In maths, probability is a chance of occurrence of random events. Tossing a coin is an example of probability. When you toss a coin, the outcome may be head or tail. But if you toss 2 coins simultaneously, the sample space will have 4 possibilities. Here we will learn about the outcomes of coin toss probabilities along with the examples.

## Coin Toss Probability

We generally see a coin toss before the commencement of a match to take the decision between two teams. The result of tossing a coin experiment is head or tail. Obtaining the result as the head is 50% and the tail is also 50%. If you toss one coin, there are only two possible outcomes.

The probability occurrence of an event is always measured between 0 and 1. 1 indicates the occurrence of an event and 0 represents the unlikely occurrence of an event probability.

Number of possible outcomes = 2

Number of outcomes to get head = 1

Probability of getting head = ½

Probability of an event = \(\frac { Number of favourable outcomes }{ Total number of possible outcomes } \)

### Probability of Tossing Two Coins

We can find the probability of tossing 2 coins at a time or tossing 3 coins probability. Here we will learn the complete details of two coin-tossing probabilities. When we toss two coins simultaneously then the possible outcomes are two heads, two tails, one head and one tail. The sample space S = {(H, H), (H, T), (T, H), (T, T). Here ‘H’ represents the head and ‘T’ represents the tail.

The total number of outcomes = 2² = 4

Then, the probability of getting 2 tails = \(\frac { 1 }{ 4 } \). As the sample space as only 1 time and the total number of outcomes are 4.

### Solved Examples on Probability of Flipping 2 Coins

**Example 1:
**If two coins are flipped randomly. Find the probability of

(i) getting two heads

(ii) getting one tail

(iii) getting no tail

**Solution:
**If two coins are tossed, then the sample space is S = {HH, TT, HT, TH}

**(i) getting two heads**

The number of times, we get two heads = 1

So, probability of getting two heads P(E1) = \(\frac { 1 }{ 4 } \)

**(ii) getting one tail**

The number of times, we can get one tail = 2 = {HT, TH}

So, probability of getting one tail P(E2) = \(\frac { 2 }{ 4 } \) = ½

**(iii) getting no tail**

The number of times, we can get no tail = 1 = {HH}

So, probability of getting no tail P(E3) = \(\frac { 1 }{ 4 } \)

**Example 2:
**When 2 coins are tossed, find the probability of

(i) getting atmost 1 head

(ii) getting 1 head and 1 tail

(iii) getting at least 1 tail

**Solution:
**If two coins are tossed, then the sample space is S = {HH, TT, HT, TH}

**(i) getting atmost 1 head**

Event of getting atmost 1 head = {TT, TH, HT} = 3

Therefore, P(getting atmost 1 head) = \(\frac { 3 }{ 4 } \)

**Event of getting 1 head and 1 tail = { TH, HT} = 2**

(ii) getting 1 head and 1 tail

(ii) getting 1 head and 1 tail

Therefore, P(getting 1 head and 1 tail) = \(\frac { 2}{ 4 } \) = ½

**(iii) getting at least 1 tail**

Event of getting at least 1 tail = {TT, TH, HT} = 3

Therefore, P(getting at least 1 tail) = \(\frac { 3 }{ 4 } \)

### FAQ’s on Probability of Flipping Two Coins

**1. What is the sample space of tossing 2 coins?**

The sample space of tossing two coins is {HH, TT, HT, TH}.

**2. How to find the probability of two coins?**

The formula to find the probability of two coins = \(\frac { Number of favourable outcomes }{ 4 } \). Place the values to get the answer.

**3. When two coins are tossed what is the probability of getting tails for both the coins?**

When two coins are tossed, the number of favourable outcomes = 4. The chance of getting two tails = \(\frac { 1 }{ 4 } \)

**4. What is the probability of getting 2 heads when the two coins are tossed simultaneously?**

When two coins are tossed, the number of favourable outcomes = 4. The probability of getting two heads = \(\frac { 1 }{ 4 } \)