{"id":83173,"date":"2022-06-01T16:39:40","date_gmt":"2022-06-01T11:09:40","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=83173"},"modified":"2022-05-10T14:19:41","modified_gmt":"2022-05-10T08:49:41","slug":"eureka-math-grade-8-module-2-end-of-module-assessment","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-grade-8-module-2-end-of-module-assessment\/","title":{"rendered":"Eureka Math Grade 8 Module 2 End of Module Assessment Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 8th Grade Module 2 End of Module Assessment Answer Key<\/h2>\n

Eureka Math Grade 8 Module 2 End of Module Assessment Task Answer Key<\/h3>\n

Question 1.
\n\u25b3ABC\u2245 \u25b3A’B’C’. Use the picture to answer the question below.
\n\"Eureka
\nDescribe a sequence of rigid motions that would prove a congruence between \u25b3ABC and \u25b3A’B’C’.
\nAnswer:
\nLet T be the Translation AWNG \\(\\overrightarrow{A^{\\prime} A}\\) so that t(A’) = A. Let R be the rotation around A, d degrees so that R(A’B’) = AB. By hypothesis |AB| = |A’B’|. Let |\u2220A| = |\u2220A|, |\u2220B| = |\u2220B|, so the composition \u028c.R.T will map \u2206A’B’C’ to \u2206A’B’C’ to \u2206ABC, i.e., \u028c(R(T(\u25b3A’B’C’))) = \u25b3ABC<\/p>\n

Question 2.
\nUse the diagram to answer the question below.<\/p>\n

k || l
\n\"Eureka
\nAnswer:
\n\"Eureka<\/p>\n

Line k is parallel to line l. m\u2220EDC=41\u00b0 and m\u2220ABC=32\u00b0. Find the m\u2220BCD. Explain in detail how you know you are correct. Add additional lines and points as needed for your explanation.
\nAnswer:
\nLet F be a point on line or so that \u2220DCF is a straight angle. Then because r || l, \u2220EDC \u2245 \u2220CFA and have equal measure. \u2220ABC and \u2220CFA are the remote interior angles of \u25b3BCF which means \u2220BCD = \u2220ABC + CFA. Therefore \u2220BCD = 32 + 41 = 73\u00b0.<\/p>\n

Question 3.
\nUse the diagram below to answer the questions that follow. Lines L1<\/sub> and L2<\/sub> are parallel, L1<\/sub> || L2<\/sub>. Point N is the midpoint of segment GH.
\n\"Eureka<\/p>\n

a. If the measure of \u2220IHM is 125\u00b0, what is the measure of \u2220IHJ? \u2220JHN? \u2220NHM?
\nAnswer:
\n\u2220IHJ = 55\u00b0
\n\u2220JHN = 125\u00b0
\n\u2220NHM = 55\u00b0<\/p>\n

b. What can you say about the relationship between \u22204 and \u22206? Explain using a basic rigid motion. Name another pair of angles with this same relationship.
\nAnswer:
\n\u22204 & \u22206 are alternate interior angles that are equal because L1<\/sub> || L2<\/sub>. Let R be a rotation of 180\u00b0 around point N. Then R(N) = N, R(L3<\/sub>) = L3<\/sub> and R(L1<\/sub>) = L2<\/sub>. Rotations are degree preserving so (\u22204) = \u22206
\n\u22203 & \u22205 are also alternate interior angles that are equal.<\/p>\n

c. What can you say about the relationship between \u22201 and \u22205? Explain using a basic rigid motion. Name another pair of angles with this same relationship.
\nAnswer:
\n\u22201 & \u22205 are corresponding angles that are equal because L1<\/sub> || L2<\/sub>. Let T be the Translation along vector \\(\\overrightarrow{G H}\\). Then T(L2<\/sub>) = L1<\/sub> and T(\u22205) = \u22201.
\n\u22203 & \u22207 are also corresponding angles that are equal.<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 8th Grade Module 2 End of Module Assessment Answer Key Eureka Math Grade 8 Module 2 End of Module Assessment Task Answer Key Question 1. \u25b3ABC\u2245 \u25b3A’B’C’. Use the picture to answer the question below. Describe a sequence of rigid motions that would prove a congruence between \u25b3ABC and \u25b3A’B’C’. Answer: … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/83173"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=83173"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/83173\/revisions"}],"predecessor-version":[{"id":137265,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/83173\/revisions\/137265"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=83173"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=83173"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=83173"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}