Go through the Spectrum Math Grade 6 Answer Key Chapter 6 Lesson 6.2 Calculating Area: Quadrilaterals and get the proper assistance needed during your homework.
Spectrum Math Grade 6 Chapter 6 Lesson 6.2 Calculating Area: Quadrilaterals Answers Key
Area is the number of square units it takes to cover a figure. To find the area of a rectangle, multiply the length by the width. A = lw
A = 7 × 2
A = 64 square units
A = s × s = 8 × 8
A = 64 square units
Find the area of each rectangle below.
Question 1.
a.
A = ___ sq. m
Answer:
Given rectangle is of 6 yd. long and 3 yd. wide.
Area of rectangle = length×width
Here length is 6 yd and width is 3 yd.
Area = 6×3
= 18 sq.yd
Thus, the area will be 18 sq.yd
b.
A = ___ sq. m
Answer:
Given square is of 18m length.
Area of square = length×length
Area = 18×18
= 324 sq.m
Thus, the area will be 324 sq.m
c.
A = ___ sq. cm
Answer:
Given rectangle is of 23 cm long and 12 cm wide.
Area of rectangle = length×width
Here length is 23 cm and width is 12 cm.
Area = 23×12
= 276 sq.cm
Thus, the area will be 276 sq.cm
Question 2.
a.
A = ___ sq. km
Answer:
Given rectangle is of 24 km long and 9 km wide.
Area of rectangle = length×width
Here length is 24 km and width is 9 km.
Area = 24×9
= 216 sq.km
Thus, the area will be 216 sq.km
b.
A = ___ sq. in.
Answer:
Given square is of 23 in. length.
Area of square = length×length
Area = 23×23
= 529 sq.in.
Thus, the area will be 529 sq.in.
c.
A = ___ sq. ft.
Answer:
Given rectangle is of 8 ft long and 6 ft wide.
Area of rectangle = length×width
Here length is 8 ft and width is 6 ft.
Area = 8×6
= 48 sq.ft
Thus, the area will be 48 sq.ft
Find the length of each rectangle below.
Question 3.
a.
A =’54 sq. in.
Answer:
Given that the area of rectangle is 54 sq.in and the side length is 6 in.
Area of rectangle = length×width
54 = 6×width
54÷6 = (6×width)÷6
9 = width
Thus, the length of the width will be 9 in.
b.
A = 58.5 sq. ft.
l = ____ ft.
Answer:
Given that the area of rectangle is 58.5 sq.ft and the side length is 4.5 ft.
Area of rectangle = length×width
58.5 = 4.5×width
58.5÷4.5 = (4.5×width)÷4.5
13 = width
Thus, the length of the width will be 13 ft.
c.
A = 81 sq. m.
l = ____ m
Answer:
Given that the area of rectangle is 81 sq.m and the side length is 9 m.
Area of rectangle = length×width
81 = 9×width
81÷9 = (9×width)÷9
9 = width
Thus, the length of the width will be 9 m.
As all the side lengths are equal, it will be a square.
A parallelogram is a polygon with 2 sets of parallel sides. To find the area of a parallelogram, multiply the measure of its base by the measure of its height: A = b × h or A = bh.
b = 8 in. and h = 7 in. What is A?
A = b × h A = 8 × 7 = 56 in.2 or 56 square inches.
Find the area of each parallelogram.
Question 1.
a.
A = ____ sq. cm
Answer:
Given that the height of the parallelogram is 24 cm and the base length is 26 cm.
Area of parallelogram = base×height
= 24×26
= 624 sq.cm
Thus, the area of the parallelogram is 624 sq.cm
b.
A = ____ sq. in.
Answer:
Given that the height of the parallelogram is 15 in. and the base length is 30 in.
Area of parallelogram = base×height
= 15×30
= 450 sq.in
Thus, the area of the parallelogram is 450 sq.in
c.
A = ____ sq. mm
Answer:
Given that the height of the parallelogram is 21 mm and the base length is 33 mm.
Area of parallelogram = base×height
= 21×31
= 651 sq.mm
Thus, the area of the parallelogram is 651 sq.mm
Question 2.
a.
A = ____ sq. in.
Answer:
Given that the height of the parallelogram is 18 in. and the base length is 17 in.
Area of parallelogram = base×height
= 17×18
= 306 sq.in
Thus, the area of the parallelogram is 306 sq.in
b.
A = ____ sq. m
Answer:
Given that the height of the parallelogram is 10.5 m and the base length is 15 m.
Area of parallelogram = base×height
= 15×10.5
= 157.5 sq.m
Thus, the area of the parallelogram is 157.5 sq.m
c.
A = ____ sq. cm
Answer:
Given that the height of the parallelogram is 12.5 cm and the base length is 11 cm.
Area of parallelogram = base×height
= 11×12.5
= 137.5 sq.cm
Thus, the area of the parallelogram is 137.5 sq.cm
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