Ratio Word Problems Worksheet can be a great way to teach students and interrelate mathematics concepts to real-world scenarios. Using Simple Word Problems on Ratio Worksheet students can get enough practice to apply their knowledge on ratios.
Students can definitely master the concept of Ratio as well as enhance their thinking skills too by solving the questions over here on a regular basis. These Printable Math Worksheets on Simple Word Problems on Ratio are free to download in PDF Formats and you can use them as a quick guide for the Ratio Topic.
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Simple Ratio Problems with Solutions
I. A Laughing club has 30 members, of which 18 are males and the rest are females. What is the ratio of females to all club members?
Solution:
Given,
No. of members in the laughing club=30
No. of males in the club=18
No. of females in the club=30 – 18=12
The ratio of females to all club members=12/30=6/15=2/5
Therefore, the ratio of females to all club members is 2/5.
II. A pattern has 3 Red triangles for every 18 yellow triangles. What is the ratio of red triangles to all triangles?
Solution:
Given that,
No. of Red triangles=3
No. of yellow triangles=18
No. of all triangles=18+3=21
The ratio of red triangles to all triangles=3/21=1/7
Therefore, the ratio of Red triangles to all triangles is 1/7.
III. In traffic the ratio of scooters to cars is 4:9. If there are a total of 12 scooters. Find the total number of Cars?
Solution:
Given that,
The ratio of scooters to cars=4:9
No. of scooters=12
Let the total number of scooters=4x
Let the total number of cars=9x
4x=12
x=12/4=3
The total number of cars=9x=9(3)=27.
Therefore, the total number of cars is 27.
IV. In a musical instruments shop, the ratio of trumpets to violins is 4:7. If the total number of trumpets is 8. Find the total number of violins?
Solution:
Given that,
The ratio of trumpets to violins is =4:7
Let the total number of trumpets=4x
Let the total number of violins is=7x
The total number of trumpets is= 8
i.e. 4x=8
x=8/4=2
The total number of violins=7x=7(2)=14
Hence, the total number of violins is 14.
V. There were 500 shirts in a shop. Redshirts were double the number of yellow shirts. white shirts were 4 more in number than the red shirts. blue shirts were 20 more than green shirts. green shirts were 3 more than yellow shirts and 7 less than white shirts. How many shirts of each color were there in the shop?
Solution:
Let the number of yellow Shirts be ‘x’.
Given that,
green shirts are 3 more than yellow shirts.
Then, the number of green shirts = (x + 3)
And when, number of blue shirts are 18 more than the number of green shirts, then the number of blue shirts = (x + 3 + 20)
= (x + 23)
when, red shirts are double the number of yellow shirts. Then, the number of red shirts = 2x
And number of white shirts are 2 more than the number of red shirts. Then, number of white shirts = (2x + 4)
Now, number of total shirts = 500
Therefore,
x + x + 3 + x + 23 + 2x + 2x + 4 = 500
7x + 30 = 500
7x = 500 – 30
x = 470/7
x = 67
So, the number of yellow shirts is 67.
Number of green shirts = 67 + 3 =70
Number of blue shirts = 72 + 20 = 92
Number of red shirts = 2*67= 134
Number of white shirts = 134+ 4 = 138.
Therefore, there are 67 yellow shirts,70 green shirts, 92 blue shirts,134 red shirts, and 138 white shirts.
VI. There are 4 boys to every 2 girls in the class of 60 students. How many girls and boys are there in the class?
Solution:
Given that,
No. of students in the class=60
Let the number of boys in the class=4x
Let the number of girls in the class=2x
4x+2x=60
6x=60
x=60/6=10
No. of boys=4x=4(10)=40
No. of girls=2x=2(10)=20
Hence, there are 40 boys and 20 girls in a class of 60 students.
VII. Number of people can be seated in the two buses are in the ratio 5:6. No. of people can be seated in the first bus is 50. Find the number of people seated in the second bus?
Solution:
Given that,
The number of people can be seated in the two buses are in the ratio= 5:6
Let the no. of people seated in the first bus=5x
Let the no. of people seated in the second bus=6x
No. of people can be seated in the first bus is= 50
i.e. 5x=50
x=50/5=10
Number of people seated in the second bus=6x=6(10)=60
Hence, Number of people seated in the second bus is 60.
VIII. The ratio of adult visitors to child visitors to a museum is 1 : 3. The number of child visitors exceeds the number of adult visitors by 40. Find the total number of visitors to the museum?
Solution:
Given that,
The ratio of adult visitors to child visitors to a museum is 1 : 3
Let the adult visitors be x.
Let the child visitors be 3x.
The number of child visitors exceeds the number of adult visitors by= 40
i.e. 3x-x=40
2x=40
x=40/2=20
Number of child visitors to the museum=3x=3(20)=60
Number of adult visitors to the museum=1x=1(20)=20
Total number of visitors to the museum=60+20=80
Hence, the total number of visitors to the museum is 80.
IX. Divide Rs540 into three parts such that the first part is 4/5 of the second and the ratio between the second and third is 6: 8.
Solution:
Given that Rs540 divided into three parts such that the first part is 4/5 of the second and the ratio between the second and third is 6:8
From the given data, let the common multiple of these ratio = a.
Then, the second and third ratio = 6a and 8a
Given that the first part is 4/5 of the second part
The first part is 4/5 × 6a = 24/5a
Given 24/5a + 6a + 8a = Rs540
24a+30a+40a=2700
a=28.72
Now, substitute the a value to find the answer.
The first part = 24/5a = 24/5(28.72)=137.85
The second part = 6a = 6 × 28.72 =172.32
The third part = 8a = 8× 28.72 =229.76
Therefore, the divided three parts are 137.85, 172.32, 229.76.
X. Jay has 20 balls, 12 of which are red and 8 of which are blue. Amar has 10 balls, all of them either red or blue. If the ratio of the red balls to the blue balls is the same for both Jay and Amar, then Jay has how many more blue balls than Amar?
Solution:
Given that,
Amar has 10 balls, all of them either red or blue.
Let x = number of blue balls for Amar
10 – x = number red balls for Amar
We get the ratio from Jay
Jay has 20 balls, 12 of which are red and 8 of which are blue.
red/blue=12/8=3/2
We use the same ratio for Amar.
red/blue=3/2=10-x/x
By cross multiplying we get,
3 × x = 2 × (10 – x)
3x = 20 – 2x
5x=20
x=20/5=4.
Amar has 4 blue balls.
Jay has 8 blue balls. So, he has 8– 4 = 4 more blue balls than Amar.
Therefore, Jay has 4 more blue balls than Amar.
XI. The ratio of the selling price and the cost price of a car is 7 : 5. If seller made a profit of Rs8,000 when he sold the car, what was the selling price of the car?
Solution:
Given,
The ratio of the selling price and the cost price of a car = 7 : 5
Let the selling price of the car=7x
Let the cost Price of the car=5x
Profit=Rs 8000
7x-5x=8000
2x=8000
x=4000
Selling Price of the Car=7x=7(4000)=28000.