\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Example-Answer-Key-1.png\")
<\/p>\na. Use the model to answer the following questions.
\n<\/p>\n
How many fives are in the model?
\nAnswer:
\n5<\/p>\n
How many threes are In the model?
\nAnswer:
\n2<\/p>\n
What does the expression represent in words?
\nAnswer:
\nThe sum of two groups of five and two groups of three<\/p>\n
What expression could we write to represent the model?
\nAnswer:
\n2 \u00d7 5 + 2 \u00d7 3<\/p>\n
b. Use the new model and the previous model to answer the next set of questions.<\/p>\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Example-Answer-Key-2.png\")
\nHow many fives are in the model?
\nAnswer:
\n2<\/p>\n
How many threes are in the model?
\nAnswer:
\n2<\/p>\n
What does the expression represent in words?
\nAnswer:
\nTwo groups of the sum of five and three<\/p>\n
What expression could we write to represent the model?
\nAnswer:
\n(5 + 3) + (5 + 3) or 2(5 + 3)<\/p>\n
Is the model in part (a) equivalent to the model in part (b)?
\nAnswer:
\nYes, because both expressions have two 5\u2019s and two 3\u2019s. Therefore, 2 \u00d7 5 + 2 \u00d7 3 = 2(5 + 3).<\/p>\n
d. What relationship do we see happening on either side of the equal sign?
\nAnswer:
\nOn the left-hand side, 2 is being multiplied by 5 and then by 3 before adding the products together. On the right-hand side, the 5 and 3 are added first and then multiplied by 2.<\/p>\n
e. In Grade 5 and in Module 2 of this year, you have used similar reasoning to solve problems. What Is the name of the property that is used to say that 2(5 + 3) is the same as 2 \u00d7 5 + 2 \u00d7 3?
\nAnswer:
\nThe name of the property is the distributive property.<\/p>\n
Example 2.
\nNow we will take a look at an example with variables. Discuss the questions with your partner.
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Example-Answer-Key-3.png\")
<\/p>\n
What does the model represent in words?
\nAnswer:
\na plus a plus b plus b, two a\u2019s plus two b\u2019s, two times a plus two times b<\/p>\n
What does 2a mean?
\nAnswer:
\n2a means that there are 2 a\u2019s or 2 \u00d7 a.<\/p>\n
How many a\u2019s are in the model?
\nAnswer:
\n2<\/p>\n
How many b\u2019s are in the model?
\nAnswer:
\n2<\/p>\n
What expression could we write to represent the model?
\nAnswer:
\n2a + 2b<\/p>\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Example-Answer-Key-4.png\")
<\/p>\n
How many a\u2019s are in the expression?
\nAnswer:
\n2<\/p>\n
How many b\u2019s are in the expression?
\nAnswer:
\n2<\/p>\n
What expression could we write to represent the model?
\nAnswer:
\n(a + b) + (a + b) = 2(a + b)<\/p>\n
Are the two expressions equivalent?
\nAnswer:
\nYes. Both models include 2 a\u2019s and 2 b\u2019s. Therefore, 2a + 2b = 2(a + b).<\/p>\n
Example 3.<\/p>\n
Use GCF and the distributive property to write equivalent expressions.
\n1. 3f + 3g = __________
\nAnswer:
\n3(f + g)<\/p>\n
What is the question asking us to do?
\nAnswer:
\nWe need to rewrite the expression as an equivalent expression in factored form, which means the expression is written as the product of factors. The number outside of the parentheses is the GCF.<\/p>\n
How would Problem 1 look if we expanded each term?
\nAnswer:
\n3 \u2219 f + 3 \u2219 g<\/p>\n
What is the GCF in Problem 1?
\nAnswer:
\n3<\/p>\n
How can we use the GCF to rewrite this expression?
\nAnswer:
\n3 goes on the outside, and f + g will go inside the parentheses. 3(f + g)<\/p>\n
2. 6x + 9y = __________
\nAnswer:
\n3(2x + 3y)<\/p>\n
What is the question asking us to do?
\nAnswer:
\nWe need to rewrite the expression as an equivalent expression in factored form, which means the expression is written as the product of factors. The number outside of the parentheses is the GCF.<\/p>\n
How would Problem 2 look if we expanded each term?
\nAnswer:
\n2 \u2219 3 \u2219 x + 3 \u2219 3 \u2219 y<\/p>\n
What is the GCF in Problem 2?
\nAnswer:
\nThe GCF is 3.<\/p>\n
How can we use the GCF to rewrite this expression?
\nAnswer:
\nI will factor out the 3 from both terms and place it in front of the parentheses. I will place what is left in the terms inside the parentheses: 3(2x + 3y).<\/p>\n
3. 3c + 11c = _________
\nAnswer:
\nc(3 + 11)<\/p>\n
Is there a greatest common factor in Problem 3?
\nAnswer:
\nYes. When I expand, I can see that each term has a common factor c.
\n3 \u2219 c + 11 \u2219 c<\/p>\n
Rewrite the expression using the distributive property.
\nAnswer:
\nc(3 + 11)<\/p>\n
4. 24b + 8 = _________
\nAnswer:
\n8(3b + 1)<\/p>\n
Explain how you used GCF and the distributive property to rewrite the expression in Problem 4.
\nAnswer:
\nI first expanded each term. I know that 8 goes into 24, so I used it in the expansion.
\n2 \u2219 2 \u2219 2 \u2219 3 \u2219 b + 2 \u2219 2 \u2219 2
\nI determined that 2 \u2219 2 \u2219 2, or 8, is the common factor. So, on the outside of the parentheses I wrote 8, and on the inside I wrote the leftover factor, 3b + 1 \u2219 8(3b + 1)<\/p>\n
Why is there a 1 in the parentheses?
\nAnswer:
\nWhen I factor out a number, lam leaving behind the other factor that multiplies to make the original number. In this case, when I factor out an 8 from 8, I am left with a 1 because 8 \u00d7 1 = 8.<\/p>\n
How is this related to the first two examples?
\nAnswer:
\nIn the first two examples, we saw that we could rewrite the expressions by thinking about groups.
\nWe can either think of 24b + 8 as 8 groups of 3b and 8 groups of 1 or as 8 groups of the sum of 3b + 1. This shows that 8(3b) + 8(1) = 8(3b + 1)is the some as 24b + 8.<\/p>\n
Exercise 1.
\nApply the distributive property to write equivalent expressions.
\na. 7x + 7y
\nAnswer:
\n7(x + y)<\/p>\n
b. 15g + 20h
\nAnswer:
\n5(3g + 4h)<\/p>\n
c. 18m + 42n
\nAnswer:
\n6(3m + 7n)<\/p>\n
d. 30a + 39b
\nAnswer:
\n3(10a + 13b)<\/p>\n
e. 11f + 15f
\nAnswer:
\nf(11 + 15)<\/p>\n
f. 18h + 13h
\nAnswer:
\nh(18 + 13)<\/p>\n
g. 55m + 11
\nAnswer:
\n11(5m + 1)<\/p>\n
h. 7 + 56y
\nAnswer:
\n7(1 + 8y)<\/p>\n
2.
\nEvaluate each of the expressions below.
\na. 6x + 21 y and 3(2x + 7y)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0x = 3 and y = 4
\nAnswer:
\n6(3) + 21(4)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a03(23 + 74)
\n18 + 84\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 3(6 + 28)
\n102\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a03(34)
\n102\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0102<\/p>\n
b. 5g + 7g and g(5 + 7)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 g = 6
\nAnswer:
\n5(6) + 7(6)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 6(5 + 7)
\n30 + 42\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a06(12)
\n72\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 72<\/p>\n
c. 14x + 2 and 2(7x + 1)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 x = 10
\nAnswer:
\n14(10) + 2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a02(7.10 + 1)
\n140 + 2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a02(70 + 1)
\n142\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 2(71)
\n142\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 142<\/p>\n
d. Explain any patterns that you notice in the results to parts (a) – c).
\nAnswer:
\nBoth expressions in parts (a) – (c) evaluated to the same number when the indicated value was substituted for the variable. This shows that the two expressions are equivalent for the given values.<\/p>\n
e. What would happen if other values were given for the variables?
\nAnswer:
\nBecause the two expressions in each part are equivalent, they evaluate to the same number, no matter what value is chosen for the variable.<\/p>\n
Closing<\/p>\n
How can use you use your knowledge of GCF and the distributive property to write equivalent expressions?
\nAnswer:
\nWe can use our knowledge of GCF and the distributive property to change expressions from standard form to factored form.<\/p>\n
Find the missing value that makes the two expressions equivalent.
\n4x + 12y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ___(x + 3y)
\n35x + 50y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ___(7x + 10y)
\n18x + 9y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ___(2x + y)
\n32x + 8y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ___(4x + y)
\n100x + 700y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ___(x + 7y)
\nAnswer:
\n4x + 12y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a04 (x + 3y)
\n35x + 50y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a05(7x + 10y)
\n18x + 9y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a09(2x + y)
\n32x + 8y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a08(4x + y)
\n100x + 700y\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0100(x + 7y)<\/p>\n
Explain how you determine the missing number.
\nAnswer:
\nI would expand each term and determine the greatest common factor. The greatest common factor is the number that is placed on the blank line.<\/p>\n
Question 1.
\nUse models to prove that 3(a + b) is equivalent to 3a + 3b.
\nAnswer:
\n![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Problem-Set-Answer-Key-5.png\")
<\/p>\n
Question 2.
\nUse greatest common factor and the distributive property to write equivalent expressions in factored form for the following expressions.
\na. 4d + 12e
\nAnswer:
\n4(d + 3e) or 4(1d + 3e)<\/p>\n
b. 18x + 30y
\nAnswer:
\n6(3x + 5y)<\/p>\n
c. 21a + 28y
\nAnswer:
\n7(3a + 4y)<\/p>\n
d. 24f + 56g
\nAnswer:
\n8(3f + 7g)<\/p>\n
Use greatest common factor and the distributive property to write equivalent expressions in factored form.<\/p>\n
Question 1.
\n2x + 8y
\nAnswer:
\n2(x + 4y)<\/p>\n
Question 2.
\n13ab + 15 ab
\nAnswer:
\nab(13 + 15)<\/p>\n
Question 3.
\n20g + 24h
\nAnswer:
\n4(5g + 6h)<\/p>\n
Greatest Common Factor – Round 1
\nDirections: Determine the greatest common factor of each pair of numbers.<\/p>\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Greatest-Common-Factor-Answer-Key-6.png\")
<\/p>\n
Question 1.
\nGCF of 10 and 50
\nAnswer:
\n10<\/p>\n
Question 2.
\nGCF of 5 and 35
\nAnswer:
\n5<\/p>\n
Question 3.
\nGCF of 3 and 12
\nAnswer:
\n3<\/p>\n
Question 4.
\nGCF of 8 and 20
\nAnswer:
\n4<\/p>\n
Question 5.
\nGCF of 15 and 35
\nAnswer:
\n5<\/p>\n
Question 6.
\nGCF of 10 and 75
\nAnswer:
\n5<\/p>\n
Question 7.
\nGCF of 9 and 30
\nAnswer:
\n3<\/p>\n
Question 8.
\nGCF of 15 and 33
\nAnswer:
\n3<\/p>\n
Question 9.
\nGCF of 12 and 28
\nAnswer:
\n4<\/p>\n
Question 10.
\nGCF of 16 and 40
\nAnswer:
\n8<\/p>\n
Question 11.
\nGCF of 24 and 32
\nAnswer:8
\nQuestion 12.
\nGCF of 35 and 49
\nAnswer:
\n7<\/p>\n
Question 13.
\nGCF of 45 and 60
\nAnswer:
\n15<\/p>\n
Question 14.
\nGCF of 48 and 72
\nAnswer:
\n24<\/p>\n
Question 15.
\nGCF of 50 and 42
\nAnswer:
\n2<\/p>\n
Question 16.
\nGCF of 45 and 72
\nAnswer:
\n9<\/p>\n
Question 17.
\nGCF of 28 and 48
\nAnswer:
\n4<\/p>\n
Question 18.
\nGCF of 44 and 77
\nAnswer:
\n11<\/p>\n
Question 19.
\nGCF of 39 and 66
\nAnswer:
\n3<\/p>\n
Question 20.
\nGCF of 64 and 88
\nAnswer:
\n8<\/p>\n
Question 21.
\nGCF of 42 and 56
\nAnswer:
\n14<\/p>\n
Question 22.
\nGCF of 28 and 42
\nAnswer:
\n14<\/p>\n
Question 23.
\nGCF of 13 and 91
\nAnswer:
\n13<\/p>\n
Question 24.
\nGCF of 16 and 84
\nAnswer:
\n4<\/p>\n
Question 25.
\nGCF of 36 and 99
\nAnswer:
\n9<\/p>\n
Question 26.
\nGCF of 39 and 65
\nAnswer:
\n13<\/p>\n
Question 27.
\nGCF of 27 and 87
\nAnswer:
\n3<\/p>\n
Question 28.
\nGCF of 28 and 70
\nAnswer:
\n14<\/p>\n
Question 29.
\nGCF of 29 and 91
\nAnswer:
\n13<\/p>\n
Question 30.
\nGCF of 34 and 51
\nAnswer:
\n17<\/p>\n
Greatest Common Factor – Round 2
\nDirections: Determine the greatest common factor of each pair of numbers.<\/p>\n
![\"Eureka](\"https:\/\/ccssanswers.com\/wp-content\/uploads\/2021\/04\/Eureka-Math-Grade-6-Module-4-Lesson-11-Greatest-Common-Factor-Answer-Key-7.png\")
<\/p>\n
Question 1.
\nGCF of 20 and 80
\nAnswer:
\n20<\/p>\n
Question 2.
\nGCF of 10 and 70
\nAnswer:
\n10<\/p>\n
Question 3.
\nGCF of 9 and 36
\nAnswer:
\n9<\/p>\n
Question 4.
\nGCF of 12 and 24
\nAnswer:
\n12<\/p>\n
Question 5.
\nGCF of 15 and 45
\nAnswer:
\n15<\/p>\n
Question 6.
\nGCF of 10 and 95
\nAnswer:
\n5<\/p>\n
Question 7.
\nGCF of 9 and 45
\nAnswer:
\n9<\/p>\n
Question 8.
\nGCF of 18 and 33
\nAnswer:
\n3<\/p>\n
Question 9.
\nGCF of 12 and 32
\nAnswer:
\n4<\/p>\n
Question 10.
\nGCF of 16 and 56
\nAnswer:
\n8<\/p>\n
Question 11.
\nGCF of 40 and 7
\nAnswer:
\n8<\/p>\n
Question 12.
\nGCF of 35 and 63
\nAnswer:
\n7<\/p>\n
Question 13.
\nGCF of 30 and 75
\nAnswer:
\n15<\/p>\n
Question 14.
\nGCF of 42 and 72
\nAnswer:
\n6<\/p>\n
Question 15.
\nGCF of 30 and 28
\nAnswer:
\n2<\/p>\n
Question 16.
\nGCF of 33 and 99
\nAnswer:
\n33<\/p>\n
Question 17.
\nGCF of 38 and 76
\nAnswer:
\n38<\/p>\n
Question 18.
\nGCF of 26 and 65
\nAnswer:
\n13<\/p>\n
Question 19.
\nGCF of 39 and 48
\nAnswer:
\n3<\/p>\n
Question 20.
\nGCF of 72 and 88
\nAnswer:
\n8<\/p>\n
Question 21.
\nGCF of 21 and 56
\nAnswer:
\n7<\/p>\n
Question 22.
\nGCF of 28 and 52
\nAnswer:
\n4<\/p>\n
Question 23.
\nGCF of 51 and 68
\nAnswer:
\n17<\/p>\n
Question 24.
\nGCF of 48 and 84
\nAnswer:
\n12<\/p>\n
Question 25.
\nGCF of 21 and 63
\nAnswer:
\n21<\/p>\n
Question 26.
\nGCF of 64 and 80
\nAnswer:
\n16<\/p>\n
Question 27.
\nGCF of 36 and 90
\nAnswer:
\n18<\/p>\n
Question 28.
\nGCF of 28 and 98
\nAnswer:
\n14<\/p>\n
Question 29.
\nGCF of 39 and 91
\nAnswer:
\n13<\/p>\n
Question 30.
\nGCF of 38 and 95
\nAnswer:
\n19<\/p>\n","protected":false},"excerpt":{"rendered":"
Engage NY Eureka Math 6th Grade Module 4 Lesson 11 Answer Key Eureka Math Grade 6 Module 4 Lesson 11 Example Answer Key a. Use the model to answer the following questions. How many fives are in the model? Answer: 5 How many threes are In the model? Answer: 2 What does the expression represent … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/86626"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=86626"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/86626\/revisions"}],"predecessor-version":[{"id":137133,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/86626\/revisions\/137133"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=86626"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=86626"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=86626"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}