Hence the answer is 5.<\/p>\n

Question 7.
\n11 – 5 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 11 + 1 – 5 =6 . Hence the answer is 6.<\/p>\n

Question 8.
\n12 – 5 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 5 = 7. Hence the answer is 7.<\/p>\n

Question 9.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 5 = 9. Hence the answer is 9.<\/p>\n

Question 10.
\n10 – 4 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 4 = 6. Hence the answer is 6.<\/p>\n

Question 11.
\n11 – 4 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 +1 – 4 = 7. Hence the answer is 7.<\/p>\n

Question 12.
\n12 – 4 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 4 = 8. Hence the answer is 8.<\/p>\n

Question 13.
\n13 – 4 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 4 = 9. Hence the answer is 9.<\/p>\n

Question 14.
\n10 – 7 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 7 = 3. Hence the answer is 3.<\/p>\n

Question 15.
\n11 – 7 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 7 = 4. Hence the answer is 4.<\/p>\n

Question 16.
\n12 – 7 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 7 = 5. Hence the answer is 5.<\/p>\n

Question 17.
\n15 – 7 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 7 = 8. Hence the answer is 8.<\/p>\n

Question 18.
\n10 – 6 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 6 = 4. Hence the answer is 4.<\/p>\n

Question 19.
\n11 – 6 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 6 = 5. Hence the answer is 5.<\/p>\n

Question 20.
\n12 – 6 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 6 = 6. Hence the answer is 6.<\/p>\n

Question 21.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 6 = 8. Hence the answer is 8.<\/p>\n

Question 22.
\n10 – 9 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 9 = 1. Hence the answer is 1.<\/p>\n

Question 23.
\n11 – 9 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 9 = 2. Hence the answer is 2.<\/p>\n

Question 24.
\n12 – 9 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 9 = 3. Hence the answer is 3.<\/p>\n

Question 25.
\n17 – 9 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 7 – 9 = 8. Hence the answer is 8.<\/p>\n

Question 26.
\n10 – 8 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 8 = 2. Hence the answer is 2.<\/p>\n

Question 27.
\n11 – 8 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 8 = 3. Hence the answer is 3.<\/p>\n

Question 28.
\n12 – 8 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.<\/p>\n

Question 29.
\n16 – 8 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 8 = 8. Hence the answer is 8.<\/p>\n

Question 30.
\n10 – 6 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 6 = 4. Hence the answer is 4.<\/p>\n

Question 31.
\n13 – 6 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 6 = 7. Hence the answer is 7.<\/p>\n

Question 32.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 6 = 9. Hence the answer is 9.<\/p>\n

Question 33.
\n10 – 7 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 7 = 3. Hence the answer is 3.<\/p>\n

Question 34.
\n13 – 7 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 7 = 6. Hence the answer is 6.<\/p>\n

Question 35.
\n14 – 7 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 7 = 7. Hence the answer is 7.<\/p>\n

Question 36.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 7 = 9. Hence the answer is 9.<\/p>\n

Question 37.
\n10 – 8 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 9 = 2. Hence the answer is 2.<\/p>\n

Question 38.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 8 = 5. Hence the answer is 5.<\/p>\n

Question 39.
\n14 – 8 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 8 = 6. Hence the answer is 6.<\/p>\n

Question 40.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 7 – 8 = 9. Hence the answer is 9.<\/p>\n

Question 41.
\n10 – 9 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 9 = 1. Hence the answer is 1.<\/p>\n

Question 42.
\n13 – 9 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 9 = 4. Hence the answer is 4.<\/p>\n

Question 43.
\n14 – 9 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 9 = 5. Hence the answer is 5.<\/p>\n

Question 44.
\n18 – 9 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 +8 – 9 = 9. Hence the answer is 9.<\/p>\n

B. Subtraction from Teens<\/p>\n

\"Eureka<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-18-Sprint-Answer-Key-2\"<\/p>\n

Question 1.
\n10 – 2 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit, giving you 10 – 2 = 8. Hence the answer is 8.<\/p>\n

Question 2.
\n11 – 2 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit, giving you 10 + 1 – 2 = 9. Hence the answer is 9.<\/p>\n

Question 3.
\n10 – 4 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 – 4= 6. Hence the answer is 6.<\/p>\n

Question 4.
\n11 – 4 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 1 – 4 = 7. Hence the answer is 7.<\/p>\n

Question 5.
\n12 – 4 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 2 – 4 = 8. Hence the answer is 8.<\/p>\n

Question 6.
\n13 – 4 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 3 – 4 = 9. Hence the answer is 9.<\/p>\n

Question 7.
\n10 – 3 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 – 3= 7. Hence the answer is 7.<\/p>\n

Question 8.
\n11 – 3 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 1 – 3 = 8. Hence the answer is 8.<\/p>\n

Question 9.
\n12 – 3 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 2 – 3 = 9. Hence the answer is 9.<\/p>\n

Question 10.
\n10 – 6 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10- 6 = 4. Hence the answer is 4.<\/p>\n

Question 11.
\n11 – 6 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 1 – 6 = 4. Hence the answer is 4.<\/p>\n

Question 12.
\n12 – 6 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 2 – 6 = 6. Hence the answer is 6.<\/p>\n

Question 13.
\n15 – 6 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 +5 – 6 = 9. Hence the answer is 9.<\/p>\n

Question 14.
\n10 – 5 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 – 5 = 5. Hence the answer is 5.<\/p>\n

Question 15.
\n11 – 5 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 1 – 5 = 6. Hence the answer is 6.<\/p>\n

Question 16.
\n12 – 5 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 2 – 5 = 7. Hence the answer is 7.<\/p>\n

Question 17.
\n14 – 5 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 4 – 5 = 9. Hence the answer is 9.<\/p>\n

Question 18.
\n10 – 8 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 8 = 2. Hence the answer is 2.<\/p>\n

Question 19.
\n11 – 8 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 1 – 8 = 2. Hence the answer is 2.<\/p>\n

Question 20.
\n12 – 8 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 2 – 8 = 4. Hence the answer is 4.<\/p>\n

Question 21.
\n17 – 8 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 7 – 8 = 9. Hence the answer is 9.<\/p>\n

Question 22.
\n10 – 7 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit gives you 10 – 7 = 3. Hence the answer is 3.<\/p>\n

Question 23.
\n11 – 7 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 7 = 4. Hence the answer is 4.<\/p>\n

Question 24.
\n12 – 7 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 7 = 5. Hence the answer is 5.<\/p>\n

Question 25.
\n16 – 7 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 7 = 9. Hence the answer is 9.<\/p>\n

Question 26.
\n10 – 9 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 9 = 1. Hence the answer is 1.<\/p>\n

Question 27.
\n11 – 9 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 9 = 2. Hence the answer is 2.<\/p>\n

Question 28.
\n12 – 9 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 9 = 3. Hence the answer is 3.<\/p>\n

Question 29.
\n18 – 9 =
\nAnswer:
\n9<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 8 – 9 = 9. Hence the answer is 9.<\/p>\n

Question 30.
\n10 – 5 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 5 = 5. Hence the answer is 5.<\/p>\n

Question 31.
\n13 – 5 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 5 = 8. Hence the answer is 8.<\/p>\n

Question 32.
\n10 – 6 =
\nAnswer:
\n4<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 6 = 4. Hence the answer is 4.<\/p>\n

Question 33.
\n13 – 6 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 6 = 7. Hence the answer is 7.<\/p>\n

Question 34.
\n14 – 6 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 6 = 8. Hence the answer is 8.<\/p>\n

Question 35.
\n10 – 7 =
\nAnswer:
\n3<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 7 = 3. Hence the answer is 3.<\/p>\n

Question 36.
\n13 – 7 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 7 = 6. Hence the answer is 6.<\/p>\n

Question 37.
\n15 – 7 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 7 = 8. Hence the answer is 8.<\/p>\n

Question 38.
\n10 – 8 =
\nAnswer:
\n2<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 8 = 2. Hence the answer is 2.<\/p>\n

Question 39.
\n13 – 8 =
\nAnswer:
\n5<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 8 = 5. Hence the answer is 5.<\/p>\n

Question 40.
\n14 – 8 =
\nAnswer:
\n6<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 8 = 6. Hence the answer is 6.<\/p>\n

Question 41.
\n16 – 8 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 15 + 1 – 8 = 8. Hence the answer is 8.<\/p>\n

Question 42.
\n10 – 9 =
\nAnswer:
\n1<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 10 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10- 9 = 1. Next, you subtract the subtrahend tens digit from the new minuend tens digit. 0 – 0 = 0. Hence the answer is 1.<\/p>\n

Question 43.
\n16 – 9 =
\nAnswer:
\n7<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 9 = 7. Next, you subtract the subtrahend tens digit from the new minuend tens digit. 0 – 0 = 0. Hence the answer is 7.<\/p>\n

Question 44.
\n17 – 9 =
\nAnswer:
\n8<\/p>\n

Explanation:
\nTo solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit giving you 10 + 7 – 9 = 8. Hence the answer is 7.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 18 Problem Set Answer Key<\/h3>\n

Question 1.
\nPair the objects to decide if the number of objects is even.
\n\"Eureka\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 Even\/Not Even
\nAnswer:
\nThe number of objects is even.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-3\"<\/p>\n

Explanation:
\nAs asked in the question I have paired the set of objects. By observing the objects we could tell that the number of objects is even.<\/p>\n

\"Eureka\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 Even\/Not Even
\nAnswer:
\nThe number of objects is not even.<\/p>\n

\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-4\"<\/p>\n

Explanation:
\nAs asked in the question I have paired the set of objects. By observing the objects we could tell that the number of objects is not even.<\/p>\n

\"Eureka\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0 Even\/Not Even
\nAnswer:
\nThe number of objects is even.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-5\"<\/p>\n

Explanation:
\nAs asked in the question I have paired the set of objects. By observing the objects we could tell that the number of objects is even.<\/p>\n

Question 2.
\nDraw to continue the pattern of the pairs in the space below until you have drawn 10 pairs.
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Sprint-Answer-Key-6\"<\/p>\n

Explanation:
\nAs asked in the question I have drawn the pattern of pairs in the space given above. By observing the pairs we have drawn we could tell that the number of objects is even.<\/p>\n

Question 3.
\nWrite the number of dots in each array in Problem 2 in order from least to greatest.
\nAnswer:
\n2 4 6 8 10 12 14 16 18 20<\/p>\n

Explanation:
\nThe number of dots in each array in problem 2 in order from least to greatest is 2 4 6 8 10 12 14 16 18 20<\/p>\n

Question 4.
\nCircle the array in Problem 2 that has 2 columns of 7.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Sprint-Answer-Key-12\"<\/p>\n

Explanation:
\nI have circled the array in problem 2 that has 2 columns of 7.<\/p>\n

Question 5.
\nBox the array in Problem 2 that has 2 columns of 9.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Sprint-Answer-Key-13\"<\/p>\n

Explanation:
\nI have circled the array in problem 2 that has 2 columns of 9.<\/p>\n

Question 6.
\nRedraw the following sets of dots as columns of two or 2 equal rows.<\/p>\n

a. \"Eureka
\nThere are _________ dots.<\/p>\n

Is ____ an even number?
\nAnswer:
\nThere are 10 dots. The number 10 is an even number.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-7\"<\/p>\n

Explanation:
\nI have redrawn the following sets of dots as columns of two. By counting, there are 10 dots and that number is an even number.<\/p>\n

b. \"Eureka
\nThere are _________ dots.<\/p>\n

Is ____ an even number?
\nAnswer:
\nThere are 15 dots. The number 15 is an odd number.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-8\"<\/p>\n

Explanation:
\nI have redrawn the following sets of dots as columns of two. By counting, there are 15 dots and that number is an odd number.<\/p>\n

Question 7.
\nCircle groups of two. Count by twos to see if the number of objects is even.
\n\"Eureka<\/p>\n

a. There are _______ twos. There are ______ left over.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-9\"<\/p>\n

Explanation:
\nI have circled groups of two. And by counting the twos we can identify the number of objects is even.<\/p>\n

b. Count by twos to find the total.
\n_____, _____, _____, _____, _____, ______, _____, _____, ______
\nAnswer:
\n2, 4, 6, 8, 10, 12, 14, 16, 18<\/p>\n

Explanation:
\nThere are 9 twos we have circled as asked in the above question. Hence by counting the number of twos the total is 2, 4, 6, 8, 10, 12, 14, 16, 18<\/p>\n

c. This group has an even number of objects: True or False
\nAnswer:
\nTrue<\/p>\n

Explanation:
\nThe 8 is divisible by 2 as we have 8 two’s circled in the group. Hence this group has an even number of objects.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 18 Exit Ticket Answer Key<\/h3>\n

Redraw the following sets of dots as columns of two or 2 equal rows.<\/p>\n

Question 1.
\n\"Eureka
\nThere are _________ dots.<\/p>\n

Is ____ an even number?
\nAnswer:
\nThe 13 is an odd number.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-10\"<\/p>\n

Explanation:
\nI have redrawn the set of stars as a column of two. In this, we got 13 dots as that 13 is not divisible by 2 we could say that set of stars is an even number.<\/p>\n

Question 2.
\n\"Eureka
\nThere are _________ dots.<\/p>\n

Is ____ an even number?
\nAnswer:
\nThere are 16 dots and the number 16 is an even number.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Problem-Set-Answer-Key-11\"<\/p>\n

Explanation:
\nI have redrawn the set of stars as a column of two. In this, we got 16 dots as 16 is divisible by 2 so we could say that set of stars is an even number.<\/p>\n

Eureka Math Grade 2 Module 6 Lesson 18 Homework Answer Key<\/h3>\n

Question 1.
\nPair the objects to decide if the number of objects is even.<\/p>\n

\"Eureka\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Even\/Not Even
\nAnswer:
\nThe number of objects here is even.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-14\"<\/p>\n

Explanation:
\nI have redrawn the set of objects as a column of two. In this we got 6 objects as that 12 is divisible by 2 we could say that set of stars is an even number.<\/p>\n

\"Eureka\u00a0 \u00a0 Even\/Not Even
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-15\"<\/p>\n

Explanation:
\nI have redrawn the set of stars as a column of two. In this, we got 11 objects as that 11 is not divisible by 2 we could say that set of stars is an odd number.<\/p>\n

\"Eureka\u00a0 \u00a0 \u00a0 \u00a0\u00a0 Even\/Not Even
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-16\"<\/p>\n

Explanation:
\nI have redrawn the set of stars as a column of two. In this we got 12 objects as that 12 is divisible by 2 we could say that set of stars is an even number.<\/p>\n

Question 2.
\nDraw to continue the pattern of the pairs in the spaces below until you have drawn zero pairs.
\n\"Eureka
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-17\"<\/p>\n

Explanation:
\nI have continued to draw the pattern of pairs in the spaces above until we got zero pairs.<\/p>\n

Question 3.
\nWrite the number of hearts in each array in Problem 2 in order from greatest to least.
\nAnswer:
\n18, 16, 14, 12, 10, 8, 6, 4, 2<\/p>\n

Question 4.
\nCircle the array in Problem 2 that has 2 columns of 6.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-18\"<\/p>\n

Explanation:
\nI have circled the array in problem 2 that has 2 columns of 6.<\/p>\n

Question 5.
\nBox the array in Problem 2 that has 2 columns of 8.
\nAnswer:
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-19\"<\/p>\n

Explanation:
\nI have circled the array in problem 2 that has 2 columns of 8.<\/p>\n

Question 6.
\nRedraw the set of stars as columns of two or 2 equal rows.
\n\"Eureka
\nThere are _________ stars.
\nIs ____ an even number?
\nAnswer:
\nThere are 12 stars.
\nAnd 12 is an even number.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-20\"<\/p>\n

Explanation:
\nI have redrawn the set of stars as a column of two. In this we got 12 stars as that 12 is divisible by 2 we could say that set of stars is an even number.<\/p>\n

Question 7.
\nCircle groups of two. Count by twos to see if the number of objects is even.
\n\"Eureka<\/p>\n

a. There are _______ twos. There are ______ left over.
\nAnswer:
\nThere are 8 twos. There are none left over.
\n\"Eureka-Math-Grade-2-Module-6-Lesson-18-Homework-Answer-Key-21\"<\/p>\n

Explanation:
\nBy counting the given group we had known there are 8 twos and there are none left over. Hence the number of objects is even as 8 twos is divisible by 2.<\/p>\n

b. Count by twos to find the total.
\n_____, _____, _____, _____, _____, ______, _____, _____
\nAnswer:
\n2, 4, 6, 8, 10, 12, 14, 16<\/p>\n

Explanation:
\nThere are 8 twos we have circled as asked in the above question. Hence by counting the number of twos the total is 2, 4, 6, 8, 10, 12, 14, 16<\/p>\n

c. This group has an even number of objects: True or False.
\nAnswer:
\nTrue.<\/p>\n

Explanation:
\nThe 8 is divisible by 2 as we have 8 two’s circled in the group. Hence this group has an even number of objects.<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 2nd Grade Module 6 Lesson 18 Answer Key Eureka Math Grade 2 Module 6 Lesson 18 Sprint Answer Key A. Subtraction from Teens Question 1. 10 – 3 = Answer: 7 Explanation: To solve the problem we must put the largest number on top and the smallest number at the bottom … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70362"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=70362"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70362\/revisions"}],"predecessor-version":[{"id":136038,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/70362\/revisions\/136038"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=70362"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=70362"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=70362"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}