{"id":97856,"date":"2022-07-12T16:09:25","date_gmt":"2022-07-12T10:39:25","guid":{"rendered":"https:\/\/ccssanswers.com\/?p=97856"},"modified":"2022-05-10T15:23:52","modified_gmt":"2022-05-10T09:53:52","slug":"eureka-math-algebra-2-module-3-lesson-18","status":"publish","type":"post","link":"https:\/\/ccssanswers.com\/eureka-math-algebra-2-module-3-lesson-18\/","title":{"rendered":"Eureka Math Algebra 2 Module 3 Lesson 18 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math Algebra 2 Module 3 Lesson 18 Answer Key<\/h2>\n

Eureka Math Algebra 2 Module 3 Lesson 18 Opening Exercise Answer Key<\/h3>\n

Opening Exercise:<\/p>\n

Complete the following table of values of the function f(x) = 2x<\/sup>. We want to sketch the graph of y f(x) and then reflect that graph across the diagonal line with equation y = x.<\/p>\n

\"Eureka<\/p>\n

Answer:<\/p>\n

\"Eureka<\/p>\n

On the set of axes below, plot the points from the table and sketch the graph of y = 2x<\/sup>. Next, sketch the diagonal line with equation y = x, and then reflect the graph of y = 2x<\/sup> across the line.<\/p>\n

\"Eureka<\/p>\n

Answer:<\/p>\n

\"Eureka<\/p>\n

Eureka Math Algebra 2 Module 3 Lesson 18 Exercise Answer Key<\/h3>\n

Exercises:<\/p>\n

Exercise 1.
\nComplete the following table of values of the function g(x) = log2<\/sub>(x). We want to sketch the graph of y = g(x) and then reflect that graph across the diagonal line with equation y = x.<\/p>\n

\"Eureka<\/p>\n

Answer:<\/p>\n

\"Eureka<\/p>\n

On the set of axes below, plot the points from the table and sketch the graph of y = log2<\/sub>(x). Next, sketch the diagonal line with equation y = x, and then reflect the graph of y = log2<\/sub>(x) across the line.<\/p>\n

\"Eureka<\/p>\n

Answer:<\/p>\n

\"Eureka<\/p>\n

Exercise 2.
\nWorking independently, predict the relation between the graphs of the functions f(x) = 3x<\/sup> and g(x) = log3<\/sub>(x). Test your predictions by sketching the graphs of these two functions. Write your prediction in your notebook, provide justification for your prediction, and compare your prediction with that of your neighbor.<\/p>\n

\"Eureka<\/p>\n

Answer:
\nThe graphs will be reflections of each other about the diagonal.<\/p>\n

\"Eureka<\/p>\n

Exercise 3.
\nNow let\u2019s compare the graphs of the functions f2<\/sub>(x) = 2 and f3<\/sub>(x) = 3. Sketch the graphs of the two exponential functions on the same set of axes; then, answer the questions below.<\/p>\n

\"Eureka<\/p>\n

Answer:<\/p>\n

\"Eureka<\/p>\n

a. Where do the two graphs intersect?
\nAnswer:
\nThe two graphs intersect at the point (0, 1).<\/p>\n

b. For which values of x is 2x<\/sup> < 3x<\/sup>?
\nAnswer:
\nIf x > 0, then 2x<\/sup> < 3x<\/sup><\/p>\n

c. For which values of x is 2x<\/sup> > 3x<\/sup>?
\nAans:
\nIf x < 0, then 2x<\/sup> > 3x<\/sup><\/p>\n

d. What happens to the values of the functions 12 and 13 as x \u2192 \u221e?
\nAnswer:
\nAs x \u2192 \u221e, both f2<\/sub>(x) \u2192 \u221e\u201a and f3<\/sub>(x) \u2192 \u221e.<\/p>\n

e. What happens to the values of the functions 12 and 13 as x \u2192 -\u221e?
\nAnswer:
\nAs x \u2192 -\u221e,both f2<\/sub>(x) \u2192 0 and f3<\/sub>(x) \u2192 0.<\/p>\n

f. Does either graph ever intersect the x-axis? Explain how you know.
\nAnswer:
\nNo. For every value of x, we know 2x<\/sup> \u2260 0 and 3x<\/sup> \u2260 0.<\/p>\n

Exercise 4.
\nAdd sketches of the two logarithmic functions g2<\/sub>(x) = log2<\/sub>(x) and g3<\/sub>(x) = log3<\/sub>(x) to the axes with the graphs of the exponential functions from Exercise 3; then, answer the questions below.<\/p>\n

\"Eureka<\/p>\n

a. Where do the two logarithmic graphs intersect?
\nAnswer:
\nThe two graphs intersect at the point (1, 0).<\/p>\n

b. For which values of x is log2<\/sub>(x) < log3<\/sub>(x)?
\nAnswer:
\nIf x < 1, then log2<\/sub>(x) < log3<\/sub>(x).<\/p>\n

c. For which values of x is log2<\/sub>(x) > log3<\/sub>(x)?
\nAnswer:
\nIf x > 1, then log2<\/sub>(x) > log3<\/sub>(x).<\/p>\n

d. What happens to the values of the functions g2<\/sub> and g3<\/sub> as x \u2192 \u221e?
\nAnswer:
\nAs x \u2192 \u221e, both g2<\/sub>(x) \u2192 \u221e and g3<\/sub>(x) \u2192 \u221e.<\/p>\n

e. What happens to the values of the functions g2<\/sub> and g3<\/sub> as x \u2192 0?
\nAnswer:
\nAs x \u2192 0, both g2<\/sub>(x) \u2192 -\u221e and g3<\/sub>(x) \u2192 -\u221e.<\/p>\n

f. Does either graph ever intersect the y-axis? Explain how you know.
\nAnswer:
\nNo. Logarithms are only defined for positive values of x.<\/p>\n

g. Describe the similarities and differences in the behavior of f2<\/sub>(x) and g2<\/sub>(x) as x \u2192 \u221e.
\nAnswer:
\nAs x \u2192 \u221e, both f2<\/sub>(x) \u2192 \u221e and g2<\/sub>(x) \u2192 \u221e; however, the exponential function gets very large very quickly, and the logarithmic function gets large rather slowly.<\/p>\n

Eureka Math Algebra 2 Module 3 Lesson 18 Problem Set Answer Key<\/h3>\n

Question 1.
\nSketch the graphs of the functions f(x) = 5x<\/sup> and g(x) = log5<\/sub>(x).
\nAnswer:<\/p>\n

\"Eureka<\/p>\n

Question 2.
\nSketch the graphs of the functions f(x) = (\\(\\frac{1}{2}\\))x<\/sup> and g(x) = log\\(\\frac{1}{2}\\)<\/sub>(x).
\nAnswer:<\/p>\n

\"Eureka<\/p>\n

Question 3.
\nSketch the graphs of the functions f1<\/sub>(x) = (\\(\\frac{1}{2}\\))x<\/sup> and f2<\/sub>(x) = (\\(\\frac{3}{4}\\))x<\/sup> on the same sheet of graph paper, and answer the following questions.<\/p>\n

a. Where do the two exponential graphs intersect?
\nAnswer:
\nThe graphs intersect at the point (0, 1).<\/p>\n

b. For which values of x is (\\(\\frac{1}{2}\\))x<\/sup> < (\\(\\frac{3}{4}\\))x<\/sup>?
\nAnswer:
\nIf x > 0, then (\\(\\frac{1}{2}\\))x<\/sup> < (\\(\\frac{3}{4}\\))x<\/sup>.<\/p>\n

c. For which values of x is (\\(\\frac{1}{2}\\))x<\/sup> > (\\(\\frac{3}{4}\\))x<\/sup>??
\nAnswer:
\nIf x < 0, then (\\(\\frac{1}{2}\\))x<\/sup> < (\\(\\frac{3}{4}\\))x<\/sup>.<\/p>\n

d. What happens to the values of the functions f1<\/sub> and f2<\/sub> as x \u2192 \u221e?
\nAnswer:
\nAs x \u2192 \u221e,both f1<\/sub>(x) \u2192 0 and f2<\/sub>(x) \u2192 0.<\/p>\n

e. What are the domains of the two functions f1<\/sub> and f2<\/sub>?
\nAnswer:
\nBoth functions have domain (-\u221e, \u221e).<\/p>\n

\"Eureka<\/p>\n

Question 4.
\nUse the information from Problem 3 together with the relationship between graphs of exponential and logarithmic functions to sketch the graphs of the functions g1<\/sub>(x) = log\\(\\frac{1}{2}\\)<\/sub>(x) and g2<\/sub>(x) = log>\\(\\frac{3}{4}\\)<\/<\/sub>(x) on the same sheet of graph paper. Then, answer the following questions.<\/p>\n

\"Eureka<\/p>\n

a. Where do the two logarithmic graphs intersect?
\nAnswer:
\nThe graphs intersect at the point (1, 0).<\/p>\n

b. For which values of x is log\\(\\frac{1}{2}\\)<\/sub>(x) < log\\(\\frac{3}{4}\\)<\/sub>(x)?
\nAnswer:
\nWhen x < 1, we have log\\(\\frac{1}{2}\\)<\/sub>(x) < log\\(\\frac{3}{4}\\)<\/sub>(x).<\/p>\n

c. For which values of x is log\\(\\frac{1}{2}\\)<\/sub>(x) > log\\(\\frac{3}{4}\\)<\/sub>(x)?
\nAnswer:
\nWhen x > 1, we have log\\(\\frac{1}{2}\\)<\/sub>(x) > log\\(\\frac{3}{4}\\)<\/sub>(x).<\/p>\n

d. What happens to the values of the functions g1<\/sub> and g2<\/sub> as x \u2192 \u221e?
\nAnswer:
\nAs x \u2192 \u221e, both g1<\/sub>(x) \u2192 -\u221e and g2<\/sub>(x) \u2192 -\u221e.<\/p>\n

e. What are the domains of the two functions g1<\/sub> and g2<\/sub>?
\nAnswer:
\nBoth functions have domain (0, \u221e).<\/p>\n

Question 5.
\nFor each function f, find a formula for the function h in terms of x.<\/p>\n

a. If f(x) = x3<\/sup>, find h(x) = 128f(\\(\\frac{1}{4}\\)x) + f(2x).
\nAnswer:
\nh(x) = 10x3<\/sup><\/p>\n

b. If (x) = x2<\/sup> + 1, find h(x) = f(x + 2) – f(2).
\nAnswer:
\nh(x) = x2<\/sup> + 4x<\/p>\n

c. If f(x) = x3<\/sup> + 2x2<\/sup> + 5x + 1, find h(x) = \\(\\frac{f(x)+f(-x)}{2}\\)
\nAnswer:
\nh(x) = 2x2<\/sup> + 1<\/p>\n

d. If (x) = x3<\/sup> + 2x2<\/sup> + 5x + 1, find h(x) = \\(\\frac{f(x)-f(-x)}{2}\\)
\nAnswer:
\nh(x) = x3<\/sup> + 5x<\/p>\n

Question 6.
\nIn Problem 5, parts (c) and (d), list at least two aspects about the formulas you found as they relate to the function f(x) = x3<\/sup> + 2x2<\/sup> + 5x + 1.
\nAnswer:
\nThe formula for 1(c) is all of the even power terms off. The formula for 1(d) is all of the odd power terms off. The sum of the two functions gives f back again; that is, \\(\\frac{f(x)+f(-x)}{2}\\) + \\(\\frac{f(x)-f(-x)}{2}\\) = f<\/p>\n

Question 7.
\nFor each of the functions f and g below, write an expression for (i) f(g(x)), (ii) g(f(x)) and (iii) f(f(x)) in terms of x.<\/p>\n

a. f(x) = x\\(\\frac{2}{3}\\)<\/sup>, g(x) = x12<\/sup>
\nAnswer:
\ni. f(g(x)) = x8<\/sup>
\nii. g(f(x)) = x8<\/sup>
\niii. f(f(x)) = x\\(\\frac{4}{9}\\)<\/sup><\/p>\n

b. f(x) = \\(\\frac{\\boldsymbol{b}}{x-a}\\), g(x) = \\(\\frac{\\boldsymbol{b}}{\\boldsymbol{x}}\\) + a for two numbers a and b, when x is not 0 or a.
\nAnswer:
\ni. f(g(x)) = x
\nii. g(f(x)) = x
\niii. f(f(x)) = \\(\\frac{b}{\\frac{b}{x-a}-a}\\), which is equivalent to f(f(x)) = \\(\\frac{b(x-a)}{b+a^{2}-a x}\\)<\/p>\n

c. f(x) = \\(\\frac{x+1}{x-1}\\) g(x) = \\(\\frac{x+1}{x-1}\\) when x is not 1 or -1
\nAnswer:
\ni. f(g(x)) = x
\nii. g(f(x)) = x
\niii. f(f(x)) = x<\/p>\n

d. f(x) = 2x<\/sup>, 9(x) = log2<\/sub>(x)
\nAnswer:
\ni. f(g(x)) = x
\nii. g(f(x)) = x
\niii. f(f(x)) = x<\/p>\n

e. f(x) = ln(x), g(x) = ex<\/sup>
\nAnswer:
\ni. f(g(x)) = x
\nii. g(f(x)) = x
\niii. f(f(x)) = ln(ln(x))<\/p>\n

f. f(x) = 2 . 100x<\/sup>, g(x) = \\(\\frac{1}{2}\\)log(\\(\\frac{1}{2}\\)x)
\nAnswer:
\ni. f(g(x)) = x
\nii. g(f(x)) = x
\niii. f(f(x)) = 2 . 10000100x<\/sup><\/p>\n

Eureka Math Algebra 2 Module 3 Lesson 18 Exit Ticket Answer Key<\/h3>\n

Question 1.
\nThe graph of a logarithmic function g(x) = logb<\/sub>(x) is shown below.<\/p>\n

\"Eureka<\/p>\n

a. Explain how to find points on the graph of the function f(x) = bx<\/sup>
\nAnswer:
\nA point (x, y) is on the graph of f if the corresponding point (y, x) is on the graph of g.<\/p>\n

b. Sketch the graph of the function f(x) = bx<\/sup> on the same axes.
\nAnswer:
\n\"Eureka<\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math Algebra 2 Module 3 Lesson 18 Answer Key Eureka Math Algebra 2 Module 3 Lesson 18 Opening Exercise Answer Key Opening Exercise: Complete the following table of values of the function f(x) = 2x. We want to sketch the graph of y f(x) and then reflect that graph across the diagonal … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/97856"}],"collection":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/comments?post=97856"}],"version-history":[{"count":1,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/97856\/revisions"}],"predecessor-version":[{"id":136273,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/posts\/97856\/revisions\/136273"}],"wp:attachment":[{"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/media?parent=97856"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/categories?post=97856"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ccssanswers.com\/wp-json\/wp\/v2\/tags?post=97856"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}