Go through the Spectrum Math Grade 6 Answer Key Chapter 6 Lesson 6.6 Surface Area: Rectangular Solids and get the proper assistance needed during your homework.
Spectrum Math Grade 6 Chapter 6 Lesson 6.6 Surface Area: Rectangular Solids Answers Key
Find the surface area of each rectangular solid.
Question 1.
a.
SA = ____ sq. in.
Answer:
Given rectangular solid is 3 in. wide, 5 in. long and 2 in. high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(5×3 + 3×2 + 2×3)
= 2×(15+6+6)
=2×27
=54
The surface area of the rectangular solid is 54 sq.in
b.
SA = ____ sq. ft.
Answer:
Given rectangular solid is 1.5 ft wide, 8 ft long and 1.3 ft high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(8×1.5 + 1.5×1.3 + 1.3×8)
= 2×(12+1.95+10.4)
=2×24.35
=48.7
The surface area of the rectangular solid is 48.7 sq.ft
c.
SA = ____ sq. yd.
Answer:
Given rectangular solid is 8 yd wide, 7 yd long and 2 yd high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(7×8 + 7×2 + 2×8)
= 2×(56+14+16)
=2×86
=172
The surface area of the rectangular solid is 172 sq.yd
Question 2.
a.
SA = ____ sq. cm
Answer:
Given solid is 10 cm wide, 14 cm long and 12 cm high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(14×10 + 10×12 + 12×14)
= 2×(140+120+168)
= 2×428
= 856
The surface area of the rectangular solid is 856 sq.cm
b.
SA = ____ sq. m
Answer:
Given rectangular solid is 6m wide, 2 m long and 5 m high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(2×6 + 6×5 + 5×2)
= 2×(12+30+10)
= 2×52
= 104
The surface area of the rectangular solid is 104 sq.m
c.
SA = ____ sq. in.
Answer:
Given rectangular solid is 2 in. wide, 14 in. long and 6 in. high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(14×2 + 2×6 + 6×14)
= 2×(28+6+84)
= 2×118
= 236
The surface area of the rectangular solid is 236 sq.in.
Question 3.
a.
SA = ____ sq. ft.
Answer:
Given rectangular solid is 6.5 ft wide, 3.5 ft long and 2 ft high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(3.5×6.5 + 6.5×2 + 2×3.5)
= 2×(22.75+13+7)
= 2×42.75
= 85.5
The surface area of the rectangular solid is 85.5 sq.ft.
b.
SA = ____ sq. mm
Answer:
Given rectangular solid is 20 mm wide, 38 mm long and 12.5 mm high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(38×20 + 20×12.5 + 12.5×38)
= 2×(760+250+475)
= 2×1485
= 2970
The surface area of the rectangular solid is 2970 sq.mm.
c.
SA = ____ sq. cm
Answer:
Given rectangular solid is 2 cm wide, 3.2 cm long and 6.6 cm high
Surface area of the solid = 2×(length×width + width×height + height×length)
= 2×(3.2×2 + 2×6.6 + 6.6×3.2)
= 2×(6.4+13.2+21.12)
= 2×40.72
= 81.44
The surface area of the rectangular solid is 81.44 sq.cm.